Re: [PHP-DB] I'm completely lost here
David, The database gets updated with a record, but all the fields end up being empty in the db. Can anyone see what's out of whack here? I'd appreciate the help. http://pastebin.com/y8kcymnN There isn't much context to your request and I don't see how your table is defined. How are you assigning the values to the variables that you are trying to insert into the database? Do you have register_globals enabled? -- Gary -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] I'm completely lost here
David, Just did that like Richard had suggested also and I do get the expected results. I suspect I need to put the same thing in my query correct? like this: mysql_query (INSERT INTO inventory(image, year, make, model, milage, price)VALUES($_POST['image'], $_POST['year'], $_POST['make'], $_POST['model'], $_POST['milage'] , $_POST['price'])); I might be stating the obvious here, but you should really validate your input. If this is just an exercise or a simple test, that will work. If it's an application that, especially, is accessible on the internet, you definitely need to validate and ensure that you're receiving sane input. -- Gary -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Pg Transactional Function
All,
I've written a procedural function to [hopefully] create less cluttered code
when working with PostgreSQL transactions and I am soliciting criticism and
suggestions on how to make it better (or to scrap it).
function db_exec_transaction($dbh, $query_and_params, $results_array,
$error_str)
{
if (!is_array($query_and_params))
die('Queries and parameters variable must be an array type');
pg_query($dbh, 'begin');
foreach ($query_and_params as $i = $qp)
{
if (empty($qp['params']))
$stmt = pg_query($dbh, $qp['query']);
else
$stmt = pg_query_params($dbh, $qp['query'], $qp['params']);
if ($stmt === false)
{
$error_str = pg_last_error($dbh);
pg_query($dbh, 'rollback');
return false;
}
else
$results_array[] = $stmt;
}
pg_query($dbh, 'commit');
$error_str = null;
return true;
}
A lame and mostly useless example of how I intend to call it is as follows:
function foo_bar_handler($dbh)
{
$query_resources = array();
$queries = array();
$queries[] = array('query' = 'select * from foo for update',
'params' = array());
$queries[] = array('query' = 'delete from foo',
'params' = array());
$queries[] = array('query' = 'select * from bar where fizz = $1 and buzz =
$2',
'params' = array(42, 15));
$stmt = db_exec_transaction($dbh, $queries, $query_resources, $error_str);
if ($stmt === false)
{
echo $error_str . \n;
return false;
}
/* Fetch and do something with the results */
$rows = pg_fetch_all($query_resources[0]);
echo 'Rows retrieved: ' . pg_num_rows($query_resources[0]) . \n;
$the_answers = pg_fetch_all($query_resources[2]);
/* Release the resources */
pg_free_result($query_resources[0]);
pg_free_result($query_resources[1]);
pg_free_result($query_resources[2]);
return true;
}
Any comments, criticisms, or suggestions are very much appreciated.
Thank you,
Gary Chambers
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[PHP-DB] UPDATE IF
I have a table in a mysql db that has 3 columns that I want to insert (update) data if the rowcolumn is empty (IS NULL). However I want to start at the first column, if this column is not null, then move to insert the data into column 2, if that is empty, then insert data into column 3. I have been looking over the manual and boards but am not finding a solution. Can anyone point me in the right direction. -- Gary __ Information from ESET Smart Security, version of virus signature database 5952 (20110314) __ The message was checked by ESET Smart Security. http://www.eset.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Cant Get Data
I have a 3 step form that calls the data from a mysql DB. First is a
dropdown to select a state, which then brings up a dynamically created check
list of the counties in that state, so far all works well. I am unable to
get the checkbox choices to appear on the third page.
If someone could take a look at this and tell me where I am going wrong.
This is the code for the page that creates the checkboxes. There are some
extra lines in there where I was trying to get it to work. Again this works
fine, but my guess is that see this may shed light.
?php
$county1=$_SESSION['county$i'];
$counties=$_SESSION['counties'];
$row_name=$_SESSION['name'] = $row[name];
$count_choice=$_SESSION['name'];
$result1=$_SESSION['$result'];
$choice=$_POST['state'];
if ( isset($_POST['submit']) ) { // if form is submitted, process it
for($i=1; $i=$_POST['counties']; $i++) {
if ( isset($_POST[county$i] ) ) {
print $_POST[county$i]. is checked.br/;
}
}
} else { // if form isn't submitted, output the form
$county_choice=$_SESSION['county$1'];
print form action=\phpForm3.php\ method=\POST\\n;
/*$link = mysql_connect(, , );
mysql_select_db();*/
$result = mysql_query(SELECT * FROM `counties` WHERE state_id = '$choice')
or die(mysql_error());
if ($result) {
print table width=200 border=1\n;
print thnbsp; /th\n;
print th State /th\n; //2 fields in Counties table, State and County
print th County /th\n;
print /tr\n;
//create table
$i = 0;
while ( $row = mysql_fetch_array($result) ) {
$i++;
print tr\n;
print tdinput type=\checkbox\ name=\county$i\
value=\$row[name]\/td\n;
echo td{$row['state_id']}/td\n;
echo td{$row['name']}/td\n;
echo /tr\n;
}//end while
print /table\n;
} else {
echo(PError performing query: .
mysql_error() . /P);
}
print input type=\hidden\ name=\counties\ value=\$i\/\n;
print input type=\submit\ name=\submit\ value=\Go\/\n;
}
This is the page that I am unable to get to call the checkbox selections
?php
$count_choice1=$_SESSION['county$i'];
$count_choice2=$POST['counties'];
$count_choice3=$_POST['name'];
$result1=$_SESSION['$result'];
/*$count_choice=$_SESSION['name']; */
$count_choice=$_POST['county$i'];
$choice=$_SESSION['name'];
$_POST[county$i];
$result = mysql_query(SELECT * FROM `counties` WHERE name = '$choice') or
die(mysql_error());
/*$query = mysql_query(SELECT * FROM counties );
$result = mysql_query($query) or die (Error in query: $query.
.mysql_error());;
echo $row['name'];
echo $query;*/
while($row = mysql_fetch_array($result))
{
echo $row['name'];
/*{$row['name']}br ;*/
}
echo $choice;
/*echo $_SESSION['county$i'];
echo $_SESSION['counties'];
echo $_SESSION['name'];
echo $count_choice;
echo $row['name'];
echo $county$1;
echo $counties;
echo $row_name; */
?
--
Any Suggestions?
Thank you.
Gary
__ Information from ESET Smart Security, version of virus signature
database 5893 (20110221) __
The message was checked by ESET Smart Security.
http://www.eset.com
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[PHP-DB] Any good explanations of pg_send_execute and friends?
Has anyone found anything in their travels around the web?
The manual is okay, but the examples are so simplistic it's difficult
to understand how it should really be used. For example, if I have a
loop of pg_send_execute based INSERT statements inside a transaction*,
and one of them fails, how and when do I check for that (given that
the pg_send_execute is asynchronous)?
* That is:
BEGIN
for (...)
{
pg_send_execute(...);
}
COMMIT
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[PHP-DB] PDOException: could not find driver (postgres)
What could be causing this please? Going direct, using pg_connect, is
not a problem.
The code in question looks like
$pdo = new PDO('pgsql:host=localhost;port=5432;dbname=mydb', 'dbuser',
'dbpass');
(I think - I've yet to be able to debug it down to a single line)
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Re: [PHP-DB] PDOException: could not find driver (postgres)
On 4/22/10, Niel Archer wrote: What could be causing this please? Going direct, using pg_connect, is not a problem. Make sure you have the PDO postgres driver enabled in your php.ini, it does not use the same driver as the Postgres extension. Aha! Okay, thanks! It's working now... -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Postgres - how to skip 'sequence' columns
On 4/13/10, Chris wrote: Gary . wrote: Is it possible to skip column(s) in the target table when using pg_copy_from? ... It seems not from looking at the php manual. You could use http://www.php.net/manual/en/function.pg-put-line.php instead. Yeah. I was hoping to use pg_copy_from to avoid looping over the array in php, but I can do that. Thanks. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Fatal error: Call to undefined function pq_query()
What the... What is causing this? I can use pg_connect without complaint, why does pq_query give this problem? PHP 5.3.1 FWIW. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Fatal error: Call to undefined function pq_query()
On Tue, Apr 13, 2010 at 10:40 AM, Firan Corneliu wrote: Are you sure you're not using q instead of g :) Err. My first thought was What a strange thing to ask. Then I looked... Thanks. I'd been looking at that for a good hour or so... *embarrassed* -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Postgres - how to skip 'sequence' columns
Is it possible to skip column(s) in the target table when using
pg_copy_from? When I tried to bulk insert some data from a csv
file by way of pg_copy_from I received the error Warning:
pg_copy_from() [function.pg-copy-from]: Copy command failed:
ERROR: permission denied for relation xyz, pretty much as I
expected since things look like:
CREATE SEQUENCE xyz;
CREATE TABLE some_table (
id int NOT NULL PRIMARY KEY DEFAULT nextval('xyz')
...
(i.e. the first column is automatically populated by the db itself).
The csv file contains only data for the second and subsequent
columns, so anyway needs to hop right one column.
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[PHP-DB] Injection Attack?
I have a DB on a site that is not really up anymore (a redirect because of a merger), and it seems to have been attacked. I always use REMOTE_IP so that I have a record and able to ban IP's of the endless form spammers, however on this attack, the IP listed is my local IP (actually my old one since I changed ISP's). I was wondering how they did this and how do I protect on other DB's. Some of the other injected text inot almost every field is. 1 AND USER_NAME() = \'; DESC users; -- 1\' OR \'1\'=\'1 There is plenty more, however they submitted the form about 12 times per second. Any thoughts? Gary __ Information from ESET Smart Security, version of virus signature database 4895 (20100225) __ The message was checked by ESET Smart Security. http://www.eset.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] PHP- Mysql problem
Daniel, Now that is just funny stuff... Have you tried http://lmgtfy.com/?q=access+denied+for+user+odbc+localhost or the newer http://www.lmbify.com/search.php?s=access+denied+for+user+odbc+localhost Daniel Brown danbr...@php.net wrote in message news:ab5568160906180636r239f214eh7e4871da7139c...@mail.gmail.com... On Thu, Jun 18, 2009 at 06:03, NADARAJAH SIVASUTHAN NADARAJAHnsivasut...@live.com wrote: Warning: mysql_query() [function.mysql-query]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\wamp\www\ap_v5\inc\profile.inc.php on line 285 http://google.com/search?q=Access%20denied%20for%20user%20'ODBC'@'localhost'%20(using%20password:%20NO) http://fart.ly/dm6m7 -- /Daniel P. Brown daniel.br...@parasane.net || danbr...@php.net http://www.parasane.net/ || http://www.pilotpig.net/ 50% Off All Shared Hosting Plans at PilotPig: Use Coupon DOW1 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] change coldfusion to mysql/php
Hi, I don't know of a tool, although there may be one. If the pages are really simple I would think that it wouldn't be that hard to redo them by hand. Gary -Original Message- From: Koller Michel [mailto:[EMAIL PROTECTED] Sent: Thu, May 08, 2008 7:26 AM To: php-db@lists.php.net Subject: [PHP-DB] change coldfusion to mysql/php Hello I have 3 simple Homepages, all makes with coldfusion. Now i must all tre Homepages change from coldfusion to PHP/MySQL. My question is, sombody know a tool thats can help me this to realisize? (sorry for my bad english) Thanks M.K. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Parse error: syntax error, unexpected T_ELSE
Hi,
I suggest you echo $del_str to see exactly what your query is.
There may be something unexpected in $_GET['Id'].
Echo the whole query so you can see everything in context.
Gary
-Original Message-
From: Javier Viegas [mailto:[EMAIL PROTECTED]
Sent: Tue, April 15, 2008 5:56 PM
To: php-db@lists.php.net
Subject: Re: [PHP-DB] Parse error: syntax error, unexpected T_ELSE
Thanks Daniel i ´ve removed the unexpected else secction. Now
it works but
it tells me that there might be a syntax error on the query,
this is good
news because now i know i´m having connection with the
database but also
there must be something wrong with the query.
$del_str = DELETE FROM libros WHERE bnumero=.$_GET['Id'];
Is this correct, i´ve checked and the correct syntax to use
would be delete
from libros where bnumero='something';
Given 'something' is taken from a variable called Id it seems
reasonable to
me the way it is written. Do you see anything wrong?
Thanks again.
On Tue, Apr 15, 2008 at 6:03 PM, Daniel Brown
[EMAIL PROTECTED] wrote:
On Tue, Apr 15, 2008 at 4:49 PM, Javier Viegas
[EMAIL PROTECTED]
wrote:
Hi, i have this script wich basically connects to a
database and delete
a
record according to the Id parameter given. The problem
is that when i
test
it i get this error:
*Parse error*: syntax error, unexpected T_ELSE in *
/var/www/biblio/scripts/delete.php* on line *31
Javier,
This block:
} else {
$r_string = 'errorcode=4';
}
is incorrect. You call an else condition on line
21, so PHP
expects that block to be the last for that if() condition. Either
remove the } else { and $r_string = 'errorcode=4'; lines
or rewrite
the condition.
And if that's your real database login information, change it and
update all of your scripts and systems ASAP.
This is the script:
*?php
/*
deletescore.php: deletes record for passed id from
highscores table
and
returns status to Flash
*/
// fill with correct data for your server configuration
$server = localhost;
$username = root;
$password = itsveryeasy;
$database = biblioteca;
//connect to database added by calm
mysql_connect($server, $username, $password);
if (!mysql_connect($server, $username, $password)) {
$r_string = 'errorcode=1';
} elseif (!mysql_select_db($database)) {
$r_string = 'errorcode=2';
} else {
$del_str = DELETE FROM libros WHERE bnumero=.$_GET['Id'];
if (!mysql_query ($del_str)) {
$msg = mysql_error();
$r_string = 'errorcode=3msg='.$msg;
} else {
$r_string = 'errorcode=0';
}
} else {
$r_string = 'errorcode=4';
}
echo $r_string;
?
Wha am i doing wrong??
Thanks.
Javier
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Re: [PHP-DB] webserver script to localhost MySQL?
thanks. I removed the additional ' at the end
and get this error (adding the echo as suggested)
http://testgbalkam.ipower.com/baddblog/
99.252.22.106
Warning: Cannot modify header information - headers already sent by (output
started at
/hermes/bosweb/web250/b2508/ipw.testgbalkam/public_html/baddblog/wp-config.php:11)
in
/hermes/bosweb/web250/b2508/ipw.testgbalkam/public_html/baddblog/wp-includes/functions.php
on line 1438
Error establishing a database connection
- Original Message -
From: Gary Wardell [EMAIL PROTECTED]
To: 'gary balkam' [EMAIL PROTECTED]
Sent: Saturday, March 22, 2008 4:57 AM
Subject: RE: [PHP-DB] webserver script to localhost MySQL?
Hi,
Usually the line number give is very accurate.
define('DB_HOST', '99.252.22.106:/tmp/mysql.sock'');//
Looks to me like the quote marks aren't matched.
Also, it may be that after you fix the quotes you will get another error.
I suggest displaying DB_HOST:
echo(DB_HOST);
So you can verify that the ip address and port are picked up correctly.
Gary
-Original Message-
From: gary balkam [mailto:[EMAIL PROTECTED]
Sent: Fri, March 21, 2008 10:15 PM
To: Subject: [PHP-DB] webserver script to localhost MySQL?
I'm pretty new to php and mysql. And I just found this news
group about 4
minutes ago.
What I need to know, is how do I connect a wordpress
application, located on
a web server to a database located on my own computer. The
reason for doing
this instead of syncing the dbs is the Sql server on the web
host is shared
and SLOW. Mine only runs 1 maybe 2 databases. wordpress and
maybe gallery
(maybe a forum later)
How can i do this?
URL is http://www.baddblog.info changed this to
http://testgbalkam.ipower.com/baddblog/
here is the wp_config.php
?php
// ** MySQL settings ** //
define('DB_NAME', 'junior');// The name of the database
define('DB_USER', 'gbalkam'); // Your MySQL username
define('DB_PASSWORD', ''); // ...and password
define('DB_HOST', '99.252.22.106:/tmp/mysql.sock'');//
99% chance you
won't need to change this value define('DB_CHARSET', 'utf8');
define('DB_COLLATE', '');
// You can have multiple installations in one database if you
give each a
unique prefix
$table_prefix = 'wp_'; // Only numbers, letters, and
underscores please!
// Change this to localize WordPress. A corresponding MO file for the
// chosen language must be installed to wp-content/languages.
// For example, install de.mo to wp-content/languages and set
WPLANG to 'de'
// to enable German language support.
define ('WPLANG', '');
/* That's all, stop editing! Happy blogging. */
define('ABSPATH', dirname(__FILE__).'/');
require_once(ABSPATH.'wp-settings.php');
?
This script as above generates this error:
Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING in
/home/content/g/b/a/gbalkam/html/wp-config.php on line 6
PHP on LOCALHOST
Apache Version Apache/2.2.8 (Win32) DAV/2 mod_ssl/2.2.8
OpenSSL/0.9.8g
mod_autoindex_color PHP/5.2.5
PHP on WEBSERVER
Activate/Deactivate Languages
PHP Version PHP 5.x
The wordpress works on localhost under apache.
Any ideas why this isnt working?
Thanks in advance
php noobie
GBalkam
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RE: [PHP-DB] webserver script to localhost MySQL?
Hi,
Ok, the warning is a warning and can safely be ignored since this debugging
code.
