Re: [PHP-DB] Doctrine or another recomended ORM?
http://cakephp.org/ On Jan 16, 2011, at 6:02 AM, Miriam Natanzon wrote: Hi, I want to choose an open-source ORM platform to use as a base for many different applications as a standard environment in my organization. ( we used DBI for PERL in the past). I saw and read about Doctrine - Does anyone have any positive/negative experience with it? Is it efficient enough (in the term of runtime)? another recommend environment?? (I have to mention that we are working with relational-DB but not in all projects. maybe there is another environment that is more tailored to the case of just performing queries in constant syntax and security checking?) thanks a lot!!! Miriam
Re: [PHP-DB] Stuck in apostrophe hell
On Aug 2, 2010, at 4:42 PM, Bret Hughes wrote:
I would turn on query logging and see what exactly is making it to mysql.
Niel Archer wrote:
Before I send the following SQL to MySQL from PHP I print it to screen. PHP
chokes on it, but I can paste the exact same query from the screen directly
to MySQL and it works just fine. For example:
Here's the relevant PHP code:
==
$sql_insert_registration = sprintf(INSERT INTO
Registrations (
Class_ID,
prid,
Registrant,
Company,
Phone,
Email
)
VALUES (
$_POST[Class_ID],
$_POST[prid],
'%s',.
parseNull($_POST['Company']).,
'$_POST[Phone]',
'$_POST[Email]'
), mysql_real_escape_string($_POST['Registrant']));
echo pre.$_POST[Registrant]./pre;
echo pre.mysql_real_escape_string($_POST[Registrant])./pre;
echo pre.$sql_insert_registration./pre;
if (!mysql_query($sql_insert_registration, $con)) { die('Error: ' .
mysql_error());
==
Here's the output:
===
INSERT INTO
Registrations (
Class_ID,
prid,
Registrant,
Company,
Phone,
Email
)
VALUES (
355,
257,
'Brian O\'Brien',NULL,
'612-456-5678',
'paul_s_john...@mnb.uscourts.gov'
)
Error: You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use near
'Brien', 'Class registration confirmation', ' This email ' at line 16
==
Also very oddly if the name O'Brien is input into the HTML form with two
apostrophes side by side (O''Brien) then MySQL will take it (but then of
course we have the problem of two apostrophes side by side inserted into
the MySQL table). For example:
===
INSERT INTO
Registrations (
Class_ID,
prid,
Registrant,
Company,
Phone,
Email
)
VALUES (
355,
257,
'Brian O\'\'Brien',NULL,
'612-456-5678',
'paul_s_john...@mnb.uscourts.gov'
)
You have been signed up for the class,
and a confirmation email has been sent to you.
=
Very strange.
I've checked various PHP variables and cannot figure out. It works fines
from another PHP server that's using the same MySQL database.
Thanks,
Paul
Probably needs a double backslash for O'Brien. One to escape the
apostrophe and one to escape the backslash escaping the apostrophe. ;-)
This would be because you're not using mysql_real_escape_string() on the
third parameter. Try this (not tested):
$sql_insert_registration = sprintf(INSERT INTO
Registrations (
Class_ID,
prid,
Registrant,
Company,
Phone,
Email
)
VALUES (%s, %s, '%s', '%s', '%s', '%s'), $_POST[Class_ID],
$_POST[prid],
mysql_real_escape_string(parseNull($_POST['Company'])),
mysql_real_escape_string($_POST[Phone]),
mysql_real_escape_string($_POST[Email]),
mysql_real_escape_string($_POST['Registrant']));
--
Niel Archer
niel.archer (at) blueyonder.co.uk
To reduce the amount of repetitive called to mysql_real_escape_string(), create
a method/function to do the work for you
?php
function escape ($item) {
if (is_array ($item)) {
foreach ($item as $field = $value) {
$escaped[$field] = escape ($value);
}
}
else {
$escaped = mysql_real_escape_string ($item);
}
return $escaped;
}
$_POST['Company'] = parseNull ($_POST['Company']);
$p = escape ($_POST);
$sql = INSERT INTO Registrations (Class_ID, prid, Registrant, Company, Phone,
Email) VALUES ('{$p['Class_ID']}', '{$p['prid']}', '{$p['Registrant']}',
'{$p['Company']}', '{$p['Phone']}', '{$p['Email']}');
?
Don't know if that helps any, but it may take some of the monotony out of it.
Cheers,
~Philip
http://lonestarlightandsound.com/
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Re: [PHP-DB] help in implementing a progress bar
On Jan 7, 2010, at 2:36 PM, Vinay Kannan wrote:
Hello,
Theres this project that I am working on, and a specific module does take
few secs to process, I am thinking it would be cool to be showing a progress
bar(some kind on a .gif image) while the script runs, does any one have an
idea how to implement this?
Thanks,
Vinay K
This isn't really database related, but ok...
?php
// Progress.php
class Progress {
public function start () {
echo file_get_contents ('progress.html');
flush ();
}
public function end ($url) {
$text = script type=\text/javascript\;
$text .= window.location = '$url';;
$text .= /script;
echo $text;
flush ();
}
}
?
?php
// process.php - process the stuff
$progress = new Progress();
$progress-start();
// ... Do your processing here ...
$progress-end('nextpage.php');
?
In the progress.html file, it would just be an html page that has an animated
gif (and whatever else you want on it). Hope this helps.
~Philip
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Re: [PHP-DB] Random pick
On Dec 15, 2009, at 6:02 PM, David McGlone wrote:
On Monday 14 December 2009 21:44:24 Chris wrote:
Chris wrote:
David McGlone wrote:
On Monday 14 December 2009 21:02:37 Chris wrote:
David McGlone wrote:
Hi everyone,
I've been lurking in the shadows on the list for quite some time and
now
I'm in need of a little info or advise.
I'm looking for a way to grab a record out of a database on a
certain day
each month and I'm wondering if this can be accomplished with just a
mysql query or would I need to use PHP also?
A mysql query would do it but you'd use something to talk to mysql and
process the results (whether it's php, perl, python, ruby etc depends
on your other requirements).
What I'm trying to do is to have a record picked from the database at
random on the 1st of every month and display it on the page. Here is
some code I have been working with:
$query = SELECT DATEADD(mm, DATEDIFF(mm,0,getdate()), 0);
$result = @mysql_query($query);
if (!$result){
$query = SELECT * FROM monthlyPooch ORDER BY RAND() LIMIT 1;
$result = @mysql_query($query);
while ($row = mysql_fetch_array($result)){
echo $row[poochName] ;
echo $row[Birthdate];
}
}
You can check the day of the month in php then do your other query:
$today = date('j');
See http://php.net/date for date formats and what they return.
if ($today !== 1) {
echo Today isn't the first. No need to continue.\n;
exit;
}
..
random query etc here.
Hmmm. This isn't exactly what I'm looking for. What I'm trying to do is get a
new picture on the 1st of every month and display it for that whole month.
Could you not just create a mysql table that contains the month and a url to a
file?
?php
// image.php
$currentMonth = date('n');
$sql = SELECT `image_location` FROM `monthly_images` WHERE `month` =
$currentMonth LIMIT 1;
$result = mysql_query($sql);
list ($loc) = mysql_result ($result);
header (Content-type: image/png);
readfile ($loc);
exit;
?
And then in your HTML:
img src=image.php alt=MonthlyImage title=Yay for me! /
I just wrote that code here in the email, but it should get you going in the
right direction. Hope that helps!
