Caught that :) Thanks for the tip... worked just perfect (after I fixed
typo)
On Friday, March 28, 2003, at 12:57 AM, Foong wrote:
sorry
typo error should be:
date('Y')
Foong
Foong [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
hi,
$start = mktime ( 0, 0, 0, 1, 1, date['Y']); //
Greetings all,
A while ago I was using asp and when I started using php the harder
thing to learn was Dealing with dates. There isn't a datediff function
like asp.. Instead you have timestamps. Powerful it may be but a little
hard to learn about and use. Other wise I find php to be very
Hello Adam,
Since timestamps are in seconds you just subtract them and then use date
to convert it to a more human readable format.
?php
$yesterday = time() - 86400;
print date('m/d/y', $yesterday);
?
You could also use the strtotime function to convert a string to a
timestamp.
PHP
hi,
using date(dS); how can i can increase the days so that it shows
19th 20th 21st
I have tried
while ($i 2){
$day++;
echo' td'.$day.'/td';
$i++;
}
but i get:
19th 19ti 19tj
thanks for your help
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Hi all,
I have a form where users will be adding publication dates for uploaded
files. I want to store the date in mySQL as date('U') format. If the
date is entered as mm/dd/ - will the date function know this or is
there some way of 'telling' php how the date to be converted is
- Original Message -
From: Charles Kline [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, March 19, 2003 2:17 PM
Subject: [PHP] date question
Hi all,
I have a form where users will be adding publication dates for uploaded
files. I want to store the date in mySQL as date('U
Hi,
when retrieving a date from MySQL in n/MM/DD, how can I present this to
the user of a site in readable format i.e. 19th March 2003?
Thanks for your help
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when retrieving a date from MySQL in n/MM/DD, how can I present
this
to
the user of a site in readable format i.e. 19th March 2003?
SELECT DATE_FORMAT(column,' ... ') AS f_date FROM table WHERE ...
Look up DATE_FORMAT in the MySQL manual, Chapter 6. It works almost the
same as the PHP
If I have a date in this format :19-MAR-03 how do I get the next date (the
date plus 1)?
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If I have a date in this format :19-MAR-03 how do I get the next date
(the
date plus 1)?
echo strtoupper(date('d-M-y',strtotime($date +1 day)));
But why do you have it in that format to begin with?
---John W. Holmes...
PHP Architect - A monthly magazine for PHP Professionals. Get your copy
Hi
I want to check if $var 14 days or $var 14 days
($var = $date2 - $date1)
$date1 = 2003-01-16;
$date2 = 2003-03-16;
How can i check this?
Are there any functions for this or do i have to make one?
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$FourteenDays = 86400 * 14;
$var = $FourteenDays - (strtotime($date2) - strtotime($date1));
Now if $var is 0, 14 days has not passed.
Niklas
-Original Message-
From: Fredrik [mailto:[EMAIL PROTECTED]
Sent: 12. maaliskuuta 2003 12:06
To: [EMAIL PROTECTED]
Subject: [PHP] date check
I have a date field in mysql in this format: Y-m-d H:i:s
I would like to echo Today if the date is today, can someone offer some
help? Thanks.
warm regards,
Sebastian - [BBR] Gaming Clan
http://www.broadbandreports.com
On 05-Mar-2003 Sebastian wrote:
I have a date field in mysql in this format: Y-m-d H:i:s
I would like to echo Today if the date is today, can someone offer some
help? Thanks.
SELECT IF(TO_DAYS(datefld)=TO_DAYS(current_date),'Today',LEFT(datefld,10)) as
datefld, ...
