Thanks for your respond I use PF not OPF. If SVC modeled with a gen with PG=0 Do we need to set ENFORCE_Q_LIM to 1 or not? Because if it isn't set to 1 may exceeds its limits. If it modeled in BS column of bus matrix, How much is the generated reactive power at voltages except 1 p.u.?
________________________________ From: Ray Zimmerman <[email protected]> To: MATPOWER discussion forum <[email protected]> Sent: Thursday, August 1, 2013 5:46 PM Subject: Re: PF by removing Line I am assuming you are using PF, not OPF ... 1. You can model it with a gen with PG = 0, then QG will be solved to keep the bus voltage at the set point. Or you can model it as a reactive injection (in QD column of bus matrix). Or you can model it as a capacitor bank (BS column of bus matrix). 2. By default MATPOWER's power flow enforces the voltage set point at the expense of the Q limit. -- Ray Zimmerman Senior Research Associate B30 Warren Hall, Cornell University, Ithaca, NY 14853 phone: (607) 255-9645 On Aug 1, 2013, at 3:30 AM, Power Engineer <[email protected]> wrote: 1. for modeling SVC by zero P-output generator does we need a reference voltage? Can wemodel SVC by a reactive power injection like capacitor bank? >2. I use default MATPOWER options for PF. > > > >________________________________ > From: "[email protected]" <[email protected]> >To: [email protected] >Sent: Wednesday, July 31, 2013 2:27 PM >Subject: RE: PF by removing Line > > > > >1, zero P-output might imply SVC or synchronous condenser >2. your PF might have option that ignore the Q-limit. > >BR//Yongtao > >From:[email protected] >[mailto:[email protected]] On Behalf Of Power Engineer >Sent: 31. juli 2013 10:38 >To: MATPOWER forum >Subject: PF by removing Line > >Dear all >I have 2 questions >1. in case 57 and 118 we have some generators with zero active output, Do they >model special equipment? >2. I run PF for case 57 by removing line between 8 and 9 while the power flow >is converging the reactive limit of generator at bus 9 violated. >results.success > >ans = > > 1 > >results.gen(:,1:5) > >ans = > > 1 511.91 142.3 200 -140 > 2 0 -1.9005 50 -17 > 3 40 16.317 60 -10 > 6 0 6.774 25 -8 > 8 450 34.892 200 -140 > 9 0 86.611 9 -3 > 12 310 151.03 155 -150 > > >************************************************************************************** The contents of this e-mail message and any attachments are confidential and are intended solely for the addressee. If you have received this transmission in error, please immediately notify the sender by return e-mail and delete this message and its attachments. Any unauthorized use, copying or dissemination of this transmission is prohibited. Neither the confidentiality nor the integrity of this message can be vouched for following transmission on the Internet. ************************************************************************************** > >