~Philip
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[PHP-DB] Group by
Hi. In a mysql query, it is recommended that GROUP BY fields be indexed? Using EXPLAIN on one of my queries, I noticed no change between having indexed by GROUP BY field and not indexing it. Any thoughts would be appreciated. In this example, should `history_field` be indexed...? SELECT MAX(`timestamp`) AS `max_ts` FROM `history` WHERE `req_id` = 17 AND `history_record_id` = 35 GROUP BY `history_field` Thanks, ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Group by
On Dec 9, 2009, at 12:58 PM, h...@deweywilliams.com wrote:
The only SELECT is on MAX('timestamp'). There is really nothing to Group BY
in this query.
Dewey
Philip Thompson wrote:
Hi.
In a mysql query, it is recommended that GROUP BY fields be indexed? Using
EXPLAIN on one of my queries, I noticed no change between having indexed by
GROUP BY field and not indexing it. Any thoughts would be appreciated.
In this example, should `history_field` be indexed...?
SELECT MAX(`timestamp`) AS `max_ts` FROM `history` WHERE `req_id` = 17 AND
`history_record_id` = 35
GROUP BY `history_field`
Thanks,
~Philip
Well, that was just an example query. My real one is
SELECT `h`.*
FROM (
SELECT MAX(`history_timestamp`) AS `max_ts`
FROM `history`
WHERE `req_id` = 17 AND `history_record_id` = 35
GROUP BY `history_field`
) AS `max`
INNER JOIN `history` `h` ON `max`.`max_ts` = `h`.`history_timestamp`
WHERE `req_id` = 17 AND `history_record_id` = 35
GROUP BY `history_field`
This returns the results I need. The explain (split up) from this query is...
++-++--++
| id | select_type | table | type | possible_keys
|
++-++--++
| 1 | PRIMARY | h | ref |
req_id_history_record_id,history_timestamp |
| 1 | PRIMARY | derived2 | ALL | NULL
|
| 2 | DERIVED | history| ref | req_id_history_record_id
|
++-++--++
--+-+-+--+--+
key | key_len | ref | rows | Extra
|
--+-+-+--+--+
req_id_history_record_id | 8 | const,const |3 | Using temporary;
Using filesort |
NULL | NULL| NULL|2 | Using where
|
req_id_history_record_id | 8 | |3 | Using where; Using
temporary; Using filesort |
--+-+-+--+--+
3 rows in set (0.01 sec)
There's only 10 records in table right now... but the # of rows it's going to
traverse before find the results is very small.
Do I need to include `history_field` in the inner select?
Thanks,
~Philip
[PHP-DB] Multiple MySQL schemas
Hi all. We are wanting to create an app that contains multiple clients. Each clients has anywhere from 1 user to more than a hundred. We had the idea of separating each client into its own database schema. This reduces the single point of failure - if 1 client db dies, it doesn't kill the others. This keeps the individual schemas smaller, which will allow us to asynchronously (for lack of a better word) transfer our backups to our network w/o causing bottlenecks. It also guarantees the separation of data (even though the application takes care of this, it's *that extra step*). Is it reasonable to create a new database per client? Or should we cluster several clients together (5-10) into a single database? What are the pros and cons of each? Note that some clients are *linked* and share data, so those would not be mutually exclusive. What is the maximum number of schemas per MySQL instance - I'm guessing this is based on the filesystem (RHEL)? Thanks in advance, ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Doc to PDF with mssql
On Nov 4, 2009, at 4:00 PM, Chris wrote: Chris wrote: Rafael Costa Pimenta wrote: But the link http://doc2pdf.sourceforge.net/overview.html seems to use e-mail, i did not understand, I just want to extract a word .doc file from the mssql database, save in a temp directory, convert to the PDF format and let the user download the PDF file. There's a lot of stuff in there. Concentrate on each part separately and don't worry about the next part just yet. try http://www.phplivedocx.org/2009/02/06/convert-doc-to-pdf-in- php/ for changing your doc to a pdf. To get a doc in/out of mssql, there seems to be some magic you have to do: http://www.webdeveloper.com/forum/archive/index.php/t-213799.html If they don't work you're going to have to be more specific about what you're having problems with. See also http://www.rochester.edu/it/web/WebHelp/mssql/datatypes.html Could you not just encode the doc file before putting it in the database. Decode it when you get it out. http://php.net/base64_encode http://php.net/base64_decode Hope that helps. ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] SELECT LIKE with % and without %
On May 2, 2009, at 6:43 PM, Emiliano Boragina wrote: Hello. I am using this: $sql = SELECT * FROM table WHERE ID LIKE '%$_GET[id]%' AND title LIKE '%$_GET[word]%'; But I want exactlu ID, not one part of many possibles Ids in the DB. How can I do that? PLEASE tell me your cleaning that input... http://php.net/mysql_real_escape_string And to answer your question: ?php $id = mysql_real_escape_string ($_GET['id']); $word = mysql_real_escape_string ($_GET['word']); $sql = SELECT * FROM `table` WHERE `ID` = '$id' AND `title` = '$word'; ? Read more on MySQL's LIKE functionality. Google can help you. HTH, ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Question about databases and foreign keys
On Sep 15, 2008, at 10:03 AM, Jason Pruim wrote: On Sep 15, 2008, at 10:59 AM, Micah Gersten wrote: Use 2 tables. You never know what the app might grow into and you should do it right the first time. That's what I was thinking too... Just wanted to hear it from someone else... NOW I get to learn about foreign keys and how to update things with them! So if anyone knows of a good resource I'd appreciate it... Until then, I'm off to search the web and figure this stuff out! I'm sure Google will probably be your best resource for what you need to find out. ;) I'll throw this out there though. When dealing with foreign keys and multiple tables, remember to index appropriately. For example: Table `users`: user_id int(10) primary key -- other fields here -- clock_id int(10) Table `clocking`: clock_id int(10) primary key clock_in int(10) clock_out int(10) In table `clocking`, clock_id is already indexed because it's primary. Be sure to index clock_id in `users` so that when you join on the two, you'll have optimal speed! ALTER TABLE `users` ADD INDEX (`clock_id`); And an example query... SELECT `u`.`user_id`, `c`.`clock_in`, `c`.`clock_out` FROM `users` `u` INNER JOIN `clocking` `c` ON `u`.`clock_id` = `c`.`clock_id` WHERE (`u`.`user_id` = '$user_id' AND `c`.`clock_in` 'sometime' AND `c`.`clock_out` 'someothertime'); Something along those lines. I always find it useful to have unique names throughout the database, so if you reference a name, you know where it originated. Because of this, I can just look at `users` and determine that `clock_id` is a foreign key. Hope that helps a little! ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Question about databases and foreign keys
On Sep 15, 2008, at 2:12 PM, Micah Gersten wrote: You'll actually want to have the User Id in the clocking table, not the other way around. User Id is the foreign key because it has a many to one relationship with the time logging. Thank you, Micah Gersten onShore Networks Internal Developer http://www.onshore.com Yes, I agree with that. That was just a quick example that I whipped up (and obviously didn't think enough about). ;) So, follow Micah's advice, people. =D ~Philip Philip Thompson wrote: I'll throw this out there though. When dealing with foreign keys and multiple tables, remember to index appropriately. For example: Table `users`: user_id int(10) primary key -- other fields here -- clock_id int(10) Table `clocking`: clock_id int(10) primary key clock_in int(10) clock_out int(10) In table `clocking`, clock_id is already indexed because it's primary. Be sure to index clock_id in `users` so that when you join on the two, you'll have optimal speed! ALTER TABLE `users` ADD INDEX (`clock_id`); And an example query... SELECT `u`.`user_id`, `c`.`clock_in`, `c`.`clock_out` FROM `users` `u` INNER JOIN `clocking` `c` ON `u`.`clock_id` = `c`.`clock_id` WHERE (`u`.`user_id` = '$user_id' AND `c`.`clock_in` 'sometime' AND `c`.`clock_out` 'someothertime'); Something along those lines. I always find it useful to have unique names throughout the database, so if you reference a name, you know where it originated. Because of this, I can just look at `users` and determine that `clock_id` is a foreign key. Hope that helps a little! ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php innerHTML is a string. The DOM is not a string, it's a hierarchal object structure. Shoving a string into an object is impure and similar to wrapping a spaghetti noodle around an orange and calling it lunch. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] PDO prepared statements and value list for MySQL IN
On Jul 8, 2008, at 11:55 AM, TK wrote:
I'd like to use a PDO prepared statement to perform a MySQL query
that uses the IN function.
