. It is starting to make sense. I see the correlation between the manual example and the code you show. Surprisingly (and equally confusing) the book I have also uses a while loop with mysql_fetch_array to display a list.
The &getimg variable comes in from the javasript function on the other page embedded in the url: window.open('../../assets/img760/img.php?getimg=alfstag1') the variable content is the field (imgname) that I use to find the record. I have been passing all of the variables manually via the url but it would be best if I used a database as there are around 400 to show and changes in a db are easier than in the html head. This may be the problem as I now get "supplied argument not valid mysql result" on this line. $query = "select imglocation,height,width from img where imgname='$getimg'"; Thank you for taking the time with me on this. I will see if I can find the remaining problems and get to coding the 400+ pages that I need to get this into. It looks like I might be able to use the GetImageSize function to do this same thing? maybe? All I am doing is getting the location (url) of an image and its height and width for an <img src= > statement..... maybe I am making this into a bigger job than necessary?? I think I have been working on it too long today and I need a long walk..... Anyway, thank you again for taking the time and for the book recommendation. Mike "Kurt Lieber" <[EMAIL PROTECTED]> wrote in message E15yfMr-0003fP-00@z8">news:E15yfMr-0003fP-00@z8... > On Tuesday 30 October 2001 11:58 am, turtle wrote: > > No reading that section of the manual did me no good. I do not understand > > other than I cannot store the results as a variable. > > yes, you can. > > > > Is there any of what I have done that is usable? > > yes, there is. see below. It's probably not solid enough to cut 'n' paste, > but it at least shows you how to get return results from mysql. > > > A recommendation for a book that covers this would be helpful... the > > manual on this area is way to abbreviated for someone who has only used PHP > > for 2 weeks. > > "Beginning PHP4" by Wrox > > > > <? > $link = mysql_connect('localhost')or die ("Could not connect"); > mysql_select_db('img760')or die ("Could not select database"); > $query = "select imglocation,height,width from img where > imgname=$getimg"; //****you haven't defined $getimg anywhere that I can see > // also need to enclose it in quotes: '$getimg' > $results = mysql_fetch_array($query); //new line > $imglocation = $reults['imglocation']; > $height = $results['height']; > $width = $results['width']; > ?> -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]