Re: The seven step-Mathematical preliminaries

2009-06-17 Thread Quentin Anciaux

2009/6/17 Torgny Tholerus tor...@dsv.su.se:

 Bruno Marchal skrev:
 Torgny,

 I agree with Quentin.
 You are just showing that the naive notion of set is inconsistent.
 Cantor already knew that, and this is exactly what forced people to
 develop axiomatic theories. So depending on which theory of set you
 will use, you can or cannot have an universal set (a set of all sets).
 In typical theories, like ZF and VBG (von Neuman Bernay Gödel) the
 collection of all sets is not a set.

 It is not the naive notion of set that is inconsistent.  It is the naive
 *handling* of sets that is inconsistent.

 This problem has two possible solutions.  One possible solution is to
 deny that it is possible to create the set of all sets.  This solution
 is chosen by ZF and VBG.

 The second possible solution is to be very careful of the domain of the
 All quantificator.  You are not allowed to substitute an object that is
 not included in the domain of the quantificator.  It is this second
 solution that I have chosen.

 What is illegal in the two deductions below, is the substitutions.
 Because the sets A and B do not belong to the domain of the All
 quantificator.

 You can define existence by saying that only that which is incuded in
 the domain of the All quantificator exists.  In that case it is correct
 to say that the sets A and B do not exist, because they are not included
 in the domain.  But I think this is a too restrictive definition of
 existence.  It is fully possible to talk about the set of all sets.  But
 you must then be *very* careful with what you do with that set.  That
 set is a set, but it does not belong to the set of all sets, it does not
 belong to itself.  It is also a matter of definition; if you define
 set as the same as belonging to the set of all sets, then the set of
 all sets is not a set.  This is a matter of taste.  You can choose
 whatever you like, but you must be aware of your choice.  But if you
 restrict yourself too much, then your life will be poorer...

  In NF, some have developed
 structure with universal sets, and thus universe containing
 themselves. Abram is interested in such universal sets. And, you can
 interpret the UD, or the Mandelbrot set as (simple) model for such
 type of structure.

 Your argument did not show at all that the set of natural numbers
 leads to any trouble. Indeed, finitism can be seen as a move toward
 that set, viewed as an everything, potentially infinite frame (for
 math, or beyond math, like it happens with comp).

 The problem of naming (or given a mathematical status) to all sets
 is akin to the problem of giving a name to God. As Cantor was
 completely aware of. We are confused on this since we exist. But the
 natural numbers, have never leads to any confusion, despite we cannot
 define them.


 The proof that there is no biggest natural number is illegal, because
 you are there doing an illegal deduction, you are there doing an illegal
 substitution, just the same as in the deductions below with the sets A
 and B.  You are there substituting an object that is not part of the
 domain of the All quatificator.

No the proof is based on PA and in PA you do not have an axiom
restricting the successor function and as such it is defined in the
axiom that you don't have an upper bound limit. The proof is *valid*
against the axioms. *You* are doing an illegal deduction by not taking
into accound the rules with wich you work.

Regards,
Quentin

 --
 Torgny Tholerus

 You argument against the infinity of natural numbers is not valid. You
 cannot throw out this little infinite by pointing on the problem
 that some terribly big infinite, like the set of all sets,  leads
 to trouble. That would be like saying that we have to abandon all
 drugs because the heroin is very dangerous.
 It is just non valid.

 Normally, later  I will show a series of argument very close to
 Russell paradoxes, and which will yield, in the comp frame,
 interesting constraints on what computations are and are not.

 Bruno


 On 13 Jun 2009, at 13:26, Torgny Tholerus wrote:


 Quentin Anciaux skrev:

 2009/6/13 Torgny Tholerus tor...@dsv.su.se:


 What do you think about the following deduction?  Is it legal or
 illegal?
 ---
 Define the set A of all sets as:

 For all x holds that x belongs to A if and only if x is a set.

 This is an general rule saying that for some particular symbol-
 string x
 you can always tell if x belongs to A or not.  Most humans who think
 about mathematics can understand this rule-based definition.  This
 rule
 holds for all and every object, without exceptions.

 So this rule also holds for A itself.  We can always substitute A
 for
 x.  Then we will get:

 A belongs to A if and only if A is a set.

 And we know that A is a set.  So from this we can deduce:

 A beongs to A.
 ---
 Quentin, what do you think?  Is this deduction legal or illegal?


 It depends if you allow a set to be part of itselft or not.

 If you 

Re: The seven step-Mathematical preliminaries

2009-06-17 Thread Torgny Tholerus

Bruno Marchal skrev:
 Torgny,

 I agree with Quentin.
 You are just showing that the naive notion of set is inconsistent.  
 Cantor already knew that, and this is exactly what forced people to  
 develop axiomatic theories. So depending on which theory of set you  
 will use, you can or cannot have an universal set (a set of all sets).  
 In typical theories, like ZF and VBG (von Neuman Bernay Gödel) the  
 collection of all sets is not a set.

It is not the naive notion of set that is inconsistent.  It is the naive 
*handling* of sets that is inconsistent.

This problem has two possible solutions.  One possible solution is to 
deny that it is possible to create the set of all sets.  This solution 
is chosen by ZF and VBG.

The second possible solution is to be very careful of the domain of the 
All quantificator.  You are not allowed to substitute an object that is 
not included in the domain of the quantificator.  It is this second 
solution that I have chosen.

What is illegal in the two deductions below, is the substitutions.  
Because the sets A and B do not belong to the domain of the All 
quantificator.

You can define existence by saying that only that which is incuded in 
the domain of the All quantificator exists.  In that case it is correct 
to say that the sets A and B do not exist, because they are not included 
in the domain.  But I think this is a too restrictive definition of 
existence.  It is fully possible to talk about the set of all sets.  But 
you must then be *very* careful with what you do with that set.  That 
set is a set, but it does not belong to the set of all sets, it does not 
belong to itself.  It is also a matter of definition; if you define 
set as the same as belonging to the set of all sets, then the set of 
all sets is not a set.  This is a matter of taste.  You can choose 
whatever you like, but you must be aware of your choice.  But if you 
restrict yourself too much, then your life will be poorer...

  In NF, some have developed  
 structure with universal sets, and thus universe containing  
 themselves. Abram is interested in such universal sets. And, you can  
 interpret the UD, or the Mandelbrot set as (simple) model for such  
 type of structure.

 Your argument did not show at all that the set of natural numbers  
 leads to any trouble. Indeed, finitism can be seen as a move toward  
 that set, viewed as an everything, potentially infinite frame (for  
 math, or beyond math, like it happens with comp).

 The problem of naming (or given a mathematical status) to all sets  
 is akin to the problem of giving a name to God. As Cantor was  
 completely aware of. We are confused on this since we exist. But the  
 natural numbers, have never leads to any confusion, despite we cannot  
 define them.
   

The proof that there is no biggest natural number is illegal, because 
you are there doing an illegal deduction, you are there doing an illegal 
substitution, just the same as in the deductions below with the sets A 
and B.  You are there substituting an object that is not part of the 
domain of the All quatificator.

--
Torgny Tholerus

 You argument against the infinity of natural numbers is not valid. You  
 cannot throw out this little infinite by pointing on the problem  
 that some terribly big infinite, like the set of all sets,  leads  
 to trouble. That would be like saying that we have to abandon all  
 drugs because the heroin is very dangerous.
 It is just non valid.

 Normally, later  I will show a series of argument very close to  
 Russell paradoxes, and which will yield, in the comp frame,  
 interesting constraints on what computations are and are not.

 Bruno


 On 13 Jun 2009, at 13:26, Torgny Tholerus wrote:

   
 Quentin Anciaux skrev:
 
 2009/6/13 Torgny Tholerus tor...@dsv.su.se:

   
 What do you think about the following deduction?  Is it legal or  
 illegal?
 ---
 Define the set A of all sets as:

 For all x holds that x belongs to A if and only if x is a set.

 This is an general rule saying that for some particular symbol- 
 string x
 you can always tell if x belongs to A or not.  Most humans who think
 about mathematics can understand this rule-based definition.  This  
 rule
 holds for all and every object, without exceptions.

