Re: [PHP] Array keys referencing value from another array key???
Gerard Samuel wrote:
Not sure if the subject was worded correctly, but
I was looking to see if this (or something like it) is possible.
$array = array('key_1' = 'This is some text',
'key_2' = 'b' . $array['key_1'] . '/b'
);
And the array structure would be something like -
array('key_1' = 'This is some text',
'key_2' = 'bThis is some text/b')
Just wanted to see if it were possible, as my attempts were futile.
Its not a requirement on my end, just wanted to see if it were possible... :)
Thanks
It is possible in 2 steps:
1. create the array:
$array = array('key_1' = 'This is some text');
2. Add the second key:
$array['key_2'] = 'b' . $array['key_1'] . '/b';
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[PHP] array key starting with digit ending with string
I have an unusual situation where I have to communicate with an MS based
soap server. They have named one of their variables with a name leading
with a 1 such as 1variable. Nusoap loads the variable descriptions from the
wsdl document and compares the variable names I am trying to send with the
ones listed in the wsdl. In this process my sent to the function is
something like $data =
array('thisvar'=$myFirstVar,'thatvar'=$mySecondVar,'1othervar'=$myLastVar
). Later when the variable names are cycled through on a loop the following
test is used...
if($data[$currentVarNameInCycle])
{
do something
}
Is there some way force the recognition of the key when it leads with a
digit?
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Re: [PHP] array key starting with digit ending with string
[snip]
if($data[$currentVarNameInCycle])
{
do something
}
Is there some way force the recognition of the key when it leads with
a
digit?
[/snip]
not sure I follow 100% but you could use a regular expression to
detemine if it starts with a string.
if (preg_match('/^\d/',$array_key)) {
//do something
}
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Re: [PHP] array key starting with digit ending with string
[snip]
not sure I follow 100% but you could use a regular expression to
detemine if it starts with a string.
if (preg_match('/^\d/',$array_key)) {
//do something
}
[/snip]
I mean starts with a digit, sorry for 2 emails. I should proofread.
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[PHP] Array Question
I am using the following array and function in the template for my website.
It works great, but I want to to be better. I would to make it so the last
item displayed looks differently than the others, but I have been unable to
figure out how to distinguish the last item.
When displayed, the crumbs look like:
SITENAME » RANDOM » ITEM
I would like ITEM to look differently. Can anyone tell me how to modify the
select ITEM?
// CRUMBS ARRAY
$crumbs = array(
array( RANDOM, RANDOM_URL ),
array( ITEM, ITEM_URL )
);
// CRUMBS FUNCTION
function breadCrumbs($crumbs) {
if ( count($crumbs) 0 ) {
$spacer = span
style=\color:#94cf42;font-size:15px;font-weight:bold;\raquo;/span ;
$breadCrumbs = a href=\URL/\SITE_NAME/a\n;
foreach( $crumbs as $crumb ) {
if ( count($crumb) == 2 ) {
$breadCrumbs .= $spacera href=\$crumb[1]\$crumb[0]/a\n;
}
}
echo !-- ### BREADCRUMBS STARTS HERE
### --\n;
echo span class=\breadcrumbs\\n;
echo $breadCrumbs;
echo /span\n;
echo !-- BREADCRUMBS ENDS HERE
--\n;
}
}
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Re: [PHP] Array Problem
On 16-Apr-2004 Flavio Fontana wrote:
Hi
I have i Problem i got a variable a=2351 now i need to create an
array out of this variable
a[0]=1
a[1]=3
a[2]=5
a[3]=1
I have an idea to use the modulo function an do some Math but im sure
there is a nicer way of solving my prob
$a = preg_split('||', $a, -1, PREG_SPLIT_NO_EMPTY);
Regards,
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[PHP] Array Sorting Headaches
Greetings everyone : Having a hard time with this one. I have a multi-dim array $foo[$x][$y]['key'], where $x and $y are numeric. Here is some sample data : Array ( [$x] = Array ( [0] = Array ( [invoiceid] = 11842 [product] = myproduct [domain] = foo.net [expires] = February 28, 2004 ) [1] = Array ( [invoiceid] = 10295 [product] = myotherproduct [domain] = foo.net [expires] = December 9, 2003 ) [2] = Array ( [invoiceid] = 10202 [product] = product1 [domain] = foo.bar [expires] = January 19, 2003 ) [3] = Array ( [invoiceid] = 10005 [product] = product2 [domain] = foo.bar [expires] = December 11, 2002 ) ) ) I need to filter the results so that I get the latest expiry date for each product. The expires field actually contains a timestamp. So for the sample array above, the resultant array would have only keys 0 and 2, filtering out all the rest. There are around 180+ main entries, with any number of sub entries, but each sub entry has the same four keys. Any ideas? Getting a rather large headache mulling over this. Thanks again, Burhan -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Array Problem
Hi I have i Problem i got a variable a=2351 now i need to create an array out of this variable a[0]=1 a[1]=3 a[2]=5 a[3]=1 I have an idea to use the modulo function an do some Math but im sure there is a nicer way of solving my prob thx Flavio -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array Problem
That's how you could do it ...
$ar = array();
$len = strlen($a);
for ($i = 0; $i $len; ++$i) {
$ar[] = $a{$i};
}
HTH
Richard
Friday, April 16, 2004, 11:00:49 PM, you wrote:
Hi
I have i Problem i got a variable a=2351 now i need to create an array out of this
variable
a[0]=1
a[1]=3
a[2]=5
a[3]=1
I have an idea to use the modulo function an do some Math but im
sure there is a nicer way of solving my prob
thx Flavio
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Re: [PHP] Array Problem
That's how you could do it ...
$ar = array();
$len = strlen($a);
for ($i = 0; $i $len; ++$i) {
$ar[] = $a{$i};
}
If I remember well strlen is used for checking the length of a string...
Arthur
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Re: [PHP] Array Problem
How about count()
That's how you could do it ...
$ar = array();
$len = strlen($a);
for ($i = 0; $i $len; ++$i) {
$ar[] = $a{$i};
}
HTH
Richard
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Re: [PHP] Array Problem
Saturday, April 17, 2004, 7:38:46 PM, Arthur Radulescu wrote:
That's how you could do it ...
$ar = array();
$len = strlen($a);
for ($i = 0; $i $len; ++$i) {
$ar[] = $a{$i};
}
If I remember well strlen is used for checking the length of a string...
It does ...
I didn't look closely enough :(
So .. the var has to be converted to str first ... or use a temp var
converted to string ...
except of course someone comes up with a better method of solving the
problem at hand.
just for reference: the original problem (as I now understand it) was
how to 'convert' a number into an array ...
Friday, April 16, 2004, 11:00:49 PM, Flavio Fontana wrote:
Hi
I have i Problem i got a variable a=2351 now i need to create an array out of this
variable
a[0]=1
a[1]=3
a[2]=5
a[3]=1
I have an idea to use the modulo function an do some Math but im
sure there is a nicer way of solving my prob
thx Flavio
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Re: [PHP] Array Problem
Hi,
Saturday, April 17, 2004, 7:00:49 AM, you wrote:
FF Hi
FF I have i Problem i got a variable a=2351 now i need to create an array out of this
variable
FF a[0]=1
FF a[1]=3
FF a[2]=5
FF a[3]=1
FF I have an idea to use the modulo function an do some Math but
FF im sure there is a nicer way of solving my prob
FF thx Flavio
If you treat the variable as a string it is already an array of
characters
try echo $a{0};
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Tom
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Re: [PHP] Array problem
Hi noginn,
$columntotals[$count] = $columntotals[$count] + $sum;
^-^
ERROR HERE
Seem you tried to assign columntotal[index] with itself and you never
defined it. You should tried this one.
= $columntotals[$count] = $sum;
Is right?
Sorry, I confuse with your words total of totals?
Good Luck,
Firman
- Original Message -
From: noginn [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, March 22, 2004 12:33 AM
Subject: [PHP] Array problem
This has been confusing me a little for a few hours now.
Heres a snip of my code which is causing the problem:
$content = table border='0' cellspacing='0' cellpadding='5'\n;
$content .= tr\n;
$content .= tdnbsp;/td\n;
$tasks = new dbconnect;
$tasks-connect();
$tasks-query(SELECT tid, tname FROM tasks);
while(list($tid, $tname) = $tasks-fetch_rows()) {
$content .= td valign='top' align='center'span
class='highlight'$tname/span/td\n;
}
$content .= tdnbsp;/td\n;
$content .= /tr\n;
$projects = new dbconnect;
$projects-connect();
$projects-query(SELECT pid, pname FROM projects);
* $columntotals = array();*
$colour = 0;
while(list($pid, $pname) = $projects-fetch_rows()) {
$tasks-data_seek(0);
$rowtotal = 0;
$count = 0;
if ($colour % 2) {
$bgcolour = #FF;
}
else {
$bgcolour = #F9F9F9;
}
$colour++;
$content .= tr\n;
$content .= td valign='top' align='center'span
class='highlight'$pname/span/td\n;
while(list($tid, $tname) = $tasks-fetch_rows()) {
$logs = new dbconnect;
$logs-connect();
$logs-query(SELECT SUM(hours) from logs WHERE pid = '$pid'
AND tid = '$tid' AND date = '$sdate' AND date = '$edate');
list($sum) = $logs-fetch_rows();
if (!$sum) {
$sum = 0;
}
$rowtotal = $rowtotal + $sum;
*$columntotals[$count] = $columntotals[$count] + $sum;*
$count++;
$content .= td bgcolor='$bgcolour'
align='center'$sum/td\n;
}
$content .= td align='center'b$rowtotal/b/td\n;
}
$content .= /tr\n;
$content .= tr\n;
$content .= tdnbsp;/td\n;
$sumofcolumntotals = 0;
for ($i=0; $isizeof($columntotals); $i++)
{
$sumofcolumntotals = $sumofcolumntotals + $columntotals[$i];
$content .= td align='center'b$columntotals[$i]/b/td\n;
}
$content .= td align='center'b$sumofcolumntotals/b/td\n;
$content .= /tr\n;
$content .= /table\n;
I have made the lines inwhich I know are causing problems in bold.
Basicly, I am creating a report of some data and need to count up totals
of each column and then again total the totals if you get me.
Here is the errors I am getting.
*Notice*: Undefined offset: 0 in
*C:\WWW\Apache2\htdocs\php\coursework\reports_projects.php* on line *58*
*Notice*: Undefined offset: 1 in
*C:\WWW\Apache2\htdocs\php\coursework\reports_projects.php* on line *58*
*Notice*: Undefined offset: 2 in
*C:\WWW\Apache2\htdocs\php\coursework\reports_projects.php* on line *58*
*Notice*: Undefined offset: 3 in
*C:\WWW\Apache2\htdocs\php\coursework\reports_projects.php* on line *58
*Now I understand in a way why its happening, because im trying to
insert into $columntotals something which isnt valid, but I can't think
of a way to stop this at the moment.
Hope to hear soon, thanks in advance guys.
-noginn
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Re: [PHP] Array problem
Ye that is true, however to create the totals of each columns I had to
somehow do this.
I have fixed the problem in a way, but it was probably a very crude way
of doing so.
$rowtotal = $rowtotal + $sum;
if(!empty($columntotals[$count])) {
$columntotals[$count] = $columntotals[$count] + $sum;
}
else {
$columntotals[$count] = $sum;
}
$count++;
So now it won't try and add itself if it is empty.
