Re: [PHP] undefined variable

2006-04-30 Thread Smart Software
isset always returns 0

i create  dynamic textbox called quantity0, textbox1, textbox3...

then i a, trying to get the content of the textbox but it is always 0.

as you can see, i tried the suggestions but it still dont work.

is there something iam doing wroing? why is the textbox always 0?




  New row number: 
  name of textbox: 
  
  

   " 
TEST

  

 







""Richard Lynch"" <[EMAIL PROTECTED]> schreef in bericht 
news:[EMAIL PROTECTED]
> On Sat, April 29, 2006 5:42 am, Smart Software wrote:
>> code below shows all records from products table with an textbox and
>> an
>> order button for each record
>
>> How can i add the content of the textbox?
>> i tried this:
>>  > ?>">
>>
>> but all i get is an error telling me there is a undefined varable
>
> You probably are following some kind of tutorial that assumes
> "register_globals" is "on" -- or you are simply used to that
> environment.
>
> So when you try to use $quantity, it's not defined.
>
> The value you want is in $_REQUEST['quantity'];
>
> You should do something like this:
>
>   //Get data from REQUEST:
>  $quantity = isset($_REQUEST['quantity']) ? $_REQUEST['quantity'] : 0;
>  //Force valid data:
>  $quantity = (int) $quantity;
>  //rest of script here.
> ?>
>
> -- 
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> http://l-i-e.com/artists.htm 

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Re: [PHP] undefined variable

2006-04-29 Thread Richard Lynch
On Sat, April 29, 2006 5:42 am, Smart Software wrote:
> code below shows all records from products table with an textbox and
> an
> order button for each record

> How can i add the content of the textbox?
> i tried this:
>   ?>">
>
> but all i get is an error telling me there is a undefined varable

You probably are following some kind of tutorial that assumes
"register_globals" is "on" -- or you are simply used to that
environment.

So when you try to use $quantity, it's not defined.

The value you want is in $_REQUEST['quantity'];

You should do something like this:



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Re: [PHP] undefined variable

2006-04-29 Thread John Wells

> 2006/4/29, Smart Software <[EMAIL PROTECTED]>:
> How can i add the content of the textbox?
> i tried this:
>   ?>">
>
> but all i get is an error telling me there is a undefined varable



It looks like you're trying to get at $quantity, but have you pulled
it from the submitted form yet? If your form's method is "post" then
reference the quantity value with $_POST['quantity']; if your form's
method is "get", use $_GET['quantity'].

You sound very new to this, and the fact that you're building a
shopping cart is worrisome...so please read up on the importance of
verifying your form data, i.e. always "sanitize" submitted values
before using them in SQL calls. And simply check that the values you
get are what you expect, i.e. if you're expecting a number in
$_POST['quantity'], make sure it's a number...

By the way, values submitted in a form will be strings, so in the
example above you'd actually be checking for the *existence of numbers
only* in the string.  Good luck.

HTH,
John W

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Re: [PHP] undefined variable

2006-04-29 Thread Martin Alterisio

2006/4/29, Smart Software <[EMAIL PROTECTED]>:


code below shows all records from products table with an textbox and an
order button for each record



   
 


 ">







if someone presses the button, an item will be ordered.

How can i add the content of the textbox?
i tried this:
 ">

but all i get is an error telling me there is a undefined varable



Can you post what the error looks like?

thanx for all help

N. Karademir

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[PHP] Undefined Variable Problems...

2005-03-06 Thread Nick Zukin
Sorry if this has been covered before.  I just joined this list.

My host just upgraded PHP to 4.3.10 from 4.1.2.  A couple of my clients are
using systems such as PHP-NUKE or various message boards.  I hadn't been
paying attention to my log files, but all of a sudden they got huge,
especially the error logs.  They're filled mostly with undefined variable
errors, but also a couple others, for example:

[Sun Mar  6 00:35:50 2005] [error] PHP Notice:  Undefined variable:
forum_admin in /home/scott/.org/html/mainfile.php on line 79
[Sun Mar  6 00:35:51 2005] [error] PHP Notice:  Undefined offset:  1 in
/home/scott/.org/html/mainfile.php on line 486
[Sun Mar  6 00:35:51 2005] [error] PHP Notice:  Undefined index:  2 in
/home/scott/.org/html/mainfile.php on line 216

line 79, if ($forum_admin == 1) {
line 486, $uname = $cookie[1];
line 216, $pwd = "$user[2]";

Line 79 is not part of a function or class.  It is the first reference to
$forum_admin in the script.  The other two are within functions and the
first call within those functions.  What's being assigned to both of them
are either in the function call itself or globals.

I do have globals turned on.

Should I worry about any of this?  The pages seem to be working fine?  Is
this going to slow things down?  Should I just turn off the logging of such
errors, if I can?

Thanks for any help.  My log files are in the gigabytes with 90% of that
over the last month.

Nick

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Re: [PHP] UNDEFINED VARIABLE ON LOCALHOST

2004-11-29 Thread Ross Hulford
It was my error reporting.forgot I replaced my ini file.
"John Nichel" <[EMAIL PROTECTED]> wrote in message 
news:[EMAIL PROTECTED]
> Ross Hulford wrote:
>> I have a porblem with undefined variables on loacalhost. Any ideas why? I 
>> have turned registed variables on.
>>
>>
>> R.
>
> Without seeing any code, I'm going to guess that you haven't defined a 
> variable before trying to use it.  Wanna make it go away?  Turn off 
> 'notices' in your error reporting, or make sure your variables are defined 
> before you try to use them.
>
> -- 
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> ÜberGeek
> KegWorks.com
> 716.856.9675
> [EMAIL PROTECTED] 

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Re: [PHP] UNDEFINED VARIABLE ON LOCALHOST

2004-11-29 Thread Greg Donald
On Mon, 29 Nov 2004 17:11:47 -, Ross Hulford <[EMAIL PROTECTED]> wrote:
> I have a porblem with undefined variables on loacalhost. Any ideas why? I
> have turned registed variables on.

Where's the code?



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Re: [PHP] UNDEFINED VARIABLE ON LOCALHOST

2004-11-29 Thread John Nichel
Ross Hulford wrote:
I have a porblem with undefined variables on loacalhost. Any ideas why? I 
have turned registed variables on.

R. 
Without seeing any code, I'm going to guess that you haven't defined a 
variable before trying to use it.  Wanna make it go away?  Turn off 
'notices' in your error reporting, or make sure your variables are 
defined before you try to use them.

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ÜberGeek
KegWorks.com
716.856.9675
[EMAIL PROTECTED]
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[PHP] UNDEFINED VARIABLE ON LOCALHOST

2004-11-29 Thread Ross Hulford
I have a porblem with undefined variables on loacalhost. Any ideas why? I 
have turned registed variables on.


R. 

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Re[2]: [PHP] Undefined variable using hyperlink

2003-12-10 Thread Richard Davey
Hello,

Wednesday, December 10, 2003, 5:45:17 PM, you wrote:

>> $msgid = $_GET['msgid'];

P> That seems to have corrected the problem.  Thank you very much.

Cool - do you understand why though? I don't mean to sound
patronising, so please don't take offence at my question, just making
sure.

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Re: [PHP] Undefined variable using hyperlink

2003-12-10 Thread PHP
That seems to have corrected the problem.  Thank you very much.



On 12/10/03 11:56 AM, "Richard Davey" <[EMAIL PROTECTED]> wrote:

> Hello,
> 
> Wednesday, December 10, 2003, 4:53:18 PM, you wrote:
> 
> P> I can retrieve email from the email account, but when I click on a link in
> P> the email.php to open the email in body.php, $msgid is not defined in
> P> body.php.  It's got to be something basic, but right now, it escapes me.
> P> Right now this is running on my Windows 2000 Pro machine.
> 
> At the start of body.php try adding this:
> 
> $msgid = $_GET['msgid'];

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Re: [PHP] Undefined variable using hyperlink

2003-12-10 Thread Richard Davey
Hello,

Wednesday, December 10, 2003, 4:53:18 PM, you wrote:

P> I can retrieve email from the email account, but when I click on a link in
P> the email.php to open the email in body.php, $msgid is not defined in
P> body.php.  It's got to be something basic, but right now, it escapes me.
P> Right now this is running on my Windows 2000 Pro machine.

At the start of body.php try adding this:

$msgid = $_GET['msgid'];

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[PHP] Undefined variable using hyperlink

2003-12-10 Thread PHP

I'm having some basic problems with the following pages, index.php (frames
base), email.php, and body.php.

 

I can retrieve email from the email account, but when I click on a link in
the email.php to open the email in body.php, $msgid is not defined in
body.php.  It's got to be something basic, but right now, it escapes me.
Right now this is running on my Windows 2000 Pro machine.

 

Any help would be appreciated.  Thank you in advance.