 So this rule also holds for A itself.  We can always substitute A  
 for
 x.  Then we will get:

 A belongs to A if and only if A is a set.

 And we know that A is a set.  So from this we can deduce:

 A beongs to A.
 ---
 Quentin, what do you think?  Is this deduction legal or illegal?

 
 It depends if you allow a set to be part of itselft or not.

 If you accept, that a set can be part of itself, it makes your
 deduction legal regarding the rules.
   
 OK, if we accept that a set can be part of itself, what do you think
 about the following deduction? Is it legal or illegal?

 ---
 Define the set B of all sets that do not belong to itself as:


Re: The seven step-Mathematical preliminaries

2009-06-16 Thread Bruno Marchal


Torgny,

I agree with Quentin.
You are just showing that the naive notion of set is inconsistent.  
Cantor already knew that, and this is exactly what forced people to  
develop axiomatic theories. So depending on which theory of set you  
will use, you can or cannot have an universal set (a set of all sets).  
In typical theories, like ZF and VBG (von Neuman Bernay Gödel) the  
collection of all sets is not a set. In NF, some have developed  
structure with universal sets, and thus universe containing  
themselves. Abram is interested in such universal sets. And, you can  
interpret the UD, or the Mandelbrot set as (simple) model for such  
type of structure.

Your argument did not show at all that the set of natural numbers  
leads to any trouble. Indeed, finitism can be seen as a move toward  
that set, viewed as an everything, potentially infinite frame (for  
math, or beyond math, like it happens with comp).

The problem of naming (or given a mathematical status) to all sets  
is akin to the problem of giving a name to God. As Cantor was  
completely aware of. We are confused on this since we exist. But the  
natural numbers, have never leads to any confusion, despite we cannot  
define them.

You argument against the infinity of natural numbers is not valid. You  
cannot throw out this little infinite by pointing on the problem  
that some terribly big infinite, like the set of all sets,  leads  
to trouble. That would be like saying that we have to abandon all  
drugs because the heroin is very dangerous.
It is just non valid.

Normally, later  I will show a series of argument very close to  
Russell paradoxes, and which will yield, in the comp frame,  
interesting constraints on what computations are and are not.

Bruno


On 13 Jun 2009, at 13:26, Torgny Tholerus wrote:


 Quentin Anciaux skrev:
 2009/6/13 Torgny Tholerus tor...@dsv.su.se:

 What do you think about the following deduction?  Is it legal or  
 illegal?
 ---
 Define the set A of all sets as:

 For all x holds that x belongs to A if and only if x is a set.

 This is an general rule saying that for some particular symbol- 
 string x
 you can always tell if x belongs to A or not.  Most humans who think
 about mathematics can understand this rule-based definition.  This  
 rule
 holds for all and every object, without exceptions.

 So this rule also holds for A itself.  We can always substitute A  
 for
 x.  Then we will get:

 A belongs to A if and only if A is a set.

 And we know that A is a set.  So from this we can deduce:

 A beongs to A.
 ---
 Quentin, what do you think?  Is this deduction legal or illegal?


 It depends if you allow a set to be part of itselft or not.

 If you accept, that a set can be part of itself, it makes your
 deduction legal regarding the rules.

 OK, if we accept that a set can be part of itself, what do you think
 about the following deduction? Is it legal or illegal?

 ---
 Define the set B of all sets that do not belong to itself as:

 For all x holds that x belongs to B if and only if x does not belong  
 to x.

 This is an general rule saying that for some particular symbol- 
 string x
 you can always tell if x belongs to B or not.  Most humans who think
 about mathematics can understand this rule-based definition.  This  
 rule
 holds for all and every object, without exceptions.

 So this rule also holds for B itself.  We can always substitute B for
 x.  Then we will get:

 B belongs to B if and only if B does not belong to B.
 ---
 Quentin, what do you think?  Is this deduction legal or illegal?


 -- 
 Torgny Tholerus

 

http://iridia.ulb.ac.be/~marchal/




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Re: The seven step-Mathematical preliminaries

2009-06-14 Thread Bruno Marchal


On 12 Jun 2009, at 17:16, A. Wolf wrote:





 We agree then.

 Yes, it's my fault for creating a semantics argument.  I'm usually  
 too busy
 to even read the list...every once in a while something pops up and  
 I feel
 obliged to comment even when it's the middle of a conversation.

No problem.




 I actually have some questions for the list members that are  
 relevant to the
 list content, and this coming week is break.  I may have a chance to  
 post
 them.  They're much more on the philosophical side than the  
 mathematical,
 though.


Don't hesitate,

Bruno

http://iridia.ulb.ac.be/~marchal/




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Re: The seven step-Mathematical preliminaries

2009-06-14 Thread Bruno Marchal

On 12 Jun 2009, at 20:31, Jesse Mazer wrote:


 Even for just an arithmetical realist. (All mathematicians are  
 arithmetical realist, much less are mathematical realist. I am not  
 an arithmetical realist).


 I assume you meant to write I am not a mathematical realist?


Yes.



 OK, but this leads to a further question. I remember from Penrose's  
 book that he talked about various levels of oracle machines  
 (hypercomputers)--for example, a first order-oracle machine was like  
 a Turing machine but with an added operation that could decide in  
 one step whether any Turing program halts or not, a second-order  
 oracle machine was like a Turing machine but with operations that  
 could decide whether a Turing machine program *or* a first-order  
 oracle machine program halts, and so forth.



 Hmm... let us say OK (but this could be ambiguous). This gives  
 mainly the arithmetical hierarchy when you start from the oracle for  
 the halting problem. There are relativized hierarchy based on any  
 oracle, and then starting from the halting problem in that oracle.  
 The degrees are structured in a very complex way.


 I don't know the meaning of the phrases arithmetical hierarchy or  
 relativized hierarchy, is there any simple way of explaining? In  
 any case, the problem I am mainly concerned with is the set of all  
 propositions that would be considered well-formed-formulas (WFFs) in  
 the context of Peano arithmetic (so it would involve arithmetical  
 symbols like + and x as well as logical symbols from first-order  
 logic, and they'd be ordered in such a way that the symbol-string  
 would express a coherent statement about arithmetic that could be  
 either true or false). Is there some way to come up with a rule that  
 would allow you to judge the true or falsity of *every* member of  
 this set of propositions using some kind of sufficiently powerful  
 hypercomputer (presumably a fairly powerful one like the 'omega- 
 order oracle machine' or beyond), just by checking every possible  
 value for the numbers that could be substituted in for variable  
 symbols? That would allow us to make sense of the distinction  
 between truths about arithmetic and statements about arithmetic  
 provable by some axiomatic system like the Peano axioms (the issue  
 Brent Meeker was talking about in the post at 
 http://www.mail-archive.com/everything-list@googlegroups.com/msg16562.html 
  ), without having to worry about the meaning that we assign to  
 arithmetical symbols like the number 2, or about philosophical  
 questions about where our understanding of that meaning comes from.


I think you are asking something impossible. The notion of elementary  
aritmetical truth will always be simpler than the notion you need to  
define the hypercomputer. Just Gödel's incompleteness theorem  
justifies in an transparent way the separation between truth and  
provability in such or such formal theory. The arithmetical hierachy  
is the one I was describing with the sequence of alternation of  
quantifiers starting from decidable formula. That hierarchy does  
indeed described a sequence of hypermachine (because each level  
posses a Sigma_i or Pi_i completeness notion, which generalize the  
notion of universality for machine-with-oracle. I will have some  
opportunity to describe notion even more powerful. But only (with  
Church thesis) the Sigma_1 universality has an effective universal  
counterpart, represented by any computer, or universal language  
interpreter.




 Instead we'd have a purely formal definition about how to judge the  
 truth-value of WFFs beyond those the Peano axioms can judge,


Remember that  PA+consistent PA is uncomputably more powerful than  
PA. And ZF set theory is much much more powerful than PA, ...

This is something I will have to explain, at least for AUDA, but in  
all those discussions we have to distinguih the notion of  
computability (which is universal and does not depend on the choice of  
formalism), with the notion of provability which is formalism dependent.
And then we can generalize the notion of computability, and even of  
provability.