But if anyone has more ideas of how I can create a cleaner piece of code
then please let me know! :)
-noginn
Firman Wandayandi wrote:
Hi noginn,
$columntotals[$count] = $columntotals[$count] + $sum;
^-^
ERROR HERE
Seem you tried to assign columntotal[index] with itself and you never
defined it. You should tried this one.
= $columntotals[$count] = $sum;
Is right?
Sorry, I confuse with your words total of totals?
Good Luck,
Firman
- Original Message -
From: noginn [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, March 22, 2004 12:33 AM
Subject: [PHP] Array problem
This has been confusing me a little for a few hours now.
Heres a snip of my code which is causing the problem:
$content = table border='0' cellspacing='0' cellpadding='5'\n;
$content .= tr\n;
$content .= tdnbsp;/td\n;
$tasks = new dbconnect;
$tasks-connect();
$tasks-query(SELECT tid, tname FROM tasks);
while(list($tid, $tname) = $tasks-fetch_rows()) {
$content .= td valign='top' align='center'span
class='highlight'$tname/span/td\n;
}
$content .= tdnbsp;/td\n;
$content .= /tr\n;
$projects = new dbconnect;
$projects-connect();
$projects-query(SELECT pid, pname FROM projects);
* $columntotals = array();*
$colour = 0;
while(list($pid, $pname) = $projects-fetch_rows()) {
$tasks-data_seek(0);
$rowtotal = 0;
$count = 0;
if ($colour % 2) {
$bgcolour = #FF;
}
else {
$bgcolour = #F9F9F9;
}
$colour++;
$content .= tr\n;
$content .= td valign='top' align='center'span
class='highlight'$pname/span/td\n;
while(list($tid, $tname) = $tasks-fetch_rows()) {
$logs = new dbconnect;
$logs-connect();
$logs-query(SELECT SUM(hours) from logs WHERE pid = '$pid'
AND tid = '$tid' AND date = '$sdate' AND date = '$edate');
list($sum) = $logs-fetch_rows();
if (!$sum) {
$sum = 0;
}
$rowtotal = $rowtotal + $sum;
*$columntotals[$count] = $columntotals[$count] + $sum;*
$count++;
$content .= td bgcolor='$bgcolour'
align='center'$sum/td\n;
}
$content .= td align='center'b$rowtotal/b/td\n;
}
$content .= /tr\n;
$content .= tr\n;
$content .= tdnbsp;/td\n;
$sumofcolumntotals = 0;
for ($i=0; $isizeof($columntotals); $i++)
{
$sumofcolumntotals = $sumofcolumntotals + $columntotals[$i];
$content .= td align='center'b$columntotals[$i]/b/td\n;
}
$content .= td align='center'b$sumofcolumntotals/b/td\n;
$content .= /tr\n;
$content .= /table\n;
I have made the lines inwhich I know are causing problems in bold.
Basicly, I am creating a report of some data and need to count up totals
of each column and then again total the totals if you get me.
Here is the errors I am getting.
*Notice*: Undefined offset: 0 in
*C:\WWW\Apache2\htdocs\php\coursework\reports_projects.php* on line *58*
*Notice*: Undefined offset: 1 in
*C:\WWW\Apache2\htdocs\php\coursework\reports_projects.php* on line *58*
*Notice*: Undefined offset: 2 in
*C:\WWW\Apache2\htdocs\php\coursework\reports_projects.php* on line *58*
*Notice*: Undefined offset: 3 in
*C:\WWW\Apache2\htdocs\php\coursework\reports_projects.php* on line *58
*Now I understand in a way why its happening, because im trying to
insert into $columntotals something which isnt valid, but I can't think
of a way to stop this at the moment.
Hope to hear soon, thanks in advance guys.
-noginn
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[PHP] Array problem
This has been confusing me a little for a few hours now.
Heres a snip of my code which is causing the problem:
$content = table border='0' cellspacing='0' cellpadding='5'\n;
$content .= tr\n;
$content .= tdnbsp;/td\n;
$tasks = new dbconnect;
$tasks-connect();
$tasks-query(SELECT tid, tname FROM tasks);
while(list($tid, $tname) = $tasks-fetch_rows()) {
$content .= td valign='top' align='center'span
class='highlight'$tname/span/td\n;
}
$content .= tdnbsp;/td\n;
$content .= /tr\n;
$projects = new dbconnect;
$projects-connect();
$projects-query(SELECT pid, pname FROM projects);
* $columntotals = array();*
$colour = 0;
while(list($pid, $pname) = $projects-fetch_rows()) {
$tasks-data_seek(0);
$rowtotal = 0;
$count = 0;
if ($colour % 2) {
$bgcolour = #FF;
}
else {
$bgcolour = #F9F9F9;
}
$colour++;
$content .= tr\n;
$content .= td valign='top' align='center'span
class='highlight'$pname/span/td\n;
while(list($tid, $tname) = $tasks-fetch_rows()) {
$logs = new dbconnect;
$logs-connect();
$logs-query(SELECT SUM(hours) from logs WHERE pid = '$pid'
AND tid = '$tid' AND date = '$sdate' AND date = '$edate');
list($sum) = $logs-fetch_rows();
if (!$sum) {
$sum = 0;
}
$rowtotal = $rowtotal + $sum;
*$columntotals[$count] = $columntotals[$count] + $sum;*
$count++;
$content .= td bgcolor='$bgcolour'
align='center'$sum/td\n;
}
$content .= td align='center'b$rowtotal/b/td\n;
}
$content .= /tr\n;
$content .= tr\n;
$content .= tdnbsp;/td\n;
$sumofcolumntotals = 0;
for ($i=0; $isizeof($columntotals); $i++)
{
$sumofcolumntotals = $sumofcolumntotals + $columntotals[$i];
$content .= td align='center'b$columntotals[$i]/b/td\n;
}
$content .= td align='center'b$sumofcolumntotals/b/td\n;
$content .= /tr\n;
$content .= /table\n;
I have made the lines inwhich I know are causing problems in bold.
Basicly, I am creating a report of some data and need to count up totals
of each column and then again total the totals if you get me.
Here is the errors I am getting.
*Notice*: Undefined offset: 0 in
*C:\WWW\Apache2\htdocs\php\coursework\reports_projects.php* on line *58*
*Notice*: Undefined offset: 1 in
*C:\WWW\Apache2\htdocs\php\coursework\reports_projects.php* on line *58*
*Notice*: Undefined offset: 2 in
*C:\WWW\Apache2\htdocs\php\coursework\reports_projects.php* on line *58*
*Notice*: Undefined offset: 3 in
*C:\WWW\Apache2\htdocs\php\coursework\reports_projects.php* on line *58
*Now I understand in a way why its happening, because im trying to
insert into $columntotals something which isnt valid, but I can't think
of a way to stop this at the moment.
Hope to hear soon, thanks in advance guys.
-noginn
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Re: [PHP] array $_POST problem
On Tuesday 16 March 2004 12:16, thou spake: You're the Joey Kelly who runs the LUG in NoLA, yes? Yes, that's me. Have you been to one of our meetings lately? We redid our website recently: http://www.nolug.org Thanks for saying hi :-) snip Upon post, you need to get materials as such: $materials = $_POST['materials']; That looks interesting (using the , etc.) I'll have to look into that. What the problem ended up being was bad syntax. I was using $materials[quantity][1] = $_POST[$materials][quantity][1]; instead of $materials[quantity][1] = $_POST[materials][quantity][1]; ...using a variable instead of a string to reference the array. snip Personally, I'd rename your form elements to: $materials[$item][quantity] $materials[$item][price] $materials[$item][description] Chris Excellent idea. In truth, I just picked up this project again after 1.5 years, so I expect to find other newbie mistakes in it. FYI, the project (WebInvoicer) is listed on my projects page, and I expect to release a new version of it (I'm refactoring it completely, and it will have the MySQL backend, etc.) in a few weeks. I'll probably post it on freshmeat, as well. Thanks to all who offered their suggestions :-) -- Joey Kelly Minister of the Gospel | Linux Consultant http://joeykelly.net I may have invented it, but Bill made it famous. --- David Bradley, the IBM employee that invented CTRL-ALT-DEL -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Array to String conversion error
Hi All,
I have a function that gets a single field from a mssql db. That field
contains data that is then parsed out to represent a survey's results.
The function;
function quesresults(){
$query = SELECT sur_ans
FROM au_survey;
$result = MSSQL_QUERY($query) or die(Can not execute query
$query. );
$row = mssql_fetch_array($result);
$thearray = explode('__', $row); - This is line 40
$i = 1;
foreach($thearray as $topelement){
foreach(explode('--', $topelement) as $element){
echo $element;
echo br;
}
echo question $i;
echo br;
$i++;
}
}
When I call the function I get;
Notice: Array to string conversion in \WWW\mypath\srvyclass.inc.php on line
40
Array
question 1
What am I missing?
alex hogan
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RE: [PHP] Array to String conversion error
Alex Hogan mailto:[EMAIL PROTECTED]
on Tuesday, March 16, 2004 9:48 AM said:
$row = mssql_fetch_array($result);
$thearray = explode('__', $row); - This is line 40
$row is an entire array. you don't explode an entire array, you only
explode the contents of an element of an array.
print_r($row) will give you some clues.
you'll need to access a specific element within the array. like:
$thearray = explode('__', $row[0][0]);
What am I missing?
unless i'm wrong, the above.
chris.
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[PHP] array $_POST problem
Hello, I have a SuSE 9.0 Linux server running PHP and Apache2 (my phpinfo() data is at http://redfishnetworks.com/~jkelly/test.php), and my problem is this: I've got a sticky problem that I need to solve. I've just turned on register_globals in my PHP php.ini file, and therefore have to run my form variables through $_POST: $variable = $_POST[$variable]; echo $variable; The problem I'm having is that the script Im trying to refactor worked great before I turned register_globals off. The script posts an array, and I can't seem to figure out how to $_POST the array. Here is the script with register_globals OFF (this is on my old server, by the way, running SuSE 7.3), as you can see the script works fine with register_globals off: http://joeykelly.net/materials.php Here is the script with register_globals ON: http://redfishnetworks.com/~jkelly/materials.php Notice the huge nested array at the bottom when you click [SUBMIT]? That's my trouble. In both cases, changing the extension from .php to .phps shows you the source code. As you can see, above the form I've tried several attempts to access the data, all of which seem to fail. My question: What am I doing wrong? I suspect that I'm having trouble with nested arrays, etc.. The thing that bothers me is that the data is available (see the array printout at the bottom?). If I can't make this work, I'm going to have to resort to munging a bunch of scalars ($quantity1, $quantity2, etc.), which to me is an awful kludge that I'd rather not sign my name to. Thanks for any help. -- Joey Kelly Minister of the Gospel | Linux Consultant http://joeykelly.net I may have invented it, but Bill made it famous. --- David Bradley, the IBM employee that invented CTRL-ALT-DEL -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] array $_POST problem
Hello Joey, Tuesday, March 16, 2004, 6:16:34 PM, you wrote: JK I have a SuSE 9.0 Linux server running PHP and Apache2 (my phpinfo() data is JK at http://redfishnetworks.com/~jkelly/test.php), and my problem is this: JK I've got a sticky problem that I need to solve. I've just turned on JK register_globals in my PHP php.ini file, and therefore have to run my form JK variables through $_POST: If you don't know in what way PHP sends the POST data, then the best solution is simply to view it: ? echo pre; print_r($_POST); echo /pre; ? (Or you can var_dump the whole thing) By looking at the structure like this you'll soon see how to access the values inside of it rather than second-guessing all the time. -- Best regards, Richard Davey http://www.phpcommunity.org/wiki/296.html -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] array $_POST problem
Joey Kelly mailto:[EMAIL PROTECTED] on Tuesday, March 16, 2004 10:17 AM said: The problem I'm having is that the script Im trying to refactor worked great before I turned register_globals off. The script posts an array, and I can't seem to figure out how to $_POST the array. the script posts an array, and you can't figure out how to $_POST the array? Here is the script with register_globals OFF (this is on my old server, by the way, running SuSE 7.3), as you can see the script works fine with register_globals off: http://joeykelly.net/materials.php why don't you just turn register_globals off again? chris. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] array $_POST problem
You're the Joey Kelly who runs the LUG in NoLA, yes?
