Colin,

Let's not argue too much ;). Here how I calculated (It may look simplist and
would require experimentation to confirm):

List with 6 elements
Yours: 6 loops with 2 operations each = 12
Mine: 3 loops with 3 operations = 9

List with 100 elements
Yours: 100 loops with 2 operations each = 200
Mine: 50 loops with 3 operations = 100

I'll try to run tests to confirm and ready to apologize if I'm wrong.

Laurent.


> -----Original Message-----
> From: Colin Holgate [mailto:[EMAIL PROTECTED]]
> Sent: 8 f�vrier, 2002 11:05
> To: [EMAIL PROTECTED]
> Subject: RE: <lingo-l> turning a list back to front
> 
> 
> >   repeat with i = 1 to nb/2
> >     tmp = theList[i]
> >     theList[i] = theList[nb+1-i]
> >     theList[nb+1-i] = tmp
> >   end repeat
> >end
> >
> >This one using just one list: memory economy and is faster 
> than colin's (for
> >a list of 10 elements, Colin's algorithm is doing 20 
> operations, mine's
> >doing only 15).
> 
> 
> I'm not so sure about your 20/15 comparison. In mine I was doing an 
> append of a get, in effect, which for a six element list is 12 
> operations. In yours you're doing a get, then a set of another get, 
> followed by another set. You do that for half the list amount, but it 
> still totals 12 operations.
> 
> 
> -- 
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