Humans provability is generally considered as much larger than PA  
arithmetic.



 albeit one that cannot actually be put into practice for arbitrary  
 propositions without actually having such a hypercomputer (but for  
 some specific propositions like the Godel statement for the Peano  
 axioms, I think we can come up with an argument for why the  
 hypercomputer should judge this statement 'true' as long as we  
 believe the Peano axioms are consistent, so in this sense defining  
 arithmetical truth in terms of such a hypercomputer is  
 *conceptually* useful).

The whole incompleteness phenomena bears on all notion of  
hypercomputations. I prefer to call hypercomputers Gods or angels,  
and both humans and machines can accelerate their work by invoking  
them. The notion of real numbers are based on such 

Re: The seven step-Mathematical preliminaries

2009-06-14 Thread Quentin Anciaux

2009/6/14 Torgny Tholerus tor...@dsv.su.se:

 Quentin Anciaux skrev:
 Well it is illegal regarding the rules meaning with these rules set B
 does not exist as defined.


 What is it that makes set A to exist, and set B not to exist?  What is
 the (important) differences between the definition of set A and the
 definition of set B?  In both cases you are defining a set by giving a
 property that all members of the set must fulfill.

Yes and one fulfil it according to the given rules the other not.

I would add that your excercise is inconsistent from the start,
whatever a set is, your argument is contradictory whatever the rules
are.

 Why is the deduction legal for set A, but illegal for set B?  There is
 the same type of deduction in both places, you are just making a
 substitution for the all quantificator in both cases.

That's all the point of puting rules and checking that something is
correct or not according to it. 1+1=3 is false according to PA... that
doesn't mean you couldn't find a rule or mapping that would render
this statement true ***regarding the chosen rules***/

Regards,
Quentin

 --
 Torgny Tholerus


 2009/6/13 Torgny Tholerus tor...@dsv.su.se:

 Quentin Anciaux skrev:

 2009/6/13 Torgny Tholerus tor...@dsv.su.se:


 What do you think about the following deduction?  Is it legal or illegal?
 ---
 Define the set A of all sets as:

 For all x holds that x belongs to A if and only if x is a set.

 This is an general rule saying that for some particular symbol-string x
 you can always tell if x belongs to A or not.  Most humans who think
 about mathematics can understand this rule-based definition.  This rule
 holds for all and every object, without exceptions.

 So this rule also holds for A itself.  We can always substitute A for
 x.  Then we will get:

 A belongs to A if and only if A is a set.

 And we know that A is a set.  So from this we can deduce:

 A beongs to A.
 ---
 Quentin, what do you think?  Is this deduction legal or illegal?


 It depends if you allow a set to be part of itselft or not.

 If you accept, that a set can be part of itself, it makes your
 deduction legal regarding the rules.

 OK, if we accept that a set can be part of itself, what do you think
 about the following deduction? Is it legal or illegal?

 ---
 Define the set B of all sets that do not belong to itself as:

 For all x holds that x belongs to B if and only if x does not belong to x.

 This is an general rule saying that for some particular symbol-string x
 you can always tell if x belongs to B or not.  Most humans who think
 about mathematics can understand this rule-based definition.  This rule
 holds for all and every object, without exceptions.

 So this rule also holds for B itself.  We can always substitute B for
 x.  Then we will get:

 B belongs to B if and only if B does not belong to B.
 ---
 Quentin, what do you think?  Is this deduction legal or illegal?


 --
 Torgny Tholerus








 




-- 
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Re: The seven step-Mathematical preliminaries

2009-06-13 Thread Quentin Anciaux

2009/6/13 Torgny Tholerus tor...@dsv.su.se:

 Jesse Mazer skrev:

  Date: Fri, 12 Jun 2009 18:40:14 +0200
  From: tor...@dsv.su.se
  To: everything-list@googlegroups.com
  Subject: Re: The seven step-Mathematical preliminaries
 
  It is, as I said above, for me and all other humans to understand what
  you are talking about. It is also for to be able to decide what
  deductions or conclusions or proofs that are legal or illegal.

 Well, most humans who think about mathematics can understand
 rule-based definitions like 0 is a whole number, and N is a whole
 number if it's equal to some other whole number plus one--you seem to
 be the lone exception.

 As for being able to decide what deductions or conclusions or proofs
 that are legal or illegal, how exactly would writing out all the
 members of the universe solve that? For example, I actually write
 out all the numbers from 0 to 1,038,712 and say that they are members
 of the universe I want to talk about. But if I write out some axioms
 used to prove various propositions about these numbers, they are still
 going to be in the form of general *rules* with abstract variables
 like x and y (where these variables stand for arbitrary numbers in the
 set), no? Or do you also insist that instead of writing axioms and
 making deductions, we also spell out in advance every proposition that
 shall be deemed true? In that case there is no room at all for
 mathematicians to make deductions or write proofs, all of math
 would just consist of looking at the pre-established list of true
 propositions and checking if the proposition in question is on there.

 What do you think about the following deduction?  Is it legal or illegal?
 ---
 Define the set A of all sets as:

 For all x holds that x belongs to A if and only if x is a set.

 This is an general rule saying that for some particular symbol-string x
 you can always tell if x belongs to A or not.  Most humans who think
 about mathematics can understand this rule-based definition.  This rule
 holds for all and every object, without exceptions.

 So this rule also holds for A itself.  We can always substitute A for
 x.  Then we will get:

 A belongs to A if and only if A is a set.

 And we know that A is a set.  So from this we can deduce:

 A beongs to A.
 ---
 Quentin, what do you think?  Is this deduction legal or illegal?

It depends if you allow a set to be part of itselft or not.

If you accept, that a set can be part of itself, it makes your
deduction legal regarding the rules. If you don't then the statement
is illegal regarding the rules (it violates the rule saying that a set
can't contains itself, which means that A in this system is not a set
thus all the reasoning in *that system* is false.

Choosing one rule or the other tells nothing about the rule itself
unless you can find a contradiction by choosing one or the other.

Regards,
Quentin

But I can't see why a set as I understand it cannot be part of
itself... {1,2,3} is included in {1,2,3} is true, what is the exact
problem with that statement ? (written differently all elements of the
set A are elements of the set B === A is included in B, here as A and
B are the same A is included in A.

 --
 Torgny Tholerus

 




-- 
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Re: The seven step-Mathematical preliminaries

2009-06-13 Thread Torgny Tholerus

Quentin Anciaux skrev:
 2009/6/13 Torgny Tholerus tor...@dsv.su.se:
   
 What do you think about the following deduction?  Is it legal or illegal?
 ---
 Define the set A of all sets as:

 For all x holds that x belongs to A if and only if x is a set.

 This is an general rule saying that for some particular symbol-string x
 you can always tell if x belongs to A or not.  Most humans who think
 about mathematics can understand this rule-based definition.  This rule
 holds for all and every object, without exceptions.

 So this rule also holds for A itself.  We can always substitute A for
 x.  Then we will get:

 A belongs to A if and only if A is a set.

 And we know that A is a set.  So from this we can deduce:

 A beongs to A.
 ---
 Quentin, what do you think?  Is this deduction legal or illegal?
 

 It depends if you allow a set to be part of itselft or not.

 If you accept, that a set can be part of itself, it makes your
 deduction legal regarding the rules.

OK, if we accept that a set can be part of itself, what do you think 
about the following deduction? Is it legal or illegal?

---
Define the set B of all sets that do not belong to itself as:

For all x holds that x belongs to B if and only if x does not belong to x.

This is an general rule saying that for some particular symbol-string x 
you can always tell if x belongs to B or not.  Most humans who think 
about mathematics can understand this rule-based definition.  This rule 
holds for all and every object, without exceptions.

So this rule also holds for B itself.  We can always substitute B for 
x.  Then we will get:

B belongs to B if and only if B does not belong to B.
---
Quentin, what do you think?  Is this deduction legal or illegal?


-- 
Torgny Tholerus

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Re: The seven step-Mathematical preliminaries

2009-06-13 Thread Quentin Anciaux

Well it is illegal regarding the rules meaning with these rules set B
does not exist as defined.


