https://docs.google.com/file/d/0B6id5Hf-xMWOYXVjekJCN1ZkQk0/edit?pli=1

Ed:

I suggest that you integrate these experimental results from Paintilli into
your thinking. I see high energy particle tracks an many counts in the
gamma ray energy range. The last two slides show gammas.


On Wed, Mar 5, 2014 at 8:09 PM, Edmund Storms <[email protected]> wrote:

> Bob, 23.8 MeV of energy must be released for each He made. Each emitted
> He4 from Be8 needs to carry 23.8 MeV of energy. Please explain how even a
> small fraction of that energy can appear as spin.
>
> When alpha particles pass through material, a series of nuclear reactions
> can occur that emit radiation. In addition,  bremsstrahlung radiation is
> emitted as the alpha slows down. Hagelstrin describes these processes in
> the papers I attached previously. I suggest you read them.
>
> Ed
>
> On Mar 5, 2014, at 5:07 PM, Bob Cook wrote:
>
> Ed--
>
> You said:
>
> >However, the resulting alpha would have too much energy for the secondary
> radiation to be missed.<
>
> If the alphas are in high spin states upon the decomposition of Be-8, then
> small amounts of energy associated with transition from one state to the
> next lower state would never be seen.  If  many electrons are involved in
> the reaction it seems likely only small energy packets would be released.
> The secondary radiation may be missed.
>
> Why do you imply the secondary radiation should necessarily be a high
> energy photon(s)?
>
> Bob
>
> ----- Original Message -----
> *From:* Edmund Storms <[email protected]>
> *To:* [email protected]
> *Cc:* Edmund Storms <[email protected]>
> *Sent:* Wednesday, March 05, 2014 3:34 PM
> *Subject:* Re: [Vo]:"Christopher H. Cooper"
>
>
> On Mar 5, 2014, at 3:45 PM, David Roberson wrote:
>
> Ed, I was not suggesting that this reaction is the main one, I was merely
> pointing out that it is possible.  Someone made a blanket statement that
> this path was not possible and I wanted to clear the air.
>
>
> Dave, none of us has the time to describe every aspect of the issue in
> each e-mail. We all have to assume the reader has done some homework and
> knows that the statement is not  complete and that the writer also know
> this. In any case, emission of a photon makes the process two body, not one
> body as I was describing.
>
> The conservation of energy and momentum does not prevent this from
> happening as was stated.  Had the original proposition been that it was not
> likely or observed I would have remained silent.
>
>
> The fact is that during cold fusion NO energetic gamma is emitted, which
> was known in 1989. Therefore, this issue is not relevant. People propose
> the He4 is emitted as an alpha, which means the helium has translational
> energy. This is not possible when one particle is involved, which is what I
> said. Takahashi proposes Be8 forms and decomposes into two alpha, which
> does conserve energy and momentum and is not inconsistent with the basic
> requirements. However, the resulting alpha would have too much energy for
> the secondary radiation to be missed. Therefore, this proposed reaction
> does not occur. Each theory suggested so far can be eliminated by
> identifying these conflicts with observation.  If the observations were not
> so many and so strong, a person might conclude that LENR is impossible,
> which of course is the skeptical conclusion. Nevertheless, the effect is
> real and therefore it must have an explanation. Until people actually
> search where the keys are located rather than under the lamppost, success
> will be impossible.
>
> Ed Storms
>
>
> Dave
>
>
>
> -----Original Message-----
> From: Edmund Storms <[email protected]>
> To: vortex-l <[email protected]>
> Cc: Edmund Storms <[email protected]>
> Sent: Wed, Mar 5, 2014 5:29 pm
> Subject: Re: [Vo]:"Christopher H. Cooper"
>
> Yes Dave, that is true, but that is not what is observed. This reaction is
> known to happen less than 1% of the time during hot fusion and it produces
> a 23 MeV gamma that is required to conserve momentum. This reaction is
> clearly not observed. We know this for a fact. Therefore, this idea is
> irrelevant.
>
> Ed Storms
> On Mar 5, 2014, at 2:34 PM, David Roberson wrote:
>
