Jed, According to the reference I have found water vapor and liquid water remain in combination at a pressure of 15.7902 psi absolute when subject to 102 C. Since you and others appear to believe that most of the mass of water going to the customer equipment is liquid then that would likely be the situation. The temperature reading of the combination should be accurate, but the pressure reading could well indicate 1 atm according to a gauge even though it remains actually higher. I suspect that the Bernoulli principle is getting into the act in this case due to the rapid motion of the fluid.
This situation might explain why the steam is not dry as many would expect. According to my hypothesis it is extremely wet even at 102 C and subject to a false gauge pressure reading of 1 atm. So, Rossi might be right about the gauge reading 0.0 bar while at the same time I.H. is correct about the true pressure within the stream being at a higher level. The proof of this statement requires that we figure out how to properly apply the Bernoulli principle. This idea may lead to a blind alley, but it does seem appropriate. Dave -----Original Message----- From: Jed Rothwell <jedrothw...@gmail.com> To: vortex-l <vortex-l@eskimo.com> Sent: Tue, Aug 23, 2016 10:06 am Subject: Re: [Vo]:Interesting Steam Calculation David Roberson <dlrober...@aol.com> wrote: Where did the pressure of 15.75 psi abs come from? I thought the pressure of the 102C dry steam (assumed) was 1 atmos.--not 15.75 abs. I think your assumed conditions above 1 atmos. were never measured. Rossi reported the pressure was 0.0 bar, which Murray took to mean mean barG; i.e. 1 atm. Murray and others from I.H. disputed this, saying it had to be more than 1 atm, as described in Exhibit 5. If it was substantially more than 1 atm, the fluid would be liquid, not vapor. See: https://durathermfluids.com/pdf/techpapers/pressure-boiling-point.pdf - Jed