2009/6/13 Torgny Tholerus tor...@dsv.su.se:

 Quentin Anciaux skrev:
 2009/6/13 Torgny Tholerus tor...@dsv.su.se:

 What do you think about the following deduction?  Is it legal or illegal?
 ---
 Define the set A of all sets as:

 For all x holds that x belongs to A if and only if x is a set.

 This is an general rule saying that for some particular symbol-string x
 you can always tell if x belongs to A or not.  Most humans who think
 about mathematics can understand this rule-based definition.  This rule
 holds for all and every object, without exceptions.

 So this rule also holds for A itself.  We can always substitute A for
 x.  Then we will get:

 A belongs to A if and only if A is a set.

 And we know that A is a set.  So from this we can deduce:

 A beongs to A.
 ---
 Quentin, what do you think?  Is this deduction legal or illegal?


 It depends if you allow a set to be part of itselft or not.

 If you accept, that a set can be part of itself, it makes your
 deduction legal regarding the rules.

 OK, if we accept that a set can be part of itself, what do you think
 about the following deduction? Is it legal or illegal?

 ---
 Define the set B of all sets that do not belong to itself as:

 For all x holds that x belongs to B if and only if x does not belong to x.

 This is an general rule saying that for some particular symbol-string x
 you can always tell if x belongs to B or not.  Most humans who think
 about mathematics can understand this rule-based definition.  This rule
 holds for all and every object, without exceptions.

 So this rule also holds for B itself.  We can always substitute B for
 x.  Then we will get:

 B belongs to B if and only if B does not belong to B.
 ---
 Quentin, what do you think?  Is this deduction legal or illegal?


 --
 Torgny Tholerus

 




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RE: The seven step-Mathematical preliminaries

2009-06-13 Thread Jesse Mazer



 Date: Sat, 13 Jun 2009 11:05:22 +0200
 From: tor...@dsv.su.se
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries
 
 
 Jesse Mazer skrev:
 
   Date: Fri, 12 Jun 2009 18:40:14 +0200
   From: tor...@dsv.su.se
   To: everything-list@googlegroups.com
   Subject: Re: The seven step-Mathematical preliminaries
  
   It is, as I said above, for me and all other humans to understand what
   you are talking about. It is also for to be able to decide what
   deductions or conclusions or proofs that are legal or illegal.
 
  Well, most humans who think about mathematics can understand 
  rule-based definitions like 0 is a whole number, and N is a whole 
  number if it's equal to some other whole number plus one--you seem to 
  be the lone exception.
 
  As for being able to decide what deductions or conclusions or proofs 
  that are legal or illegal, how exactly would writing out all the 
  members of the universe solve that? For example, I actually write 
  out all the numbers from 0 to 1,038,712 and say that they are members 
  of the universe I want to talk about. But if I write out some axioms 
  used to prove various propositions about these numbers, they are still 
  going to be in the form of general *rules* with abstract variables 
  like x and y (where these variables stand for arbitrary numbers in the 
  set), no? Or do you also insist that instead of writing axioms and 
  making deductions, we also spell out in advance every proposition that 
  shall be deemed true? In that case there is no room at all for 
  mathematicians to make deductions or write proofs, all of math 
  would just consist of looking at the pre-established list of true 
  propositions and checking if the proposition in question is on there.
 
 What do you think about the following deduction?  Is it legal or illegal?
 ---
 Define the set A of all sets as:
 
 For all x holds that x belongs to A if and only if x is a set.

It's well known that if you allow sets to contain themselves, and allow 
arbitrary rules for what a given set can contain, then you can get 
contradictions like Russell's paradox (the set of all sets which do not contain 
themselves). But what relevance does this have to arithmetic? Are you afraid 
the basic Peano axioms might lead to two propositions which can be derived in 
finite time from the axioms but which are mutually contradictory? If so I don't 
see how allowing only a finite collection of numbers actually helps--like I 
said in an earlier post, the number of propositions that can be proved about a 
finite set of numbers can still be infinite. I suppose it might be possible to 
make it finite by disallowing propositions which are created merely by 
connecting other propositions with the AND or OR logical operators, but it's 
still the case that if your largest whole number BIGGEST is supposed to be at 
least as large as some numbers humans have already conceived--say, as large as 
10^100--then there is no way we could actually write out all possible 
propositions about these numbers that follow from some Peano-like axiom system 
to check manually that no two propositions contradicted each other (do you want 
to try to calculate 10^100 + A and A + 10^100 for every possible value of A 
smaller than 10^100 to verify explicitly that they are equal in every case?) 
So, it seems that unless you want to make your universe of numbers *very* 
small, you have to rely on some sort of mental model of arithmetic to be 
confident that you won't get contradictions from the axioms you start from, 
just like how people are confident in the non-contradictoriness of the Peano 
axioms based on their mental model of counting discrete objects like marbles 
(see my comments in the last paragraph of the post at 
http://www.mail-archive.com/everything-list@googlegroups.com/msg16564.html ).

Jesse
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Re: The seven step-Mathematical preliminaries

2009-06-12 Thread A. Wolf

 There, they call arithmetic soundness what me (and many logician) call 
 soundness, when they refer to theories about numbers.  Like Mendelson I 
 prefer to use the term logically valid, to what you call soundness.

I may have misstated myself, but the wiki article you pointed me to agrees 
with what I tried to say: A logical system is sound if every provable 
statement is valid.  Validity is not the same as soundness.  There are valid 
arguments that are unsound.  For example, if I say x is not equal to x, 
therefore there are no more than five natural numbers, this is a valid 
(i.e., logically true) argument.  But it's also an unsound argument, because 
there is no interpretation where x is not equal to x.

What you're calling soundness I would call omega-consistent, but I see from 
the article that this is sometimes called arithmetical soundness.

 The word true alone has no meaning. It refers always to a model, or to a 
 collection of models.

One could make the same argument about the symbol = not having any meaning 
outside of a model, but true has a standard meaning in logic, one that is 
often used interchangeably with valid (a stronger property).  The general 
true means true under any interpretation.

 Oh, you mean a definition of natural number such that the model would be 
 finite in scope. This is non sense for me. Pace Torgny.

Nonsense for me too, apart from the philisophical musings.

 Well, there is just no categorical first order definition of the finite 
 sets of natural numbers.  And second order definition, assumes  the notion 
 of infinite set.

I'm not sure what you mean here.  Of course there is no categorical 
first-order theory of N.

Anna


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Re: The seven step-Mathematical preliminaries

2009-06-12 Thread Bruno Marchal

On 11 Jun 2009, at 21:43, Jesse Mazer wrote:




 Countably infinite does not mean recursively countably infinite.  
 This is something which I will explain in the seventh step thread.

 There is theorem by Kleene which links Post-Turing degrees of  
 unsolvability with the shape of arithmetical formula. With P  
 denoting decidable predicates (Sigma_0) we have

 ExP(x)  Sigma_1  (mechanical)
 AxP(x) Pi_1
 ExAyP(x,y) Sigma_2
 AxEyP(x,y) Pi_2
 etc.


 Ah, that makes sense--I hadn't thought of combining multiple  
 universal quantifiers in that way, but obviously you can do so and  
 get a meaningful statement about arithmetic that for a mathematical  
 realist should be either true or false.



Even for just an arithmetical realist. (All mathematicians are  
arithmetical realist, much less are mathematical realist. I am not an  
arithmetical realist).
Of course some exotic philosopher could pretend they are not  
arithmetical realist, but this is near non sense for me.






 OK, but this leads to a further question. I remember from Penrose's  
 book that he talked about various levels of oracle machines  
 (hypercomputers)--for example, a first order-oracle machine was like  
 a Turing machine but with an added operation that could decide in  
 one step whether any Turing program halts or not, a second-order  
 oracle machine was like a Turing machine but with operations that  
 could decide whether a Turing machine program *or* a first-order  
 oracle machine program halts, and so forth.