It looks like your constant doesn't have a port number so questiuons you need
to find out about:
Is it trying to connect on the proper port by default? (My guess is no)
Or does the define need to be changed to set the proper port number? (My guess
is probably)
Or is the host you're trying to connect to unreachable?
Or is the port being blocked by a firewall?
Once you get the connection working you can remove the echo.
Gary
-Original Message-
From: gary balkam [mailto:[EMAIL PROTECTED]
Sent: Sat, March 22, 2008 4:53 AM
To: Gary Wardell; php-db@lists.php.net
Subject: Re: [PHP-DB] webserver script to localhost MySQL?
thanks. I removed the additional ' at the end
and get this error (adding the echo as suggested)
http://testgbalkam.ipower.com/baddblog/
99.252.22.106
Warning: Cannot modify header information - headers already
sent by (output
started at
/hermes/bosweb/web250/b2508/ipw.testgbalkam/public_html/baddbl
og/wp-config.php:11)
in
/hermes/bosweb/web250/b2508/ipw.testgbalkam/public_html/baddbl
og/wp-includes/functions.php
on line 1438
Error establishing a database connection
- Original Message -
From: Gary Wardell [EMAIL PROTECTED]
To: 'gary balkam' [EMAIL PROTECTED]
Sent: Saturday, March 22, 2008 4:57 AM
Subject: RE: [PHP-DB] webserver script to localhost MySQL?
Hi,
Usually the line number give is very accurate.
define('DB_HOST', '99.252.22.106:/tmp/mysql.sock'');//
Looks to me like the quote marks aren't matched.
Also, it may be that after you fix the quotes you will get
another error.
I suggest displaying DB_HOST:
echo(DB_HOST);
So you can verify that the ip address and port are picked
up correctly.
Gary
-Original Message-
From: gary balkam [mailto:[EMAIL PROTECTED]
Sent: Fri, March 21, 2008 10:15 PM
To: Subject: [PHP-DB] webserver script to localhost MySQL?
I'm pretty new to php and mysql. And I just found this news
group about 4
minutes ago.
What I need to know, is how do I connect a wordpress
application, located on
a web server to a database located on my own computer. The
reason for doing
this instead of syncing the dbs is the Sql server on the web
host is shared
and SLOW. Mine only runs 1 maybe 2 databases. wordpress and
maybe gallery
(maybe a forum later)
How can i do this?
URL is http://www.baddblog.info changed this to
http://testgbalkam.ipower.com/baddblog/
here is the wp_config.php
?php
// ** MySQL settings ** //
define('DB_NAME', 'junior');// The name of the database
define('DB_USER', 'gbalkam'); // Your MySQL username
define('DB_PASSWORD', ''); // ...and password
define('DB_HOST', '99.252.22.106:/tmp/mysql.sock'');//
99% chance you
won't need to change this value define('DB_CHARSET', 'utf8');
define('DB_COLLATE', '');
// You can have multiple installations in one database if you
give each a
unique prefix
$table_prefix = 'wp_'; // Only numbers, letters, and
underscores please!
// Change this to localize WordPress. A corresponding MO
file for the
// chosen language must be installed to wp-content/languages.
// For example, install de.mo to wp-content/languages and set
WPLANG to 'de'
// to enable German language support.
define ('WPLANG', '');
/* That's all, stop editing! Happy blogging. */
define('ABSPATH', dirname(__FILE__).'/');
require_once(ABSPATH.'wp-settings.php');
?
This script as above generates this error:
Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING in
/home/content/g/b/a/gbalkam/html/wp-config.php on line 6
PHP on LOCALHOST
Apache Version Apache/2.2.8 (Win32) DAV/2 mod_ssl/2.2.8
OpenSSL/0.9.8g
mod_autoindex_color PHP/5.2.5
PHP on WEBSERVER
Activate/Deactivate Languages
PHP Version PHP 5.x
The wordpress works on localhost under apache.
Any ideas why this isnt working?
Thanks in advance
php noobie
GBalkam
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[PHP-DB] webserver script to localhost MySQL?
I'm pretty new to php and mysql. And I just found this news group about 4
minutes ago.
What I need to know, is how do I connect a wordpress application, located on
a web server to a database located on my own computer. The reason for doing
this instead of syncing the dbs is the Sql server on the web host is shared
and SLOW. Mine only runs 1 maybe 2 databases. wordpress and maybe gallery
(maybe a forum later)
How can i do this?
URL is http://www.baddblog.info
here is the wp_config.php
?php
// ** MySQL settings ** //
define('DB_NAME', 'junior');// The name of the database
define('DB_USER', 'gbalkam'); // Your MySQL username
define('DB_PASSWORD', ''); // ...and password
define('DB_HOST', '99.252.22.106:/tmp/mysql.sock'');// 99% chance you
won't need to change this value define('DB_CHARSET', 'utf8');
define('DB_COLLATE', '');
// You can have multiple installations in one database if you give each a
unique prefix
$table_prefix = 'wp_'; // Only numbers, letters, and underscores please!
// Change this to localize WordPress. A corresponding MO file for the
// chosen language must be installed to wp-content/languages.
// For example, install de.mo to wp-content/languages and set WPLANG to 'de'
// to enable German language support.
define ('WPLANG', '');
/* That's all, stop editing! Happy blogging. */
define('ABSPATH', dirname(__FILE__).'/');
require_once(ABSPATH.'wp-settings.php');
?
This script as above generates this error:
Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING in
/home/content/g/b/a/gbalkam/html/wp-config.php on line 6
PHP on LOCALHOST
Apache Version Apache/2.2.8 (Win32) DAV/2 mod_ssl/2.2.8 OpenSSL/0.9.8g
mod_autoindex_color PHP/5.2.5
PHP on WEBSERVER
Activate/Deactivate Languages
PHP Version PHP 5.x
The wordpress works on localhost under apache.
Any ideas why this isnt working?
Thanks in advance
php noobie
GBalkam
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end
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RE: [PHP-DB] Help with JOIN query
Hi, The way I think I'd approach it is to use an outer join where table a is joined to a subquery where the subquery returns only the max timestamp from table b. Gary -Original Message- From: Graham Cossey [mailto:[EMAIL PROTECTED] Sent: Thu, March 06, 2008 5:17 PM To: J. Hill; php-db@lists.php.net Subject: Re: [PHP-DB] Help with JOIN query On Thu, Mar 6, 2008 at 9:54 PM, J. Hill [EMAIL PROTECTED] wrote: I may be a little confused: the desire is to return all the rows from TableA that match the record_id of a row in TableB that has the MAX timestamp? If so, why not something like: SELECT * FROM TableA a, TableB b WHERE a.record_id=b.record_id timestamp=(SELECT MAX(timestamp) FROM TableB) ORDER BY action; I'm guessing I'm confused, that it's something more complicated you're looking for. Thanks Krister and all for your help thus far. Jeff, I'm after all rows from TableA then the latest action from TableB for each selected record in TableA. I'm starting to think maybe I should build an array of results using 2 queries then sort the array using PHP functionality, but I'd rather do it in MySQL if it's possible. Graham -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Help with JOIN query
Ahh, to bad, I started using it with 5.0. I'm also a long time user of SQL Server. Sorry if I caused confusion. Gary -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Help with JOIN query
I know the feeling. I've been trying to hookup MYSQL as a linked server on MS SQL Server. There are a few articles out there that make mention of it but no where does anybody say exactly how to do it. Gary -Original Message- From: Graham Cossey [mailto:[EMAIL PROTECTED] Sent: Thu, March 06, 2008 6:33 PM To: Gary Wardell; php-db@lists.php.net Subject: Re: [PHP-DB] Help with JOIN query On Thu, Mar 6, 2008 at 10:59 PM, Gary Wardell [EMAIL PROTECTED] wrote: Ahh, to bad, I started using it with 5.0. I'm also a long time user of SQL Server. Sorry if I caused confusion. Gary You were getting my hopes up there Gary :-( -- Graham -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] independent session data for multiple browser windows
They'll be accessing different account records in different windows. I keep track of the current account id in the session data, as well as a number of other account-specific items. Once I was made aware of the multiple-window requirement, and started looking more closely at sessions, it seemed (from the PHP documentation) that I could start a new session, with a different name and id, and that would take care of it. In fact I CAN start sessions with independent names and ids, but their DATA doesn't seem to be completely independent. Assuming that they are interacting through forms on the pages in the different windows, why not put the UID of the record they are accessing in a hidden field in the form? Gary -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Password decryption
Hi,
Note from the manual:
PASSWORD() encryption is one-way (not reversible).
Also note:
===
Note
The PASSWORD() function is used by the authentication system in
MySQL Server; you should not use it in your own applications.
For that purpose, consider MD5() or SHA1() instead. Also see RFC 2195, section
2 (Challenge-Response Authentication Mechanism
(CRAM)), for more information about handling passwords and authentication
securely in your applications.
===
The way to do it is to encrypt the response password from the logon and compare
the encrypted versions; rather than decrypting for
the compare.
Gary
-Original Message-
From: Nasreen Laghari [mailto:[EMAIL PROTECTED]
Sent: Sat, February 16, 2008 10:18 PM
To: php-db@lists.php.net
Subject: [PHP-DB] Password decryption
Hi,
I'm junior in PHP and stuck on Encryption.
I have encrypted password using SQL :
$query = insert into user (userid,password,) values
('$username',Password('$pass'));;
Which is working perfect. Now I'm working on Login page where
I have to compare passwords.. As password in database is
encrypted so I need to decrypt it back for compression. I
have tried the flowing but not working.
if ($pwd != Password($info['password']))
{
echo(-);
//header(Location: abuse.php);
}
and
if ($pwd != $info(Password(['password']))
{
echo(-);
//header(Location: abuse.php);
}
Could any one please help..
Thank you
__
__
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know-it-all with Yahoo! Mobile. Try it now.
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RE: [PHP-DB] Importing CSV files to MySql Db issue.
Chris, If you're using spaces for enclosing then I'm sure you're not handling something properly. Chris,Carter,[EMAIL PROTECTED] -- 3 records Chris Carter,[EMAIL PROTECTED] -- 2 records Don't you mean: Chris,Carter,[EMAIL PROTECTED] -- 3 *fields* Chris Carter,[EMAIL PROTECTED] -- 2 *fields* And both only result in one record for each CSV line? Or do PHP and MySql handle CSV files different from most other applications? Gary -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] odbc_connect - urgent
Hi, You didn't mention which OS this is on. If it's Windows, there is another factor. The timeout in ODBC and OLEDB refer to the time the server on the other end takes to complete the operation. This is independent of the timeout set at the socket layer. So, you could set the ODBC timeout to 10 seconds, but that doesn't change the socket timeout. It will still wait for the 30 or 60 seconds, or whatever it is, before abandoning the socket. This is a Windows thing and has to do with the way they implemented sockets. Gary -Original Message- From: iODBC Maintainer [mailto:[EMAIL PROTECTED] Sent: Thu, January 10, 2008 4:09 PM To: Gustavo Ramalho Cc: php-db@lists.php.net Subject: Re: [PHP-DB] odbc_connect - urgent HI Gustavo, Hi, im in serious problems. First sorry for bad english. Im try to connect with many servers to take some information, but when one of those is offline my script in php is fails and not proced. Did have any way to configure te odbc_connect timeout?? its take to many time to resolve take site is off or online. Im try to ping the server but sometimes the server of internet is not same the sql server. Unfortunately you cannot set the login timeout using the odbc_setoption like: odbc_setoption ($conn, 1, 103 /*SQL_LOGIN_TIMEOUT*/, 30) since the current php odbc layer cannot handle setting connection parameters before making an actual connection. However most ODBC drivers do have some capabilities to adjust timeouts. Which driver are you using to connect to sql server? Patrick -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] align
Or even if it's not in a table, put a div around it and use: style= text-align: right or equivalent css Of course this assumes he's using html to display it. Gary -Original Message- From: Bastien Koert [mailto:[EMAIL PROTECTED] Sent: Tue, January 01, 2008 11:21 AM To: arafat uddin; php-db Subject: RE: [PHP-DB] align assuming that the data sits in a table, right align the cell or use a css class to do the same thing bastien Date: Tue, 1 Jan 2008 14:56:34 +0600 From: [EMAIL PROTECTED] To: php-db@lists.php.net Subject: [PHP-DB] align hi, i hav fall in a problem my problem is in the table digit shows like below 12,000.00 6,000.00 3,000.00 1,00.00 but i have to align from right like 12,000 .00 6,000 .00 3,000 .00 1,00 .00 how it possible? _ Read what Santa`s been up to! For all the latest, visit asksantaclaus.spaces.live.com! http://asksantaclaus.spaces.live.com/ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Credit Card Encryption
Hmm, This is kind of throwing a new twist on things. When it comes to liability, who is liable, the merchant running the system, the develper that created the system, or both? If the develper is included, would that be mitigated in that he created the system to the merchant's specifications? Also, in terms of the developer, would this be covered under errors and omissions insurance, or would they take the position that the developer should have known better and was negligent in creating a non-compliant system leaving the developer on the hook for damages? Gary -Original Message- From: Bastien Koert [mailto:[EMAIL PROTECTED] Sent: Wed, December 19, 2007 11:02 PM To: Daniel Brown Cc: Keith Spiller; php-db@lists.php.net Subject: RE: [PHP-DB] Credit Card Encryption Dan, Normally I would completely agree, its our job to find those solutions. Unfortunately, the sector that my FT job deals with is retail and many of our clients are in this bind with PCI data. Hefty fines are charged to those not in compliance. The major CC companies are taking this so seriously and the ramifications are being felt in many IT shops. Compliance failure can lead to loss o privileges to accept CCs. Its gonna force us to be more creative in how we handle the data and create the applications that allow our clients to offer ecommerce, we will have to learn some business skills to make this happen. It may mean that its becomes more contractual in dealing with third parties, where the ecommece shop effects payment on behalf of the vendors. The OP may need to help his client work out a better way to manage the transactions between the related parties by finding ways to automate the various transactions and provide gateway access... I, too, like to eat... ;-P bastien Date: Wed, 19 Dec 2007 17:21:57 -0500 From: [EMAIL PROTECTED] To: [EMAIL PROTECTED] Subject: Re: [PHP-DB] Credit Card Encryption CC: [EMAIL PROTECTED]; php-db@lists.php.net On Dec 19, 2007 4:45 PM, Bastien Koert [EMAIL PROTECTED] wrote: Nope, I still would not recommmend it. The only place the CC data should travel to is the payment gateway. Anything else is a security risk. Why does your client process by hand? They should be using a payment gateway. That's true, Bastien, but if for whatever reason it's not an option for them, what? Tell them it's tough cookies and they're SOL? Our job as programmers - especially freelance - is to make things happen as safely and securely as we can, but as a bottom line, make it happen. I'm sure we (most of us) take the responsibility to discourage a client from making such choices, and to educate them on alternatives that are better for their interests, but still - at the end of the day, we're still just code monkeys. We're expected to build what the client needs, or else they'll find someone else to do it for them. And I don't really like to go hungry. ;-) -- Daniel P. Brown [Phone Numbers Go Here!] [They're Hidden From View!] If at first you don't succeed, stick to what you know best so that you can make enough money to pay someone else to do it for you. _ Exercise your brain! Try Flexicon! http://puzzles.sympatico.msn.ca/chicktionary/index.html?icid=htmlsig -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Credit Card Encryption
And if you do store it, don't store it on the websderver. Make sure it's on another server behind another firewall. You don't want someone that hacks into your web server to have ready access to your database. I think AES is supposed to be the best, then 3DES is next. (That's 3DES, or triple DES, not DES) But like Chris said: if you don't have to, dont do it. But if you must, encrypt all of the personal information data points, not just the CC info. Gary -Original Message- From: Chris [mailto:[EMAIL PROTECTED] Sent: Tue, December 18, 2007 9:30 PM To: Keith Spiller Cc: php-db@lists.php.net Subject: Re: [PHP-DB] Credit Card Encryption Keith Spiller wrote: Hi Everyone, I'm trying to determine the best method to store credit card numbers in a mysql database. As yet I have been unable to determine whether I should use MySQL AES, DES or a PHP encryption method. I would greatly appreciate any advice you guys could offer. Why do you need to store c/c info? If at all possible, don't. If you're looking for something like recurring payments, use paypal or one of the other payment providers that support it. -- Postgresql php tutorials http://www.designmagick.com/ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] UPDATE syntax
Hi, I'm a beginner at PHP and MySql but a long time MS SQL server user. Maybe it should be `advertisements`.`displayed` instead? I just did a test and my Query browser doesn't like `interestcodes.id` but likes `interestcodes`.`id`. Notice the quotes (accents) on each side to the period. Gary -Original Message- From: Ron Piggott [mailto:[EMAIL PROTECTED] Sent: Thu, December 13, 2007 7:20 PM To: php-db@lists.php.net Subject: [PHP-DB] UPDATE syntax Can anyone see something wrong with this syntax? UPDATE `advertisements` INNER JOIN `advertisements_rate_plans` ON `advertisements.rate_plan` = `advertisements_rate_plans.reference` SET `advertisements.displayed` = 0 WHERE `advertisements.start_date` = '2007-12-13' AND `advertisements.end_date` = '2007-12-13' AND `advertisements.approved` =1 AND `advertisements.paid` =1 AND `advertisements.displayed` =1 AND `advertisements_rate_plans.type` =2 I am getting this error message: #1054 - Unknown column 'advertisements.displayed' in 'field list' There is a column called displayed in table advertisements. I am on the http://dev.mysql.com/doc/refman/5.0/en/update.html page and I am missing something. Ron -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Form mail() problem
Hi,
This is an SMTP error, not a PHP error. Since you imply the PHP code hasn't
changed then something else must have changed.