I've got a sticky problem that I need to solve. I've just turned on
register_globals in my PHP php.ini file, and therefore have to run my form
variables through $_POST:
$variable = $_POST[$variable];
echo $variable;
Or you can use extract();
The problem I'm having is that the script Im trying to refactor worked
great
before I turned register_globals off. The script posts an array, and I
can't
seem to figure out how to $_POST the array.
It seems like the array is posted just fine.
In both cases, changing the extension from .php to .phps shows you the
source
code. As you can see, above the form I've tried several attempts to access
the data, all of which seem to fail.
How is it failing? Looking at the source, you are definitely on the right
track.
My question: What am I doing wrong? I suspect that I'm having trouble with
nested arrays, etc.. The thing that bothers me is that the data is
available
(see the array printout at the bottom?).
Upon post, you need to get materials as such:
$materials = $_POST['materials'];
to list out the quantity, you can do any the following:
foreach( $materials['quantity'] as $quantity ) {
echo $quantity . 'br';
}
foreach( $materials['description'] as $description ) {
echo $description . 'br';
}
for( $i = 0; $i 5; $i++ ) {
echo $materials['description'][$i] . '::' . $materials['quantity'][$i] .
'br';
}
Personally, I'd rename your form elements to:
$materials[$item][quantity]
$materials[$item][price]
$materials[$item][description]
Chris
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RE: [PHP] Array to String conversion error
$row is an entire array. you don't explode an entire array, you only
explode the contents of an element of an array.
print_r($row) will give you some clues.
you'll need to access a specific element within the array. like:
$thearray = explode('__', $row[0][0]);
That was it... Thanks Chris.
alex
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[PHP] Array Question
I would like to be able to search an array for a match the a specific variable. So far, I have been trying to use preg_grep but am not getting the results that I want. Basically, I would have a variable: $url = domain.com I would like to search an array to see if the value of the variable $url exists in this array. The array would look like: $archives = array( domain.com,domain2.com); As for the results of the search, I just need a simple yes/no 1/0 response. What would be the best method of handling this? Thank You, Jason Williard -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array Question
I would like to search an array to see if the value of the variable $url exists in this array. The array would look like: in_array() - michal migurski- contact info and pgp key: sf/cahttp://mike.teczno.com/contact.html -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] array data
Hello Imran,
Wednesday, February 11, 2004, 8:17:11 PM, you wrote:
IA Is not working, is it correct way
IA File1.php
IA? $colors = array('red','blue','green','yellow'); ?
IAform action=file2.php method=post
IA input type=hidden type name=colors value=?=$colors?
IA /fomr
You can't do it like this. Rather, do the following:
form action=whatever.php method=post
input type=hidden name=colors[] value=red
input type=hidden name=colors[] value=blue
input type=hidden name=colors[] value=green
Or if you prefer you can use some PHP code to write out the input tags
based on a colors array:
?
$colors = array('red','blue','green','yellow');
foreach ($colors as $color)
{
echo input type=hidden name=colors[] value=\$color\;
}
?
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RE: [PHP] array data
It is not the correct way because $colors being an array, the HTML code for
the hidden input element will look like this (once the HTML has been
generated by PHP):
[code]
input type=hidden name=colors value=Array
[/code]
What you probably want to do instead is something like this:
[code]
?
foreach ($colors as $color) {
?
input type=hidden name=colors[] value=?= $color ?
?
}
? // close loop
[/code]
This will create the following HTML (for the given example)...
[code]
input type=hidden name=colors[] value=red
input type=hidden name=colors[] value=blue
input type=hidden name=colors[] value=green
input type=hidden name=colors[] value=yellow
[/code]
... and File2.php will do its job as desired.
Shaunak
-Original Message-
From: Imran Asghar [mailto:[EMAIL PROTECTED]
Sent: Wednesday, February 11, 2004 3:17 PM
To: [EMAIL PROTECTED]
Subject: [PHP] array data
Hi,
Is not working, is it correct way
File1.php
? $colors = array('red','blue','green','yellow'); ?
form action=file2.php method=post
input type=hidden type name=colors value=?=$colors?
/fomr
File2.php
?
echo $colors[0];
echo $colors[1];
echo $colors[2];
echo $colors[4];
?
imee
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[PHP] array data
Hi,
Is not working, is it correct way
File1.php
? $colors = array('red','blue','green','yellow'); ?
form action=file2.php method=post
input type=hidden type name=colors value=?=$colors?
/fomr
File2.php
?
echo $colors[0];
echo $colors[1];
echo $colors[2];
echo $colors[4];
?
imee
[PHP] array block
I'm having array block, trying to format the data in a two dimensional
associative array.
$menu = array (
'link1' = array(
'url' = 'foo',
'title' = 'bar'
),
'link2' = array(
'url' = 'foo',
'title' = 'bar'
)
);
foreach($menu as $k = $v) { etc..
need to end up with
a href=url title=titlelink(x)/a
Can't seem to put this together in my head. Long day I guess.
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[PHP] Array Key Test
Hi, How would I go about determining if a specific key exists in an array? I want to see if $conf['hOpt'] is defined. is_array only works at the $conf level. I tried count(array_keys($conf, 'hOpt')), but always get 0. What am I doing wrong here? Thanks, Cameron -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array Key Test
Cameron B. Prince wrote: How would I go about determining if a specific key exists in an array? http://php.net/isset I want to see if $conf['hOpt'] is defined. is_array only works at the $conf level. I tried count(array_keys($conf, 'hOpt')), but always get 0. if (isset($conf['h0pt'])) -- Stuart -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Array into $_SESSION
Hi all, can somebody remind me how to propperly insert not just one but many variables into a $_SESSION handle? php manual doesn't explain it very well. It just says that it can be done. Thanks in advanced, Cesar Aracena -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array into $_SESSION
On Friday 02 January 2004 02:11 am, Cesar Aracena wrote:
Hi all,
can somebody remind me how to propperly insert not just one but many
variables into a $_SESSION handle? php manual doesn't explain it very well.
It just says that it can be done.
$_SESSION['foo'] = array('a', 'b', 'c', 'd', 'e');
var_dump($_SESSION['foo'][3]); = 'd'
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Re: [PHP] Array into $_SESSION
Thanks a lot :)
Gerard Samuel [EMAIL PROTECTED] escribió en el mensaje
news:[EMAIL PROTECTED]
On Friday 02 January 2004 02:11 am, Cesar Aracena wrote:
Hi all,
can somebody remind me how to propperly insert not just one but many
variables into a $_SESSION handle? php manual doesn't explain it very
well.
It just says that it can be done.
$_SESSION['foo'] = array('a', 'b', 'c', 'd', 'e');
var_dump($_SESSION['foo'][3]); = 'd'
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RE: [PHP] Array into $_SESSION
session_register(user); session_register(authLevel); session_register(sessionExpire); $user=$userDataFromForm; $authLevel = $authLevelFromDB; $sessionExpire = time() + 3600; etc... -Original Message- From: Cesar Aracena [mailto:[EMAIL PROTECTED] Sent: Friday, January 02, 2004 2:11 AM To: [EMAIL PROTECTED] Subject: [PHP] Array into $_SESSION Hi all, can somebody remind me how to propperly insert not just one but many variables into a $_SESSION handle? php manual doesn't explain it very well. It just says that it can be done. Thanks in advanced, Cesar Aracena -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Array into $_SESSION
Sorry, my bad. This is the Register Globals on version... with RegisterGlobals off you would simply use.. $_SESSION['user'] = $userDataFromForm; $_SESSION['authLevel'] -Original Message- From: Larry Brown [mailto:[EMAIL PROTECTED] Sent: Friday, January 02, 2004 11:33 AM To: Cesar Aracena; PHP List Subject: RE: [PHP] Array into $_SESSION session_register(user); session_register(authLevel); session_register(sessionExpire); $user=$userDataFromForm; $authLevel = $authLevelFromDB; $sessionExpire = time() + 3600; etc... -Original Message- From: Cesar Aracena [mailto:[EMAIL PROTECTED] Sent: Friday, January 02, 2004 2:11 AM To: [EMAIL PROTECTED] Subject: [PHP] Array into $_SESSION Hi all, can somebody remind me how to propperly insert not just one but many variables into a $_SESSION handle? php manual doesn't explain it very well. It just says that it can be done. Thanks in advanced, Cesar Aracena -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] array data to XML
newbie ... Is it possible to format data in array to XML and display ? Thanks !
Re: [PHP] Array problem....
Well just so you understand why I needed something like that here is
the finished result below
?php
function show() {
require 'path/to/dbconnector.inc';
$sql_subs = mysql_query(SELECT * FROM $t_02,$db)or die(mysql_error());
$i = 0;
while(list($id,$sub,$msk,$dns01,$dns02,$rtrs,$rnge) =
mysql_fetch_row($sql_subs)) {
$_SESSION[$i] = subnet $subbrnetmask $msk {broption
domain-name-servers $dns01, $dns02;broption routers $rtrs;brrange
$rnge;br}br;
$i++; }
?
Then ...
?php
call_user_func(show);
echo $_session['0'];
echo $_session['1'];
...
?
And you get...
subnet 128.110.22.110
netmask 255.255.255.0 {
option domain-name-servers 128.110.22.4, 128.110.29.3;
option routers 128.110.22.1;
range ;
}
Which allows for easy reading of configuration variables and the ability
to modify the individual vars using a form etc.
Thanks again for all who gave me some pointers on using numbers instead
of names for my session vars.
Jas
Chris W. Parker wrote:
Jas mailto:[EMAIL PROTECTED]
on Wednesday, December 10, 2003 3:44 PM said:
having no idea you could use numbers as session variable names I kinda
feel like a retard right now. You solution worked, thank you very
much.
It's an array just like any other which you probably realize now. ;)
Also, unless you're doing some math or something with those variables
you might to split them up into their own cells (I don't really know if
this is going to be useful for you or not):
{
$_SESSION[$iCtr]['var1'] = $var1;
$_SESSION[$iCtr]['var2'] = $var2;
$_SESSION[$iCtr]['var3'] = $var3;
$_SESSION[$iCtr]['var4'] = $var4;
$_SESSION[$iCtr]['var5'] = $var5;
...
}
HTH,
Chris.
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RE: [PHP] Array problem....
Jas mailto:[EMAIL PROTECTED]
on Thursday, December 11, 2003 7:21 AM said:
Well just so you understand why I needed something like that here is
the finished result below
[snip]
$i = 0;
while(list(...) = mysql_fetch_row(...)) {
$_SESSION[$i] = ...;
$i++;
}
I want to change my suggestion and recommend that you go along with what
John Holmes suggested a little after my post. Read his post again and
see if it is helpful to you. Keep note of the following aspect:
You can remove the $i = 0; and the $i++; by changing $_SESSION[$i] =
...; to $_SESSION[] = ...;.
i.e. The following two code blocks perform the same task:
Current:
$i = 0;
while(list(...) = mysql_fetch_row(...)) {
$_SESSION[$i] = ...;
$i++;
}
New:
while(list(...) = mysql_fetch_row(...)) {
$_SESSION[] = ...;
}
Chris.
