[PHP-DB] odbc_columns()
Yo ho hoodbc_columns() on DB2! Now, it returns a resource ID, as expected but you cannot call odbc_fetch_row() on it or it'll segfault. Hmm.. I filled out a report on this, since I cracked open the php_odbc.c file and verified that all the data's coming back from DB2, and that the bindcols() method is working. After more playing, I still cannot seem to actually USE the results of an odbc_columns() call on DB2 since just about everything "fetch-related" segfaults. Is there another method or set of methods that I'm missing? Thoughts? Ideas? -Szii -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] Connectivity to AS/400
There's been a lot of talk about this recently. Check the archives for the last 2 months, and PHPBuilder.com Last I heard, you needed DRDA(DB2 Connect) installed, as well as the runtime client. Also on the client - DB2 Application Development package. Use this to compile PHP --with-ibm-db2=path. Make sure you run the CATALOG commands on the client so that it can find the AS400 database. 'Luck! -Szii At 10:41 AM 2/4/2001 -0800, Pete Lancashire wrote: I'm going to be trying to connect to the native DB2 database in a AS/400 So far thats all I know about the IBM side. Can someone give me a short update on what options I have ? TIA !!! -pete -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] db2 with php
Well, if it says that it's looking for it in /etc/httpd/modules then it's obviously not looking in /home/db2inst1/sqllib/lib, eh? Try a symlink... "ln -s /home/db2inst1/sqllib/lib/libdb2.so.1 /etc/httpd/modules/libphp4.so/libdb2.so.1" Or copy the library. Or I think you can add a line into /etc/ld.so.conf too. -Szii At 11:08 PM 2/4/2001 -0500, Chris Book wrote: Hello, I've installed db2 and created the default instance at /home/db2inst1/. PHP is compiled with the --with-ibm-db2 option, however when I try to start apache I get the message: "Cannot load /etc/httpd/modules/libphp4.so into server: libdb2.so.1: cannot open shared object file: No such file or directory" when I try to load the php4 module. libdb2.so.1 exists in /home/db2inst1/sqllib/lib/ so I'm not sure why php can't find it. Can anyone help me with this? Thanks, Chris Book [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] Tricky one - include($identifer);
http://www.php.net/manual/en/function.eval.php Couple of notes from the userbase show how to include HTML in a php $content passed to eval() 'Luck. -Szii At 05:07 PM 2/8/2001 +1300, Simon Helson wrote: Hey guys - I've been mulling this one over for a few days now - and still haven't come up with anything intelligent to sort it... I'm building a site where you can edit the content on the fly - basically allowing you to write code and add pages without touching a telnet or ftp session etc etc etc... So I end up with chunks of text stored in my database - which I then pull out and (currently) do the following with: pull text out of database to $content echo $content; This works real nice when the text is plain HTML - makes setting up a site nice-n-easy.. however, I want certain people to be able to put php code in their snippets using ? and ? as you would when editing a normal php file. This is where my $echo falls over - none of the php code is executed (as you would expect). What I really want to be able to do is: include($content); I haven't been able to find any ways to do this though - eval() looks for just php code and include() and require() look for filenames. I really don't want to store my snippets as files - but I guess I may have to if I can't find a way to pull em out of a database and include() em. Any help would be much appreciated Cheers Simon -- THE WORST HOMING PIGEON This historic bird was released in Pembrokeshire in June 1953 and was expected to reach its base that evening. It was returned by post, dead, in a cardboard box eleven years later from Brazil. -- Stephen Pile, "The Book of Heroic Failures" -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP-DB] mysql_insert_id()
Is there a known way to "reset" this field? If I make a call and it succeeds, then it should be set. If it fails, shouldn't it at least be reset to 0 or -1 instead of simply the last successful insert? Is this the expected behavior? -Szii -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] Updating multiple forms
Off the top of my head, and it's 3am local so take this with a grain of salt, but I think that this will work... Update Table1, Table2 SET Table1.column1 = 'blah', Table2.column1='foo' WHERE Table1.ID = x AND Table2.ID = y 'Luck -Szii - Original Message - From: Lester June Cabrera [EMAIL PROTECTED] To: Shahmat Dahlan [EMAIL PROTECTED]; PHP-DB [EMAIL PROTECTED] Sent: Wednesday, April 18, 2001 2:29 AM Subject: Re: [PHP-DB] Updating multiple forms Multiple tables with different fields? Hmm... I don't know of any shortcut in doing it. At 05:27 PM 4/18/01 +0800, Shahmat Dahlan wrote: Yes, this is only applicable if I only have one table. What if I need to update multiple tables? Lester June Cabrera wrote: I guess you need to use the UPDATE command UPDATE tablename SET column1 = 'some value' WHEREcolumn2 = 'another value'; Did I get what you mean? Lester At 05:02 PM 4/18/01 +0800, you wrote: Apologies... Lemme rephrase my question, How do I update data into multiple tables in MySQL? Shahmat Lester June Cabrera wrote: Hi, What do you mean by updating data into multiple forms? Do you mean displaying data in multiple HTML forms? Lester At 04:53 PM 4/18/01 +0800, Shahmat Dahlan wrote: How do I update data into multiple forms? Thanks in advance.. Shahmat -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] MySQL transactions?
The newest MySQL code has transactions via their implementation of Sleepcat's BDB tables. If you use BDB tables instead of MyISAM you can do transactions. Check the syntax on CREATE TABLE for details on how to create BDB tables. 'Luck -Szii - Original Message - From: Gary Huntress [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Wednesday, April 18, 2001 8:36 PM Subject: Re: [PHP-DB] MySQL transactions? a common question. This might help http://www.mysql.com/documentation/mysql/bychapter/manual_Compatibility.html #Missing_Transactions -- Regards, Gary "SuperID" Huntress === FreeSQL.org offering free database hosting to developers Visit http://www.freesql.org "Bas Cancrinus" [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Hi, Is it possible to define a set of mysql function-calls as a transaction that commits if no error occurs and rolls back otherwise? Thanks in advance, Bas -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] PHP question needing info
*begins dousing Paul S with water before the flames start* -Szii - Original Message - From: Paul S [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Friday, April 20, 2001 3:04 PM Subject: [PHP-DB] PHP question needing info I have a question that I need help with. The question is that how do I execute a script in PHP. __ Do You Yahoo!? Yahoo! Auctions - buy the things you want at great prices http://auctions.yahoo.com/ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] reword my question
Read The Fine Manual? exec(); -Szii - Original Message - From: Paul S [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Friday, April 20, 2001 4:13 PM Subject: [PHP-DB] reword my question How do I execute a shell script in php? I just started to use php and I am learning it on the fly for a project. __ Do You Yahoo!? Yahoo! Auctions - buy the things you want at great prices http://auctions.yahoo.com/ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] Can't get my head around this problem...
Perhaps...?
$x = 0;
while ($x 7)
{
if (!isset($myArray[$x]))
{
$myArray[$x] =0;
}
}
-Szii
- Original Message -
From: Tyrone Mills [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, April 24, 2001 3:58 PM
Subject: [PHP-DB] Can't get my head around this problem...
Hello all...
I've got what is probably a stupid question, it's a problem I can't seem
to
get my head around it. Any help will be greatly appreciated.
I'm pulling a count of connections from a MySQL database and the day of
the
week it occurred on. Now the result set doesn't include empty values, so
if
there were connections on only 2 days, I only get 2 rows returned, if
there
were connections on 4 days, I get 4 rows returned. You get the idea...
Here is the PHP code I am using the get the data:
$sql = SELECT COUNT(*), (DAYOFWEEK(dialer_login_date) -1) AS DAYOFWEEK
FROM
dialer_login WHERE dialer_id = $dialer_id AND
WEEK(date_format(dialer_login_date, '%Y-%m-%d'),0) = WEEK('$last_week',0)
GROUP BY DAYOFWEEK;
$result = db_query($sql);
while ($daily_count = db_fetch_array($result))
{
$lastweek[] = $daily_count[COUNT(*)];
$day[] = $daily_count[DAYOFWEEK];
}
For the sake of this question, let's say that there were connections on
only
2 days, so we get a result set with 2 rows. Something like this:
COUNT(*) DAYOFWEEK
8 2
3 4
That's great, but I need the array $lastweek to have the value 8 in
element
2 and the value 3 in element 4 and all other elements (0,1,3,5,6) as zero.
As it sits, they are in elements 0 and 1 respectively.
I get this:
$lastweek[] = 8,3
I need this:
$lastweek[] = 0,0,8,0,3,0,0
Now I've written all manner of wild and wonderful loops that iterate
through
either $lastweek or $day and try and build a proper array. Invariably
something doesn't work right. I'm sure I'm grossly over complicating this,
but I am at my wits end. Any thoughts or ideas are most welcome.
Thanks!!
Tyrone Mills
UNIX is user-friendly, it's just picky about who its friends are...
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Re: [PHP-DB] Flash+PHP search error
This is not really related to PHPDB Send me the code . It looks like you have an unbalanced double-quote. Same thing's happening with your footer, too. Should be an easy fix. -Szii - Original Message - From: Brian Tegtmeier [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Monday, May 14, 2001 2:37 PM Subject: [PHP-DB] Flash+PHP search error I am currently in the progress of setting up a page for my client located at http://64.77.185.160/main.html which integrates a PHP search function to find keywords on a page. The problem I am running into now is when I goto that main.html page, I get this \n, $header); } } ? message above my Flash movie and have no idea why it is causing it on the Unix server with PHP 4.05. The thing is the PHP search and the Flash movie work fine for searches even with that message, its just that I'm looking for a way to remove it. The funny thing about it is it shows up only on IE and Netscape 6 for the PC/Mac but Netscape 4.76 doesn't show that text. weird. P.S. If you notice the Search Results open in the top frameset, its ok becuase I know that already. I wanted to fix this before altering the Flash to have it point to the bottom frame. Thanks for your time! :) __ FREE Personalized Email at Mail.com Sign up at http://www.mail.com/?sr=signup -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] 'the missing character'
I don't understand xcount().
Instead of xcount(), why not use strlen()?
Say we have 7100 chars
If you step through, first pass
$i = 0
$chunk_count = 2
$start = 0
$final = 3500
$text[] is chars 0-3499
second pass
$i = 1 // from $i++
$chunk_count = 2
$start = 3501 // problem is here - note the endpoint of the last pass in
$text[]?
$final = 3499
$text[] is chars 3501-7000 // what happened to char 3500 itself?
Remember that substr() takes a start point, and an offset - not an endpoint.
So after the first pass, you've read in 0-3499 as is correct, but you have
an extraneous if() clause that inc's your start by one, and then adds 3500.
Drop the second if($start == 0) clause which sets $start to 1.
'Luck
-Szii
- Original Message -
From: Jimmy Brake [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, May 15, 2001 9:54 PM
Subject: [PHP-DB] 'the missing character'
Hi!