 

Chuck

 



 

Index.php

 













 



 



 

Email.php

 



 





Email Test

  

Body, TR, TD, Table {

  color : Black;

  font : 11px Arial, Helvetica, sans-serif;

}

  



 







From

Subject

Date



Nmsgs;

  $overview = imap_fetch_overview($mbox, "1:$mnum", 0);

 

$headers = imap_headers ($mbox);

 

  // Data Table

$nbm = sizeof($overview);

  for($x= $nbm-1; $x >= 0; $x--) {

$val=$overview[$x];

$nb = $val->msgno;

$sFrom =$val->from;

$sSubject = $val->subject;

if($sSubject == '') {

$sSubject = "No Subject
Included";

}

$dDate=$val->date;

// Inbox Output

print "



$sFrom

$sSubject

$dDate

";

}

 

imap_close($mbox);

?>

 



 





 



 

 



 

Body.php

 







 New Document 



 



 

subject);

$msubject=$rawsubject[0]->text;


$mfrom=htmlspecialchars(str_replace("\"","",$mailheader->fromaddress));


$mto=htmlspecialchars(str_replace("\"","",$mailheader->toaddress));


$mcc=htmlspecialchars(str_replace("\"","",$mailheader->ccaddress));

$mreply=$mailheader->reply_toaddress;

$mdate=$mailheader->Date;

 

$mailcheck = imap_check($mbox);

$mailnumber = $mailcheck->Nmsgs;

 

// Get the structure of the email

$structure = imap_fetchstructure($mbox,$msgid);



/*

  if (isset($msgid)) {

//$msgid = "$msgid";

  } 

  

  if (empty($msgid)) {

//$mnum = $mcheck->Nmsgs;

//$msgid = "$mnum";

  }

 */ 

 

imap_close($mbox);

?>

 

 





 



 

 


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Re: [PHP] undefined variable

2003-08-29 Thread Viraj Kalinga Abayarathna
did you solve this problem? i checked the coding in my linux
box, it's working fine.

Viraj

Chris Kay wrote:
> 
> You seem confused with POST & GET, instead of using _POST to retrieve
> values from the form, you use $senders_name, and further down you set
> $_POST["msg"], which will only be used in the same php code on the same
> page
> 
> Try
> 
> $msg = "Sender's Full Name:\t" . $_POST['sender_name'] . "\n";
> $msg .="Sender's E-mail:\t" . $_POST['sender_email'] . "\n";
> $msg .="Did you like the site?\t" . $_POST['like_site'] . "\n";
> $msg .="Additional Message:\t" . $_POST['message'] . "\n\n";
> 
> $mailheaders = "From: yoyo.monash.edu.my\~nthonyak\M\n";
> $mailheaders .="Reply-To: " . $_POST['sender_email'] . "\n\n";
> 
> mail("[EMAIL PROTECTED]", "Feedback Form", $msg, $mailheaders);
> 
> --
> Chris Kay (CK)
> Eleet Internet Services
> M: 0415 451 372
> P: 02 4620 5076
> F: 02 4620 7008
> E: [EMAIL PROTECTED]
> 
> -Original Message-
> From: merryE [mailto:[EMAIL PROTECTED]
> Sent: Friday, 29 August 2003 2:38 AM
> To: [EMAIL PROTECTED]
> Subject: [PHP] undefined variable
> 
> Can anyone tell me what's wrong with my code? I tried to create a form
> in html and redirect it to php. but result said:
> Notice: Undefined variable: sender_name in c:\program files\apache
> group\apache\htdocs\do_feedback.php on line 2 and for all the variables
> ("sender_email", "like_site", and "text area").
> I have been tring to use variable but it is always said "Undefined
> variable".
> Please help, Thanks.
> 
> This is the code for form
> 
> 
> your name: 
> your email: 
>  Did you like the site?
>  yes
>  no
> 
> Additional message:
> 
> 
> 
> 
> 
> Code for php:
>  $_POST["msg"] = "Sender's Full Name:\t$sender_name\n";
> $_POST["msg"] .="Sender's E-mail:\t$sender_email\n";
> $_POST["msg"] .="Did you like the site?\t$like_site\n";
> $_POST["msg"] .="Additional Message:\t$message\n\n";
> 
> $_POST["mailheaders"] = "From: yoyo.monash.edu.my\~nthonyak\M\n";
> $_POST["mailheaders"] .="Reply-To: $sender_email\n\n";
> 
> mail("[EMAIL PROTECTED]", "Feedback Form", $msg, $mailheaders);
> 
> echo $_POST["sender_name"];
> echo "We appreciate your feedback";
>  ?>
> 
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RE: [PHP] undefined variable

2003-08-29 Thread Chris Kay

You seem confused with POST & GET, instead of using _POST to retrieve
values from the form, you use $senders_name, and further down you set
$_POST["msg"], which will only be used in the same php code on the same
page

Try


$msg = "Sender's Full Name:\t" . $_POST['sender_name'] . "\n";
$msg .="Sender's E-mail:\t" . $_POST['sender_email'] . "\n";
$msg .="Did you like the site?\t" . $_POST['like_site'] . "\n";
$msg .="Additional Message:\t" . $_POST['message'] . "\n\n";

$mailheaders = "From: yoyo.monash.edu.my\~nthonyak\M\n";
$mailheaders .="Reply-To: " . $_POST['sender_email'] . "\n\n";

mail("[EMAIL PROTECTED]", "Feedback Form", $msg, $mailheaders);

--
Chris Kay (CK)
Eleet Internet Services
M: 0415 451 372
P: 02 4620 5076
F: 02 4620 7008
E: [EMAIL PROTECTED]

-Original Message-
From: merryE [mailto:[EMAIL PROTECTED] 
Sent: Friday, 29 August 2003 2:38 AM
To: [EMAIL PROTECTED]
Subject: [PHP] undefined variable

Can anyone tell me what's wrong with my code? I tried to create a form
in html and redirect it to php. but result said:  
Notice: Undefined variable: sender_name in c:\program files\apache
group\apache\htdocs\do_feedback.php on line 2 and for all the variables
("sender_email", "like_site", and "text area").
I have been tring to use variable but it is always said "Undefined
variable".
Please help, Thanks.

This is the code for form


your name: 
your email: 
 Did you like the site?
 yes
 no

Additional message:





Code for php:
We appreciate your feedback";
 ?>

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[PHP] undefined variable

2003-08-29 Thread merryE
Can anyone tell me what's wrong with my code? I tried to create a form in html and 
redirect it to php. but result said:  
Notice: Undefined variable: sender_name in c:\program files\apache 
group\apache\htdocs\do_feedback.php on line 2 and for all the variables 
("sender_email", "like_site", and "text area").
I have been tring to use variable but it is always said "Undefined variable".
Please help, Thanks.

This is the code for form


your name: 
your email: 
 Did you like the site?
 yes
 no

Additional message:





Code for php:
We appreciate your feedback";
 ?>


Re: [PHP] Undefined variable problem

2003-08-01 Thread Curt Zirzow
* Thus wrote Ryan A ([EMAIL PROTECTED]):
> 
> Notice: Undefined variable: email1 in c:\phpdev\www\bwh\project\compare.php
> on line 117
> [...]
>
>$m = 1;
>while ($line = mysql_fetch_assoc($rs)) { //dumping into an array
>  foreach ($line as $field => $value) {
>  $tmp = $field.$m;
> $$tmp.= $value;  /* This is the error line 117*** */

Your concating a variable that doesnt exist.


Curt
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Re: [PHP] Undefined variable problem

2003-08-01 Thread Ryan A
IT WORKS!!!
Thanks for replying and the solution.
Cheers,
-Ryan


Hello,

This is a reply to an e-mail that you wrote on Fri, 1 Aug 2003 at
14:47, lines prefixed by '>' were originally written by you.

> Notice: Undefined variable: email1 in
> c:phpdevwwwbwhprojectcompare.php
> on line 117

> $$tmp.= $value;  /* This is the error line 117*** */

You are trying to append to the variable instead of create it, change
this line to:
$$tmp = $value;

David.

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Re: [PHP] Undefined variable problem

2003-08-01 Thread Joona Kulmala
Hello

This is the code:
   $m = 1;
   while ($line = mysql_fetch_assoc($rs)) { //dumping into an array
 foreach ($line as $field => $value) {
 $tmp = $field.$m;
$$tmp.= $value;  /* This is the error line 117*** */
 }
 $m++;
   }
This is basically so that i can use the array via variables like so:
if($tcl2==1){echo $tcl2;}
instead of: if($arrayname['tcl']['1']==1){echo $arrayname['tcl']['1'];} and
so onesp since i have 38 fields.
I can of course just shut off error reporting...but thats not the best
solution right? and i still wouldnt know whats causing these notices...
Simply define $$tmp -variable before adding stuff in it.

[code]
   $m = 1;
   while ($line = mysql_fetch_assoc($rs)) { //dumping into an array
 foreach ($line as $field => $value) {
$tmp = $field.$m;
$$tmp = "";
	 $$tmp .= $value; 
 }
 $m++;
   }
[/code]

No it should whine about undefined vars.

Cheers, Joona
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Re: [PHP] Undefined variable problem

2003-08-01 Thread David Nicholson
Hello,

This is a reply to an e-mail that you wrote on Fri, 1 Aug 2003 at
14:47, lines prefixed by '>' were originally written by you.

> Notice: Undefined variable: email1 in
> c:phpdevwwwbwhprojectcompare.php
> on line 117

> $$tmp.= $value;  /* This is the error line 117*** */

You are trying to append to the variable instead of create it, change
this line to:
$$tmp = $value;

David.

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[PHP] Undefined variable problem

2003-08-01 Thread Ryan A
Hi,
This is the following code given to me by Jenniffer Goodie (thank you) which
is working great but is throwing this notice:

Notice: Undefined variable: email1 in c:\phpdev\www\bwh\project\compare.php
on line 117
Notice: Undefined variable: address1 in
c:\phpdev\www\bwh\project\compare.php on line 117
Notice: Undefined variable: city1 in c:\phpdev\www\bwh\project\compare.php
on line 117
etc (30+ notices)

This is the code:
   $m = 1;
   while ($line = mysql_fetch_assoc($rs)) { //dumping into an array
 foreach ($line as $field => $value) {
 $tmp = $field.$m;
$$tmp.= $value;  /* This is the error line 117*** */
 }
 $m++;
   }

This is basically so that i can use the array via variables like so:
if($tcl2==1){echo $tcl2;}
instead of: if($arrayname['tcl']['1']==1){echo $arrayname['tcl']['1'];} and
so onesp since i have 38 fields.