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Re: [PHP] Array problem....
Yeah I understand that and it would be perfect if I only had to call
this type of function once on a page... and on any other pages that need
something like this I will do it that way but with the counter set to 0
or whatever number I choose which is a sort of view all page so your
solutions works better for this page. Thanks again.
Jas
Chris W. Parker wrote:
Jas mailto:[EMAIL PROTECTED]
on Thursday, December 11, 2003 7:21 AM said:
Well just so you understand why I needed something like that here is
the finished result below
[snip]
$i = 0;
while(list(...) = mysql_fetch_row(...)) {
$_SESSION[$i] = ...;
$i++;
}
I want to change my suggestion and recommend that you go along with what
John Holmes suggested a little after my post. Read his post again and
see if it is helpful to you. Keep note of the following aspect:
You can remove the $i = 0; and the $i++; by changing $_SESSION[$i] =
...; to $_SESSION[] = ...;.
i.e. The following two code blocks perform the same task:
Current:
$i = 0;
while(list(...) = mysql_fetch_row(...)) {
$_SESSION[$i] = ...;
$i++;
}
New:
while(list(...) = mysql_fetch_row(...)) {
$_SESSION[] = ...;
}
Chris.
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[PHP] ARRAY
I am trying to read in a text file to an array using the following code,
however everytime I try and print the contents of the $table array, it
always says ARRAY. Why won't it show me the actual contents of the file?
$row = 1;
$handle = fopen (seclog.txt,r);
while ($data = fgetcsv ($handle, 1000, ,)) {
$num = count ($data);
print p $num fields in line $row: br\n;
$row++;
for ($c=0; $c $num; $c++) {
print $data[$c] . br\n;
$table[] = $data;
}
}
fclose ($handle);
print $table;
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Re: [PHP] ARRAY
Because it's and array! print and echo take strings, not arrays, I believe. Anyway,
print_r() or a foreach loop will do it for you.
?php
print_r($table);
//or
foreach ($table as $atable){
echo $tableBr;
}
?
Something like that.
Brian Sutton [EMAIL PROTECTED] 12/10/03 01:26PM
I am trying to read in a text file to an array using the following code,
however everytime I try and print the contents of the $table array, it
always says ARRAY. Why won't it show me the actual contents of the file?
$row = 1;
$handle = fopen (seclog.txt,r);
while ($data = fgetcsv ($handle, 1000, ,)) {
$num = count ($data);
print p $num fields in line $row: br\n;
$row++;
for ($c=0; $c $num; $c++) {
print $data[$c] . br\n;
$table[] = $data;
}
}
fclose ($handle);
print $table;
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Re[2]: [PHP] ARRAY
Hi, Wednesday, December 10, 2003, 6:29:43 PM, you wrote: RM Because it's and array! print and echo take strings, not RM arrays, I believe. Anyway, print_r() or a foreach loop will do it RM for you. Agreed.. print_r() is the best, but if you're outputting all of this text into the browser (which is quite common) then I strongly suggest you wrap it with some PRE tags. You'll understand why when you try it. -- Best regards, Richardmailto:[EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] ARRAY
Richard Davey wrote: Hi, Wednesday, December 10, 2003, 6:29:43 PM, you wrote: RM Because it's and array! print and echo take strings, not RM arrays, I believe. Anyway, print_r() or a foreach loop will do it RM for you. Agreed.. print_r() is the best, but if you're outputting all of this text into the browser (which is quite common) then I strongly suggest you wrap it with some PRE tags. You'll understand why when you try it. You can always use var_dump, too. Not a pretty as print_r, but it gives you more info (mostly for debugging). And don't forget var_export. ;-) -- paperCrane Justin Patrin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Array problem....
Not very good at arrays so I figured i would look here
?php
$sql_subs = mysql_query(SELECT * FROM $t_02,$db)or
die(mysql_error());
while(list($id,$sub,$msk,$dns01,$dns02,$rtrs,$rnge) =
mysql_fetch_row($sql_subs)) {
print $sub;
print br;
print $msk;
print br;
print $dns01;
print br;
print $dns02;
print brbr; }
?
This pulls each row form a table and assigns a variable to each field,
but what I need to do is something like this...
?php
$sql_subs = mysql_query(SELECT * FROM $t_02,$db)or
die(mysql_error());
while(list($id,$sub,$msk,$dns01,$dns02,$rtrs,$rnge) =
mysql_fetch_row($sql_subs)) {
$_session['something to automaticly increment session var'] =
$sub+$msk+$dns01...
}
I have been scouring the various functions and as of yet have yet to
accomplish what I need. Any help would be great.
Thanks in advance,
jas
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RE: [PHP] Array problem....
Jas mailto:[EMAIL PROTECTED]
on Wednesday, December 10, 2003 3:21 PM said:
while(list($id,$sub,$msk,$dns01,$dns02,$rtrs,$rnge) =
mysql_fetch_row($sql_subs)) {
$_session['something to automaticly increment session var'] =
$sub+$msk+$dns01...
}
No exactly sure what you mean but here goes:
$iCtr = 0;
while(list(...)) = mysql_fetch_row(...))
{
$_SESSION[$iCtr] = $sub+$msk...;
$iCtr++;
}
HTH,
Chris.
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RE: [PHP] Array problem....
Chris W. Parker
on Wednesday, December 10, 2003 3:27 PM said:
while(list(...)) = mysql_fetch_row(...))
{
Got one too many ) in there. Should be:
while(list(...) = mysql_fetch_row(...))
{
Chris.
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Re: [PHP] Array problem....
having no idea you could use numbers as session variable names I kinda
feel like a retard right now. You solution worked, thank you very much.
Jas
Chris W. Parker wrote:
Jas mailto:[EMAIL PROTECTED]
on Wednesday, December 10, 2003 3:21 PM said:
while(list($id,$sub,$msk,$dns01,$dns02,$rtrs,$rnge) =
mysql_fetch_row($sql_subs)) {
$_session['something to automaticly increment session var'] =
$sub+$msk+$dns01...
}
No exactly sure what you mean but here goes:
$iCtr = 0;
while(list(...)) = mysql_fetch_row(...))
{
$_SESSION[$iCtr] = $sub+$msk...;
$iCtr++;
}
HTH,
Chris.
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RE: [PHP] Array problem....
Jas mailto:[EMAIL PROTECTED]
on Wednesday, December 10, 2003 3:44 PM said:
having no idea you could use numbers as session variable names I kinda
feel like a retard right now. You solution worked, thank you very
much.
It's an array just like any other which you probably realize now. ;)
Also, unless you're doing some math or something with those variables
you might to split them up into their own cells (I don't really know if
this is going to be useful for you or not):
{
$_SESSION[$iCtr]['var1'] = $var1;
$_SESSION[$iCtr]['var2'] = $var2;
$_SESSION[$iCtr]['var3'] = $var3;
$_SESSION[$iCtr]['var4'] = $var4;
$_SESSION[$iCtr]['var5'] = $var5;
...
}
HTH,
Chris.
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Re: [PHP] Array problem....
Jas wrote:
but what I need to do is something like this...
?php
$sql_subs = mysql_query(SELECT * FROM $t_02,$db)or
die(mysql_error());
while(list($id,$sub,$msk,$dns01,$dns02,$rtrs,$rnge) =
mysql_fetch_row($sql_subs)) {
$_session['something to automaticly increment session var'] =
$sub+$msk+$dns01...
}
How about:
$sql_subs = mysql_query(SELECT * FROM $t_02,$db) or die(mysql_error());
while($row = mysql_fetch_row($sql_subs))
{ $_SESSION['data'][] = $row; }
and you can use $_SESSION['data'][1]['id'], $_SESSION['data'][1]['sub'],
etc...
If you really want a + delimited string in the session, then you can use:
$_SESSION['data'][] = implode('+',$row);
Then row 1 is $_SESSION['data'][0], row 2 is $_SESSION['data'][1], etc.
Kind of begs the question of why you're doing all this, though
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Re: [PHP] array problems
$city = Ipswitch;
$city_found = 0;
$contentfile = fopen(content.txt, r);
while (!feof($contentfile) $city_found == 0);
{
$my_line = fgets($contentfile, 16384);
$content_array = explode(\t,$my_line);
if ($content_array[0] == $city)
{
$city_found = 1;
print(Matched on $content_aray[0]br\n);
}
}
print($content_array[0]\n);
I think what you got is a scope problem. You are creating $content_array
in your while loop so its scope is limited to the while loop. To test this
simply do a var_dump or print_r on $content_array outside your loop and
see if it actually is an array, which I guess it won't it will either be
null or an empty string.
To solve simply do an initialisation of the variable before the while loop
like $content_array = ''.
Regards
Stefan
Re: [PHP] array problems
On Friday 28 November 2003 16:03, [EMAIL PROTECTED] wrote: I think what you got is a scope problem. You are creating $content_array in your while loop so its scope is limited to the while loop. To test this simply do a var_dump or print_r on $content_array outside your loop and see if it actually is an array, which I guess it won't it will either be null or an empty string. To solve simply do an initialisation of the variable before the while loop like $content_array = ''. So that people don't get misled, the above is completely wrong. WHILE loops do not have their own scope. The correct answer (or the most plausible) was given in an earlier response by Marek, which pointed out that the last line(s) of the file may have just contained a CR and/or LF. -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * -- Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general -- /* Marriage is the waste-paper basket of the emotions. */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] array problems
Curtis Maurand wrote:
OK. That worked, thanks.
Is it me, or is that rather odd behavior?
It is you ;)
Shouldn't array elements
set within a loop be available to me outside the loop if the loop
exits normally? A loop is not a function (well it is, sort of.)
Should I declare the variable as global?
You are in a loop, so the variable is overwriten by new value in each
iteration.
global $content_array;
$city_found = 1;
while(!feof ...
When I was taking programming courses in college, I was taught that
breaking out of a loop like that was bad practice; that it was better
to leave a loop normally.
Depends. You could write
$continue=true;
while($continue .. other conditions .. ) {
if(... another condition ...) {
$continue = false;
}
}
I don't think this is any better then breaking out, and is certainly
slower. break and continue constructs are here for a reason and the use
is right here.
I've never programmed in C other than to
write a crude little dos2unix (actually mac2dos) utility. Mosty
i've written Perl, PHP Pascal and Basic. Pascal, Perl and Basic
don't exhibit this behavior.
All have this behavior.
I never worked with arrays in C. Am
I wrong?
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Re: [PHP] array problems
On Thu, Nov 27, 2003 at 08:19:02PM -0500, Curtis Maurand wrote:
: On Wednesday 26 November 2003 21:53, Marek Kilimajer mumble:
: Curtis Maurand wrote:
: Sorry, its a typo. it should be:
:
: $city = Ipswitch;
: $city_found = 0;
: $contentfile = fopen(content.txt, r);
: while (!feof($contentfile) $city_found == 0);
: {
: $my_line = fgets($contentfile, 16384);
: $content_array = explode(\t,$my_line);
: if ($content_array[0] == $city)
:{
: $city_found = 1;
: print(Matched on $content_aray[0]br\n);
:
: /* Break out of the while loop */
:break;
:
:}
: }
: print($content_array[0]\n);
:
: //end
:
: Is it me, or is that rather odd behavior? Shouldn't array elements
: set within a loop be available to me outside the loop if the loop
: exits normally?