I.e.:
$stmt = $pdo-prepare('
select *
from mytable
where myfield IN (:contents)
);
$stmt-bindValue(':contents', $contents);
$stmt-execute();
Here's the problem:
If $contents is set to a single value, everything's fine:
$contents = 'mystring';
How can I include multiple values in here? If $contents is set to
an array, PHP throws an Array to string conversion notice.
i.e. $contents = array('mystring1', 'mystring2');
If $contents is set to a comma-separated list, no matches are
returned (probably because the entire list is being passed to
MySQL as a single value, not multiple values).
I.e. $contents = 'mystring1,mystring2';
What's the proper way to do this? Can it be done? (Note that I do
not know how many elements will be in $contents ahead of time, so
something like IN (:contents1, :contents2) wouldn't make sense.)
Thanks for any help!
- TK
$contents = array('string1', 'string2', 'string3');
$ins = implode (',', $contents);
$sql = SELECT * FROM `table` WHERE `field` IN ($ins);
I'm not sure if the IN function only works on numeric values or if it
also works on strings as well. If contents contains strings, you may
need to put single quotes around each item. If so, change the above
to.
$ins = ' . implode (',', $contents) . ';
Hope that helps,
~Philip
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[PHP-DB] SELECT FOR UPDATE
Hi all. Which is more efficient in order to use SELECT FOR UPDATE? % SELECT * FROM `table` WHERE (`table_id` = 32) LIMIT 1 FOR UPDATE; % UPDATE `table` SET `field_name` = 'Pizza' WHERE (`table_id` = 32) LIMIT 1; OR % SELECT `field_name` FROM `table` WHERE (`table_id` = 32) LIMIT 1 FOR UPDATE; % UPDATE `table` SET `field_name` = 'Pizza' WHERE (`table_id` = 32) LIMIT 1; Note: the 2nd query in each is the same. Is there any difference in using * and specifying the actual field you want to update? It seems like there would be very little difference because this is causing a row-lock - all the data in that row is not-updatable anyway. I'm adding transactions and row-locking into my application. If I can just use the first method (because it's easier to specify '*' instead of every column I want to update), then I'd like to. Any thoughts are welcome! Thanks in advance, ~Philip Personally, most of my web applications do not have to factor 13.7 billion years of space drift in to the calculations, so PHP's rand function has been great for me... ~S. Johnson -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Timestamps
On May 2, 2008, at 8:00 AM, Jason Pruim wrote: On May 1, 2008, at 8:31 PM, Chris wrote: PS... Was it you, Jason, or someone else who asked about the security of the community knowing their database structure and I encouraged the use of `backticks` around all field and table names? Yeah it was me... Old habits die hard :) I'm working on converting everything :) A little caveat with that: 1) it's mysql specific Currently the system is just running on my server, and probably always will... so I'm not too worried about it being mysql specific. So is the query (mysql-specific). If you change to another *SQL, then you'll probably have to change the query anyway, so the backticks are not the biggest issue and they'll help you in the meantime. 2) I can disable you using backticks http://www.php.net/manual/en/language.operators.execution.php I'll have to take a look at that and see what it says in a little bit. As you mentioned Chris, the backticks are in a string, so there's not a security risk in this method. ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Timestamps
On May 1, 2008, at 7:56 AM, Jason Pruim wrote: On Apr 30, 2008, at 5:03 PM, Philip Thompson wrote: On Apr 30, 2008, at 10:54 AM, Jason Pruim wrote: Hi Yves, Thanks for the tip, that worked, I think I'll use that from now on.. Just out of curiosity though, any idea why it wasn't working as I was writing it :) Did you try putting the query that PHP is generating in phpMyAdmin or MySQL Query Browser? See if it throws an error when attempting to update. It *appears* that the query should work. No I haven't, I don't have phpMyAdmin installed since I do it all from the command line, and I don't pay for hosting yet... But I am going to need to change that. I don't believe I have heard about MySQL Query Browser though... Is it a webapp? Or do I need to install it on my local computer? Query Browser is part of the MySQL GUI tools. You can download them here and use on your local computer: http://dev.mysql.com/downloads/gui-tools/5.0.html However, if you're using command line, then that should provide the same error messages (if any) that may assist you. ~Philip PS... Was it you, Jason, or someone else who asked about the security of the community knowing their database structure and I encouraged the use of `backticks` around all field and table names? Yeah it was me... Old habits die hard :) I'm working on converting everything :) On Apr 30, 2008, at 11:47 AM, YVES SUCAET wrote: Hi Jason, It's not because you create a date/time value that you automatically have an integer-value. You need to specify first that you want the date/ time value converted to an integer value first. See http://dev.mysql.com/doc/refman/5.0/en/date-and-time-functions.html#function_unix-timestamp for an example of how to do this. Actually, by using this function, you probably don't even need to create the $modifiedTimestamp variable anymore. You can just write your SQL query as follows: $sql = Update `mytable` set timestamp=UNIX_TIMESTAMP() where Record='1'; HTH, Yves -- Original Message -- Received: Wed, 30 Apr 2008 10:39:11 AM CDT From: Jason Pruim [EMAIL PROTECTED] To: Stut [EMAIL PROTECTED]Cc: php-db@lists.php.net Subject: Re: [PHP-DB] Timestamps On Apr 30, 2008, at 11:35 AM, Stut wrote: On 30 Apr 2008, at 16:29, Jason Pruim wrote: Okay... So I know this should be simple... Trying to store a timestamp in a MySQL database... The timestamp I am making like so: $modifiedTimestamp = time(); and then just $sql = Update `mytable` set timestamp='$modifiedTimestamp' where Record='1'; Simple right? Not quite...in my database it's storing a 0 in the timestamp field which is a int(10) field. I have googled, and searched manuals, but have not been able to figure out what is going on Any Ideas? timestamp is a reserved word. Try putting it in backticks. Okay, so I did a really crappy job at my sudo code... The field name is actually Last_Updated. so my update code looks like this: Last_Updated='$modifiedTimestamp' *Slaps his wrist... Bad copy/paste! BAD!!! -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Timestamps
On Apr 30, 2008, at 10:54 AM, Jason Pruim wrote: Hi Yves, Thanks for the tip, that worked, I think I'll use that from now on.. Just out of curiosity though, any idea why it wasn't working as I was writing it :) Did you try putting the query that PHP is generating in phpMyAdmin or MySQL Query Browser? See if it throws an error when attempting to update. It *appears* that the query should work. ~Philip PS... Was it you, Jason, or someone else who asked about the security of the community knowing their database structure and I encouraged the use of `backticks` around all field and table names? On Apr 30, 2008, at 11:47 AM, YVES SUCAET wrote: Hi Jason, It's not because you create a date/time value that you automatically have an integer-value. You need to specify first that you want the date/ time value converted to an integer value first. See http://dev.mysql.com/doc/refman/5.0/en/date-and-time-functions.html#function_unix-timestamp for an example of how to do this. Actually, by using this function, you probably don't even need to create the $modifiedTimestamp variable anymore. You can just write your SQL query as follows: $sql = Update `mytable` set timestamp=UNIX_TIMESTAMP() where Record='1'; HTH, Yves -- Original Message -- Received: Wed, 30 Apr 2008 10:39:11 AM CDT From: Jason Pruim [EMAIL PROTECTED] To: Stut [EMAIL PROTECTED]Cc: php-db@lists.php.net Subject: Re: [PHP-DB] Timestamps On Apr 30, 2008, at 11:35 AM, Stut wrote: On 30 Apr 2008, at 16:29, Jason Pruim wrote: Okay... So I know this should be simple... Trying to store a timestamp in a MySQL database... The timestamp I am making like so: $modifiedTimestamp = time(); and then just $sql = Update `mytable` set timestamp='$modifiedTimestamp' where Record='1'; Simple right? Not quite...in my database it's storing a 0 in the timestamp field which is a int(10) field. I have googled, and searched manuals, but have not been able to figure out what is going on Any Ideas? timestamp is a reserved word. Try putting it in backticks. Okay, so I did a really crappy job at my sudo code... The field name is actually Last_Updated. so my update code looks like this: Last_Updated='$modifiedTimestamp' *Slaps his wrist... Bad copy/paste! BAD!!! -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] playing longblob media
