On Aug 7, 2007, at 7:48 PM, Robin van Spaandonk wrote:
In reply to Jones Beene's message of Tue, 07 Aug 2007 07:49:40 -0700:
Hi,
[snip]
If the faux-n has a significantly larger spatial near field - how
does
that change the cross section? The most logical answer would be to
enhance.
Yes, but there is a snake in the grass. Since Faux-n is not really
n, the near
field of the electron will only suffice to bring it closer to the
nucleus. But
this may only happen once. Consider that the electron is still
"tied" to the
proton by it's electric field, and hence is equally subject to the
electric
field of the larger nucleus. IOW there is every chance that the
shrunken
electron will "jump ship" at the first opportunity, forming an even
tighter
orbit around the heavy nucleus, and resulting in the proton simply
being
expelled by the repulsive force of the larger nucleus. This is a
"hydrino
destroyer", and it may be the reason that transmutation reactions
are still
rather rare.
Yes, the binding energy of the faux-n is not enough to withstand a
large E. It takes a weak reaction to create a real neutron, plus
lots of energy, to create the neutron's highly bound state.
OTOH of course there is a considerable energy release when the
electron jumps ship, which in itself may still be useful as a fuel
source,
especially if the larger nucleus is of a common element such as
Oxygen or
Silicon.
That's an interesting observation.
BTW this process may also have the net effect of *appearing* to
transform the
element in question to one which is one lower on the periodic
table, but with
the same mass. The "transformation" would effect chemical
reactions, but should
have little influence on e.g. naa.
Unless a weak reaction is triggered, it seems likely the electron
would very quickly (a few femtoseconds) return to an expanded volume
quantum waveform. There is zero point energy available to do this
expansion.
Horace Heffner
http://www.mtaonline.net/~hheffner/