Hmm... let us say OK (but this could be ambiguous). This gives  
mainly the arithmetical hierarchy when you start from the oracle for  
the halting problem. There are relativized hierarchy based on any  
oracle, and then starting from the halting problem in that oracle. The  
degrees are structured in a very complex way.





 You can go even past finite-order oracle machines into oracle  
 machines for higher ordinals too...


This leads to the hyperarithmetical hierarchy and/or analytical  
hierarchy, where you consider formula with variables for functions or  
sets. There are many non trivial theorems which relate those notions  
(and open problems, but I have not follow the recent developments).  
Imo, the best book on that subject is still the book by Rogers.




 for example, an omega-order oracle machine can tell you whether any  
 finite-order oracle machine halts, an omega-plus-one-order oracle  
 machine can tell you whether any finite-order oracle machine halts  
 *or* whether an omega-order oracle machine halts, and so forth. So I  
 assume from what you're saying above that even an omega-order oracle  
 machine would not be able to decide the truth value of every  
 proposition about arithmetic just by checking cases...if that's  
 right, what would the propositions it can't decide look like? It  
 can't just follow the pattern you showed above of adding more  
 universal quantifiers, since it has to be a proposition of finite  
 length.



Indeed, but variable can represent infinite object, like in analysis.  
 From the point of view of computability, infinite set of natural  
number, or functions from N to N, can play the role of the real numbers.




 I've also read that countable ordinals themselves can be classed as  
 either computable or noncomputable (which makes sense since I'm  
 pretty sure you can come up with a formalism where every possible  
 countable ordinal is associated with a countable symbol-string,  
 although the same ordinal might have multiple valid ways of  
 expressing it as a symbol string since order doesn't matter in sets,  
 so this doesn't help with the problem of whether the cardinality of  
 the set of all distinct countable ordinals is the same as the  
 cardinality of the set of all distinct real numbers, i.e. all  
 distinct countable symbol-strings). So, there is a first countable- 
 but-noncomputable ordinal, written as omega_1^CK (where _1 refers to  
 a subscript and ^CK refers to a superscript),


Yes. And CK is for Church and Kleene. You can see omega_1^CK as the  
least non recursive ordinal. Omega_1 (aleph_1) is the least non  
countable ordinal. Of course omega_1^CK is much smaller than Omega_1.  
And with the continuum hypothesis Omega_1 is 2^aleph_0.



 which means we should also have a notion of an omega_1^CK-order  
 oracle machine.


You are quick here! There are more than one way to make this precise.




 Would there be finite propositions about arithmetic that even this  
 fantastical device could not decide?


This can depend of which path you will follow going through the  
constructive ordinals, and yes some path define fantastical device  
capable of answering all arithmetical questions. Obviously, this  
correspond to anything but machines! But yes, with comp those objects  
makes non sense form the third person point of view, but still are  
needed to figure out the first person points of view.






 Can all propositions about arbitrary *real* 

Re: The seven step-Mathematical preliminaries

2009-06-12 Thread Bruno Marchal

Le 12-juin-09, à 09:31, Bruno Marchal a écrit :


 On 11 Jun 2009, at 21:43, Jesse Mazer wrote:



 Ah, that makes sense--I hadn't thought of combining multiple 
 universal quantifiers in that way, but obviously you can do so and 
 get a meaningful statement about arithmetic that for a mathematical 
 realist should be either true or false.


 Even for just an arithmetical realist. (All mathematicians are 
 arithmetical realist, much less are mathematical realist. I am not an 
 arithmetical realist).


Raaah... Sorry. Of course I am an arithmetical realist. I am not a 
*mathematical* realist (still less a physical realist).

With the month of June I have a lot of works to do, and I tend to do it 
simultaneously. The result is an augmentation of mistakes! I hope you 
have learned to automatically correct them. Sorry. Please, ask in case 
of remaining doubt.

Bruno

http://iridia.ulb.ac.be/~marchal/

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Re: The seven step-Mathematical preliminaries

2009-06-12 Thread Bruno Marchal


Le 12-juin-09, à 08:28, A. Wolf a écrit :


 There, they call arithmetic soundness what me (and many logician)  
 call
 soundness, when they refer to theories about numbers.  Like  
 Mendelson I
 prefer to use the term logically valid, to what you call soundness.

 I may have misstated myself, but the wiki article you pointed me to  
 agrees
 with what I tried to say:


That wiki article is not so good.




 A logical system is sound if every provable
 statement is valid.

... meaning true in all models of the theory.  OK.

Like a tautology, for example  P OR NOT P  is true is all models  
(those with P true, and those with P false).

A propositional calculus is sound if it proves only tautologies (true  
in all models),
and complete if it proves all tautologies, that is: all the  
propositions which are true in all models.

The intuitive idea is that a reasoning is valid if its truth status  
does not depend on the way we interpret it.



 Validity is not the same as soundness.

Logicians from different fields use terms in different ways. In  
provability logic and in recursion theory, soundness means often  
arithmetical soundness.
For example, in recursion theory,  theory will be said Sigma_2 sound  
when all Sigma_2 propositions proved in the theory are true ... in the  
usual model (N,+,*).



 There are valid
 arguments that are unsound.  For example, if I say x is not equal  
 to x,
 therefore there are no more than five natural numbers, this is a  
 valid
 (i.e., logically true) argument.  But it's also an unsound argument,  
 because
 there is no interpretation where x is not equal to x.


Here most, if not all logicians, would disagree. Both in classical and  
intuitionistic logic, To deduce any proposition from a falsity is  
always a valid argument. Nobody will say that an argument is non valid  
because its premise are absurd. Except in the relevance logic field.  
Well, they will say that the reasoning is not ... relevant.





 What you're calling soundness I would call omega-consistent, but I  
 see from
 the article that this is sometimes called arithmetical soundness.


Soundness is a semantical notion. By the Tarski phenomenon such a  
notion cannot be even just defined or expressed in the theory. That is  
why Gödel makes the terrible effort for not using such a notion, which  
was considered a bit controversial in those days.
Omega-consistency, like consistency, can be defined in a purely  
syntactical way, and is much weaker than soundness.





 The word true alone has no meaning. It refers always to a model,  
 or to a
 collection of models.

 One could make the same argument about the symbol = not having any  
 meaning
 outside of a model, but true has a standard meaning in logic, one  
 that is
 often used interchangeably with valid (a stronger property).  The  
 general
 true means true under any interpretation.


That is validity for me. But let us not debate on vocabulary,  
especially before making a bit more logic.



 Oh, you mean a definition of natural number such that the model  
 would be
 finite in scope. This is non sense for me. Pace Torgny.

 Nonsense for me too, apart from the philisophical musings.


OK.




 Well, there is just no categorical first order definition of the  
 finite
 sets of natural numbers.  And second order definition, assumes  the  
 notion
 of infinite set.

 I'm not sure what you mean here.  Of course there is no categorical
 first-order theory of N.


We agree then. For the others, a theory is categorical if all its  
model are isomorphic. In a sense, such a theory succeeds in capturing  
completely its semantics. By well know theorems, such theories are  
very rare, and in fact, when effective, very poor and very exceptional.

Bruno

http://iridia.ulb.ac.be/~marchal/




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Re: The seven step-Mathematical preliminaries

2009-06-12 Thread A. Wolf

 Logicians from different fields use terms in different ways. In 
 provability logic and in recursion theory, soundness means often 
 arithmetical soundness.

I understand.

Part of the reason for my particular viewpoint: there's a group of 
professors at the college I work at who are working on bottom-up provability 
of computer programs under specific constraints.  Soundness for them means 
the proof systems they use never prove a program is correct (meaning, it 
meets formal, mathematically-written specifications) when it's actually 
incorrect, provided the constraints are applied correctly.  When the 
constraints are not applied correctly, it's acceptable for the system to 
prove things that aren't correct, and they still consider this sound for 
their purposes.

 We agree then.

Yes, it's my fault for creating a semantics argument.  I'm usually too busy 
to even read the list...every once in a while something pops up and I feel 
obliged to comment even when it's the middle of a conversation.

I actually have some questions for the list members that are relevant to the 
list content, and this coming week is break.  I may have a chance to post 
them.  They're much more on the philosophical side than the mathematical, 
though.