It should. However, you must be sure to take the right action if the
loop exists unnormally.
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Re: [PHP] array problems
Thank you, I'll try that.
Curtis
On Wednesday 26 November 2003 21:53, the council of elders heard Marek
Kilimajer mumble incoherently:
Curtis Maurand wrote:
Sorry, its a typo. it should be:
$city = Ipswitch;
$city_found = 0;
$contentfile = fopen(content.txt, r);
while (!feof($contentfile) $city_found == 0);
{
$my_line = fgets($contentfile, 16384);
$content_array = explode(\t,$my_line);
if ($content_array[0] == $city)
{
$city_found = 1;
print(Matched on $content_aray[0]br\n);
/* Break out of the while loop */
break;
}
}
print($content_array[0]\n);
//end
As I stated. The match happens and the Matched on... message
happens, but the print statement outside the while loop does
not. Its php-4.2.2 running on RedHat 8.0 (don't go there.) Its
the stock redhat php package. I don't trust redhat libraries for
building php from scratch. Of course, this might actually be the
problem, too. :-)
Curtis
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Re: [PHP] array problems
OK. That worked, thanks.
Is it me, or is that rather odd behavior? Shouldn't array elements
set within a loop be available to me outside the loop if the loop
exits normally? A loop is not a function (well it is, sort of.)
Should I declare the variable as global?
global $content_array;
$city_found = 1;
while(!feof ...
When I was taking programming courses in college, I was taught that
breaking out of a loop like that was bad practice; that it was better
to leave a loop normally. I've never programmed in C other than to
write a crude little dos2unix (actually mac2dos) utility. Mosty
i've written Perl, PHP Pascal and Basic. Pascal, Perl and Basic
don't exhibit this behavior. I never worked with arrays in C. Am
I wrong?
On Wednesday 26 November 2003 21:53, the council of elders heard Marek
Kilimajer mumble incoherently:
Curtis Maurand wrote:
Sorry, its a typo. it should be:
$city = Ipswitch;
$city_found = 0;
$contentfile = fopen(content.txt, r);
while (!feof($contentfile) $city_found == 0);
{
$my_line = fgets($contentfile, 16384);
$content_array = explode(\t,$my_line);
if ($content_array[0] == $city)
{
$city_found = 1;
print(Matched on $content_aray[0]br\n);
/* Break out of the while loop */
break;
}
}
print($content_array[0]\n);
//end
As I stated. The match happens and the Matched on... message
happens, but the print statement outside the while loop does
not. Its php-4.2.2 running on RedHat 8.0 (don't go there.) Its
the stock redhat php package. I don't trust redhat libraries for
building php from scratch. Of course, this might actually be the
problem, too. :-)
Curtis
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Re: [PHP] array problems
On Wednesday 26 November 2003 04:45, Curtis Maurand wrote:
consider the following code (content.txt is tab delimited).
$city = Ipswitch;
$content = fopen(content.txt, r);
$city_found = 0;
while (!feof($content) $city_found == 0)
{
$my_line = fgets($content, r);
$content_array = explode(\t,$my_line);
if ($content_array == $city)
You can't do this comparison, $city is a string and $content_array is an
array. It's meaningless to compare them.
{
print(Matched on $content_array[0]);
$city_found = 1;
}
}
print($content_array[0]br\n);
Here's the trouble.
inside the while loop $content_array is available to me.
outside the loop $content_array is not available. What
am I doing wrong?
How did you confirm this observation?
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Re: [PHP] array problems
Sorry, its a typo. it should be:
$city = Ipswitch;
$city_found = 0;
$contentfile = fopen(content.txt, r);
while (!feof($contentfile) $city_found == 0);
{
$my_line = fgets($contentfile, 16384);
$content_array = explode(\t,$my_line);
if ($content_array[0] == $city)
{
$city_found = 1;
print(Matched on $content_aray[0]br\n);
}
}
print($content_array[0]\n);
//end
As I stated. The match happens and the Matched on... message happens,
but the print statement outside the while loop does not. Its php-4.2.2
running on RedHat 8.0 (don't go there.) Its the stock redhat php package.
I don't trust redhat libraries for building php from scratch. Of course,
this might actually be the problem, too. :-)
Curtis
On Tue, 25 Nov 2003, Marek Kilimajer wrote:
Curtis Maurand wrote:
Hello,
consider the following code (content.txt is tab delimited).
$city = Ipswitch;
$content = fopen(content.txt, r);
$city_found = 0;
while (!feof($content) $city_found == 0)
{
$my_line = fgets($content, r);
$content_array = explode(\t,$my_line);
if ($content_array == $city)
This will never be equal, $content_array is an array, $city is a string
{
print(Matched on $content_array[0]);
$city_found = 1;
}
}
print($content_array[0]br\n);
Here's the trouble.
inside the while loop $content_array is available to me.
outside the loop $content_array is not available. What
am I doing wrong?
The file might end with an empty line, in that case $my_line in the last
iteration contains only the newline character.
--
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mailto:[EMAIL PROTECTED]
http://www.maurand.com
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Re: [PHP] array problems
Curtis Maurand wrote:
Sorry, its a typo. it should be:
$city = Ipswitch;
$city_found = 0;
$contentfile = fopen(content.txt, r);
while (!feof($contentfile) $city_found == 0);
{
$my_line = fgets($contentfile, 16384);
$content_array = explode(\t,$my_line);
if ($content_array[0] == $city)
{
$city_found = 1;
print(Matched on $content_aray[0]br\n);
/* Break out of the while loop */
break;
}
}
print($content_array[0]\n);
//end
As I stated. The match happens and the Matched on... message happens,
but the print statement outside the while loop does not. Its php-4.2.2
running on RedHat 8.0 (don't go there.) Its the stock redhat php package.
I don't trust redhat libraries for building php from scratch. Of course,
this might actually be the problem, too. :-)
Curtis
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[PHP] Array dimension
I understand that in PHP there is only one dimension array, and in order to create several dimensions, yo need to nested the same function array(), but in conclusion you obtain n dimensions of the array whatever the implementation, I have already figured it out the problem , thanks anyway for all your help, bye. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] array problems
Hello,
consider the following code (content.txt is tab delimited).
$city = Ipswitch;
$content = fopen(content.txt, r);
$city_found = 0;
while (!feof($content) $city_found == 0)
{
$my_line = fgets($content, r);
$content_array = explode(\t,$my_line);
if ($content_array == $city)
{
print(Matched on $content_array[0]);
$city_found = 1;
}
}
print($content_array[0]br\n);
Here's the trouble.
inside the while loop $content_array is available to me.
outside the loop $content_array is not available. What
am I doing wrong?
Thanks in advance.
Curtis
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Re: [PHP] array problems
On Tue, Nov 25, 2003 at 03:45:11PM -0500, Curtis Maurand wrote:
:
: Hello,
: consider the following code (content.txt is tab delimited).
:
: $city = Ipswitch;
: $content = fopen(content.txt, r);
: $city_found = 0;
: while (!feof($content) $city_found == 0)
: {
: $my_line = fgets($content, r);
: $content_array = explode(\t,$my_line);
: if ($content_array == $city)
: {
: print(Matched on $content_array[0]);
: $city_found = 1;
: }
: }
: print($content_array[0]br\n);
:
: Here's the trouble.
:
: inside the while loop $content_array is available to me.
: outside the loop $content_array is not available. What
: am I doing wrong?
Your if statement is wrong. You can't compare an array with a string.
And your $content_array is not guaranteed to exist when it reaches your
print() statement. You can test for existence with is_array(). But you
already have this knowledge via your $city_found variable. Use it.
Here's a revision (untested):
$city = Ipswitch;
$content = fopen(content.txt, r);
$city_found = false;
while (!feof($content))
{
$my_line = fgets($content, r);
$content_array = explode(\t,$my_line);
if ($content_array[0] == $city)
{
print(Matched on $content_array[0]);
$city_found = true;
break;
}
}
if ($city_found)
{
print($content_array[0]br\n);
}
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Re: [PHP] array problems
Curtis Maurand wrote:
Hello,
consider the following code (content.txt is tab delimited).
$city = Ipswitch;
$content = fopen(content.txt, r);
$city_found = 0;
while (!feof($content) $city_found == 0)
{
$my_line = fgets($content, r);
$content_array = explode(\t,$my_line);
if ($content_array == $city)
This will never be equal, $content_array is an array, $city is a string
{
print(Matched on $content_array[0]);
$city_found = 1;
}
}
print($content_array[0]br\n);
Here's the trouble.
inside the while loop $content_array is available to me.
outside the loop $content_array is not available. What
am I doing wrong?
The file might end with an empty line, in that case $my_line in the last
iteration contains only the newline character.
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[PHP] array confusion...
Hi,
I must be missing something in this array. To me this makes no sense.
Here is it broken down...
Declartion:
$gtotals = array(
CO1 = 0,
CO2 = 0,
CO3 = 0,
CO4 = 0,
CO5 = 0,
CO6 = 0,
CO7 = 0
);
Code run:
while ( list( $action_code, $date_created, $date_letter_send ) =
mysql_fetch_row( $raw_res ) )
{
if ( $action_code == 'C01' || $action_code == 'C02' ||
$action_code == 'C03' || $action_code == 'C04' ||
$action_code == 'C05' || $action_code == 'C06' ||
$action_code == 'C07'
)
{
$totals[$date_created][$action_code]['created_count']++;
$gtotals[$action_code]++;
$dgtotals[$date_created]++;
$ggtt++;
$count++;
}
}
print_r results:
Array
(
[CO1] = 0
[CO2] = 0
[CO3] = 0
[CO4] = 0
[CO5] = 0
[CO6] = 0
[CO7] = 0
[C01] = 15
[C02] = 40
[C03] = 50
[C04] = 4
[C05] = 4
)
Now, the problem I'm having is that when I echo $array['C06'] and
$array['C07'] I'm getting (nothing..). Could someone point out how this
can be, and what I've done wrong?
-Dan Joseph
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Re: [PHP] array confusion...
On Mon, 2003-11-24 at 13:42, Dan Joseph wrote: Hi, I must be missing something in this array. To me this makes no sense. Here is it broken down... Declartion: $gtotals = array( CO1 = 0, CO2 = 0, CO3 = 0, CO4 = 0, CO5 = 0, CO6 = 0, CO7 = 0 ); [snip] print_r results: Array ( [CO1] = 0 [CO2] = 0 [CO3] = 0 [CO4] = 0 [CO5] = 0 [CO6] = 0 [CO7] = 0 [C01] = 15 [C02] = 40 [C03] = 50 [C04] = 4 [C05] = 4 ) Now, the problem I'm having is that when I echo $array['C06'] and $array['C07'] I'm getting (nothing..). Could someone point out how this can be, and what I've done wrong? I think you might have some letter 'O's instead of the number 0. Notice that you have CO1 and C01 when you print_r. They are different keys. - Brad -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] array confusion...
