The magnetic fields may be very high frequent which will cause eddy currents in the shielding plates, creating counter magnetic fields, resulting in strongly reduced magnetic interference. In that sence shielding will work.
Op woensdag 24 juli 2013 schreef David Roberson ([email protected]) het volgende: > Good point Eric. But keep in mind that a Faraday shield would not stop a > magnetic field. They can eliminate electrostatic fields, but not magnetic > ones unless the field is at a very high frequency. This is an important > piece of the puzzle if true. > > Dave > > > -----Original Message----- > From: Eric Walker <[email protected] <javascript:_e({}, 'cvml', > '[email protected]');>> > To: vortex-l <[email protected] <javascript:_e({}, 'cvml', > '[email protected]');>> > Sent: Wed, Jul 24, 2013 1:45 am > Subject: Re: [Vo]:Ni 61 does not react. (Ideas why this would be?) > > On Tue, Jul 23, 2013 at 10:25 PM, Axil Axil > <[email protected]<javascript:_e({}, 'cvml', '[email protected]');> > > wrote: > >> Today, Defkalion stated that the reactor packs huge magnetic fields >> capable of disrupting all electronic equipment in the general vicinity of >> the reactor core. The core had to be shielded by a double ply faraday cage. >> That huge field is produced by nano-particles in a bath of infrared >> radiation. >> > This makes it sound like there is a current of some kind. If so, that > is a point in favor of energetic particles (coherent groups, perhaps) and a > point against slow deuterium/helium formation, which, presumably, would not > produce currents (unless I'm misunderstanding an implication). > > Eric > >