Anna


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Re: The seven step-Mathematical preliminaries

2009-06-12 Thread Torgny Tholerus

Jesse Mazer skrev:

  Date: Wed, 10 Jun 2009 09:18:10 +0200
  From: tor...@dsv.su.se
  To: everything-list@googlegroups.com
  Subject: Re: The seven step-Mathematical preliminaries
 
  Jesse Mazer skrev:
 
  Date: Tue, 9 Jun 2009 18:38:23 +0200
  From: tor...@dsv.su.se
  To: everything-list@googlegroups.com
  Subject: Re: The seven step-Mathematical preliminaries
 
  For you to be able to use the word all, you must define the domain
  of that word. If you do not define the domain, then it will be
  impossible for me and all other humans to understand what you are
  talking about.
 
  OK, so how do you say I should define this type of universe? Unless
  you are demanding that I actually give you a list which spells out
  every symbol-string that qualifies as a member, can't I simply provide
  an abstract *rule* that would allow someone to determine in principle
  if a particular symbol-string they are given qualifies? Or do you have
  a third alternative besides spelling out every member or giving an
  abstract rule?
 
  You have to spell out every member. 

 Where does this have to come from? Again, is it something you have a 
 philosophical or logical definition for, or is it just your aesthetic 
 preference?

It is, as I said above, for me and all other humans to understand what 
you are talking about.  It is also for to be able to decide what 
deductions or conclusions or proofs that are legal or illegal.  It has 
nothing to do with my aesthetic preference.


  Because in a *rule* you are 
  (implicitely) using this type of universe, and you will then get a
  circular definition.

 A good rule (as opposed to a 'bad' rule like 'the set of all sets that 
 do not contain themselves') gives a perfectly well-defined criteria 
 for what is contained in the universe, such that no one will ever have 
 cause to be unsure about whether some particular symbol-string they're 
 given at belongs in this universe. It's only circular if you say in 
 advance that there is something problematic about rules which define 
 infinite universes, but again this just seems like your aesthetic 
 preference and not something you have given any philosophical/logical 
 justification for.

What do you mean by some particular symbol-string?

I suppose that you mean by this is: If you take any particular 
symbol-string from this universe, then no one will ever have cause to be 
unsure about whether this symbol-string belongs in this universe.  So 
you are defining this universe by supposing that you have this 
universe to start with.  Is that not a typical circular definition?

-- 
Torgny Tholerus

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RE: The seven step-Mathematical preliminaries

2009-06-12 Thread Jesse Mazer



 Date: Fri, 12 Jun 2009 18:40:14 +0200
 From: tor...@dsv.su.se
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries
 
 
 Jesse Mazer skrev:
 
   Date: Wed, 10 Jun 2009 09:18:10 +0200
   From: tor...@dsv.su.se
   To: everything-list@googlegroups.com
   Subject: Re: The seven step-Mathematical preliminaries
  
   Jesse Mazer skrev:
  
   Date: Tue, 9 Jun 2009 18:38:23 +0200
   From: tor...@dsv.su.se
   To: everything-list@googlegroups.com
   Subject: Re: The seven step-Mathematical preliminaries
  
   For you to be able to use the word all, you must define the domain
   of that word. If you do not define the domain, then it will be
   impossible for me and all other humans to understand what you are
   talking about.
  
   OK, so how do you say I should define this type of universe? Unless
   you are demanding that I actually give you a list which spells out
   every symbol-string that qualifies as a member, can't I simply provide
   an abstract *rule* that would allow someone to determine in principle
   if a particular symbol-string they are given qualifies? Or do you have
   a third alternative besides spelling out every member or giving an
   abstract rule?
  
   You have to spell out every member. 
 
  Where does this have to come from? Again, is it something you have a 
  philosophical or logical definition for, or is it just your aesthetic 
  preference?
 
 It is, as I said above, for me and all other humans to understand what 
 you are talking about.  It is also for to be able to decide what 
 deductions or conclusions or proofs that are legal or illegal.  It has 
 nothing to do with my aesthetic preference.

Well, most humans who think about mathematics can understand rule-based 
definitions like 0 is a whole number, and N is a whole number if it's equal to 
some other whole number plus one--you seem to be the lone exception. What's 
more, I kind of think you're playing dumb here, because I bet *you* would 
have little problem with a rule-based definition of a finite set that didn't 
actually spell out every member, like 0 is a member of the set, and N is in 
the set if it's equal to some other member of the set plus one, *unless* the 
'other member of the set' is equal to 1,038,712 in which case no members of the 
set are larger than that. Here, can't you understand that the set includes 
every whole number from 0 to 1,038,712 without my having to write out every 
member? And the mental process that allows you to decide whether some string of 
symbols (say, 1692) would qualify as a member of that set is exactly the same 
as the mental process that would allow you to decide whether some string of 
symbols would qualify as a member of the whole numbers which have no upper 
limit.
As for being able to decide what deductions or conclusions or proofs that are 
legal or illegal, how exactly would writing out all the members of the 
universe solve that? For example, I actually write out all the numbers from 0 
to 1,038,712 and say that they are members of the universe I want to talk 
about. But if I write out some axioms used to prove various propositions about 
these numbers, they are still going to be in the form of general *rules* with 
abstract variables like x and y (where these variables stand for arbitrary 
numbers in the set), no? Or do you also insist that instead of writing axioms 
and making deductions, we also spell out in advance every proposition that 
shall be deemed true? In that case there is no room at all for mathematicians 
to make deductions or write proofs, all of math would just consist of 
looking at the pre-established list of true propositions and checking if the 
proposition in question is on there.

 
 
   Because in a *rule* you are 
   (implicitely) using this type of universe, and you will then get a
   circular definition.
 
  A good rule (as opposed to a 'bad' rule like 'the set of all sets that 
  do not contain themselves') gives a perfectly well-defined criteria 
  for what is contained in the universe, such that no one will ever have 
  cause to be unsure about whether some particular symbol-string they're 
  given at belongs in this universe. It's only circular if you say in 
  advance that there is something problematic about rules which define 
  infinite universes, but again this just seems like your aesthetic 
  preference and not something you have given any philosophical/logical 
  justification for.
 
 What do you mean by some particular symbol-string?
 
 I suppose that you mean by this is: If you take any particular 
 symbol-string from this universe, then no one will ever have cause to be 
 unsure about whether this symbol-string belongs in this universe.  So 
 you are defining this universe by supposing that you have this 
 universe to start with.  Is that not a typical circular definition?
No, I'm saying take some particular collection of symbols like 
0,1,2,3,4,5,6,7,8,9, then any finite ordered group of them

RE: The seven step-Mathematical preliminaries

2009-06-12 Thread Jesse Mazer



From: marc...@ulb.ac.be
To: everything-list@googlegroups.com
Subject: Re: The seven step-Mathematical preliminaries
Date: Fri, 12 Jun 2009 09:31:46 +0200


On 11 Jun 2009, at 21:43, Jesse Mazer wrote:



Countably infinite does not mean recursively countably infinite. This is 
something which I will explain in the seventh step thread.
There is theorem by Kleene which links Post-Turing degrees of unsolvability 
with the shape of arithmetical formula. With P denoting decidable predicates 
(Sigma_0) we have
ExP(x)  Sigma_1  (mechanical) AxP(x) Pi_1ExAyP(x,y) Sigma_2AxEyP(x,y) Pi_2etc.

Ah, that makes sense--I hadn't thought of combining multiple universal 
quantifiers in that way, but obviously you can do so and get a meaningful 
statement about arithmetic that for a mathematical realist should be either 
true or false.


Even for just an arithmetical realist. (All mathematicians are arithmetical 
realist, much less are mathematical realist. I am not an arithmetical realist).

I assume you meant to write I am not a mathematical realist?





OK, but this leads to a further question. I remember from Penrose's book that 
he talked about various levels of oracle machines (hypercomputers)--for 
example, a first order-oracle machine was like a Turing machine but with an 
added operation that could decide in one step whether any Turing program halts 
or not, a second-order oracle machine was like a Turing machine but with 
operations that could decide whether a Turing machine program *or* a 
first-order oracle machine program halts, and so forth. 