Does anyone know of a function in php that will take a chunk of text and
seperate it into 'chunks' preferably returning it in an array?
The reason being is that I have some columns(oracle) that are set to
varchar2(4000) and I have text that is 4000+ AND :-) I cannot change it to
another format.
I was unable to find a chunk maker so I built one.
function chunk_maker($text)
{
// have to count the number of characters, if over 3500 characters
need to split into chunks of 3500 characters
$count = xcount($text);
if($count 3500)
{
$chunk_count = $count/3500;
//need to clean up the $chunk_count by removing the
trailing decimals and
//adding one to the total to make sure we do not loose in
characters
$chunk_count = floor($chunk_count)+1;
$i=0;
$start=0;
while($i != $chunk_count)
{
// err well this helps to make sure we get the
correct amount of characters
if($start == 0)
{
$final = 3500;
} else {
$final = 3499;
}
//now we need to make the chunks and stick them in
an array
$text2[]=substr($text,$start,$final);
// err well this helps to make sure we get the
correct amount of characters
if($start == 0)
{
$start=1;
}
$start=$start+3500;
$i++;
}
} else {
$text2[] = $text;
}
return($text2);
}
function xcount($text)
{
global $debug;
foreach (count_chars($text) as $my_value)
$length=$length+$my_value;
tracker($length);
return($length);
}
If I just failed to find the right functions please let me know, otherwise
please help! :-)
Jimmy Brake
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Re: [PHP-DB] Filling mysql db with access db
Export as a comma-delimited file, explode() the file one line at a time along commas, and use insert via normal methods. Not sure if MySQL has a parser for comma-delim (probably does) but this way you have more control over how it goes in. -Szii - Original Message - From: Gabriel [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Wednesday, May 16, 2001 8:47 AM Subject: [PHP-DB] Filling mysql db with access db How can i import data from an access database to a mysql db. Thanks in advance, Gabriel. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] 'the missing character' YIKES
Oh, btw, if you're splitting along chars, make sure you don't munge your data TOO much. Breaking mid-word can be annoying, esp if it's to be displayed as a page. I have a splitter I wrote that'll either break along word boundries, or along sentance boundries. Haven't pounded it yet, but it seems to work... -Szii - Original Message - From: Jimmy Brake [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Tuesday, May 15, 2001 9:58 PM Subject: [PHP-DB] 'the missing character' YIKES I forgot to detail the problem, I loose a character every once in a while basically every 3500 characters. Jimmy Brake Cool Tools and Stuff Critical Path Inc. Making your job easier -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] mySQL Addition Problem
Sorry, last message was a little vague.
Your SQL will fail because of the ',' after the SET clause.
Therefore affected_rows shows 0, and inserts a new row.
Then when you match with the LIKE clause, it's going to match
multiple times.
Miles, you were SO close with #2. =)
-Szii
- Original Message -
From: Miles Thompson [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, May 16, 2001 3:50 PM
Subject: Re: [PHP-DB] mySQL Addition Problem
Dammit, that code looks right.
So
1. Have you tried it at the mysql console? What results?
2. How accurately does day match $day? Have you tried = instead of LIKE?
Maybe it's doing it twice?
3. Is day distinct? How do you know you have only one?
When you tested with 2, assuming i had a value of 1, was the result 5 or
6?
Strange - Miles Thompson
At 05:43 PM 5/16/01 -0400, SubvertTRL wrote:
I am making a simple script that counts votes per day for a site and uses
a
simple database, All i want to do is increment the field by one. the
first
time i run the script it works, after that it doubles it. so instead of
1,
it adds 2. i know its doubling it because i tried adding 2, 3, and 4 and
it
doubled all those... the field is a BIGINT UNSIGNED, i've tried it with
just INT, nothing seems to work, i used to have PHP get the field value,
increment it, then update the row in the database with the new number, it
doubleed it that way. now i use straight mySQL code to do it all in one
shot, still doubles it.. can any one help me???
heres my code... less database info :)
$results = mysql_query(UPDATE trlvotes SET i=i+1, WHERE day LIKE
'$day');
if (mysql_affected_rows($results) == 0){
mysql_query(INSERT INTO trlvotes (id, day, i) VALUES (null, '$day',
1));
}
mysql_close();
you can email me at [EMAIL PROTECTED]
thanks!
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Re: [PHP-DB] Storing duplicate checkbox values
I got around it by using a standard naming scheme.
(This will work if you have LESS than $num_items, but not more. If you
have LESS, then it'll just hit the not set while loop more.)
Oh, ignore the XMP They're just there to keep Win-based systems from
trying to interpret the code.
XMP
$num_items = 80;
for ($x = 0; $x $num_items; $x++)
{
echo INPUT TYPE='checkbox' name='f_checkbox_ . $x . ' value='$x'
}
This will give you $num_items checkboxes.
Then after the POST/GET, you can do this...
for($x = 0; $x $num_items; $x++)
{
$proto = 'f_checkbox_' . $x;
if (isset($$proto)) // It's checked, therefore it's set - if it's not
checked, it's just not set.
{
echo Set\n;
}
else
{
echo Not set\n;
}
}
/XMP
This will give you Set/Not Set lines 80 times.
G'luck..
-Szii
- Original Message -
From: John Starkey [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, May 16, 2001 5:42 PM
Subject: [PHP-DB] Storing duplicate checkbox values
Ok This one has me stumped.
I'm working on a survey for an author. There is already a total of 35
questions and their corresponding columns in the main table. She has three
other questions that have identical checkboxes, 30 each. I want to put
them in the second table and just make reference to the record_id from the
main table and the question number, so that I don't end up with 90 columns
in this second table.
Anyone have any suggestions on a quick way to do this? Obviously the
checkboxes will need to have unique names, but the columns won't. I'm
pretty fried on this and ready to take the not so efficient route of
having 90 columns.
This is a MySQL/PHP4 job.
Thanks,
John
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Re: [PHP-DB] Need Database Design help
Hmmit may be easier to just do this... Group Definition Table DefID GroupName User Definition Table --- UserID GroupMember Table --- MapID UserID GroupID Then you can assign a user to a group by inserting a new record into the GroupMember Table where UserID is the user, and GroupID is the new group. If you want to search all users in Group West you could say (assuming Group Definition Table is populated with 1 North 2 South 3 East 4 West ) SELECT UserID from GroupMemberTable WHERE GroupID = 4; or if you wanted to check multiple groups, SELECT UserID from GroupMemberTable WHERE GroupID IN (4,2,3); The map table may get huge depending on the number of users/groups, but it's a possibility. -Szii - Original Message - From: Doug Schasteen [EMAIL PROTECTED] To: php-db list [EMAIL PROTECTED] Sent: Friday, May 18, 2001 1:13 PM Subject: [PHP-DB] Need Database Design help I'll try to simplify my problem so that this isn't a long read and is easy to understand. Tree Table: -- node_id node_name parent_id I use the above table's rows to create an online tree in php and javascript. The parent_id column is just a pointer to a the node_id of which the current node branches off of. The tree is used to group users, which we store in another table. Users Table: user_id node_id Now, if I wanted to compare side by side the users of one node to the users of another node, I would do a select * from tree, users where users.node_id = tree.node_id and node_id = 'x' for each node id. I created the database this way so that I could do comparisons with polling results. My problem comes when the tree gets large and I want to compare a group of nodes to another group of nodes. For instance, the tree splits out into southwest and northwest divisions, and under each of those it splits out into the groups where the users reside. There will be no users linked directly to the southwest or northwest nodes, but I want to compare all the users that are in groups that are PART of the northwest node to all users that are in groups that are part of the southwest node. I could probably do a Where parent_id = 'node id of northwest division but what if the tree splits up even farther than that? What if the tree originally splits into North and South divisions, and under each of those divisions it goes into East and West, and then splits into groups. I'd have to be able to know the parent's of the parents in a single SQL statement. I don't see how I can do this without redesigning the database, and I'm not even sure what I would need to change in order to get the database to work. If anyone out there is a database design expert and can see my mistake right away, please help me out. - Doug Schasteen -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] RE: Storing Code in a db?
XML would be perfect for this. You store the XML in the database (usually a BLOB/CLOB/Long VARCHAR/etc) and your script pulls the XML out, and parses it there. You can have a set of input forms written in PHP which'll generate the XML for you. Of course, this assumes some knowledge of XML, but theoretically you could do it with a flat file format (like comma/tilde delimited) and just store the string in the database. It's trivial to write a PHP script that generates PHP directly... $str = echo \hi!\;; // you can use single-quotes if you're more comfortable with them $str .= echo \Done!\;; // note that it's got a ; INSIDE the string...it's PHP in there, after all eval($str); If you wanted to pre-generate it, I don't see any reason why you couldn't addslashes() the code, and INSERT it that way. Pull it back out, stripslashes() it, and eval() it. Voila! -Szii - Original Message - From: Mark McCray [EMAIL PROTECTED] To: olinux [EMAIL PROTECTED]; php-db [EMAIL PROTECTED] Sent: Monday, July 02, 2001 5:54 PM Subject: Re: [PHP-DB] RE: Storing Code in a db? Here was the application I was thinking of creating for my organization. We wanted to make an online survey tool. Where you can create a survey, with sections, possibly subsections, questions, and acceptable answers. It's easy enough to create this stuff each and every time, but it's ridiculously tedious. So why not make an application that does it automatically. So we were thinking that you kind of have to define the different types of questions/answers that can be used in the survey. For example, a straight text field, multiline text field, 5 radio button selection, 5 option pull-down, Yes/No radio button, checkboxes, etc... So in defining the types of questions/answers, we thought it might be cool to define each type of answer and the code that goes along with generating it. So when defining the survey questions, you tell it that the question has a 3 radio button answer, and the system would pull code from the database to help generate the question/answer html dynamically when someone goes to the survey. I know you could store the functions as includes, but just thought it would be cool if people could store the code in the database, because there might just be an answer type that I haven't yet thought to program. Marky on 7/1/01 2:34 PM, olinux at [EMAIL PROTECTED] wrote: Couldn't you just store the php commands as a txt file and then use a SSI [server side include]? olinux It would be very convenient to be able to store PHP (or any other server side code) in a database, then retrieve and execute it. I store a lot of website content with embedded HTML commands in a database. Being able to store PHP code in the database as well would be very convenient. Lets think about something: if we put some code in a field and then we out the of code from code put in temporal file and then include in our principal code :))) but i have a doubt eval funcion we work with functions printf, echo? i don't think so. The only way I can think of doing it would involve a lot of very messy parsing out of the php commands. I expect that would take way to much processing time. I don't imagine that would work for entire functions either. Maybe just individual PHP commands. Any ideas Thanks! Rita _ Do You Yahoo!? Get your free @yahoo.com address at http://mail.yahoo.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] kinda unrelated, but curious...
