on 2/27/02 2:51 AM, Marco Coletta at [EMAIL PROTECTED] appended the
following bits to my mbox:
I would like to upgrade to newer version of php, ho can supply detailed
instructions.
You can start here:
http://www.php.net/manual/en/installation.php
And if you have difficulty, post your
That may work for a single field in a record that is NULL, but I'm trying to
join two tables, and report the lines that do not have an entry in the
second thus:
Question Table
Q_idQuestion
1Question 1
2Question 2
3Question 3
4Question 4
Response Table
Robin
That may work for a single field in a record that is NULL, but I'm trying to
join two tables, and report the lines that do not have an entry in the
second thus:
Question Table
Q_idQuestion
1Question 1
2Question 2
3Question 3
4Question 4
I am wondering if there is a good tutorial on how to use php to make users
come from a page before they can access another. For instance, say you have
one page called index.php which contains a form that once filled in links to
a confirmation page to verify the users data was entered correctly
Hi there :) I use session variables to do this, once the user has logged in
and you know they are who they say they are, set a session variable using
session_register(isloggedin);
$isloggedin = yes;
And at the top of every page you want protected simply do a check to see if
it is set or not.
Hi there :)
I believe you can connect to an Advantage Db through unified odbc functions.
Check the manual at
www.php.net
Cheers, Joe :)
Stewart Gateley [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Has anybody had any luck or tried connecting to ADS from PHP?
Hello-
We are currently developing a PHP client for the Advantage Database Server
and expect to have it released in approx. 2 weeks. As mentioned in the
previous post, it will access ADS through a unified ODBC method.
Please contact me directly for additional information or if you are
Can you accomplish this without having the user logged in? I am unconcerned
with whether or not the user has logged in, I simply need the user to not be
able to bypass a page with a form to go directly to the end page which will
connect and store the form contents into a db.
Thanks in advance,
Hello!!
What I would do is have both the 2 page and the last page on the the
same page!!
All my pages are only two...a form page and a processing page...that's
it
However
You could also have a variable pass from page to page, like a hidden
variable, either in a form, or with
hi jas,
am sure you asked this before and i already replied. Anyway miles posted
this which is more elaborated than the one i proposed:
***
This is at the top of every file requiring an authenticated user on one of
our sites:
? include(secure.php)?
and secure.php consists of this, all on one
Hi,
I've come across a problem and I'm affraid that I'm lacking the skills of
writing proper SQL queries in order to solve this. I'm building a little
search engine for my site (yes, from scratch! It doesn't have to be the
best, but I think that for my personal use it will be enough) and the bit
Jas,
Try looking into the $HTTP_REFERER variable, for example;
?
if ($HTTP_REFERER != PageItShouldBeComingFrom.php) {
Header (Location: index.php);
}
// blah blah
?
Cheers
-Original Message-
From: jas [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, 27 February 2002 6:04 PM
To:
$article_query = mysql_query(select article_name, article_text from
articles where article_name LIKE '%$q%' ORDER BY $q_count DESC ) or die
(mysql_error());
Put the ORDER BY $q_count DESC in your SQL statement and that will make
MySQL do the sorting for you. PHP will get it already sorted.
Greetings everyone,
I've been having a very frustrating problem over the past few months that
I've ***finally*** tracked down the cause of
Any questions/comments/thoughts/ideas you can provide would be *greatly*
appreciated.
Symptoms:
- IE, Opera, Lynx all report page cannot be displayed
when I do:
session_start();
session_register('signor');
session_register('username');
I get:
Warning: Cannot send session cookie - headers already sent by (output
started at /var/www/html/index.php:3) in
/var/www/html/index.php on line 14
Warning: Cannot send
Ryan,
you need to make all of those calls *before* ANY output has been sent by
your script, otherwise you can't send a header any more. so the TOP of a
script might look like
?php
session_start();
$signor = $monsieur + $madame;
session_register(signor);
// the rest of your code goes here
?
html
Can anyone tell me how to access linux system commands using php. Tried the
system() cmd but no luck. Does it require a wrapper to work?Thanks,
JJ
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Have a look at trying backticks.
