Re: [PHP] Anybody have a function to encode a string?

2002-03-20 Thread maxwello

 I need a function that encodes stuff, with a key.  It, of course, needs to
 be decodable too.  Does anbody know/have a function like this? 

What is everyone's thoughts on RC4Crypt? 
http://sourceforge.net/projects/rc4crypt/
http://www.paphe.com/php/tutorials/230101.php



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Re: [PHP] Anybody have a function to encode a string?

2002-03-20 Thread maxwello

  I need a function that encodes stuff, with a key.  It, of course, needs
to
  be decodable too.  Does anbody know/have a function like this?

http://www.php.net/manual/en/ref.mcrypt.php

How about situations when mcrypt is not available?



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Re: [PHP] $DOCUMENT_ROOT behavior linux vs solaris

2002-03-20 Thread Alexander Skwar

»Dennis Moore« sagte am 2002-03-20 um 02:14:16 -0500 :
 So when I build my paths I get an extra /.  Is there any way to make Sun version 
to work like the Linux version.   I hate to go back and change all my code.

Uhm, is the double / a problem?  On Linux, it doesn't seem to hurt.

Alexander Skwar
-- 
How to quote:   http://learn.to/quote (german) http://quote.6x.to (english)
Homepage:   http://www.iso-top.de  | Jabber: [EMAIL PROTECTED]
   iso-top.de - Die günstige Art an Linux Distributionen zu kommen
   Uptime: 2 days 21 hours 25 minutes

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Re: [PHP] Anybody have a function to encode a string?

2002-03-20 Thread maxwello

 I need a function that encodes stuff, with a key.  It, of course, needs to
 be decodable too.  Does anbody know/have a function like this? 

What is everyone's thoughts on RC4Crypt? 
http://sourceforge.net/projects/rc4crypt/
http://www.paphe.com/php/tutorials/230101.php



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[PHP] $PHP_SELF on include file

2002-03-20 Thread José León Serna

Hello:
I would like to do the following:

a.php
--

  include b.php;


b.php
--

echo $PHP_SELF;


in b.php, instead show a.php as the script is executing, I want to know if
there's a way to show b.php, that is, the included file is being executed.

Regards.



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Re: [PHP] $PHP_SELF on include file

2002-03-20 Thread José León Serna

Hello:
 try it with __FILE__
 you might have to work a little on the resulting string, but it at least
 delivers the current file's name
What is __FILE__, a global var, an environment variable? Could you put a
simple example?

Regards and thanks for your quick answer.


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[PHP] Loading files via HTTP or directly from the server?

2002-03-20 Thread andy

Hi there,

I did recently discover that I might have a important failure in my webapp.
But I am not sure about it.
All the image files, js, css files I am accessing are loaded like this:
http://www.server.com/test/image.gif
Same with JS and css files. Now I am wondering if it would be faster to
access them directly from the disk on the server. due to my architecture I
can only use apsolute pathnames. I tryed /folder/file.gif but this does not
work.

Thanx for any help,

Andy



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[PHP] Re: Making a simple borderless pop up window with a Close button

2002-03-20 Thread qartis

If you want a popup window that lacks a border entirely, check out
chromeless windows at www.microbians.com



Denis L. Menezes [EMAIL PROTECTED] wrote in message
000f01c1cf3f$5321d520$c900a8c0@d8d0l7">news:000f01c1cf3f$5321d520$c900a8c0@d8d0l7...
 Hello friends.

 I am making a database website where I need to add a small help button for
 every field on the form. Whenever the user clicks the small help button, I
 wish to show a titleless popup window containing the help text and a
close
 button. Can someone  help me with the php script for this.

 Thanks
 Denis




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Re: [PHP] $PHP_SELF on include file

2002-03-20 Thread Wolfram Kriesing

On Wednesday 20 March 2002 10:12, José León Serna wrote:
 Hello:
  try it with __FILE__
  you might have to work a little on the resulting string, but it at least
  delivers the current file's name

 What is __FILE__, a global var, an environment variable? Could you put a
 simple example?

print( __FILE__ );
echo __FILE__;
will show the current file name

-- 
Wolfram

... translating template engine 
  http://sf.net/projects/simpletpl

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Re: [PHP] $PHP_SELF on include file

2002-03-20 Thread José León Serna

Hello:
 echo __FILE__;
 will show the current file name
Oops! Thanks! ;-))

Regards.


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[PHP] Receipts

2002-03-20 Thread Daniel Alsén

This may seem a bit off topic - but i am getting really tired of this...

I am subscribing to a variety of mailing lists and receives hundreds, and
sometimes thousands, of e-mails every day. One thing - that is almost unique
to this list - is that some of you send a request for a read receipt with
every mail. Why? Dou you really want read receipts from thousands of
subscribers?

It is not only annoying. It´s rude!

And no - i am not considering to deny or automatically send read receipts.
It is, when properly used, a good function. And i want to choose when to
send them. Although not being forced to deny receipts from a mailing list.

# Daniel Alsén| www.mindbash.com #
# [EMAIL PROTECTED]  | +46 705 38 10 30 #
# ICQ: 63006462   | +46 8 694 82 22  #
# PGP: http://www.mindbash.com/pgp/  #


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[PHP] PHP - mssql

2002-03-20 Thread chris

Hi. I have a table that contains lots of names in mssql. and i want to make
a page
where each of theese individuals can login with that spesific username and
password.
So my question is : what is the proper (best) command to use for sending and
returning the info?

?PHP
$link = mssql_connect($hostname,$username,$password);
$dblink = mssql_select_db($dbname, $link);
if ( $link  $dblink )
{
$query = select * from members where user = '$user' and pass = '$pass';
$result = mssql_query( $query );
if ( $result ) echo correct login;
else echo wrong login;
}
?

This is not working... i have tried everything i can think of that can work
but with no luck.
So if someone have a solution for me... i would apriciate it :)

(and yes i do have defined all the vars in the script they are just not that
important here)

-Chris




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[PHP] Source Code Formatter

2002-03-20 Thread José León Serna

Hello:
   Any of you know about any source code formatter for PHP? I mean a tool to
take a source code and produces an output file with the source code indented
like it must be.

Regards.


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RE: [PHP] Re: Return the column names of MySQL table?

2002-03-20 Thread Tim Ward

The result of the DESCRIBE query is a dataset like that of any other query
so ... 

$query = DESCRIBE montileaux_events ;
if ($result = mysql_query($query))
{   while ($field = mysql_fetch_array($result))
{   foreach($field as $key = $val)
{   echo $key : $val |;
}
echo(br);
}
}

Tim Ward
Internet Chess www.chessish.com http://www.chessish.com 

--
From:  Kevin Stone [SMTP:[EMAIL PROTECTED]]
Sent:  19 March 2002 23:21
To:  [EMAIL PROTECTED]
Subject:  RE: [PHP] Re:  Return the column names of MySQL table?

Philip thanks for the tip-off to the mysql_list_fields() function..
that
simplifies things quite a bit.  Problem solved. :)

I'm still wondering about the other method though.  I noticed the
DESCRIBE table_name method in the MySQL docs but couldn't figure
out
how to use it.  Alone it seems to return information about only the
first column...

?
$query = DESCRIBE montileaux_events ;
$result = mysql_fetch_array(mysql_query($query))
foreach ($result as $key = $val)
{
echo $key : $val br;
}
?

--- returns -
0 : keynum 
Field : keynum 
1 : int(11) 
Type : int(11) 
2 : 
Null : 
3 : PRI 
Key : PRI 
4 : 
5 : auto_increment 
Extra : auto_increment 
6 : select,insert,update,references 
Privileges : select,insert,update,references
--

keynum is the name of the frist column in the table.  But beyond
that
there doesn't appear to be any data to increment through.  The
function
returns this and only this.  Am I using it wrong?

Thanks,
Kevin


-Original Message-
From: Philip Hallstrom [mailto:[EMAIL PROTECTED]] 
Sent: Tuesday, March 19, 2002 4:02 PM
To: Geoff Hankerson
Cc: Kevin Stone; [EMAIL PROTECTED]
Subject: [PHP] Re: Return the column names of MySQL table?

Or if you want to do this within PHP use the mysql_list_fields
function.

On Tue, 19 Mar 2002, Geoff Hankerson wrote:

 I believe it is:
 describe tablename;
 - Original Message -
 From: Kevin Stone [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]
 Sent: Tuesday, March 19, 2002 4:43 PM
 Subject:  Return the column names of MySQL table?


  Forgive me for the off topic question.  This is a MySQL
question..
has
  nothing to do with PHP directly.  However I was not able to find
an
  answer in the MySQL documentation, on Usenet, or the MySQL
mailing
list
  archives.  Also MySQL.com's  mail manager is on the fritz so I
can't
  even subscribe to the MySQL email list.  Anyway since many of
you
are
  familiar with SQL this is as good a place to ask this question
as
any.
 
  I simply need to return a list of column names of a MySQL table.
What's
  the syntax to do that?
 
  Thanks,
  Kevin
 


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Re: [PHP] Making a simple borderless pop up window with a Closebutton

2002-03-20 Thread bvr



The 3rd parameter to JavaScript function window.open() allows you to 
disable a number of window elements every browser has,
these include the toolbar (buttons), location, status, menubar, scrollbars.
This functionality is provided by the most common browsers and versions 
(MSIE and Netscape) and will also work in Mozilla and Netscape 6.  I 
don't know about the JavaScript implementation in Opera, but if it 
supports JS it is likely to support these options too (or at least 
ingores them).

bvr.


Joe Webster wrote:

It only works in IE -- it makes use of the 'Full Screen' (F11) option and
tricks IE into doing so... hope you don't want it to work in NS, Opera... or
anything else




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[PHP] mail

2002-03-20 Thread Sven Jacobs

hey 

Is it possible to put somebody in CC when you use the mail() function ???



Re: [PHP] PHP - Forced header downloads

2002-03-20 Thread Rénald CASAGRAUDE

Ian Wayne wrote:
 
[...]
 
 /*retrieve filename from url*/
 $current=$REQUEST_URI;
 $url=parse_url($current);
 $fileq=$url[query];
 $file=$fileq..mov;
 
 /*force download*/
 header(Content-type:application/octet-stream\n);
 header(Content-disposition:attachment; filename=\$file\\n);
 header(Content-transfer-encoding:binary\n);
 header(Content-length:.filesize($file).\n);
 
 /*send file contents */
 $fp=fopen($file,r);
 fpassthru($fp);
 
 I can't tell you how long it's taken me to download anything and I'm still
 getting can't add header errors, but at least I'm downloading something. But
 how do I download the desired movie file?

You don't need newline (\n) at the end of your header

R.

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Re: [PHP] mail

2002-03-20 Thread RIVES Sergio

yes I guess
http://www.php.net/manual/en/function.mail.php
Good luck.
SR


Sven Jacobs a écrit :

 hey

 Is it possible to put somebody in CC when you use the mail() function ???


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[PHP] Sorting

2002-03-20 Thread Uma Shankari T.



Hii,

Actually i want to sort the files form mysql database using php
sorting.I can get the correct result using php sorting if the data's are
stored in the array like this format.

 $temp=array(apple,Orange,Gova)

please tell me how i will store the field details in a array fetched from
mysql database 


-Uma





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Re: [PHP] mail

2002-03-20 Thread TV Karthick Kumar

Yeah, just add Cc:[EMAIL PROTECTED] to your headers, that's
it...

Karthick


- Original Message -
From: Sven Jacobs [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, March 20, 2002 11:51 AM
Subject: [PHP] mail


 hey

 Is it possible to put somebody in CC when you use the mail() function ???



_
Do You Yahoo!?
Get your free @yahoo.com address at http://mail.yahoo.com


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[PHP] How to parse db-stored code

2002-03-20 Thread heinisch

Hi Folks,
I have stored several selects in a mysql-db,
it is possible to parse the answer, but I couldn´t remember how.
f.e.
the answer on a query is:
select * from somewhere where foo='$foo' and foofoo='$foofoo'
this is a string, what is the method to make the $foo-vars
real vars?

TIA Oliver


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Re: [PHP] how to seek and convert an email address to mailto link

2002-03-20 Thread Pekka Saarinen

At 3/20/2002, you wrote:
$newstr = preg_replace('/\b(\S+@\S+)\b/',
'a href=mailto:\1;\1/a', $oldstr);

Take the time to learn Perl-style regular expressions. You can practically
write Photoshop with them.

miguel

Thanks! It seems to work fine.
If I had time I'd try to learn regexp, but first I'll have to learn how not 
to be busy all the time.

Pekka


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Re: [PHP] Sorting

2002-03-20 Thread Oliver Heinisch

At 20.03.2002  16:29, you wrote:



Hii,

Actually i want to sort the files form mysql database using php
sorting.I can get the correct result using php sorting if the data's are
stored in the array like this format.