Most of the time, by word of mouth. Other than that, scan the 'net, look on the job boards. If you're new to the field, put your name in a couple recruiters hands. Sure, it's not freelance, and you won't make as much, but a couple jobs and you start to become known. Once you're known, and have a portfolio, it just gets easier from there on out. Also look for part time work from home PHP jobs. You can pick up some reputation that way before quitting your REAL job. These are a real PITA to find, but they do exist. Oh, and let all your friends know that you're a PHP/web coder looking for work. It's amazing how many people know people that know people and you end up with work. 8-) -Szii - Original Message - From: David Balatero [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Monday, July 02, 2001 11:27 PM Subject: [PHP-DB] kinda unrelated, but curious... ...where do you people pick up freelance jobs? Any input on this? - David Balatero [EMAIL PROTECTED] - -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] Not Really A DB Question
This is not VB - this is better. Probably want to name all of your text fields something similar, since they'll be mixed in with the drop downs, radio buttons, etc... Check $HTTP_POST_VARS and $HTTP_GET_VARS in your form's target. -Szii - Original Message - From: Peter J. Krawetzky [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Friday, July 27, 2001 5:30 AM Subject: [PHP-DB] Not Really A DB Question How do you loop through all the text objects in a PHP script? In otherwords, I want use logic to check the value of each textbox without specifically referencing the actual object name. Visual Basic has this type of logic. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP-DB] MySQL Modules and multiple database
Opening multiple databases on the same database machine seems unsupported. While you CAN do it, it has a tendency to reuse the last connection even in lieu of a specific database. Right now we're using mysql_db_query() to get around it, but with that becoming deprecated, we need to find anothe solution. Anyone have any ideas/thoughts? Thanks. -Szii -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] MySQL Modules and multiple database
Done both. In fact, I create an object which has 2 database objects in it. If I dump the objects, I can WATCH as they merge and point at the same database. I go back to using mysql_db_query() and everything's fine. It would appear that the mysql_select_db() is not persisting. If you call it on two different links, it's seems to modify both links. Almost like it's global *shrug* -Szii - Original Message - From: Paul Burney [EMAIL PROTECTED] To: Szii [EMAIL PROTECTED]; php mailing list [EMAIL PROTECTED] Sent: Monday, August 13, 2001 2:28 PM Subject: Re: [PHP-DB] MySQL Modules and multiple database on 8/13/01 1:56 PM, Szii ([EMAIL PROTECTED]) wrote: Opening multiple databases on the same database machine seems unsupported. While you CAN do it, it has a tendency to reuse the last connection even in lieu of a specific database. Right now we're using mysql_db_query() to get around it, but with that becoming deprecated, we need to find anothe solution. Before each query (from a different database), you can call the function; mysql_select_db($database_name, $connection_id) You can also specify the connection id for your queries: mysql_query($query, $connection_id) Just make sure that you select the db before each query otherwise a query will use the last selected database. Sincerely, Paul Burney +-+-+ | Paul Burney | P: 310.825.8365 | | Webmaster Programmer | E: [EMAIL PROTECTED] | | UCLA - GSEIS - ETU | W: http://www.gseis.ucla.edu/ | +-+-+ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] db's war
IMHO, having run all three, I summarize them like this... MySQL, Postgres Fast, open source, free. Good for projects, small-medium sized businesses, and playing around. DB2 Good, solid database. Their UI needs work (it's 100% java-based) and it's significantly more complex (and pricier) than the OpenSource ones. However, it IS slower. It can handle MUCH larger datasets. It can be run in a clustered environment. It has the robustness for large business, but can be handled by a medium sized one. Oracle Often referred to as the Cadillac of Databases, this thing's a beast. Expect to not only pay through the nose for it, but also for help/contractors/DBAs to set it up, tune it, maintain it, and handle the problems. It -can- be setup by smaller firms, but definately do your homework here. Go with someone who's been doing it a while and is in the enterprise space you want to be in. It's also got a HUGE set of applications and modules that can run on top of the raw database (no one else really has this from a single vendor) but that's a whole new can of worms, costs, problems, etc. My personal favorite is DB2. The key to DB2, though, is not the common sense things like do the training classes and get a book. The key is in their UI stuff. Ditch it. Learn the command lines, the scripting tools, and the database connectivity stuff. Sure, you can do simple things with their UI, but it's going to restrict you in a lot of ways. DB2 is big enough for real enterprise work but small enough not to get out of hand. However, DB2 is almost the cost of Oracle (purchasing) but your recurring costs are considerably cheaper. Oracle does have the advantage of being first and so the knowledge base/finding people who know a bit about Oracle is easier, and they DO have all of the applications modules which DB2 currently does not have. (Rumors are that they're looking at expanding into that realm a little more, but I don't know anything for sure.) If you need a consolodated system for the whole company, well, Oracle wins that hands down. If you just need a super fast lightweight database, OpenSource. For everything else, DB2. And if you need a kick-arse track-anything-anywhere-anyhow system, look at Camstar Systems, which will handle backends of both DB2 and Oracle. It's better than the Oracle MES/tracking modules. -Szii - Original Message - From: Paul Gardiner [EMAIL PROTECTED] To: [EMAIL PROTECTED]; Sommai Fongnamthip [EMAIL PROTECTED] Sent: Tuesday, September 18, 2001 3:16 AM Subject: Re: [PHP-DB] db's war Hi, I'm also very interested in other peoples thoughts and reactions to this. We've been hit twofold, we run on SCO which Caldera has now taken over and also use Informix which IBM have acquired, whom I'm sure will try to make us move to DB2 at some point. The other trouble we have is a lot of our programs are written in Informix 4GL and so will be a pain to convert. I would have liked to of had a DB independent 4GL but this was already in place before I got here. The only real other choice like you say is Oracle but I've always heard bad things regarding pricing where they are concerned. They had a special offer on for anyone who jumped over two them quickly but I like to 'look before you leap' :) We plan to start looking at possible alternative's before we're forced to change and so would be glad to hear from anyone else who is in the same boat so to speak. Best Regards, - Paul - - Original Message - From: Sommai Fongnamthip [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Tuesday, September 18, 2001 2:36 AM Subject: [PHP-DB] db's war hi I'd like to survey php commnunity about how do you think about merge between informix and ibm? Did there remain only 2 major dbms (oracle and db2)? do you think MySQL will be the leader with next version 4? SF -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] Learning PHP Sessions
You do not need to destroy session variables. You can
session_unregister() them, if you'd like.
$session_start();
$foo = Hi;
session_register(foo);
Next page...
if (isset($foo))
{
echo $foo; // will print Hi if done correctly
session_unregister(foo);
}
Sessions are automatically destroyed when the client-side browser
shuts down and the garbage collector runs. If you want to force
a session deletion, use session_destroy(). Use it with caution, though,
since it's usually better to let the garbage collector do the work
periodically instead of cleaning up each session individually.
Check out http://www.php.net/manual/en/ref.session.php
'Luck
-Szii
- Original Message -
From: Matthew Tedder [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, October 30, 2001 12:30 PM
Subject: [PHP-DB] Learning PHP Sessions
?php
/*
Hi,
I'm new to PHP and am having trouble understanding how to use PHP
sessions. My book tells in near the beginning how to start them and
register
session variables, but I can't figure out how to destroy a session or
later
read those session variables. I'm also trying to do this across frames,
but
can't even get it to work within a single page.
Here's what I've learned so far and what my problems are:
*/
/* To start a session */
session_start();
/* To register a session variable */
session_register(myvar);
$myvar = some value;
/*
PROBLEM #1: From the above commands, I get a $PHPSESSID that seems to be
globally available for use, but I cannot seem to read my values back out
of
the registered session variable from anywhere... I tried:
*/
print $myvar\n; /* and absolutely nothing is printed */
/* To destroy a session */
session_destroy();
/*
PROBLEM #2: This says there is no session to destroy. It's rather
strange
because I can still print the $PHPSESSID value..
I've attached my code...
*/
?
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Re: [PHP-DB] Another Drop down question
The easiest way...
$getlist = mysql_query(SELECT distinct Writer FROM stories);
echo select name=\WriterName\\n;
echo option value='All'Search All/option;
while ($row = mysql_fetch_array($getlist)) {
echo ' option value='.$row[Writer].''.$row[Writer]./option\n;
}
echo /select\n;
-Szii
- Original Message -
From: Kim Kohen [EMAIL PROTECTED]
To: PHP [EMAIL PROTECTED]
Sent: Wednesday, March 27, 2002 5:18 PM
Subject: [PHP-DB] Another Drop down question
Hello all,
I'm trying for the first time to use a dynamically created popup menu from a
mysql database. The menu is of (article) writers' names and will be used in
a select query.
Using snippets of code I've gleaned from here and the mysql list, I've the
popup working fine but I'd like to include either a blank entry or a 'Search
all Writers' entry in the menu and this is where I'm stuck.
The code I have is:
$getlist = mysql_query(SELECT distinct Writer FROM stories);
echo select name=\WriterName\\n;
while ($row = mysql_fetch_array($getlist)) {
echo ' option value='.$row[Writer].''.$row[Writer]./option\n;
}
echo /select\n;
If anyone could point me in the right direction or direct me to appropriate
documentation I'd be most appreciative.
Cheers and thanks
kim
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Re: [PHP-DB] need some help...
Not really a database question, but why not...
Step 1: Clean up the code...
a) Convert all double-quote to single quotes in the HTML portion.
I usually use doubles for PHP and singles for HTML. I hate
having to escape quotes.
b) Use of spacing and indentation.
old
**
div align=left
table border=0 cellpadding=0 cellspacing=0 width=95%
tr
td width=100%p
font face=Tahoma, Verdana, Arial, Helvetica size=1img
src=/images/menu-reviews.gif width=137 height=20brbr?php
$db = mysql_connect( db, **, **);
mysql_select_db( net3dual_reviews,$db);
$r = mysql_query(SELECT * FROM hwureviews ORDER BY num DESC LIMIT 7);
$max = mysql_query(select max(num) from hwureviews,$db);
while($a=mysql_fetch_array($r)) {
printf (nbsp;nbsp;nbsp;nbsp;a href=\%s\img src=\%s\
border=\0\/abrnbsp;nbsp;- a
href=\%s\%s/abrbr,$a[url],$a[picurl],$a[picurl],$a[title])
;
}
?
/font/p
/td
/tr
/table
/div
**
new
**
div align='left'
table border='0' cellpadding='0' cellspacing='0' width='95%'
tr
td width='100%'p
font face='Tahoma, Verdana, Arial, Helvetica' size='1'
img src='/images/menu-reviews.gif' width='137' height='20'brbr
?php
$db = mysql_connect( 'db, **, **);
mysql_select_db( net3dual_reviews,$db);
$r = mysql_query(SELECT * FROM hwureviews ORDER BY num DESC LIMIT 7);
$max = mysql_query(select max(num) from hwureviews,$db);
while($a=mysql_fetch_array($r))
{
printf (nbsp;nbsp;nbsp;nbsp;a href=\%s\img src=\%s\
border='0'/abrnbsp;nbsp;-
a
href='%s'%s/abrbr,$a[url],$a[picurl],$a[picurl],$a[title]);
}
?
