SpiderWebb,
One posting to one list is enough...
I dont know if this is possible in PHP (Newbie) im working on a project
where each product has 3 diffierent prices depending on the amount sold so
say for example 1- 100 price A 101-299 price B and above 300 Price C.
What
I need to be able to
I dont know if this is possible in PHP (Newbie) im working on a project
where each product has 3 diffierent prices depending on the amount sold so
say for example 1- 100 price A 101-299 price B and above 300 Price C. What
I need to be able to do is increment an mysql database field each time an
Hi Brett,
[please keep conversations on the list - someone else might have helped you
more promptly - others might benefit from following the conversation]
This is how I have the code written:
if ($num_results 0){
fopen(http://www.vcathletics.org/Misc/AdminMenu.htm,r;);
}
If I go to
Alex,
Congrats at getting Apache off the ground.
Lots of advice here about hardware, but...
Are both your WS and Svr Windows boxes? If so, which OpSys?
If you want both to share access to the Internet, consider modem sharing
or ICS (Internet Connection Service - IIRC - M$ not v.generous on advice
Hi all,
I have a problem i know you can help me with.
I have this flushet out from a loop command:
Year: 2000 ID: 14 Value: 300
Year: 2002 ID: 11 Value: 640
Year: 2002 ID: 10 Value: 100
Year: 2003 ID: 11 Value: 200
Year: 2004 ID: 11 Value: 150
Year: 2005 ID: 11 Value: 250
I need PHP
Hi,
I'ld suggest this:
// inside your loop
$array[$year] += $value;
HTH,
Bastian
Martin Allan Jensen schrieb:
Hi all,
I have a problem i know you can help me with.
I have this flushet out from a loop command:
Year: 2000 ID: 14 Value: 300
Year: 2002 ID: 11 Value: 640
Year: 2002
Bastian Vogt [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Hi,
I'ld suggest this:
// inside your loop
$array[$year] += $value;
HTH,
Bastian
Lets say $year is 2000
There is not defined index 2000 at $array.
It is going to be undefined offset.
--
PHP
Lets say $year is 2000
There is not defined index 2000 at $array.
It is going to be undefined offset.
Hm... I think it's gonna work, but if it's one of the don'ts in
progamming style, could you tell me why you shouldn't do this and how to
make it better (and nice)?
Regards,
Bastian
--
PHP
Bastian Vogt [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Lets say $year is 2000
There is not defined index 2000 at $array.
It is going to be undefined offset.
Hm... I think it's gonna work, but if it's one of the don'ts in
progamming style, could you
How do I strip from a string? Actually, I need to change it to a
legal
char so I can send it via the URL.
Look at
www.php.net/urlencode
or
www.php.net/rawurlencode
---John W. Holmes...
PHP Architect - A monthly magazine for PHP Professionals. Get your copy
today. http://www.phparch.com/
But, now i need to make another loop where it takes the key [2000]
and put's it into $year and takes the value 300 and put it into
$value
Can you help me with it, am really not good at arrays.
you can assign the variables like this:
$year = '2000'
$value = array['2000'] //gets the
for($i=0;$i5;$i++){
for($j=0;$j5;$j++){
$new_array[$i]+=$j;
}
}
for($i=0;$i5;$i++){
print($new_array[$i]);
}
this works, so Vogt's solution should solve your problem
Lets say $year is 2000
There is not defined index 2000 at $array.
It is going to be undefined offset.
-Original Message-
From: Martin Allan Jensen [mailto:[EMAIL PROTECTED]]
Sent: 10 December 2002 12:41
But, now i need to make another loop where it takes the key
[2000] and put's it into $year and takes the value 300 and
put it into $value
Can you help me with it, am really not
You might read the database to see how many have been sold previously
and put that into a PHP variable. Add the amount that you'd be
incrementing it by (I assume it's possible that it will increment by
more than one at a time), determine the price point, and then update
the row with both the new
List,
I've been looking on and off for now for a class or plug-in or something
that will allow an application user to define table specifications (#rows,
#columns, spanning, etc) then allow them to enter table data (headers, body
data, title, footer, etc.) in a graphical representation of the
I can't seem to get more then 255 characters to be sent back from a field
in our MSSQL database, unless the fields is a TEXT type, which is very
inefficient. Anyone know a fix? (I've already tried modifying the max size
variables in the php.ini under the MSSQL section.)
--
Adam Voigt
You didn't mention it so did you check http://www.phpclasses.org - there's a
lot of good stuff there - you will need to register however.
HTH
Rich
-Original Message-
From: Hutchins, Richard [mailto:[EMAIL PROTECTED]]
Sent: 10 December 2002 14:52
To: [EMAIL PROTECTED]
Subject: [PHP-DB]
this little snippet works for me.
mssql_query(set textsize 65536);
HTH
Jeff
Adam Voigt
Didn't work, thanks anyway.