Regards,
--
Don Read
Here is my current query:
$qAnnouncement =
'SELECT id,headline
FROM tbl_funding
WHERE 1
AND ((UNIX_TIMESTAMP (datestamp) = ' .
strtotime($attributes[startdate]) . ') AND (UNIX_TIMESTAMP (datestamp)
= ' . strtotime($attributes[startdate]) . ')) LIMIT 0, 30';
Where datestamp is set in MySQL
today. http://www.phparch.com/
-Original Message-
From: charles kline [mailto:[EMAIL PROTECTED]
Sent: Monday, March 03, 2003 6:22 PM
To: [EMAIL PROTECTED]
Subject: [PHP] date range assistance needed
Here is my current query:
$qAnnouncement =
'SELECT id,headline
FROM
Greetings all.
I have used strtotime() function in the past, and done this:
if($time = strtotime('24 hours ago')) {
$new = new!;
}
with it being in UNIX time stamp .. But now I have a different client where
the time stamp in mysql is formatted like:
2002-08-29 10:53:09
what function would I
I have used strtotime() function in the past, and done this:
if($time = strtotime('24 hours ago')) {
$new = new!;
}
with it being in UNIX time stamp .. But now I have a different client
where
the time stamp in mysql is formatted like:
2002-08-29 10:53:09
what function would I use in
]
To: 'Sebastian' [EMAIL PROTECTED]; 'php list'
[EMAIL PROTECTED]
Sent: Sunday, March 02, 2003 12:40 AM
Subject: RE: [PHP] Date question
|
| SELECT column - INTERVAL 24 HOUR FROM your_table WHERE ...
|
| ---John W. Holmes...
- Original Message -
From: John W. Holmes [EMAIL PROTECTED]
To: 'Sebastian
Hi,
Sunday, March 2, 2003, 3:39:37 PM, you wrote:
S Greetings all.
S I have used strtotime() function in the past, and done this:
if($time = strtotime('24 hours ago')) {
S $new = new!;
S }
S with it being in UNIX time stamp .. But now I have a different client where
S the time stamp in mysql
Hi Bryan,
$t = mktime(0,0,0,date('m')+1,1,date('Y'));
Gives you timestamp of first day, next month.
Format accordingly with date().
is there such a say to now get the date of the first
weekday after that date?
You can brute force it:
// grab the timestamp
$t =
Hello,
I would ask you a question about date type
if I have a variable from date type ($newdate) such as 2003-02-17
how can I separate $newdate into 3 different variables? I want to create
such variables:
$day=17
$month=2
$year=2003
I searched a lot, but I didn't find how to do this.
I'll be very
From: Alexander Tsonev [EMAIL PROTECTED]
Hello,
I would ask you a question about date type
if I have a variable from date type ($newdate) such as 2003-02-17
how can I separate $newdate into 3 different variables? I want to create
such variables:
$day=17
$month=2
$year=2003
I searched a
Hello,
Does anyone know a way to do this easily? I have a script that pretty much
says this is due on the first of next month but I would like it to
actually use the correct date.
Thanks,
Bryan
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Does anyone know a way to do this easily? I have a script that pretty much
says this is due on the first of next month but I would like it to
actually use the correct date.
You would think strtotime(first of next month) would work, but it doesn't.
This does:
$t =
--- Bryan Koschmann - GKT [EMAIL PROTECTED] wrote:
Does anyone know a way to do this easily? I have a script that pretty much
says this is due on the first of next month but I would like it to
actually use the correct date.
Well, you need:
1. The day of the month, which is always going to be
Use the mktime function:
mktime (0,0,0,(date(n,$date)+1),1,date(Y,$date))
Where the variable $date contains whatever is the starting date. The
function handles a December date just fine also.
On Wednesday, February 26, 2003, at 03:28 PM, Bryan Koschmann - GKT
wrote:
Hello,
Does anyone know a
On Wed, 26 Feb 2003, 1LT John W. Holmes wrote:
|You would think strtotime(first of next month) would work, but it doesn't.
|This does:
|
|$t = mktime(0,0,0,date('m')+1,1,date('Y'));
|
|Gives you timestamp of first day, next month. Format accordingly with
|date().