Hmm... let us say OK (but this could be ambiguous). This gives mainly the 
arithmetical hierarchy when you start from the oracle for the halting problem. 
There are relativized hierarchy based on any oracle, and then starting from 
the halting problem in that oracle. The degrees are structured in a very 
complex way. 

I don't know the meaning of the phrases arithmetical hierarchy or 
relativized hierarchy, is there any simple way of explaining? In any case, 
the problem I am mainly concerned with is the set of all propositions that 
would be considered well-formed-formulas (WFFs) in the context of Peano 
arithmetic (so it would involve arithmetical symbols like + and x as well as 
logical symbols from first-order logic, and they'd be ordered in such a way 
that the symbol-string would express a coherent statement about arithmetic that 
could be either true or false). Is there some way to come up with a rule that 
would allow you to judge the true or falsity of *every* member of this set of 
propositions using some kind of sufficiently powerful hypercomputer (presumably 
a fairly powerful one like the 'omega-order oracle machine' or beyond), just by 
checking every possible value for the numbers that could be substituted in for 
variable symbols? That would allow us to make sense of the distinction between 
truths about arithmetic and statements about arithmetic provable by some 
axiomatic system like the Peano axioms (the issue Brent Meeker was talking 
about in the post at 
http://www.mail-archive.com/everything-list@googlegroups.com/msg16562.html ), 
without having to worry about the meaning that we assign to arithmetical 
symbols like the number 2, or about philosophical questions about where our 
understanding of that meaning comes from. Instead we'd have a purely formal 
definition about how to judge the truth-value of WFFs beyond those the Peano 
axioms can judge, albeit one that cannot actually be put into practice for 
arbitrary propositions without actually having such a hypercomputer (but for 
some specific propositions like the Godel statement for the Peano axioms, I 
think we can come up with an argument for why the hypercomputer should judge 
this statement 'true' as long as we believe the Peano axioms are consistent, so 
in this sense defining arithmetical truth in terms of such a hypercomputer is 
*conceptually* useful).


You can go even past finite-order oracle machines into oracle machines for 
higher ordinals too...

This leads to the hyperarithmetical hierarchy and/or analytical hierarchy, 
where you consider formula with variables for functions or sets. There are 
many non trivial theorems which relate those notions (and open problems, but I 
have not follow the recent developments). Imo, the best book on that subject 
is still the book by Rogers.

Again, I'm only interested here in the type of propositions that would be 
judged WFFs in the context of the Peano axioms, and I think in this case the 
variables only refer to particular numbers, right? Or is it possible to write a 
WFF in this context where the variables refer to functions or sets?
Like you I am an arithmetical realist but not necessarily a realist about 
arbitrary sets. I think it may be problematic to talk about sets that are so 
big that most of their numbers have no finite description, as must be true of 
any uncountable set. If there is no *rule* which maps countable ordinals

RE: The seven step-Mathematical preliminaries

2009-06-11 Thread Bruno Marchal

On 10 Jun 2009, at 20:00, Brent Meeker wrote:


 Bruno Marchal wrote:

 On 10 Jun 2009, at 02:20, Brent Meeker wrote:



 I think Godel's imcompleteness theorem already implies that there  
 must
 be non-unique extensions, (e.g. maybe you can add an axiom either  
 that
 there are infinitely many pairs of primes differing by two or the
 negative of that).  That would seem to be a reductio against the
 existence of a hypercomputer that could decide these propositions by
 inspection.


 Not at all. Gödel's theorem implies that there must be non-unique
 *consistent* extensions. But there is only one sound extension. The
 unsound consistent extensions, somehow, does no more talk about
 natural numbers.

 OK. But ISTM that statement implies that we are relying on an  
 intuitive notion
 as our conception of natural numbers, rather than a formal definition.

You are right. We have to rely on our intuition. After Gödel we know  
that even our use of formal system has to be based on our intuition of  
the natural number, and we don't have any fixed and complete  
formalization of the natural numbers.



 I guess I
 don't understand unsound in this context.

Unsound means false in the structure (N, +, *). We can define this  
formally in a theory which is richer than PA, like ZF set theory. Of  
course we can't define sound for ZF. Intuition just cannot be  
avoided. Today we can understand how machine can develop intuition,  
despite this cannot be formalized.





 Typical example: take the proposition that PA is inconsistant. By
 Gödel's second incompletenss theorem, we have that PA+PA is
 inconsistent is a consistent extension of PA. But it is not a sound
 one. It affirms the existence of a number which is a Gödel number  
 of a
 proof of 0=1. But such a number is not a usual number at all.

 Suppose, for example, that the twin primes conjecture is undecidable  
 in PA. Are
 you saying that either PA+TP or PA+~TP must be unsound?


Yes. That is why, unlike in Set Theory, nobody seriously doubt about  
the excluded middle principle in the structure (N,+,*).




 And what exactly does
 unsound mean?

It really means false in the structure (N,+,*).



 Does it have a formal definition or does it just mean
 violating our intuition about numbers?

As I said, you can formalize the notion of soundness in Set Theory.  
But this adds nothing, except that it shows that the notion of  
soundness has the same level of complexity that usual analytical or  
topological set theoretical notions. So you can also say that  
unsound means violation of our intuitive understanding of what the  
structure (N,+,*) consists in. We cannot formalize in any absolute  
way that understanding, but we can formalize it in richer theories  
used everyday by mathematicians.

Bruno


http://iridia.ulb.ac.be/~marchal/




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Re: The seven step-Mathematical preliminaries

2009-06-11 Thread Bruno Marchal
On 10 Jun 2009, at 20:17, Jesse Mazer wrote:


 From: marc...@ulb.ac.be
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries
 Date: Wed, 10 Jun 2009 18:03:26 +0200


 On 10 Jun 2009, at 01:50, Jesse Mazer wrote:



 Such an hypercomputer is just what Turing called an oracle. And  
 the haslting oracle is very low in the hierarchy of possible oracles.
 And Turing results is that even a transfinite ladder of more and  
 more powerful oracles that you can add on Peano Arithmetic,  will  
 not give you a complete theory. Hypercomputing by constructive  
 extension of PA, with more and more powerful oracles does not help  
 to overcome incompleteness, unless you add non constructive ordinal  
 extension of hypercomputation.
 This is the obeject of the study of the degrees of unsolvability,  
 originated by Emil Post.


 Interesting, thanks. But I find it hard to imagine what kind of  
 finite proposition about natural numbers could not be checked simply  
 by plugging in every possible value for whatever variables appear in  
 the proposition...certainly as long as the number of variables  
 appearing in the proposition is finite, the number of possible ways  
 of substituting specific values for those variables is countably  
 infinite and a hypercomputer should be able to check every case in a  
 finite time.


Countably infinite does not mean recursively countably infinite. This  
is something which I will explain in the seventh step thread.

There is theorem by Kleene which links Post-Turing degrees of  
unsolvability with the shape of arithmetical formula. With P  
denoting decidable predicates (Sigma_0) we have

ExP(x)  Sigma_1  (mechanical)
AxP(x) Pi_1
ExAyP(x,y) Sigma_2
AxEyP(x,y) Pi_2
etc.

This will defined countably infinite set which are more and more  
complex, and which needs more and more non-mechanical procedures. You  
can intuitively understand, perhaps, that to be the coded of an  
halting procedure (Sigma_1) needs less hypercomputation than to be  
the coded of an everywhere defined procedure, which is Sigma_2.





 Does what you're saying imply you can you have a proposition which  
 somehow implicitly involves an infinite number of distinct variables  
 even though it doesn't actually write them all out?

The complexity grows up even when you restrict yourself to a finite  
number of variables. By the theorem of Kleene, the complexity comes  
from the alternation of the quantifiers.



 Can all propositions about arbitrary *real* numbers (which are of  
 course uncountably infinite) be translated into equivalent  
 propositions about whole numbers in arithmetic?