/font/p
/td
/tr
/table
/div
**
Since you have to put a string value, assign all output to a single string called
$output.
Note that I moved your printf() to an echo, and simplified your output string by
preassigning
variables. An extra step, but greatly enhances readability and maintenance...
Also remember that the .= is an append operator whereas = is assignment.
even newer
**
// Assign the stuff before...
$output =
div align='left'
table border='0' cellpadding='0' cellspacing='0' width='95%'
tr
td width='100%'p
font face='Tahoma, Verdana, Arial, Helvetica' size='1'
img src='/images/menu-reviews.gif' width='137' height='20'brbr
;
?php
$db = mysql_connect( 'db, **, **);
mysql_select_db( net3dual_reviews,$db);
$r = mysql_query(SELECT * FROM hwureviews ORDER BY num DESC LIMIT 7);
$max = mysql_query(select max(num) from hwureviews,$db);
while($a=mysql_fetch_array($r))
{
$url = $a[url];
$picurl = $a[picurl];
$title = $a[title];
// add in each link to the review
$output .= nbsp;nbsp;nbsp;nbsp;
a href='$url'
img src='$picurl' border='0'
/a
brnbsp;nbsp;-
a href='$picurl'
$title
/a
brbr;
}
?
// finish the structure HTML
$output .=
/font/p
/td
/tr
/table
/div
;
// Now fopen() the file, fputs the $output, and fclose() the file.
**
http://www.php.net/manual/en/function.fopen.php
http://www.php.net/manual/en/function.fputs.php
http://www.php.net/manual/en/function.fclose.php
Party on!
-Szii
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Re: [PHP-DB] Complex (for me) table join - help please?
Try SELECT TableA.Category, TableB.PersonID FROM TableA LEFT JOIN TableB ON (TableA.CategoryID = TableB.TableAID) WHERE TableB.ClientID = $cid ORDER BY TableA.Category ASC LEFT JOIN states that you should return all TableA, inserting NULL for TableB if there is no match. 'Luck -Szii - Original Message - From: Peter Westergaard [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Friday, April 19, 2002 2:46 PM Subject: [PHP-DB] Complex (for me) table join - help please? I'm trying to perform a join that seems like it should be simple, but I'm just ending up in a morass. Hopefully someone who's standing a step or two back from the problem can help me solve this one... What I have: Table A (Category): with a 3-tier category structure: -Nature -Category -Sub-Category Table B (Responsibility): with a reference to Table A, and a client id, and the id of a person responsible for that Sub-category for that client. -TableA-id -Client-id -Person-id So, what I want is a simple select which will fetch for me all rows in (Category) with the relevant person from (Responsibility) if there is one for a specific Client, but with a blank in that column if there isn't one. ie. (Category) has 10 entries (let's call them Ca-Cj), and (Responsibility) has 5 entries for Client 1 (Ca,Cb,Cc,Cd,Ce) and 3 entries for Client 2 (Cd,Ce,Cf). When I run the select for Client 1, I'd like to see... Ca - person Cb - person Cc - person Cd - person Ce - person Cf - Cg - Ch - Ci - Cj - And when I run the same select for Client 2 I'd like to see: Ca - Cb - Cc - Cd - person Ce - person Cf - person Cg - Ch - Ci - Cj - I tried a basic outer join type select, and of course for Client 1 I miss Cf, and when I use it for Client 2 I miss Ca-Cc. Anyone able to sort me out here? I need to use a basic Select (instead of building a temp table or using variables in a PHP script) because another database process that I don't control needs to do the same thing. Think it's possible, or am I going to have to go and insert records into Responsibility for every entry in Category for every Client, resulting in (#Categories x #Clients) rows? (The latter idea sure doesn't make me happy, but it would be 'easier' to build, if not to maintain. (And, as you can appreciate, since I'm not the one maintaining it, I'm like THAT CLOSE from just going that way and saying 'screw em'!) Hopefully, -Peter Westergaard -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Re: Retrieve information from mutiple tables
mysql_fetch_array() brings back an associative array by default.
It's not $result[0] but instead $results[column_name]
Also, you can use is_set() on subarrays.
if ((isset($result[col1]))
(is_array($result[col1]))
(sizeof($result[col1])))
{
// do stuff here
}
Remember that the above SEQUENCE is important. If you deviate from it,
you may get unknown variable or other error messages.
-Szii
- Original Message -
From: Prodoc [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, April 22, 2002 2:38 PM
Subject: Re: [PHP-DB] Re: Retrieve information from mutiple tables
Does the simple case (without specifying MainID) work?
And are you pretty sure that $row['MainID'] actually holds a valid value?
Have you tried printing the whole of the above query to see what it actually
contains?
If it looks valid try copy-paste that query into the mysql command-line to
see what comes up.
I tried the query in the mysql command-line and this does give me the
data I want to get.
$row['MainID'] does hold a valid value is this should mean I doing
something wrong at displaying the values, doesn't it?
I just started using mysql and php it will probebly be a stupid mistake
I made.
I get one or more values back using the mysql command-line and I'm
trying to display the values one by one by using $result =
mysql_fetch_row (res) (I tried mysql_fetch_array as well) but it only
displays one result by using $result[0].
$result[1] or higher doesn't give me anything, what could be the problem?
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Re: [PHP-DB] auto-increment question
This is more of a MySQL question, but you can set the column default for the auto_increment column to something other than 1. Look up the SET DEFAULT clause of the table create / alter table calls. -Szii - Original Message - From: Dan Swensen [EMAIL PROTECTED] To: php [EMAIL PROTECTED] Sent: Monday, April 22, 2002 10:21 PM Subject: [PHP-DB] auto-increment question Hi all, I'm wondering if there is a way to start an auto-increment field at a number other than 1. I'm working on a table meant to store large amounts of users, each with their own unique ID, but my employer wants the UIDs to be a four- digit number, rather than starting at 1 -- but they still need to auto- increment. Can this be done, or do I need to find a workaround (and if so, can anyone suggest anything?) Thanks in advance, Dan -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] please help!
You're not evaluating the variable correctly...
Instead of...
$site = .row['site'].;
It should be...
$site = $row[site];
Or
$site = $row['site']
I'm not sure why you have leading and trailing
periods, either. Looks like you were trying to
do string appends, but they're not being used
correctly
'Luck
-Szii
- Original Message -
From: Evans, Josh [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, April 23, 2002 11:26 AM
Subject: [PHP-DB] please help!
Database: sites
I have to columns: id and site. I will have approx 800 entries in the db
when I am finished and what I want it to do and start with 1st entry and
ping the site and display in a table on the screen if it was able to ping
site or not.
This is what I have so far. My problem is I am not sure how to make it
select a entry, perform the ping, record the results, and then continue to
the next entry.
?
$db = mysql_connect(localhost,,) or die(Problem connecting);
mysql_select_db(josh) or die(Problem selecting database);
$query = SELECT * FROM josh.sites;
$result = mysql_query($query) or die (Query failed);
$numofrows = mysql_num_rows($result);
for($i = 0; $i $numofrows; $i++) {
$row = mysql_fetch_array($result);
if($i % 2) { //this means if there is a remainder
$site = .row['site'].; its not pulling a site from the
database?
$host1 = `ping -n 4 $site`;
if (eregi(reply, $host1)) {
echo $site is up!;
} else {
echo ($site is down!);
}
echo (p);
?
Please Help!
Josh Evans
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Re: [PHP-DB] User getting superuser access. ack!
Well, that looks like a problem within the findLoginType()
call. Since it's not been included, it's hard to help you. :)
'Luck
-Szii
- Original Message -
From: J. Wharton [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, April 23, 2002 11:09 AM
Subject: [PHP-DB] User getting superuser access. ack!
I am having a problem where from certain browsers, a user gets the superuser
access, but from mine, she gets normal access. Help!
Here is a snippet of my code:
//findLoginType returns a single character code stored in the user table for
each user.
//variable $username=$REMOTE_USER as previously defined.
$hm=findLoginType($username);
if ($hm=='s')
{echo meta http-equiv=\refresh\ content=\0; URL=supaIndex.php\;}
else
{ //do normal user stuff}
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Re: [PHP-DB] User getting superuser access. ack!
It looks like $indinfo *may* get set to FALSE
and passed back on a failed query. I'd vardump()
the $username in findLoginType() and make sure
it's going in correctly, and that your output is not
FALSE coming out.
I also seem to remember something about
== not being an equality operator for strings.
Seems like, and I may be incorrect here, that
$a == $b is only true if they reference the same
object in memory. Perhaps there's something
about that for $a == 's'
For giggles, use strcmp() and see if it helps.
That == issue is about 1-2 years old by now,
and I'm not sure if it ever changed, or what the
status is currently.
'Luck!
-Szii
- Original Message -
From: J. Wharton [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, April 24, 2002 8:51 AM
Subject: Re: [PHP-DB] User getting superuser access. ack!
here's the code for findLoginType($username):
function findLoginType($username)
{
$dbusername=foo;
$password=bar;
DBConnect($dbusername, $password); //sets up a connection with the mysql
database
$userquery=select * from users where username='$username';
$theresultsplz=mysql_query($userquery) or die (mysql_error());
$indinfo=mysql_fetch_object($theresultsplz);
return $indinfo-usertype;
}
[EMAIL PROTECTED] wrote in message
01c701c1eb00$3fdf7120$[EMAIL PROTECTED]">news:01c701c1eb00$3fdf7120$[EMAIL PROTECTED]...
Well, that looks like a problem within the findLoginType()
call. Since it's not been included, it's hard to help you. :)
'Luck
-Szii
- Original Message -
From: J. Wharton [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, April 23, 2002 11:09 AM
Subject: [PHP-DB] User getting superuser access. ack!
I am having a problem where from certain browsers, a user gets the
superuser
access, but from mine, she gets normal access. Help!
Here is a snippet of my code:
//findLoginType returns a single character code stored in the user table
for
each user.
//variable $username=$REMOTE_USER as previously defined.