I can of course just shut off error reporting...but thats not the best
solution right? and i still wouldnt know whats causing these notices...

Any ideas?

Cheers,
-Ryan



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RE: [PHP] undefined variable: action

2003-06-12 Thread Ford, Mike [LSS]
> -Original Message-
> From: Ryan M [mailto:[EMAIL PROTECTED]
> Sent: 11 June 2003 20:22
> 
> Thanks for the advice... The link worked Now it is saying this:
> 
> Notice: Undefined index: action in
> 
> It only says this if there is no action...it goes away once I 
> click the link
> and the action=someaction Is there a way to fix my php

Simplest way to fix this is to use the @ silence operator:

   @$_GET['action']

will return NULL if $_GET['action'] is undefined.

>  so 
> that I dont
> have to change all of the web sites hosted on my server?? Thanks!

The only way to do that is to reduce the error reporting level to not include 
E_NOTICE.  Ideally, you should run a development server which has error reporting set 
to E_ALL, and only copy scripts to your production server once they produce no 
messages at this level -- your production server can then run with a reduced error 
reporting level (even down to none at all, if you feel confident about that ;). 
Ideally, if your production server does run with no error reporting, you should have 
error logging enabled as a safety net!

Cheers!

Mike

-
Mike Ford,  Electronic Information Services Adviser,
Learning Support Services, Learning & Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS,  LS6 3QS,  United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730  Fax:  +44 113 283 3211 

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Re: [PHP] undefined variable: action

2003-06-11 Thread Lars Torben Wilson
On Wed, 2003-06-11 at 13:40, Mark wrote:
> Or you can simply turn off NOTICE error reporting in the php.ini file
> or use ini_set or error_reporting() to not include notices. This
> should not affect functionality. 

That's not a good idea; it's treating the symptom, not the problem. A
better idea is to crank up error reporting all the way on your dev box,
write your code so that it doesn't generate any NOTICES etc, and then
turn off display_errors on the production box. It's a good idea to log
the errors or write a handler or something for when errors aren't being
displayed.



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 - Boycott Starbucks!  http://www.haidabuckscafe.com -




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Re: [PHP] undefined variable: action

2003-06-11 Thread Mark
Or you can simply turn off NOTICE error reporting in the php.ini file
or use ini_set or error_reporting() to not include notices. This
should not affect functionality. 


--- Lars Torben Wilson <[EMAIL PROTECTED]> wrote:
> On Wed, 2003-06-11 at 12:22, Ryan M wrote:
> > Thanks for the advice... The link worked Now it is saying
> this:
> > 
> > Notice: Undefined index: action in
> > 
> > It only says this if there is no action...it goes away once I
> click the link
> > and the action=someaction Is there a way to fix my php so
> that I dont
> > have to change all of the web sites hosted on my server?? Thanks!
> > 
> > Ryan
> 
> Check and initialize your input variables:
> 
> if (!isset($_GET['action'])) {
> $action = '';
> } else {
> $action = $_GET['action'];
> }
> 
> switch ($action) {
> case 'something':
>do_something();
> break;
> case 'something_else':
>do_something_else();
> break;
> default:
>echo "Unrecognized action given";
> break;
> }
> 
> If this is something you need to do for every page on your site,
> put
> the if() check into an auto-prepended file or something.
> 
> 
> Hope this helps,
> 
> Torben
> 
> 
> -- 
>  Torben Wilson <[EMAIL PROTECTED]>   
> +1.604.709.0506
>  http://www.thebuttlesschaps.com 
> http://www.inflatableeye.com
>  http://www.hybrid17.com 
> http://www.themainonmain.com
>  - Boycott Starbucks!  http://www.haidabuckscafe.com
> -
> 
> 
> 
> 
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> 


=
Mark Weinstock
[EMAIL PROTECTED]
***
You can't demand something as a "right" unless you are willing to fight to death to 
defend everyone else's right to the same thing.
***

__
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Yahoo! Calendar - Free online calendar with sync to Outlook(TM).
http://calendar.yahoo.com

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Re: [PHP] undefined variable: action

2003-06-11 Thread Lars Torben Wilson
On Wed, 2003-06-11 at 12:22, Ryan M wrote:
> Thanks for the advice... The link worked Now it is saying this:
> 
> Notice: Undefined index: action in
> 
> It only says this if there is no action...it goes away once I click the link
> and the action=someaction Is there a way to fix my php so that I dont
> have to change all of the web sites hosted on my server?? Thanks!
> 
> Ryan

Check and initialize your input variables:

if (!isset($_GET['action'])) {
$action = '';
} else {
$action = $_GET['action'];
}

switch ($action) {
case 'something':
   do_something();
break;
case 'something_else':
   do_something_else();
break;
default:
   echo "Unrecognized action given";
break;
}

If this is something you need to do for every page on your site, put
the if() check into an auto-prepended file or something.


Hope this helps,

Torben


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 http://www.thebuttlesschaps.com  http://www.inflatableeye.com
 http://www.hybrid17.com  http://www.themainonmain.com
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RE: [PHP] undefined variable: action

2003-06-11 Thread Jay Blanchard
[snip]
Thanks for the advice... The link worked Now it is saying this:

Notice: Undefined index: action in

It only says this if there is no action...it goes away once I click the
link and the action=someaction Is there a way to fix my php so that
I dont have to change all of the web sites hosted on my server?? Thanks!
[/snip]

There are some caveats, but change register_globals to 'on' in php.ini
and then go read about register globals on the php sitethere are
some things to condsider about the security vulnerability of certain
variables;

Jay

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Re: [PHP] undefined variable: action

2003-06-11 Thread Ryan M
Thanks for the advice... The link worked Now it is saying this:

Notice: Undefined index: action in

It only says this if there is no action...it goes away once I click the link
and the action=someaction Is there a way to fix my php so that I dont
have to change all of the web sites hosted on my server?? Thanks!

Ryan

"Jay Blanchard" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
[snip]
Hows it goin?? Im pretty new to this, so I have a pretty simple
question. I am running an apache server with php 4 on a win 2k machine.
When I try to do something like this: Some Action";

if ($action == "someaction") {
echo "Anything";
}
?>

It says: Notice: Undefined variable: action in .

Ive built plenny of pages with simple things like that, and they all
work...is it a problem with my apache server??? Thanks in advance
[/snip]

You probably updated PHP recently and register_globals is now 'off'. Try

if($_GET['action'] == "someaction"){
 do foo
}

HTH!

Jay



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RE: [PHP] undefined variable: action

2003-06-11 Thread Jay Blanchard
[snip]
Hows it goin?? Im pretty new to this, so I have a pretty simple
question. I am running an apache server with php 4 on a win 2k machine.
When I try to do something like this: Some Action";

if ($action == "someaction") {
echo "Anything";
}
?>

It says: Notice: Undefined variable: action in .

Ive built plenny of pages with simple things like that, and they all
work...is it a problem with my apache server??? Thanks in advance
[/snip]

You probably updated PHP recently and register_globals is now 'off'. Try

if($_GET['action'] == "someaction"){
 do foo
}

HTH!

Jay

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[PHP] undefined variable: action

2003-06-11 Thread Ryan M
Hows it goin?? Im pretty new to this, so I have a pretty simple question. I
am running an apache server with php 4 on a win 2k machine. When I try to do
something like this:
Some Action";

if ($action == "someaction") {
echo "Anything";
}
?>

It says: Notice: Undefined variable: action in .

Ive built plenny of pages with simple things like that, and they all
work...is it a problem with my apache server??? Thanks in advance

Ryan



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Re: [PHP] undefined variable notice - how to furn of

2003-01-09 Thread Gurvinder Singh
or give error_reporting(0); in the start of the file

"Joseph W. Goff" <[EMAIL PROTECTED]> wrote in message
002601c2b803$26a67110$bdcaa8c0@jg42000">news:002601c2b803$26a67110$bdcaa8c0@jg42000...
> In the php.ini file set error reporting to E_ALL & ~E_NOTICE
>
> - Original Message -
> From: "Borut Kovacec" <[EMAIL PROTECTED]>
> To: "PHP Mailing List" <[EMAIL PROTECTED]>
> Sent: Thursday, January 09, 2003 9:57 AM
> Subject: [PHP] undefined variable notice - how to furn of
>
>
> Hi
>
> I just installed new php 4.2.3 on Win XP, Apache 1.3.24..
> Everything works fine, just now I'm getting "Notice" messages for every
> undefined variable or undefined index in arrays..
>
> So now I have to use issset() everytime to avoid this messages...
>
> ..is there any way to turn this messages off, because if prior versions I
> never got them..??
>
> Borut
>
>



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Re: [PHP] undefined variable notice - how to furn of

2003-01-09 Thread Joseph W. Goff
In the php.ini file set error reporting to E_ALL & ~E_NOTICE

- Original Message -
From: "Borut Kovacec" <[EMAIL PROTECTED]>
To: "PHP Mailing List" <[EMAIL PROTECTED]>
Sent: Thursday, January 09, 2003 9:57 AM
Subject: [PHP] undefined variable notice - how to furn of


Hi

I just installed new php 4.2.3 on Win XP, Apache 1.3.24..
Everything works fine, just now I'm getting "Notice" messages for every
undefined variable or undefined index in arrays..

So now I have to use issset() everytime to avoid this messages...

..is there any way to turn this messages off, because if prior versions I
never got them..??