  $temp=array(apple,Orange,Gova)

please tell me how i will store the field details in a array fetched from
mysql database
even if you could sort the data with the correct select
f.e. select * from your_db where something='tru' order by 
the_field_you_wnt_to_sort,

the method you requested is something like
while($res=result_from_db_select)
(sorry for result_from_db_select but as I´m using objects for 
databaseactions, I
don´t know the exact commands maybe mysql_fetch_row)
{
for($i=0; $i  count($res); $i++) // counts all fields that come back
{
 $temp[$i] = $res[$i];
}
}
if you have a named array, you could also use an array for the names
f.e. $arraynames=array(first_col,second_col,third_col)
the your code would like
while($res=result_from_db_select)
{
for($i=0; $i  count($res); $i++) // counts all fields that come back
{
 $temp[$arraynames[$i]] = $res[$i];
}
}
HTH Oliver



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[PHP] Re:SOLVED [PHP] How to parse db-stored code

2002-03-20 Thread heinisch

At 20.03.2002  12:17, you wrote:
SOLVED !
  I have stored several selects in a mysql-db,
  it is possible to parse the answer, but I couldn´t remember how.
  f.e.  the answer on a query is:
  select * from somewhere where foo='$foo' and foofoo='$foofoo'
  this is a string, what is the method to make the $foo-vars
  real vars?

i would say, you can either do
  $val = $$whatYouGotFromTheDB;
or
  eval ( \$val=.$whatYouGotFromTheDB );
where $whatYouGotFromTheDB = '$foo';
should work either way, good luck

Thanks for the quick answer, I meant eval().

Oliver


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[PHP] email password and username

2002-03-20 Thread Craig

I am trying to create a system where a user can retreive there user name and
password details.

The problem is that the user name /password is in one table and the contact
details are in another. The contact details are refrenced to the username.

I want to acheive the following:
1. A user enters their email address into a form
2. The form submits to the database
3. The form checks the email and picks up the username / password
4. An email is sent to the relevant address with the password details

Can this be done? If so how??

Any comments will be grateful



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Re: [PHP] Re: [NEWMAN] make an if or else if statement from mysql.

2002-03-20 Thread Philip J. Newman

$sql = SELECT accessIP FROM `access` ORDER BY `accessID` DESC;
$sql_result = mysql_query($sql, $connection) or die (Could not get Query);

if (db_num_rows()  0) {
// Update view where ip = visitor_ip
 } else {

 // Normal insert
  $sql = INSERT INTO `access` (`accessID`, `accessIP`, `accessDNS`,
`accessTIME`, `accessUPDATE`, `accessVIEW`) VALUES ('', '$proxy_ip',
'$proxy_dns', '$add_date', NOW(NULL), '0');
 $result = mysql_query($sql);
 }

this gives me

Fatal error: Call to undefined function: db_num_rows() in
d:\hosting\crushme\index.php on line 20

anyone helo me fix this


- Original Message -
From: Philip J. Newman [EMAIL PROTECTED]
To: Julio Nobrega Trabalhando [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Wednesday, March 20, 2002 8:46 AM
Subject: Re: [PHP] Re: [NEWMAN] make an if or else if statement from
mysql.


 if (db_num_rows()  0) {

 mysql_query(UPDATE access SET access VIEW= accessVIEW+1 WHERE
accessIP
 = accessIP);  // Update view where ip = visitor_ip

  } else {

 $sql = INSERT INTO `access` (`accessID`, `accessIP`, `accessDNS`,
 `accessTIME`, `accessUPDATE`, `accessVIEW`) VALUES ('', '$proxy_ip',
 '$proxy_dns', '$add_date', NOW(NULL), '0');
 $result = mysql_query($sql);

  }

  if (db_num_rows()  0) {= WHERE DOSE THIS VERABLE COME FROM?

 - Original Message -
 From: Julio Nobrega Trabalhando [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]
 Sent: Wednesday, March 20, 2002 8:45 AM
 Subject: [PHP] Re: [NEWMAN] make an if or else if statement from
mysql.


  Select before to see if exists:
 
  if (db_num_rows()  0) {
 // Update view where ip = visitor_ip
  } else {
  // Normal insert
  }
 
  --
 
  Julio Nobrega.
 
  Um dia eu chego lá:
  http://sourceforge.net/projects/toca
 
  Ajudei? Salvei? Que tal um presentinho?
  http://www.submarino.com.br/wishlistclient.asp?wlid=664176742884
 
 
  Philip J. Newman [EMAIL PROTECTED] wrote in message
  003401c1cf85$1afe54c0$0401a8c0@philip">news:003401c1cf85$1afe54c0$0401a8c0@philip...
  I have a log of IP numbers that come to WEBSITE A
 
  $sql = INSERT INTO `access` (`accessID`, `accessIP`, `accessDNS`,
  `accessTIME`, `accessUPDATE`, `accessVIEW`) VALUES ('', '$proxy_ip',
  '$proxy_dns', '$add_date', NOW(NULL), '0');
 
  This has worked well, how ever when someone comes back with the same
  accessIP then I would like then accessVIEW aadds a +1 to the value.
 
  I would like help to create this ..
 
 
  if (!$remote_addr) - if the ip that they are using is the same as one
in
  the table then update the record and use the accessID for that record.
 
  else if there isn't that $remote_addr in the table then it is added.
 
  I have yet to start on the code, so would some direction.
 
  Philip J. Newman
  PhilipNZ :: Design Solutions
  http://www.philipnz.com/
  [EMAIL PROTECTED]
  ICQ# 20482482
  +64 25 6144012
 
 
 
  --
  PHP General Mailing List (http://www.php.net/)
  To unsubscribe, visit: http://www.php.net/unsub.php
 
 
 





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Re: [PHP] mail

2002-03-20 Thread Krzysztof Kocjan

 
//--
 function sendmail( $From, $To, $CC, $BCC, $Replay_To, $Subject, 
$Body, $Mailer, $Extra_Header ) {

 $Header = '';
 $Header .= 'From: ' . $From . \n;
 $Header .= 'Reply-To: ' . $Replay_To . \n;

 if ( $CC != '' ) {
 $Header .= CC:  . $CC . \n;
 }
 if ( $BCC != '' ) {
 $Header .= BCC:  . $BCC . \n;
 }
 if ( $Mailer == '' ) {
 $Header .= X-Mailer: PHP/ . phpversion();
 } else {
 $Header .= $Mailer;
 }
 $Header .= $Extra_Header;

 mail( $To, $Subject, $Body, $Header );


Krzysiek

Sven Jacobs wrote:

 hey 
 
 Is it possible to put somebody in CC when you use the mail() function ???
 
 
 --
 Aktualnosci gospodarcze. Gielda. Kursy. Stopy. Waluty. Kredyty... 
 Bezplatny Biuletyn Ekonomiczny.  http://biznes.interia.pl/biuletyn/
 
 



--
Doniesienia z ostatniej chwili  http://newsroom.interia.pl/



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RE: [PHP] Re: [NEWMAN] make an if or else if statement from mysql.

2002-03-20 Thread Brian Drexler

Try if(mysql_num_rows($sql_result)) instead of db_num_rows.  Hope this
helps.

Brian Drexler

-Original Message-
From: Philip J. Newman [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, March 20, 2002 7:09 AM
To: Philip J. Newman; Julio Nobrega Trabalhando
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP] Re: [NEWMAN] make an if or else if statement from
mysql.


$sql = SELECT accessIP FROM `access` ORDER BY `accessID` DESC;
$sql_result = mysql_query($sql, $connection) or die (Could not get Query);

if (db_num_rows()  0) {
// Update view where ip = visitor_ip
 } else {

 // Normal insert
  $sql = INSERT INTO `access` (`accessID`, `accessIP`, `accessDNS`,
`accessTIME`, `accessUPDATE`, `accessVIEW`) VALUES ('', '$proxy_ip',
'$proxy_dns', '$add_date', NOW(NULL), '0');
 $result = mysql_query($sql);
 }

this gives me

Fatal error: Call to undefined function: db_num_rows() in
d:\hosting\crushme\index.php on line 20

anyone helo me fix this


- Original Message -
From: Philip J. Newman [EMAIL PROTECTED]
To: Julio Nobrega Trabalhando [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Wednesday, March 20, 2002 8:46 AM
Subject: Re: [PHP] Re: [NEWMAN] make an if or else if statement from
mysql.


 if (db_num_rows()  0) {

 mysql_query(UPDATE access SET access VIEW= accessVIEW+1 WHERE
accessIP
 = accessIP);  // Update view where ip = visitor_ip

  } else {

 $sql = INSERT INTO `access` (`accessID`, `accessIP`, `accessDNS`,
 `accessTIME`, `accessUPDATE`, `accessVIEW`) VALUES ('', '$proxy_ip',
 '$proxy_dns', '$add_date', NOW(NULL), '0');
 $result = mysql_query($sql);

  }

  if (db_num_rows()  0) {= WHERE DOSE THIS VERABLE COME FROM?

 - Original Message -
 From: Julio Nobrega Trabalhando [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]
 Sent: Wednesday, March 20, 2002 8:45 AM
 Subject: [PHP] Re: [NEWMAN] make an if or else if statement from
mysql.


  Select before to see if exists:
 
  if (db_num_rows()  0) {
 // Update view where ip = visitor_ip
  } else {
  // Normal insert
  }
 
  --
 
  Julio Nobrega.
 
  Um dia eu chego lá:
  http://sourceforge.net/projects/toca
 
  Ajudei? Salvei? Que tal um presentinho?
  http://www.submarino.com.br/wishlistclient.asp?wlid=664176742884
 
 
  Philip J. Newman [EMAIL PROTECTED] wrote in message
  003401c1cf85$1afe54c0$0401a8c0@philip">news:003401c1cf85$1afe54c0$0401a8c0@philip...
  I have a log of IP numbers that come to WEBSITE A
 
  $sql = INSERT INTO `access` (`accessID`, `accessIP`, `accessDNS`,
  `accessTIME`, `accessUPDATE`, `accessVIEW`) VALUES ('', '$proxy_ip',
  '$proxy_dns', '$add_date', NOW(NULL), '0');
 
  This has worked well, how ever when someone comes back with the same
  accessIP then I would like then accessVIEW aadds a +1 to the value.
 
  I would like help to create this ..
 
 
  if (!$remote_addr) - if the ip that they are using is the same as one
in
  the table then update the record and use the accessID for that record.
 
  else if there isn't that $remote_addr in the table then it is added.
 
  I have yet to start on the code, so would some direction.
 
  Philip J. Newman
  PhilipNZ :: Design Solutions
  http://www.philipnz.com/
  [EMAIL PROTECTED]
  ICQ# 20482482
  +64 25 6144012
 
 
 
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  To unsubscribe, visit: http://www.php.net/unsub.php
 
 
 





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RE: [PHP] using reload within PHP when submitting a form

2002-03-20 Thread Rick Emery

I use this construct constantly.  Assume name of script is thisform.php3:

?php
if( isset($submit) )
{
print $myname;
exit;
}
?
HTML
HEAD
/HEAD
BODY
FORM method=post action=./thisform.php3
INPUT type=text name=myname value=BR
INPUT type=submit name=submit value=Submit
/FORM
/BODY
/HTML

-Original Message-
From: Daniel Negron/KBE [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, March 19, 2002 10:29 PM
To: [EMAIL PROTECTED]
Subject: [PHP] using reload within PHP when submitting a form


I have tried several variations within PHP to reload the page after
updating a form to PHP_SELF.  Does anyone have a working example within a
form AFTER a submit ?

**DAN**


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[PHP] Problem with gethostbyaddr()

2002-03-20 Thread Brian Drexler

Greetings all,
 I'm having a problem with the gethostbyaddr() function in PHP 4.1.2.
Whenever I use it, regardless of the IP (Intranet or Internet) it just
returns the IP.  It says in the manual if there is an error, it will return
the IP, but I can't figure out what the error is.  Anyone have any input?
Thanks in advance.

Brian Drexler
Operations Technician
Saginaw Control  Engineering
(989)799-6871 Ext. 497
http://www.saginawcontrol.com http://www.saginawcontrol.com/


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[PHP] edit record in mysql and receive error

2002-03-20 Thread Manu Verhaegen

Hi,
I have the following records in my table dnsDNS
Record 1 :
Login = company1
ip = 10.123.100.111
Record 2 :
Login = company2
ip = 10.123.101.111

I want to update recordnumber 1
I receive error

?php
  $ip=10.10.9.100;
  $company=company1;  
  $host=localhost;
  $user=username;
  $password=abcdef;
  $database=database1;
  $query = update dynDNS SET IP='$ip' where Login='$company'; 
  mysql_connect ($host, $user, $password);
  mysql_select_db($database);
  $result=mysql_query($query);
  if ($result == 0) {
echo(error);
echo(BR);
  }
?



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[PHP] LDAP and 2k

2002-03-20 Thread Matt Williams

Hi all

Has anyone been successful in authenticating ldap via win2k using 
samaccountname (username) instead of the users container name.

I can successfully do it against the cn but this is not always the same as 
the username.

All help/guidelines will be gratefully received.

matt

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[PHP] Filing Structure

2002-03-20 Thread Jesse Warden

I am coming from a Flash, Director, and VB type programming world.  Filing
structure and code structure in PHP is really new to me.

Therefore, does anyone have some an example filing structure I can look at
or documentation on how to best structure?

I downloaded a free message board (phpBB2) from sourceforge.net, and that's
a start.  Any more?

J


** Scanned for Viruses **

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Re: [PHP] HTML (to XML?) to PDF

2002-03-20 Thread Chris Boget

 Hm.  If you can't store the data as XML from the beginning (doesn't it 
 make more sense to go from XML to HTML than vice versa?), 

Yes, it does.  However, the people creating these templates don't know
XML, only HTML.  As such, that is how they are going to be stored. :|

 If your initial document is in XHTML form, you should be able to use 
 XSLT, since XHTML is a form of XML.

Yes, that would be the ideal situation.  However, that won't be the case.
So I need to find out some way to be able to either:

* Print the HTML (less tags, keep formatting) to PDF
* Convert the HTML to XML to I can then pass that onto the PDFClass
we are using.