On Tue, 2002-12-10 at 10:43, [EMAIL PROTECTED] wrote:
this little snippet works for me.
mssql_query(set textsize 65536);
HTH
Jeff
Uncommented, and set to the max value (2147483647). No effect.
On Tue, 2002-12-10 at 10:57, [EMAIL PROTECTED] wrote:
Adam.
are these lines uncommented in your php.ini? They are under [MSSQL]
; Valid range 0 - 2147483647. Default = 4096.
I am working on an application and I am not having a lot of luck
getting a form to behave the way I want. I am trying to keep the form self
referencing, not sure if that is the correct terminology. The form is an
approval form that queries a database to create a list of checkboxes.
Adam
IIRC this is a known problem with the native php SQL Server APIs which were built
using the original TDS drivers based on v6.x of SQL Server which did not support
NVARCHAR data types... if you can't change the datatype to TEXT then try a cast.
Failing that does it work if you use ODBC
Adam
IIRC this is a known problem with the native php SQL Server APIs which were built
using the original TDS drivers based on v6.x of SQL Server which did not support
NVARCHAR data types... if you can't change the datatype to TEXT then try a cast.
Failing that does it work if you use ODBC
I know this is off the topic of dbs but I can't get the mail function to work, I get
this error. Does the script need to be in the apache root?
Thanks,
Eddie
Warning: Failed to Receive in c:\program files\apache
group\apache\htdocs\aircharter\working\verify_login.php on line 69
Hi list
Anyone knows if the bug reported in http://bugs.php.net/bug.php?id=7634
has been fixed (the bug : lock table and mysql_pconnect used together could
hang the server if the tables have not been unlocked before script terminates)?
Thanks
R
--
PHP Database Mailing List
HI... sorry to interrupt again...
I have another ridiculous question...
I have a text file in my machine... and a php-file in my host (such as
host.sk etc..)
I want to use my php-file to access my text file in my machine
directly...
I used fopen, and fread stuff... but didn't work
Btw,
Can I define a global variable in a function and then successfully reference
it in the rest of the page? I know that globals are usually defined in the
page scope and referenced in a function by specifying them as globals, but it
seems logical that a variable can be created and given a value
Well I don't know how to make a socket connections... can you give me an
example please...
Sorry to bother you :D
--www.kapsul.org--
DuFronte
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, December 10, 2002 8:36 PM
To: [EMAIL PROTECTED]
-Original Message-
From: Jim [mailto:[EMAIL PROTECTED]]
Sent: 10 December 2002 18:51
Can I define a global variable in a function and then
successfully reference
it in the rest of the page?
Yes.
(Why didn't you just try it?)
Cheers!
Mike
I tried fsockopen()... but it doesn't work too...
--www.kapsul.org--
DuFronte
-Original Message-
From: dufronte [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, December 11, 2002 1:49 AM
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] read a file from local harddisk
I am attempting to UPDATE a table and I have having absolutely ZERO
success. Here is the query:
$tmp = $_POST['sbcuid'].-.$_POST['system'][$a];
$update = UPDATE accounts SET atime='NOW()' WHERE
\id-sys\='.$tmp.';
echo $update;
$result1 =
Looks like this groups saves the day again.
John Krewson [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
mssql_pconnect cannot be closed as you mentioned:
http://www.php.he.net/manual/en/function.mssql-pconnect.php
I am using this as well, calling MSSQL on a
$tmp = $_POST['sbcuid'].-.$_POST['system'][$a];
$update = UPDATE accounts SET atime='NOW()' WHERE
\id-sys\='.$tmp.';
echo $update;
$result1 = mysql_query($update, $Prod) or die(mysql_error());
echo mysql_affected_rows();
Try:
$update = UPDATE accounts SET atime=NOW() WHERE id-sys='$tmp';
is it a mysql field type of datetime?
if so, you may want to use this instead
$timestamp=date(Y-m-j H:i:s);
$update = UPDATE accounts SET atime='$timestamp' WHERE id-sys='$tmp';
that puts the current timestamp in mysql format for entry into your table.
Cheers
Jason
-Original Message-
SCOTT,
I am attempting to UPDATE a table and I have having absolutely ZERO
success. Here is the query:
$tmp = $_POST['sbcuid'].-.$_POST['system'][$a];
$update = UPDATE accounts SET atime='NOW()' WHERE
\id-sys\='.$tmp.';
echo $update;
$result1 = mysql_query($update, $Prod) or
select query question
OK, I have 3 tables
Products Table
prodid
fgnumber
name
description
Faqs Table
faqid
question
answer
FaqsRelatedToProducts Table
fpid
fgnumber
faqid
I want to select all the faq question and answer pairs that
SCOTT,
The list's crystal ball filter is down for maintenance.
Show us the tbl schema and the debug print of $update.
Then we won't be firing blind!