On Apr 28, 2008, at 12:49 AM, Chris wrote: Philip Thompson wrote: On Apr 27, 2008, at 9:15 AM, Ron wrote: Hi, How can i retrieve via php a media stored in a mysql database as longblob? I'd like to be able to retrieve the media and stream it. TIA regards, ron Just like any other field type. Doesn't matter to PHP what the field type is... But it does to the browser. You'll need to send the appropriate headers for the browser to do the right thing, and since it's probably a big field instead of saving it to a variable, just echo it out. No idea what the right headers are though :) I understand that the headers are important. However, that was not the question. The question asked how to retrieve data from a mysql database using PHP. I answered that question... ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] playing longblob media
On Apr 28, 2008, at 9:22 AM, Ron wrote: hi yves, not sure how large the file is, but i'm assuming a caller would not leave a voicemail longer than a minute. max maybe 30 secs. is there a query to get the size of a data in a certain row/column? thank you regards ron Assuming you're storing the data as binary, you *should* be able to do a strlen() on the output to get the *file* size. ~Philip Yves Sucaet wrote: So how large is the file/BLOB? How many seconds/minutes of data does it contain? The previous author was right: you can retrieve BLOB fields just like any other fields. The problem is sending them back to the client. Yves - Original Message - From: Ron [EMAIL PROTECTED] To: php-db@lists.php.net Sent: Sunday, April 27, 2008 10:02 PM Subject: Re: [PHP-DB] playing longblob media i'm trying to play a WAV file, this file is a voicemail file generated by asterisk pbx. it is stored in mysql and i would like users to be able to check their voicemail via web using php script that will retrieve it from the db as a wav format already. thank you Yves Sucaet wrote: What kind of media are you trying to retrieve? Are you trying to retrieve the MySQL data and stream that through your script to the client? How big is the BLOB? If nothing else, you'll need to adapt the MIME-type in the header of your HTTP-message. HTH, Yves - Original Message - From: Ron [EMAIL PROTECTED] To: php-db@lists.php.net Sent: Sunday, April 27, 2008 9:15 AM Subject: [PHP-DB] playing longblob media Hi, How can i retrieve via php a media stored in a mysql database as longblob? I'd like to be able to retrieve the media and stream it. TIA regards, ron -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Personally, most of my web applications do not have to factor 13.7 billion years of space drift in to the calculations, so PHP's rand function has been great for me... ~S. Johnson -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] playing longblob media
On Apr 27, 2008, at 9:15 AM, Ron wrote:
Hi,
How can i retrieve via php a media stored in a mysql database as
longblob?
I'd like to be able to retrieve the media and stream it.
TIA
regards,
ron
Just like any other field type. Doesn't matter to PHP what the field
type is...
?php
$sql = SELECT `longblob_fieldname` FROM `table` WHERE (`id` = '$id')
LIMIT 1;
$result = mysql_query ($sql);
if (mysql_num_rows ($result)) {
$contents = mysql_result ($result, 0);
}
?
~Philip
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[PHP-DB] UPPER(AES_DECRYPT(...)) bug?
Hi all.
Here's my disclaimer: this question is solely MySQL-related - I just
happen to be programming in PHP.
I have found some functionality which *appears* to be a bug, but I
didn't want to report it before asking some intelligent people. I have
this simple query:
SELECT UPPER('just a lower case string') AS `UPPER_STRING`,
UPPER(AES_DECRYPT(AES_ENCRYPT('Bob Frapples', '1234ABCD'),
'1234ABCD')) AS `UPPER_NAME`;
Expected result:
UPPER_STRING UPPER_NAME
JUST A LOWER CASE STRING BOB FRAPPLES
Real result:
UPPER_STRING UPPER_NAME
JUST A LOWER CASE STRING Bob Frapples
There is a similar bug report http://bugs.mysql.com/bug.php?id=28072
that uses LCASE instead of UPPER. But, they have the same *lack of
desired functionality*. MySQL people say it's not a bug due to how
binary blah blah blah. Whatever - I don't buy that. It's not working
*as it should*. On top of that, the docs for this encrypt stuff is
quite minimal.
My questions to you: do you think this is a bug? And... is there an
alternative to searching on fields that are encrypted using the LIKE
operator?
Thanks,
~Philip
Personally, most of my web applications do not have to factor 13.7
billion years of space drift in to the calculations, so PHP's rand
function has been great for me... ~S. Johnson
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[PHP-DB] mssql_connect issues
Hi all. I have worked with a MySQL database a whole lot, but never really an MS SQL database before. Here's the problem I'm having. I call this function and then nothing else happens. No other information shows up on the page. $link = mssql_connect(myServer, me, pw); Of course, I replace the values here with the real ones, but nothing happens. I know the database exists b/c I am looking at it right now. If I echo something to the screen before this call, then it shows. If I echo something after, it does not show. If I add or die (...) after the function call, it does not show. I'm kinda lost on what it could be at this point. I have commented out everything else that it could potentially be so that I know it's this line. I get no error message... I just get nothing. Any thoughts? Thanks in advance, ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] mssql_connect
Hi again all! Right after I sent the email... I think I figured out what it was! I do not have it `uncommented` in my php.ini file! Therefore, none of the mssql_* functions would work. Sorry for that last email. ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Aliased mysql queries and mysql_fetch_array()
Hi all.
I am having a problem obtaining the specific information I need. I have
a table of people that can have multiple rows - ie, Director,
Manager, etc. However, in the projects table, each project has a
director AND manager, but not necessarily the same person.
I have the query to pull the information - and I know it works for
everything else. Now how do I reference the director/manager to store
it in a variable without having to use numerical indexing?
$query = select projects.*, locations.*, funding.*, people.* from
people as people_1 RIGHT JOIN .
(people RIGHT JOIN (funding RIGHT JOIN (locations RIGHT JOIN
projects on locations.id = .
projects.location_id) on funding.id = projects.funding_id) on
people.id = projects.manager_id) on .
people_1.id = projects.director_id $whereCondition order by
$criteria;
$result = @mysql_query($query, $link);
$i = 0;
while ($row = mysql_fetch_array($result, MYSQL_BOTH)) {
// there are much more fields, but I have only included the
// two important ones (manager and director)
$_SESSION[manager][$i] = $row[first_name] . .