Chris


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RE: [PHP] edit record in mysql and receive error

2002-03-20 Thread Rick Emery

We can't read your mind.

What kind of error do you get?

Second, I recommend that you ALWAYS add the die() clause to your mysql
function calls

-Original Message-
From: Manu Verhaegen [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, March 20, 2002 7:16 AM
To: 'Php-General (E-mail)
Subject: [PHP] edit record in mysql and receive error


Hi,
I have the following records in my table dnsDNS
Record 1 :
Login = company1
ip = 10.123.100.111
Record 2 :
Login = company2
ip = 10.123.101.111

I want to update recordnumber 1
I receive error

?php
  $ip=10.10.9.100;
  $company=company1;  
  $host=localhost;
  $user=username;
  $password=abcdef;
  $database=database1;
  $query = update dynDNS SET IP='$ip' where Login='$company'; 
  mysql_connect ($host, $user, $password);
  mysql_select_db($database);
  $result=mysql_query($query);
  if ($result == 0) {
echo(error);
echo(BR);
  }
?



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RE: [PHP] Problem with gethostbyaddr()

2002-03-20 Thread Brian Drexler

My apologies for wasting everyone's time.  gethostbyaddr() works fine, I had
gethostbyname() in my script.  Is today Monday or something?  Have a nice
day!

Brian

-Original Message-
From: Brian Drexler [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, March 20, 2002 8:15 AM
To: Php-General@Lists. Php. Net
Subject: [PHP] Problem with gethostbyaddr()


Greetings all,
 I'm having a problem with the gethostbyaddr() function in PHP 4.1.2.
Whenever I use it, regardless of the IP (Intranet or Internet) it just
returns the IP.  It says in the manual if there is an error, it will return
the IP, but I can't figure out what the error is.  Anyone have any input?
Thanks in advance.

Brian Drexler
Operations Technician
Saginaw Control  Engineering
(989)799-6871 Ext. 497
http://www.saginawcontrol.com http://www.saginawcontrol.com/


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[PHP] PHP for 3D scatterplots

2002-03-20 Thread Simon De Deyne

is there any code for this available yet?
I am looking for a way of plotting gif images of objects
in a 3D space...

thank you!
Simon


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[PHP] why doesnt this work???

2002-03-20 Thread chris

this script receives vars b and p from a form.
If b and p matches the echo on IF, then it works just fine.
The problem is that if the vars dont match the ELSE ECHO
does not apear... why not?

?
$bruker = $HTTP_POST_VARS[b];
$passord = $HTTP_POST_VARS[p];
$hostname = ;
$username = ;
$password = ;
$dbname = ;
MSSQL_CONNECT($hostname,$username,$password);
mssql_select_db($dbname);
$query = select * from medlemmer where bruker = '$bruker' and passord =
'$passord';
$result = mssql_query( $query );
for ($i = 0; $i  mssql_num_rows( $result ); ++$i)
 {

  $line = mssql_fetch_row($result);
  if( $line[1]='$bruker' and $line[2]='$passord')  echo hei $bruker.;
 else echo FEIL;
 }
?

-Chris



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RE: [PHP] why doesnt this work???

2002-03-20 Thread Rick Emery




  if( $line[1]='$bruker' and $line[2]='$passord')  {echo hei
$bruker.;}
 else {echo FEIL;}

-Original Message-
From: chris [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, March 20, 2002 8:15 AM
To: [EMAIL PROTECTED]
Subject: [PHP] why doesnt this work???


this script receives vars b and p from a form.
If b and p matches the echo on IF, then it works just fine.
The problem is that if the vars dont match the ELSE ECHO
does not apear... why not?

?
$bruker = $HTTP_POST_VARS[b];
$passord = $HTTP_POST_VARS[p];
$hostname = ;
$username = ;
$password = ;
$dbname = ;
MSSQL_CONNECT($hostname,$username,$password);
mssql_select_db($dbname);
$query = select * from medlemmer where bruker = '$bruker' and passord =
'$passord';
$result = mssql_query( $query );
for ($i = 0; $i  mssql_num_rows( $result ); ++$i)
 {

  $line = mssql_fetch_row($result);
  if( $line[1]='$bruker' and $line[2]='$passord')  echo hei $bruker.;
 else echo FEIL;
 }
?

-Chris



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Re: [PHP] why doesnt this work???

2002-03-20 Thread chris

nope... that did not do the trick...

-Chris

Rick Emery [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...



   if( $line[1]='$bruker' and $line[2]='$passord')  {echo hei
 $bruker.;}
  else {echo FEIL;}

 -Original Message-
 From: chris [mailto:[EMAIL PROTECTED]]
 Sent: Wednesday, March 20, 2002 8:15 AM
 To: [EMAIL PROTECTED]
 Subject: [PHP] why doesnt this work???


 this script receives vars b and p from a form.
 If b and p matches the echo on IF, then it works just fine.
 The problem is that if the vars dont match the ELSE ECHO
 does not apear... why not?

 ?
 $bruker = $HTTP_POST_VARS[b];
 $passord = $HTTP_POST_VARS[p];
 $hostname = ;
 $username = ;
 $password = ;
 $dbname = ;
 MSSQL_CONNECT($hostname,$username,$password);
 mssql_select_db($dbname);
 $query = select * from medlemmer where bruker = '$bruker' and passord =
 '$passord';
 $result = mssql_query( $query );
 for ($i = 0; $i  mssql_num_rows( $result ); ++$i)
  {

   $line = mssql_fetch_row($result);
   if( $line[1]='$bruker' and $line[2]='$passord')  echo hei
$bruker.;
  else echo FEIL;
  }
 ?

 -Chris



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Re: [PHP] why doesnt this work???

2002-03-20 Thread R'twick Niceorgaw

You need two = signs for comparision not just one .
Also I think you need to enclose the variables in double quote.

   if( $line[1]==$bruker and $line[2]==$passord)  echo hei
$bruker.;
 else echo FEIL;


 -Original Message-
 From: chris [mailto:[EMAIL PROTECTED]]
 Sent: Wednesday, March 20, 2002 8:15 AM
 To: [EMAIL PROTECTED]
 Subject: [PHP] why doesnt this work???


 this script receives vars b and p from a form.
 If b and p matches the echo on IF, then it works just fine.
 The problem is that if the vars dont match the ELSE ECHO
 does not apear... why not?

 ?
 $bruker = $HTTP_POST_VARS[b];
 $passord = $HTTP_POST_VARS[p];
 $hostname = ;
 $username = ;
 $password = ;
 $dbname = ;
 MSSQL_CONNECT($hostname,$username,$password);
 mssql_select_db($dbname);
 $query = select * from medlemmer where bruker = '$bruker' and passord =
 '$passord';
 $result = mssql_query( $query );
 for ($i = 0; $i  mssql_num_rows( $result ); ++$i)
  {

   $line = mssql_fetch_row($result);
   if( $line[1]='$bruker' and $line[2]='$passord')  echo hei
$bruker.;
  else echo FEIL;
  }
 ?

 -Chris



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RE: [PHP] why doesnt this work???

2002-03-20 Thread Stampe, Lars

Hi,

I am not an expert, but try

  if( $line[0]='$bruker' and $line[1]='$passord')  {echo hei $bruker.;}
 else {echo FEIL;}

atb
Lars

-Original Message-
From: chris [mailto:[EMAIL PROTECTED]]
Sent: 20 March 2002 14:22
To: [EMAIL PROTECTED]
Subject: Re: [PHP] why doesnt this work???


nope... that did not do the trick...

-Chris

Rick Emery [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...



   if( $line[1]='$bruker' and $line[2]='$passord')  {echo hei
 $bruker.;}
  else {echo FEIL;}

 -Original Message-
 From: chris [mailto:[EMAIL PROTECTED]]
 Sent: Wednesday, March 20, 2002 8:15 AM
 To: [EMAIL PROTECTED]
 Subject: [PHP] why doesnt this work???


 this script receives vars b and p from a form.
 If b and p matches the echo on IF, then it works just fine.
 The problem is that if the vars dont match the ELSE ECHO
 does not apear... why not?

 ?
 $bruker = $HTTP_POST_VARS[b];
 $passord = $HTTP_POST_VARS[p];
 $hostname = ;
 $username = ;
 $password = ;
 $dbname = ;
 MSSQL_CONNECT($hostname,$username,$password);
 mssql_select_db($dbname);
 $query = select * from medlemmer where bruker = '$bruker' and passord =
 '$passord';
 $result = mssql_query( $query );
 for ($i = 0; $i  mssql_num_rows( $result ); ++$i)
  {

   $line = mssql_fetch_row($result);
   if( $line[1]='$bruker' and $line[2]='$passord')  echo hei
$bruker.;
  else echo FEIL;
  }
 ?

 -Chris



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Re: [PHP] why doesnt this work???

2002-03-20 Thread chris

It still just comes out blank when the vars is wrong

R'Twick Niceorgaw [EMAIL PROTECTED] wrote in message
020501c1d01b$11eb1d00$[EMAIL PROTECTED]">news:020501c1d01b$11eb1d00$[EMAIL PROTECTED]...
 You need two = signs for comparision not just one .
 Also I think you need to enclose the variables in double quote.

if( $line[1]==$bruker and $line[2]==$passord)  echo hei
 $bruker.;
  else echo FEIL;


  -Original Message-
  From: chris [mailto:[EMAIL PROTECTED]]
  Sent: Wednesday, March 20, 2002 8:15 AM
  To: [EMAIL PROTECTED]
  Subject: [PHP] why doesnt this work???
 
 
  this script receives vars b and p from a form.
  If b and p matches the echo on IF, then it works just fine.
  The problem is that if the vars dont match the ELSE ECHO
  does not apear... why not?
 
  ?
  $bruker = $HTTP_POST_VARS[b];
  $passord = $HTTP_POST_VARS[p];
  $hostname = ;
  $username = ;
  $password = ;
  $dbname = ;
  MSSQL_CONNECT($hostname,$username,$password);
  mssql_select_db($dbname);
  $query = select * from medlemmer where bruker = '$bruker' and passord =
  '$passord';
  $result = mssql_query( $query );
  for ($i = 0; $i  mssql_num_rows( $result ); ++$i)
   {
 
$line = mssql_fetch_row($result);
if( $line[1]='$bruker' and $line[2]='$passord')  echo hei
 $bruker.;
   else echo FEIL;
   }
  ?
 
  -Chris
 
 
 
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  To unsubscribe, visit: http://www.php.net/unsub.php
 
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RE: [PHP] why doesnt this work???

2002-03-20 Thread Collins, Robert

instead of 'and' use ''

if($line[1] == $bruker  $line[2] == $passord){
echo hei $bruker.;
}else{
echo FEIL;
}

Robert W. Collins II
Webmaster
New Orleans Regional Transit Authority
Phone : (504) 248-3826
Email : [EMAIL PROTECTED]


-Original Message-
From: R'twick Niceorgaw [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, March 20, 2002 8:25 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] why doesnt this work???


You need two = signs for comparision not just one .
Also I think you need to enclose the variables in double quote.

   if( $line[1]==$bruker and $line[2]==$passord)  echo hei
$bruker.;
 else echo FEIL;


 -Original Message-
 From: chris [mailto:[EMAIL PROTECTED]]
 Sent: Wednesday, March 20, 2002 8:15 AM
 To: [EMAIL PROTECTED]
 Subject: [PHP] why doesnt this work???


 this script receives vars b and p from a form.
 If b and p matches the echo on IF, then it works just fine.
 The problem is that if the vars dont match the ELSE ECHO
 does not apear... why not?

 ?
 $bruker = $HTTP_POST_VARS[b];
 $passord = $HTTP_POST_VARS[p];
 $hostname = ;
 $username = ;
 $password = ;
 $dbname = ;
 MSSQL_CONNECT($hostname,$username,$password);
 mssql_select_db($dbname);
 $query = select * from medlemmer where bruker = '$bruker' and passord =
 '$passord';
 $result = mssql_query( $query );
 for ($i = 0; $i  mssql_num_rows( $result ); ++$i)
  {

   $line = mssql_fetch_row($result);
   if( $line[1]='$bruker' and $line[2]='$passord')  echo hei
$bruker.;
  else echo FEIL;
  }
 ?

 -Chris



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RE: [PHP] why doesnt this work???

2002-03-20 Thread Rick Emery

First: you need == not = to test equivalence.
Second, use  not '; otherwise $vars will not expand

if( $line[1]==$bruker and $line[2]==$passord) 
   {echo hei $bruker.;}
else {echo FEIL;}

-Original Message-
From: chris [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, March 20, 2002 8:22 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] why doesnt this work???


nope... that did not do the trick...

-Chris

Rick Emery [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...



   if( $line[1]='$bruker' and $line[2]='$passord')  {echo hei
 $bruker.;}
  else {echo FEIL;}

 -Original Message-
 From: chris [mailto:[EMAIL PROTECTED]]
 Sent: Wednesday, March 20, 2002 8:15 AM
 To: [EMAIL PROTECTED]
 Subject: [PHP] why doesnt this work???


 this script receives vars b and p from a form.
 If b and p matches the echo on IF, then it works just fine.
 The problem is that if the vars dont match the ELSE ECHO
 does not apear... why not?