First verify that the to address, [EMAIL PROTECTED] is still good buy sending
and e-mail to it.
If that checks out OK, than check with the mail server administrator. He may
have tightened the SPAM controls by requiring SMTP
clients, like PHP, to authenticate before sending mail that relays. Or perhaps
the authentication credentials in place may have
changed. Also, some mail server will allow relaying based on IP address. If
the mail server does that perhaps the IP address of
the web server has changed. Either way, whatever authentication is used may
need to be looked at and corrected.
I can't think of anything else that might be the problem.
Gary
-Original Message-
From: Tim Daff [mailto:[EMAIL PROTECTED]
Sent: Mon, December 10, 2007 1:05 AM
To: php-db@lists.php.net
Subject: [PHP-DB] Form mail() problem
I am just beginning with php, my first effort was a quote
detail form
that collects the user inputted data and makes and email out of it,
which sends to my boss. It worked fine for about 3 months
now all of
a sudden it has stopped, and made my boss angry.
Any help I could get with this would be greatly appreciated.
Here is the error code I am getting:
Warning: mail() [function.mail]: SMTP server response: 550 5.7.1
Unable to relay for [EMAIL PROTECTED] in
C:\Domains\logosunlimited.com.au
\wwwroot\contact\processquote3.php on line 284
Here is the .php code:
?php
$name=$HTTP_POST_VARS['name'];
$email=$HTTP_POST_VARS['email'];
$phone=$HTTP_POST_VARS['phone'];
$catalog=$HTTP_POST_VARS['catalog'];
$notes=$HTTP_POST_VARS['notes'];
$code=$HTTP_POST_VARS['code'];
$qty=$HTTP_POST_VARS['qty'];
$company=$HTTP_POST_VARS['company'];
$postal=$HTTP_POST_VARS['postal'];
$screen=$HTTP_POST_VARS['screen'];
$customdetails=$HTTP_POST_VARS['customdetails'];
$embroidery=$HTTP_POST_VARS['embroidery'];
// multiple recipients
$to .= '[EMAIL PROTECTED]';
// subject
$subject = 'Online Quote';
// message
$message = '
html
head
meta http-equiv=Content-Type content=text/html; charset=UTF-8 /
titleLogos Unlimited | Contact/title
style type=text/css
!--
#tableLayout #tdMain p {
}
#tdFooter {
text-align: center;
font-size: 10px;
vertical-align: middle;
background-color: #FF;
}
.image {
margin-bottom: 0px;
padding-bottom: 5px;
padding-top: 5px;
}
#tdBottom {
text-align: center;
font-size: 10px;
vertical-align: middle;
}
#tdBottom img {
text-align: center;
font-size: 10px;
vertical-align: middle;
padding-top: 2px;
margin-right: 5px;
margin-left: 5px;
width: 168px;
}
.suppliers {
text-align: left;
font-family: Tahoma, Verdana, Arial, Helvetica, sans-serif;
font-size: 10px;
}
h1 {
font-family: Tahoma, Verdana, Arial, Helvetica, sans-serif;
font-size: 14px;
font-style: normal;
border-left-width: 7px;
border-left-style: solid;
border-left-color: #83ABD2;
text-indent: 5px;
font-weight: normal;
margin-left: 20px;
padding-bottom: 0px;
}
#tdMain p {
text-align: left;
padding-left: 30px;
}
#tdSpecials {
}
#tdSpecials a {
border-top-width: 0px;
border-right-width: 0px;
border-bottom-width: 0px;
border-left-width: 0px;
border-top-style: none;
border-right-style: none;
border-bottom-style: none;
border-left-style: none;
}
#tdSpecials img {
border-top-style: none;
border-right-style: none;
border-bottom-style: none;
border-left-style: none;
padding-top: 30px;
}
#tdTest p {
text-align: left;
padding-left: 30px;
}
#tdMain {
font-family: Tahoma, Verdana, Arial, Helvetica, sans-serif;
font-size: 12px;
color: #00;
padding-top: 20px;
padding-right: 25px;
}
#tdTest {
font-family: Tahoma, Verdana, Arial, Helvetica, sans-serif;
font-size: 12px;
color: #00;
padding-top: 20px;
padding-right: 25px;
border-right-style: none;
border-left-style: none;
border-top-style: none;
border-bottom-style: none;
}
#tdNavbar {
text-align: left;
text-indent: 60px;
vertical-align: middle;
font-family: Tahoma, Verdana, Arial, Helvetica, sans-serif;
padding-top: 0px;
}
#tableLayout {
font-family: Tahoma, Verdana, Arial, Helvetica, sans-serif;
border: thin solid #848484;
padding-top: 3px;
background-image: url(http://www.logosunlimited.com.au/images/
chair.gif);
}
#tableHome {
font-family: Tahoma, Verdana, Arial, Helvetica, sans-serif;
padding-top: 3px;
background-image: url(../newstyletest
[PHP-DB] Re: [PHP] RE: the opposite of a join?
I agree with this. Never use a subquery when a join will work. The optimizer with thank you with performance. James Ausmus wrote: On 10/3/07, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote: Hi J, Checkout this, SELECT * FROM tbl_company where id not in (SELECT companyID from tbl_contacts) Brilliant! This is exactly what I was looking for, and is quite logical/readable! Thanks to everyone for the ideas! J No, don't do this! It is a very inefficient way to retrieve the information you are looking for (Use a query analysis tool to check it out yourself, if you want) - if your tables get to any larger size at all, it will start having a noticeable performance impact on your script (not to mention your DB) - let the DB do the hard work and use a LEFT JOIN syntax, the database can optimize that much more efficiently. Only if your DB doesn't support the LEFT JOIN syntax would you want to do the above. -James Regards, Lasitha Alawatta Application Developer Destinations of the World Holding Establishment P O Box: 19950 Dubai, United Arab Emirates ( Ph +971 4 295 8510 (Board) / 1464 (Ext.) 7 Fax +971 4 295 8910 + [EMAIL PROTECTED] -Original Message- From: John Pillion [mailto:[EMAIL PROTECTED] mailto:[EMAIL PROTECTED] On Behalf Of [EMAIL PROTECTED] Sent: Wednesday, October 03, 2007 2:21 PM To: [EMAIL PROTECTED]; php-db@lists.php.net Subject: [PHP-DB] the opposite of a join? I have a company table and a contacts table. In the contacts table, there is a field called companyID which is a link to a row in the company table. What is the easiest way to query the company table for all the company rows whose ID is NOT linked to in the contact table? Basically, the opposite of a join? Thanks J DOTW DISCLAIMER: This e-mail and any attachments are strictly confidential and intended for the addressee only. If you are not the named addressee you must not disclose, copy or take any action in reliance of this transmission and you should notify us as soon as possible. If you have received it in error, please contact the message sender immediately. This e-mail and any attachments are believed to be free from viruses but it is your responsibility to carry out all necessary virus checks and DOTW accepts no liability in connection therewith. This e-mail and all other electronic (including voice) communications from the sender's company are for informational purposes only. No such communication is intended by the sender to constitute either an electronic record or an electronic signature or to constitute any agreement by the sender to conduct a transaction by electronic means. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Arrays from forms....
I have a problem. I have done this before, but can't find the files.
I am using the following function to upload files from a form.
foreach ($_FILES[pictures][error] as $key = $error) {
if ($error == UPLOAD_ERR_OK) {
echo $error_codes[$error];
move_uploaded_file(
$_FILES[pictures][tmp_name][$key],
images/ .$_FILES[pictures][name][$key]
) or die(Problems with upload);
}
}
I also need to insert the filenames of the uploaded files into a database.
There are three fields in my db for these filenames, image1 image2 and
image3.
What would be the best way to get those filenames from the array into the
vars $image1 $image2 and $image3?
the first file in the array should be $image1 and so on.
Thanks in advance.
smime.p7s
Description: S/MIME cryptographic signature
RE: [PHP-DB] Arrays from forms....
Sorry about that, not CC'ing the list...
the values are not always empty, they should always have something in
them...
There should be 3 images uploading. But, I am sure just to make life
interesting,
there will be times when there could be as little as one uploaded.
-Original Message-
From: Chris [mailto:[EMAIL PROTECTED]
Sent: Thursday, November 30, 2006 10:10 PM
To: Gary E. Terry
Cc: PHP DB
Subject: Re: [PHP-DB] Arrays from forms
Gary E. Terry wrote:
I don't know if we are on the same page here... Maybe we are and I am just
an idiot.
The fields in my db are image1 image2 and image3.
There are only three fields in the form that is being passed to the
php script. But, on the form they are named pictures[].
Here is the full php I am using to process the form output:
?php
include db.inc.back.php;
foreach ($_FILES[pictures][error] as $key = $error) {
if ($error == UPLOAD_ERR_OK) {
echo $error_codes[$error];
move_uploaded_file(
$_FILES[pictures][tmp_name][$key],
bikeimages/ .$_FILES[pictures][name][$key]
) or die(Problems with upload);
${image.$key} = $_FILES['pictures']['name'];
}
}
$make = $_POST['make'];
$model = $_POST['model'];
$year = $_POST['year'];
$color = $_POST['color'];
$description = $_POST['description'];
$status = $_POST['status'];
$query = INSERT INTO `inventory` (`make`, `model`, `year`, `color`,
`description`, `image1`, `image2`, `image3`, `status`)
VALUES ('$make', '$model', '$year', '$color', '$description',
'$image1', '$image2', '$image3', '$status');;
$result = mysql_db_query($db, $query) or displayErrorQuery ($query);
echo meta http-equiv='refresh' content='0;URL=inventorylist.php';
?
$image1 $image2 and $image3 are not getting defined... Not real sure
what's
going on.
Always cc the list so others can learn or suggest things.
Are you uploading 3 images? Maybe define them first as well:
foreach ($_FILES .. ) {
${image.$key} = ;
if ($error ==
or do you mean the values are always empty?
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smime.p7s
Description: S/MIME cryptographic signature
RE: [PHP-DB] Arrays from forms....
If I print them, there's nothing. all three
Here is the same file, in test mode...
?php
include db.inc.back.php;
foreach ($_FILES[pictures][error] as $key = $error) {
if ($error == UPLOAD_ERR_OK) {
echo $error_codes[$error];
move_uploaded_file(
$_FILES[pictures][tmp_name][$key],
bikeimages/ .$_FILES[pictures][name][$key]
) or die(Problems with upload);
${image.$key} = $_FILES['pictures']['name'];
}
}
$make = $_POST['make'];
$model = $_POST['model'];
$year = $_POST['year'];
$color = $_POST['color'];
$description = $_POST['description'];
//$image1 = $_POST['image1'];
//$image2 = $_POST['image2'];
//$image3 = $_POST['image3'];
$status = $_POST['status'];
echo $image1 -- $image2 -- $image3;
/*
$query = INSERT INTO `inventory` (`make`, `model`, `year`, `color`,
`description`, `image1`, `image2`, `image3`, `status`)
VALUES ('$make', '$model', '$year', '$color', '$description',
'$image1', '$image2', '$image3', '$status');;
$result = mysql_db_query($db, $query) or displayErrorQuery ($query);
echo meta http-equiv='refresh' content='0;URL=inventorylist.php';
exit;
*/
?
I get -- -- outputted.
-Original Message-
From: Chris [mailto:[EMAIL PROTECTED]
Sent: Thursday, November 30, 2006 10:39 PM
To: Gary E. Terry
Cc: php-db@lists.php.net
Subject: Re: [PHP-DB] Arrays from forms
Gary E. Terry wrote:
Sorry about that, not CC'ing the list...
the values are not always empty, they should always have something in
them...
There should be 3 images uploading. But, I am sure just to make life
interesting,
there will be times when there could be as little as one uploaded.
If you print them out what's in them?
echo $image1;
echo $image2;
I just realized that the $key probably starts at 0 instead of 1, so you
might need to check that and then possibly:
${image.($key+1)} = $_FILES['pictures']['name'];
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RE: [PHP-DB] Arrays from forms....
Nope... here is the output.
-- -- Array ( [error] = )
-Original Message-
From: Chris [mailto:[EMAIL PROTECTED]
Sent: Thursday, November 30, 2006 10:56 PM
To: Gary E. Terry
Cc: php-db@lists.php.net
Subject: Re: [PHP-DB] Arrays from forms
Gary E. Terry wrote:
If I print them, there's nothing. all three
Here is the same file, in test mode...
?php
include db.inc.back.php;
foreach ($_FILES[pictures][error] as $key = $error) {
if ($error == UPLOAD_ERR_OK) {
echo $error_codes[$error];
move_uploaded_file(
$_FILES[pictures][tmp_name][$key],
bikeimages/ .$_FILES[pictures][name][$key]
) or die(Problems with upload);
${image.$key} = $_FILES['pictures']['name'];
}
}
Hmm, looks ok.
If you:
print_r($_FILES[pictures]);
and
print_r($_FILES[pictures]['error']);
do you get stuff there ?
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RE: [PHP-DB] Arrays from forms....
OK.. I am a moron.. Forgot that I had changed the name of the field in the
form, and got sidetracked and didn't change it in the
php... But, still not working correctly.
Here is the output: Array -- Array -- Array
from:
?php
include db.inc.back.php;
foreach ($_FILES[pictures][error] as $key = $error) {
if ($error == UPLOAD_ERR_OK) {
echo $error_codes[$error];
move_uploaded_file(
$_FILES[pictures][tmp_name][$key],
bikeimages/ .$_FILES[pictures][name][$key]
) or die(Problems with upload);
${image.($key+1)} = $_FILES['pictures']['name'];
}
}
$make = $_POST['make'];
$model = $_POST['model'];
$year = $_POST['year'];
$color = $_POST['color'];
$description = $_POST['description'];
//$image1 = $_POST['image1'];
//$image2 = $_POST['image2'];
//$image3 = $_POST['image3'];
$status = $_POST['status'];
echo $image1 -- $image2 -- $image3;
/*
$query = INSERT INTO `inventory` (`make`, `model`, `year`, `color`,
`description`, `image1`, `image2`, `image3`, `status`)
VALUES ('$make', '$model', '$year', '$color', '$description',
'$image1', '$image2', '$image3', '$status');;
$result = mysql_db_query($db, $query) or displayErrorQuery ($query);
echo meta http-equiv='refresh' content='0;URL=inventorylist.php';
exit;
*/
?
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RE: [PHP-DB] Arrays from forms....
I know you really meant :
${image.($key+1)} = $_FILES['pictures']['name'][$key];
And it works!!!
Thanks oh so very much!
-Original Message-
From: Chris [mailto:[EMAIL PROTECTED]
Sent: Thursday, November 30, 2006 11:46 PM
To: Gary E. Terry
Cc: php-db@lists.php.net
Subject: Re: [PHP-DB] Arrays from forms
Gary E. Terry wrote:
OK.. I am a moron.. Forgot that I had changed the name of the field in the
form, and got sidetracked and didn't change it in the
php... But, still not working correctly.
Here is the output: Array -- Array -- Array
Oops this:
${image.($key+1)} = $_FILES['pictures']['name'];
should be:
${image.($key+1)} = $_FILES['pictures'][$key]['name'];
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RE: [PHP-DB] PHP 4 to 5 Upgrade Issue
I need to compare PHP 4 code with PHP 5 interpreter on same machine. I am following the examples in Adam Trachtenberg's Upgrading to PHP 5 (O'Reilly 2004) listed in Appendix C: Installing PHP 5 Alongside PHP 4 with regard to using virtual hosting and relative ports on Apache httpd. I have also read the Apache docs online regarding virtual hosting. And I cannot get it to work. I have the following relevant entries in Apache httpd.conf: Listen 8181 Listen 80 VirtualHost *:80 LoadModule php4_module modules/libphp4.so DocumentRoot /srv/www/htdocs /VirtualHost VirtualHost *:8181 DocumentRoot /srv/www/htdocs ScriptAlias /* /srv/www/htdocs Directory /usr/local/php-5.0.4/bin /Directory /VirtualHost When I browse http://localhost:8181/ I always get the root (/index.html) instead of the alias (/php5/index.php). Any clues? tia, ~mark Mark, Change your DocumentRoot on *:8181 to: DocumentRoot /srv/www/htdocs/php5 Your ScriptAlias isn't really affecting that portion of the site. Your PHP5 index.php resides in /srv/www/htdocs/php5 directory, right? G.~ This email and any file transmitted with it may be confidential and is intended solely for the use of the individual or entity to whom it is addressed. If you received this email in error please notify the DBM Service Desk by forwarding this message to [EMAIL PROTECTED] This email has been scanned by networkMaryland Antivirus Service for the presence of computer viruses. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] adodb is slow
You can always strip out the support for the DB's you're not going to use. This should improve performance some. Also, ADODb is a great abstraction layer, but we've found that we use less than half of its fuctionality. It's great that the functionality is there, so you can pare it down to your needs, but it's really a cure-all when what you need is an abstraction layer that works for YOUR needs! Don't be afraid to try slimming it down, but I'd keep an original copy somewhere in case you find that your paring knife was a little too sharp!! G.~ Gary Every Sr. UNIX Administrator Ingram Entertainment Inc. 2 Ingram Blvd, La Vergne, TN 37089 Pay It Forward! -Original Message- From: Micah Stevens [mailto:[EMAIL PROTECTED] Sent: Sunday, May 22, 2005 5:35 PM To: php-db@lists.php.net Subject: Re: [PHP-DB] adodb is slow Any sort of abstraction library is going to be slower than directly using the API.. I don't see how you can get around that. -Micah On Thursday 19 May 2005 07:01 am, Oriol wrote: hi all, I'm proud to install adodb library in my framework. I succesfully got it. But, surprise! My scripts became slower than ever! Exactly the 33% of the time is spent by adodb So, I know the advantages of this library, and I understand the reason is so slow...but, well, I wondered if somebody has reached a better results with adodb doing something with the library in performance. Well, thanks in advance. See you! -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] What wrong with my Query??