$row[last_name];
$_SESSION[director][$i] = $row[people_1.first_name] . .
$row[people_1.last_name];
$i++;
}
It does not work whenever I include the table within the $row[].
Otherwise, it shouldn't be a problem. Any suggestions?
Thanks in advance,
~Philip
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Re: [PHP-DB] mysql_query
On Oct 12, 2004, at 7:15 AM, [EMAIL PROTECTED] wrote:
hello,
I have a begining question.
I've got simple html form and php script, but insert doesn' t work.
What is
wrong in my insert mysql_query?
mysql_query( insert into obiskovalci (ime, priimek, ulica, hstevilka,
pstevilka, posta) values('$ime', '$priimek', '$ulica', '$hstevilka',
'$pstevilka', '$posta'));
There's a little more you need. First you have to use the connection
you should have already opened up:
$link = mysql_connect('some_db', 'some_user', 'some_pw');
Then you have to include the `link` whenever you do a query:
mysql_query(your query, $link);
If I recall, you may not actually have to include the link every single
time if you have already established which one you're using... but it's
always safe to specify which one you're using. Maybe someone can
clarify on this.
There is also id, which is auto_increment. After fill form and press
Submit, id
is writen in table, but there is no other inputs. Nothing, except id.
Yes, consider using the $_POST[some_variable] to obtain the values.
thanks for answers
BR, Balo
Hope this helped a tiny bit.
~Philip
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[PHP-DB] Setting a timed-session
Hi all. This may be a bit elementary, however, I am confused on the functionality of it. I am wanting to create a session that logs out after a certain amount of time, no matter if the user is doing something or not. I have used the function `set_time_limit()`, but I don't know if I'm using it properly. What I do is whenever a certain page is accessed, I call that function. I tested it with 10 seconds, but nothing seemed to happen. Is it supposed to kill the session and all of the $_SESSION variables? Or what exactly is it supposed to do? I looked on the php site, but I'm still a bit baffled? Any insight? http://us4.php.net/function.set-time-limit Thanks in advance, ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] ip address
balwant, It seems to be working for me. I have looked at it from multiple computers, and it always gives the ip of that computer. Try for yourself: http://housing.uark.edu/resnet/ip.php Let me know if you get something other than your ip. ~Philip balwantsingh wrote: i tried the $_SERVER['REMOTE_ADDR'] it is giving ip address of server which is hosting the webpage not the user's ip address. pls. suggest how can IP address of an user can be obtained. with best wishes balwant -Original Message- From: Philip Thompson [mailto:[EMAIL PROTECTED] Sent: Thursday, September 30, 2004 3:45 AM To: [EMAIL PROTECTED] Subject: [PHP-DB] Re: getenv() alternative Oh, before I get a slew of emails about this one, I think I figured it out: $_SERVER['REMOTE_ADDR'] I knew it couldn't have been that difficult... brain fart! Sorry for wasting your time. ~Philip On Sep 29, 2004, at 5:02 PM, Philip Thompson wrote: Hi all. I am needing to obtain the IP address of a user who logs into the system. I tried to use `getenv(REMOTE_ADDR)`, however, this function does not work in ISAPI mode, which is what I am running. Is there an alternative to obtaining the IP address? I have looked around, but I cannot seem to find anything. Thanks in advance, ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] ip address
Ramil, On Sep 30, 2004, at 1:17 AM, Ramil Sagum wrote: On Thu, 30 Sep 2004 11:00:35 +0530, balwantsingh [EMAIL PROTECTED] wrote: i tried the $_SERVER['REMOTE_ADDR'] it is giving ip address of server which is hosting the webpage not the user's ip address. pls. suggest how can IP address of an user can be obtained. what exactly did you do? the following script works: === htmlbody Your IP Address is : ?php echo $_SERVER[REMOTE_ADDR]; ? /body/html === ramil Yes, that's what I did (with a tad bit of error-testing), and it seems to work fine for me. ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] getenv() alternative
Hi all. I am needing to obtain the IP address of a user who logs into the system. I tried to use `getenv(REMOTE_ADDR)`, however, this function does not work in ISAPI mode, which is what I am running. Is there an alternative to obtaining the IP address? I have looked around, but I cannot seem to find anything. Thanks in advance, ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: getenv() alternative
Oh, before I get a slew of emails about this one, I think I figured it out: $_SERVER['REMOTE_ADDR'] I knew it couldn't have been that difficult... brain fart! Sorry for wasting your time. ~Philip On Sep 29, 2004, at 5:02 PM, Philip Thompson wrote: Hi all. I am needing to obtain the IP address of a user who logs into the system. I tried to use `getenv(REMOTE_ADDR)`, however, this function does not work in ISAPI mode, which is what I am running. Is there an alternative to obtaining the IP address? I have looked around, but I cannot seem to find anything. Thanks in advance, ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Using sessions to gather visitor information
Hi.
On Sep 15, 2004, at 6:55 AM, Vincent Jordan wrote:
I am trying to track the users that visit one page on a site. I am
having a
couple of problems. The time seems to be 5 hours off. I do not have any
tables as of yet what I would like to do is only count an ip address
as one
in a 24 hour period, if more than one visit then update visit count.I
have
played around with the time using date() and localtime(). Here is
what I
have sofar.
ini_set('display_errors',1);
error_reporting(E_ALL ~E_NOTICE);
session_start();
$_SESSION['ip_address'] = $IP;
$_SESSION['user_agent'] = $Browser;
$_SESSION['host_name'] = $Host;
$_SESSION['visit_time'] = $now;
$now = localtime();
$now = $now[2] . : . $now[1] . : . $now[0];
$IP = getenv(REMOTE_ADDR);
$Browser = $_SERVER['HTTP_USER_AGENT'];
$Host = getHostByName($IP);
I have not setup tables yet but I think I will use this:
vid init(5) not null auto_incriment
ip varchar(25) null
agent varchar(100) null
host varchar(100) null
time varchar(10) nul
visitcount int(100) null
when a visitor loads the page I can run this
mysql_query(SELECT ip, time FROM tablename where
ip=$_SESSION['ip_address']
and time=$_SESSION['visit_time'])
I would like to query if $_SESSION['ip_address'] has visited in less
then 24
hours then kill session and close mysql connection. If last visit was
more
than 24 hours update time and add +1 to visitcount. If new visit add to
table.
Once all done how can I properly clean up the session. I have tried the
following bur get an error
unset($_SESSION);
session_destroy();
I tried this with a link to another page and got this error:
Warning: session_destroy(): Trying to destroy uninitialized session in
/home/content/html/killtest.php on line 5
I assume I forgot something.
Any help would be appreciated.
You might make sure that on the page where it says session_destroy();
that you have actually carried the session over. Meaning, if it's on a
different page than you originally started the session, make sure you
include session_start(); at the beginning of that next page.
Also, something you might want to try is first testing to see if the
session is set.
if (session_id())
session_destroy();
That part doesn't really help your specific situation (as far as
destroying the session), but I think it's good practice and will not
give an error message if your session has not been started yet and you
try to destroy it.
Hope this helps you some.
~Philip
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Re: [PHP-DB] Insert Query PROBLEMS
Aaron,
I agree with what Mark said. But I just want to say what I noticed off
hand...
On Sep 10, 2004, at 11:13 AM, Aaron Todd wrote:
I'm trying to run an INSERT query on my mysql database and it isnt
working.
Here is the query:
$updatequery = UPDATE `users`
SET
('company','fname','lname','address1','address2','city','state','zip','
phone','extension','fax','email')
When I do an UPDATE and refer to these columns, I do not include the
single quotes (or tick marks) around my fields, and it works fine. But
like Mark said, cleaning it up (1 per line) might also help - that's
just personal preference.