Borut



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RE: [PHP] undefined variable notice - how to furn of[Scanned]

2003-01-09 Thread Michael Egan
Borut,

I had this problem myself just before Christmas.

The following solution was proposed:

>> All of the PHP scripts hosted on a Linux server 
>> I'm working with have suddenly begun producing 
>> an error message:
>>
>>  undefined variable 'variablename'

> Looks like someone's tweaked the error reporting level so it's on E_ALL,
> which can be a somewhat alarmist setting :-)

> Read all about it at http://php.net/manual/en/ref.errorfunc.php

Michael Egan



-Original Message-
From: Borut Kovacec [mailto:[EMAIL PROTECTED]]
Sent: 09 January 2003 15:57
To: PHP Mailing List
Subject: [PHP] undefined variable notice - how to furn of[Scanned]


Hi

I just installed new php 4.2.3 on Win XP, Apache 1.3.24..
Everything works fine, just now I'm getting "Notice" messages for every undefined 
variable or undefined index in arrays..

So now I have to use issset() everytime to avoid this messages... 

..is there any way to turn this messages off, because if prior versions I never got 
them..??

Borut

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[PHP] undefined variable notice - how to furn of

2003-01-09 Thread Borut Kovacec
Hi

I just installed new php 4.2.3 on Win XP, Apache 1.3.24..
Everything works fine, just now I'm getting "Notice" messages for every undefined 
variable or undefined index in arrays..

So now I have to use issset() everytime to avoid this messages... 

..is there any way to turn this messages off, because if prior versions I never got 
them..??

Borut



RE: [PHP] Undefined variable error message[Scanned]

2002-12-18 Thread Michael Egan
Jon,

Many thanks - the actual problem is now solved.

As to how it occurred I think must be attributable to me at some stage in terms of 
fiddling around with the php.ini file.  Perhaps I've had too many nights like last 
night and the brain cells are depleting past a critical point!

Thanks to everybody else who responded to this query.

Michael Egan

-Original Message-
From: Jon Haworth [mailto:[EMAIL PROTECTED]]
Sent: 18 December 2002 10:39
To: Michael Egan; PHP General (E-mail)
Subject: RE: [PHP] Undefined variable error message[Scanned]


Hi Michael,

> All of the PHP scripts hosted on a Linux server 
> I'm working with have suddenly begun producing 
> an error message:
>
>   undefined variable 'variablename'

Looks like someone's tweaked the error reporting level so it's on E_ALL,
which can be a somewhat alarmist setting :-)

Read all about it at http://php.net/manual/en/ref.errorfunc.php

> The latter would suggest fairly significant 
> security issues.  Does anybody have any ideas 
> as to how this might have occurred 

Are you on a shared host, or is there someone else who admins your box? If
so, have a word with them and see if they've been fiddling with php.ini -
that's where the error reporting level is set.

Cheers
Jon

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Re: [PHP] Undefined variable error message

2002-12-18 Thread Chris Hewitt
Hmm, yes. Why did I not think of error reporting at E_ALL?

Chris Hewitt wrote:


Michael Egan wrote:


All of the PHP scripts hosted on a Linux server I'm working with have 
suddenly begun producing an error message:

undefined variable 'variablename'

Has the code been working on a different server with an earlier 
version of PHP (or this server upgraded)? It sounds as though it needs 
register_globals in php.ini turned on, or the code modified to use the 
$_GET and $_POST super globals.

HTH
Chris




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Re: [PHP] Undefined variable error message

2002-12-18 Thread Chris Hewitt
Michael Egan wrote:


All of the PHP scripts hosted on a Linux server I'm working with have suddenly begun producing an error message:

	undefined variable 'variablename'


Has the code been working on a different server with an earlier version 
of PHP (or this server upgraded)? It sounds as though it needs 
register_globals in php.ini turned on, or the code modified to use the 
$_GET and $_POST super globals.

HTH
Chris





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RE: [PHP] Undefined variable error message

2002-12-18 Thread Jon Haworth
Hi Michael,

> All of the PHP scripts hosted on a Linux server 
> I'm working with have suddenly begun producing 
> an error message:
>
>   undefined variable 'variablename'

Looks like someone's tweaked the error reporting level so it's on E_ALL,
which can be a somewhat alarmist setting :-)

Read all about it at http://php.net/manual/en/ref.errorfunc.php

> The latter would suggest fairly significant 
> security issues.  Does anybody have any ideas 
> as to how this might have occurred 

Are you on a shared host, or is there someone else who admins your box? If
so, have a word with them and see if they've been fiddling with php.ini -
that's where the error reporting level is set.

Cheers
Jon

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Re: [PHP] Undefined variable error message

2002-12-18 Thread Wico de Leeuw
http://www.php.net/manual/en/function.error-reporting.php

At 10:31 18-12-02 +, Michael Egan wrote:

All of the PHP scripts hosted on a Linux server I'm working with have 
suddenly begun producing an error message:

undefined variable 'variablename'

This occurs wherever a variable name is referred to.  I'm concerned about 
this for two reasons:

1   Will I have to go through each script making substantial alterations?

2   Has the configuration of PHP been altered in some way without my 
knowledge?

The latter would suggest fairly significant security issues.  Does anybody 
have any ideas as to how this might have occurred and the quickest way of 
resolving it?  Or of links to possible solutions?

This is particularly irritating as last night was the office Christmas 
party and I'm in a rather fragile state this morning :-(

Michael Egan

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[PHP] Undefined variable error message

2002-12-18 Thread Michael Egan
All of the PHP scripts hosted on a Linux server I'm working with have suddenly begun 
producing an error message:

undefined variable 'variablename'

This occurs wherever a variable name is referred to.  I'm concerned about this for two 
reasons:

1   Will I have to go through each script making substantial alterations?

2   Has the configuration of PHP been altered in some way without my knowledge?

The latter would suggest fairly significant security issues.  Does anybody have any 
ideas as to how this might have occurred and the quickest way of resolving it?  Or of 
links to possible solutions?

This is particularly irritating as last night was the office Christmas party and I'm 
in a rather fragile state this morning :-(

Michael Egan

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Re: [PHP] Undefined Variable

2002-12-14 Thread Anthony Ritter
Marco Tabini <[EMAIL PROTECTED]> wrote in message:
> Hey Anthony--
>
> It's definitely a register_globals problem. Your ISP has turned it off
> because it's generally considered a significant security risk.
>
> The best way to solve it is to use the superglobal $_POST to access your
> post data. In your PHP script, change all the variables that you take
> from the form into their $_POST[''] equivalent (see below for a rough
> example--I put the assignments at the beginning because I wanted to
> touch your code as little as possible). Also, keep in mind that you're
> not performing any checks on the data--I'm sure you want to do it once
> you've sorted the current problem out, but the way it is now you're
> leaving yourself exposed to a number of possible attacks.
>
> $thename = $_POST['thename'];
(snipped)
.

Yep.

That did it.  Thanks again Marco.

Two more questions:

1. Can you give me some examples about:

"leaving yourself exposed to a number of possible attacks."

and

2. Where can I pick up the PHP magazine in your post sig.

best...
TR






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Re: [PHP] Undefined Variable

2002-12-14 Thread Marco Tabini
Hey Anthony--

It's definitely a register_globals problem. Your ISP has turned it off
because it's generally considered a significant security risk.

The best way to solve it is to use the superglobal $_POST to access your
post data. In your PHP script, change all the variables that you take
from the form into their $_POST[''] equivalent (see below for a rough
example--I put the assignments at the beginning because I wanted to
touch your code as little as possible). Also, keep in mind that you're
not performing any checks on the data--I'm sure you want to do it once
you've sorted the current problem out, but the way it is now you're
leaving yourself exposed to a number of possible attacks.

$thename = $_POST['thename'];
$email = $_POST['email'];
$description = $_POST['description'];
$bizname = $_POST['bizname'];
$contactname = $_POST['contactname'];
$phone = $_POST['phone'];
$email = $_POST['email'];
$mailing = $_POST['mailing'];
$town = $_POST['town'];
$state = $_POST['state'];
$zip = $_POST['zip'];
$cat = $_POST['cat'];

if (($thename == "") && ($email == "") && ($description == "")) {
 header("Location: http://localhost/n_proserv_x.html";);
 exit;
}
$msg = "This e-mail was sent from:\n";
$msg .= "Sender's Name:$thename\n";
$msg .= $thename ."'s business name is:$bizname\n";
$msg .= "The contact person is:$contactname\n";
$msg .= $thename. "'s phone number is:$phone\n";
$msg .= $thename. "'s e-mail address is: $email\n";
$msg .= $thename. "'s mailing address is: $mailing\n";
$msg .= "Town: $town\n";
$msg .= "State: $state\n";
$msg .= "Zip Code: $zip\n";
$msg .= $thename."'s category is: $cat\n";
$msg .= "and the message is:  $description\n\n";
$to = "[EMAIL PROTECTED]";
$subject = "Narrowsburg Chamber of Commerce";
$mailheaders = "From: $thename\n";
$mailheaders .= "Reply to:$email\n\n";
mail($to, $subject, $msg, $mailheaders);
?>
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--- Begin Message ---
>"Marco Tabini <[EMAIL PROTECTED]> wrote in message:
> Best guess, your local server has register_globals on and your ISP
> doesn't. However, without seeing your code it's going to be difficult to
> tell for sure! :-)
>
>
> Marco


Thanks for the reply Marco.