$hm=findLoginType($username);
if ($hm=='s')
{echo meta http-equiv=\refresh\ content=\0; URL=supaIndex.php\;}
else
{ //do normal user stuff}
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Re: [PHP-DB] Mssql/Sybase errors
hehehe, you recoded PHP to reconnect to MSSQL, but you forgot to redo your connection stuff. Sybase error: means that you're connecting to Sybase and not MSSQL. *wink* 'Luck -Szii - Original Message - From: [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Thursday, April 25, 2002 10:18 AM Subject: [PHP-DB] Mssql/Sybase errors Hello. I have recently installed the freetds package and reconfigured PHP to connect to MSSQL. I am running a simple join query on two tables and I get the following error. bWarning/b: Sybase error: 'REQ' is not a recognized OPTIMIZER LOCK HINTS option. (severity 15) in myFile.php on line b29/bbr REQ is one of the tables in the database. here is the query, which works fine in MS Query Analyzer. Anyone run up against this problem? mssql_query(select REQ.DESCR, BUSINESS_AREA.DESCR, REQ_NUM from REQ INNER JOIN BUSINESS_AREA. ON (REQ.BUSINESS_AREA = BUSINESS_AREA.BUSINESS_AREA) WHERE REQ.BUSINESS_AREA = '$area'); I can run basic select queries, but came into this when i started using JOIN. Many thanks, Jeff my set up is PHP4.1.2/Apache/Unix/Freetds 0.53 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] FORM not inserting data
put in a var_dump($sql);die(); right after
$result = mysql_query($sql);
Then copy/paste it into mysql's command line util, and see what
you get.
-Szii
- Original Message -
From: Neil [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, April 25, 2002 6:34 PM
Subject: [PHP-DB] FORM not inserting data
Help. Help
Please, Please tell me what I am doing wrong here...I have a form to input data but
it is not posting ithere is the code. It
seems to work no errors but a query show no new additions to the table.
$sql = INSERT INTO employees (first,last,address,date_of_birth,sex,age,telephone,
parent_guardian_name,parent_guardian_workplace,work_telephone,emergency_information_contact,
list_physical_conditions_if_any,all_schools_previously_attended,examinations_passed,older_brothers,younger_brothers,older_sisters,yo
unger_sisters,
names_sisters_or_brothers_attending_school) VALUES
('$first','$last','$address','$date_of_birth',$sex','$age','$telephone','$parent_guardian_name','$parent_guardian_workplace',
'$work_telephone','$emergency_information_contact','$list_physical_conditions_if_any','$all_schools_previously_attended','$examinati
ons_passed','$older_brothers','$younger_brothers','$older_sisters','$younger_sisters','$names_sisters_or_brothers_attending_school')
;
$result = mysql_query($sql);
echo Thank you! Information entered.\n;
} else{
// display form
?
Neil
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Re: [PHP-DB] selected problem
When you build the list up, originally, you'll NOT put selected on Choose City, but move it to Alexandria. -Szii - Original Message - From: its me [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Friday, April 26, 2002 1:39 AM Subject: [PHP-DB] selected problem i have the file: edit_profile.php in it i have a form field like this: select name=location OPTION selected value=Choose City/OPTION OPTION value=10-Ramadan10-Ramadan/OPTION OPTION value=15 May15 May/OPTION OPTION value=6-October6-October/OPTION OPTION value=Abou RedesAbou Redes/OPTION OPTION value=Abou-ZabalAbou-Zabal/OPTION OPTION value=Al ArishAl Arish/OPTION OPTION value=Al MahalaAl Mahala/OPTION OPTION value=Al TourAl Tour/OPTION OPTION value=Al-NatrounAl-Natroun/OPTION OPTION value=AlexandriaAlexandria/OPTION OPTION value=AsuitAsuit/OPTION OPTION value=AswanAswan/OPTION OPTION value=BaderBader/OPTION OPTION value=Bani-SweifBani-Sweif/OPTION OPTION value=BelbisBelbis/OPTION OPTION value=Berkeit sabbBerkeit sabb/OPTION OPTION value=CairoCairo/OPTION OPTION value=DahabDahab/OPTION OPTION value=DamanhourDamanhour/OPTION OPTION value=DisoukDisouk/OPTION OPTION value=DumiatDumiat/OPTION OPTION value=Ein SoukhnaEin Soukhna/OPTION OPTION value=El- ManieaEl- Maniea/OPTION OPTION value=FayedFayed/OPTION OPTION value=FayoumFayoum/OPTION OPTION value=High DamHigh Dam/OPTION OPTION value=HurghadaHurghada/OPTION OPTION value=InshasInshas/OPTION OPTION value=IsmaeliaIsmaelia/OPTION OPTION value=Kafr Al ShiekKafr Al Shiek/OPTION OPTION value=KatamiaKatamia/OPTION OPTION value=LuxorLuxor/OPTION OPTION value=MansouraMansoura/OPTION OPTION value=MarabellaMarabella/OPTION OPTION value=MaraquiaMaraquia/OPTION OPTION value=Marsa matrouhMarsa matrouh/OPTION OPTION value=Met GhamrMet Ghamr/OPTION OPTION value=MonofiaMonofia/OPTION OPTION value=MoustorodMoustorod/OPTION OPTION value=NubiehNubieh/OPTION OPTION value=Oubour CityOubour City/OPTION OPTION value=Port SayedPort Sayed/OPTION OPTION value=Qanater El Khiraya Qanater El Khiraya/OPTION OPTION value=QliubQliub/OPTION OPTION value=QuanaQuana/OPTION OPTION value=QuesnaQuesna/OPTION OPTION value=RafahRafah/OPTION OPTION value=Ras SidrRas Sidr/OPTION OPTION value=Sadat CitySadat City/OPTION OPTION value=SaqaraSaqara/OPTION OPTION value=Sedi KrierSedi Krier/OPTION OPTION value=Sharm el ShiekSharm el Shiek/OPTION OPTION value=Shebin Al KoumShebin Al Koum/OPTION OPTION value=SuhagSuhag/OPTION OPTION value=SuiezSuiez/OPTION OPTION value=TabaTaba/OPTION OPTION value=TantaTanta/OPTION OPTION value=TebinTebin/OPTION OPTION value=ZafranaZafrana/OPTION OPTION value=ZagazikZagazik/OPTION /select as you can see there is many options:) and i got from my database: $location=Alexandria so i wanted to appear selected,how can i do this?? Rehab M.Shouman - Express yourself with a super cool email address from BigMailBox.com. Hundreds of choices. It's free! http://www.bigmailbox.com - -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Session Problem, Please Help.....
I believe it's because $CLIENTID is not set at ALL before you register it. (ie, isset($CLIENTID) would fail) Therefore it cannot register the variable...there's nothing for it to register or track. Try... $CLIENTID = ; session_register(CLIENTID); $CLIENTID=SOMEVALUE; - Original Message - From: Hayan AL Mamoun [EMAIL PROTECTED] To: PHPList (E-mail) [EMAIL PROTECTED] Sent: Thursday, May 02, 2002 3:15 AM Subject: [PHP-DB] Session Problem, Please Help. Dear all, I have a strange problem: I'm using IIS / WINNT4, PHP4 Please check these two files: -- logon.phtml: ? session_start(); session_register(CLIENTID); $CLIENTID=SOMEVALUE; header(Location: clients/editclient.phtml); ? -- clients/editclient.phtml: ? session_start(); echo CLient ID VALUE IS : $CLIENTID; ? When I run logon.phtml, it must create a session variable called CLIENTID and then move to the second page, which displays this variable. Each time I test this code I start a new instant of the IE and request logon.phtml (in order to create a new session), but it never works from the first time, while if I tested it a second time from the same instance of IE it works???! Please could anyone help, why it dosn't work from the first time? thnkx Hayan -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Re: Spaces Problem php mysql
- Original Message -
From: Hugh Bothwell [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, May 02, 2002 6:23 AM
Subject: [PHP-DB] Re: Spaces Problem php mysql
I've been pounding my head (and the keyboard with searches) over this. Do
I
have to take the first entry apart with string functions to get my desired
end, which is the entire name in one field in the database?
... make sure the value is enclosed in quotes when you try
to insert it into the database, ie
INSERT INTO table ( name ) VALUES ( '$name' )
Make sure you escape out all single quotes in $name.
$name = This is Paul's field.
.
.
.
INSERT INTO table ( name ) VALUES ( '$name' )
Will fail, because you have VALUES ('This is Paul');
Post the full value of $name via var_dump($name) and
var_dump($query) and we'll see what we can find with it.
'Luck
-Szii
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Re: [PHP-DB] Re: Spaces Problem php mysql
AddSlashes() or AddCSlashes()
-Szii
- Original Message -
From: Paul [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, May 02, 2002 4:11 PM
Subject: Re: [PHP-DB] Re: Spaces Problem php mysql
On Thursday 02 May 2002 10:10 am, you wrote:
- Original Message -
From: Hugh Bothwell [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, May 02, 2002 6:23 AM
Subject: [PHP-DB] Re: Spaces Problem php mysql
I've been pounding my head (and the keyboard with searches) over this.
Do
I
have to take the first entry apart with string functions to get my
desired end, which is the entire name in one field in the database?
... make sure the value is enclosed in quotes when you try
to insert it into the database, ie
INSERT INTO table ( name ) VALUES ( '$name' )
Make sure you escape out all single quotes in $name.
$name = This is Paul's field.
.
.
.
INSERT INTO table ( name ) VALUES ( '$name' )
Will fail, because you have VALUES ('This is Paul');
Post the full value of $name via var_dump($name) and
var_dump($query) and we'll see what we can find with it.
'Luck
-Szii
Thank you David and Szii. The urlencode solved the sending problem. But I've
had in the back of my mind to remember to deal with apostrophe's in names for
some time and just haven't done it. Good reminder. Is there any easier way to
do this than looping through each character in a string?
Paul
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Re: [PHP-DB] sql querry problem
Delete from does not work with multiple tables, AFAIK.. -Szii - Original Message - From: andy [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Friday, May 03, 2002 2:02 AM Subject: [PHP-DB] sql querry problem Hi there, I do have 2 tables. One contains an update for the other one. Before inserting I would like to delete all the entries in the old table containing the same country_code like one in the new table. I tryed: delete o.* from Cities_update_imported n, test.cities o where n.country_code = o.country_code But does not work though:-( can anybody help on that? thanx, Andy -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] need help on improving performance on this querry
SELECT DISTINCT L.* from data.languages L, data2.user U WHERE L.id IN (U.language_1, U.language_2, U.language_3) order by name; I believe the IN clause is a shade faster than multiple ORs, but I'm not 100% sure. 'Luck -Szii - Original Message - From: andy [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Tuesday, May 07, 2002 9:38 AM Subject: [PHP-DB] need help on improving performance on this querry Hi there, I do have a user table with 3 languages. I know that I should have put them into a seperate table. I still could, but would take lots of recoding. I discovered, that as soon as I leave out the OR statements the querry takes under 0.2 s. With the two OR it takes on a 1 records about 1.4 s. Is there a way to increase the performance with a different querry? I did already index the fields, but does not look much better though. SELECT DISTINCT L.* from data.languages L, data2.user U where L.id = U.language_1 or L.id = U.language_2 or L.id = U.language_3 order by name Thanx for any help, Andy -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] DB and eval. HELP !!!
foreach($website = mysql_fetch_array($result))
{
$text = You can go here: strong?=$website['originalDomain']?/strong and find
information;
eval($text);
}
You get the idea...