 ?
 $bruker = $HTTP_POST_VARS[b];
 $passord = $HTTP_POST_VARS[p];
 $hostname = ;
 $username = ;
 $password = ;
 $dbname = ;
 MSSQL_CONNECT($hostname,$username,$password);
 mssql_select_db($dbname);
 $query = select * from medlemmer where bruker = '$bruker' and passord =
 '$passord';
 $result = mssql_query( $query );
 for ($i = 0; $i  mssql_num_rows( $result ); ++$i)
  {

   $line = mssql_fetch_row($result);
   if( $line[1]='$bruker' and $line[2]='$passord')  echo hei
$bruker.;
  else echo FEIL;
  }
 ?

 -Chris



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Re: [PHP] why doesnt this work???

2002-03-20 Thread chris

it all works just fine exept that when the vars is wrong i get a blank
page...wich means that the else echo doesnt work for some reason... and if i
use == the correct vars become wrong... but it does print the else echo...
hmm...


Robert Collins [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 instead of 'and' use ''

 if($line[1] == $bruker  $line[2] == $passord){
 echo hei $bruker.;
 }else{
 echo FEIL;
 }

 Robert W. Collins II
 Webmaster
 New Orleans Regional Transit Authority
 Phone : (504) 248-3826
 Email : [EMAIL PROTECTED]


 -Original Message-
 From: R'twick Niceorgaw [mailto:[EMAIL PROTECTED]]
 Sent: Wednesday, March 20, 2002 8:25 AM
 To: [EMAIL PROTECTED]
 Subject: Re: [PHP] why doesnt this work???


 You need two = signs for comparision not just one .
 Also I think you need to enclose the variables in double quote.

if( $line[1]==$bruker and $line[2]==$passord)  echo hei
 $bruker.;
  else echo FEIL;


  -Original Message-
  From: chris [mailto:[EMAIL PROTECTED]]
  Sent: Wednesday, March 20, 2002 8:15 AM
  To: [EMAIL PROTECTED]
  Subject: [PHP] why doesnt this work???
 
 
  this script receives vars b and p from a form.
  If b and p matches the echo on IF, then it works just fine.
  The problem is that if the vars dont match the ELSE ECHO
  does not apear... why not?
 
  ?
  $bruker = $HTTP_POST_VARS[b];
  $passord = $HTTP_POST_VARS[p];
  $hostname = ;
  $username = ;
  $password = ;
  $dbname = ;
  MSSQL_CONNECT($hostname,$username,$password);
  mssql_select_db($dbname);
  $query = select * from medlemmer where bruker = '$bruker' and passord =
  '$passord';
  $result = mssql_query( $query );
  for ($i = 0; $i  mssql_num_rows( $result ); ++$i)
   {
 
$line = mssql_fetch_row($result);
if( $line[1]='$bruker' and $line[2]='$passord')  echo hei
 $bruker.;
   else echo FEIL;
   }
  ?
 
  -Chris
 
 
 
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RE: [PHP] why doesnt this work???

2002-03-20 Thread Collins, Robert

Try this


if($line[1] == '$bruker'  $line[2] == '$passord'){
echo hei $bruker.;
}else{
echo FEIL;
}


Robert W. Collins II
Webmaster
New Orleans Regional Transit Authority
Phone : (504) 248-3826
Email : [EMAIL PROTECTED]


-Original Message-
From: chris [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, March 20, 2002 8:33 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] why doesnt this work???


it all works just fine exept that when the vars is wrong i get a blank
page...wich means that the else echo doesnt work for some reason... and if i
use == the correct vars become wrong... but it does print the else echo...
hmm...


Robert Collins [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 instead of 'and' use ''

 if($line[1] == $bruker  $line[2] == $passord){
 echo hei $bruker.;
 }else{
 echo FEIL;
 }

 Robert W. Collins II
 Webmaster
 New Orleans Regional Transit Authority
 Phone : (504) 248-3826
 Email : [EMAIL PROTECTED]


 -Original Message-
 From: R'twick Niceorgaw [mailto:[EMAIL PROTECTED]]
 Sent: Wednesday, March 20, 2002 8:25 AM
 To: [EMAIL PROTECTED]
 Subject: Re: [PHP] why doesnt this work???


 You need two = signs for comparision not just one .
 Also I think you need to enclose the variables in double quote.

if( $line[1]==$bruker and $line[2]==$passord)  echo hei
 $bruker.;
  else echo FEIL;


  -Original Message-
  From: chris [mailto:[EMAIL PROTECTED]]
  Sent: Wednesday, March 20, 2002 8:15 AM
  To: [EMAIL PROTECTED]
  Subject: [PHP] why doesnt this work???
 
 
  this script receives vars b and p from a form.
  If b and p matches the echo on IF, then it works just fine.
  The problem is that if the vars dont match the ELSE ECHO
  does not apear... why not?
 
  ?
  $bruker = $HTTP_POST_VARS[b];
  $passord = $HTTP_POST_VARS[p];
  $hostname = ;
  $username = ;
  $password = ;
  $dbname = ;
  MSSQL_CONNECT($hostname,$username,$password);
  mssql_select_db($dbname);
  $query = select * from medlemmer where bruker = '$bruker' and passord =
  '$passord';
  $result = mssql_query( $query );
  for ($i = 0; $i  mssql_num_rows( $result ); ++$i)
   {
 
$line = mssql_fetch_row($result);
if( $line[1]='$bruker' and $line[2]='$passord')  echo hei
 $bruker.;
   else echo FEIL;
   }
  ?
 
  -Chris
 
 
 
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  To unsubscribe, visit: http://www.php.net/unsub.php
 
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Re: [PHP] why doesnt this work???

2002-03-20 Thread chris

Thanx for all the help guys, but i have tried all of the sugestions  but the
one that works best is the one i startet with... but that one does not work
100% either...im so confused my head is about to fall of i just dont get
it...


Robert Collins [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 Try this


 if($line[1] == '$bruker'  $line[2] == '$passord'){
 echo hei $bruker.;
 }else{
 echo FEIL;
 }


 Robert W. Collins II
 Webmaster
 New Orleans Regional Transit Authority
 Phone : (504) 248-3826
 Email : [EMAIL PROTECTED]


 -Original Message-
 From: chris [mailto:[EMAIL PROTECTED]]
 Sent: Wednesday, March 20, 2002 8:33 AM
 To: [EMAIL PROTECTED]
 Subject: Re: [PHP] why doesnt this work???


 it all works just fine exept that when the vars is wrong i get a blank
 page...wich means that the else echo doesnt work for some reason... and if
i
 use == the correct vars become wrong... but it does print the else echo...
 hmm...


 Robert Collins [EMAIL PROTECTED] wrote in message
 [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
  instead of 'and' use ''
 
  if($line[1] == $bruker  $line[2] == $passord){
  echo hei $bruker.;
  }else{
  echo FEIL;
  }
 
  Robert W. Collins II
  Webmaster
  New Orleans Regional Transit Authority
  Phone : (504) 248-3826
  Email : [EMAIL PROTECTED]
 
 
  -Original Message-
  From: R'twick Niceorgaw [mailto:[EMAIL PROTECTED]]
  Sent: Wednesday, March 20, 2002 8:25 AM
  To: [EMAIL PROTECTED]
  Subject: Re: [PHP] why doesnt this work???
 
 
  You need two = signs for comparision not just one .
  Also I think you need to enclose the variables in double quote.
 
 if( $line[1]==$bruker and $line[2]==$passord)  echo hei
  $bruker.;
   else echo FEIL;
 
 
   -Original Message-
   From: chris [mailto:[EMAIL PROTECTED]]
   Sent: Wednesday, March 20, 2002 8:15 AM
   To: [EMAIL PROTECTED]
   Subject: [PHP] why doesnt this work???
  
  
   this script receives vars b and p from a form.
   If b and p matches the echo on IF, then it works just fine.
   The problem is that if the vars dont match the ELSE ECHO
   does not apear... why not?
  
   ?
   $bruker = $HTTP_POST_VARS[b];
   $passord = $HTTP_POST_VARS[p];
   $hostname = ;
   $username = ;
   $password = ;
   $dbname = ;
   MSSQL_CONNECT($hostname,$username,$password);
   mssql_select_db($dbname);
   $query = select * from medlemmer where bruker = '$bruker' and passord
=
   '$passord';
   $result = mssql_query( $query );
   for ($i = 0; $i  mssql_num_rows( $result ); ++$i)
{
  
 $line = mssql_fetch_row($result);
 if( $line[1]='$bruker' and $line[2]='$passord')  echo hei
  $bruker.;
else echo FEIL;
}
   ?
  
   -Chris
  
  
  
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RE: [PHP] why doesnt this work???

2002-03-20 Thread Stampe, Lars

Please try this :)

for ($i = 0; $i  mssql_num_rows( $result ); $i++)

  {
  $line = mssql_fetch_row($result);

  if (($line[0] == $bruker)  ($line[1] == $passord)) 
  {
echo hei $line[0];
}
  else
{
echo FEIL;
}

Lars Stampe

-Original Message-
From: Rick Emery [mailto:[EMAIL PROTECTED]]
Sent: 20 March 2002 14:30
To: 'chris'; [EMAIL PROTECTED]
Subject: RE: [PHP] why doesnt this work???


First: you need == not = to test equivalence.
Second, use  not '; otherwise $vars will not expand

if( $line[1]==$bruker and $line[2]==$passord) 
   {echo hei $bruker.;}
else {echo FEIL;}

-Original Message-
From: chris [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, March 20, 2002 8:22 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] why doesnt this work???


nope... that did not do the trick...

-Chris

Rick Emery [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...



   if( $line[1]='$bruker' and $line[2]='$passord')  {echo hei
 $bruker.;}
  else {echo FEIL;}

 -Original Message-
 From: chris [mailto:[EMAIL PROTECTED]]
 Sent: Wednesday, March 20, 2002 8:15 AM
 To: [EMAIL PROTECTED]
 Subject: [PHP] why doesnt this work???


 this script receives vars b and p from a form.
 If b and p matches the echo on IF, then it works just fine.
 The problem is that if the vars dont match the ELSE ECHO
 does not apear... why not?

 ?
 $bruker = $HTTP_POST_VARS[b];
 $passord = $HTTP_POST_VARS[p];
 $hostname = ;
 $username = ;
 $password = ;
 $dbname = ;
 MSSQL_CONNECT($hostname,$username,$password);
 mssql_select_db($dbname);
 $query = select * from medlemmer where bruker = '$bruker' and passord =
 '$passord';
 $result = mssql_query( $query );
 for ($i = 0; $i  mssql_num_rows( $result ); ++$i)
  {

   $line = mssql_fetch_row($result);
   if( $line[1]='$bruker' and $line[2]='$passord')  echo hei
$bruker.;
  else echo FEIL;
  }
 ?

 -Chris



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RE: [PHP] PHP - mssql

2002-03-20 Thread Mark Roedel

 -Original Message-
 From: chris [mailto:[EMAIL PROTECTED]] 
 Sent: Wednesday, March 20, 2002 3:38 AM
 To: [EMAIL PROTECTED]
 Subject: [PHP] PHP - mssql
 
 
 ?PHP
 $link = mssql_connect($hostname,$username,$password);
 $dblink = mssql_select_db($dbname, $link);
 if ( $link  $dblink )
 {
 $query = select * from members where user = '$user' and pass 
 = '$pass';
 $result = mssql_query( $query );
 if ( $result ) echo correct login;
 else echo wrong login;
 }
 ?
 
 This is not working... i have tried everything i can think of 
 that can work but with no luck.

In what way isn't it working?  Do you get an error message, or just not
the result you were expecting?

If it's the latter (in particular, if you're getting correct login no
matter what values you use for $user and $pass), the issue is likely
related to the fact that mssql_query() returns a result identifier which
doesn't necessarily have any correlation to the contents of the result
set -- it'll only return false if there's an error in your query (and a
query can be error-free and still not return data).

For what you're doing, you'll probably want to take a look at
mssql_num_rows().


---
Mark Roedel   | Blessed is he who has learned to laugh
Systems Programmer|  at himself, for he shall never cease
LeTourneau University |  to be entertained.
Longview, Texas, USA  |  -- John Powell


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RE: [PHP] why doesnt this work???

2002-03-20 Thread Rick Emery

This works; I just tried it.

?php
$line = bruker;
$bruker = bruker;
$linex = passwordx;
$password = password;

if( !strcmp($line,$bruker)  !strcmp($line,$password) )  {echo hei
$bruker.;}
else {echo FEIL;}
?

-Original Message-
From: chris [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, March 20, 2002 8:41 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] why doesnt this work???


Thanx for all the help guys, but i have tried all of the sugestions  but the
one that works best is the one i startet with... but that one does not work
100% either...im so confused my head is about to fall of i just dont get
it...


Robert Collins [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 Try this


 if($line[1] == '$bruker'  $line[2] == '$passord'){
 echo hei $bruker.;
 }else{
 echo FEIL;
 }


 Robert W. Collins II
 Webmaster
 New Orleans Regional Transit Authority
 Phone : (504) 248-3826
 Email : [EMAIL PROTECTED]


 -Original Message-
 From: chris [mailto:[EMAIL PROTECTED]]
 Sent: Wednesday, March 20, 2002 8:33 AM
 To: [EMAIL PROTECTED]
 Subject: Re: [PHP] why doesnt this work???


 it all works just fine exept that when the vars is wrong i get a blank
 page...wich means that the else echo doesnt work for some reason... and if
i
 use == the correct vars become wrong... but it does print the else echo...
 hmm...