The following is the code.  Any advice would be greatly appreciated.
Happy holidays...
Tony


//this is the the html page


http://www.narrowsburg.org/getform.php"; METHOD="POST">

Your Name:
Business Name:
Contact Person:
Telephone Number:
e-mail address:
Mailing Address:
Town:State:  Zip Code:
Category:
Description of your business: 






//this is the .php file called "getform.php"

http://localhost/n_proserv_x.html";);
 exit;
}
$msg = "This e-mail was sent from:\n";
$msg .= "Sender's Name:$thename\n";
$msg .= $thename ."'s business name is:$bizname\n";
$msg .= "The contact person is:$contactname\n";
$msg .= $thename. "'s phone number is:$phone\n";
$msg .= $thename. "'s e-mail address is: $email\n";
$msg .= $thename. "'s mailing address is: $mailing\n";
$msg .= "Town: $town\n";
$msg .= "State: $state\n";
$msg .= "Zip Code: $zip\n";
$msg .= $thename."'s category is: $cat\n";
$msg .= "and the message is:  $description\n\n";
$to = "[EMAIL PROTECTED]";
$subject = "Narrowsburg Chamber of Commerce";
$mailheaders = "From: $thename\n";
$mailheaders .= "Reply to:$email\n\n";
mail($to, $subject, $msg, $mailheaders);
?>
.



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--- End Message ---
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Re: [PHP] Undefined Variable

2002-12-14 Thread Anthony Ritter
>"Marco Tabini <[EMAIL PROTECTED]> wrote in message:
> Best guess, your local server has register_globals on and your ISP
> doesn't. However, without seeing your code it's going to be difficult to
> tell for sure! :-)
>
>
> Marco


Thanks for the reply Marco.

The following is the code.  Any advice would be greatly appreciated.
Happy holidays...
Tony


//this is the the html page


http://www.narrowsburg.org/getform.php"; METHOD="POST">

Your Name:
Business Name:
Contact Person:
Telephone Number:
e-mail address:
Mailing Address:
Town:State:  Zip Code:
Category:
Description of your business: 






//this is the .php file called "getform.php"

http://localhost/n_proserv_x.html";);
 exit;
}
$msg = "This e-mail was sent from:\n";
$msg .= "Sender's Name:$thename\n";
$msg .= $thename ."'s business name is:$bizname\n";
$msg .= "The contact person is:$contactname\n";
$msg .= $thename. "'s phone number is:$phone\n";
$msg .= $thename. "'s e-mail address is: $email\n";
$msg .= $thename. "'s mailing address is: $mailing\n";
$msg .= "Town: $town\n";
$msg .= "State: $state\n";
$msg .= "Zip Code: $zip\n";
$msg .= $thename."'s category is: $cat\n";
$msg .= "and the message is:  $description\n\n";
$to = "[EMAIL PROTECTED]";
$subject = "Narrowsburg Chamber of Commerce";
$mailheaders = "From: $thename\n";
$mailheaders .= "Reply to:$email\n\n";
mail($to, $subject, $msg, $mailheaders);
?>
.



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Re: [PHP] Undefined Variable

2002-12-14 Thread Marco Tabini
Best guess, your local server has register_globals on and your ISP
doesn't. However, without seeing your code it's going to be difficult to
tell for sure! :-)


Marco
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--- Begin Message ---
Using MS Win 98 / Apache Server:

I'm trying to test a form box using the php mail() function.

All is well when I fill in the text boxes and hit submit.

I receive the e-mail.

The form action in the html page is:

http://localhost/getform.php";  METHOD="POST">

_Now_

when I copy both of those files which are:

1. The html file for the form box

- I have now changed the form action to read:

http://www.narrowsburg.org/getform.php";  METHOD="POST">

and

2. the .php file for the script

and publish them to my site which is hosted on my ISP's MS Server, and then
input data in the form boxes and hit submit:

I now get the following:
..
NOTICE: Undefined Variable: name in
d:\inetpub\www.narrowsburg.org\getform.php  in line 7


Then, when I check my e-mail I get a message with no input data from the
variables like the name, e-mail, address, etc.

Thanking all in advance who might help me out.
Tony Ritter








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[PHP] Undefined Variable

2002-12-14 Thread Anthony Ritter
Using MS Win 98 / Apache Server:

I'm trying to test a form box using the php mail() function.

All is well when I fill in the text boxes and hit submit.

I receive the e-mail.

The form action in the html page is:

http://localhost/getform.php";  METHOD="POST">

_Now_

when I copy both of those files which are:

1. The html file for the form box

- I have now changed the form action to read:

http://www.narrowsburg.org/getform.php";  METHOD="POST">

and

2. the .php file for the script

and publish them to my site which is hosted on my ISP's MS Server, and then
input data in the form boxes and hit submit:

I now get the following:
..
NOTICE: Undefined Variable: name in
d:\inetpub\www.narrowsburg.org\getform.php  in line 7


Then, when I check my e-mail I get a message with no input data from the
variables like the name, e-mail, address, etc.

Thanking all in advance who might help me out.
Tony Ritter








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[PHP] Undefined Variable

2002-11-23 Thread Adriano Santos
Hi,

I'm with problem: Undefined Variable.
I'm using :
PHP 4.2.3
MySql 3.2.39
Windows 2000

How do I make to soluction my problem ?
thanks



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RE: [PHP] Undefined Variable errors

2002-11-11 Thread John W. Holmes
> I'm migrating to PHP from ColdFusion.
> 
> I've been running some sample scripts I have found in various places
and
> all
> of them throw an error:
> 
> Notice: Undefined variable:  in
> c:\inetpub\wwwroot\myphpcalendar\ on line .
> 
> In ColdFusion, I can use the  tag to preset a variable. I've
> tried
> the following code to define the variable in PHP, but it doesn't work:
> 
> if (!isset($VarName)) {
> $VarName = 0;
> }

How does that "not work?" It should, as long as you're including the
line before the others that are giving you the notice.

You can also turn down your error_reporting setting in php.ini. You can
turn off notices and just see warnings. There is an example within
php.ini.

---John Holmes...



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[PHP] Undefined Variable errors

2002-11-11 Thread James Johnson
Hello,

I'm migrating to PHP from ColdFusion.

I've been running some sample scripts I have found in various places and all
of them throw an error:

Notice: Undefined variable:  in
c:\inetpub\wwwroot\myphpcalendar\ on line .

In ColdFusion, I can use the  tag to preset a variable. I've tried
the following code to define the variable in PHP, but it doesn't work:

if (!isset($VarName)) {
$VarName = 0;
}

Is there a setting in php.ini or a call in the beginning of the script that
I need to use?

Thanks,

James Johnson
Owell Technologies
[EMAIL PROTECTED]



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RE: [PHP] Undefined variable

2002-10-09 Thread Daniel Kushner

Try using $_POST['name'] or $_GET['name']. 

E.g.: 



Regards,
Daniel Kushner
_
Need hosting? http://thehostingcompany.us



-Original Message-
From: Muhammad Khairuzzaman [mailto:[EMAIL PROTECTED]] 
Sent: Wednesday, October 09, 2002 8:22 AM
To: [EMAIL PROTECTED]
Subject: [PHP] Undefined variable


I'm trying to process data from a form, regardless whether I'm using GET
or POST method,  the value that i get in the processed form is still
null.

I check in the error log file and this is what it say:
[Wed Oct 09 20:18:47 2002] [error] PHP Notice:  Undefined variable:
name in e:\program files\apache group\apache\htdocs\test.php3 on line 3

Or is there something wrong in my code? Or something with my setting?




  
  Name: 
   
   


---








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[PHP] Undefined variable

2002-10-09 Thread Muhammad Khairuzzaman

I'm trying to process data from a form, regardless whether I'm using GET or
POST method,  the value that i get in the processed form is still null.

I check in the error log file and this is what it say:
[Wed Oct 09 20:18:47 2002] [error] PHP Notice:  Undefined variable:  name in
e:\program files\apache group\apache\htdocs\test.php3 on line 3

Or is there something wrong in my code? Or something with my setting?




  
  Name: 
   
  


---








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Re: [PHP] Undefined variable: blabla ?

2002-10-08 Thread Chris Hewitt

Hkan wrote:

>I just reinstalled the system and everything on my computer, and thought I
>should get the latest versions of apache, php and mysql, and now I get this
>message everywhere on my pages.. hehe.. :P
>how do I "define variables" ?
>
If you have reinstalled with latest versions, maybe your earlier version 
had register_globals on. Its off by default in newer versions (see the 
README with your source). Either turn it on or better, use $var = 
$_GET['varname'] for GET variables and $var = $_POST['varname'] for 
POSTED variables.

The "undefined" means that you are using a variable before giving it a 
value. Probably caused by the above, but you may also have errors set at 
E_ALL. This is good for development as it gives warnings, not just errors.

HTH
Chris



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[PHP] Undefined variable: blabla ?

2002-10-08 Thread Håkan

I just reinstalled the system and everything on my computer, and thought I
should get the latest versions of apache, php and mysql, and now I get this
message everywhere on my pages.. hehe.. :P
how do I "define variables" ?

Håkan



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RE: [PHP] Undefined variable: PHP_SELF

2002-08-15 Thread Bob Lockie


$_SERVER['PHP_SELF'] when globals are off.

>How about this:
>
>
>
>- Vic
>
>
>-Original Message-
>From: Manuel Ochoa [mailto:[EMAIL PROTECTED]] 
>Sent: Thursday, August 15, 2002 7:20 PM
>To: PHP General
>Subject: [PHP] Undefined variable: PHP_SELF
>
>
>I keep getting "Undefined variable: PHP_SELF" when using the following:
>
>
>
>Global variables are off... What am I doing wrong?
>
>__ 
>Post your ad for free now! http://personals.yahoo.ca
>
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>




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RE: [PHP] Undefined variable: PHP_SELF

2002-08-15 Thread vic

How about this:



- Vic


-Original Message-
From: Manuel Ochoa [mailto:[EMAIL PROTECTED]] 
Sent: Thursday, August 15, 2002 7:20 PM
To: PHP General
Subject: [PHP] Undefined variable: PHP_SELF


I keep getting "Undefined variable: PHP_SELF" when using the following:



Global variables are off... What am I doing wrong?