~Philip
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Re: [PHP-DB] mysq query without subselects
Blackwater, On Sep 10, 2004, at 12:39 PM, blackwater dev wrote: Hello, I need to grab the max value of all of the data in a table grabbing the max total for each client. Example. T1 idtotal clientid 1 100 111 2 200 111 3 100 112 4 150 112 I need a query that will grab the highest total per clientid (200, and 150) then average them. My first inclination is to do a subselect select avg(total) from t1 where t1.total=(select max(total) from t1 t2 where t2.clientid=t1.clientid) But can't use subselects with mysqlhow do I do it?? Yes you can. Check this out and see if all your syntax is correct. http://dev.mysql.com/doc/mysql/en/Subqueries.html ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Please help
I think everyone knows that $sql is a statement. But what people are asking is: what is that statement?! Because if there are incorrect characters or 's in that statement, then that can break your code/statement. ~Philip On Sep 9, 2004, at 5:49 PM, Stuart Felenstein wrote: Just getting back to this thing. There are 3 files involved, search.php, connections.php and functions.php. I searched through all and couldn't find the meaning of the $sql_ext. $sql is just the sql statement I inserted into the code. Great that I can't get a response from the company. If anyone thinks it would be useful to post the code I will. That is if anyone would want to see and look at it. The weird thing is searching on one table is great. The list (all records) works great. The problem starts when I insert all my joins. Now I've tested and retested the query and I know it's fine. Thank you , Stuart --- Steve Davies [EMAIL PROTECTED] wrote: What's contained in $sql and $sql_ext ??? Stuart Felenstein wrote: I'm using a product called dbqwiksite pro. PHP generator for PHP - MySQL The code seems to be working fine except in my search page where I receive an invalid query $result = mysql_query($sql . . $sql_ext . limit 0,1) or die(Invalid query); This is the place I where the code is taking the die path. I'm guessing something belongs between the quotation marks , just not sure. Anyone ? Thank you Stuart -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] functions via event handlers
Yemi, On Sep 6, 2004, at 7:14 AM, Yemi Obembe wrote: i'd just luv to ask if it is possibble to call a function in PHP by using event handlers (like onmouseover, onload) as done in javascript? if its possible, i'd appreciate someone to tutor me on it. As far as I know, this is not possible. Since PHP is server-side scripting (not client-side like JavaScript), all the code-processing is done before it ever reaches the client's computer. Because of this, you will never be able to use the code via event handlers. If anyone knows something different, please let me and Yemi know. ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Passing variables from HTML to PHP
Hi all. This might be a simple answer, but I'm still not sure what the case is. Okay, so I have a form in my html that has some inputs. These each have a `name` and a `value` attribute to them, of course. I cannot seem to access the name/value pair in my php without using the $_POST method/variable names. Are you able to without $_POST? Example: --- html: input type=checkbox name=foo value=bar php: do this: echo foo = . $foo; // foo = bar or this: echo foo = . $_POST[foo]; // foo = bar --- So, should both of those php examples work the same? Thanks! ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Re: Passing variables from HTML to PHP
Thanks for your reply. Those who have responded, I am thankful to. ~Philip On Aug 31, 2004, at 4:14 PM, Jasper Howard wrote: if the checkbox is checked then you'll get the value in the php script. If globals are turned on then echo $foo; will work, otherwise you have to use something like: echo $_POST['foo']; its a good idea to write your scripts without dependency on globals being turned on, its a security risk for it to be on. -- -- Jasper Howard :: Database Administration Velocity7 1.530.470.9292 http://www.Velocity7.com/ -- Philip Thompson [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] Hi all. This might be a simple answer, but I'm still not sure what the case is. Okay, so I have a form in my html that has some inputs. These each have a `name` and a `value` attribute to them, of course. I cannot seem to access the name/value pair in my php without using the $_POST method/variable names. Are you able to without $_POST? Example: --- html: input type=checkbox name=foo value=bar php: do this: echo foo = . $foo; // foo = bar or this: echo foo = . $_POST[foo]; // foo = bar --- So, should both of those php examples work the same? Thanks! ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Webpage response to selection $_POST
Peter,
On Aug 30, 2004, at 12:49 PM, Peter Ellis wrote:
It doesn't look like you're actually retrieving data using the $_POSTed
data from that code snippet. Are you doing anything like $j = $_POST
['j']; in order to get the value of j before you retrieve your array
data? Or are you allowing PHP to declare $_POST variables globally?
Yes, I tried setting the $_POST information to a variable, but that
does not work either. I think I am allowing PHP to declare them
globally... how is that done exactly?
The reason you need brackets is because brackets are always used in the
declaration of a user array, assuming that this is what you want. If
you don't want an array, than your original code was correct -- []
always signals an array type to PHP.
--
Peter Ellis - [EMAIL PROTECTED]
Web Design and Development Consultant
naturalaxis | http://www.naturalaxis.com/
Do you recommend I use an array over a lot of variables? I can use
either or - there was no particular reason why I chose a single
variable.
Thanks,
~Philip
On Mon, 2004-08-30 at 11:02 -0500, Philip Thompson wrote:
Peter,
On Aug 29, 2004, at 6:26 PM, Peter Lovatt wrote:
Hi
you need to check for $_POST[user1], $_POST[user2] etc - is that
what
you are doing?
Yes, this is how I am checking the post variables.
Your other variables are done as an array - $firstName[$j] etc,
should
your
check box be
echo ' tdinput type=checkbox name=user[' . $j . ']
value=1/td' . \n;
(note the [])
Why do you have to have the []'s? I did add those, but it didn't seem
to help.
Otherwise try vardump($_POST) to see exactly what is being returned.
I also tried the vardump($_POST), and it did not seem to return
anything. I did not find anything about vardump() on the php site...
besides some non-built in function. Any more thoughts on using it?
If this does not fix it try posting the code that handles the
response
and
we will try and help.
Peter
Ok, quick question. Does the $_POST variable transfer the information
to all the pages? or just the page called in that form
action=apage.php? Because in my code I call a certain page, but
then
that page merely redirects to another page, depending what selection
was made.
The code that uses the $_POST information follows...
~Philip
?php
for ($j=0; $j=$largestDBID; $j++) {
$user = user[ . $j . ];
if ($_POST[$user]) {
echo 'tr' . \n;
echo ' td' . $dbid[$j] . '/td' . \n;
echo ' td' . $firstName[$j] . '/td' . \n;
echo ' td' . $lastName[$j] . '/td' . \n;
echo ' td' . $uid[$j] . '/td' . \n;
echo ' td' . $username[$j] . '/td' . \n;
echo ' td' . $classification[$j] . '/td' . \n;
echo '/tr' . \n;
}
}
?
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[PHP-DB] Webpage response to selection $_POST
Hi all.
I have a list of users in a database that I would like to show on a
dynamic webpage. With each of these users that shows up on the page,
there is going to be a checkbox next to their name so that I can
perform multiple tasks, such as 'Remove User' or 'Modify Information'.
I have all of the appropriate information showing up on the page,
including the checkboxes.
My question is... if I select a checkbox for a user, the other pages do
not even recognize that I have selected that checkbox and I am using
the $_POST method - why is that? I have even attempted to use the
import_request_variables function - no luck. So, I cannot verify which
users I want to perform an action on.
Anyone have any ideas? Snippets of code to follow...