Thats great, worked perfectly!
Hello Everyone,
My php/mysql application needs to keep track of the first time that a
User logs on to the site. Afterwards the User should be allowed either
3 days / 3 months/1 year of access to the site. Once the stipulated
time period is over the system should invalidate the login of the
It sounds like you're asking for triggers, which are available yet. But
you could setup a cron job to run every night to update the database. It
would be no different than doing a nightly dump for backup. You could
even have it email you the accounts that were closed and those that will
be
I assume you talking about a logged in, validated user -- because there's no
way to prevent a user from deleting their cookies, or changing their IP, or
using a different computer to access the site.
My only suggestion is that you create a user/pass login system, maintain it
with sessions, and
Dear Sirs,
How can I add or subtract two date easily. Is therea any lib or function
about this. I can not find any easy way in the manual
Best Regards
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This one time, at band camp,
qt [EMAIL PROTECTED] wrote:
Dear Sirs,
How can I add or subtract two date easily. Is therea any lib or function
about this. I can not find any easy way in the manual
if the dates are timestamps, simply
$new = $timestamp2 - $timestamp1;
cheers
Kevin
--
Dear Kevin,
I used timestamp allready as following;
$today = strtotime (1 february 2003);
$enddate = strtotime (1 march 2003);
$diff = $enddate - $today;
But result comes as
2419200
How can I convert that numbers to days
Best Regards
Kevin Waterson [EMAIL PROTECTED] wrote in message
Try:
$today = strtotime (1 february 2003);
$enddate = strtotime (2 february 2003);
$diff = $enddate - $today;
Should give you a clue!
SW
Qt [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Dear Kevin,
I used timestamp allready as following;
$today =
Dear Stephen,
Good clue!!
Is it working allways without problem such as 29 feb?
And one more hel how can I write 1 2 2003 instead of 1 february 2003
I wrote but directly but doesn' t work
thanks
Stephen Willcock [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Yes, will be OK with all dates (though the valid range of a timestamp is
typically from Fri, 13 Dec 1901 20:45:54 GMT to Tue, 19 Jan 2038 03:14:07
GMT.)
The function you want for numeric dates is:
int mktime ( int hour, int minute, int second, int month, int day, int year)
so, in your example
Hi,
I have a string in this format:
2003-02-15 13:19:02
I want to display it in a more readable format like Staurday, 11 Februardy,
2003, 13:19:02. How can I achieve that. I tried date() function but could
not get what I wanted.
-Dhaval
On Saturday 15 February 2003 16:56, Dhaval Desai wrote:
Hi,
I have a string in this format:
2003-02-15 13:19:02
I want to display it in a more readable format like Staurday, 11 Februardy,
2003, 13:19:02. How can I achieve that. I tried date() function but could
not get what I wanted.
?
echo date('the format you want', strtotime('2003-02-15 13:19:02'));
?
In this case 'the format you want' is 'l, d F, Y. H:i:s', but you should be
able to look it up in the manual for yourself. php.net/date
strtotime('2003-02-15 13:19:02') SHOULD work, converting the string to a
unix time
I have a string in this format:
2003-02-15 13:19:02
I want to display it in a more readable format like
Staurday, 11 Februardy,
2003, 13:19:02. How can I achieve that. I tried date()
function but could
not get what I wanted.
The date format above is a standard mysql date/time
Hi
I have to dates that i want to check who is biggest.
This does not work:
if( $date1 $date2){
How can i check them?
Svein Olai
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Hi Fredik,
I have to dates that i want to check who is biggest.
This does not work:
if( $date1 $date2){
How can i check them?
Presumably they're in SQL format, or something similar?