__ 
Post your ad for free now! http://personals.yahoo.ca

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Re: [PHP] Undefined variable: PHP_SELF

2002-08-15 Thread Jadiel Flores

Try $_SERVER['PHP_SELF'] instead of $PHP_SELF

At 04:19 PM 8/15/2002 -0700, you wrote:

>I keep getting "Undefined variable: PHP_SELF" when using the following:
>
>
>
>Global variables are off... What am I doing wrong?

Jadiel Flores
-
http://www.abargon.com
[EMAIL PROTECTED]
(52-55) 52-29-80-34



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RE: [PHP] Undefined variable: PHP_SELF

2002-08-15 Thread David Freeman


 > I keep getting "Undefined variable: PHP_SELF" when using the 
 > following:
 > 
 > 
 > 
 > Global variables are off... What am I doing wrong?

In current versions of PHP, $PHP_SELF is available if globals are on.
You'll need $_SERVER['PHP_SELF'] instead if you're keeping globals off.

CYA, Dave




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[PHP] Undefined variable: PHP_SELF

2002-08-15 Thread Manuel Ochoa


I keep getting "Undefined variable: PHP_SELF" when using the following:



Global variables are off... What am I doing wrong?



[PHP] undefined variable...working in PHP 4.1.2 not 4.2.1

2002-05-23 Thread Joshua E Minnie

Hey all,
I am having a problem that maybe some of you have had as well.  I am
using a session and when I pass the session variable to the next page it
comes back as undefined.  Is there some new syntax in 4.2.1 that I am
missing, I thought that I made all the necessary changes.  Here is the
entire script:

http://localhost/denied.htm";);
  exit;
}
?>
[snip] HTML CODE [snip]

[snip] MORE HTML CODE [snip]

I am getting the error at the echo statement between the HTML code, saying
that $user is undefined.  The previous page does register user.


I am running PHP 4.2.1-CGI, IIS 5, W2K SP2.


-josh



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Re: Tr: [PHP] New to PHP - Undefined variable: ??????

2002-05-01 Thread Philip Olson

Some things to consider:
 a) please read my first post :) (re: isset/empty/error_reporting)
 b) $FILE != $File != $file (case sensitive)

regards,
Philip Olson


On Thu, 2 May 2002, nico_free wrote:

> 
> - Original Message -
> From: nico_free <[EMAIL PROTECTED]>
> To: TGL <[EMAIL PROTECTED]>
> Sent: Wednesday, May 01, 2002 11:47 PM
> Subject: Re: [PHP] New to PHP - Undefined variable: ??
> 
> 
> > Well, I think the first 2 lines of your script should be :
> >
> > echo "\$FILE : $FILE";
> > var_dump($FILE);
> >
> > So, when submitting with no file, you should see some clues
> >
> > As far as I remember, your first test should be :
> >
> > <--code-->
> > if($File!="none") {
> >  print ("File name: $File_name\n");
> > ...etc
> > <--/code-->
> >
> > @++++
> >
> > - Original Message -
> > From: TGL <[EMAIL PROTECTED]>
> > To: <[EMAIL PROTECTED]>
> > Sent: Tuesday, April 30, 2002 10:44 PM
> > Subject: [PHP] New to PHP - Undefined variable: ??
> >
> >
> > > I'm new to PHP and can't get through my first script. I want to create a
> > > form that will allow the user to attach a file. I started with the file
> > > upload part of the form thinking that it ould give me the most problem,
> > and
> > > it has.
> > >
> > > This is the error message that shows when I view the page in the
> browser:
> > >
> > > Warning: Undefined variable: File in
> > > D:\inetpub\thegospellady\www\kia\form.php on line 8
> > > here is the url to the form: http://www.thegospellady.com/kia/form.php
> > >
> > > Please help.
> > >
> > >  > > /* This next conditional determines whether or not to handle the form,
> > > depending upon whether or not $File exists. */
> > > if($File) {
> > >   print ("File name: $File_name\n");
> > >   print ("File size: $File_size\n");
> > >   if(copy($File, "/users/$File_name")) {
> > >print ("Your file was successfully uploaded!\n");
> > >   } else {
> > >print ("Your file could not be copied.\n");
> > >   }
> > >   unlink($File);
> > > }
> > >
> > > print ("Upload a file to the server:\n");
> > > print (" > > ENCTYPE=\"multipart/form-data\">\n");
> > > print ("File \n");
> > > print (" VALUE=\"Submit!\">\n");
> > > ?>
> > >
> > >
> > >
> > > --
> > > PHP General Mailing List (http://www.php.net/)
> > > To unsubscribe, visit: http://www.php.net/unsub.php
> > >
> > >
> >
> 
> 
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Tr: [PHP] New to PHP - Undefined variable: ??????

2002-05-01 Thread nico_free


- Original Message -
From: nico_free <[EMAIL PROTECTED]>
To: TGL <[EMAIL PROTECTED]>
Sent: Wednesday, May 01, 2002 11:47 PM
Subject: Re: [PHP] New to PHP - Undefined variable: ??


> Well, I think the first 2 lines of your script should be :
>
> echo "\$FILE : $FILE";
> var_dump($FILE);
>
> So, when submitting with no file, you should see some clues
>
> As far as I remember, your first test should be :
>
> <--code-->
> if($File!="none") {
>  print ("File name: $File_name\n");
> ...etc
> <--/code-->
>
> @
>
> - Original Message -
> From: TGL <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Tuesday, April 30, 2002 10:44 PM
> Subject: [PHP] New to PHP - Undefined variable: ??
>
>
> > I'm new to PHP and can't get through my first script. I want to create a
> > form that will allow the user to attach a file. I started with the file
> > upload part of the form thinking that it ould give me the most problem,
> and
> > it has.
> >
> > This is the error message that shows when I view the page in the
browser:
> >
> > Warning: Undefined variable: File in
> > D:\inetpub\thegospellady\www\kia\form.php on line 8
> > here is the url to the form: http://www.thegospellady.com/kia/form.php
> >
> > Please help.
> >
> >  > /* This next conditional determines whether or not to handle the form,
> > depending upon whether or not $File exists. */
> > if($File) {
> >   print ("File name: $File_name\n");
> >   print ("File size: $File_size\n");
> >   if(copy($File, "/users/$File_name")) {
> >print ("Your file was successfully uploaded!\n");
> >   } else {
> >print ("Your file could not be copied.\n");
> >   }
> >   unlink($File);
> > }
> >
> > print ("Upload a file to the server:\n");
> > print (" > ENCTYPE=\"multipart/form-data\">\n");
> > print ("File \n");
> > print ("\n");
> > ?>
> >
> >
> >
> > --
> > PHP General Mailing List (http://www.php.net/)
> > To unsubscribe, visit: http://www.php.net/unsub.php
> >
> >
>


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Re: [PHP] New to PHP - Undefined variable: ??????

2002-05-01 Thread Philip Olson

Undefined variables errors are errors of level 
E_NOTICE.  Instead of if ($File) use if (isset($File)) 
or similiar (such as empty()). Depending on your 
mission.  A similiar example:

if (empty($form_submitted)) {
  include 'form.html';
} else {
  include 'process_form.php';
}

It's worth mentioning that one can control error 
levels both at runtime (error_reporting()) as 
well as in php.ini (.htaccess, etc).

Regards,
Philip Olson


On Tue, 30 Apr 2002, TGL wrote:

> I'm new to PHP and can't get through my first script. I want to create a
> form that will allow the user to attach a file. I started with the file
> upload part of the form thinking that it ould give me the most problem, and
> it has.
> 
> This is the error message that shows when I view the page in the browser:
> 
> Warning: Undefined variable: File in
> D:\inetpub\thegospellady\www\kia\form.php on line 8
> here is the url to the form: http://www.thegospellady.com/kia/form.php
> 
> Please help.
> 
>  /* This next conditional determines whether or not to handle the form,
> depending upon whether or not $File exists. */
> if($File) {
>   print ("File name: $File_name\n");
>   print ("File size: $File_size\n");
>   if(copy($File, "/users/$File_name")) {
>print ("Your file was successfully uploaded!\n");
>   } else {
>print ("Your file could not be copied.\n");
>   }
>   unlink($File);
> }
> 
> print ("Upload a file to the server:\n");
> print (" ENCTYPE=\"multipart/form-data\">\n");
> print ("File \n");
> print ("\n");
> ?>
> 
> 
> 
> -- 
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
> 


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[PHP] New to PHP - Undefined variable: ??????

2002-05-01 Thread TGL

I'm new to PHP and can't get through my first script. I want to create a
form that will allow the user to attach a file. I started with the file
upload part of the form thinking that it ould give me the most problem, and
it has.

This is the error message that shows when I view the page in the browser:

Warning: Undefined variable: File in
D:\inetpub\thegospellady\www\kia\form.php on line 8
here is the url to the form: http://www.thegospellady.com/kia/form.php

Please help.

\n");
  print ("File size: $File_size\n");
  if(copy($File, "/users/$File_name")) {
   print ("Your file was successfully uploaded!\n");
  } else {
   print ("Your file could not be copied.\n");
  }
  unlink($File);
}

print ("Upload a file to the server:\n");
print ("\n");
print ("File \n");
print ("\n");
?>



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RE: [PHP] undefined variable when using if ($var) {}

2002-03-25 Thread Darren Gamble

Good day.