Thanks in advance,
~Philip
form action=performaction.php method=post
table
?php
for ($j=0; $j$numRows; $j++) {
echo 'tr' . \n;
echo ' tdinput type=checkbox name=user' . $j . '
value=1/td' . \n;
echo ' td' . $dbid[$j] . '/td' . \n;
echo ' td' . $firstName[$j] . '/td' . \n;
echo ' td' . $lastName[$j] . '/td' . \n;
echo ' td' . $uid[$j] . '/td' . \n;
echo ' td' . $username[$j] . '/td' . \n;
echo ' td' . $classification[$j] . '/td' . \n;
echo ' /tr' . \n;
}
?
/table
input type=submit name=removeuser value=Remove User /
input type=submit name=modifyclass value=Modify Classification /
input type=hidden name=beenSubmitted value=1 /
/form
[PHP-DB] Enabling LDAP support
Hi again all. Sorry to bug you again. But I thought I would throw this out here again and see if anyone has any input. It would be greatly appreciated. I am running PHP on a Windows 2000 Server, and I need to enable LDAP support. So I have viewed the http://us3.php.net/manual/en/ref.ldap.php page on how to get LDAP running. However, I have run into a snag. I have copied the two required .dlls (libeay32 ssleay32) into the system folder. I also put the configuration option 'ldap.max_links = -1' in my php.ini file. Is there anything else I need to add to the .ini file? I tried uncommenting the extension for php_ldap.dll, thinking that that might make it work... but it didn't. Anyone have any suggestions b/c I'm stuck? Thanks, ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] sendmail
Aaron, On Aug 2, 2004, at 1:31 PM, Aaron Todd wrote: So far, I have been doing ok with PHP. I feel that I have picked it up rather easily. But now I need some help. I am trying to use the sendmail functions to send data entered in a form to my email address. Currently its not working at all. I am getting a Fatal Error: Call to undefined function: sendmail() in /home/virtual/site341/fst/var/www/html/register.php on line 87 You might want to consider using the 'mail()' function instead. It's given at: http://us2.php.net/manual/en/ref.mail.php I use it, and it works perfectly! I havent found very much info on the sendmail function so I was shooting in the dark with it. I did read in the manual some stuff about seting it u in the php.ini file that just went over my head. Can anyone enlighten me on this function. Thanks, Aaron Hope that helps you! ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Enabling LDAP support on Win2k Server
Hi all. I am running PHP on a Windows 2000 Server, and I need to enable LDAP support. So I have viewed the http://us3.php.net/manual/en/ref.ldap.php page on how to get LDAP running. However, I have run into a snag. I have copied the two required .dlls (libeay32 ssleay32) into the system folder. I also put the configuration option 'ldap.max_links = -1' in my php.ini file. Is there anything else I need to add to the .ini file? I tried uncommenting the extension for php_ldap.dll, thinking that that might make it work... but it didn't. Anyone have any suggestions b/c I'm stuck? Thanks, ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Empty query result
Hi all. I am querying a database of single information multiple times using a simple 'select' statement. However, whenever the data in the DB is empty or is 0 (zero), then it throws an error. However, I don't want it to throw an error, I just want it to move on to the next query. This is being shown on a webpage I have. Note that I am using a function for this select statement because I just have to change the identifier that I am looking for - saves space. So I don't use mysql_error() to show my errors, I redirect to a global 'error' page. Is there a way to get around this empty set problem? Yes, I know about using @ to suppress warnings, but it's more than this. Thanks a bunch, ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Empty query result
Pablo,
Hello Philip,
pse.. can you paste the error information?
There is no known empty set problem.
Here's my function:
function getMysqlSelectResultForUsername($identifier, $userName, $link)
{
$queryResult = mysql_query(select $identifier from theTable where
username = '$userName', $link);
if (!($queryResult = mysql_result($queryResult, 0))) {
session_register('_selectIdentifierFromTheTable');
header(location:error.php);
exit;
}
return $queryResult;
}
Here's the code that calls it:
$hall = getMysqlSelectResultForUsername('buildingID', $_userName,
$link);
$roomNum = getMysqlSelectResultForUsername('roomNum', $_userName,
$link);
$phone1 = getMysqlSelectResultForUsername('phone1', $_userName, $link);
$phone2 = getMysqlSelectResultForUsername('phone2', $_userName, $link);
$lastLogin = getMysqlSelectResultForUsername('lastLogin', $_userName,
$link);
If the mysql_result($queryResult, 0) returns zero/nothing, then it goes
to the 'error.php' page. However, I just want it to move on. For
example, if there is no 'phone2' given in the database, I want it to
just assign $phone2 to zero/nothing, not go to the error page.
Hope this helps.
Thanks,
~Philip
--
Best regards,
Pablo
PT Hi all.
PT I am querying a database of single information multiple times
using a
PT simple 'select' statement. However, whenever the data in the DB is
PT empty or is 0 (zero), then it throws an error. However, I don't
want it
PT to throw an error, I just want it to move on to the next query.
PT This is being shown on a webpage I have. Note that I am using a
PT function for this select statement because I just have to change
the
PT identifier that I am looking for - saves space. So I don't use
PT mysql_error() to show my errors, I redirect to a global 'error'
page.
PT Is there a way to get around this empty set problem? Yes, I know
PT about using @ to suppress warnings, but it's more than this.
PT Thanks a bunch,
PT ~Philip
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Re: [PHP-DB] Empty query result
Thanks all! I will try some of the suggestions that you guys gave. I
appreciate it.
~Philip
On Jul 26, 2004, at 12:52 PM, Pablo M. Rivas wrote:
Hello Philip,
read:
http://www.php.net/manual/en/function.mysql-result.php
when you do $queryResult = mysql_result($queryResult,0) you get
the error... so, you can do something like this:
function getMysqlSelectResultForUsername($identifier, $userName,
$link)
{
$queryResult = mysql_query(select $identifier from theTable
where
username = '$userName', $link);
if ($queryResult) {
$queryResult = mysql_result($queryResult, 0);
}
return $queryResult;
}
$hall = getMysqlSelectResultForUserName('buildingID',
$_userName,$link);
if (!$hall) die (error)
or you can do:
function getMySqlSelectResultForUserName($identifier,
$userName,$link) {
return mysql_query(select $identifier from TheTable where
username='$userName',$link);
}
$hall= getMysqlSelectResultForUsername('buildingID', $_userName,
$link);
if (!$hall) die(not found building!!!);
$roomNum = getMysqlSelectResultForUsername('roomNum',
$_userName,$link);
$phone1 = getMysqlSelectResultForUsername('phone1', $_userName,
$link);
$phone2 = getMysqlSelectResultForUsername('phone2', $_userName,
$link);
$lastLogin = getMysqlSelectResultForUsername('lastLogin',
$_userName,$link);
if ((!$roomNum) or (!$phone1) or (!$phone2) or (!$lastLogin)) {
echo data is missing;
} else {
...
}
PT Pablo,
--
Best regards,
Pablo
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Re: [PHP-DB] value error in PHP form
Hi. You left out the 'php' after the '?'. So it should read: ?php print $action; print $Name; ? See if that helps any. ~Philip body form name=frmname input type=text name=Name value=Rinku input type=submit name=action value=Login ? print $action; print $Name; ? /form /body /html -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] delete a record not working
Yeah, you should have a single apostrophe around the $id. So it should
read:
mysql_query(DELETE FROM open_trades WHERE id='$id');
That should do it.
~Philip
On Jun 16, 2004, at 12:04 AM, Justin wrote:
Hello, I have a simple script to retrieve and then delete a selected
script, but it does not work.
When I hit the button I get:
You have an error in your SQL syntax. Check the manual that
corresponds to your MySQL server version for the right syntax to use
near 'id' at line 11064
Any help would be appreciated.