 Robert Collins [EMAIL PROTECTED] wrote in message
 [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
  instead of 'and' use ''
 
  if($line[1] == $bruker  $line[2] == $passord){
  echo hei $bruker.;
  }else{
  echo FEIL;
  }
 
  Robert W. Collins II
  Webmaster
  New Orleans Regional Transit Authority
  Phone : (504) 248-3826
  Email : [EMAIL PROTECTED]
 
 
  -Original Message-
  From: R'twick Niceorgaw [mailto:[EMAIL PROTECTED]]
  Sent: Wednesday, March 20, 2002 8:25 AM
  To: [EMAIL PROTECTED]
  Subject: Re: [PHP] why doesnt this work???
 
 
  You need two = signs for comparision not just one .
  Also I think you need to enclose the variables in double quote.
 
 if( $line[1]==$bruker and $line[2]==$passord)  echo hei
  $bruker.;
   else echo FEIL;
 
 
   -Original Message-
   From: chris [mailto:[EMAIL PROTECTED]]
   Sent: Wednesday, March 20, 2002 8:15 AM
   To: [EMAIL PROTECTED]
   Subject: [PHP] why doesnt this work???
  
  
   this script receives vars b and p from a form.
   If b and p matches the echo on IF, then it works just fine.
   The problem is that if the vars dont match the ELSE ECHO
   does not apear... why not?
  
   ?
   $bruker = $HTTP_POST_VARS[b];
   $passord = $HTTP_POST_VARS[p];
   $hostname = ;
   $username = ;
   $password = ;
   $dbname = ;
   MSSQL_CONNECT($hostname,$username,$password);
   mssql_select_db($dbname);
   $query = select * from medlemmer where bruker = '$bruker' and passord
=
   '$passord';
   $result = mssql_query( $query );
   for ($i = 0; $i  mssql_num_rows( $result ); ++$i)
{
  
 $line = mssql_fetch_row($result);
 if( $line[1]='$bruker' and $line[2]='$passord')  echo hei
  $bruker.;
else echo FEIL;
}
   ?
  
   -Chris
  
  
  
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RE: [PHP] why doesnt this work???

2002-03-20 Thread Collins, Robert

This works :

?php
$line = array('','bob','tpw');
$bruker = 'bob';
$passord = 'pw';

if($bruker == $line[1]  $passord == $line[2]){
echo hei $bruker.;
}else{
echo FEIL;
}
?

Robert W. Collins II
Webmaster
New Orleans Regional Transit Authority
Phone : (504) 248-3826
Email : [EMAIL PROTECTED]


-Original Message-
From: chris [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, March 20, 2002 8:41 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] why doesnt this work???


Thanx for all the help guys, but i have tried all of the sugestions  but the
one that works best is the one i startet with... but that one does not work
100% either...im so confused my head is about to fall of i just dont get
it...


Robert Collins [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 Try this


 if($line[1] == '$bruker'  $line[2] == '$passord'){
 echo hei $bruker.;
 }else{
 echo FEIL;
 }


 Robert W. Collins II
 Webmaster
 New Orleans Regional Transit Authority
 Phone : (504) 248-3826
 Email : [EMAIL PROTECTED]


 -Original Message-
 From: chris [mailto:[EMAIL PROTECTED]]
 Sent: Wednesday, March 20, 2002 8:33 AM
 To: [EMAIL PROTECTED]
 Subject: Re: [PHP] why doesnt this work???


 it all works just fine exept that when the vars is wrong i get a blank
 page...wich means that the else echo doesnt work for some reason... and if
i
 use == the correct vars become wrong... but it does print the else echo...
 hmm...


 Robert Collins [EMAIL PROTECTED] wrote in message
 [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
  instead of 'and' use ''
 
  if($line[1] == $bruker  $line[2] == $passord){
  echo hei $bruker.;
  }else{
  echo FEIL;
  }
 
  Robert W. Collins II
  Webmaster
  New Orleans Regional Transit Authority
  Phone : (504) 248-3826
  Email : [EMAIL PROTECTED]
 
 
  -Original Message-
  From: R'twick Niceorgaw [mailto:[EMAIL PROTECTED]]
  Sent: Wednesday, March 20, 2002 8:25 AM
  To: [EMAIL PROTECTED]
  Subject: Re: [PHP] why doesnt this work???
 
 
  You need two = signs for comparision not just one .
  Also I think you need to enclose the variables in double quote.
 
 if( $line[1]==$bruker and $line[2]==$passord)  echo hei
  $bruker.;
   else echo FEIL;
 
 
   -Original Message-
   From: chris [mailto:[EMAIL PROTECTED]]
   Sent: Wednesday, March 20, 2002 8:15 AM
   To: [EMAIL PROTECTED]
   Subject: [PHP] why doesnt this work???
  
  
   this script receives vars b and p from a form.
   If b and p matches the echo on IF, then it works just fine.
   The problem is that if the vars dont match the ELSE ECHO
   does not apear... why not?
  
   ?
   $bruker = $HTTP_POST_VARS[b];
   $passord = $HTTP_POST_VARS[p];
   $hostname = ;
   $username = ;
   $password = ;
   $dbname = ;
   MSSQL_CONNECT($hostname,$username,$password);
   mssql_select_db($dbname);
   $query = select * from medlemmer where bruker = '$bruker' and passord
=
   '$passord';
   $result = mssql_query( $query );
   for ($i = 0; $i  mssql_num_rows( $result ); ++$i)
{
  
 $line = mssql_fetch_row($result);
 if( $line[1]='$bruker' and $line[2]='$passord')  echo hei
  $bruker.;
else echo FEIL;
}
   ?
  
   -Chris
  
  
  
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[PHP] new to php/mysql - insert not working

2002-03-20 Thread ROBERT MCPEAK

Can somebody help me with this?

The following code gets me document contains no data.  I have done a
successfull select from mysql db, but not an insertion.

I don't know how to troubleshoot this.  Any help is much appreciated. 
Thanks!

?php


$id = addslashes($id);
$visitdate = addslashes($visitdate);
$img_group = addslashes($img_group);
$img_url = addslashes($img_url);
$display = addslashes($display);



 $db = mysql_connect(www, mmc, mmc-WWW);

  if (!$db)
  {
 echo Error: Could not connect to database.  Please try again
later.;
 exit;
  }

  mysql_select_db(mmc);
  $query = insert into visitorgallery values
('.$id.', '.$img_url.', '.$visitdate.',
'.$img_group.', '.$display.', );


 
  $result = mysql_query($query);
  if ($result)
echo mysql_affected_rows(). Image inserted! ;



?

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RE: [PHP] why doesnt this work???

2002-03-20 Thread Stampe, Lars

Hi,

Let me explain what is wrong with this line:

   if( $line[1]='$bruker' and $line[2]='$passord')

when you use = instead of == it will always be true because you set $line[1]
to $bruker, you have to compare them by using ==. Also looking at your sql
query $line[0] would contain your username and $line[1] your password!

try after

  $line = mssql_fetch_row($result);

echo DEBUG : $line[0] - $line[1] - $line[2];



  if( $line[1]='$bruker' and $line[2]='$passord')  echo hei $bruker.;
else echo FEIL;

Regards
Lars Stampe

-Original Message-
From: chris [mailto:[EMAIL PROTECTED]]
Sent: 20 March 2002 14:41
To: [EMAIL PROTECTED]
Subject: Re: [PHP] why doesnt this work???


Thanx for all the help guys, but i have tried all of the sugestions  but the
one that works best is the one i startet with... but that one does not work
100% either...im so confused my head is about to fall of i just dont get
it...


Robert Collins [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 Try this


 if($line[1] == '$bruker'  $line[2] == '$passord'){
 echo hei $bruker.;
 }else{
 echo FEIL;
 }


 Robert W. Collins II
 Webmaster
 New Orleans Regional Transit Authority
 Phone : (504) 248-3826
 Email : [EMAIL PROTECTED]


 -Original Message-
 From: chris [mailto:[EMAIL PROTECTED]]
 Sent: Wednesday, March 20, 2002 8:33 AM
 To: [EMAIL PROTECTED]
 Subject: Re: [PHP] why doesnt this work???


 it all works just fine exept that when the vars is wrong i get a blank
 page...wich means that the else echo doesnt work for some reason... and if
i
 use == the correct vars become wrong... but it does print the else echo...
 hmm...


 Robert Collins [EMAIL PROTECTED] wrote in message
 [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
  instead of 'and' use ''
 
  if($line[1] == $bruker  $line[2] == $passord){
  echo hei $bruker.;
  }else{
  echo FEIL;
  }
 
  Robert W. Collins II
  Webmaster
  New Orleans Regional Transit Authority
  Phone : (504) 248-3826
  Email : [EMAIL PROTECTED]
 
 
  -Original Message-
  From: R'twick Niceorgaw [mailto:[EMAIL PROTECTED]]
  Sent: Wednesday, March 20, 2002 8:25 AM
  To: [EMAIL PROTECTED]
  Subject: Re: [PHP] why doesnt this work???
 
 
  You need two = signs for comparision not just one .
  Also I think you need to enclose the variables in double quote.
 
 if( $line[1]==$bruker and $line[2]==$passord)  echo hei
  $bruker.;
   else echo FEIL;
 
 
   -Original Message-
   From: chris [mailto:[EMAIL PROTECTED]]
   Sent: Wednesday, March 20, 2002 8:15 AM
   To: [EMAIL PROTECTED]
   Subject: [PHP] why doesnt this work???
  
  
   this script receives vars b and p from a form.
   If b and p matches the echo on IF, then it works just fine.
   The problem is that if the vars dont match the ELSE ECHO
   does not apear... why not?
  
   ?
   $bruker = $HTTP_POST_VARS[b];
   $passord = $HTTP_POST_VARS[p];
   $hostname = ;
   $username = ;
   $password = ;
   $dbname = ;
   MSSQL_CONNECT($hostname,$username,$password);
   mssql_select_db($dbname);
   $query = select * from medlemmer where bruker = '$bruker' and passord
=
   '$passord';
   $result = mssql_query( $query );
   for ($i = 0; $i  mssql_num_rows( $result ); ++$i)
{
  
 $line = mssql_fetch_row($result);
 if( $line[1]='$bruker' and $line[2]='$passord')  echo hei
  $bruker.;
else echo FEIL;
}
   ?
  
   -Chris
  
  
  
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[PHP] Re: PHP for 3D scatterplots

2002-03-20 Thread Hugh Bothwell


Simon De Deyne [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 is there any code for this available yet?
 I am looking for a way of plotting gif images of objects
 in a 3D space...

 thank you!
 Simon

Don't know of any offhand, but it doesn't sound all THAT hard to develop...
actually, it could be kind of interesting.  In fact, if you want to include
a few more details I might whip up a demo for you.

- what kind of axis scaling do you want?  (linear / log)
- axis data range figured how? (specified / auto)
- where do you want the axis drawn (back edge / full box / at 0s)
- what kind of projection (orthogonal / perspective)
- how to draw data points (single-pixel / ball / icon)
- depth indication (none / shading / drop-line to axis / other)
- should data points be scaled (no / by size / by color)
- how to handle overlapping / coincident data (ignore / emphasize)
- how to color data points (specified / per-point / random/arbitrary)



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[PHP] Accessing form variables

2002-03-20 Thread Joshua E Minnie

I have a form with a menu which I need multiple select on.  How does PHP
handle this?  I have to use $HTTP_POST_VARS[somevariable] to access
somevariable from the form.

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CIO
[EMAIL PROTECTED]

Don't work for recognition, but always do work worthy of recognition.



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[PHP] safe_mode_include_dir not working

2002-03-20 Thread Estelle Martin

Hi all,
I have PHP 4.1.2 as Apache module, Safe-Mode On. I want to use the
safe_mode_include_dir directive and ... this does not work.
I have this in the directory directive of httpd.conf, I put the include_path
to exactly the same path, I use complete path, and I always get the
safe-mode restriction in effect error.
I have found some information about this directive working for 4.0.7 and
higher, but nothing usefull ( I tried several configurations ) to me and
nothing about 4.1.2.

Any idea, or tricks from people for whom it works ?

Many thanks,

Estelle

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[PHP] Db Access Count

2002-03-20 Thread Randum Ian

Hi there,

I want to have a field in a database that counts the number of times 
that particular record has been viewed on the website. When is the best 
time to increment the count in the file and how?

Kind Regards, Ian.




[PHP] Re: why doesnt this work???

2002-03-20 Thread Matt Wallace


What I think you'd note, actually, is that you ALWAYS get the matching
echo, and never the non-matching, because you're using an assignment
operator instead of comparison. It should read if ($line[1]=='
instead of ($line[1]='.

--Matt

Chris wrote:

 this script receives vars b and p from a form.
 If b and p matches the echo on IF, then it works just fine.
 The problem is that if the vars dont match the ELSE ECHO
 does not apear... why not?
 
 ?
 $bruker = $HTTP_POST_VARS[b];
 $passord = $HTTP_POST_VARS[p];
 $hostname = ;
 $username = ;
 $password = ;
 $dbname = ;
 MSSQL_CONNECT($hostname,$username,$password);
 mssql_select_db($dbname);
 $query = select * from medlemmer where bruker = '$bruker' and passord =
 '$passord';
 $result = mssql_query( $query );
 for ($i = 0; $i  mssql_num_rows( $result ); ++$i)
  {
 
   $line = mssql_fetch_row($result);
   if( $line[1]='$bruker' and $line[2]='$passord')  echo hei $bruker.;
  else echo FEIL;
  }
 ?
 