What is this message that you get, that you don't want?

A cursory glance of the code reveals two "else" statements attached to the
same "if" statement.  You should address that.


Darren Gamble
Planner, Regional Services
Shaw Cablesystems GP
630 - 3rd Avenue SW
Calgary, Alberta, Canada
T2P 4L4
(403) 781-4948


-Original Message-
From: Martha S [mailto:[EMAIL PROTECTED]]
Sent: Monday, March 25, 2002 9:44 AM
To: [EMAIL PROTECTED]
Subject: [PHP] undefined variable when using if ($var) {}


I'm rather new to PHP, so this should be fairly easy to answer. I checked
the manual and FAQ already.

I'm using the following code, and I get the following message if $id has
nothing in the var (i have it set to a default of  type int, not null in
mysql). Is there a way around this or something I'm missing?

Thanks :)

-- code---

if ($id) {

   $result = mysql_query("SELECT * FROM entries WHERE id=$id",$db);

   $myrow = mysql_fetch_array($result);

   printf("\n");
   printf("%s", $myrow["title"]);
   printf("%s | ", $myrow["id"]);
   printf("%s", $myrow["posted"]);
   printf("%s\n", $myrow["post"]);
   printf("\n");

   printf("all");

   } else {

do {

printf("%s %s\n", $myrow["id"], $PHP_SELF,
$myrow["id"], $myrow["title"], $myrow["post"]);

  } while ($myrow = mysql_fetch_array($result));

} else {

  // no records to display

  echo "Sorry, no records were found!";

}




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[PHP] undefined variable when using if ($var) {}

2002-03-25 Thread Martha S

I'm rather new to PHP, so this should be fairly easy to answer. I checked
the manual and FAQ already.

I'm using the following code, and I get the following message if $id has
nothing in the var (i have it set to a default of  type int, not null in
mysql). Is there a way around this or something I'm missing?

Thanks :)

-- code---

if ($id) {

   $result = mysql_query("SELECT * FROM entries WHERE id=$id",$db);

   $myrow = mysql_fetch_array($result);

   printf("\n");
   printf("%s", $myrow["title"]);
   printf("%s | ", $myrow["id"]);
   printf("%s", $myrow["posted"]);
   printf("%s\n", $myrow["post"]);
   printf("\n");

   printf("all");

   } else {

do {

printf("%s %s\n", $myrow["id"], $PHP_SELF,
$myrow["id"], $myrow["title"], $myrow["post"]);

  } while ($myrow = mysql_fetch_array($result));

} else {

  // no records to display

  echo "Sorry, no records were found!";

}




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[PHP] Undefined Variable in IF...ELSE IF ...ELSE IF (NEWBIE ?)

2002-03-15 Thread Daniel Negron/KBE

I have error's enabled in php.ini.  I keep getting  Undefined variable when
I run a script that contains IF or ELSE IF's.  Is this normal because the
variable hasn't been set at the beginning of the script ?



Thank You

<><><><><><><><><><><><><><><><>

Daniel Negrón
Lotus Notes Administrator / Developer
KB Electronics, Inc.
954.346.4900x122
http://www.kbelectronics.com

<><><><><><><><><><><><><><><><>


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Re: [PHP] Undefined variable

2001-10-19 Thread Dimitris Kossikidis

This should work ...

if ( IsSet($id) ) {
.
sql statement
}else{
.
}

- Original Message -
From: "Tshering Norbu" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Friday, October 19, 2001 12:22 PM
Subject: [PHP] Undefined variable


> Dear list,
>
> I test the  following script on local web server and it runs fine. But
when
> I upload the script to the real web server I get the following
> error/message, but the script works fine. Do you know why?
>
> Here is the error/message I get:
>
> Undefined variable : id in test.php on line 6
>
>
> And here is the script file (test.php):
>
> 
> 
>  $db = mysql_connect("localhost", "root", "root");
> mysql_select_db("penpal",$db);
> if ($id)
>
> $result = mysql_query("select * from penpal where id = $id",$db);
> $myrow = mysql_fetch_array($result);
> printf("ID: %s\n", $myrow["id"]);
> printf("Name: %s\n", $myrow["name"]);
> printf("Age/Sex/Location: %s\n", $myrow["asl"]);
> printf("Description: %s\n", $myrow["description"]);
> printf("Email: %s\n", $myrow["email"]);
> } else {
> $result = mysql_query("select * from penpal order by id desc", $db);
> if ($myrow = mysql_fetch_array($result)) {
> do {
>printf("%s %s\n", $PHP_SELF,
$myrow["id"],
> $myrow["name"], $myrow["asl"]);
> } while ($myrow = mysql_fetch_array($result));
> }   else {
> echo "Sorry, no records";
>}
> }
> ?>
> 
> 
>
>
>
> The id field in my table has the attribute: id tinyint (4)
>
> Thanks in advance
> NOBBY
>
>
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RE: [PHP] Undefined variable

2001-10-19 Thread Boaz Yahav

it's a warning, not an error...
you should check if it is set before you use it :

If(IsSet($id)) {
Do something...
}

Sincerely

  berber

Visit http://www.weberdev.com Today!!! 
To see where PHP might take you tomorrow.

-Original Message-
From: Tshering Norbu [mailto:[EMAIL PROTECTED]]
Sent: Friday, October 19, 2001 11:23 AM
To: [EMAIL PROTECTED]
Subject: [PHP] Undefined variable


Dear list,

I test the  following script on local web server and it runs fine. But
when
I upload the script to the real web server I get the following
error/message, but the script works fine. Do you know why?

Here is the error/message I get:

Undefined variable : id in test.php on line 6


And here is the script file (test.php):



ID: %s\n", $myrow["id"]);
printf("Name: %s\n", $myrow["name"]);
printf("Age/Sex/Location: %s\n", $myrow["asl"]);
printf("Description: %s\n", $myrow["description"]);
printf("Email: %s\n", $myrow["email"]);
} else {
$result = mysql_query("select * from penpal order by id desc", $db);
if ($myrow = mysql_fetch_array($result)) {
do {
   printf("%s %s\n", $PHP_SELF,
$myrow["id"],
$myrow["name"], $myrow["asl"]);
} while ($myrow = mysql_fetch_array($result));
}   else {
echo "Sorry, no records";
   }
}
?>





The id field in my table has the attribute: id tinyint (4)

Thanks in advance
NOBBY


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[PHP] Undefined variable

2001-10-19 Thread Tshering Norbu

Dear list,

I test the  following script on local web server and it runs fine. But when
I upload the script to the real web server I get the following
error/message, but the script works fine. Do you know why?

Here is the error/message I get:

Undefined variable : id in test.php on line 6


And here is the script file (test.php):



ID: %s\n", $myrow["id"]);
printf("Name: %s\n", $myrow["name"]);
printf("Age/Sex/Location: %s\n", $myrow["asl"]);
printf("Description: %s\n", $myrow["description"]);
printf("Email: %s\n", $myrow["email"]);
} else {
$result = mysql_query("select * from penpal order by id desc", $db);
if ($myrow = mysql_fetch_array($result)) {
do {
   printf("%s %s\n", $PHP_SELF, $myrow["id"],
$myrow["name"], $myrow["asl"]);
} while ($myrow = mysql_fetch_array($result));
}   else {
echo "Sorry, no records";
   }
}
?>





The id field in my table has the attribute: id tinyint (4)

Thanks in advance
NOBBY


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Re: [PHP] Undefined Variable in formular... what happens???

2001-09-18 Thread Philip Olson


Most likely it has to do with your error_reporting setting.  See :

  http://uk.php.net/manual/en/phpdevel-errors.php#internal.e-notice  
  http://uk.php.net/manual/en/features.error-handling.php

Level E_NOTICE produces Warnings such as "Undefined Variable", so, doing
the following :

  echo $iamnotset; 

Produces such a Error/Warning.  Any "direct" use of $iamnotset will, which
is why functions such as isset() and empty() exist :

  if (isset($var)) echo $var;

I am guessing either you have :

  if ($submit) {
// process form and no Warnings as $submit is set
  } else {
// show form and WILL show the Warnings as $submit is not set
  }

Consider :

  if (isset($submit)) {

It's not uncommon to have E_NOTICE off but good little PHP developers
develop with error_reporting turned up full blast, E_ALL in da house!

Second, perhaps you expect register_globals to be on, see the following :

  http://uk.php.net/manual/en/configuration.php#ini.register-globals
  http://uk.php.net/manual/en/security.registerglobals.php

If off, foo.php?fruit=apple will not create $fruit but rather, you'd go
through a predefined variable like : $HTTP_GET_VARS['fruit'].

  http://uk.php.net/manual/en/language.variables.predefined.php  


Regards,
Philip Olson

On Tue, 18 Sep 2001, Ingo wrote:

> hello
> i am using win2000 xitami, php and access. so my problem is that the script
> couldn't find the variable.. .
> so i cant save the user changed buttons and editfields...
> 
> is that a known problem with xitami and php?  when i try
> to run the script on a real webserver with .php installed, it works fine.
> 
> thanx ingo
> 
> 
> 
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[PHP] Undefined Variable in formular... what happens???

2001-09-18 Thread Ingo

hello
i am using win2000 xitami, php and access. so my problem is that the script
couldn't find the variable.. .
so i cant save the user changed buttons and editfields...

is that a known problem with xitami and php?  when i try
to run the script on a real webserver with .php installed, it works fine.

thanx ingo



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Re: [PHP] 'Undefined Variable' help...

2001-09-04 Thread Philip Olson

Hi Uchendu!