'Luck
-Szii
- Original Message -
From: Bogdan ROMAN [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, May 20, 2002 5:16 AM
Subject: [PHP-DB] DB and eval. HELP !!!
Hello
I busted my a$$ out to figure it out but i had to ask for help.
Considering you have this line in a DB (TEXT field):
You can go here: strong?=$website['originalDomain']?/strong and find information
That needs to be output in a html webpage between two p tags.
How can you eval the ?=$website['originalDomain']? to the contents of
$website['originalDomain'] ?
I've tried this:
print 'p'.preg_replace( '\?=(.*?)\?'esi, '\\1', $row['title'] ).'/p'
Where $row is the result from mysql_fetch_assoc() function and 'title' is the field
containing the above line. If i use the above
line of code (with preg_replace) or if i simply try to eval the code i get errors like:
Warning: Unexpected character in input: '\' (ASCII=92) state=1 in
h:\wwwroot\work\site\website_gen.php(41) : regexp code on line 1
Parse error: parse error, unexpected $ in h:\wwwroot\work\site\website_gen.php(41) :
regexp code on line 1
Fatal error: Failed evaluating code: $website[\'originalDomain\'] in
h:\wwwroot\work\site\website_gen.php on line 41
As you note, it automatiaclly adds slashes to the ['originalDomain']. I tried to
remove them with stripslashes() or even again
preg_replace() but doesnt work.
Please help !!!
Thank you,
Bogdan
Bogdan Roman
email:[EMAIL PROTECTED]
msn:[EMAIL PROTECTED]
yahoo:bogdanbog
website:http://bog.ath.cx
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Re: [PHP-DB] problems 'adding' to MySQL DBs
Here's a hint...ALWAYS use proxies for your query strings.
$query = insert into firsttab (first_name, last_name) values
('$first_name', '$last_name');
mysql_query($query);
var_dump($query); // copy output and paste into the mysql
// command line interface.
You can also use the mysql_error() and mysql_errno() calls
to see what went wrong.
-Szii
- Original Message -
From: cin [EMAIL PROTECTED]
html
body
? php
mysql_connect(localhost, test, testpw);
mysql_select_db(testdb);
msyql_query(insert into firsttab (first_name, last_name) values
('$first_name', '$last_name'));
print ($first_name);
print ( );
print ($last_name);
print (p);
print (blah blah blah);
?
/body
/html
i have used the appropriate grant privileges to ensure said user can indeed
do the requested action in the script.
any help is appreciated.
thanks.
cin
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Re: [PHP-DB] DB and eval. HELP !!!
Oops, minor oversights on my part.
If you're calling eval() in the context of a PHP script, you
don't have to ?= ? the eval'd code...
foreach($website = mysql_fetch_array($result))
{
$text = You can go here: strong$website['originalDomain']/strong and find
information;
}
The above code doesn't even require an eval() call.
Apologies for the confusion..
-Szii
- Original Message -
From: [EMAIL PROTECTED]
To: Bogdan ROMAN [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Monday, May 20, 2002 11:11 AM
Subject: Re: [PHP-DB] DB and eval. HELP !!!
foreach($website = mysql_fetch_array($result))
{
$text = You can go here: strong?=$website['originalDomain']?/strong and
find information;
eval($text);
}
You get the idea...
'Luck
-Szii
- Original Message -
From: Bogdan ROMAN [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, May 20, 2002 5:16 AM
Subject: [PHP-DB] DB and eval. HELP !!!
Hello
I busted my a$$ out to figure it out but i had to ask for help.
Considering you have this line in a DB (TEXT field):
You can go here: strong?=$website['originalDomain']?/strong and find
information
That needs to be output in a html webpage between two p tags.
How can you eval the ?=$website['originalDomain']? to the contents of
$website['originalDomain'] ?
I've tried this:
print 'p'.preg_replace( '\?=(.*?)\?'esi, '\\1', $row['title'] ).'/p'
Where $row is the result from mysql_fetch_assoc() function and 'title' is the field
containing the above line. If i use the above
line of code (with preg_replace) or if i simply try to eval the code i get errors
like:
Warning: Unexpected character in input: '\' (ASCII=92) state=1 in
h:\wwwroot\work\site\website_gen.php(41) : regexp code on line 1
Parse error: parse error, unexpected $ in h:\wwwroot\work\site\website_gen.php(41) :
regexp code on line 1
Fatal error: Failed evaluating code: $website[\'originalDomain\'] in
h:\wwwroot\work\site\website_gen.php on line 41
As you note, it automatiaclly adds slashes to the ['originalDomain']. I tried to
remove them with stripslashes() or even again
preg_replace() but doesnt work.
Please help !!!
Thank you,
Bogdan
Bogdan Roman
email:[EMAIL PROTECTED]
msn:[EMAIL PROTECTED]
yahoo:bogdanbog
website:http://bog.ath.cx
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Re: [PHP-DB] DB and eval. HELP !!!
I'm sorry, I'm having an off day. This'll be my last post on the
subject. *sigh* Apologies up front...
while($website = mysql_fetch_array($result))
{
$text = You can go here: strong . $website['originalDomain'] . /strong and
find information;
echo $text;
}
I'll shut up now... :)
-Szii
- Original Message -
From: [EMAIL PROTECTED]
To: Bogdan ROMAN [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Monday, May 20, 2002 11:21 AM
Subject: Re: [PHP-DB] DB and eval. HELP !!!
Oops, minor oversights on my part.
If you're calling eval() in the context of a PHP script, you
don't have to ?= ? the eval'd code...
foreach($website = mysql_fetch_array($result))
{
$text = You can go here: strong$website['originalDomain']/strong and find
information;
}
The above code doesn't even require an eval() call.
Apologies for the confusion..
-Szii
- Original Message -
From: [EMAIL PROTECTED]
To: Bogdan ROMAN [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Monday, May 20, 2002 11:11 AM
Subject: Re: [PHP-DB] DB and eval. HELP !!!
foreach($website = mysql_fetch_array($result))
{
$text = You can go here: strong?=$website['originalDomain']?/strong and
find information;
eval($text);
}
You get the idea...
'Luck
-Szii
- Original Message -
From: Bogdan ROMAN [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, May 20, 2002 5:16 AM
Subject: [PHP-DB] DB and eval. HELP !!!
Hello
I busted my a$$ out to figure it out but i had to ask for help.
Considering you have this line in a DB (TEXT field):
You can go here: strong?=$website['originalDomain']?/strong and find
information
That needs to be output in a html webpage between two p tags.
How can you eval the ?=$website['originalDomain']? to the contents of
$website['originalDomain'] ?
I've tried this:
print 'p'.preg_replace( '\?=(.*?)\?'esi, '\\1', $row['title'] ).'/p'
Where $row is the result from mysql_fetch_assoc() function and 'title' is the
field containing the above line. If i use the
above
line of code (with preg_replace) or if i simply try to eval the code i get errors
like:
Warning: Unexpected character in input: '\' (ASCII=92) state=1 in
h:\wwwroot\work\site\website_gen.php(41) : regexp code on line
1
Parse error: parse error, unexpected $ in h:\wwwroot\work\site\website_gen.php(41)
: regexp code on line 1
Fatal error: Failed evaluating code: $website[\'originalDomain\'] in
h:\wwwroot\work\site\website_gen.php on line 41
As you note, it automatiaclly adds slashes to the ['originalDomain']. I tried to
remove them with stripslashes() or even again
preg_replace() but doesnt work.
Please help !!!
Thank you,
Bogdan
Bogdan Roman
email:[EMAIL PROTECTED]
msn:[EMAIL PROTECTED]
yahoo:bogdanbog
website:http://bog.ath.cx
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Re: [PHP-DB] JOIN statement not producing expected output
If you're looking to do cross-table joins, I'd advise a good book/class on basic SQL or you're going to get in over your head very very quickly. SELECT * FROM table1,table2; This WILL run, but there's no where clause. Therefore it will return all of table1 matched against all of table 2. SELECT * FROM table1,table2 WHERE table1.col1 = table2.col2; will limit your result set to the match of the two tables (and is an implicit INNER JOIN call.) The SQL language is (mostly) database independant. Here's a link to the mySQL website which'll give some basic info on SELECTs. http://www.mysql.com/documentation/mysql/bychapter/manual_Reference.html#SELECT 'Luck -Szii - Original Message - From: admin [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Monday, May 20, 2002 5:48 PM Subject: [PHP-DB] JOIN statement not producing expected output Okay, now this is my first try on fetching data from two tables, and frankly I'm starting to pull my hair out ;) All I want is to fetch some data from two seperate tables in my database. So far I have tried different approches, and below is what I think should work, but doesn't :( SELECT * FROM table1,table2 This I pasted into phpmyadmin, and it outputted two rows from table2 with ekstra columns at the tail of each row. These ekstra columns was just the same output from table2. Now I have searched the web, but have not found a simple solution for my problem. Any ideas? If you need more info, please let me know :) -Lasse -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] replication questions
From the mySQL Replication docs... snip -- In Version 3.23.15, all of the tables and databases will be replicated. Starting in Version 3.23.16, you can restrict replication to a set of databases with replicate-do-db directives in `my.cnf' or just exclude a set of databases with replicate-ignore-db. -- Two-way replication is not supported yet. http://www.mysql.com/documentation/mysql/bychapter/manual_MySQL_Database_Administration.html#Replication 'Luck -Szii - Original Message - From: Jeff Field [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Monday, May 20, 2002 6:03 PM Subject: [PHP-DB] replication questions I think I understand how to set up replication but have a couple unanswered questions. I'm hoping the list can help. I have two servers with MySQL. Each server currently has completely different databases, except for the standard mysql permissions database. Server 1 is in production and server 2 is basically a development box. I would like to replicate server 1's databases to server 2 (in effect, creating a hot-swap), but then that would mean that server 2 not only has the production db's, but also the development db's. My question are: 1) Is that even possible to do? Can a slave to a master also have additional db's on it that the master doesn't even know about? 2) If the answer to question one is yes, then what do you do regarding the mysql permissions db on the slave? BTW, I'm thinking that my setup perhaps has to be more along the following lines: The master contains all my db's, both production and development. The production db's (as well as the development db's) would sit there in production on server 1, replicating all the data to server 2. I would have to set the permissions for both production and development db's on server 1. Meanwhile, as the production server is sitting there and replicating all it's important data to the development box, I could still work on the development db's on the slave box (thereby not fooling around with the production box). The issue, as I see it, would be that the slave box's development db's would soon go out of synch with the development db's on the master (because I'd be inserting, updating, etc. records on the development db's on the slave and the master would never know). I could set up two-way replication, but since I don't really care about the development db's being in synch on the master, why bother. Does this make sense? Anyway, I hope I've made this clear enough for someone to jump with answers and comments. Jeff -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] xml doc validation .... details ...... ! ! ! !