 -Chris


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[PHP] Re: Delete Confirmation

2002-03-20 Thread Matt Wallace

Daniel Negron/Kbe wrote:

 Does anyone have examples of record deletions from php to mysql


Could you be more specific?

$sql = DELETE from tablename where tablename_idx = $index;
$result = mysql_query($sql);

would be a very simple example of deleting a record from a hypothetical 
database with php, but I'm not sure if that's what you were really asking.





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[PHP] Re: new to php/mysql - insert not working

2002-03-20 Thread Matt Wallace


The actual typo in your code is a trailing comma in your sql statement.

  '.$img_group.', '.$display.', );

Strip out the comma after your last single quote.

It's very useful to have CLI access to mysql. Then you could just say,
print QUERY: $query BR\n;
and instead of executing it, paste it into the mysql CLI and see what it has
to say. You may also want to keep an eye on your web server logs, or
raise php errors so they are printed in the web server output, but in this 
case, you'd probably see no error.

--Matt


Robert McPeak wrote:

 Can somebody help me with this?
 
 The following code gets me document contains no data.  I have done a
 successfull select from mysql db, but not an insertion.
 
 I don't know how to troubleshoot this.  Any help is much appreciated. 
 Thanks!
 
 ?php
 
 
 $id = addslashes($id);
 $visitdate = addslashes($visitdate);
 $img_group = addslashes($img_group);
 $img_url = addslashes($img_url);
 $display = addslashes($display);
 
 
 
  $db = mysql_connect(www, mmc, mmc-WWW);
 
   if (!$db)
   {
  echo Error: Could not connect to database.  Please try again
 later.;
  exit;
   }
 
   mysql_select_db(mmc);
   $query = insert into visitorgallery values
   ('.$id.', '.$img_url.', '.$visitdate.',
 '.$img_group.', '.$display.', );
 
 
  
   $result = mysql_query($query);
   if ($result)
   echo mysql_affected_rows(). Image inserted! ;
 
 
 
 ?
 



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Re: [PHP] new to php/mysql - insert not working

2002-03-20 Thread Michael Egan

Robert,

I still feel fairly new to this myself but if I find that I'm having
problems writing to the database I generally try to echo the query to
the page and then test this out directly with the command line prompt
directly to the database.

At least that way you can test out the query in isolation.

Good luck,

Michael

 The following code gets me document contains no data.  I have done a
 successfull select from mysql db, but not an insertion.
 
 I don't know how to troubleshoot this.  Any help is much appreciated.
 Thanks!
 
 ?php
 
 $id = addslashes($id);
 $visitdate = addslashes($visitdate);
 $img_group = addslashes($img_group);
 $img_url = addslashes($img_url);
 $display = addslashes($display);
 
  $db = mysql_connect(www, mmc, mmc-WWW);
 
   if (!$db)
   {
  echo Error: Could not connect to database.  Please try again
 later.;
  exit;
   }
 
   mysql_select_db(mmc);
   $query = insert into visitorgallery values
 ('.$id.', '.$img_url.', '.$visitdate.',
 '.$img_group.', '.$display.', );
 
 
   $result = mysql_query($query);
   if ($result)
 echo mysql_affected_rows(). Image inserted! ;
 
 ?
 
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[PHP] Re: Accessing form variables

2002-03-20 Thread Matt Wallace


If your form is:

SELECT name=a
OPTION value=11/OPTION
OPTION value=22/OPTION
/SELECT

SELECT name=b
OPTION value=11/OPTION
OPTION value=22/OPTION
/SELECT

Then you'd have two php post variables available, a and b, each
would have a value of 1 or 2, which you could get from HTTP_POST_VARS
or, with later php versions, $_POST[a] and $_POST[b].

Joshua E Minnie wrote:

 I have a form with a menu which I need multiple select on.  How does PHP
 handle this?  I have to use $HTTP_POST_VARS[somevariable] to access
 somevariable from the form.
 
 --
 Joshua E Minnie
 CIO
 [EMAIL PROTECTED]
 
 Don't work for recognition, but always do work worthy of recognition.
 
 
 



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[PHP] Re: sessions not so secure..solution?

2002-03-20 Thread Matt Wallace

Steve Clay wrote:

 Hello,
   I'm building an e-commerce site which uses sessions to
 hold my $cart object.  This works great but I've two worries:
 
 1) When the user connects through our secure hostname, can I ensure
 the browser will send the server the cookie (w/ SESSID)?  The user
 will shop through domain.com and checkout via https:secure.domain.com.
 (haven't got cert yet)


If your cookie domain is .domain.com, it will send the cookie to
both, however, you don't really WANT to use the same cookie in both
places.


 2) While the user shops the SESSID is thrown around insecurely (no big
 deal, just a cart).  But when I move the user to a secure server to
 get sensitive info a resourceful hacker could also go to the checkout
 script using this SESSID and 'confirm' the real user's personal
 details (kept in another registered session object).


Yes, and so this is inappropriate. Allocate a cookie for all pages (ssl
and not). When they transition to SSL for checkout, then give them an
SSL cookie as well, and associate it with the old cookie. You could store
them in a session -- I do it in a database table. Store the time you
allocated the SSL cookie. Mandate that when someone views a secure page, to
be considered authenticated, they must hand you the SSL-only cookie. You
can use its association to retrieve the cart, but not to let someone else 
interrupt the ordering process, or use its authentication properties to
view personal details, cancel an order, etc. Since you set the cookie to
be SSL-ONLY (there's a flag for that in setcookie()), it won't be passed
in the clear. Associate the assignment time of the cookie with it, and each
pageview, reset it to some reasonable number, say 5-30 min. After that time
expires, the cookie is no good and you reassign one. In my own scheme, that's
when a user re-enters their password.


Anyhow, the dual-cookie approach will allow you to maintain reasonable

security.




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[PHP] HTTP_Upload with PHP

2002-03-20 Thread Rick

We have an application that used PHP's FTP function to upload files. Now it
worked until we upgraded to 4.1.2. We have now downgraded back to 4.1.1 but
still no luck, it won't work.

We have set upload_max_filesize and post_max_size as well, and that doesn't
seem to help. Here is the following code. It has not changed since it went
live:

srand((double)microtime()*100); //Create random timestamp for the
file temp file
$randval = rand();
//Creates a temp file that the file gets put in, we then read that file
$tmpfile = /tmp/ . $file_name . $randval;
copy($file,$tmpfile);//line 272
ftp_put($this-connection,$file_name,$tmpfile,FTP_BINARY); //line 273
unlink($tmpfile);
return true;

This is inside a function, and $file is the handle for the uploaded file and
$file_name is the name of the uploaded file. The weird thing is that this
will work for small files ( 1MB). Anything bigger, it gives us the
following errors:

Warning: Unable to open 'none' for reading: No such file or directory in
/Ftp.inc on line 272
Warning: error opening /tmp/IP4_0EngALLMsi.exe1419195771 in /Ftp.inc on line
273

Any ideas? It seems as if the big files are not getting passed in?

Thanks,
/rick



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Re: [PHP] HTTP_Upload with PHP

2002-03-20 Thread Rasmus Lerdorf

'none' comes from a failed file upload.  Figure out why the file upload is
not working.  Did you perhaps turn file uploads off in your php.ini file?

-Rasmus

On Wed, 20 Mar 2002, Rick wrote:

 We have an application that used PHP's FTP function to upload files. Now it
 worked until we upgraded to 4.1.2. We have now downgraded back to 4.1.1 but
 still no luck, it won't work.

 We have set upload_max_filesize and post_max_size as well, and that doesn't
 seem to help. Here is the following code. It has not changed since it went
 live:

 srand((double)microtime()*100); //Create random timestamp for the
 file temp file
 $randval = rand();
 //Creates a temp file that the file gets put in, we then read that file
 $tmpfile = /tmp/ . $file_name . $randval;
 copy($file,$tmpfile);//line 272
 ftp_put($this-connection,$file_name,$tmpfile,FTP_BINARY); //line 273
 unlink($tmpfile);
 return true;

 This is inside a function, and $file is the handle for the uploaded file and
 $file_name is the name of the uploaded file. The weird thing is that this
 will work for small files ( 1MB). Anything bigger, it gives us the
 following errors:

 Warning: Unable to open 'none' for reading: No such file or directory in
 /Ftp.inc on line 272
 Warning: error opening /tmp/IP4_0EngALLMsi.exe1419195771 in /Ftp.inc on line
 273

 Any ideas? It seems as if the big files are not getting passed in?

 Thanks,
 /rick



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[PHP] Multipage form

2002-03-20 Thread David Johansen

I was just wondering what was the best way to handle a multipage form. Would
the best way be to keep passing the variables through the forms as hidden
values or should I use sessions and store all the values as session
variables? What's the best way to handle all of this? Also the different
forms will all be in the same php file that loops to itself if that makes a
difference. Thanks,
Dave



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[PHP] environment variable code fails

2002-03-20 Thread jrfoutin

?
session_start();
include($DOCUMENT_ROOT/php/main.home.php);
?

The environment variable in this code on index.php is not invoking
main.home.php page in php folder in htdocs on new server.

Code worked on previous server setup, but fails on new server. Other php

calls to MySQL db in ported site code that uses environment variable
seems to work fine, but this very first start page code fails.

What can be wrong?--JRF


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[PHP] Problem with HTTP Authorization

2002-03-20 Thread Brian Drexler

I realize this may be a bit out of the scope of this list, but I'm sure
someone out there can help.  Here is my problem.  I'm using
htaccess/htpasswd for authentication on my site.  I want to know if there is
a way that when a user opens a link in a new window, their htaccess
information stays the same.  As it is right now, if USER1 clicks on a link
that opens a new window, the new window has no user.  I'd like the new
window to have USER1 as the user.  Is this possible?



Brian Drexler
Operations Technician
Saginaw Control  Engineering
(989)799-6871 Ext. 497
http://www.saginawcontrol.com http://www.saginawcontrol.com/


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[PHP] mysql update help needed

2002-03-20 Thread ROBERT MCPEAK

Can somebody straighten this out for me?

I can't get the update to work.  I'm sure the variables are being
passed to the code.  Thanks!

if ($postaction==edit)

{
echo it firedBr;
// process form

$db = mysql_connect(myhost, myuname,
mypword);

 mysql_select_db(mydb);

$sql = UPDATE mytable SET
img_url=$img_url,visitdate=$visitdate,img_group=$img_group,display=$display,
caption=$caption where id = $id;

$result = mysql_query($sql);

echo center;
echo Thank you! Information entered.\n;
echo /center;

}

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RE: [PHP] Calling Javascript-function from php-script ...

2002-03-20 Thread Kevin Stone

I'm not quite sure what you mean...  If Javascript were disabled then
this whole argument would be moot.  Since our method requires Javascript
to properly function we're really not interested in that particular
situation.  :)

There are two ways a PHP script (or any scripting language for that
matter) can send input to a Javascript.  One, by dynamically generating
a local Javascript with the lines of code necessary to perform a certain
task.  Two, by sending information through the URL string to a remote
Javascript which runs functions based on that information.

Classic Input/Output.  It doesn't matter where the input is coming from
so long as the program gets what is expecting.  So in this sense the two
unrelated programs (one server side, one client side) are communicating,
just not directly.

Bottom line is the method works so I don't understand what there is to
debate.  See here for a working example

http://www.helpelf.com/fetch_data.html

It's not very sophisticated yet (all the junk left in the URL, et al).
But it does what I'm talking about.  You can copy  paste this
Javascript into any web page and it'll return the same database
information gathered by the PHP script.
-Kevin

-Original Message-
From: Alexander Skwar [mailto:[EMAIL PROTECTED]] 
Sent: Tuesday, March 19, 2002 4:27 PM
To: Kevin Stone
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP] Calling Javascript-function from php-script ...

»Kevin Stone« sagte am 2002-03-19 um 14:11:42 -0700 :
 Not entirely true.  Javascript is directly linked to HTML and HTML is
 directly linked to PHP so you can have PHP talk to Javascript through
 HTML.

I still don't agree.  You can of course create JavaScripts dynamically
in PHP.  However, PHP won't talk to JS, it's the browser which will
execute the dynamically created JS and then maybe talk back to the
server and thus execute some PHP code.  This may seem like nitpicking,
but I don't think it is.  If PHP were to execute the JS, it would work
even when the user had disabled JS in his browser.

Alexander Skwar
-- 
How to quote:   http://learn.to/quote (german) http://quote.6x.to
(english)
Homepage:   http://www.iso-top.de  | Jabber:
[EMAIL PROTECTED]
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   Uptime: 2 days 12 hours 18 minutes

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[PHP] drop down box

2002-03-20 Thread ...::: M.E. Suliman :::...

Hi

I need to get info from a specific field in a MySQL database to appear in a
drop box as options. Has anyone any ideas on this.

Thanks

Mohamed





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[PHP] page expired message

2002-03-20 Thread Gonzalez, Zara E

Is there any way to avoid getting this message when I hit back on my browser

Warning: Page has Expired The page you requested was created using information
you submitted in a form. This page is no longer available. As a security
precaution, Internet Explorer does not automatically resubmit your information
for you. 

To resubmit your information and view this Web page, click the Refresh button.

I get it when I am using a form with session variables...

Zara

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Re: [PHP] Calling Javascript-function from php-script ...