The easiest way is to convert them to unix timestamps (look into the date()
and mktime()
I have a function that I use to return the number of days between two dates. It
worked fine on my Mandrake 7.0 server running PHP 4. I am trying to run it on a
RedHat 8.0 box with the same version of PHP. On Mandrake, strtotime() and mktime()
returned a negative number for dates prior to
On Thursday 06 February 2003 23:13, Rob Quenzer wrote:
I have a function that I use to return the number of days between two
dates. It worked fine on my Mandrake 7.0 server running PHP 4. I am
trying to run it on a RedHat 8.0 box with the same version of PHP. On
Mandrake, strtotime() and
Is it possible to read a string from a text file (i.e.
0502031130) and be able to use that in a date function such as:
$date = date(dmyHi, strtotime('+28 days));
How would I use that string as the date in the above code?
TIA,
Ed
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To
Hi,
Thursday, February 6, 2003, 2:41:42 AM, you wrote:
ehhc Is it possible to read a string from a text file (i.e.
ehhc 0502031130) and be able to use that in a date function such as:
ehhc $date = date(dmyHi, strtotime('+28 days));
ehhc How would I use that string as the date in the above
Is it possible to read a string from a text file (i.e.
0502031130) and be able to use that in a date function such as:
$date = date(dmyHi, strtotime('+28 days));
How would I use that string as the date in the above code?
What database are you using? You can probably do all of this in
I'm not using this for any database related function. What I'm trying to
do is come up with a method for scheduling processes needed for our
company that are run through command line php scripts. I'll be using cron
or to run a command that will check the date within the file and see if
the
I'm not using this for any database related function. What I'm trying
to
do is come up with a method for scheduling processes needed for our
company that are run through command line php scripts. I'll be using
cron
or to run a command that will check the date within the file and see
if
the
I don't know of another program. As long as you write a unix timestamp
or some date format that can be parsed by strtotime(), then you can do
it this way. Use fopen()/fread() to get the last time saved in the file.
If you're using unix timestamps, just see if the current time is greater
Hello friends.
The follwing code displays the date on my webpage :
echo date (l dS of F Y h:i:s A);
However, I need to add 12 hrs to this date befor displaying on the webpage. Can
someone please help me to modify the above code?
Thanks
Denis
Hi,
Monday, February 3, 2003, 11:10:36 AM, you wrote:
DLM Hello friends.
DLM The follwing code displays the date on my webpage :
DLM echo date (l dS of F Y h:i:s A);
DLM However, I need to add 12 hrs to this date befor displaying on the webpage. Can
someone please help me to modify the above
echo date (l dS of F Y h:i:s A);
However, I need to add 12 hrs to this date befor displaying on the
webpage. Can someone please help me to modify the above code?
$t = time() + (12 * 60 * 60);
echo date (l dS of F Y h:i:s A, $t);
Larry
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To
Hello ppl,
Well, I want to compate date is php, could anybody tell me which is the best
way to do so? I have tried various ways but nothing seems consistent.
I tried for example:
if(2003-1-15 2003-1-11)
{
echo true;
}
which doesn't work in some cases...
Thank you!
Best Regards,
Dhaval
- Original Message -
From: Dhaval Desai [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Saturday, January 11, 2003 8:38 AM
Subject: [PHP] Date Comparison
Well, I want to compate date is php, could anybody tell me which is the
best way to do so?
Look at PHPs date functions http
On Saturday 11 January 2003 21:38, Dhaval Desai wrote:
Hello ppl,
Well, I want to compate date is php, could anybody tell me which is the
best way to do so? I have tried various ways but nothing seems consistent.
I tried for example:
if(2003-1-15 2003-1-11)
{
echo true;
}
which
Hello friends.
Happy New Year to you all.
Our school holds many seminars of varying durations and dates. I want to make a page
which says What's on today which will show all the seminars that are on today.
However the entry in the database will show two fields Commencing Date and Ending
date.
At 05:23 PM 12/31/02 +0800, Denis L. Menezes wrote:
Hello friends.
Is there a routine in PHP I can use to find if today's date fits between
the commencing date and the ending date?