> Ed, the energy can be released in the form of a particle, such as an
> alpha, and a gamma ray.  Energy and momentum can be conserved in that
> manner.  The bulk of the energy will be given to the gamma ray due to the
> large difference in masses.    Think of a rifle firing a bullet.  Most of
> the energy ends up in the bullet while linear momentum is conserved.
>
> Dave
>
>
>
> -----Original Message-----
> From: Edmund Storms <[email protected]>
> To: vortex-l <[email protected]>
> Cc: Edmund Storms <[email protected]>
> Sent: Wed, Mar 5, 2014 4:09 pm
> Subject: Re: [Vo]:"Christopher H. Cooper"
>
> Bob, we are discussing a basic and fundamental concept. The energy
> generated when mass-energy is released requires emission of at least two
> particles for the energy to be dissipated. I know of no example in nature
> where this requirement does not operate when energy is released.  If energy
> is not released immediately, but is retained in the nucleus, this nucleus
> is found to be unstable and will eventually release energy over a period of
> time by emission of a particle, including a photon.  This is how nature is
> found to behave. Imagining otherwise is not useful unless you have observed
> support for the idea.
>
> Ed Storms
>
>
> On Mar 5, 2014, at 2:01 PM, Bob Cook wrote:
>
> Ed--
>
> You said:
>
> >>Yes, that is what I'm saying. LENR can not result in a single alpha
> because two particles are required to conserve momentum when energy is
> released. <<
>
> I note that, if there is no linear momentum to start, two particles would
> not be required.  I do not believe conservation of angular momentum
> requires two particles either.  And keep in mind that potential energy may
> be changed to the energy of angular momentum/spin energy in LENR.
>
> Bob
>
> ----- Original Message -----
> *From:* Edmund Storms <[email protected]>
> *To:* [email protected]
> *Cc:* Edmund Storms <[email protected]>
> *Sent:* Wednesday, March 05, 2014 12:06 PM
> *Subject:* Re: [Vo]:"Christopher H. Cooper"
>
>
> On Mar 5, 2014, at 12:28 PM, Jones Beene wrote:
>
> From: Edmund Storms
>
> Jones, bremsstrahlung or "slowing down radiation" is not
> produced by photons.
>
> Who said it was?
>
>
> I'm not answering a claim. I'm simply giving information. You brought up
> photons by talking about gamma emissions, which are photons. You then added
> the production of bremsstrahlung, which I simply pointed out is not
> produced by gamma.
>
> You brought up photons. I asked for adequate documentation
> of intense photon emission - and am still waiting.
>
>
> I sent a list of references. If you want a copy of a particular paper to
> read, ask and I will send what I have.  Unfortunately, I can not send using
> Vortex and I can not send all the papers.
>
>
> This is generated by energetic electrons or particles such
> as alpha emission. LENR produces neither kind of radiation.
>
> What? Are you now saying that the helium you claim to see in Pd-D does not
> begin as an alpha particles?
>
>
> Yes, that is what I'm saying. LENR can not result in a single alpha
> because two particles are required to conserve momentum when energy is
> released.
>
>
> Therefore, bremsstrahlung is not an issue because all the
> mass-energy is dissipated as photons.
>
> There is no proof of this.
>
>
> The proof is in the behavior. This is the only conclusion consistent with
> all behavior. Unfortunately, a book is required to present this information
> in a form and as complete as you require. I'm attempting to do this. Please
> be patient.
>
>
> The only question is how this happens.  I have proposed a
> mechanism. The only issue is whether this mechanism is plausible and
> consistent will all the other observations.
>
> It is not plausible if you cannot document photons sufficient to account
> for
> the heat.
>
>
> I agree, the measurement of heat and radiation have not been done in a way
> to show a quantitative correlation. However, I suggest you apply this
> standard to the other explanations as well. If you do, I think you will
> have to agree that no explanation meeting this requirements presently
> exists, including your own.
>
> Ed Storms
>
>
> Where is the documentation?
>
> Jones
>
>
> <winmail.dat>
>
>
>
>
>
>
>
>
>

Reply via email to