2002-03-20 Thread Andrew Lopucki

I think the point here is that it be made clear to those who might get 
confused that the javascript (unless it's a server-side script) is running in 
a browser and as such there is no way for the server to 'make a call to it by 
URL.'  The Javascript can call the server but the server-side PHP script 
cannot call the client.  Therefore, no PHP script can 'call' a javascript 
function.


On Wednesday 20 March 2002 12:44 pm, Kevin Stone wrote:
 I'm not quite sure what you mean...  If Javascript were disabled then
 this whole argument would be moot.  Since our method requires Javascript
 to properly function we're really not interested in that particular
 situation.  :)

 There are two ways a PHP script (or any scripting language for that
 matter) can send input to a Javascript.  One, by dynamically generating
 a local Javascript with the lines of code necessary to perform a certain
 task.  Two, by sending information through the URL string to a remote
 Javascript which runs functions based on that information.

 Classic Input/Output.  It doesn't matter where the input is coming from
 so long as the program gets what is expecting.  So in this sense the two
 unrelated programs (one server side, one client side) are communicating,
 just not directly.

 Bottom line is the method works so I don't understand what there is to
 debate.  See here for a working example

 http://www.helpelf.com/fetch_data.html

 It's not very sophisticated yet (all the junk left in the URL, et al).
 But it does what I'm talking about.  You can copy  paste this
 Javascript into any web page and it'll return the same database
 information gathered by the PHP script.
 -Kevin

 -Original Message-
 From: Alexander Skwar [mailto:[EMAIL PROTECTED]]
 Sent: Tuesday, March 19, 2002 4:27 PM
 To: Kevin Stone
 Cc: [EMAIL PROTECTED]
 Subject: Re: [PHP] Calling Javascript-function from php-script ...

 »Kevin Stone« sagte am 2002-03-19 um 14:11:42 -0700 :
  Not entirely true.  Javascript is directly linked to HTML and HTML is
  directly linked to PHP so you can have PHP talk to Javascript through
  HTML.

 I still don't agree.  You can of course create JavaScripts dynamically
 in PHP.  However, PHP won't talk to JS, it's the browser which will
 execute the dynamically created JS and then maybe talk back to the
 server and thus execute some PHP code.  This may seem like nitpicking,
 but I don't think it is.  If PHP were to execute the JS, it would work
 even when the user had disabled JS in his browser.

 Alexander Skwar

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RE: [PHP] drop down box

2002-03-20 Thread Demitrious S. Kelly

This is actually a small excerpt from a program I've written in the
past... hope it helps...

function show_downtime_form() {
global $conf_file;
global $filter;
$data=file($conf_file);
foreach ( $data as $line ) {
$bang=explode(':', $line);
$idents[]=$bang[0];
}
$idents=array_unique($idents);
echo 'div align=centerhr width=300';
echo 'form name=inputform action=reports.php
method=post';
echo 'Match Idents To:br';
echo 'input type=text name=filter value='.$filter.'';
echo 'br - OR Select - br';
echo 'select name=temp onchange=doEcho()';
echo 'option selected--From Current Idents--';
foreach($idents as $ident) {
echo 'option value='.$ident.''.$ident;
}
echo '/select';
echo 'br';
echo 'input type=submit value=search';
echo '/form';
echo '/div';
}

-Original Message-
From: ...::: M.E. Suliman :::... [mailto:[EMAIL PROTECTED]] 
Sent: Wednesday, March 20, 2002 9:57 AM
To: [EMAIL PROTECTED]
Subject: [PHP] drop down box

Hi

I need to get info from a specific field in a MySQL database to appear
in a
drop box as options. Has anyone any ideas on this.

Thanks

Mohamed





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[PHP] HTMLnetscape issue

2002-03-20 Thread Vlad Kulchitski

Hi,

Sorry for repeating myself, but am lost and still can't find a solution
to the following problem, I need to specify a background image for td
like the code below:

tr
  td background=images/bottomcell_bg.gif/td
/tr

This code works EVERYWHERE (in all browsers) but Netscape Navigator 4.xx
versions.

Please help,
Thanks,
Vlad
http://kulchitski.com

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RE: [PHP] Calling Javascript-function from php-script ...

2002-03-20 Thread Kevin Stone

I think the point here is that I'm right and you're wrong *JUST JOKING!*

Seriously you're absolutely right, a PHP script can not activate a
Javascript function.  What I'm saying (and what I wanted the original
poster to understand) is that a PHP script CAN send input to a
Javascript, and based on that input run a specific function.  A
Javascript can activate a PHP function in the same way.  So in this way
a Javascript and a PHP script can in fact communicate. (please note the
preceeding a before the words Javascript and PHP.. we're not talking
about the languages here only the physical scripts, because we could be
talking about any two interpreted languages).

*phew* Are we done yet?  I really need to get back to work.  LOL  :D
-Kevin

-Original Message-
From: Andrew Lopucki [mailto:[EMAIL PROTECTED]] 
Sent: Wednesday, March 20, 2002 10:51 AM
To: Kevin Stone; [EMAIL PROTECTED]
Subject: Re: [PHP] Calling Javascript-function from php-script ...

I think the point here is that it be made clear to those who might get 
confused that the javascript (unless it's a server-side script) is
running in 
a browser and as such there is no way for the server to 'make a call to
it by 
URL.'  The Javascript can call the server but the server-side PHP script

cannot call the client.  Therefore, no PHP script can 'call' a
javascript 
function.


On Wednesday 20 March 2002 12:44 pm, Kevin Stone wrote:
 I'm not quite sure what you mean...  If Javascript were disabled then
 this whole argument would be moot.  Since our method requires
Javascript
 to properly function we're really not interested in that particular
 situation.  :)

 There are two ways a PHP script (or any scripting language for that
 matter) can send input to a Javascript.  One, by dynamically
generating
 a local Javascript with the lines of code necessary to perform a
certain
 task.  Two, by sending information through the URL string to a remote
 Javascript which runs functions based on that information.

 Classic Input/Output.  It doesn't matter where the input is coming
from
 so long as the program gets what is expecting.  So in this sense the
two
 unrelated programs (one server side, one client side) are
communicating,
 just not directly.

 Bottom line is the method works so I don't understand what there is to
 debate.  See here for a working example

 http://www.helpelf.com/fetch_data.html

 It's not very sophisticated yet (all the junk left in the URL, et al).
 But it does what I'm talking about.  You can copy  paste this
 Javascript into any web page and it'll return the same database
 information gathered by the PHP script.
 -Kevin

 -Original Message-
 From: Alexander Skwar [mailto:[EMAIL PROTECTED]]
 Sent: Tuesday, March 19, 2002 4:27 PM
 To: Kevin Stone
 Cc: [EMAIL PROTECTED]
 Subject: Re: [PHP] Calling Javascript-function from php-script ...

 Kevin Stone sagte am 2002-03-19 um 14:11:42 -0700 :
  Not entirely true.  Javascript is directly linked to HTML and HTML
is
  directly linked to PHP so you can have PHP talk to Javascript
through
  HTML.

 I still don't agree.  You can of course create JavaScripts dynamically
 in PHP.  However, PHP won't talk to JS, it's the browser which will
 execute the dynamically created JS and then maybe talk back to the
 server and thus execute some PHP code.  This may seem like nitpicking,
 but I don't think it is.  If PHP were to execute the JS, it would work
 even when the user had disabled JS in his browser.

 Alexander Skwar

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Re: [PHP] HTMLnetscape issue

2002-03-20 Thread heinisch

At 20.03.2002  13:11, you wrote:

Hi,

Sorry for repeating myself, but am lost and still can't find a solution
to the following problem, I need to specify a background image for td
like the code below:

tr
   td background=images/bottomcell_bg.gif/td
/tr

This code works EVERYWHERE (in all browsers) but Netscape Navigator 4.xx
versions.
UNTESTED
Try an $nbsp; insidetd/td as:
trtd background=images/bottomcell_bg.gifnbsp;/td/tr
HTH Oliver


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Re: [PHP] building a control panel in php

2002-03-20 Thread James Arthur

On Wednesday 20 Mar 2002 02:42, Thalis A. Kalfigopoulos wrote:
  -Original Message-
  From: Miguel Cruz [mailto:[EMAIL PROTECTED]]
  Sent: Tuesday, March 19, 2002 5:49 PM
  To: Paul ...
  Cc: [EMAIL PROTECTED]
  Subject: Re: [PHP] building a control panel in php
 
  On Wed, 20 Mar 2002, Paul ... wrote:
   just thinking about making a small control panel for my server so i
  can do
   the web hosting related things from the web... would php be a good
  language
   to do this in and if so why?.. what would be the ups and downs?
 
  The fastest way would be to download Webmin from here
  (http://www.webmin.com/), then change all the comments so it says you
  wrote it.
 
  Seriously, you might want to look into that because a lot of people have
 
  already put a lot of work into making something fairly comprehensive.
 
  miguel

 Yes, but how safe can one feel having all this power-functionality over a
 webpage? (I presume lots of stuff is SETUID;Correct?)

Webmin is modular. You only install the modules you want to control over the 
web. You can also retrict access to port 1 (on which it lives by default) 
in the normal way. I imagine you can set it to do HTTPS connections as well, 
but I've not tried that because I only use it locally.

--jaa

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RE: [PHP] HTMLnetscape issue

2002-03-20 Thread Vlad Kulchitski

STILL DOESN'T WORK :(

-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]] 
Sent: 20 ÂÅÒÅÚÎÑ 2002 Ò. 13:29
To: [EMAIL PROTECTED]
Subject: Re: [PHP] HTMLnetscape issue

At 20.03.2002  13:11, you wrote:

Hi,

Sorry for repeating myself, but am lost and still can't find a solution
to the following problem, I need to specify a background image for td
like the code below:

tr
   td background=images/bottomcell_bg.gif/td
/tr

This code works EVERYWHERE (in all browsers) but Netscape Navigator 4.xx
versions.
UNTESTED
Try an $nbsp; insidetd/td as:
trtd background=images/bottomcell_bg.gifnbsp;/td/tr
HTH Oliver


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Re: [PHP] HTMLnetscape issue

2002-03-20 Thread James Arthur

On Wednesday 20 Mar 2002 18:11, Vlad Kulchitski wrote:
 Hi,

 Sorry for repeating myself, but am lost and still can't find a solution
 to the following problem, I need to specify a background image for td
 like the code below:

 tr
   td background=images/bottomcell_bg.gif/td
 /tr

 This code works EVERYWHERE (in all browsers) but Netscape Navigator 4.xx
 versions.

Yes, Netscape 4.x doesn't do table backgrounds according to HTML spec. There 
is no solution for it, and you'll have to work your way around it, either by 
changing the design for your page, or by giving an alternative layout which 
is displayed when netscape users pay a visit.

The second way I mentioned is really surprisingly easy using CSS.

--jaa

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Re: [PHP] Making a simple borderless pop up window with a Close button

2002-03-20 Thread Joe Webster

Using the options parameter will allow you to get rid of toolbarts and
scrollbars, but NOT the window's border, which the question was asking.

-Joe

Bvr [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...


 The 3rd parameter to JavaScript function window.open() allows you to
 disable a number of window elements every browser has,
 these include the toolbar (buttons), location, status, menubar,
scrollbars.
 This functionality is provided by the most common browsers and versions
 (MSIE and Netscape) and will also work in Mozilla and Netscape 6.  I
 don't know about the JavaScript implementation in Opera, but if it
 supports JS it is likely to support these options too (or at least
 ingores them).

 bvr.


 Joe Webster wrote:

 It only works in IE -- it makes use of the 'Full Screen' (F11) option and
 tricks IE into doing so... hope you don't want it to work in NS, Opera...
or
 anything else
 





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[PHP] Re: PHP - mssql

2002-03-20 Thread Joe Webster

I doubt msSQL differs from MySQL --

$link = mssql_connect( $host, $user, $pass ) or die( Can't connect to the
DB! );
mssql_select_db( $dbname, $link ) or die( Can't select database );

$query = SELECT * FROM members WHERE user='$user' AND pass='$pass';;
$result = mssql_query( $query, $link );
if(!mssql_num_rows( $result )){
die( Username/Password no good );
}
else{
die( Everything is okay! );
}

like i said, i think all the mysql functions in php have a mssql equiv. --
like mssql_num_rows().


-Joe

Chris [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 Hi. I have a table that contains lots of names in mssql. and i want to
make
 a page
 where each of theese individuals can login with that spesific username and
 password.
 So my question is : what is the proper (best) command to use for sending
and
 returning the info?

 ?PHP
 $link = mssql_connect($hostname,$username,$password);
 $dblink = mssql_select_db($dbname, $link);
 if ( $link  $dblink )
 {
 $query = select * from members where user = '$user' and pass = '$pass';
 $result = mssql_query( $query );
 if ( $result ) echo correct login;
 else echo wrong login;
 }
 ?

 This is not working... i have tried everything i can think of that can
work
 but with no luck.
 So if someone have a solution for me... i would apriciate it :)

 (and yes i do have defined all the vars in the script they are just not
that
 important here)

 -Chris






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RE: [PHP] mysql update help needed

2002-03-20 Thread Rick Emery

if ($postaction==edit)

-Original Message-
From: ROBERT MCPEAK [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, March 20, 2002 11:44 AM
To: [EMAIL PROTECTED]
Subject: [PHP] mysql update help needed


Can somebody straighten this out for me?