Actually, your sql syntax is wrong. The SET keyword if for UPDATE not
INSERT
Use
$sql = INSERT INTO mfadmin
(id,account,planlimit,name,email,password,lastlogin,datecreated,expiry,l
astip) VALUES
('','$accname_lc','$plans','$yourname','$email','$password','$datetoday'
,'$datetoday','$expirydate','123.123.123.123');
Gary Every
Sr. UNIX Administrator
Ingram Entertainment Inc.
2 Ingram Blvd, La Vergne, TN 37089
Pay It Forward!
-Original Message-
From: HarryG [mailto:[EMAIL PROTECTED]
Sent: Thursday, March 24, 2005 11:27 PM
To: php-db@lists.php.net
Subject: [PHP-DB] What wrong with my Query??
What the hell is wrong with this MYSQL query?? PHP keeps giving me the
error message:
You have an error in your SQL syntax. Check the manual that corresponds
to your MySQL server version for the right syntax to use near
'limit=2, name='test1', email='[EMAIL PROTECTED]', password='t
$query = INSERT INTO mfadmin SET id='', account='$accname_lc',
limit=$plans, name='$yourname', email='$email', password='$password',
lastlogin='$datetoday', datecreated='$datetoday', expiry='$expirydate',
lastip=123.123.123.123;
This is my table structure
CREATE TABLE `admin` (
`id` int(10) unsigned NOT NULL auto_increment,
`account` varchar(50) NOT NULL default '',
`limit` int(10) unsigned NOT NULL default '0',
`name` varchar(50) NOT NULL default '',
`email` varchar(50) NOT NULL default '',
`password` varchar(50) NOT NULL default '',
`lastlogin` varchar(50) NOT NULL default '',
`datecreated` varchar(50) NOT NULL default '',
`expiry` varchar(50) NOT NULL default '',
`lastip` varchar(50) NOT NULL default '',
PRIMARY KEY (`id`)
) TYPE=MyISAM;
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Re: [PHP-DB] Re: Passing url parameters
Got a question can one send a full array to another page with out having out put each value stored in it manually? On Sun, 03 Oct 2004 05:54:54 +0530, Amit Arora [EMAIL PROTECTED] wrote: You can set this to anything you want. http://www.url.com?new_field=value And you can get the value using the $_GET['new_field'] Amit www.digitalamit.com Stuart Felenstein wrote: I swear this is not a repeat of earlier post :) When passing variables via URL, my understanding is that the value passed is the database column name. What I don't understand is the name / label part. It seems like the only name I can use is the same name as the value. i.e. Database column: Myfield Value: _get[Myfield] Name: Myfield (this is the one I want to change, so my database column is not identified in the url) This make sense ? I hope this is not off topic. If it is my apologies. Stuart -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Help needed
Check to see if your register_globals is set to off in php.ini. If so (likely, since it defaults to that value) you'll need to access your POST and GET variables like this: GET vars: $var = $_GET['var']; POST vars: $var = $_POST['var']; Gary Every Sr. UNIX Administrator Ingram Entertainment Inc. 2 Ingram Blvd, La Vergne, TN 37089 Pay It Forward! -Original Message- From: Manoj Japher [mailto:[EMAIL PROTECTED] Sent: Monday, October 04, 2004 9:29 AM To: [EMAIL PROTECTED] Subject: [PHP-DB] Help needed hi, I am new to PHP and I am not sure if this is the right forum. I am trying to run PHP thro webmin using CGI scripts. PHP runs fine except that when I am trying to read variables coming thro' a form after hitting the submit button, I get NULL values. I can read and write to the database without any trouble. The problem is reading the form values. Any help would be greatly appreciated. Many Thanks, Manoj Life,it is not a problem to be solved, but a process to be managed. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] PHP 5 Error Handling
Good question. I've tried the __LINE__ and __FILE__ in my
error-handling, but it does the same thing you're experiencing, getting
the line in the function/method as opposed to the actual error line. The
only way I've gone around it is whenever there may be an exception, such
as a sql statement, etc I assign $line_no = __LINE__ and if an exception
gets thrown, the $line_no is captured, and I can use the info to print
to the logs or the screen or ...
G.
Gary Every
Sr. UNIX Administrator
Ingram Entertainment Inc.
2 Ingram Blvd, La Vergne, TN 37089
Pay It Forward!
-Original Message-
From: Joseph Crawford [mailto:[EMAIL PROTECTED]
Sent: Tuesday, September 14, 2004 5:55 AM
To: [PHP-DB] Mailing List
Subject: [PHP-DB] PHP 5 Error Handling
Guys,
i have been working with custom exception classes that extend the
general exception. Here is some code i have
public function command($cmd) {
if($cmd) {
$res = fputs($this-connection, $cmd);
$this-response = fgets($this-connection, 128);
switch($this-getCode()) {
case 500:
throw new CommandException($cmd);
break;
}
}
}
public function selectGroup($group) {
$this-group = $group;
if(substr($this-response,0,3) == 200) {
THIS IS THE LINE THAT THROWS THE ERROR
$this-command(NoSuchCommand\n);
$this-response = fgets($this-connection, 1024);
}
$info = split( , $this-response);
$this-first = $info[2];
$this-last = $info[3];
}
now when the error is thrown and i do $e-getLine(); it shows the line
of the file where the throw statement is. Is there a way to make it
show the actual line number of the line that is the error? the
$this-command(NoSuchCommand\n); line.
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For a GMail account
contact me OFF-LIST
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RE: [PHP-DB] Please help
What exactly is in the $sql and $sql_ext?? Try to put it into a variable so you can print out what you're sending to the DB Such as: $query = $sql . . $sql_ext . limit 0,1; Echo $query . BR; If your $sql and $sql_ext combine to make a valid sql query, the is just putting a space inside the query, and it is valid Gary Every Sr. UNIX Administrator Ingram Entertainment Inc. 2 Ingram Blvd, La Vergne, TN 37089 Pay It Forward! -Original Message- From: Stuart Felenstein [mailto:[EMAIL PROTECTED] Sent: Wednesday, September 08, 2004 2:29 PM To: [EMAIL PROTECTED] Subject: [PHP-DB] Please help I'm using a product called dbqwiksite pro. PHP generator for PHP - MySQL The code seems to be working fine except in my search page where I receive an invalid query $result = mysql_query($sql . . $sql_ext . limit 0,1) or die(Invalid query); This is the place I where the code is taking the die path. I'm guessing something belongs between the quotation marks , just not sure. Anyone ? Thank you Stuart -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Search page
K, first off I'm brand new to PHP and databases. So I
hope my question isn't stupid or unfitting to the
list.
Welcome! Only those that don't ask are unfitting
I am creating a search and results page of, right
now 3 fields with more to add.
Perhaps not necessary to my question, I have created a
working SQL statement which involved one main
transactional table and a number of joins to static
tables where the id codes inserted into the main table
are referenced. All is fine.
I thought I could use AND / OR statements, but both
don't allow for any number of fields unusued or force
a return if the first condition is met. I have a
variable in the SQL statment , like LocationCity =
'resset1', LocationState = 'resset2', etc.
Just sure how to get the code to see if it was passed
a value or not. Also to treat each field
independently, so if the user leaves the first 2
unchanged , and only enters the 3rd it will search for
that particular condition.
Try this, which is assuming that you are sending variables through POST
// Start the query off right
$query = Select * FROM table_name WHERE (;
Foreach($_POST as $key-$value) {
if($value != '') {
// Add the query part
$query_frag .= $key = '$value' AND ;
}
}
// Now you have something that looks like
// $query_frag = first_var = 'Value1' AND second_var = 'Value2' AND
third_var = 'Value3' AND
// Get rid of that last AND, plus close out your parentheses
$query_frag_trimmed = rtrim($query_frag,AND ) . ')';
// Now $query_frag_trimmed = first_var = 'Value1' AND second_var =
'Value2' AND third_var = 'Value3'
// If you want to limit your query, tack on a limit clause on the end
$offset = 0;
$rows = 50;
$query_frag_trimmed .= LIMIT $offset,$rows;
// Now put it all together
$completed_query = $query . $query_frag_trimmed;
// You've got:
// $completed_query = Select * FROM table_name WHERE ( first_var =
'Value1' AND second_var = 'Value2' AND third_var = 'Value3') LIMIT
0,50;
// And send that to mysql
Also I should mention, that when the Search form comes
up, all the drop down menus say Please Select, that
label actually has a value, which I assume is common.
Regardless on submit that value is going.
I was looking at the following code but the !='' tells
me that it's looking for an empty string. So if my
dead Please Select value is sent , do I need to put
the value in there, i.e. !='XXX' ?
?php
if (isset($HTTP_GET_VARS['states']) $HTTP_GET_VARS['states']!=''){
if (!isset($isNotFirst) OR $isNotFirst==false){
$isNotfirst = true;
$KT_search = '1=1 AND ';
}else{
$KT_search .=' AND ';
}
$KT_search .='LocationState = \''.$HTTP_GET_VARS['states'].'\' '; } ?
Well I hope I don't get flamed since I'm obviously
clueless and seeking some advice when perhaps I should
be finding it on my own.
Thank you ,
Stuart
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RE: [PHP-DB] Text area
You need to add slashes to your return:
Return input type=textarea rows=\5\ cols=\70\ name=\\;
Or use single quotes:
Return 'input type=textarea rows=5 cols=70 name=';
Gary Every
Sr. UNIX Administrator
Ingram Entertainment Inc.
2 Ingram Blvd, La Vergne, TN 37089
Pay It Forward!
-Original Message-
From: Hafidz Abdullah [mailto:[EMAIL PROTECTED]
Sent: Tuesday, August 24, 2004 3:44 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Text area
Hi again, everyone.
I also have a problem creating my text area. I meant to do a text area
(measuring 5 rows by 70 columns) which accompanies the words: First 50
words are free. Subsequent 50 words or part thereof, $50 will be
charged:
function write_textarea()
{
return input type=textarea rows=5 cols=70 name=;
}
Doesn't work. How can I make it work?
Thanks regards,
Hafidz
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RE: [PHP-DB] Re: LAMP
The answer to that is SPEED. Nothing short of Oracle comes even close Gary Every Sr. UNIX Administrator Ingram Entertainment Inc. 2 Ingram Blvd, La Vergne, TN 37089 Pay It Forward! -Original Message- From: Lester Caine [mailto:[EMAIL PROTECTED] Sent: Tuesday, August 03, 2004 1:15 AM To: [EMAIL PROTECTED] Subject: [PHP-DB] Re: LAMP Gavin Amm wrote: I'd really like to find a Linux distro that is a LAMP system right out of the box. (Linux, Apache, MySQL, PHP) Are there any out there? Thankfully not ;) I want LAFP but LAPP seems still to be more popular on Linux. WHY does everybody run lemming like after MySQL. It STILL has to catch up with the better FREE database engines ;) -- Lester Caine - L.S.Caine Electronic Services -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Turning off Save Password
I'm trying to turn off the save password function so that I can do an auth page that refuses to save passwords on the client side. I've tried some JS but it works only in IE, not Netscape. So, I'm looking for a server-side solution to this. Any ideas? Gary Every Sr. UNIX Administrator Ingram Entertainment Inc. 2 Ingram Blvd, La Vergne, TN 37089 Pay It Forward! -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Turning off Save Password
Fixed my own problem. Within the tag, you can use autocomplete=off To turn off the prompting or the autocompletion of any field. Apologize for this off-topic post, but I was searching for a non-javascript server-side solution Gary Every Sr. UNIX Administrator Ingram Entertainment Inc. 2 Ingram Blvd, La Vergne, TN 37089 Pay It Forward! -Original Message- From: Gary Every Sent: Thursday, July 01, 2004 8:46 AM To: [EMAIL PROTECTED] Subject: [PHP-DB] Turning off Save Password I'm trying to turn off the save password function so that I can do an auth page that refuses to save passwords on the client side. I've tried some JS but it works only in IE, not Netscape. So, I'm looking for a server-side solution to this. Any ideas? Gary Every Sr. UNIX Administrator Ingram Entertainment Inc. 2 Ingram Blvd, La Vergne, TN 37089 Pay It Forward! -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Re: [PHP] update count
If you aren't using a unique key, you can always use LIMIT 1 at the end of your query, but unless your ORDERing correctly to get the exact data row you want to update, this can have unexpected results. Gary Every Sr. UNIX Administrator Ingram Entertainment Inc. 2 Ingram Blvd, La Vergne, TN 37089 Pay It Forward! -Original Message- From: Bob Lockie [mailto:[EMAIL PROTECTED] Sent: Wednesday, June 16, 2004 9:21 AM To: PHP-DB Mailing List Subject: [PHP-DB] Re: [PHP] update count On 06/16/04 09:53 John Nichel spoke: Bob Lockie wrote: What is the best way to only do an update if it going to update only one row? I want to protect my code so that it won't accidentally update more than one row. I can do a select first but there must be an easier way. :-) UPDATE thisDB.thisTable SET thisTable.thisColumn = 'thisValue' WHERE thisTable.uniqueColumn = 'someUniqueValue' Ok, a primary key is unique, right? -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Sample Code
Here's a quick and easy one though: SELECT * from your_table WHERE your_date_field BETWEEN '2004-06-01' AND '2004-06-15'; Gary Every Sr. UNIX Administrator Ingram Entertainment Inc. 2 Ingram Blvd, La Vergne, TN 37089 Pay It Forward! -Original Message- From: Mike Koponick [mailto:[EMAIL PROTECTED] Sent: Tuesday, June 15, 2004 11:44 AM To: [EMAIL PROTECTED] Subject: [PHP-DB] Sample Code Hello all, I was wondering if anyone had some sample code that I could use for a small project. What I would like to do is select data in a date field, like: From: 6-1-04 To: 6-15-04 Then output to a text file. I have other selections within this data that I will make, and I think can figure out. The part I'm having trouble with is exporting the data and selecting between two dates. I'm running PHP4 and MySQL 4.1. Thank in advance for your help. Mike -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Re: datetime update
Actually it would be:
UPDATE table SET dateTime=NOW() WHERE record_id='$the_one_you_want';
Or
INSERT INTO table (record_id,dateTime) VALUES
('$the_one_you_want',NOW());
Gary Every
Sr. UNIX Administrator
Ingram Entertainment Inc.
2 Ingram Blvd, La Vergne, TN 37089
Pay It Forward!
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Sent: Thursday, June 10, 2004 4:10 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Re: datetime update
Hi all,
i have a datetime field in a mysql database and it's defined with a
default
of '-00-00 00:00:00:'
now, when i add a record to the database, i want to fill that field
with the date and current time.
can anyone point me ?
Via PHP:
$dateTime = date('Y-m-d H:i:s');
mysql_query(INSERT INTO table SET dateTime = '$dateTime');
Via MySQL:
mysql_query(INSERT INTO table SET dateTime = NOW());
Take a look here for other useful MySQL date and time functions:
http://dev.mysql.com/doc/mysql/en/Date_and_time_functions.html
Hope it helps. Regards,
Torsten Roehr
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RE: [PHP-DB] Re: automatic call reference creation
Here's what you can do: 1. CREATE your table with an autoincrement column as well as a date column. 2. When the customer service rep logs the call, they click on the submit button, which will place the data into the DB 3. Right after you do the insert, (in PHP) do: $suffix = mysql_insert_id($Resource_id); 4. $padded_suffix = str_pad($suffix, 5, 0, STR_PAD_LEFT); // This will // pad the $suffix with 0's (up to five characters) 5. $dat = dat(Y-m-d); 6. $callcode = $dat . $padded_suffix; 7. // Show them the call code echo Your call code is $callcode; You don't need to store the call code, since you can recreate it using the autoincrement, the date field, and str_pad. Of course, if space is not an issue, you could always store the concatenated string into another column. Gary Every Sr. UNIX Administrator Ingram Entertainment Inc. 2 Ingram Blvd, La Vergne, TN 37089 Pay It Forward! -Original Message- From: pete M [mailto:[EMAIL PROTECTED] Sent: Thursday, June 10, 2004 5:59 AM To: [EMAIL PROTECTED] Subject: [PHP-DB] Re: automatic call reference creation using the autoincrement you'd have to create the entry first ! otherwise your gonna have problems with concurrent users Gawie Marais wrote: thanx for the replys guys... basically i need a PHP formula to generate a 'call refenrence code' that is unique to give out to clients whenever they log a call. this unique 'call reference code should be inserted into a mysql field within a table. all i need is a formula to get the last entered code and increment it by one - the intended code should be forumated by php by using the current date i.e. 20040101 + a numerical value i.e. 001 for the first 'call reference code' for the day. when the next call is logged, the next unique available numerical should be assigned and combined with the date to form the call reference number. hope this makes it a bit clearer. Pete M [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] not sure what u want here but have you looked at the identiry field ?? its called auto_increment in mysql and this gives it record in a database a unique number eg Insert into table (date_call)values(now() ) then after the insert do select last_insert_id() pedro Gawie Marais wrote: hi all, i need to create an automatic call reference. i though it would work using the date as ccyymmdd and by adding a '001', '002', etc to the end. now, i know how to format the date but how would i increment the 001, 002 at the end... ? i understand that i would have to check back to the database to check the last one used. but how... ? alternatively is to just generate a random number, check it against the database to see if it's not already used. if not use it. if its used already, just create another one... ? OR do you guys have any laternative suggestions ? Regards, Gawie. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Display mysql query results divided in dynamic numbered pages
Look at:
http://www.phpclasses.org/browse/package/92.html
It's a pager class that does:
Previous 1 2 3 4 5 6 7 8 9 10 Next
Gary Every
Sr. UNIX Administrator
Ingram Entertainment Inc.