Hi, I think you might have some letter 'O's instead of the number 0. Notice that you have CO1 and C01 when you print_r. They are different keys. I think you are correct! hahaha... oh man, one of those Mondays! Thank you sir! -Dan Joseph -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Array + postgresql + braincramp
The problem is most likely that I have been looking at it for too long and missed the obvious. I know I can make multiple fields in the database and work with it that way, but I'm sure an array is the proper solution. We have a form (and how many of our tales start off like that? Bet it beats once upon a time). which gathers data for work orders. And we want to assign multiple people to a particular job. tdinput TYPE=checkbox NAME=workers[ ] VALUE=82Worker0 input TYPE=checkbox NAME=workers[ ] VALUE=83Worker1 input TYPE=checkbox NAME=workers[ ] VALUE=84Worker2 input TYPE=checkbox NAME=workers[ ] VALUE=85Worker3 /tdtr With the values being the employee/student id number. The values for workers[ ] are passed along with the rest of the input from the form via a post statement. When I get to processing page I checked to see if there was data via some echo's and it does indeed seem as though the data made it through. echo $workers[0] br; echo $workers[1] br; (each returns the values expected) In the dataset (postgresql) I defined workers as integer [ ] so it should be able to receive the data and it should be an array of integers. My update statement is as follows: $update_now=UPDATE work_orders SET add_info2='$add_info2', status='$status', workers =$workers, when_assigned='$now' where work_order_id='$work_id' ; which gives the following error message. UPDATE work_orders SET add_info2='fagsh', status='Working', workers =Array, when_assigned='1069188482' where work_order_id='1' [nativecode=ERROR: Attribute array not found ]. When I try imploding $workers, converting it to a string and putting that into workers it tells me the following. UPDATE work_orders SET add_info2='qwer', status='Working', workers =83, when_assigned='1069188871' where work_order_id='1' [nativecode=ERROR: column workers is of type integer[] but expression is of type integer You will need to rewrite or cast the expression ] Any and all advice/help much appreciated. -- Dr. Roy F. Cabaniss Associate Professor of Marketing University of Arkansas Monticello http://cabanisspc.uamont.edu signature.asc Description: This is a digitally signed message part
RE: [PHP] Array + postgresql + braincramp
While you can use an array type in postgresql, in most cases I'd recommend
against it. This is basically a repeating group, and in a relational
database the proper way to handle this type of need would be to have a
related table with a Many to 1 relationship back to the parent table.
If you are intent on using the array type, I believe your insert syntax
requires that the values be provided like so
In insert: values ('{value1, value2, .. value_n}' etc
In update: Set Columnname = '{value1, value2, .. value_n}'
-Original Message-
From: Roy Cabaniss [mailto:[EMAIL PROTECTED]
Sent: Tuesday, November 18, 2003 12:55 PM
To: List PHP General
Subject: [PHP] Array + postgresql + braincramp
The problem is most likely that I have been looking at it for too long
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RE: [PHP] Array -- If
Sounds like what you want is the in_array function.
http://us4.php.net/manual/en/function.in-array.php
$cases = array( 5, 15, 30, 60, 90, 120 );
if ( in_array($count, $cases) ) {
EXECUTE PAGE
}
Regards,
Erik Osterman
http://osterman.com/
-Original Message-
From: Jason Williard [mailto:[EMAIL PROTECTED]
Sent: Wednesday, November 05, 2003 6:42 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Array -- If
I am building a script that I would like to have do a specific task
based on whether specific counts have been reached.
Basically, the script checks for connectivity in a specific port. If
the connectivity fails, it increases the count by 1. It does this every
minute. I would like the script to page me at specific marker points
(i.e. 5, 15, 30, 60, 90, 120, etc). Is there anyway to make an if
statement or something similar to run in any case where the COUNT value
equals one of the numbers in the array?
Example:
$cases = array( 5, 15, 30, 60, 90, 120 );
if ( $count = {ITEM IN $cases} ){
EXECUTE PAGE
}
Thanks,
Jason Williard
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[PHP] Array -- If
I am building a script that I would like to have do a specific task
based on whether specific counts have been reached.
Basically, the script checks for connectivity in a specific port. If
the connectivity fails, it increases the count by 1. It does this every
minute. I would like the script to page me at specific marker points
(i.e. 5, 15, 30, 60, 90, 120, etc). Is there anyway to make an if
statement or something similar to run in any case where the COUNT value
equals one of the numbers in the array?
Example:
$cases = array( 5, 15, 30, 60, 90, 120 );
if ( $count = {ITEM IN $cases} ){
EXECUTE PAGE
}
Thanks,
Jason Williard
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Re: [PHP] Array maybe? Or many SQL insert queries
Jake McHenry wrote: Hi everyone, here's what I'm doing. As of right now, I don't have anything implemented, but here's what I need to do. I have a web page, with a drop down list of hotels, an input box for the users frequent hotel number, and a add button. At the bottom of the page is a update and continue button to move the user to the next page with more options. What my boss wants is, when someone puts in a number, and clicks add, he wants it to take that number and put it below the box, all on the fly. I know I could do this through repeated sql insert querys, but I was wondering if I could just put them into an array, then update the database with one query after the user clicks the update and continue button at the bottom, to get them to the next page? This sounds like something javascript can fix. If you can be a bit more precise below the box doesn't mean much. What box? Is it a big green box? Blue box? Box of boxes? If you want on the fly then its javascript. For php to work, you'd have to send a request to the server, which would kill your on the fly part. -- Burhan Khalid phplist[at]meidomus[dot]com http://www.meidomus.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Array maybe? Or many SQL insert queries
-Original Message- From: Burhan Khalid [mailto:[EMAIL PROTECTED] Sent: Saturday, November 01, 2003 3:50 AM To: Jake McHenry; [EMAIL PROTECTED] Subject: Re: [PHP] Array maybe? Or many SQL insert queries Jake McHenry wrote: Hi everyone, here's what I'm doing. As of right now, I don't have anything implemented, but here's what I need to do. I have a web page, with a drop down list of hotels, an input box for the users frequent hotel number, and a add button. At the bottom of the page is a update and continue button to move the user to the next page with more options. What my boss wants is, when someone puts in a number, and clicks add, he wants it to take that number and put it below the box, all on the fly. I know I could do this through repeated sql insert querys, but I was wondering if I could just put them into an array, then update the database with one query after the user clicks the update and continue button at the bottom, to get them to the next page? This sounds like something javascript can fix. If you can be a bit more precise below the box doesn't mean much. What box? Is it a big green box? Blue box? Box of boxes? If you want on the fly then its javascript. For php to work, you'd have to send a request to the server, which would kill your on the fly part. -- Burhan Khalid phplist[at]meidomus[dot]com http://www.meidomus.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php I don't know why I said on the fly.. Lol.. The box I'm referring to is the input field box. I just need what's submitted via the input field and add button to show up in a list below the input box, to show the account numbers that were entered. I can either insert them into the database each time the add button is clicked, or my preference if possible, put them in an array of some kind then submit them all at once. To get a picture of what I want...: Site Logo __ |__| ADD Submit and Continue Submit and Exit That's basically what this page looks like. What I need is when the person inputs the account number in the input box, and clicks add, it needs to refresh the page with the added number below that box, then again for each number they enter. Like I said, I can do this with multiple accesses to the database, but I would like to know of a way I could submit them all at once instead of multiple accesses to the database. Let me know if you need more info. Thanks, Jake McHenry Nittany Travel MIS Coordinator http://www.nittanytravel.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array maybe? Or many SQL insert queries
Jake McHenry wrote:
-Original Message-
From: Burhan Khalid [mailto:[EMAIL PROTECTED]
Sent: Saturday, November 01, 2003 3:50 AM
To: Jake McHenry; [EMAIL PROTECTED]
Subject: Re: [PHP] Array maybe? Or many SQL insert queries
Jake McHenry wrote:
Hi everyone, here's what I'm doing.
As of right now, I don't have anything implemented, but
here's what I
need to do.
I have a web page, with a drop down list of hotels, an
input box for
the users frequent hotel number, and a add button. At the bottom
of
the page is a update and continue button to move the user
to the next
page with more options.
What my boss wants is, when someone puts in a number, and
clicks add,
he wants it to take that number and put it below the box,
all on the
fly. I know I could do this through repeated sql insert
querys, but I
was wondering if I could just put them into an array, then
update the
database with one query after the user clicks the update
and continue
button at the bottom, to get them to the next page?
This sounds like something javascript can fix. If you can be
a bit more
precise below the box doesn't mean much. What box? Is it a
big green
box? Blue box? Box of boxes?
If you want on the fly then its javascript. For php to work, you'd
have to send a request to the server, which would kill your
on the fly
part.
I don't know why I said on the fly.. Lol..
The box I'm referring to is the input field box. I just need what's
submitted via the input field and add button to show up in a list
below the input box, to show the account numbers that were entered. I
can either insert them into the database each time the add button is
clicked, or my preference if possible, put them in an array of some
kind then submit them all at once. To get a picture of what I want...:
Site Logo
__
|__| ADD
Submit and Continue Submit and Exit
That's basically what this page looks like. What I need is when the
person inputs the account number in the input box, and clicks add, it
needs to refresh the page with the added number below that box, then
again for each number they enter.
You can attach a javascript function to the onclick event of the Add
button that populates your drop down. Of course, this assumes that you
have a predefined array of all possible values (in javascript) that the
user can enter.
However, if your user can arbitrarily enter values, and all you need to
do is add them to the drop down list, then some simple javascript DOM
is all you need. Then when the user clicks on the Submit and Continue
button, use php to read the dropdown array (appending [] to the name
attribute's value will help -- like this select name=foo[] then
$_POST['foo'][0] would hold the value of your selected index).
If you are not a big fan of javascript + DOM (this is, after all, a PHP
list) -- you can use PHP to dynamically populate the dropdown by
appending the value of the entered box to the array. Something along the
lines of (untested):
$textbx = isset($_POST['textbx']) ? $_POST['textbx'] : NULL;
$menu = array();
if ($textbx != NULL)
{
$menu['somevalue'] = $textbx;
} else { echo select name=\chooser[]\option value=\NULL\
selected=\selected\Please enter a value/option/select;
}
/* we now assume that the array was populated */
echo select name=\chooser[]\\n;
echo option value=\NULL\ selected=\selected\Value Entered
Below/option\n;
while(list($k,$v) = each($menu))
{
echo option value=\.$k.\.$v./option\n;
}
echo /select;
Hope this helps.
--
Burhan Khalid
phplist[at]meidomus[dot]com
http://www.meidomus.com
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RE: [PHP] Array maybe? Or many SQL insert queries
-Original Message-
From: Burhan Khalid [mailto:[EMAIL PROTECTED]
Sent: Saturday, November 01, 2003 11:16 AM
To: Jake McHenry; [EMAIL PROTECTED]
Subject: Re: [PHP] Array maybe? Or many SQL insert queries
Jake McHenry wrote:
-Original Message-
From: Burhan Khalid [mailto:[EMAIL PROTECTED]
Sent: Saturday, November 01, 2003 3:50 AM
To: Jake McHenry; [EMAIL PROTECTED]
Subject: Re: [PHP] Array maybe? Or many SQL insert queries
Jake McHenry wrote:
Hi everyone, here's what I'm doing.
As of right now, I don't have anything implemented, but
here's what I
need to do.
I have a web page, with a drop down list of hotels, an
input box for
the users frequent hotel number, and a add button. At the bottom
of
the page is a update and continue button to move the user
to the next
page with more options.
What my boss wants is, when someone puts in a number, and
clicks add,
he wants it to take that number and put it below the box,
all on the
fly. I know I could do this through repeated sql insert
querys, but I
was wondering if I could just put them into an array, then
update the
database with one query after the user clicks the update
and continue
button at the bottom, to get them to the next page?
