OK,
I follow your math now and it seems like a sound theory with the
only assumption that an inertial mass change occurs.
Regards
Francis X roarty
Snip
Maybe if I rephrase the principles or clarify the computations.
I proposed extracting momentum from the energy and inertial mass
change, the dp/dt change, instead of the energy difference, as did
Haisch and Moddel. Both concepts have the difficulty that the energy
and inertial mass change is not experimentally verified, and thus not
quantifiable for engineering purposes. By converting mass changes in
cavity traverses to momentum gain, however, as I propose, energy is
ultimately made available by converting the dp/dt change thrust into
device momentum, especially for space propulsion. Also, if
sufficient momentum is gained with respect to drive energy input,
then such a thruster drive can be mounted on a large armature of an
electric generator in order to produce electrical energy directly.
Here is the description of the device principles: "On each transition
from thick cavity to thin cavity, the gas flow transfers momentum to
the walls due to the angular acceleration. The gas "snakes" through
the thrust cells. The momentum transferred in the thin cavities is
upward in Fig. 1. The momentum transferred in the thick cavities is
downward in Fig. 1. Since the same gas flows through all cavities in
a row, the mass flow for the cells is identical. If there is no
change of inertial mass in the thin cavities, then no net thrust
results. However, if the inertial mass of the gas molecules/atoms is
less in the thin cavities, then less momentum is transferred toward
the top of Fig. 1 by the gas when in the thin cavities, and a net
thrust develops downward in Fig. 1."
I corrected some typos in the calculation and clarified the
narrative: "If we use r=10^-5 m, and v= 10^-4 m/s, we get a
centrifugal force F = m*(V^2)/r of about 10 N/kg. The gas flows
through an orifice 10^-6m x 10^-5 m, or 10^-11 m^2. Argon is 1.784 g/
l. At 10^-4 m/s the flow rate is 10^-14 g/s = 10^-17 kg/s. With an
effective r of 10^-5 m, the mass of gas accelerating is the volume
10^-11 m^2 x 10^-5 m = 10^-16 m^3 times the density, or (10^-16 m^3)
(1.78x10^3 kg/(1000 cm^3)) (10^2 cm)^3/m^3 = 1.78x10^-10 kg. This
gives a very rough thrust per cell of about (10 N/kg)(1.78x10^-10 kg)/
2 = about 10^-9 N = 1x10^-10 kgf. Given 10^14 cells/m^3, we have
(1x10^-10 kgf)(10^14 cells/m^3) = 10^4 kg of thrust per cubic meter
of cells. However, if the inertial mass reduction is only 0.01
percent, then the thrust is only 1 kg per cubic meter of cells."
