Thanks for your respond
I use PF not OPF.
If  SVC modeled with a gen with PG=0 Do we need to set ENFORCE_Q_LIM  to 1 or 
not? Because if it isn't set to 1 may exceeds its limits.
If it modeled in BS column of bus matrix, How much is the generated reactive 
power at voltages except 1 p.u.? 



________________________________
 From: Ray Zimmerman <[email protected]>
To: MATPOWER discussion forum <[email protected]> 
Sent: Thursday, August 1, 2013 5:46 PM
Subject: Re: PF by removing Line
 


I am assuming you are using PF, not OPF ...

1. You can model it with a gen with PG = 0, then QG will be solved to keep the 
bus voltage at the set point. Or you can model it as a reactive injection (in 
QD column of bus matrix). Or you can model it as a capacitor bank (BS column of 
bus matrix).

2. By default MATPOWER's power flow enforces the voltage set point at the 
expense of the Q limit.

-- 
Ray Zimmerman
Senior Research Associate
B30 Warren Hall, Cornell University, Ithaca, NY 14853
phone: (607) 255-9645





On Aug 1, 2013, at 3:30 AM, Power Engineer <[email protected]> wrote:

1. for modeling SVC by zero P-output generator does we need a reference 
voltage? Can wemodel SVC  by a reactive power injection like capacitor bank?
>2. I use default MATPOWER options for PF.
>
>
>
>________________________________
> From: "[email protected]" <[email protected]>
>To: [email protected] 
>Sent: Wednesday, July 31, 2013 2:27 PM
>Subject: RE: PF by removing Line
> 
>
>
> 
>1, zero P-output might imply SVC or synchronous condenser
>2. your PF might have option that ignore the Q-limit.
> 
>BR//Yongtao
> 
>From:[email protected] 
>[mailto:[email protected]] On Behalf Of Power Engineer
>Sent: 31. juli 2013 10:38
>To: MATPOWER forum
>Subject: PF by removing Line
> 
>Dear all 
>I have 2 questions
>1. in case 57 and 118 we have some generators with zero active output, Do they 
>model special equipment? 
>2. I run PF for case 57 by removing line between 8 and 9 while the power flow 
>is converging the reactive limit of generator at bus 9 violated.
>results.success
> 
>ans =
> 
>     1
> 
>results.gen(:,1:5)
> 
>ans =
> 
>            1       511.91     142.3          200         -140
>            2            0       -1.9005           50          -17
>            3           40       16.317           60          -10
>            6            0        6.774           25           -8
>            8          450       34.892          200         -140
>            9            0        86.611            9           -3
>           12          310       151.03          155         -150
> 
> 
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