Jones wrote. > > Fred, > > Given that this kind of efficient electrolysis you > have been talking about is a surface effect - why > would you not maximize the surface area? such as by > switching to a stainless steel foil, instead of tubes > or plates - you should be able to get an order of > magnitude (or several) more surface area for the same > weight of stainless.... perhaps by forming two layers > of SS-foil into a double "jelly-roll" spiral? > Sure thing Jones.But the spacing may be a significant factor for getting OH gas as opposed to the HO-OH liquid or O2 or H2 instead of H formed at the anode or cathode metal-water interface. The Joe Cell has about 4,000 square cm of floating/"neutral" plate area plus the 2"dia x 10 inch cathode surface and the 6"dia x ~ 12" anode-shell. Autoionization puts about 1.0E8 OH-/cm^2 on one side and 1.0E8 H3O+/cm^2 on the other side of a plate or foil that can neutralize by electron exchange through the plate or foil without showing up in the battery circuit that is measuring the current through the series grouping of cells.
So, in the Joe Cell at 12 volts @ 1.0 ampere electrolysis current is augmented by Free Energy through-the-plate discharge and Metal-Water Interface AutoDissociation Effects. Helmholtz didn't take the biased plate backside layer or the back streaming of O2 onto the plate surfaces to get AutoDissociation of water into account. :-) Fred > http://www.outokumpu.com/pages/Page____5668.aspx