2 Ingram Blvd, La Vergne, TN 37089
Pay It Forward!
-Original Message-
From: Kpromos [mailto:[EMAIL PROTECTED]
Sent: Thursday, May 20, 2004 8:35 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Display mysql query results divided in dynamic
numbered pages
Importance: High
Dears, I'm new to php, so I'm not able to solve the following problem. I
have a function with a while loop that generates the results of a mysql
query. I'd need to generate a flow of the results, divided in pages as
... Previous 1 2 3 4 Next ...
The function I'm using follows .. and also the script that should
generate the numbered pages. Someone could help me in incorporating the
script that follows too?
= function displaying the results ==
function display($show_what) {
switch ($show_what) {
case :
$sql = select * from news2 ORDER BY date DESC, time
DESC;
break;
}
display_posts($sql);
}
function display_posts($sql) {
connect();
$result = mysql_query($sql) or die(mysql_error());
?
table width=100% border=0 cellpadding=5 align=CENTER
tr
td hr align=RIGHT size=1 width=100% noshade /td
/tr
?
while($row = mysql_fetch_array($result)) {
? trtd ?
if($last_date == $row[date]):?
p class=dateb?echo $row[time]?/b
?else:?
p class=date?echo $row[time]? - b?echo
$row[date]?/b
?endif;
$cat_num = $row[category_id];
$cat_result = mysql_query(select categories.category from
news2, categories where news2.category_id = categories.category_id and
news2.category_id = '$cat_num');
$cat = mysql_fetch_array($cat_result);
?
br
..
/tr
?
}
?
/table
?
}
=== script for generating the pages ===
$table = 'news2'; // The name of your table in the database
$limit = '2'; // How many results should be shown at a time
$scroll = '10'; // How many elements to the navigation bar are shown at
a time
// Get the total number of rows in a database
$query1 = mysql_query (SELECT * FROM news2);
$numrows = mysql_num_rows ($query1);
//
if (!isset ($_GET[show])) {
$display = 1; // Change to $NUMROWS if DESCENDING order is
required
} else {
$display = $_GET[show];
}
// Return results from START to LIMIT
$start = (($display * $limit) - $limit);
$query2 = mysql_query (SELECT * FROM $table LIMIT $start,$limit);
while ($myrow = mysql_fetch_array ($query2)) {
echo p.$myrow[ROW]./p; // EDIT TO REFLECT YOUR RESULTS
}
//
$paging = ceil ($numrows / $limit);
// Display the navigation
if ($display 1) {
$previous = $display - 1;
echo a href=\$_SERVER[PHP_SELF]?show=1\ First/a | ;
echo a href=\$_SERVER[PHP_SELF]?show=$previous\
Previous/a | ;
}
if ($numrows != $limit) {
if ($paging $scroll) {
$first = $_GET[show];
$last = ($scroll - 1) + $_GET[show];
} else {
$first = 1;
$last = $paging;
}
if ($last $paging ) {
$first = $paging - ($scroll - 1);
$last = $paging;
}
for ($i = $first;$i = $last;$i++){
if ($display == $i) {
echo b$i/b ;
} else {
echo a
href=\$_SERVER[PHP_SELF]?show=$i\$i/a ;
}
}
}
if ($display $paging) {
$next = $display + 1;
echo | a href=\$_SERVER[PHP_SELF]?show=$next\Next /a |
;
echo a href=\$_SERVER[PHP_SELF]?show=$numrows\Last /a;
}
//
?
Thanks for all,
Alessandro Folghera
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[PHP-DB] [RESOLVED] RE: Secure MySQL Access md5()
Thanks for the info Hans! I've got it working now. -Original Message- From: Hans Lellelid [mailto:[EMAIL PROTECTED] Sent: Thursday, May 13, 2004 7:28 PM To: Gary Theisen Cc: '[EMAIL PROTECTED]' Subject: Re: Secure MySQL Access md5() Hi, Passwords in the mysql.users table must be encrypted using MySQL's native PASSWORD() function, not MD5(). With newer versions of MySQL, I think there is some change in this, but AFAIK for 4.0.18 this is still true. When connecting to the database you always use the plaintext password, and MySQL will do the encrypting (using PASSWORD()) and check it against what is in the row of the users table. HTH, Hans Gary Theisen wrote: Hi all, I've got: WinNT php 4.3.1 phpmyadmin 2.5.6 MySQL 4.0.18-nt I can connect to my db via my php script using: [php] $connection = mysql_connect (localhost, root, ) [/php] That works no problem. This will not work however: [php] $somePass = md5(somePass); $connection = mysql_connect (localhost, someID, $somePass) [/php] gives me this error: [quote] Access denied for user: '[EMAIL PROTECTED]' mailto:'[EMAIL PROTECTED]' (Using password: YES) [/quote] I set someID up in the db using phpmyadmin, with it's password using the md5() function. I can see via phpmyadmin that someID does indeed have a 32 byte encrypted password stored. I can then compare the stored md5 password to the md5 password I'm passing to try to connect...via $somePass. The encrypted passwords match exactly. Why wouldn't the match be confirmed...allowing me to connect? Thanks! -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Secure MySQL Access md5()
Hi all, I've got: WinNT php 4.3.1 phpmyadmin 2.5.6 MySQL 4.0.18-nt I can connect to my db via my php script using: [php] $connection = mysql_connect (localhost, root, ) [/php] That works no problem. This will not work however: [php] $somePass = md5(somePass); $connection = mysql_connect (localhost, someID, $somePass) [/php] gives me this error: [quote] Access denied for user: '[EMAIL PROTECTED]' mailto:'[EMAIL PROTECTED]' (Using password: YES) [/quote] I set someID up in the db using phpmyadmin, with it's password using the md5() function. I can see via phpmyadmin that someID does indeed have a 32 byte encrypted password stored. I can then compare the stored md5 password to the md5 password I'm passing to try to connect...via $somePass. The encrypted passwords match exactly. Why wouldn't the match be confirmed...allowing me to connect? Thanks!
[PHP-DB] No user table access to phpMyAdmin - How?
Hi all, Installed software/os: Win NT 4.0 IIS 4.0 PHP 4.3.1 MySQL 4.1.1 phpMyAdmin 2.5.6 I'm wondering how I can hide phpMyAdmin access via a webpage to the mysql.mysql tablespecifically the user table. I don't want anyone using phpMyAdmin to have access to the user table. I only want to control that db table through the command line on the server itself. How/What do I need to configure?? Thanks, Gary
[PHP-DB] MySQL Password() PHP encryption?
Hi all, I've recently upgraded my mysql to v 4.1.1 (on win nt 4.0) and set the Passwords in the user table to the mysql Password() function. Now, this doesn't work anymore when call from a php web script (which is a good thing, cause it's plain text): mysql_connect (localhost, theID, thePassord); gives me this error: Client does not support authentication protocol requested by server ... Since my mysql.mysql user table now has the 41 bit encrypted passwords stored...how to I connect with my php scripts? I've tried md5(), sha1()...but they don't generate the same 41 bit encrypted password. Anyone have a suggestion? Thanks!
[PHP-DB] Testing - no emails since 11:45 AM 3/23/04
Testing, have received no emails since 11:45 Gary Every Sr. UNIX Administrator Ingram Entertainment Inc. 2 Ingram Blvd, La Vergne, TN 37089 Pay It Forward! -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Re: How to simplify DB creation?
Hans Lellelid offered this bit: After a long period of quite intense development, the Propel team is pleased to announce the release of Propel 1.0.0-alpha1. Propel is an object persistence layer for PHP5 based on Apache Torque. In practical terms, Propel allows you to use objects instead of SQL to read and write rows in your database tables. Propel provides (1) a generator that creates SQL definition files (DDL) and PHP classes for your datamodel, and (2) a runtime engine that transparently handles object persistence and retrieval. Propel makes it easy to customize generated classes; additionally, the use of XML, PHP classes, and the Phing build tool make it easy to integrate Propel with an existing application framework. Visit http://propel.phpdb.org to learn more about Propel. Some of Propel's features include: * Use of simple XML schema for datamodel definition * Generation of PEAR-style compliant, phpdoc commented, PHP5 classes. * Easy to customize object model ( changes won't get overwritten). * Generation of SQL definition files (DDL) for your RDBMS * Several popular databases supported: MSSQL, MySQL, PostgreSQL, SQLite. * Support for reverse-engineering XML schema from database * Use Criteria OO query system instead of writing SQL queries * Generated methods to easily efficiently work with (foreign key) relationships Gary Every Sr. UNIX Administrator Ingram Entertainment Inc. 2 Ingram Blvd, La Vergne, TN 37089 Pay It Forward! -Original Message- From: Thierry B. [mailto:[EMAIL PROTECTED] Sent: Monday, March 22, 2004 3:23 PM To: [EMAIL PROTECTED] Subject: [PHP-DB] Re: How to simplify DB creation? You have also this IDE : http://www.codecharge.com -- Click below to answer / cliquez ci dessous pour me repondre http://cerbermail.com/?MQkxTL4vUP Michal Masa [EMAIL PROTECTED] a écrit dans le message de news:[EMAIL PROTECTED] Hi, We plan to write a simple DB with app. 10 tables. Are there any tools that simplify and automatize the creation of PHP scripts for the database? Like automatic generation of PHP scripts that produce HTML input forms, generation of value lists, validation, sorting and searching? Well documented PHP library could be also useful. Regards, Mike -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] output formatting question
1. Get the result set in an array: $result
Now, do this:
?php
foreach($result as $row) {
$first = $row['first_name'];
$last = $row['last_name'];
$phone = $row['phone'];
/*
I'm assuming, perhaps incorrectly, that your phone is stored in the
database without any dashes, e.g. 2135551212, which is the most
efficient way. You'll need to assure that the area code is always
entered, though.
*/
echo '
TRTD' . $first . ' ' . $last . '/td
TD(' . substr($phone,0,3) . ') ' . substr($phone,3,3) . '-'
. substr($phone,6,4) . '/td/TR';
}
?
That will give you in HTML:
TRTDJohn Smith/TDTD(213) 555-1212/TD/TR
Some other formatting hints for this:
$first = ucfirst(strtolower($first));
will give you John even if the DB has JOHN or john
Gary Every
Sr. UNIX Administrator
Ingram Entertainment Inc.
2 Ingram Blvd, La Vergne, TN 37089
Pay It Forward!
-Original Message-
From: redhat [mailto:[EMAIL PROTECTED]
Sent: Tuesday, March 09, 2004 9:24 AM
To: phplist
Subject: [PHP-DB] output formatting question
I have a small database of employee names and phone extensions that I
have put together. I have also put together a very simple php page that
enables endusers to pull up this directory listing. My question is
simple, the output right now is in one long column (actually, three,
first name, last name, extension) and I would like to break the page
down into two columns (consisting of the three database columns each).
I am not a php programmer and would appreciate any help. If there is a
good article out there that someone could point me to that would be
great - that is how I figured out how to do the other.
thanks,
DF
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RE: [PHP-DB] How do you make an IN span multiple tables?
Select * from table1 t1, table2 t2, table3 t3 WHERE ((t1.thread_ref IN (1,2,3,4,5,6,7,8,9,10)) or (t2.thread_ref IN (1,2,3,4,5,6,7,8,9,10)) or (t3.thread_ref IN (1,2,3,4,5,6,7,8,9,10))) Gary Every Sr. UNIX Administrator Ingram Entertainment Inc. 2 Ingram Blvd, La Vergne, TN 37089 Pay It Forward! -Original Message- From: Richard Davey [mailto:[EMAIL PROTECTED] Sent: Thursday, March 04, 2004 8:36 AM To: php-db Subject: [PHP-DB] How do you make an IN span multiple tables? Hi, I'm a bit stuck with the following: I need to select data from 3 different tables and want to do it via a SELECT ... IN query. Each table has a primary key called thread_ref. I would like to do something like this: SELECT * FROM table1, table2, table3 WHERE thread_ref IN (1,2,3,4,5,6,7,8,9,10) Now the problem is that MySQL complains about the thread_ref being ambiguous - which I know that it is. But putting a table name in-front of it will limit the IN query to that specific table and cause no results to be returned. It is possible that not all of the tables will contain all of the thread_ref's in question. Does anyone have any ideas or is it just not possible using this method? I'm not using MySQL 4 otherwise I would have looked at using a UNION. -- Best regards, Richard Davey http://www.phpcommunity.org/wiki/296.html -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Accessing my variables
You're missing a ' in your include statement, after .php
Gary Every
Sr. UNIX Administrator
Ingram Entertainment Inc.
2 Ingram Blvd, La Vergne, TN 37089
Pay It Forward!
-Original Message-
From: J. Kevin C. Burton [mailto:[EMAIL PROTECTED]
Sent: Wednesday, February 11, 2004 11:29 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Accessing my variables
Hey all.. I am using PHP5 and apache 2.0 on windows xp pro.
My problem is:
I have an include file: global.inc.php
Inside that file I have:
$myVariable = xankjndckjnskncd;
now I have a index.php that has:
?
Include('global.inc.php);
Print $myVariable;
?
Anyone got a clue on this one?
Kevin
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RE: [PHP-DB] Results with ledger stripes?
Haven't been following this thread, but here's how we do it:
If($bgc == '') {
$bgc = #DD;
} elseif($bgc == #FF) {
$bgc = #DD;
} else {
$bgc = #FF;
}
Gary Every
Sr. UNIX Administrator
Ingram Entertainment Inc.
2 Ingram Blvd, La Vergne, TN 37089
Pay It Forward!
-Original Message-
From: Ryan Jameson (USA) [mailto:[EMAIL PROTECTED]
Sent: Monday, January 26, 2004 12:00 PM
To: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Results with ledger stripes?
$bg1 = #dd;
$bg2 = #ff;
While ...
$bg3 = $bg2;
$bg2 = $bg1;
$bg1 = $bg3;
echo tr bgcolor='$bg1'
Makes sense?
Ryan
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Sent: Sunday, January 25, 2004 6:43 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Results with ledger stripes?
Hello all,
I'm in the midst of creating an internet speed test system thingamabob
for my website. It's basically finished...but ugly as sin. What I'd
like to do is have the results (an average of each domain tested) listed
in a nice pretty table with alternating background colors, kinda like a
ledger. How on earth do I do this?
Here's what I've got thus far:
?php
echo Average speeds of each domain tested:br; $mongo = @mysql_query
(SELECT
substring_index(name,'.',-2),ROUND(AVG(speed),1) FROM `readings` GROUP
BY
substring_index(name,'.',-2) ORDER BY substring_index(name,'.',-2)
ASC); echo tabletrtdDomain/tdtdAverage Speed/td/tr\n;
while ($mongorow = mysql_fetch_array($mongo, MYSQL_NUM)) { echo
trtd$mongorow[0]/tdtd$mongorow[1]/td/tr\n;}
echo /table;
?
And I'd like it to spit out something along these lines:
table
tr bgcolor=#ddtddomain1.com/tdtd666.6 kbps/td/tr tr
bgcolor=#fftddomain2.com/tdtd3000.0 kbps/td/tr repeat
until done /table
The gizmo is up and running at
http://www.dibcomputers.com/bandwidthmeter/index.php if you care to have
a gander.
Thanks a bunch,
Dan
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RE: [PHP-DB] PHP export to CSV
You should try this: Header(Content-Type: text/plain); Header(Content-Disposition: attachment; filename=file.csv); Then output the text you want to send. Make sure you double-quote it so that the newlines work! $eol = \n; echo Field 1,Field 2,$field_variable,$eol .. This sends a stream of info WHEN THE USER DECIDES what to do with it. That means if they click cancel, the file is not created, and you have no cleanup Works great! -Original Message- From: John Greco [mailto:[EMAIL PROTECTED] Sent: Monday, December 22, 2003 9:20 AM To: [EMAIL PROTECTED] Subject: [PHP-DB] PHP export to CSV Anyone ever get some code to select from the DB and drop into a CSV file? -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] CREATE TABLE LIKE, error
Try:
CREATE table new_table SELECT * from old_table limit 1;
delete from new_table;
This will give you the same structure in both tables, and the deletion will make the
new_table empty.
-Original Message-
From: Adam i Agnieszka Gasiorowski FNORD [mailto:[EMAIL PROTECTED]
Sent: Monday, December 15, 2003 10:28 AM
To: Lista PHP DB
Subject: [PHP-DB] CREATE TABLE LIKE, error
I cannot use this query
CREATE TABLE table LIKE other_table;
, which is supposed to create an
empty clone of the other_table named
table.
Was it added in some later MySQL version?
It's in the manual on mysql.com, bo no version info
available.