SELECT * FROM Table WHERE NOW() = StartDate AND NOW() = EndDate
Rick
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Our school holds many seminars of varying durations and dates. I want
to
make a page which says What's on today which will show all the
seminars
that are on today. However the entry in the database will show two
fields
Commencing Date and Ending date.
Is there a routine in PHP I can use to
I have a form with several date fields. I want to be able to set these by
selecting from a calendar display. Does anyone know of any php function or
code which would let me do this?
Regards
Peter Goggin
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G'day Peter
I have a form with several date fields. I want to be able to
set these by selecting from a calendar display. Does anyone
know of any php function or code which would let me do this?
If you mean having some sort of pop-up calendar display that the user
can select a date from
I have two periods in time from a Cisco router that I would like to find the
difference in seconds. I am not sure the best way to do this since it is not
a date, but rather an amount of time since last reset.
Here is the numbers
181 days, 7:11:06.66
//stands for 181 days, 7 hours, 11 minutes,
I don't think you can use strtotime in that case. However, assuming that
your data is properly formatted every time, you can use a simple
function like this (I'm doing it from memory, so it might not actually
work):
?php
function conv_time ($s)
{
preg_match (/^([0-9]*) days,
okay, this is just me thinking out loud... none of this is tested...
?
function something($time)
{
$time = substr($time, 0, -3);
list($days,$theRest) = explode(' days, ', $time);
list($h,$m,$s) = explode(':', $theRest);
$days = $days * 86400;
$h = $h * 360;
$m = $m *
How can I get a string containing the month part of a date the user types
in?
e.g. if they type in 06/07/200 I want to get 06
thanks,
diana
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with drop down boxes for year, month and day.
Michael Egan
-Original Message-
From: Diana Castillo [mailto:[EMAIL PROTECTED]]
Sent: 19 December 2002 14:05
To: [EMAIL PROTECTED]
Subject: [PHP] date part[Scanned]
How can I get a string containing the month part of a date the user types
Castillo [mailto:[EMAIL PROTECTED]]
Sent: Thursday, December 19, 2002 9:05 AM
To: [EMAIL PROTECTED]
Subject: [PHP] date part
How can I get a string containing the month part of a date the user types
in?
e.g. if they type in 06/07/200 I want to get 06
thanks,
diana
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any part needed.
Eddie
-Original Message-
From: Diana Castillo [mailto:[EMAIL PROTECTED]]
Sent: Thursday, December 19, 2002 9:05 AM
To: [EMAIL PROTECTED]
Subject: [PHP] date part
How can I
, December 19, 2002 9:38 AM
To: Edward Peloke
Cc: Diana Castillo; [EMAIL PROTECTED]
Subject: RE: [PHP] date part
I just tried that script, for me under Linux with Mozilla and Netscape, I had to try
5 times before I could move the mouse from the button to the menu fast enough, every
other time
Sorry ADAM, didn't mean to call you Allan, I apologize!
-Original Message-
From: Edward Peloke [mailto:[EMAIL PROTECTED]]
Sent: Thursday, December 19, 2002 10:11 AM
To: [EMAIL PROTECTED]
Subject: RE: [PHP] date part
Thanks Allan! That is good to know. It is just a script that I
[mailto:[EMAIL PROTECTED]]
Sent: Thursday, December 19, 2002 10:11 AM
To: [EMAIL PROTECTED]
Subject: RE: [PHP] date part
Thanks Allan! That is good to know. It is just a script that I downloaded from the internet. Not sure how to make it work
How can I get a string containing the month part of a date the user
types
in?
e.g. if they type in 06/07/200 I want to get 06
If you know that's the format they're going to use, the you can just use
substr() to grab the first two characters.
---John W. Holmes...