=dn
I understand that the column name does not normally need quotes, but
without quotes on the column name I get a mysql error message about no
I have definitely isolated the problem. If I change the column name
that the match is being performed on from 'id-sys' to 'id_sys' I can execute
the query without having to worry about quoting the column name and
everything works. I think that I am just going to leave the column name
I'm REALLY new at this and someone else actually wrote the following but,
can anyone tem me why this works in Windows but not in Linux? It falls
through to the NO, it's still not working statement. If I remove the $ in
$con from $result = mysql_query(SELECT * FROM mytable WHERE myrow REGEXP
I have definitely isolated the problem. If I change the column name
that the match is being performed on from 'id-sys' to 'id_sys' I can
execute
the query without having to worry about quoting the column name and
everything works. I think that I am just going to leave the column name
Hi guys'n'gals ;)
I am very new to the world of PHP, and still trying to get my foot in the
door. Not doing too bad so far, good fun it all is... but i am having a
problem working out what exactly the problem is here with sessions.
Here is the code for page one of the tutorial, i copied it
Thanks John and Cornelia for a fast response :). I have edited my ini file
as you suggested, and I changed the code around a bit and experimented a
bit more with it, but I still have some problems. This is exactly how the
file looks;
?
// page1.php
session_start();
hello burton,
can you send session.save_path from your php.ini here?
a.v.l
Hartleigh Burton [EMAIL PROTECTED] schrieb im Newsbeitrag
news:[EMAIL PROTECTED]...
Thanks John and Cornelia for a fast response :). I have edited my ini file
as you suggested, and I changed the code around a bit and
Is PHP running as a module in Apache/IIS? If yes then you will need to
bounce your web server to pick up the new ini settings...
Rich
-Original Message-
From: Hartleigh Burton [mailto:[EMAIL PROTECTED]]
Sent: 10 December 2002 14:01
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Still having
Warning: open(/tmp\sess_1df563d6d8c8b4b16534c438251e7107, O_RDWR) failed:
No such file or directory (2) in E:\Webroot\tutorial\page1.php on line 3
Warning: open(/tmp\sess_1df563d6d8c8b4b16534c438251e7107, O_RDWR) failed:
No such file or directory (2) in Unknown on line 0
Warning: Failed to
John hit the nail right on the head, i was editing the windows\php.ini,
after all thats what the manual said PHP uses. When in actual fact it was
the copy of php.ini I had in my PHP root directory.
Anyways, cheers for the help :)
Hartleigh Burton
www.channel-x.org
--
PHP Database Mailing
Try:
SELECT DISTINCT F.question, F.answer
FROM Faqs AS F, FaqsRelatedToProducts Table AS FP
WHERE F.faqid = FP.faqid
DTH?
Ignatius
- Original Message -
From: Michael Knauf/Niles [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, December
Hi there everyone,
I use the following code to collect date from multiple tickboxes on my form:
if (count($selection) = 1) {
for ($i=0;$icount($selection);$i++) {
echo $selection[$i];
}};
$selection is the ID number and passes fine, but what I need it to do is
query my DB via the above query
I am trying to figure out how to take the data that I have collected in
a form and format it into another page basically a bunch of tables and
graphics, and then email that form to a specific email address.
I have been able to get it to collect, place into the page, but now how
to email the
Try the mail function, you can get creative and use html as well. It's documented:
http://www.php.net/manual/en/function.mail.php
Ryan
-Original Message-
From: Ryan Holowaychuk [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, December 10, 2002 4:23 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB]
Spiderwebb [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
I dont know if this is possible in PHP (Newbie) im working on a project
where each product has 3 diffierent prices depending on the amount sold so
say for example 1- 100 price A 101-299 price B and above
This is where I am stuck, I can not get the variables to be placed in to
the email.
/* message */
$message = '
html
head
titleQuote Request/title
/head
body
font size=4 face=Arial, Helvetica, sans-serif font color=#FF
table width=105% border=0 cellspacing=3 cellpadding=2
tr
Hi,
When you use single quotes to define your strings php variables will not
be replaced.
Try
$message = ...$customer..;
You will have to escape all double quotes used in the string (\) or use
single quote.
- Frank
This is where I am stuck, I can not get the variables to be placed in
to
All my reasons to ask you all about this ,because I'm currently
developing a web-base multiplayer game with PHP. In my game, I created
my Own browser with VB so user will probably don't know which files
they're executed (for security reasons). But the problem is, I really
hard too figure out how
Hi everyone,
I am giving a shot at a typical login script, which plucks usernames,
passwords, and access levels from 2 databases. The passwords database uses
md5 encryption, I havn't much of a clue what I am doing with that though.
My real problem, if thats not it, lies with the verification. I
On Wednesday 11 December 2002 13:10, Hartleigh Burton wrote:
? if ($submit) {
$db = mysql_connect(localhost, dbname, dbpassword);
mysql_select_db(mydb, $db);
$db_user =
SELECT ID FROM dbusers
WHERE UserName = '$username';
$db_pass =
SELECT
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