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Re: [PHP-DB] Fake BDD
Check out SQLite BENARD Jean-philippe wrote: Hi, We use ORACLE DataBase for all our projects and we can't install mysql/postgresql on our server. A new project needs a little database (only 1 table). I heard about something like an API in order to use text files in place of real database system and that we could use SQL query to return results. Does someone know this tool and could help us? Many thanks in advance. (o_ BENARD Jean-Philippe - Consultant STERIA Infogérance (o_ (o_ //\ RENAULT DTSI/ODPS/[EMAIL PROTECTED] * ALO * API : MLB 02C 1 14 (/)_ (\)_ V_/_ 2 Av du vieil étang * 78181 MONTIGNY-LE-BRETONNEUX Tél : +33 1-30-03-47-83 * Fax : +33 1-30-03-42-10 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] multiple queries
Or do the same with the BETWEEN keyword: SELECT * FROM dates WHERE store='$store' AND date BETWEEN DATE_SUB(now(), interval 3 day) AND DATE_ADD(now(), interval 3 day) Richard Davey wrote: Hello Cameron, Tuesday, December 2, 2003, 1:08:19 AM, you wrote: CS $sql = SELECT * from dates where store=$store and date=$date; CS ultimately I would like to display data for 3 days on either side of CS this. The following is un-tested, but a quick look over the MySQL manual should firm this up for you: SELECT * FROM dates WHERE store='$store' AND date DATE_SUB(now(), interval 3 day) AND date DATE_ADD(now(), interval 3 day) -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] form not working...
Don't you need to start your form BEFORE your input type's
-Original Message-
From: jas [mailto:[EMAIL PROTECTED]
Sent: Monday, November 10, 2003 11:38 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] form not working...
For some reason my form to edit selected items is not working, I think I
need a new set of eyes.
Any help is appreciated...
Jas
// inc.php
function db_retrieve() {
require 'dbase.inc.php';
$tble = $_SESSION['table'];
$show = @mysql_query(SELECT * FROM $tble LIMIT 0, 15,$db)or
die(mysql_error());
while ($row = @mysql_fetch_array($show)) {
@list($nItemSKU, $bActive, $nUserID, $nItemConfig, $tItemType,
$tDepartment, $blSerialNumber, $nPropertyNumber, $blHostName, $nIPID,
$tRoomNumber, $tNotes) = $row;
$_SESSION['table'] .= tr class=fntMAINtd valign=top
align=left$nItemSKU/td
td valign=top align=left$bActive/td
td valign=top align=left$nUserID/td
td valign=top align=left$nItemConfig/td
td valign=top align=left$tItemType/td
td valign=top align=left$tDepartment/td
td valign=top align=left$blSerialNumber/td
td valign=top align=left$nPropertyNumber/td
td valign=top align=left$blHostName/td
td valign=top align=left$nIPID/td
td valign=top align=left$tRoomNumber/td
td valign=top align=left$tNotes/td
td valign=top align=leftinput name=edit type=checkbox
value=$blSerialNumber/td
/tr; }
$_SESSION['number'] = mysql_num_rows($show); }
?php
session_start();
require 'scripts/inc.php';
if ((!isset($_POST['edit'])) or ($_POST = )) {
$_SESSION['table'] = t_items;
call_user_func(db_retrieve);
} elseif ((isset($_POST['edit'])) or (!$_POST = )) {
require 'scripts/dbase.inc.php';
$tble = $_SESSION['table'];
$edt = mysql_query(SELECT * FROM $tble WHERE
blSerialNumber=\$edit\,$db)or die(mysql_error());
while ($row = mysql_fetch_array($edt)) {
list($nItemSKU, $bActive, $nUserID, $nItemConfig, $tItemType,
$tDepartment, $blSerialNumber, $nPropertyNumber, $blHostName, $nIPID,
$tRoomNumber, $tNotes) = $row;
$_SESSION['table'] .= tr class=fntMAIN
td valign=top align=leftinput name=nItemSKU type=text size=30
value=$nItemSKU/td
td valign=top align=leftinput name=bActive type=text size=30
value=$bActive$bActive/td
td valign=top align=leftinput name=nUserID type=text size=30
value=$nUserID$nUserID/td
td valign=top align=leftinput name=nItemConfig type=text
size=30 value=$nItemConfig$nItemConfig/td
td valign=top align=leftinput name=tItemType type=text size=30
value=$tItemType$tItemType/td
td valign=top align=leftinput name=tDepartment type=text
size=30 value=$tDepartment$tDepartment/td
td valign=top align=leftinput name=blSerialNumber type=text
size=30 value=$blSerialNumber$blSerialNumber/td
td valign=top align=leftinput name=nPropertyNumber type=text
size=30 value=$nPropertyNumber$nPropertyNumber/td
td valign=top align=leftinput name=blHostName type=text
size=30 value=$blHostName$blHostName/td
td valign=top align=leftinput name=nIPID type=text size=30
value=$nIPID$nIPID/td
td valign=top align=leftinput name=tRoomNumber type=text
size=30 value=$tRoomNumber$tRoomNumber/td
td valign=top align=leftinput name=tNotes type=text size=30
value=$tNotes$tNotes/td
td valign=top align=leftinput name=save type=button value=Save
class=frmBTNS/td
/tr; }
}
?
form action=?php echo $_SERVER['PHP_SELF']; ? method=post
?php echo $_SESSION['table']; ?
input name=edit type=button value=edit selected items
class=frmBTNS
/form
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RE: [PHP-DB] Re: Page counter from a query ?
Just do an extract on your $_GET var (if security concerns are negligible) Say you get line is: ?sid=123form=12 // Execute this extract($_GET) // You end up with: $sid == 123; $form == 12; Gary Every Sr. UNIX Administrator Ingram Entertainment (615) 287-4876 Pay It Forward mailto:[EMAIL PROTECTED] http://accessingram.com -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Sent: Tuesday, November 04, 2003 9:01 AM To: pete M Cc: [EMAIL PROTECTED] Subject: Re: [PHP-DB] Re: Page counter from a query ? question/comment... i don't use PEAR currently. but i noticed this class expects register_globals=on and would therefore not to work on my system. Or does another parent class take care of the translation between $form and $_GET['form']? Jeff pete M [EMAIL PROTECTED]To: [EMAIL PROTECTED] cc: Subject: [PHP-DB] Re: Page counter from a query ? 11/04/2003 09:53 AM I use PEAR db to make my life easy.. here's their pager class http://vulcanonet.com/soft/index.php?pack=pager pete Larry Sandwick wrote: Is there a way to limit the number of pictures being display from a query? Example. Let say I have 100 pictures and I would like to display only 20. How would I put the numbers at the bottom of the page? 1 2 3 4 5 When you click on 1 you get 1 - 20, and when you click on 2 you get 21 - 40. I believe I can use the limit command for the query, I just do not understand how to put the query on the number. Any help would greatly be appreciated!!! TIA Larry Sandwick Sarreid, Ltd. Network/System Administrator phone: (252) 291-1414 x223 fax : (252) 237-1592 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Page counter from a query ?
There are a lot of paging scripts out there, you could look on hotscripts.com for some, but the query could be simple, such as this // The setup $page[1] = 0,10; $page[2] = 10,10; $page[3] = 20,10; ... // The link echo a href=\$PHP_SELF?pagid=1\1/a ; // At the top of the script $lim = $page[$pagid] // which would equal 0,10 $sql = SELECT columns from table limit $lim; and so on . .. Does that help? Gary Every Sr. UNIX Administrator Ingram Entertainment (615) 287-4876 Pay It Forward mailto:[EMAIL PROTECTED] http://accessingram.com -Original Message- From: Larry Sandwick [mailto:[EMAIL PROTECTED] Sent: Monday, November 03, 2003 1:35 PM To: [EMAIL PROTECTED] Subject: [PHP-DB] Page counter from a query ? Is there a way to limit the number of pictures being display from a query? Example. Let say I have 100 pictures and I would like to display only 20. How would I put the numbers at the bottom of the page? 1 2 3 4 5 When you click on 1 you get 1 - 20, and when you click on 2 you get 21 - 40. I believe I can use the limit command for the query, I just do not understand how to put the query on the number. Any help would greatly be appreciated!!! TIA Larry Sandwick Sarreid, Ltd. Network/System Administrator phone: (252) 291-1414 x223 fax : (252) 237-1592 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Help installing phpmysearch
But do you have php compiled --with-curl? check phpinfo(); Gary Every Sr. UNIX Administrator Ingram Entertainment (615) 287-4876 Pay It Forward mailto:[EMAIL PROTECTED] http://accessingram.com -Original Message- From: Joseph Allard [mailto:[EMAIL PROTECTED] Sent: Tuesday, October 28, 2003 3:59 PM To: [EMAIL PROTECTED] Subject: [PHP-DB] Help installing phpmysearch I was trying to install phpmysearch but I get this error instead : On your system must have Curl compiled in PHP! - Please check www.php.net how you can do this. Set in your php.ini allow_call_time_pass_reference to On. Well, the problem is that it already says, ON! So, what is the actual problem? I have attached a copy of the php.ini file, so that you can see for yourself. Thanks. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Round a number
Try the rtrim function in php Gary Every Sr. UNIX Administrator Ingram Entertainment (615) 287-4876 Pay It Forward mailto:[EMAIL PROTECTED] http://accessingram.com -Original Message- From: Shaun [mailto:[EMAIL PROTECTED] Sent: Friday, October 03, 2003 10:12 AM To: [EMAIL PROTECTED] Subject: [PHP-DB] Round a number Hi, I have a query that returns a number from culculation in my table. It returns say 4.00, 8.75, 0.00, 12.50 etc. How can I get MySQL to return the number without any zeros, i.e. 4, 8.75, 0, 12.5 etc? Thanks for your help -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] show list of values and new values
Create a table (items) with selectable items with these columns
select_id | selection | description
+---+
1 | #00 | White
1 | #FF | Black
2 | other | Another type
2 | second| Second Type
use select * from items where select_id='1';
into a variable, say $colors
then
?php
echo select name=color;
foreach($colors as $color) {
$selection = $color['selection'];
$description = $color['description'];
echo option value=\$selection\$description/option;
}
echo /select;
/* That will build a dropdown with the available colors (select_id='1')
*/
form
Then build an input type=text 3 times to do an add to the db, with
select_id,selection, and description. That will add a row to the table, and
each time you run the script above, it will be populated with all the rows
that have select_id='1'. You can use the same table with different
select_id's for different dropdowns.
Gary Every
Sr. UNIX Administrator
Ingram Entertainment
(615) 287-4876
Pay It Forward
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-Original Message-
From: Hull, Douglas D [mailto:[EMAIL PROTECTED]
Sent: Wednesday, October 01, 2003 2:52 PM
To: Note To php mysql List (E-mail)
Subject: [PHP-DB] show list of values and new values
Just for example, in php how can I show a list of colors so
the user can
select one? Also if needed the user could add a new color.
This could be a
drop down or whatever.
How can I make this dynamic so when the user adds the new color that
anywhere I show the list of colors in my web pages the new
color would be
available for selection for this user and all users following?
Kind of confusing, let me know if you need more detail.
Thanks,
Doug.
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RE: [PHP-DB] mySQL vs pgSQL | php vs others
El Mié 24 Sep 2003 07:24, nabil escribió: Dear all; I have been using Mysql for a long time, but I have a benchmark Q. Is pgsql , better ? faster ? more reliable than mysql ? Maybe not faster in FTS, but surely MORE reliable!!! any comment ? Some people say that php is not for a very big enterprise, banking , application !! they said that java or even .NET is better ... I m against that but what do you all think ? I'm not that sure. But one thing I am sure of is that I woud never put a bank account aplication using MySQL! And why is that? MySQL is as secure as the application that accesses it. We use it extensively for sensitive data, and it crunches numbers just fine. It ranks up with Oracle in speed, lacking some features, which will be available soon, such as stored procedures and triggers, and sub-selects which are very soon to be available. Think .NET, think swiss cheese! Think Java, think long load times, think PHP, think quick SSI and security as long as you pass it through ssl -- 16:22:01 up 33 days, 8:04, 1 user, load average: 0.26, 0.37, 0.38 - Martín Marqués |[EMAIL PROTECTED] Programador, Administrador, DBA | Centro de Telematica Universidad Nacional del Litoral - -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Re: UPDATE part of a column
The best way to do this is a text field, NOT a textarea, and if need be, use multiple fields. A textarea, by look and definition is inviting carriage returns to be used. Limit the users to the input you want, and remember, GIGO (garbage in, garbage out) Gary Every Sr. UNIX Administrator Ingram Entertainment (615) 287-4876 Pay It Forward mailto:[EMAIL PROTECTED] http://accessingram.com -Original Message- From: João Cândido de Souza Neto [mailto:[EMAIL PROTECTED] Sent: Tuesday, September 23, 2003 9:15 AM To: [EMAIL PROTECTED]; [EMAIL PROTECTED] Subject: [PHP-DB] Re: UPDATE part of a column Can you use strip_tags(nl2br($textarea)) Shaun [EMAIL PROTECTED] escreveu na mensagem news:[EMAIL PROTECTED] Hi, I have a column in my table called address. When users add an address with a textarea they sometimes press return for a new line and this seems to be putting line breaks into the database, so I have 2 questions: 1. How can I clean the table, so for example changing: Ashfield Business CentreBR The Idlewells PrecinctBR Sutton-in-AshfieldBR to: Ashfield Business Centre, The Idlewells Precinct, Sutton-in-Ashfield, 2, Is there a way to make sure the data is 'clean' before entering into the table? Thanks for your help -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Selection problem
Try unset after the if statement
if ($nameb == ){
$query = SELECT * FROM recipes WHERE points $pointsb;
} else {
$query = SELECT * FROM recipes WHERE name = '$nameb';
$new_nameb = $nameb;
unset($nameb);
}
Gary Every
Sr. UNIX Administrator
Ingram Entertainment
(615) 287-4876
Pay It Forward
mailto:[EMAIL PROTECTED]
http://accessingram.com
-Original Message-
From: Chris Payne [mailto:[EMAIL PROTECTED]
Sent: Sunday, September 07, 2003 5:43 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Selection problem
Hi there everyone,
I'm having a strange problem, I have a form with 2 fields, 1
is for points
(Weightwatcher points) and one is for recipe names. If you
select points
(IE: 1-3, 3-6,6-9,9 and above) it works perfectly, displays
the recipes and
allows you to select a new points range from the dropdown.
Next to it, on the same form, you can also select by recipe
name and ignore
the points instead selecting by the recipe name - this works
fine, you can
select 1, view it and then select another.
The problem comes when you select a recipe from the dropdown
and view it,
then decide you want to select points instead - the points
won't work once
you have selected a recipe. Can anyone see anything below
that is wrong? I
am sure it's the if statement, i'm not sure how to handle it
as you can
select either option to get the result.
Any help would really be appreciated, if I haven't confused
you all to death
:-)
Regards
Chris
?
if ($nameb == ){
$query = SELECT * FROM recipes WHERE points $pointsb;
} else {
$query = SELECT * FROM recipes WHERE name = '$nameb';
};
$sql_result = mysql_query($query,$connection)
or die(Couldn't execute query.);
while ($row = mysql_fetch_array($sql_result)) {
$id = $row[id];
$name = $row[name];
$points = $row[points];
$ingredients = $row[ingredients];
$instructions = $row[instructions];
};
?
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RE: [PHP-DB] determining if a query returns no value
Youy could use:
if(!$result) {
// Don't display
} else {
echo Title;
}
You fill in the blanks
Gary Every
Sr. UNIX Administrator
Ingram Entertainment
(615) 287-4876
Pay It Forward
mailto:[EMAIL PROTECTED]
http://accessingram.com
-Original Message-
From: Wendall Williams [mailto:[EMAIL PROTECTED]
Sent: Thursday, August 07, 2003 12:34 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] determining if a query returns no value
I'm building a resume page and I am having a problem. I need
to query a
table to determine if the client has any entries in that
table. If they do,
it needs to display the category title once then display the
entries in
rows. If the client has no entries for that category, it
needs to move on
to the next category.
Here is a sample of the code as it is now:
$result = mysql_query(SELECT showname, role, network FROM
tbltv where id =
$_GET[clientID]);
if (!$result) {
echo(pError performing query: . mysql_error() . /p);
exit();
}
// Display the title of category
echo(tr bgcolor='#66');
echo(td colspan='3'font
color='#FF'bTELEVISION/b/font/td/tr);
// set column vars
$cols = array('#CC','#99');
$i = 0;
// generate table row
while ( $row = mysql_fetch_array($result) ) {
echo(tr bgcolor= . $cols[$i++%2] . td .
$row[showname] .
/tdtd . $row[role] . /tdtd . $row[network] .
/td/tr);
}
You can see that the Category Title (in this case
TELEVISION) is printed
before the array is fetched. This was done to avoid
displaying the Title
above every row. However, if the client does not have any
entries in this
category, it (obviously) prints the title anyway and then
moves on to the
next category.
What statement would say if $result returned no value move on ??
Thanks for your help.
Wendall Williams
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RE: [PHP-DB] Condition for Adding data
Well, you're initializing $food to ; then testing to see if it has a
value, which it never will.
If you're getting the $food variable from a POST or a GET op, you'll need to
grab it from the appropriate array,
$food = $_POST['food'];
echo $food;
to see what is being passed.
Gary Every
Sr. UNIX Administrator
Ingram Entertainment
(615) 287-4876
Pay It Forward
mailto:[EMAIL PROTECTED]
http://accessingram.com
-Original Message-
From: gatimu [mailto:[EMAIL PROTECTED]
Sent: Tuesday, July 22, 2003 7:34 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Condition for Adding data
Hi
I need help!, I am quite new to php and I am trying to create
a condition
that will load a specific page after a form has been
submitted to enter
data in my database, I have tried using this code (I created
it) but it
wont work, all I get is a messege on the browser that says the page
address incorrect
Here is how i have scripted the code
?php
$food=;
if($food==milk)
{
$pgload=milk.php;
}
if ($food==eggs)
{
$pgload=egg.php;
}
if ($food==ham)
{
$pgload=ham.php;
}
echo form name=appForm method=post action=.$pgload.