PHP Architect - A monthly
Following on to the L T:
$ar = explode(/,$thestring);
thenL
$ar[0] = 06
$ar[1] = 07
$ar[2] = 200
- Original Message -
From: John W. Holmes [EMAIL PROTECTED]
To: 'Diana Castillo' [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Thursday, December 19, 2002 11:56 AM
Subject: RE: [PHP] date part
How can I format a date coming out of a MySQL? I know how to format today's date but
not a date coming out of MySQL. I have looked through the manual, but I must be blind
because I cannot figure it out.
Thanks,
Clint
Use this:
function makedate($format, $indate)
{
$temp = explode(-, $indate);
$fulldate = mktime(0, 0, 0, $temp[1], $temp[2], $temp[0]);
$temp = date($format, $fulldate);
return ($temp);
}
and call it with
: Friday, December 13, 2002 11:55 AM
Subject: [PHP] Date Formatting
How can I format a date coming out of a MySQL? I know how to format today's
date but not a date coming out of MySQL. I have looked through the manual,
but I must be blind because I cannot figure it out.
Thanks,
Clint
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[EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, December 13, 2002 12:55 PM
Subject: [PHP] Date Formatting
How can I format a date coming out of a MySQL? I know how to format today's
date but not a date coming out of MySQL. I have looked through the manual,
but I must be blind because I cannot
: [PHP] Date Formatting
How can I format a date coming out of a MySQL? I know how to format today's date but
not a
date coming out of MySQL. I have looked through the manual, but I must be blind
because I
cannot figure it out.
Thanks,
Clint
--
PHP General Mailing List (http://www.php.net
thanks for all the replies. I was able to use the date_format() from MySQL.
Clint
- Original Message -
From: Rick Emery [EMAIL PROTECTED]
To: Clint Tredway [EMAIL PROTECTED];
[EMAIL PROTECTED]
Sent: Friday, December 13, 2002 1:13 PM
Subject: Re: [PHP] Date Formatting
MYSQL will do all
-Original Message-
From: DL Neil [mailto:[EMAIL PROTECTED]]
Sent: 10 December 2002 19:52
=as a Windows user I struggle to cope with some of these UNIX
concepts, so I
hit Google - with no joy, and ripped through the SuSE manuals
(I'm a closet
Linux user - will become one, just
Mike,
No complaints about explanations in PHP manual - I often say that it IS a
cut-above the average. However it does NOT explain the underlying concepts
of timestamps, (quite rightly) expecting that we pick up such from
other/more appropriate sources. Hence my comments are refering to such
=now let's take a look at the UNIX Epoch. Various
'quotations' have surfaced
in this email, and I don't recall that it is well discussed
within the PHP
manual (it being a UNIX definition after all...). The epoch 'began'
1Jan1970, sure enough (exactly as quoted). HOWEVER it is defined
Justin,
Jumping in late...
Daylight Savings Time?
John, I think Daylight Saving Time creates a difference of 1 hour and
not
1 day :)
True... but I checked it anyway -- by adding just one and two hours to the
stamp... which made no difference... but when I added 86400 to the stamp,
it
all
Thanks heaps -- very reassuring :)
Justin
on 09/12/02 9:49 PM, DL Neil ([EMAIL PROTECTED]) wrote:
Justin,
Jumping in late...
Daylight Savings Time?
John, I think Daylight Saving Time creates a difference of 1 hour and
not
1 day :)
True... but I checked it anyway -- by adding just one
-Original Message-
From: DL Neil [mailto:[EMAIL PROTECTED]]
Sent: 09 December 2002 10:50
[snip...]
=now let's take a look at the UNIX Epoch. Various
'quotations' have surfaced
in this email, and I don't recall that it is well discussed
within the PHP
manual (it being a UNIX
Hello gurus,
Ford, Mike [LSS] [EMAIL PROTECTED] wrote:
[snip]
To amplify on this:
...
[/snip]
Interesting comments! ...not sure if I understood everything though :(
Anyway, for Justin's original problem, I think it'll be solve by simply
doing two things:
1. Add GMT to the end of the string
Hi,
I'm running the following code on two servers:
?