http://www.php.net/manual/en/language.operators.execution.php
[TK]
-Original Message-
From: Jeremiah Jester [mailto:[EMAIL PROTECTED]]
Sent: Thursday, 28 February 2002 12:37 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] accessing system cmds w/ PHP
JJ,
I seem to recall most people saying that the shorthand works best
$output = `chmod -R 777 *';
HTH
beau
// -Original Message-
// From: Jeremiah Jester [mailto:[EMAIL PROTECTED]]
// Sent: Thursday, 28 February 2002 9:37 AM
// To: [EMAIL PROTECTED]
// Subject: [PHP-DB] accessing
Hi.
I need some guidance for writing an effective query (instead of processing
through PHP).
I lets says I have two tables, tblCDs and tblOrders.
tblCD
cdID| cdTitle | cdArtist
--
1 | Great Hits | Bon Jovi
2 | Forever
SELECT
tblCD.cdID,
tblCD.cdTitle,
tblCD.cdArtist
FROM
tblCD,
tblOrders
WHERE
tblOrders.cdID = tblCD.cdID
AND tblCD.cdID NOT IN (
SELECT cdID FROM tblOrders
)
The support for this sort of nested query will very
Hello...
Try exec()
I know it works moving files.
Dan
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, February 27, 2002 7:37 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] accessing system cmds w/ PHP
Can anyone tell me how to access linux
select * from tblCd
where cdId not in (select distinct cdId from tblOrders);
On Thu, Feb 28, 2002 at 12:37:49PM +1000, Adam Royle wrote:
Hi.
I need some guidance for writing an effective query (instead of processing
through PHP).
I lets says I have two tables, tblCDs and tblOrders.
Hi,
Woud someone be able to help?
I can't for the life of me figure out how to get this to store a image path
instead of the image itself. In other words I want to make this so that the
user isn't uploading an image. I want to use a radio or check box that they
pick from.
Any help would be
Hi,
I assumed that you was used MySQL for database. With MySQL you
can used this SQL to find different row
select tblcd.* from tblcd left join tblorder on
tblcd.cdid=tblorder.cdid where tblorder.cdid is null
sommai
At 12:37 28/2/2002 +1000, Adam Royle wrote:
Hi.
I need
Hi folks,
i'm currently developing an module which provides an object based
access to databases content (does not mean that i use OOP)
for example we have defined an class descriptor for person,
which specifies, that an person-record consists of the fields
ID (which is the OID, fetched from
I have a question, let's say i have my main page (so called) called
indexphp
I have also displayed a buttonin indexphp, which i will used the
onClick event to trigger a windowopen function to the same main
page, indexphp (but with parameters)
input type=button value=Add New Records
Sorry about the priority, guess it was set unintentionally, out of habit from my
working place, I think.
Beau Lebens wrote:
please don't use the important (X-Priority header) on your message - we're
all important here :)
anyway, your question - it's actually JavaScript that you want, and
Hello guys,
anyone can help me with this kind of error log
tail -f /www/log/error_log
[ cut ]
PHP Warning: Failed to write session data (files) Please verify that
the current setting of sessionsave_path is correct (/tmp) in Unknown on
line 0
PHP Warning: Failed to write session data (files)
Hi,
I have an Image table in a MySQL database that will be used to store the
location of all images used on my site Some images will relate to an
Article table (articleid) and some images may relate to a Member table
(memberid)
As it's possible that there may be an articleid that is the same as
check if YOU can write/read on tmp.
Erwien Samantha Y a écrit :
Hello guys,
anyone can help me with this kind of error log
tail -f /www/log/error_log
[ cut ]
PHP Warning: Failed to write session data (files). Please verify that
the current setting of session.save_path is correct
the permision in /tmp it's OK ,
because my session it's work already in /tmp , but the i stil got an
error message bellow.
wIEn
[EMAIL PROTECTED] wrote:
check if YOU can write/read on tmp.
Erwien Samantha Y a écrit :
Hello guys,
anyone can help me with this kind of error log
tail -f
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