?
any ideas on how i can go around this problem?
Gatimu
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RE: [PHP-DB] commas
Check out the php function number_format($field,0) Gary Every Sr. UNIX Administrator Ingram Entertainment (615) 287-4876 Pay It Forward mailto:[EMAIL PROTECTED] http://accessingram.com -Original Message- From: Chris Mach [mailto:[EMAIL PROTECTED] Sent: Thursday, July 17, 2003 7:43 AM To: [EMAIL PROTECTED] Subject: [PHP-DB] commas Is there a function that will strip or add commas? I'm trying to do calculations with attendance numbers of football games... for example: 33,153 right now I don't have a comma for the numbers in the database. So the above example is 33153 in my database. If I put the comma in, when I try to do calculations with php it sees it as 33 instead of 33,153. So is there a way to add that comma afterwards? Perhaps a string function at will put the comma in after the first 3 characters? Thanks -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Date problem
snip // Do some number crunching here // $newnow = $now-$numweeks; echo $now; $converted_date = date(d-m-y,$now); echo br$converted_date; /snip You should be running your $convewrted_date on $newnow, not $now Gary Every Sr. UNIX Administrator Ingram Entertainment (615) 287-4876 Pay It Forward mailto:[EMAIL PROTECTED] http://accessingram.com -Original Message- From: Chris Payne [mailto:[EMAIL PROTECTED] Sent: Monday, July 14, 2003 3:45 AM To: php Subject: [PHP-DB] Date problem Hi there everyone, I use the below code to grab the current date, convert it to a unix timestamp to do some bits then it's supposed to change the date back with the new values (IE: current date - x amount of seconds) but it's not doing it correctly, it's probably DEAD obvious to everyone as my brain has probably fried :-) But here's the code, when I convert it back to d,m,Y it says it's 2004 which it shouldn't. Thanks Chris --- $secsinweek = 604800; $numweeks = $secsinweek * 7; $curdate = date(d-m-Y); // Split the strings into day, month, year list($cd, $cm, $cy) = split(-, $curdate); // Create unix time stamps for the start and end date $now = mktime(0,0,0,$cd,$cm,$cy); // Do some number crunching here // $newnow = $now-$numweeks; echo $now; $converted_date = date(d-m-y,$now); echo br$converted_date;
RE: [PHP-DB] mysql_fetch_array issues.
Do you have select permissions on that DB/table?
If you have GRANT permissions, try
GRANS SELECT, INSERT, UPDATE, DELETE ON db.tablename to
'youruser'@'your.ip.address' IDENTIFIED BY 'yourpassword';
your.ip.address can be substituted with localhost if you're on the same box.
Gary Every
Sr. UNIX Administrator
Ingram Entertainment
(615) 287-4876
Pay It Forward
mailto:[EMAIL PROTECTED]
http://accessingram.com
-Original Message-
From: Greg Hetrick [mailto:[EMAIL PROTECTED]
Sent: Wednesday, July 09, 2003 12:31 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] mysql_fetch_array issues.
I do not have the die statment -- the DB is the same except
the name and I
have double checked that I just did a back up of the previous
db and moved
it to the new server. I have done some more digging, my query
appears to
work, but I almost appears that I have a problem with selecting the
database --
if I comment out the mysql_select -- statment I get the same
error, perhaps
I just can't get to that DB.
intresting.
I guess I can assume at this point there is something flaky with my DB
Jeffrey N Dyke [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Do you have an 'or die(mysql_error())' statement following your
mysql_query($result) line. 99% of the time, this error
means your query
failed. if it works on another serverare the fields
the same, the
dbname, the tablename?
hth
jeff
Greg Hetrick
[EMAIL PROTECTED]To:
[EMAIL PROTECTED]
net cc:
Subject: [PHP-DB]
mysql_fetch_array issues.
07/09/2003 12:04
PM
I am getting the following error when attempting to pull
data out of a
mysql
DB
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL
result
resource in
/home/pffl/public_html/pffl/webpage/html/dataentry.php on line
125
I can take this same code to a different web server and it
is pulling
correctly!
I am currently running Apache 2.0.46 with PHP 4.3.2 I was
running Apache
1.3.x with PHP 4.3.1 and getting the same thing, any ideas?
here is the
chunk of code where I use the function.
while ($myrow=mysql_fetch_array($result))
{
?
option value=?print $myrow['name'];?, ?print
$myrow['team'];? ? echo $myrow[name]; ?/option
?
}
Any Ideas.
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RE: [PHP-DB] Reading from a file
Looks like the first question was answered correctly, for the second one look at the ltrim and rtrim functions. $var = ; $var = rtrim($var); echo :$var:; output is :: Gary Every Sr. UNIX Administrator Ingram Entertainment (615) 287-4876 Pay It Forward mailto:[EMAIL PROTECTED] http://accessingram.com -Original Message- From: Rick Dahl [mailto:[EMAIL PROTECTED] Sent: Tuesday, July 01, 2003 11:11 AM To: [EMAIL PROTECTED] Subject: [PHP-DB] Reading from a file I need to read from a file that is tab delimited. Is there anyway to specify that it reads between each tab and that is it. I know fread() uses bytes to figure out what to read but that isn't very practical in my case. Also, how do I get rid of any white space at the end of a variable if there is some once it is read in? - Rick
RE: [PHP-DB] Splitting Product Catalogue Over Multiple Pages?
If you're trying to do paging, it's quite simple (there are tons of examples
out there, search google for paging php)
$sql = select count(*) from table_name
$number_of_records = mysql_query($sql);
$pointer=0;
$recs_per_page=20;
if($number_of_records $recs_per_page) {
// do a limit and keep the pointer
$sql = select * from other_table limit $pointer,$recs_per_page;
$pointer += $recs_per_page;
This isn't complete by any means but the point should be clear. You limit
the query by LIMIT starting_point,number_of_records_to_return at the end
of the sql statement.
Don't worry about the values in the column, just the amount of records you
want to return
Gary Every
Sr. UNIX Administrator
Ingram Entertainment
(615) 287-4876
Pay It Forward
mailto:[EMAIL PROTECTED]
http://accessingram.com
-Original Message-
From: Boa Constructor [mailto:[EMAIL PROTECTED]
Sent: Thursday, June 26, 2003 10:25 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Splitting Product Catalogue Over Multiple Pages?
Greetings all, I'm not sure if this has been discussed
recently, I've read
bits and pieces and I can't remember where I read everything
so if it has
been brought up recently - sorry.
If I do an SQL (MySQL) query on the first example to get the
min and max IDs
then I will get 1 and 6 respectively. I will then be able to
loop from 1 to
6 and return all 6 products from the database. If however I
wanted to split
this in to two pages with 3 items in each page then using the
first example
below I could grab the min ID and add 2 to it to make 3. I
could not do
this using the second example because if I grab the min ID I
would get 3, if
I add 2 to it then I would get 5. 5 does not exit in this
table so that
wouldn't work. How in example 2 would I be able to split
this over two
pages?
//example 1
ID Product_Name
1 Hoover
2 Kettle
3 Fridge
4 Cooker
5 Food Mixer
6 TV
//example 2
ID Product_Name
3 Fridge
4 Cooker
7 Microwave Oven
8 Freezer
9 DVD Player
10 Computer
Any ideas?
Anything is much appreciated.
Graeme :)
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RE: [PHP-DB] Splitting Product Catalogue Over Multiple Pages?
LIMIT 0,10 will return the first ten records of a result set. To make more
sense, you should do an ORDER BY of some field to get the info sorted
correctly.
LIMIT takes 1 or two arguments
If there is only one argument, say 10, it will return the first ten records.
If there are two arguments, LIMIT 20,10 it will return 10 records starting
at record 20.
More info at
http://www.mysql.com/doc/en/SELECT.html
Search for limit on that page.
Gary Every
Sr. UNIX Administrator
Ingram Entertainment
(615) 287-4876
Pay It Forward
mailto:[EMAIL PROTECTED]
http://accessingram.com
-Original Message-
From: Boa Constructor [mailto:[EMAIL PROTECTED]
Sent: Friday, June 27, 2003 9:20 AM
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Splitting Product Catalogue Over Multiple Pages?
Gary, thanks for your reply, I think I'll need 2 have a think
about this. I
didn't totally understand:
You limit
the query by LIMIT
starting_point,number_of_records_to_return at the end
of the sql statement.
I've never used LIMIT before, could you explain this a bit
more or point me
to some info?
Cheers,
Graeme :)
- Original Message -
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Friday, June 27, 2003 2:39 PM
Subject: RE: [PHP-DB] Splitting Product Catalogue Over Multiple Pages?
If you're trying to do paging, it's quite simple (there are tons of
examples
out there, search google for paging php)
$sql = select count(*) from table_name
$number_of_records = mysql_query($sql);
$pointer=0;
$recs_per_page=20;
if($number_of_records $recs_per_page) {
// do a limit and keep the pointer
$sql = select * from other_table limit $pointer,$recs_per_page;
$pointer += $recs_per_page;
This isn't complete by any means but the point should be
clear. You limit
the query by LIMIT
starting_point,number_of_records_to_return at the end
of the sql statement.
Don't worry about the values in the column, just the amount
of records you
want to return
Gary Every
Sr. UNIX Administrator
Ingram Entertainment
(615) 287-4876
Pay It Forward
mailto:[EMAIL PROTECTED]
http://accessingram.com
-Original Message-
From: Boa Constructor [mailto:[EMAIL PROTECTED]
Sent: Thursday, June 26, 2003 10:25 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Splitting Product Catalogue Over Multiple Pages?
Greetings all, I'm not sure if this has been discussed
recently, I've read
bits and pieces and I can't remember where I read everything
so if it has
been brought up recently - sorry.
If I do an SQL (MySQL) query on the first example to get the
min and max IDs
then I will get 1 and 6 respectively. I will then be able to
loop from 1 to
6 and return all 6 products from the database. If however I
wanted to split
this in to two pages with 3 items in each page then using the
first example
below I could grab the min ID and add 2 to it to make 3. I
could not do
this using the second example because if I grab the min ID I
would get 3, if
I add 2 to it then I would get 5. 5 does not exit in this
table so that
wouldn't work. How in example 2 would I be able to split
this over two
pages?
//example 1
ID Product_Name
1 Hoover
2 Kettle
3 Fridge
4 Cooker
5 Food Mixer
6 TV
//example 2
ID Product_Name
3 Fridge
4 Cooker
7 Microwave Oven
8 Freezer
9 DVD Player
10 Computer
Any ideas?
Anything is much appreciated.
Graeme :)
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RE: [PHP-DB] md5 question!
It's all dependent on the seed the first two characters of the hash
You take a password, say apass and pass it through md5
Say you get :
dFeRDfss3456fdddsas/..
When the user types in their password, this is what happens
The string above is retrieved, and the password entered, apass is run
through md5 WITH THE KNOWN SEED, dF
The output of md5 will be
dFeRDfss3456fdddsas/..
and it is compared to what is stored. If they match, hunky-dory, the auth is
granted
Upon creating an md5 hash, the seed is randomly generated, so that two users
with the same password may have completely different hash strings.
Gary Every
Sr. UNIX Administrator
Ingram Entertainment
(615) 287-4876
Pay It Forward
mailto:[EMAIL PROTECTED]
http://accessingram.com
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Sent: Tuesday, June 24, 2003 4:47 AM
To: JeRRy; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] md5 question!
They would be the same, they have to be. If you can de-crypt
it, there has to
be some method of validation. So, if someone choose the same
password as you
did, and you stored those in a DB as encrypted with md5, then
they would look
identical. So, you would know the other person's password.
Hi,
Hmmm okay... So if the passowrd was.
jerry
and the md5 output was
SKHDJHDJDHJDHSfdfs
and another user sets their passowrd to the same as
mine does that mean the md5 output would be identical
to the last as the same password is entered?
e.g.
User 1:
Username: Fred
Password: jerry
User 2:
Username: notfred
Password: jerry
Or is each entry unique ?
I'm thinking if each entry was unique than reversing
the md5 action could be inconclusive. But if the
output is the same if the same password is entered
than sure it's reliable. But I could be barking up
the wrong tree all together here, so correct me if I
am wrong. I have not used md5 before so learning on
that behalf.
Jerry
--- [EMAIL PROTECTED] wrote: Just use brute
force...
Example:
md5('password') will ALWAYS produce the same output!
So, if I intercept a pmd5 encrypted password that
looks like: SKHGDOIUYFB
then I could just say:
if (strcmp (md5('password'), SKHGDOIUYFB) == 0)
printf(Your password is: %s\n, password);
So, just start a loop going through all possible
combinations od legal password
character and encrypt with md5, then compare.
Hard? Not at all, Time consuming, perhaps, but with
3+ Ghz processors coming
out you'd be surprised how quickly one could loop
through billlions of possible
password combinations. Enter distributed
environments and it is much fatser.
The key is not to rely on passwords but to rely on
other system security
messures, use SSL, so it is hard to intercept in the
first place, make sure
your system is secure so these passwords cannot be
extracted from your DB
without you knowing about it, etc...
Marco,
Thanks, that's what I originally thought that it
was
one way. So websites that have the option to
retrieve
password don't use md5?
I guess technically there MUST be a way to break
the
barrier where you can reverse it. If there is a
way
to make it there is always a way to break it,
somehow.
But what I have heard and read it's very
tight
and probably the best method to handle passwords
for
now, until something new is released. Which will
happen when md5 is broken, like everything else
after
a little bit of time.
Jerry
--- Marco Tabini [EMAIL PROTECTED] wrote: Hi
Jerry--
No, md5 is a one-way hash. That's why it's so
safe--because if someone
steals the information he still can't tell what
the
passwords are.
You may want to reset the passwords upon your
users'
request and send it
to them via e-mail instead.
Cheers,
Marco
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On Tue, 2003-06-24 at 08:35, JeRRy wrote:
Hi,
If I use md5 to handle passwords to my
database is
there a way to reverse the action if someone
forgets
their password? Is there a way for me to
decode
the
32bit to plain text?
Jerry
http://mobile.yahoo.com.au - Yahoo! Mobile
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Telstra or Vodafone mobile.
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President
Marco Tabini Associates, Inc.
28 Bombay Avenue
Toronto, ON M3H 1B7
Canada
Phone: (416) 630-6202
Fax: (416) 630-5057
Web: http://www.tabini.ca
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RE: [PHP-DB] Two-column display of data, second method
You could always use the % operand
snip
$cols_wanted = 2;
if(($faculty_found % $cols_wanted) == 0) {
// Then do a TR
echo 'tr';
} else {
// Then it's the first column, and don't end the row
}
/snip
This also simplifies it so that you can decide to use three, four or five
columns, just by changing the $cols_wanted variable
Gary Every
Sr. UNIX Administrator
Ingram Entertainment
(615) 287-4876
Pay It Forward
mailto:[EMAIL PROTECTED]
http://accessingram.com
-Original Message-
From: Becoming Digital [mailto:[EMAIL PROTECTED]
Sent: Thursday, June 19, 2003 5:01 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Two-column display of data, second method
Nice job. There's a fair bit of room for optimization, but
unless your data
sets are very large, it's probably not necessary. However,
if you're compulsive
(as I tend to be), you'll optimize every bit of code to the
best of your
abilities. And yes, I know I'm crazy. ;P
Edward Dudlik
Becoming Digital
www.becomingdigital.com
- Original Message -
From: David Shugarts [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, 19 June, 2003 17:43
Subject: [PHP-DB] Two-column display of data, second method
When I went looking for a script that would give me a
two-column layout that
would list my faculty members in two roughly equal columns,
alphabetized
down the first column and then the second, I did not find
such a script.
[There was indeed a two-column script, but it fed the data
row-by-row.]
I wrote this one and am glad to share it. The math statements
could surely
be condensed, but I was using them to confirm the results. This script
either creates two equal columns if the total number of items
is even, or it
makes the first column the longer if the total number of items is odd.
--Dave Shugarts
?php
/* *** Now selects the Faculty names ** */
$sql =SELECT FirstName, Middle, LastName
FROM $table_name
ORDER BY LastName, FirstName;
/* ** Now passes the result of the search ** */
$faculty_result = @mysql_query($sql, $connection) or die(Error #.
mysql_errno() . : . mysql_error());
$faculty_found = @mysql_num_rows($faculty_result);
$faculty_half = $faculty_found / 2;
$faculty_round = round($faculty_found / 2);
$faculty_remain = $faculty_found - $faculty_round;
echo table border=0
trtd colspan=2 align=centerb
Two-Column header
/bbr/td/tr
trtd width=49%\n;
for ($rownum = 1; $rownum = $faculty_round; $rownum++)
{
$row = mysql_fetch_array($faculty_result);
$FirstName=$row['FirstName'];
$Middle=$row['Middle'];
$LastName=$row['LastName'];
$faculty_block =
font class=facultydoc
$FirstName $Middle $LastName
/font
br
;
echo $faculty_blockbr;
}
echo /tdtd\n;
for ($rownum = 1; $rownum = $faculty_remain; $rownum++)
{
$row = mysql_fetch_array($faculty_result);
$FirstName=$row['FirstName'];
$Middle=$row['Middle'];
$LastName=$row['LastName'];
$faculty_block =
font class=facultydoc
$FirstName $Middle $LastName
/font
br
;
echo $faculty_blockbr;
}
echo /td/trbr/table;
?