$stamp = 1039525200;
echo date('D, d M Y',$stamp);
?
On my local development box (Free BSD, PHP 4.1.1, on AUSTRALIAN time), the
above echo's Wed, 11 Dec 2002 (I consider this to be the correct date.
However on the live server (Red Hat, PHP
Daylight Savings Time?
---John W. Holmes...
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-Original Message-
From: Justin French [mailto:[EMAIL PROTECTED]]
Sent: Sunday, December 08, 2002 8:59 PM
To: php
Subject: [PHP] date
Hello,
John W. Holmes [EMAIL PROTECTED] wrote:
Daylight Savings Time?
John, I think Daylight Saving Time creates a difference of 1 hour and not
1 day :)
Anyway, I live in a place where we don't practice this so I could be
wrong...
...[snip]...
Now, what could be causing this problem?
But, then again, it could be just because the other server's time is really
late... (caused by old motherboard batteries, etc.)
- E
@ Edwin [EMAIL PROTECTED] wrote:
Hello,
John W. Holmes [EMAIL PROTECTED] wrote:
Daylight Savings Time?
John, I think Daylight Saving Time creates a
on 09/12/02 1:30 PM, @ Edwin ([EMAIL PROTECTED]) wrote:
Daylight Savings Time?
John, I think Daylight Saving Time creates a difference of 1 hour and not
1 day :)
True... but I checked it anyway -- by adding just one and two hours to the
stamp... which made no difference... but when I added
Hi,
Monday, December 9, 2002, 11:59:07 AM, you wrote:
JF Hi,
JF I'm running the following code on two servers:
JF ?
JF $stamp = 1039525200;
JF echo date('D, d M Y',$stamp);
?
JF On my local development box (Free BSD, PHP 4.1.1, on AUSTRALIAN time), the
JF above echo's Wed, 11 Dec 2002 (I
Justin French [EMAIL PROTECTED] wrote:
[snip]
Perhaps strtotime() is NOT running off GMT,
[/snip]
Bingo!
...or, Bull's eye!, whatever :)
Anyway, I think this is implied in the manual.
http://www.php.net/manual/en/function.strtotime.php
Also, check User Contributed Notes:
piran at
on 09/12/02 3:06 PM, @ Edwin ([EMAIL PROTECTED]) wrote:
[snip]
Perhaps strtotime() is NOT running off GMT,
[/snip]
Bingo!
*GULP*... so, what we're saying is, that if I intend to pass data around on
multiple servers (in different timezones) using a unix timestamp for dates
(which i prefer
Justin French [EMAIL PROTECTED] wrote:
on 09/12/02 3:06 PM, @ Edwin ([EMAIL PROTECTED]) wrote:
[snip]
Perhaps strtotime() is NOT running off GMT,
[/snip]
Bingo!
*GULP*... so, what we're saying is, that if I intend to pass data around
on
multiple servers (in different timezones)
Ok guys,
having a problem here. I did my table with 6 fields, they are:
id position name timein timeout date
I have a form to insert the info on the fields, and at the date field, I
have a drop down menu that returns me the next 7 days (the date in d/m/y),
people will choose the date they
-
From: Miguel Brás [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, December 06, 2002 10:39 PM
Subject: [PHP] Date again
Ok guys,
having a problem here. I did my table with 6 fields, they are:
id position name timein timeout date
I have a form to insert the info on the fields
On Saturday 07 December 2002 11:39, Miguel Brás wrote:
Ok guys,
having a problem here. I did my table with 6 fields, they are:
id position name timein timeout date
I have a form to insert the info on the fields, and at the date field, I
have a drop down menu that returns me the next 7
Hi,
please could someone tell me how i can return a month in text from an int
ie
getMonth(12)
How about:
$Months = array( , 'Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun',
'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec' );
echo $Months[12]; // Dec
Rick
--
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