Yes, this is very possible!  Here are a few things that come to mind.
There are of course many ways to do this :

To check the existance of a variable, consider isset() as it checks for
the existance of a variable :

if (isset($HTTP_GET_VARS['images']))

Maybe set some default values for unset variables :

   if (!isset($width)) $width = 300;
   if (!isset($breads)) {
  $breads = array('rye','wheat','raison');
   }

A little debugging :

  

  

A "Undefined Variable" Error is level E_NOTICE.  More error handling
information can be found here :

  http://www.php.net/manual/en/features.error-handling.php

Doing the following will create a "Undefined Variable" Warning such as :

  if ($submit) // if (isset($submit))
  echo $iamnotset; // if (isset($iamnotset)) echo $iamnotset;

  Warning: Undefined variable: submit in /home/http/file.php on line 24
  Warning: Undefined variable: iamnotset in /home/http/file.php on line 25

Related places :

  Using Register Globals  :
  http://www.php.net/manual/en/security.registerglobals.php

  Variables from outside PHP  :
  http://www.php.net/manual/en/language.variables.external.php

  Configuration : error_reporting :
  http://www.php.net/manual/en/configuration.php#ini.error-reporting

Hope that helps, good luck :)

Regards,
Philip Olson



On Tue, 4 Sep 2001, Uchendu Nwachukwu wrote:

> OK, I have a problem calling a function using default variables.
> 
> In 'gallery.inc':
> -
> function gallery ($filename, $first = 1, $tablewidth = 4, $total = 20) {
> echo "Filename: $filename, First image: $first, Table Width:
> $tablewidth, Total: $total";
> }
> -
> 
> In 'gallery.php':
> -
> include('/path/to/gallery.inc');
> ...
> gallery('test.txt',$first,$width,$images);
> -
> 
> $first, $width and $images are variables that are defined by the URL, as if
> they were submitted through a form using HTTP GET, and they are designed to
> be used like that.
> 
> My problem is, if I don't define those variables in the URL when I run
> gallery.php, PHP will come back with 'Undefined Variable' errors. Is there
> any way I can prevent that from happening?
> 
> TIA!
> 
> --
> Uchendu Nwachukwu
> unndunn AT yahoo DOT com - www.unndunn.com
> 
> 
> 
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[PHP] 'Undefined Variable' help...

2001-09-04 Thread Uchendu Nwachukwu

OK, I have a problem calling a function using default variables.

In 'gallery.inc':
-
function gallery ($filename, $first = 1, $tablewidth = 4, $total = 20) {
echo "Filename: $filename, First image: $first, Table Width:
$tablewidth, Total: $total";
}
-

In 'gallery.php':
-
include('/path/to/gallery.inc');
...
gallery('test.txt',$first,$width,$images);
-

$first, $width and $images are variables that are defined by the URL, as if
they were submitted through a form using HTTP GET, and they are designed to
be used like that.

My problem is, if I don't define those variables in the URL when I run
gallery.php, PHP will come back with 'Undefined Variable' errors. Is there
any way I can prevent that from happening?

TIA!

--
Uchendu Nwachukwu
unndunn AT yahoo DOT com - www.unndunn.com



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Re: [PHP] "undefined variable view ..."

2001-08-26 Thread David Robley

On Mon, 27 Aug 2001 02:59, Wolfgang Schneider wrote:
> Hi everybody,
> can someone have a look at this bit of code please and help me out?
> I am getting an error message when calling a php page containing the
> code below, and the message reads:
>
> "Warning: Undefined index: view in
> c:/bibelcenter.de/www/links/links.php3 on line 76"
>
> Now the line 76 in question is the last one of the code section below
> ... can someone tell me what's missing there? how could this "index
> view" be defined?
> 
>
>  # Get the content before showing the webpage
> if ($HTTP_GET_VARS['category'] == 'top_links')
>{
>   $your_current_location = "Most Popular Links";
>   $category_links=Top_Hits($sp_max_top_links);
> }
> else if ($HTTP_GET_VARS['category'] == 'new_links')
> {
>   $your_current_location = "Newly Added Links";
>   $category_links=Newly_Added($sp_max_new_links);
> }
> else
> {
>   $categories = viewPage($HTTP_GET_VARS['category']);
>   $your_current_location =
> display_category($HTTP_GET_VARS['category']);
>   $category_links =
> display_category_links($HTTP_GET_VARS['category'],
> $HTTP_GET_VARS['view']);
> }
> _
>
> Any helpful ideas? I only get this warning message in my Win2k
> machine which I have set up for testing webpages purposes, it does
> not show up on my ISP's server ... so I suspect that somehow the
> server's php tolerates something in the code which my php version
> here somehow puts up the warning ...
> Any helpful hints and ideas are much appreciated. Thank you!

There will probably be different levels of error reporting in the two 
php.ini files.

view is an index of the array $HTTP_GET_VARS, and is apparently not 
defined at that part of the script.

-- 
David Robley  Techno-JoaT, Web Maintainer, Mail List Admin, etc
CENTRE FOR INJURY STUDIES  Flinders University, SOUTH AUSTRALIA  

   A cat sleeps fat, yet walks thin.

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[PHP] "undefined variable view ..."

2001-08-26 Thread Wolfgang Schneider

Hi everybody,
can someone have a look at this bit of code please and help me out? 
I am getting an error message when calling a php page containing the
code below, and the message reads:

"Warning: Undefined index: view in
c:/bibelcenter.de/www/links/links.php3 on line 76"

Now the line 76 in question is the last one of the code section below
... can someone tell me what's missing there? how could this "index
view" be defined?


 # Get the content before showing the webpage 
if ($HTTP_GET_VARS['category'] == 'top_links')
   {   
$your_current_location = "Most Popular Links";
$category_links=Top_Hits($sp_max_top_links);
}
else if ($HTTP_GET_VARS['category'] == 'new_links')
{   
$your_current_location = "Newly Added Links";
$category_links=Newly_Added($sp_max_new_links);
}
else
{
$categories = viewPage($HTTP_GET_VARS['category']);
$your_current_location =
display_category($HTTP_GET_VARS['category']);
$category_links =
display_category_links($HTTP_GET_VARS['category'],
$HTTP_GET_VARS['view']);
}
_

Any helpful ideas? I only get this warning message in my Win2k
machine which I have set up for testing webpages purposes, it does
not show up on my ISP's server ... so I suspect that somehow the
server's php tolerates something in the code which my php version
here somehow puts up the warning ... 
Any helpful hints and ideas are much appreciated. Thank you!
God bless you with His grace and peace 
Wolfgang 

Looking for Biblical information? COME AND SEE! 
-- ONLINE Courses: http://classes.bibelcenter.de ... NEW!
-- BibelCenter: http://www.bibelcenter.de 
-- Bookstore: http://www.worthy.net/BibelCenter/ 




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Re: [PHP] Undefined Variable

2001-03-18 Thread David Robley

On Sun, 18 Mar 2001 00:13, Jorge Alvarez wrote:
> Hi there,
>
> I get this error every time I try to use a variable that has not been
> declared. Is this new to PHP4? I do not recall this error in the past,
> echo $MYVAR echoed nothing if $MYVAR was not set but no error was
> raised.
>
> How can I revert PHP behavior to 'no-error' with undeclared variables?
>
> Many thanks in advance,
>
> Jorge Alvarez
> PHP4 new user

You may need to play around with the value of error_reporting in your 
php.ini file.

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[PHP] Undefined Variable

2001-03-17 Thread Jorge Alvarez

Hi there,

I get this error every time I try to use a variable that has not been
declared. Is this new to PHP4? I do not recall this error in the past, echo
$MYVAR echoed nothing if $MYVAR was not set but no error was raised.

How can I revert PHP behavior to 'no-error' with undeclared variables?

Many thanks in advance,

Jorge Alvarez
PHP4 new user





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RE: [PHP] Undefined variable

2001-02-04 Thread PHPBeginner.com

try setting error_reporting(0) in PHP.ini



Sincerely,

 Maxim Maletsky
 Founder, Chief Developer

 PHPBeginner.com (Where PHP Begins)
 [EMAIL PROTECTED]
 www.phpbeginner.com


-Original Message-
From: Dundee (Roland) [mailto:[EMAIL PROTECTED]]
Sent: Sunday, February 04, 2001 5:35 AM
To: Php_List
Subject: [PHP] Undefined variable


Hello

When creating a page(php) on Win2000 I get alot of 'Undefined variable'
error messages, but there are no errors at all running the same page on a
apache server.

How come?


Thanks for some hints.

Roland


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Re: [PHP] Undefined variable

2001-02-03 Thread Steve Werby

"Dundee (Roland)" <[EMAIL PROTECTED]> wrote:
> When creating a page(php) on Win2000 I get alot of 'Undefined variable'
> error messages, but there are no errors at all running the same page on a
> apache server.

Is the variable a user defined variable?  If so, my guess is the error
reporting level for the two servers is different.  See the error handling
section of php.ini and see if the default settings differ b/w the two
servers.  Also see error_reporting() if you're explicitly using that
function.  If the variable is a PHP or environment variable perhaps the
variable is available on Apache, but not on Win2k.  I have very little
experience with PHP on Windows so it could be something else, but that's
where I'd start.

--
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COO
24-7 Computer Services, LLC
Tel: 804.817.2470
http://www.247computing.com/


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[PHP] Undefined variable

2001-02-03 Thread Dundee \(Roland\)

Hello

When creating a page(php) on Win2000 I get alot of 'Undefined variable'
error messages, but there are no errors at all running the same page on a
apache server.

How come?


Thanks for some hints.

Roland


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