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RE: [PHP-DB] Limit return Size
Or $sql = SELECT concat(LEFT(columnName,255),...) FROM tableName; Gary Every Sr. UNIX Administrator Ingram Entertainment (615) 287-4876 Pay It Forward mailto:[EMAIL PROTECTED] http://accessingram.com -Original Message- From: Hutchins, Richard [mailto:[EMAIL PROTECTED] Sent: Friday, June 20, 2003 2:46 PM To: [EMAIL PROTECTED] Subject: RE: [PHP-DB] Limit return Size Try: $sql = SELECT LEFT(columnName,255) FROM tableName; Using that syntax should return the first 255 characters from the selected column, reading LEFT to right. I tested it in the command line and it worked just fine. Hope that helps. Rich -Original Message- From: Marie Osypian [mailto:[EMAIL PROTECTED] Sent: Friday, June 20, 2003 3:06 PM To: [EMAIL PROTECTED] Subject: [PHP-DB] Limit return Size I would like to know how I limit my answer from a mysql database query to display only a limited size? Is this done in the query or the php? i.e. Our Performance Results area includes First Quarter 2003 investment returns for virtually every 529 savings programs. See how your 529 plan performed... This question is alot longer but it was stopped and ... added when it reached the desired size. Thanks MAO -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Problems with formvalues by using Suse 8.2
To protect yourself by keeping register_globals off but still have access to
your GET and POST info, do the following:
snip
foreach($_POST as $key=$value) {
$$key = $value;
}
// Now all the post vars are in their corresponding key names
// You can do the same with $_GET vars
/snip
Using the $$key assigns whatever $key is to a variable with that value, e.g.
$key = sid;
$value = W;
So:
$$key = $value;
will make the following true:
$sid == W;
It's a pretty good way of re-doing pages that were written with
register_globals=on to run with register_globals=off
Gary Every
Sr. UNIX Administrator
Ingram Entertainment
(615) 287-4876
Pay It Forward
mailto:[EMAIL PROTECTED]
http://accessingram.com
-Original Message-
From: Thorsten Körner [mailto:[EMAIL PROTECTED]
Sent: Thursday, June 19, 2003 2:05 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Problems with formvalues by using Suse 8.2
Hi
Am Donnerstag, 19. Juni 2003 20:07 schrieb Ruprecht Helms:
Hi,
under using Suse 8.2 I've the problem that the values of
formfields will be
put out or worked withit within a phpscript.
The testscript with phpinfo() is working fine.
What have I to set (in the php.ini) that php is handling the
formfieldvalues properly?
Seems to be a little bit OT here.
Your question is not very precise, but I'll give it a try.
Depending on your form-method, you can request the values by
accessing either
$_GET['formfieldname'] or $_POST['formfieldname'] where
formfieldname has to
be replaced by the real names of the fields.
Hope that's it.
CU
Thorsten
--
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RE: [PHP-DB] Ignoring specific values in an inner join query?
$abfrage3=select distinct Anschriften.ID as aid, Anschriften.PLZ as aplz, Anschriften.STRASSE as astrasse, Anschriften.HNR as ahnr from Anschriften inner join Master on Anschriften.ID=Master.A inner join Master as m on Master.FN=m.FN inner join Personen on m.NN=Personen.ID where Personen.Name like '%$name%' AND whatever_field_you_want IS NOT NULL AND whatever_other_field IS NOT NULL; Gary Every Sr. UNIX Administrator Ingram Entertainment (615) 287-4876 Pay It Forward mailto:[EMAIL PROTECTED] http://accessingram.com -Original Message- From: Andr Sannerholt [mailto:[EMAIL PROTECTED] Sent: Tuesday, June 10, 2003 10:42 AM To: [EMAIL PROTECTED] Subject: [PHP-DB] Ignoring specific values in an inner join query? Hi everybody. How to let mysql ignore specific values in an inner join query? In this case I want it to ignore Null-Values! $abfrage3=select distinct Anschriften.ID as aid, Anschriften.PLZ as aplz, Anschriften.STRASSE as astrasse, Anschriften.HNR as ahnr from Anschriften inner join Master on Anschriften.ID=Master.A inner join Master as m on Master.FN=m.FN inner join Personen on m.NN=Personen.ID where Personen.Name like '%$name%'; Regards André -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Calling Stored Procedures of Oracle in php
If this is a cut-n-paste of the code, check the line below for spelling:
begin prcoedurename('[EMAIL PROTECTED]','3');end;;
^^^
Gary Every
Sr. UNIX Administrator
Ingram Entertainment
(615) 287-4876
Pay It Forward
mailto:[EMAIL PROTECTED]
http://accessingram.com
-Original Message-
From: Ketan Parekh [mailto:[EMAIL PROTECTED]
Sent: Friday, June 06, 2003 9:24 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Calling Stored Procedures of Oracle in php
Hi,
I want to call a oracle stored procedure from php and
retrieve the values.
My procedure has 2 parameters which i have to pass and based
on that it will
return values. I am using the below code. I am getting errors
like wrong
arguements passed. Can anybody tell me the reason?
$conn = ora_logon(abc,xyz);
$curs = ora_open($conn);
$query = begin prcoedurename('[EMAIL PROTECTED]','3');end;;
ora_parse($curs, $query);
ora_exec($curs);
ora_fetch($curs);
$nrows = ora_numrows($curs);
echo $nrows;
exit;
--
Thanks,
Ketan Parekh
-
Cybage Software Pvt Ltd.
6686359 Ext 235
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RE: [PHP-DB] Datetime help in an INSERT...
1. Change your field name from date to something like datefield (or backtick
it)
2. Place single quotes within your VALUES parens, e.g.
$denylog = INSERT INTO deny (account, td, datefield ) VALUES ('$tmp',
'$td', NOW() )
Gary Every
Sr. UNIX Administrator
Ingram Entertainment
(615) 287-4876
Pay It Forward
mailto:[EMAIL PROTECTED]
http://accessingram.com
-Original Message-
From: NIPP, SCOTT V (SBCSI) [mailto:[EMAIL PROTECTED]
Sent: Wednesday, June 04, 2003 2:06 PM
To: 'Rankin, Randy'; '[EMAIL PROTECTED]'
Subject: RE: [PHP-DB] Datetime help in an INSERT...
No, the field is a Datetime field rather than a Timestamp field.
-Original Message-
From: Rankin, Randy [mailto:[EMAIL PROTECTED]
Sent: Wednesday, June 04, 2003 1:59 PM
To: '[EMAIL PROTECTED]'
Subject: RE: [PHP-DB] Datetime help in an INSERT...
Correction ( I typed this in a hurry ) ...
If you are using MySql and the date field is of type
timestamp, you should
_not_
have to insert anything using the query. It will update
automatically when
the record is inserted and/or updated.
ie; $denylog = INSERT INTO deny (account, td ) VALUES ($tmp, $td );
Randy
-Original Message-
From: Rankin, Randy [mailto:[EMAIL PROTECTED]
Sent: Wednesday, June 04, 2003 1:56 PM
To: '[EMAIL PROTECTED]'
Subject: RE: [PHP-DB] Datetime help in an INSERT...
If you are using MySql with the date field is of type
timestamp, you should
have to insert anything using the query. It will update
automatically when
the record is inserted and/or updated.
ie; $denylog = INSERT INTO deny (account, td ) VALUES ($tmp, $td );
Randy
-Original Message-
From: NIPP, SCOTT V (SBCSI) [mailto:[EMAIL PROTECTED]
Sent: Wednesday, June 04, 2003 1:47 PM
To: '[EMAIL PROTECTED]'
Cc: '[EMAIL PROTECTED]'
Subject: RE: [PHP-DB] Datetime help in an INSERT...
The error I am receiving is:
You have an error in your SQL syntax near ' NOW())' at line 1
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Sent: Wednesday, June 04, 2003 1:45 PM
To: NIPP, SCOTT V (SBCSI)
Subject: Re: [PHP-DB] Datetime help in an INSERT...
what kind of error are you getting?
I am stumbling across something that I thought I have
done before,
and I am not having any luck finding an example of this.
Basically, I am
wanting to timestamp the date and time into new entries in a simple
database
table. The following section is the actual code for this,
and I cannot
figure out how to get the date/time stamp to populate into
the database.
Thanks in advance for the help. I suspect this is a very
simple fix.
$denylog = INSERT INTO deny (account, td, date) VALUES ($tmp, $td,
NOW());
$denylog_result = mysql_query($denylog, $Prod) or
die(mysql_error());
Scott Nipp
Phone: (214) 858-1289
E-mail: [EMAIL PROTECTED]
Web: http:\\ldsa.sbcld.sbc.com
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[PHP-DB] Test
Sorry about the test, but . . .
RE: [PHP-DB] Array Question
CartArray['itemid'] = $itemid; note where $qty = CartArray['qty']; /note Gary Every Sr. UNIX Administrator Ingram Entertainment (615) 287-4876 Pay It Forward mailto:[EMAIL PROTECTED] http://accessingram.com -Original Message- From: Boa Constructor [mailto:[EMAIL PROTECTED] Sent: Monday, June 02, 2003 2:27 PM To: [EMAIL PROTECTED] Subject: [PHP-DB] Array Question Hello everyone. If I wanted to pass a item ID along with a quantity to an associative array called CartArray how would I pass it to the PHP script? I'll get this shopping cart working yet !! Cheers, Graeme :) -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Permission Denied; Upload
Unable to open '' for reading: That means you're not actually sending a filename to be read! I get this error during test of the above page: Warning: Unable to open '' for reading: Permission denied in C:\SammiWWW\entry.php on line 27 Couldn't copy the file!
[PHP-DB] Anybody out there?
Is the list active? I've seen nothing all day. Gary Every Sr. UNIX Administrator Ingram Entertainment (615) 287-4876 Pay It Forward mailto:[EMAIL PROTECTED] http://accessingram.com
RE: [PHP-DB] Login and link back...
Have you thought about using BASIC AUTH in Apache? That way, you don't even
need to build a login page, just authenticate each page. Here's what we use:
Note that some of the functions used in this script are not included, and
need to be commented out or a function written for them. It's rather
self-explanatory.
We also create a .htaccess file with all the username/passwords in a central
location. You'll need to modify tour httpd.conf file to look in that central
location for all the pages.
## Function: check_auth()
## Description: Checks authentication against the mysql user info database
and
##verifies the password. This function is absolutely critical.
##If it's not right, you could be letting people into the website
##unintentionally. Always make sure that login failure occurs
##unless you have a positive ID!!!
## Additionally it determines if the user has read and digitally
accepted
##IEI's liability statement by calling liability_statment_check().
## Arguments: none
## Returns: success- returns true
##failure- exits via auth_header()
function check_auth() {
global
$conn_id,$PHP_AUTH_USER,$PHP_AUTH_PW,$PHP_AUTH_REALM,$REQUEST_URI,$sid;
global $WEBUSER_TABLE,$WEBAUTH_TABLE;
global $redirect;
# The only way out of this function is:
# 1) A recursive call to auth_header()
# 2) A TRUE return to the caller
# Is USER and PASS set?
if( !isset($PHP_AUTH_USER) || !isset($PHP_AUTH_PW)) {
if ($redirect=='y'){
log_it(LOG_DEBUG,caught redirect);
auth_header($PHP_AUTH_REALM);
} else {
log_it(LOG_DEBUG,redirecting);
Header(Location: /index.php?redirect=y);
exit();
}
}
# Does USER have trailing whitespace? BAD MYSQL!
if (ereg(' +$',$PHP_AUTH_USER)){
auth_header($PHP_AUTH_REALM);
}
# Is USER known to the system?
$sql = SELECT * FROM $WEBUSER_TABLE WHERE
web_user_id='$PHP_AUTH_USER' AND web_password='$PHP_AUTH_PW';
$row = get_row($conn_id,$sql);
if($row is_array($row)) {
# Yes, so...
# See if they've been disabled
if($row['web_access_level'] == 'D'){
## Start the Auth over again
## auth_header($PHP_AUTH_REALM);
## include('/error_disabled.php');
Header(Location: /error_disabled.php);
exit();
}
# Check logged_in state
$sql = SELECT logged_in FROM $WEBAUTH_TABLE WHERE
web_user_id='$PHP_AUTH_USER';
$row = get_row($conn_id,$sql);
if(!$row || !is_array($row)) {
# First time login for USER, let him through
authorize_user($PHP_AUTH_USER);
return(TRUE);
} else {
# RETURN POINT FROM FUNCTION
# USER's logged_in status is something other than 'N' which is
acceptable
# for access
if ($row['logged_in'] != 'Y'){
update_logged_in_status($PHP_AUTH_USER,'Y');
if ($redirect!='y') auth_header($PHP_AUTH_REALM);
} else {
log_it(LOG_INFO,checkauth() SUCCESS: user=$PHP_AUTH_USER
pass=NO-SOUP-FOR-YOU-TOO);
# update_logged_in_status($PHP_AUTH_USER,'Y');
}
}
liability_statement_check();
return(TRUE);
} else {
# USER NOT KNOWN
auth_header($PHP_AUTH_REALM);
}
}
Gary Every
Sr. UNIX Administrator
Ingram Entertainment
(615) 287-4876
Pay It Forward
mailto:[EMAIL PROTECTED]
http://accessingram.com
-Original Message-
From: NIPP, SCOTT V (SBCSI) [mailto:[EMAIL PROTECTED]
Sent: Wednesday, March 19, 2003 10:39 AM
To: '[EMAIL PROTECTED]'
Subject: [PHP-DB] Login and link back...
I am curious about what you guys may have along the
lines of best
practices for forwarding from a URL to a login, and then
jumping back to the
original URL automatically. I have several separate
applications that all
need to utilize the same login mechanism. I want the user to
be able to
enter the URL for the application and if they are not logged
in it redirects
them to a login screen. I already have the sessions junk setup and
understand all of that portion. I am mainly interested in
how people are
handling the return to a URL after successful login.
I have done some research on this, and discovered the
$HTTP_REFERER
variable however the PHP site discourages using this. I have
also thought
of adding code to each page to export an origin variable to
be passed to
the login page such that it can be used to return the user.
I thought of
this method, but I am not real clear on how to manage this.
Does anyone
have any suggestion on implementing this, or another
alternative that I have
not touched on yet? Thanks in advance.
Scott Nipp
Phone: (214) 858
RE: [PHP-DB] SELECT * FROM Command *REVISED*
SELECT * FROM tablename WHERE zipcode='$zipcode' ORDER BY entered_date;
Gary Every
Sr. UNIX Administrator
Ingram Entertainment
(615) 287-4876
Pay It Forward
mailto:[EMAIL PROTECTED]
http://accessingram.com
-Original Message-
From: Michelle Whelan [mailto:[EMAIL PROTECTED]
Sent: Wednesday, March 19, 2003 1:04 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] SELECT * FROM Command *REVISED*
-Ok, this is what I have. I hope this is what you are
looking for. I'm looking to format this search results page
so that the results come back with the entire entry that also
matches the zipcode that was searched.
ex: zipcode search = 90210
results for 90210 are:
contactname
phone number
city
date posted
etc.
AND, somehow ( I'm thinking ordered list) to have a format
for multiple results sorted by date.
Is this possible?
Thanks again in advance
Michael
html
head
titlewww..com/title
/head
body BACKGROUND=images/dirt.gif text=#FF
link=#FF vlink=#00 alink=#00 BGPROPERTIES=fixed
?
/* MySQL details */
$dbHost = mysql;
$dbUser = ;
$dbPass = ;
$dbName = ;
$table = havedirt;
/* Attempt connection to MySQL server */
$link = @mysql_connect($dbHost, $dbUser, $dbPass);
/* If connection wasnt successful... */
if (!$link)
{
print (bError:/b Could not connect to database.);
exit;
}
/* Attempt to select our database */
if ([EMAIL PROTECTED]($dbName))
{
print(bError:/b Could not find $dbName database.);
exit;
}
$ZipCode = $_POST[zipcode];
/* Build SQL query to fetch all entries from the table */
$query = SELECT * FROM $table WHERE zipcode = $ZipCode;
/* Execute query */
$result = mysql_query($query);
/* If there was a problem with the query... */
if (!$result || @mysql_num_rows($result) 1)
{
print(No entries in table $table.);
exit;
}
print(table);
/* For each table entry returned... */
while($row = mysql_fetch_array($result))
{
/* Add details to output variable */
print(trtd . $row['zipcode'] . /td);
print(tr);
}
print(/table);
/* Close link to MySQL */
mysql_close($link);
?
/body
/html
RE: [PHP-DB] Column Sort Question
Shouldn't you be using $_GET or, since register_globals are set to off, $order_by should contain FIRSTNAME Gary Every Sr. UNIX Administrator Ingram Entertainment (615) 287-4876 Pay It Forward mailto:[EMAIL PROTECTED] http://accessingram.com -Original Message- From: Jerry [mailto:[EMAIL PROTECTED] Sent: Wednesday, March 05, 2003 3:40 PM To: [EMAIL PROTECTED] Subject: [PHP-DB] Column Sort Question Hi All, This is a newbie question. I am using PHP Version 4.2.3 with register_globals=off. I am trying to creating a simple address book with mysql as the backend. I have a form that passes what the user wants to query from the address book and it returns everything in a table with column heading just fine. I use $myvar1=$_POST['myvar1']; to pass the info from the form to the php file. I am using the following in the header fields of the table: th nowrap a href=?php echo $PHP_SELF?order_by=FIRSTNAME; ?First Name/a /th This doesn't work (I get a bunch of errors) and I think it's because the variable from $_POST are not staying persistent. I tried playing around with session with no luck. What is the best way to resort on a column? Thanks, Jerry -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
