i used the address 80008000 (-a option in mkimage) for the uImage.i used the same address as the entry address(-e option).
Also can you confirm the points i said in the previous post.That would clarify a lot to me. I believe that the -a option in mkimage is irrelevant.I think the relevent address in the mkimage command is the entry image address(-e option).This address is used by u-boot to copy the compressed uimage(but without the 64k header i.e zImage only).After this the process is the same as zimage as there is no 64k header.Can you also confirm this. about the multi-arch thing I think that the problem with using uImage is that the entry address may not lie in the ram space of all the boards that the kernel can support.Right??? But if this is the case the we will have to change the bootenv of u-boot as we need to load the compressed zimage/uimage somewhere in the ram first.Am I correct? -- For more options, visit http://beagleboard.org/discuss --- You received this message because you are subscribed to the Google Groups "BeagleBoard" group. To unsubscribe from this group and stop receiving emails from it, send an email to beagleboard+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