I can't get the update to work.  I'm sure the variables are being
passed to the code.  Thanks!

if ($postaction==edit)

{
echo it firedBr;
// process form

$db = mysql_connect(myhost, myuname,
mypword);

 mysql_select_db(mydb);

$sql = UPDATE mytable SET
img_url=$img_url,visitdate=$visitdate,img_group=$img_group,display=$display,
caption=$caption where id = $id;

$result = mysql_query($sql);

echo center;
echo Thank you! Information entered.\n;
echo /center;

}

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[PHP] Announcement: Smarty template engine 2.0.1 available

2002-03-20 Thread Monte Ohrt

This is a point release, a few bug fixes  clean up.

http://www.phpinsider.com/php/code/Smarty/

There have been some nice plugins contributed to the plugin repository
too!

http://www.phpinsider.com/php/code/Smarty/contribs/plugins/


Version 2.0.1
-
- rename plugin .make_timestamp.php to shared.make_timestamp.php
(Monte)
- changed crc32() generated values, replace '-' with 'N' (Monte)
- added support for +/- N syntax in html_select_date year values
(Monte)
- fixed behavior of inserts with script attribute. (Andrei)
- fixed bug with $smarty.cookies and $smarty.server. (Andrei)
- wordwrap and indent are missing from 2.0 release, now fixed.
(Monte)
- removed show_info_header and show_info_include variables. (Monte)


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Director of Technology, ispi Inc.

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[PHP] Problem with posting

2002-03-20 Thread James Arthur

I'm writing a voting script, but I have a problem with it.

Voters cast their vote by submitting a form. When this form is received it is 
added to the database, and a session variable is set saying that they've 
voted. The problem is that once someone's voted they can just press reload on 
their browser and it sends another vote. This happens in Netscape 4.x. All 
other browsers either do not submit form data or recognise that the session 
variable is set.

Any ideas on how to fix this? Thanks.

--jaa

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RE: [PHP] Problem with posting

2002-03-20 Thread Rick Emery

What do you mean All other browsers either do not submit form data?

show your code.  

What kind of user authentication are you using?  If none, they'll vote and
vote often.


-Original Message-
From: James Arthur [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, March 20, 2002 1:39 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Problem with posting


I'm writing a voting script, but I have a problem with it.

Voters cast their vote by submitting a form. When this form is received it
is 
added to the database, and a session variable is set saying that they've 
voted. The problem is that once someone's voted they can just press reload
on 
their browser and it sends another vote. This happens in Netscape 4.x. All 
other browsers either do not submit form data or recognise that the session 
variable is set.

Any ideas on how to fix this? Thanks.

--jaa

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Re: [PHP] HTMLnetscape issue

2002-03-20 Thread Erik Price


On Wednesday, March 20, 2002, at 01:11  PM, Vlad Kulchitski wrote:

 Sorry for repeating myself, but am lost and still can't find a solution
 to the following problem, I need to specify a background image for td
 like the code below:

 tr
   td background=images/bottomcell_bg.gif/td
 /tr

 This code works EVERYWHERE (in all browsers) but Netscape Navigator 4.xx
 versions.

You're fighting an unwinnable battle.  Give up on Crapscape 4.x, it is 
full of bugs.

Erik






Erik Price
Web Developer Temp
Media Lab, H.H. Brown
[EMAIL PROTECTED]


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Re: [PHP] Problem with posting

2002-03-20 Thread Miguel Cruz

On Wed, 20 Mar 2002, James Arthur wrote:
 I'm writing a voting script, but I have a problem with it.

 Voters cast their vote by submitting a form. When this form is received
 it is added to the database, and a session variable is set saying that
 they've voted. The problem is that once someone's voted they can just
 press reload on their browser and it sends another vote. This happens in
 Netscape 4.x. All other browsers either do not submit form data or
 recognise that the session variable is set.

How about this:

When they go to the page that provides the voting form, generate a unique
random number and store it in your database. Send that number as a hidden
variable on the voting form.

When the form is submitted, look up the number in the database and store 
their vote alongside it.

That way, if they resubmit, it just replaces their earlier vote.

miguel


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RE: [PHP] HTMLnetscape issue

2002-03-20 Thread Nathan Cassano


Yes here is a solution to this problem and I am surprised no one on this
list pointed it out.

Simply put a transparent dot within a cell table that you wish to have
the background image display.
Netscape 4 in retarded in the fact that it will not display a cell
background image unless it has cell content.


tr
td background=images/bottomcell_bg.gifimg
src=images/transparent_1x1_dot.gif/td
/tr

-Original Message-
From: Vlad Kulchitski [mailto:[EMAIL PROTECTED]] 
Sent: Wednesday, March 20, 2002 10:12 AM
To: [EMAIL PROTECTED]
Subject: [PHP] HTMLnetscape issue


Hi,

Sorry for repeating myself, but am lost and still can't find a solution
to the following problem, I need to specify a background image for td
like the code below:

tr
  td background=images/bottomcell_bg.gif/td
/tr

This code works EVERYWHERE (in all browsers) but Netscape Navigator 4.xx
versions.




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Re: [PHP] Multipage form

2002-03-20 Thread Erik Price


On Wednesday, March 20, 2002, at 11:57  AM, David Johansen wrote:

 I was just wondering what was the best way to handle a multipage form. 
 Would
 the best way be to keep passing the variables through the forms as 
 hidden
 values or should I use sessions and store all the values as session
 variables? What's the best way to handle all of this? Also the different
 forms will all be in the same php file that loops to itself if that 
 makes a
 difference. Thanks,

These can be a pain in the ASS.  But as for the answer to your question, 
it's really more a matter of personal preference and the particular 
application you have.  For instance, if I were writing a shopping cart 
or some extremely complicated sequence of forms that fork off into a 
tree-like structure, I'd probably just give up on hidden form fields and 
use session variables.  But because session variables can be tricky to 
unset (you have to make sure the user explicitly executes a script to 
unset them), I try to avoid it when I can.  I have a linear multi-part 
form (not one that branches into different directions) where I take user 
input and throw it all into hidden form fields -- very tedious, yes, but 
I have finer control over what values get passed around as the user 
moves on.

Side note: the trickiest thing can be getting multiple-listbox values to 
be passed on, since it'll be hard to put multiple values into a single 
form field.  The way to do it is a miniature loop for each case where 
you need to do this, that places each value into an element of an 
array -- then implode the array into a string and put the string into 
the hidden form field.  Explode the string back into an array on the 
next part of the form.

For a branching, tree-like system I'd probably use sessions unless for 
some reason you can't -- just make sure the user has a way of knowing 
what's in their cart (or equivalent for your site) somewhere, so that 
if they closed the window in the middle of filling out the form, 
possibly expecting it to reset all of their work, then they won't be 
surprised when they try to fill out the same form later and see all of 
their old values from their session.

Good luck


Erik





Erik Price
Web Developer Temp
Media Lab, H.H. Brown
[EMAIL PROTECTED]


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RE: [PHP] HTMLnetscape issue

2002-03-20 Thread Vlad Kulchitski

The problem is it doesn't show the picture background, even if I type text in that 
cell...

-Original Message-
From: Nathan Cassano [mailto:[EMAIL PROTECTED]] 
Sent: 20 ÂÅÒÅÚÎÑ 2002 Ò. 14:43
To: [EMAIL PROTECTED]; Vlad Kulchitski
Subject: RE: [PHP] HTMLnetscape issue


Yes here is a solution to this problem and I am surprised no one on this
list pointed it out.

Simply put a transparent dot within a cell table that you wish to have
the background image display.
Netscape 4 in retarded in the fact that it will not display a cell
background image unless it has cell content.


tr
td background=images/bottomcell_bg.gifimg
src=images/transparent_1x1_dot.gif/td
/tr

-Original Message-
From: Vlad Kulchitski [mailto:[EMAIL PROTECTED]] 
Sent: Wednesday, March 20, 2002 10:12 AM
To: [EMAIL PROTECTED]
Subject: [PHP] HTMLnetscape issue


Hi,

Sorry for repeating myself, but am lost and still can't find a solution
to the following problem, I need to specify a background image for td
like the code below:

tr
  td background=images/bottomcell_bg.gif/td
/tr

This code works EVERYWHERE (in all browsers) but Netscape Navigator 4.xx
versions.




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RE: [PHP] HTMLnetscape issue

2002-03-20 Thread Vlad Kulchitski


I agree, but there are sites like heavy GRAPHICS sites that look fine
everywhere you know what I am saying... the only solution I see is to
add more cells, like even 1 pix cells and 100 pix wide if I want a line
of graphic etc... that is the only solution I see

-Original Message-


 Sorry for repeating myself, but am lost and still can't find a
solution
 to the following problem, I need to specify a background image for
td
 like the code below:

 tr
   td background=images/bottomcell_bg.gif/td
 /tr

 This code works EVERYWHERE (in all browsers) but Netscape Navigator
4.xx
 versions.

You're fighting an unwinnable battle.  Give up on Crapscape 4.x, it is 
full of bugs.

Erik






Erik Price
Web Developer Temp
Media Lab, H.H. Brown
[EMAIL PROTECTED]


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[PHP] Sessions

2002-03-20 Thread Joshua E Minnie

I am kind of confused by this error that I am receiving when I try to logout
of a session.  If somebody could pleae help me out here.

Warning: Cannot send session cache limiter - headers already sent (output
started at /home/www/wildwebtech/cumc/default.php:9) in
/home/www/wildwebtech/cumc/default.php on line 10

Here is the code that is causing the problem.

?
  session_start();

  $result = session_unregister(valid_user);
  session_destroy();
?

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CIO
[EMAIL PROTECTED]

Don't work for recognition, but always do work worthy of recognition.



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Re: [PHP] Db Access Count

2002-03-20 Thread Randum Ian

To increment the field $count by one I can just do $count ++ can I?

Cheers, Ian.

- Original Message - 
From: Randum Ian 
To: PHP Mailing List 
Sent: Wednesday, March 20, 2002 4:20 PM
Subject: [PHP] Db Access Count


Hi there,

I want to have a field in a database that counts the number of times 
that particular record has been viewed on the website. When is the best 
time to increment the count in the file and how?

Kind Regards, Ian.


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Re: [PHP] Problem with posting

2002-03-20 Thread James Arthur

On Wednesday 20 Mar 2002 19:40, Rick Emery wrote:
 What do you mean All other browsers either do not submit form data?

I mean when the user hits 'reload' the POST data is not resubmitted. Some 
browsers do not resubmit form data, some do, and some prompt.

 What kind of user authentication are you using?  If none, they'll vote and
 vote often.

A session variable is used to store who has voted and who has not. Netscape 
and Mozilla seem to eschew this somehow. Not sure how. In IE it works fine, 
even when you choose to resubmit the form data.

Hit http://wired.st-and.ac.uk/ to see what happens.

--jaa

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Re: [PHP] Accessing form variables

2002-03-20 Thread Miguel Cruz

On Wed, 20 Mar 2002, Joshua E Minnie wrote:
 I have a form with a menu which I need multiple select on.  How does PHP
 handle this?  I have to use $HTTP_POST_VARS[somevariable] to access
 somevariable from the form.

For a multiple select, stick [] after the HTML name and you'll get it back 
as an array with one element for each item the user selects:

   select multiple name=colors[]
  blah blah
   /select

Will get you an array in $_REQUEST['colors'] .

miguel


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Re: [PHP] Again, and Again, and AGAIN!

2002-03-20 Thread Mike Gohlke

Are you hitting enter while in one of the fields or clicking the submit 
button.  I've seen versions of IE that would not set the submit button 
if enter was used.  Personally, I would check for isset($username)  
isset($password).

Mike...

(Sorry for the very late reply, etc.  I've been dealing with a screwy 
server for the past few days:(

Jason Wong wrote:

On Sunday 17 March 2002 13:14, Jason Wong wrote:


You're using 4.1.1, $HTTP_POST_VARS{} has been replaced by $_POST[] (see
changelog/history/php.ini for details).



Sorry a typo:

$HTTP_POST_VARS[] has been replaced by $_POST[]







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Re: [PHP] HTMLnetscape issue

2002-03-20 Thread James Arthur

On Wednesday 20 Mar 2002 19:43, Nathan Cassano wrote:
 Yes here is a solution to this problem and I am surprised no one on this
 list pointed it out.

 Simply put a transparent dot within a cell table that you wish to have
 the background image display.
 Netscape 4 in retarded in the fact that it will not display a cell
 background image unless it has cell content.


 tr
 td background=images/bottomcell_bg.gifimg
 src=images/transparent_1x1_dot.gif/td
 /tr

Not only that, but it doesn't inherit the background image from its parent 
properly. For example,

table background=myimage.gif
trtdSome text/tdtdMore text/td/tr
tr colspan=2tdEven more text/td/tr
/table

You'll find that the background is repeated in each cell, not that the cells 
are transparent and the table area has a background. This is mightily 
annoying.

--jaa

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[PHP] TIMESTAMP and COMPARISON

2002-03-20 Thread chris allen

Hello,


I am looking for a standard way to compare to dates. I have a date/time
stored in a field in a mysql table as
date_added TIMESTAMP(14). (IE mmddhhmmss).

I want to delete all records in this table if date_added is older than 2
hours.

IE
if current_date   date_added +2 hours then delete record.

How do I do this from within mysql?
Do I need to go outside of mysql and code it in php to do this?
I read that mysql wants calculations done on the app side as compared to the
server side.
What do others do with these kind of situations?
It appears that if I have to bring data out of the table and do a comparison
it wouldnt be efficient.

Thanks,
ccma


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