what i was trying to say if you go 46.5' and that ends up being 2' past spkr
A then you go half the distance to the next sprinkler as this is how far
spkr A will throw and is the basis of it's sq ft., yes it will probably
always be more than 46.5'......but if you end your remote footprint at the
46.5' you will be cheating yourself, so take each line separately starting
at 46.5' ending it at the closest center between sprinklers MORE than or
Equal to 46.5' to have the correct number of heads on each line flowing, the
last line is where you get closest as you can to 1500, but as I said it will
probably be over 1500.....all heads flow 1/2 their distance to the next one
right..unnerstand??



n Tue, Apr 20, 2010 at 11:41 AM, Brad <[email protected]> wrote:

> If you calc 1640 SF, now the min. length is 49', not 46.5'
>
> -----Original Message-----
> From: tom poisal [mailto:[email protected]]
> Sent: Tuesday, April 20, 2010 10:34 AM
> To: [email protected]
> Subject: Re: Calc Area
>
> The length along the branch line, 1.2 x sq rt 1500 = 46.5' is measured from
> the wall (or center point between 2 spkrs) along the line, if it ends up
> mathmatically short of the center of two sprinklers you must pick up that
> additional sprinkler (end it at the center between the next head) and that
> "square " becomes the lengh S (be it 64') times L as a sq ft footprint, go
> to the next line and repeat, to the 46.5' and add those together, keep
> repeating until you reach 1500 sq ft, which will probably be more like 1640
> or some such. If you want to really fine tune you can decrease the .1
> density which is for the 1500 sq ft to the correct one for 1640
>
> Tom Poisal, CET
>
>
>
> On Tue, Apr 20, 2010 at 10:58 AM, Ron Greenman <[email protected]
> >wrote:
>
> > And remember that FM is 1:1.4 suggesting that the adjusted ratio for
> > each entity has to be equal to or greater than 1: 1.2 (NFPA) or 1:1.4
> > (FM).
> >
> > On Tue, Apr 20, 2010 at 7:54 AM, Brad <[email protected]> wrote:
> > > Something I overlooked until about 8 years ago: 1.2 x AREA USED---
> > > Example 1500 SF- min. length 46.5', maybe 4 heads---- 1590 SF- min.
> > length
> > > 48', maybe 5 heads!
> > >
> > > -----Original Message-----
> > > From: Roland Huggins [mailto:[email protected]]
> > > Sent: Tuesday, April 20, 2010 9:36 AM
> > > To: [email protected]
> > > Subject: Re: Calc Area
> > >
> > > counting sprinklers is ONLY a casual means to check to ensure you are
> > > CLOSE to the required floor area.  You must measure actual floor area
> > > with no regard to sprinkler spacing or distance to wall.  Now in
> > > defining the area of coverage for each sprinkler, your question raises
> > > a point often asked.  In a non-symmetrical layout, you use the longer
> > > on each side to define S and L such that the sprinkler is always in
> > > the center of the imaginary box.  Not well explained by the standard
> > > since it mainly talks about distance to walls.
> > >
> > > Roland
> > >
> > >
> > > On Apr 19, 2010, at 11:41 PM, George Medina Jr wrote:
> > >
> > >>
> > >> If I am calculating a tree type system using the area/design method,
> > >> and have several different lengths between sprinklers on a branch
> > >> line. Would I use the longest length to determine the amount of
> > >> sprinklers on a branch line. I have always used an average (which
> > >> I've probably been wrong all these years).
> > >>
> > >> 1.2vdesign area
> > >>           S
> > >> S= Distance between sprinklers on branch line
> > >>
> > >>
> > >>
> > >> 1.2vdesign area
> > >>           S
> > >> S= Distance between sprinklers on branch line
> > >>
> > >>
> > >>
> > >>
> > >> George Medina Jr.
> > >>
> > >>
> > >> _______________________________________________
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> > >>
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> >
> > --
> > Ron Greenman
> > Instructor
> > Fire Protection Engineering
> > Bates Technical College
> > Tacoma, WA
> >
> > Member:
> > SFPE, ASCET, NFPA, AFSA, NFSA AFAA, NIBS, WSAFM, WFC
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-- 
Tom Poisal, CET
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