Your questions are far too vague and XML/XML:Schema/XSLT etc are far too complicated to explain without definitive focus'd questions. XML allows you to do whatever YOU want in whatever format YOU want. Best help I can give is this... http://www.w3.org/ 'Luck -Szii - Original Message - From: toby z [EMAIL PROTECTED] To: php db [EMAIL PROTECTED] Sent: Monday, May 20, 2002 6:52 PM Subject: [PHP-DB] xml doc validation details .. ! ! ! ! well its something like i need to take user input and store it somewhere and then retrieve it back thru DOM and i guess i need to store that input in an xml doccument like the one i sent earlier or do i now the thing that im most concerned bout is . this doccument or anyother that i try tomake using the scheema doesent get validated i keep getting an error fo one of the fields for each . i've tried changing the field types but ... even that doesnt change anything .. secondly i made a single scheema . and i included all the elements in it . user-info, content-info, categry,.. with all their subelements . i think im right or am i third .i have a few elements in the scheema that are repeated . do u think that cud be the problem ? so thats it ... if u want me to tell u more plz do let me know thnx a million toby __ Do You Yahoo!? LAUNCH - Your Yahoo! Music Experience http://launch.yahoo.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] String datetime to DateTime
Hmm...odd. I guess their %s (yes that was a typo) looks for a space as a delimiter and not the specified next one. Easiest workarounds off the cuff... 1) sscanf() to get the bulk of the data out, then regex out the %s string. 2) eregi_replace() Jun with the numeric 3) Dump it as numeric instead of a string month name 4) eregi_replace() the /'s with spaces then sscanf() it. 'Luck -Mike - Original Message - From: Glenn Holden [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Thursday, June 20, 2002 8:48 AM Subject: Re: [PHP-DB] String datetime to DateTime Thanks for the help, Mike. Trouble with sscanf... Incidentally I changed the $s in the format string to %s, I think that was a typo. :-) $str = 12/Jun/2002:01:02:26 -0600; $newstr = sscanf($str,%d/%s/%d:%d:%d:%d %s,$day,$mon,$year,$hour,$min,$sec,$offset); The trouble I'm having is with the first %s. It doesn't see the next delimiter so it puts the remaining text up to the next space into the $mon string. result: $day = 12 $mon = Jun/2002:01:02:26 other variables are empty Looking at php help online, there was a spanish user comment that seemed to be the same problem. And even though I can't read spanish, it looks like only a work around was suggested. I can work around this further but does anyone have a solution using sscanf? I'm not too clear on the acceptable syntax for the format string. Some comments intimate that I could use regular expressions withing there, but it doesn't seem to work either. Thanks in advance for any thoughts. Glenn [EMAIL PROTECTED] wrote in message news:046401c217fb$56310b00$[EMAIL PROTECTED]... DateTime formats are closer to what you have. strtotime() will give you an unsigned integer(ususally long/32bit) for the number of seconds since the unix epoch. Automagically from what you have to mySQL DateTime...nope...not that I can think of or find. If you have the Unix timestamp in ulong format, you can use date() to put it in the correct format. Obvious workaround... MySQL retrieves and displays DATETIME values in '-MM-DD HH:MM:SS' format. The supported range is '1000-01-01 00:00:00' to '-12-31 23:59:59'. $str = 12/Jun/2002:01:02:26 -0600; $newstr = sscanf($str,%d/%s/%d:%d:%d:%d $s,$day,$mon,$year,$hour,$min,$sec,$offset); $newdatestr = rebuild it here I never noticed that it didn't store the GMT offset before. heh. 'Luck -Mike - Original Message - From: Glenn Holden [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Wednesday, June 19, 2002 3:58 PM Subject: [PHP-DB] String datetime to DateTime Hello All! I have a unix time stamp in string format like this: 12/Jun/2002:01:02:26 -0600 I am trying to turn that back into a mySQL DateTime value. I've experimented with strtotime with no luck. I'm not really sure if that's what it's for. I can, of course, parse the string manually to build a datetime that MySQL will accept, but isn't there a function that handles this? How do -you- do this? Thanks! -Glenn -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] got it, thanks
Because it's not $s in the context of a printf() call. It is %s to denote a string replacement. -Mike - Original Message - From: Matthew Crouch [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Monday, June 24, 2002 12:41 PM Subject: [PHP-DB] got it, thanks Seth Yount wrote: in you print statement you have ?lastname=%s, shouldn't that be '$s' denoting a variable being passed? Try that out. gl -- Seth Matthew Crouch wrote: this bit from my index page is giving me 2 headaches: 1. it isn't passing anything into the URL 2. the page that gets called (name.php) sits and tries to load forever. it looks like it's even filling up my hard drive with data (?!) Note: it does this (#2) even if I type in the URL with a variable and value, like name.php?lastname=smith ? printf (form method=\post\ action=\name.php?lastname=%s\, $lastname); ? div align=center input type=Text name=lastname size=75 input type=Submit name=submit value=Search for Last Name /div /form /div -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] check two tables at same time?
SQL JOINs... http://www.mysql.com/doc/J/O/JOIN.html -Mike - Original Message - From: Noah Spitzer-Williams [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Monday, June 24, 2002 4:21 PM Subject: [PHP-DB] check two tables at same time? hey guys, im trying to figure out a query that i can return rows from more than one table at a time. for example, i have two identical tables in structure and i want to return rows from both using one query. maybe this will help: select * from table1 and table2 where condition='value' is there any way to do this? thanks! - Noah -- TradeMyTraffic! Web Services http://www.trademytraffic.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Works with one server and not the other
MySQL doesn't support subselects.
Look up mysql_insert_id(). It'll return the ID of the last inserted record.
Or just break out the second INSERT statement into one SELECT
and then the actual INSERT.
-Mike
- Original Message -
From: Christine Clerc [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, June 24, 2002 2:48 PM
Subject: [PHP-DB] Works with one server and not the other
Hi,
I want to populate two related tables : here is the code
include (connect.php);
$req=select * from tab where num='$mod';
$result=mysql_query($req,$db);
if ($ligne=mysql_fetch_array($result))
//if the data is already there do nothing
{continue;}
//otherwise put it in table 1
$req2=INSERT INTO tab (num) VALUES ('$mod');
$result2=mysql_query($req2,$db);
//and then add the relational element to table 2
$req4=INSERT INTO inter (id_tab) SELECT id_tab FROM
tab WHERE num='$mod';
$result4=mysql_query($req4, $db);
The first part works fine on both servers (table 1)
Table 2 fills up fine on my machine but not on the server wher it is
supposed to go !
Any idea ?
Christine
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Re: [PHP-DB] what the heck? (elementary question)
- Original Message - From: Cosby, Christopher [EMAIL PROTECTED] I don't want to start a tangent here, but the most accepted way for generating HTML with PHP is to NOT generate HTML with PHP. Thus, the original code should be written like this: Huh? .. most accepted way for generating ...is NOT generate..? Brain fart? =) I will regularly use large echo style statements to generate HTML, especially SELECT tags and result tables. As far as the POST/GET question, you technically can use POST and GET methods simultaneously, but it's nasty. For best results, stay away from the register_globals functionality and use $HTTP_POST_VARS[] and $HTTP_GET_VARS[] instead. Both of which are deprecated. =( _GET _POST are the new ones. POST will allow larger form submits as well, like file uploads. GET are for smaller and faster data sets. Go to WeSellBooksByTheMillions and buy a good PHP book for reference. They have lots of basics like this in them. I prefer most anything from Wrox Press (http://www.wrox.com/) www.php.net www.phpbuilder.com RIP Computer Literacy bookstores after the Barnes and Noble acquisition. -Mike -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Re: brand new elementary question
Just a quick follow up... from http://www.w3.org/MarkUp/html-spec/html-spec_8.html#SEC8.1 When there is only one single-line text input field in a form, the user agent should accept Enter in that field as a request to submit the form. and a random link... http://ppewww.ph.gla.ac.uk/~flavell/www/formquestion.html 'Luck. -Mike - Original Message - From: Martin Clifford [EMAIL PROTECTED] To: [EMAIL PROTECTED]; [EMAIL PROTECTED] Sent: Monday, June 24, 2002 1:56 PM Subject: [PHP-DB] Re: brand new elementary question If your form is up to standards, then hitting the enter key on any field, with the exception of textarea, should submit the form. If you are using an image for your submit button via the input type=image tag, then you'd have to tab until on the image before hitting enter for it to work. HTH Martin Seth Yount [EMAIL PROTECTED] 06/24/02 03:58PM initially I would look at your button type in the source code. Their are two basic types of buttons, the ' submit ' and the ' clear form '. If that doesn't work, post back gl -- Seth Matthew Crouch wrote: got my other one sorted out; thanks everyone. now: how do i get it so when you hit enter on the keyboard it's the same as hitting the submit button with the mouse? When I hit enter, it clears my form and reloads the current page. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] PHP in Database Fields..
exec() the query results. -Mike - Original Message - From: Matthew Tedder [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Monday, June 24, 2002 2:31 PM Subject: [PHP-DB] PHP in Database Fields.. Question: I want to put PHP code into database fields holding HTML text, how can I make it execute that PHP before sending to the browser?? Currently, I get the text from MySQL and print it The browser shows the PHP code mixed into the HTML. Matthew -- Anything that can be logically explained, can be programmed. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] PHP in Database Fields..