This sounds like something javascript can fix. If you can be
a bit more
precise below the box doesn't mean much. What box? Is it a
big green
box? Blue box? Box of boxes?
If you want on the fly then its javascript. For php to work,
you'd
have to send a request to the server, which would kill your
on the fly
part.
I don't know why I said on the fly.. Lol..
The box I'm referring to is the input field box. I just need
what's
submitted via the input field and add button to show up in a list
below the input box, to show the account numbers that were
entered. I
can either insert them into the database each time the add
button is
clicked, or my preference if possible, put them in an array of
some
kind then submit them all at once. To get a picture of what
I want...:
Site Logo
__
|__| ADD
Submit and Continue
Submit and Exit
That's basically what this page looks like. What I need is when
the
person inputs the account number in the input box, and
clicks add, it
needs to refresh the page with the added number below that
box, then
again for each number they enter.
You can attach a javascript function to the onclick event of the Add
button that populates your drop down. Of course, this assumes
that you
have a predefined array of all possible values (in
javascript) that the
user can enter.
However, if your user can arbitrarily enter values, and all
you need to
do is add them to the drop down list, then some simple
javascript DOM
is all you need. Then when the user clicks on the Submit and
Continue
button, use php to read the dropdown array (appending [] to the name
attribute's value will help -- like this select name=foo[] then
$_POST['foo'][0] would hold the value of your selected index).
If you are not a big fan of javascript + DOM (this is, after
all, a PHP
list) -- you can use PHP to dynamically populate the dropdown by
appending the value of the entered box to the array.
Something along the
lines of (untested):
$textbx = isset($_POST['textbx']) ? $_POST['textbx'] : NULL;
$menu = array(); if ($textbx != NULL) {
$menu['somevalue'] = $textbx;
} else { echo select name=\chooser[]\option value=\NULL\
selected=\selected\Please enter a value/option/select; }
/* we now assume that the array was populated */
echo select name=\chooser[]\\n;
echo option value=\NULL\ selected=\selected\Value Entered
Below/option\n;
while(list($k,$v) = each($menu))
{
echo option value=\.$k.\.$v./option\n;
}
echo /select;
Hope this helps.
--
Burhan Khalid
phplist[at]meidomus[dot]com
http://www.meidomus.com
I'm not making a drop down box, I just want the contents of what is
added to be displayed on the page.
I got all of this done by creating an array and storing it in a
session variable.
Here's the code...
if ($_POST['2_Add'] != )
{
if (($_POST['Frequent_Flyer_Program'] != )
($_POST['Frequent_Flyer_Number'] != ))
{
$array = array();
$new =
{$_POST['Frequent_Flyer_Program']},{$_POST['Frequent_Flyer_Number']}
;
$old = $_SESSION['Frequent_Flyer'];
$array = array_merge($old, $new);
$_SESSION['Frequent_Flyer'] = $array;
}
header(Location: profile2.php);
}
The only dilema I have now is... How can I allow the user to remove
entries from this array if they make a mistake?
On the other pages where the add button is, and the list, I have a
foreach loop that explodes the array
[PHP] Array maybe? Or many SQL insert queries
Hi everyone, here's what I'm doing. As of right now, I don't have anything implemented, but here's what I need to do. I have a web page, with a drop down list of hotels, an input box for the users frequent hotel number, and a add button. At the bottom of the page is a update and continue button to move the user to the next page with more options. What my boss wants is, when someone puts in a number, and clicks add, he wants it to take that number and put it below the box, all on the fly. I know I could do this through repeated sql insert querys, but I was wondering if I could just put them into an array, then update the database with one query after the user clicks the update and continue button at the bottom, to get them to the next page? I will need to use this same outline for the this page, plus the next 2 pages in sequence for car and flyer numbers. Or, if anyone has a better way of an array or sql queries, that will work as well. :-) Thanks, Jake McHenry Nittany Travel MIS Coordinator http://www.nittanytravel.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Array Hell
Hi All, Im having a headache trying to sort this out... I have my array which is created each time a user adds an item to my basket, this all works fine. The problem im having is that when the user adds the item to the cart they have the option of selecting '0' as the quantity which in effect removes it from the basket. for example at position 0 on the array below the customer has product 22, the customer has ordered 6. $array[0][0] = 22 $array[0][1] = 6 If the customer inputs the value 0 into quantity the array looks like this: $array[0][0] = 22 $array[0][1] = 0 The question is who can i filter the array removing any values that have 0 in [x][1], i would also need to re-order the array from 0 to 'n'. Hope that all makes sence And before you ask i have looked everywhere at the manual (i got even more lost) Regards R -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] array of java-objects
Hi,
I'm trying to use our java-code in php.
But strange things happens
Maybe I did a simple mistake..
$MyInf=new Java(myUtil.myInfo);
This is inside of a loop through 3 items:
$MyAttributes=array();
$MyAttributes=$MyInf-MyAttrReader($v, ,, $item);
$c=null;
$c=count($MyAttributes);
so far ok, $c shows the correct number
but when doing this :
reset($MyAttributes);
$sa=$MyAttributes[0]; /* I can use 0 because there are always more than one
elements inside*/
var_dump($sa);
it comes up with a java-object only for the first entry
object(java)(1) { [0]= int(4) }
int(20)
int(36)
And then of course it's impossible to call methods on the objects because
they are no objects
Fatal error: Call to a member function on a non-object
Every hint woul'd be appreciated
thanks, Helke
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Re: [PHP] Array Hell
* Thus wrote Richard Cook ([EMAIL PROTECTED]):
Hi All,
Im having a headache trying to sort this out...
If the customer inputs the value 0 into quantity the array looks like this:
$array[0][0] = 22
$array[0][1] = 0
The question is who can i filter the array removing any values that have 0
in [x][1], i would also need to re-order the array from 0 to 'n'.
foreach ($array as $i =$item) {
if ( $item[1]) {
$new_array[] = $item;
}
}
$array = $new_array;
There might be an elegant way with one of the functions in
http://php.net/array
Curt
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Re: [PHP] array of java-objects
Hi,
please post your full code
Helke Schröder wrote:
Hi,
I'm trying to use our java-code in php.
But strange things happens
Maybe I did a simple mistake..
$MyInf=new Java(myUtil.myInfo);
This is inside of a loop through 3 items:
$MyAttributes=array();
$MyAttributes=$MyInf-MyAttrReader($v, ,, $item);
$c=null;
$c=count($MyAttributes);
so far ok, $c shows the correct number
but when doing this :
reset($MyAttributes);
$sa=$MyAttributes[0]; /* I can use 0 because there are always more than one
elements inside*/
var_dump($sa);
it comes up with a java-object only for the first entry
object(java)(1) { [0]= int(4) }
int(20)
int(36)
And then of course it's impossible to call methods on the objects because
they are no objects
Fatal error: Call to a member function on a non-object
Every hint woul'd be appreciated
thanks, Helke
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Re: [PHP] array of java-objects
Hi,
thanks for the replay
the var_dump on the array of java-objects looks interesting:
the first, which is ok:
array(8) { [0]= object(java)(1) { [0]= int(3) } [1]= object(java)(1)
[0]= int(4) } [2]= object(java)(1) { [0]= int(5) } [3]=
object(java)(1) { [0]= int(6) } [4]= object(java)(1) { [0]= int(7) }
[5]= object(java)(1) { [0]= int(8) } [6]= object(java)(1) { [0]=
int(9) } [7]= object(java)(1) { [0]= int(10) } }
but the second is strange:
array(8) { [0]= int(20) [1]= object(java)(1) { [0]= int(21) } [2]=
object(java)(1286082128) { } [3]= object(java)(1) { [0]= int(23) } [4]=
object(java)(1) { [0]= int(24) } [5]= object(java)(1) { [0]= int(25) }
[6]= object(java)(1) { [0]= int(26) } [7]= object(java)(1) { [0]=
int(27) } }
Why is that? The first element of that array is not a java-object.
The same with the third one:
array(9) { [0]= int(37) [1]= object(java)(1) { [0]= int(38) } [2]=
object(java)(1) { [0]= int(39) } [3]= object(java)(1) { [0]= int(40) }
[4]= object(java)(1) { [0]= int(41) } [5]= object(java)(1) { [0]=
int(42) } [6]= object(java)(1) { [0]= int(43) } [7]= object(java)(1)
[0]= int(44) } [8]= object(java)(1) { [0]= int(45) } }
thanks in advance, Helke
here is the code:
?php
error_reporting(E_ALL);
echo(htmlheadtitletest ldx per php/title/headbody);
$ldaphost=195.180.92.49;
$such_art=inh;
$filter=cn=*;
$base=dc=schule,dc=de;
$LdxInf=null;
$LdxInf=new Java(ldxUtil.LdxInterface);
$ObjectDNs=null;
$ObjectDNs=$LdxInf-FindObjects($ldaphost, , , $filter, $base);
echo(hr);
array_walk($ObjectDNs, traverse_array);
echo(hr);
echo(table);
foreach ($ObjectDNs as $item)
{
$LdxAttributes=null;
echo(trtd bgcolor=\#FF8000\);
var_dump($LdxInf);
echo(/td/tr);
echo(trtd bgcolor=\#00\.$item./td);
$LdxAttributes=array();
$LdxAttributes=$LdxInf-InheritanceReader($ldaphost, ,, $item);
$c=null;
$c=count($LdxAttributes);
echo(td.$c./td/tr);
reset($LdxAttributes);
echo(trtd bgcolor=\#C0C0C0\);
var_dump($LdxAttributes);
echo(/td/tr);
$sa=null;
$sa=new Java('ldxUtil.LdxAttribute');
reset($LdxAttributes);
$sa=$LdxAttributes[0];
echo(trtd bgcolor=\#80\);
var_dump($sa); /*the first object comes as java-object, the both following
as int(20) and int(37)*/
echo(/td/tr);
$s=null;
/*$s=$sa-getAttribute();
echo(trtd bgcolor=\#80FF80\);
var_dump($s);
echo(/td/tr);
echo(trtd.$s./td/tr);*/
unset($s);
unset($sa);
reset($LdxAttributes);
for ($i=0;$i$c;$i++)
{
echo(trtdsome text/td/tr);
$a=null;
$a=new Java('ldxUtil.LdxAttribute');
/*echo(trtd.$LdxAttributes[$i]-getAttribute()./td/tr);*/
unset($a);
}
unset($LdxAttributes);
unset($c);
}
function traverse_array($value) {
print $value.br;
}
unset($ObjectDNs);
unset($LdxInf);
unset($base);
unset($filter);
unset($such_art);
unset($ldaphost);
echo(/table/body/html);
?
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[PHP] Array in SQL-table
I want to store an ARRAY in a SQL-table but don't know how to define it in the table. The PHP-stuff is working OK but the DB-thing isn't. Anyone tried this? Hopefully it is Reidar Solberg -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array in SQL-table
If the field isn't required to be searchable, you could just serialize the array and shove that into a VARCHAR column.. Then unserialize the return value for that column. Jordan S. Jones Reidar wrote: I want to store an ARRAY in a SQL-table but don't know how to define it in the table. The PHP-stuff is working OK but the DB-thing isn't. Anyone tried this? Hopefully it is Reidar Solberg -- I am nothing but a poor boy. Please Donate.. https://www.paypal.com/xclick/business=list%40racistnames.comitem_name=Jordan+S.+Jonesno_note=1tax=0currency_code=USD -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Array to string?