Thanks
form action=? echo $PHP_SELF ? method=post
?php
mysql_pconnect(localhost,root,password);
mysql_select_db(options);
$result = mysql_query(select * from open_trades);
while ($row = mysql_fetch_array($result))
{
print trtd;
print INPUT TYPE='RADIO' NAME='id' VALUE='id';
print /tdtd;
print $row[id];
print /tdtd;
print $row[open_date];
print /tdtd;
print $row[short_long_trade];
print /tdtd;
print $row[expiry];
print /td/tr\n;
}
print /table\n;
?
input type=submit name=submit value=close/form
?php
if($submit)
{
mysql_query(DELETE FROM open_trades WHERE id=$id);
echo Thank you! Information updated.;
echo mysql_error();
echo mysql_errno();
}
?
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Re: [PHP-DB] Re: Erroneous date and time
Have you tried with a insted of A for am/pm indication? Yes, I have tried both 'a' and 'A'. Still gives an incorrect time. ~Philip Hope can help Bye Franciccio Philip Thompson [EMAIL PROTECTED] ha scritto nel messaggio news:[EMAIL PROTECTED] Hi all. Maybe there's something I'm doing incorrectly, but I cannot get the date() function to return the appropriate time. It's always 12 hours off. I've tried using 24-hour time and 12-hour time (with AM/PM), but they both give the wrong time. I even emailed the server admin to make sure that the server clock was set correctly, and he said that it was. I don't know... Here's my PHP: $problemDateTime = date(Y-m-d g:i:s A); which returns: 2004-06-13 11:24:21 PM To the untrained eye ;), that might appear correct. But that was actually submitted at 11:24 AM, not PM. So, that's my code. Any suggestions?? Thanks a bunch, ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Fwd: [PHP-DB] anonymous select error
I agree about the semi-colon: not allowed. But also, specify '$link' in
your mysql_error(). This tells it explicitly what the error is
referring to, even though it should be able to figure it out on it's
own.
echo 'MySQL Error: ' . mysql_error($link);
Hope this helps - seems to work for me.
~Philip
I'm not sure you need a semi-colon after the table name.
$result = mysql_query( 'Select * From newsletter_subscribers', $db );
To: [EMAIL PROTECTED]
MIME-Version: 1.0
Content-Type: text/plain; charset=us-ascii
I'm trying this query:
$link = mysql_connect( $site, $id, $pass );
if (!$link) {
die('Could not connect: ' . mysql_error());
}
echo 'Connected successfullybr';
$db = mysql_select_db( $dbname, $link);
if( !$db ) {
echo DB falsebr;
exit;
}
$result = mysql_query( 'Select * From
newsletter_subscribers;', $db );
if (!$result) {
echo DB Error, could not list tablesbr;
echo 'MySQL Error: ' . mysql_error();
exit;
}
with this output:
Connected successfully
DB Error, could not list tables
MySQL Error:
I dont understand why there is an error, but it prints
nothing for the error. Any ideas? Thanks, Josh
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[PHP-DB] Erroneous date and time
Hi all. Maybe there's something I'm doing incorrectly, but I cannot get the date() function to return the appropriate time. It's always 12 hours off. I've tried using 24-hour time and 12-hour time (with AM/PM), but they both give the wrong time. I even emailed the server admin to make sure that the server clock was set correctly, and he said that it was. I don't know... Here's my PHP: $problemDateTime = date(Y-m-d g:i:s A); which returns: 2004-06-13 11:24:21 PM To the untrained eye ;), that might appear correct. But that was actually submitted at 11:24 AM, not PM. So, that's my code. Any suggestions?? Thanks a bunch, ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] mysql results, arrays, and for loops
Hi all! I am using a select statement to obtain all the dates whenever someone submitted a problem in a database. Well, I want to get the result (which could be multiple dates) and then print that in a table format with some other information on a webpage. So I want to use a FOR loops and go through each of the dates and dynamically create a table. My question is: how do I store the results of the select query? Would I want to store them in an array, and then just parse through each element of the array, and what is the syntax for that? Or is there a better way? Thanks, ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Re: mysql results, arrays, and for loops
Yes, thanks to all that assisted. I got it working like a charm!
~Philip
On Jun 11, 2004, at 9:30 AM, Torsten Roehr wrote:
Philip Thompson [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Hi all!
I am using a select statement to obtain all the dates whenever someone
submitted a problem in a database. Well, I want to get the result
(which could be multiple dates) and then print that in a table format
with some other information on a webpage. So I want to use a FOR loops
and go through each of the dates and dynamically create a table.
My question is: how do I store the results of the select query? Would
I
want to store them in an array, and then just parse through each
element of the array, and what is the syntax for that? Or is there a
better way?
You can loop through your query results in this way:
$result = mysql_query('SELECT * FROM table');
while ($row = mysql_fetch_assoc($result)) {
// row is now the current record set as an associative array, keys
represent the field names
// do what you want with row, e.g. print a field value from column
date
echo $row['date'];
}
Is this what you are looking for?
Regards,
Torsten Roehr
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[PHP-DB] HTTP header information
Hi all. I am running a website to where a user needs to login to authenticate themselves to perform certain tasks. So a user logs in, and I start a session (in PHP, of course). Well, the catch is, I am doing this all from one page, 'viewer.php', and I just tack on the specific view/page that I want them to see, depending on the link selected on that page. Meaning, they click on the 'submit problem' link and it goes to 'viewer.php?type=submitproblem'. The problem comes whenever I load the view 'submitproblem' and I start a session with session_start(), which carries over the variable to tell whether or not the user is logged in. If they have not logged in whenever they click on 'submitproblem' then it will redirect them to 'viewer.php?type=login'. So I log in, and then go to 'submitproblem'. This is where I get the error: Warning: session_start(): Cannot send session cookie - headers already sent. Essentially, I understand why this is occurring, but is there an easy way to get around it without creating a new page, such as 'submitproblem.php' instead of 'viewer.php?type=submitproblem'??? Thanks a bunch ~Philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Re: HTTP header information
On Jun 10, 2004, at 9:44 AM, Torsten Roehr wrote:
Philip Thompson [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Hi all.
I am running a website to where a user needs to login to authenticate
themselves to perform certain tasks. So a user logs in, and I start a
session (in PHP, of course). Well, the catch is, I am doing this all
from one page, 'viewer.php', and I just tack on the specific view/page
that I want them to see, depending on the link selected on that page.
Meaning, they click on the 'submit problem' link and it goes to
'viewer.php?type=submitproblem'.
The problem comes whenever I load the view 'submitproblem' and I start
a session with session_start(), which carries over the variable to
tell
whether or not the user is logged in. If they have not logged in
whenever they click on 'submitproblem' then it will redirect them to
'viewer.php?type=login'. So I log in, and then go to 'submitproblem'.
This is where I get the error: Warning: session_start(): Cannot send
session cookie - headers already sent. Essentially, I understand why
this is occurring, but is there an easy way to get around it without
creating a new page, such as 'submitproblem.php' instead of
'viewer.php?type=submitproblem'???
Make sure that NO output is done before session_start() is called. Can
you
post some of your code?
Regards,
Torsten Roehr
See, that's the case. Because I'm essentially just changing the content
within the page, it never leaves the page 'viewer.php' - it just
changes the content by tacking on '?type=login, submitproblem, etc'.
But my code in the beginning of the file 'submitproblem.view' is:
?php
session_start();
if (!session_is_registered('_isLoggedIn')) {
header (Location:viewer.php?type=login);
} else {
// do the stuff to submit a problem if they have
// logged in and have pressed the submit button
// in the html
}
?
// then here is all the html for that page
So, does that help any?
~Philip
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