I'm sorry, brainfart. Don't exec(), eval(). Apologies. -Mike - Original Message - From: Matthew Tedder [EMAIL PROTECTED] To: [EMAIL PROTECTED] Cc: [EMAIL PROTECTED] Sent: Monday, June 24, 2002 4:00 PM Subject: Re: [PHP-DB] PHP in Database Fields.. On Monday 24 June 2002 09:21 pm, [EMAIL PROTECTED] wrote: exec() the query results. I can't seem to get that to work... Basically, I want to put my variables into the code in order to theme HTML code within data base fields. Consider the following for example: $glPageFG = #FF; $mystr = centerfont color=$glPageFGThemed Text!/font/center; print exec($mystr);// Doesn't work exec($mystr);// Doesn't work print $mystr; // Doesn't work after an exec(), either.. The only part of the PHP reference guide I can check online at the moment is not telling me much, either.. Matthew -Mike - Original Message - From: Matthew Tedder [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Monday, June 24, 2002 2:31 PM Subject: [PHP-DB] PHP in Database Fields.. Question: I want to put PHP code into database fields holding HTML text, how can I make it execute that PHP before sending to the browser?? Currently, I get the text from MySQL and print it The browser shows the PHP code mixed into the HTML. Matthew -- Anything that can be logically explained, can be programmed. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- Anything that can be logically explained, can be programmed. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] what the heck? (elementary question)
One large PHP block is more efficient than multiple small blocks of php. It's a tradeoff of multiple invocations of the parser versus having the parse run through (and ignore) normal text. We have run tests inhouse that validate the performance difference is fairly small, but it does exist. This was about two years ago, though, so perhaps the engine is now a one-time invocation and my test is invalid. -Mike - Original Message - From: [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Monday, June 24, 2002 8:00 PM Subject: Re: [PHP-DB] what the heck? (elementary question) Keep with Christophers original statement. It is more efficient to not have large echo values. gl -- Seth [EMAIL PROTECTED] wrote: - Original Message - From: Cosby, Christopher [EMAIL PROTECTED] I don't want to start a tangent here, but the most accepted way for generating HTML with PHP is to NOT generate HTML with PHP. Thus, the original code should be written like this: Huh? .. most accepted way for generating ...is NOT generate..? Brain fart? =) I will regularly use large echo style statements to generate HTML, especially SELECT tags and result tables. As far as the POST/GET question, you technically can use POST and GET methods simultaneously, but it's nasty. For best results, stay away from the register_globals functionality and use $HTTP_POST_VARS[] and $HTTP_GET_VARS[] instead. Both of which are deprecated. =( _GET _POST are the new ones. POST will allow larger form submits as well, like file uploads. GET are for smaller and faster data sets. Go to WeSellBooksByTheMillions and buy a good PHP book for reference. They have lots of basics like this in them. I prefer most anything from Wrox Press (http://www.wrox.com/) www.php.net www.phpbuilder.com RIP Computer Literacy bookstores after the Barnes and Noble acquisition. -Mike -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Re: DB400 on AS/400
There's a long thread somewhere in the archives of PHPBuilder.com in regards to getting DB2/PHP to work on an AS/400. -Mike - Original Message - From: John Lim [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Tuesday, June 25, 2002 12:01 AM Subject: [PHP-DB] Re: DB400 on AS/400 Hi Mike I have heard successful reports of using odbc to connect to db400. I have not personally done so. Regards, John Mike Germain [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... I am trying to do a query on a database on an AS/400. The database is in DB400 format which is simaluar to DB2. Can PHP access databases in DB400 via ODBC or does it only work in DB2? thx, Mike -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] A JOIN that works sometimes ?
Make sure you're exec'ing against the correct database with identical schema. Different MySQL versions? Schema? Permissions? var_dump() and cut'n'paste onto the server to make sure the query DOES run, then look for remote DB connection issues, permissions, database, etc. Are there multiple num fields across the two tables such that the ORDER BY clause is ambiguous? Whole lot of possibilities. Run the var_dump() query first...it's the best place to start. 'Luck. -Mike - Original Message - From: Christine Clerc [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Tuesday, June 25, 2002 12:35 AM Subject: [PHP-DB] A JOIN that works sometimes ? Could anyone please help me with that query ? $req=SELECT * FROM tab AS C INNER JOIN inter AS A ON C.id_tab=A.id_tab WHERE A.id_cat IS NULL OR A.id_cat = 0 ORDER BY num; $result = mysql_query ($req,$db); It works on my machine but not on the server. Christine -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] email format: meeting request
You're going to have to rip open the MS-specific format and handbuild (or script) your PHP to custom-build that format with the correct data fields. While it can be done, it's a good bit of time and energy. -Mike - Original Message - From: Dib, Walid (MED, Stagiaire GEMS) [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Tuesday, June 25, 2002 1:38 AM Subject: [PHP-DB] email format: meeting request Hello, I have a little bit difficult question, I need to send email under format meeting request to automatically update the calendar in outlook, how can I do that with PHP and what parameters use?? Thank you Walid -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Form not working...
okay, couple of questions in this one... =)
First...
?=$myData? is shorthand for ?php echo $myData; ? if you care.
With a textarea there is no value attribute.
TEXTAREA?=$myData?/TEXTAREA
Your UPDATE call via sprintf() is okay for the parameter passing,
but you're missing single quotes around the text values.
UPDATE test SET (number = 1, name = 'the Name', Desc = 'the Desc');
When dealing with PHP and DBs, the single best thing you can do is
var_dump($your_query) and then cut-n-paste into the command line
utility. It is, hands down, the single easiest (and fastest) way to figure out
why your query doesn't work.
'Luck!
-Mike
- Original Message -
From: NIPP, SCOTT V (SBCSI) [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, June 25, 2002 11:03 AM
Subject: [PHP-DB] Form not working...
I am working on a Call Log application for our SA group. I
currently have the database back-end configured and working OK. Right now I
am working with 3 pages, one is to post new entries, the second is a log
view of all entries, and the last is a page that updates an existing entry.
I have the first two pages working OK. The problem is the update page does
not post back into the database.
I am working in Dreamweaver, and I am still quite new to PHP and web
page development in general. I am not sure what some of the DreamWeaver PHP
code is doing, and I cannot figure out why I am not able to get the update
page to post to the database. The update page is connecting successfully to
the database, because I have it's fields populated from the database for the
entry to be updated. One other minor issue I am having, is getting a PHP
variable to populate a text area on the page. Is this even possible?
Thanks in advance, and below is the code for the problem page.
?php require_once('Connections/Test.php'); ?
?php
function GetSQLValueString($theValue, $theType, $theDefinedValue = ,
$theNotDefinedValue = )
{
$theValue = (!get_magic_quotes_gpc()) ? addslashes($theValue) : $theValue;
switch ($theType) {
case text:
$theValue = ($theValue != ) ? ' . $theValue . ' : NULL;
break;
case long:
case int:
$theValue = ($theValue != ) ? intval($theValue) : NULL;
break;
case double:
$theValue = ($theValue != ) ? ' . doubleval($theValue) . ' :
NULL;
break;
case date:
$theValue = ($theValue != ) ? ' . $theValue . ' : NULL;
break;
case defined:
$theValue = ($theValue != ) ? $theDefinedValue :
$theNotDefinedValue;
break;
}
return $theValue;
}
$editFormAction = $HTTP_SERVER_VARS['PHP_SELF'];
if (isset($HTTP_SERVER_VARS['QUERY_STRING'])) {
$editFormAction .= ? . $HTTP_SERVER_VARS['QUERY_STRING'];
}
if ((isset($HTTP_POST_VARS[MM_update])) ($HTTP_POST_VARS[MM_update]
== form1)) {
$updateSQL = sprintf(UPDATE oncall SET sa=%s, ptime=%s, rtime=%s,
sbcuid=%s, name=%s, problem=%s, resolution=%s, pass=%s, ctime=%s,
duration=%s, ttrp=%s, feedback=%s, P1=%s WHERE callid=%s,
GetSQLValueString($HTTP_POST_VARS['sa'], text),
GetSQLValueString($HTTP_POST_VARS['ptime'], date),
GetSQLValueString($HTTP_POST_VARS['rtime'], date),
GetSQLValueString($HTTP_POST_VARS['sbcuid'], text),
GetSQLValueString($HTTP_POST_VARS['name'], text),
GetSQLValueString($HTTP_POST_VARS['problem'],
text),
GetSQLValueString($HTTP_POST_VARS['resolution'],
text),
GetSQLValueString($HTTP_POST_VARS['pass'], text),
GetSQLValueString($HTTP_POST_VARS['ctime'], date),
GetSQLValueString($HTTP_POST_VARS['duration'],
date),
GetSQLValueString($HTTP_POST_VARS['ttrp'], date),
GetSQLValueString($HTTP_POST_VARS['feedback'],
text),
GetSQLValueString($HTTP_POST_VARS['P1'], text),
GetSQLValueString($HTTP_POST_VARS['callid'], int));
mysql_select_db($database_Test, $Test);
$Result1 = mysql_query($updateSQL, $Test) or die(mysql_error());
}
$tmp = $_GET['callid'];
mysql_select_db($database_Test, $Test);
$query_Update = SELECT * FROM oncall WHERE callid='$tmp';
$Update = mysql_query($query_Update, $Test) or die(mysql_error());
$row_Update = mysql_fetch_assoc($Update);
$totalRows_Update = mysql_num_rows($Update);
?
html
head
titleUntitled Document/title
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Re: [PHP-DB] INNER JOIN by field content
You need to have keys in each table to join them together.
Once you have those keys in place, you can match the keys
across the tables and use a WHERE clause to filter the results.
'Luck!
-Mike
- Original Message -
From: José Moreira [EMAIL PROTECTED]
To: Php-Db [EMAIL PROTECTED]
Sent: Tuesday, June 25, 2002 6:48 AM
Subject: [PHP-DB] INNER JOIN by field content
for building my website i am implementing a tree-style data organization.
for that i have a mysql table called 'jm_tree':
CATID, int(10)auto_increment - Index
PARENT, int(10) -the CATID of
the 'parent' node
TEXT, varchar(40) - small
description
TYPEset('FOLDER','FILE','LINK','POST') - the type of object
and for each TYPE of object i have a corresponding table like :
ex.: for a TYPE 'FILE' i have a 'jm_files' table [ that has the CATID field
also ( as a FK ) ]
with all the files related to that node.
i want to know is ( and i am perfectly aware that this in possible using
multiple queries and PHP ) if it's possible that in one MySQL query to
INNER JOIN the 'jm_tree' table to the specifical table ( jm_files, jm_links,
fo fo fo )
according to the contents of the 'jm_tree.type'
99%-possibility-of-being-wrong-something-like-example :)
SELECT * FROM jm_tree INNER JOIN jm_files IF jm_tree.type='FILE'
INNER JOIN jm_links IF jm_tree.type='LINKS'
Best Regards,
José Moreira
Técnico de Informática | IT Technician
Vila Nova de Gaia, Portugal
E-mail: [EMAIL PROTECTED]
MSN: [EMAIL PROTECTED]
ICQ: 136936120
IRC: gray (irc.ptnet.org)
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Re: [PHP-DB] Re: DB400 on AS/400
Sorry, that was vague. ODBC is a standard of connectivity and IS supported by the AS/400 platform. With that said, if AS/400 has ODBC support and PHP has ODBC support then the two can talk. -Mike - Original Message - From: [EMAIL PROTECTED] To: [EMAIL PROTECTED] Cc: [EMAIL PROTECTED] Sent: Tuesday, June 25, 2002 12:24 PM Subject: Re: [PHP-DB] Re: DB400 on AS/400 There's a long thread somewhere in the archives of PHPBuilder.com in regards to getting DB2/PHP to work on an AS/400. -Mike - Original Message - From: John Lim [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Tuesday, June 25, 2002 12:01 AM Subject: [PHP-DB] Re: DB400 on AS/400 Hi Mike I have heard successful reports of using odbc to connect to db400. I have not personally done so. Regards, John Mike Germain [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... I am trying to do a query on a database on an AS/400. The database is in DB400 format which is simaluar to DB2. Can PHP access databases in DB400 via ODBC or does it only work in DB2? thx, Mike -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