Hello everybody. Is there any built-in function to convert an array to string? Thanks. __ Do you Yahoo!? The New Yahoo! Shopping - with improved product search http://shopping.yahoo.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array to string?
I just found it: implode. Sorry to bother you. __ Do you Yahoo!? The New Yahoo! Shopping - with improved product search http://shopping.yahoo.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Array of Classes
Greetings.. Doing some persistant connection socket-based PHP stuff and I'm trying to figure out a few things: 1) How can I create an array of classes so they could be referenced, for instance: $array[$uniqueID][$class-var] = 10; ? 2) Would it instantiate when that particular element was used and would the constructor run at that point? 3) Any way to dispose/destroy of an object once it's done being used to free up the resources? Thanks, Rob -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array of Classes
On Mon, 6 Oct 2003 13:41:22 -0400, you wrote:
1) How can I create an array of classes so they could be referenced, for
instance: $array[$uniqueID][$class-var] = 10; ?
2) Would it instantiate when that particular element was used and would the
constructor run at that point?
3) Any way to dispose/destroy of an object once it's done being used to free
up the resources?
?
class A {
function A () {
echo (pCreated/p);
}
function B ($s = None) {
echo (pinput : $s/p);
}
}
$C = array();
for ($i = 0; $i 3; $i++)
{
$C[$i] = new A();
}
for ($i = 0; $i 3; $i++)
{
$C[$i]-B($i);
}
for ($i = 0; $i 3; $i++)
{
unset ($C[$i]);
}
?
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Re: [PHP] Array of Classes
Cheers! Just what I was looking for. :)
Rob
David Otton [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
On Mon, 6 Oct 2003 13:41:22 -0400, you wrote:
1) How can I create an array of classes so they could be referenced, for
instance: $array[$uniqueID][$class-var] = 10; ?
2) Would it instantiate when that particular element was used and would
the
constructor run at that point?
3) Any way to dispose/destroy of an object once it's done being used to
free
up the resources?
?
class A {
function A () {
echo (pCreated/p);
}
function B ($s = None) {
echo (pinput : $s/p);
}
}
$C = array();
for ($i = 0; $i 3; $i++)
{
$C[$i] = new A();
}
for ($i = 0; $i 3; $i++)
{
$C[$i]-B($i);
}
for ($i = 0; $i 3; $i++)
{
unset ($C[$i]);
}
?
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[PHP] Array question
Good morning all!! Can you nest an array within an array?? Example: $paArgs['aCheckBoxes[$iIndex]['sName']'] Thank you in advance. Robin 'Sparky' Kopetzky Black Mesa Computers/Internet Service Grants, NM 87020 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array question
On Sat, 2003-09-27 at 12:18, Robin Kopetzky wrote: Good morning all!! Can you nest an array within an array?? Example: $paArgs['aCheckBoxes[$iIndex]['sName']'] You mean can you retrieve an array entry by giving a key defined by a value in another array? To do so remove the outer quotes in your above statement and add a $ to the interior array. Example: $paArgs[$aCheckBoxes[$iIndex]['sName']] Cheers, Rob. -- .. | InterJinn Application Framework - http://www.interjinn.com | :: | An application and templating framework for PHP. Boasting | | a powerful, scalable system for accessing system services | | such as forms, properties, sessions, and caches. InterJinn | | also provides an extremely flexible architecture for | | creating re-usable components quickly and easily. | `' -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array question
On Saturday 27 September 2003 11:18, Robin Kopetzky wrote: Good morning all!! Can you nest an array within an array?? Example: $paArgs['aCheckBoxes[$iIndex]['sName']'] Yes, but like this $array['aCheckBoxes'][] = $iIndex['sName'] This means: $array is an array aCheckBoxes is a item in $array aCheckBoxes is also an array $iIndex is an item in the aCheckBoxes array $iIndex is an array. Hope this helps. -Jackson Thank you in advance. Robin 'Sparky' Kopetzky Black Mesa Computers/Internet Service Grants, NM 87020 -- jackson miller cold feet creative 615.321.3300 / 800.595.4401 [EMAIL PROTECTED] cold feet presents Emma the world's easiest email marketing Learn more @ http://www.myemma.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array question
http://www.php.net/manual/en/language.types.array.php
If you mean having an array inside an array, of course ? $arr =
array(array('data')); ?. There you have an array inside another
one, 'data' will be here $var['0']['0'].
If you meant using an array item as the key in another array,
then you do it as with a normal var ? $arr1[$arr2['0']]; ?.
Remember not to quote $arr2 just as you wouldn't a quote a var
when using it as the key.
In your question you're mixing both:
Example: $paArgs['aCheckBoxes[$iIndex]['sName']']
Unquote 'aCheckBoxes[$iIndex]['sName']' and put the $ sign in
front:
$paArgs[$aCheckBoxes[$iIndex]['sName']]
I hope this helped.
Cristian
Robin Kopetzky wrote:
Good morning all!!
Can you nest an array within an array??
Example: $paArgs['aCheckBoxes[$iIndex]['sName']']
Thank you in advance.
Robin 'Sparky' Kopetzky
Black Mesa Computers/Internet Service
Grants, NM 87020
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[PHP] How to do Javascript for the HTML/PHP Array (See Below)
Hi Fellas! Here's the clipping of an article about putting HTML variables into a PHP Array upon submission. Right now, I'm having trouble getting Javascript to do the error checking of each of the HTML variable if it's variable name is treated as an array. Anyone know of a workaround to it where Javascript can detect and work with the HTML Array-like variable name??? --snip-- 3. How do I create arrays in a HTML form? To get your form result sent as an array to your PHP script you name the input, select or textarea elements like this: input name=MyArray[] input name=MyArray[] input name=MyArray[] input name=MyArray[] Notice the square brackets after the variable name, that's what makes it an array. You can group the elements into different arrays by assigning the same name to different elements: input name=MyArray[] input name=MyArray[] input name=MyOtherArray[] input name=MyOtherArray[] This produces two arrays, MyArray and MyOtherArray, that gets sent to the PHP script. It's also possible to assign specific keys to your arrays: input name=AnotherArray[] input name=AnotherArray[] input name=AnotherArray[email] input name=AnotherArray[phone] The AnotherArray array will now contain the keys 0, 1, email and phone. Note: Specifying an arrays key is optional in HTML. If you do not specify the keys, the array gets filled in the order the elements appear in the form. Our first example will contain keys 0, 1, 2 and 3. See also Array Functions and Variables from outside PHP. --snip-- -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] How to do Javascript for the HTML/PHP Array (See Below)
if f = your form then f.elements['MyArray[]'] is a javascript array of input elements. Scott Fletcher wrote: Hi Fellas! Here's the clipping of an article about putting HTML variables into a PHP Array upon submission. Right now, I'm having trouble getting Javascript to do the error checking of each of the HTML variable if it's variable name is treated as an array. Anyone know of a workaround to it where Javascript can detect and work with the HTML Array-like variable name??? --snip-- 3. How do I create arrays in a HTML form? To get your form result sent as an array to your PHP script you name the input, select or textarea elements like this: input name=MyArray[] input name=MyArray[] input name=MyArray[] input name=MyArray[] Notice the square brackets after the variable name, that's what makes it an array. You can group the elements into different arrays by assigning the same name to different elements: input name=MyArray[] input name=MyArray[] input name=MyOtherArray[] input name=MyOtherArray[] This produces two arrays, MyArray and MyOtherArray, that gets sent to the PHP script. It's also possible to assign specific keys to your arrays: input name=AnotherArray[] input name=AnotherArray[] input name=AnotherArray[email] input name=AnotherArray[phone] The AnotherArray array will now contain the keys 0, 1, email and phone. Note: Specifying an arrays key is optional in HTML. If you do not specify the keys, the array gets filled in the order the elements appear in the form. Our first example will contain keys 0, 1, 2 and 3. See also Array Functions and Variables from outside PHP. --snip-- -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] How to do Javascript for the HTML/PHP Array (See Below)
Ah! So I do this to make it work where count can be any number... f.elements['MyArray[]'][count].value That does work now. It's been mind boggling to do the conversion between JavaScript, HTML and PHP when it come to an array but I'm learning. :-) Thanks a million... Scott F. Marek Kilimajer [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] if f = your form then f.elements['MyArray[]'] is a javascript array of input elements. Scott Fletcher wrote: Hi Fellas! Here's the clipping of an article about putting HTML variables into a PHP Array upon submission. Right now, I'm having trouble getting Javascript to do the error checking of each of the HTML variable if it's variable name is treated as an array. Anyone know of a workaround to it where Javascript can detect and work with the HTML Array-like variable name??? --snip-- 3. How do I create arrays in a HTML form? To get your form result sent as an array to your PHP script you name the input, select or textarea elements like this: input name=MyArray[] input name=MyArray[] input name=MyArray[] input name=MyArray[] Notice the square brackets after the variable name, that's what makes it an array. You can group the elements into different arrays by assigning the same name to different elements: input name=MyArray[] input name=MyArray[] input name=MyOtherArray[] input name=MyOtherArray[] This produces two arrays, MyArray and MyOtherArray, that gets sent to the PHP script. It's also possible to assign specific keys to your arrays: input name=AnotherArray[] input name=AnotherArray[] input name=AnotherArray[email] input name=AnotherArray[phone] The AnotherArray array will now contain the keys 0, 1, email and phone. Note: Specifying an arrays key is optional in HTML. If you do not specify the keys, the array gets filled in the order the elements appear in the form. Our first example will contain keys 0, 1, 2 and 3. See also Array Functions and Variables from outside PHP. --snip-- -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] array encapsulate
I'd like to do this, but it produces an error:
if ($_POST{[detail][11][116]} !$_POST{[detailtext][19][114]}) {
so I'm left doing this
if ($_POST[detail][11][116] !$_POST[detailtext][19][114]) {
How can I encapsulate the array so it is a multi-dimensional array and not just
a string length?
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Re: [PHP] array encapsulate
if ($_POST[detail][11][116] !$_POST[detailtext][19][114]) {
How can I encapsulate the array so it is a multi-dimensional array and
not just
a string length?
I'm not exactly sure what you're array structure is but that syntax is
correct.
$_POST['key1']['key2']...
Larry
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Re: [PHP] array encapsulate
How do I know it won't just assume that $_POST[detail][11][116] means the
116th character in the string $_POST[detail][11]?
Larry E . Ullman wrote:
if ($_POST[detail][11][116] !$_POST[detailtext][19][114]) {
How can I encapsulate the array so it is a multi-dimensional array and
not just
a string length?
I'm not exactly sure what you're array structure is but that syntax is
correct.
$_POST['key1']['key2']...
Larry
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Re: [PHP] array encapsulate
Bill wrote: How do I know it won't just assume that $_POST[detail][11][116] means the 116th character in the string $_POST[detail][11]? Because $_POST['detail'][11] is an array (or it should be). If you're in doubt, make sure it is with is_array(). -- ---John Holmes... Amazon Wishlist: www.amazon.com/o/registry/3BEXC84AB3A5E/ php|architect: The Magazine for PHP Professionals www.phparch.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array Push and Keys
On Thu, 28 Aug 2003 18:14:39 -0400, you wrote:
While($row=mysql_fetch_array($res) {
That *should* create the array above, but as I mentioned array_push does not
seem to be taking the keys I just get a Parse error message for the
line. (the first array_push)
Ahem. Count the brackets? :)
(On a style point, your code would be easier to read for bugs like this if
you added some whitespace.)
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