Here you are jumping from arithmetical truth to analytical truth. In  
principle analytical truth extends the whole arithmetical hierarchy.  
So the correct answer is no. But this is for arbitrary analytical  
truth. By a sort of miracle, the analytical truth that we met in the  
everyday practice of analysis can be translated in arithmetical  
proposition. A well known example is the Riemann's hypothesis which is  
equivalent to a Pi_1 arithmetical proposition. I have personally  
stopped to believe in the relevance of analytical truth in the  
ontology. Epistemologically, it is not difficult to build arithmetical  
relation such that you need analytical devices to solve them. A bit  
like higher cardinal in set theory can provide light in combinatorial  
problems in braids and knots theory.


 Or am I taking the wrong approach here, and the reason a  
 hypercomputer can't decide every proposition about arithmetic  
 unrelated to the issue of how many distinct variables can appear in  
 a proposition?


It is related to the number of variables, but the hierarchy grows up  
without necessitating to go beyond finite number of variables. The  
interesting story about the degree of complexity of hypermachines  
happens between the recursively countable and the less and less  
recursively countable, and they are all captured by formula with  
finite number of variables.

I hope I will be able to put some light on this in the seventh step  
thread, or in some possible AUDA thread in the future. The quantified  
guardian angel, that is the modal logic G* extended with the  
quantifier, is already undecidable even in the presence of an oracle  
for the whole arithmetical truth. Even a GOD or hypermachine  
capable of answering all Sigma_i and Pi_i questions can still not  
answer general provability question bearing on a machine. The  
arithmetical second Plotinian God, that is Plato's NOUS, or  
intellect, is already beyond the reach of the first Plotinian God (the  
ONE, or arithmetical truth).

No machine can make a complete theory of what machine can and cannot  
do. When the complexity of machine go above the treshold of  
universality, they are faced with an intrinsically huge complexity.  
Machines can understand themselves only very partially. They can  
progress by transforming

Re: The seven step-Mathematical preliminaries

2009-06-11 Thread A. Wolf

 As I said, you can formalize the notion of soundness in Set Theory.  But 
 this adds nothing, except that it shows that the notion of  soundness has 
 the same level of complexity that usual analytical or  topological set 
 theoretical notions. So you can also say that  unsound means violation 
 of our intuitive understanding of what the structure (N,+,*) consists in. 
 We cannot formalize in any absolute way that understanding, but we can 
 formalize it in richer theories  used everyday by mathematicians.

You're using soundness in a different sense than I'm familiar with. 
Soundness is a property of logical systems that states in this proof 
system, provable implies true.  Godel's Completeness Theorem shows there 
exists a system of logic (first-order logic, specifically) that has this 
soundness property.  In other words, nothing for which an exact and complete 
proof in first-order logic exists, is false.

Soundness is particularly important to logicians because if a system is 
unsound, any proofs made with that system are essentially meaningless. 
There are limits to what you can do with higher-order logical systems 
because of this.

I think what you're bickering over isn't the soundness of the system.  I 
think it's the selection of the label natural number, which is a 
completely arbitrary label.  Any definition for natural number which is 
finite in scope refers to a different concept than the one we mean when we 
say natural number.  Any finite subset of N is less useful for 
mathematical proofs (and in some cases, much harder to define--not all 
subsets of N are definable in the structure {N: +, *}, after all) than the 
whole shebang, which is why we immediately prefer the infinite definition.

Anna


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Re: The seven step-Mathematical preliminaries

2009-06-11 Thread Bruno Marchal


On 11 Jun 2009, at 14:48, A. Wolf wrote:


 As I said, you can formalize the notion of soundness in Set  
 Theory.  But
 this adds nothing, except that it shows that the notion of   
 soundness has
 the same level of complexity that usual analytical or  topological  
 set
 theoretical notions. So you can also say that  unsound means  
 violation
 of our intuitive understanding of what the structure (N,+,*)  
 consists in.
 We cannot formalize in any absolute way that understanding, but  
 we can
 formalize it in richer theories  used everyday by mathematicians.

 You're using soundness in a different sense than I'm familiar with.


I am indeed not using the term soundness like it is used in  
soundness and completeness theorem, like for first order predicate  
logic.
I use it, like many provability logician to mean true in the  
standard (usual) model of arithmetic.

See
http://en.wikipedia.org/wiki/Soundness
There, they call arithmetic soundness what me (and many logician) call  
soundness, when they refer to theories about numbers.
Like Mendelson I prefer to use the term logically valid, to what you  
call soundness.

Should not be a problem in this list, given that we don't use the  
notion of models, nor of logical validity. I refer very rarely to  
Gödel's completness, and when I do so, I do it in the form  a theory  
has a model iff it is consistent (this can be proved to be the case  
for first order theory).


 Soundness is a property of logical systems that states in this proof
 system, provable implies true.  Godel's Completeness Theorem shows  
 there
 exists a system of logic (first-order logic, specifically) that has  
 this
 soundness property.  In other words, nothing for which an exact and  
 complete
 proof in first-order logic exists, is false.

 Soundness is particularly important to logicians because if a system  
 is
 unsound, any proofs made with that system are essentially meaningless.
 There are limits to what you can do with higher-order logical systems
 because of this.

I am not sure I follow you. You mean by true, I guess true in, or  
satisfied by, all models, or false in any models. A theory is sound  
if what is provable in the theory is satisfied by (true in) all models  
of the theory.
A deduction A = B is sound, or logically valid, if all models which  
satisfy  A satisfy B.

The word true alone has no meaning. It refers always to a model, or  
to a collection of models.




 I think what you're bickering over isn't the soundness of the system.

It is the arithmetical soundness.


  I
 think it's the selection of the label natural number, which is a
 completely arbitrary label.

Nooo, come on.



 Any definition for natural number which is
 finite in scope refers to a different concept than the one we mean  
 when we
 say natural number.

I don't see what you mean here. Robinson Arithmetic, which is a finite  
theory, can be see as a definition of the usual natural numbers, but  
like any definitions, finite or infinite (but then recursively  
axiomatisable), it has non standard models satisfying the definition.

Oh, you mean a definition of natural number such that the model would  
be finite in scope. This is non sense for me. Pace Torgny.


 Any finite subset of N is less useful for
 mathematical proofs (and in some cases, much harder to define--not all
 subsets of N are definable in the structure {N: +, *}, after all)  
 than the
 whole shebang, which is why we immediately prefer the infinite  
 definition.

Well, there is just no categorical first order definition of the  
finite sets of natural numbers. And second order definition, assumes  
the notion of infinite set.

Bruno


http://iridia.ulb.ac.be/~marchal/




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Re: The seven step-Mathematical preliminaries

2009-06-11 Thread Brent Meeker

A. Wolf wrote:
 As I said, you can formalize the notion of soundness in Set Theory.  But 
 this adds nothing, except that it shows that the notion of  soundness has 
 the same level of complexity that usual analytical or  topological set 
 theoretical notions. So you can also say that  unsound means violation 
 of our intuitive understanding of what the structure (N,+,*) consists in. 
 We cannot formalize in any absolute way that understanding, but we can 
 formalize it in richer theories  used everyday by mathematicians.
 
 You're using soundness in a different sense than I'm familiar with. 
 Soundness is a property of logical systems that states in this proof 
 system, provable implies true.  Godel's Completeness Theorem shows there 
 exists a system of logic (first-order logic, specifically) that has this 
 soundness property.  In other words, nothing for which an exact and complete 
 proof in first-order logic exists, is false.

I'm not sure I understand this.  True and false are just arbitrary 
attributes of propositions in logic.  I read you last sentence above as saying: 
Given premises, which I assume true, then any inference from them using 
first-order logic will be true.  But that just means I will not be able to 
infer a contradiction (=false).  In other words, first-order logic is 
consistent.

Of course if I start with contradictory premises I will be able construct a 
proof in first order logic that proves X and not-X which is false.

Brent

 
 Soundness is particularly important to logicians because if a system is 
 unsound, any proofs made with that system are essentially meaningless. 
 There are limits to what you can do with higher-order logical systems 
 because of this.
 
 I think what you're bickering over isn't the soundness of the system.  I 
 think it's the selection of the label natural number, which is a 
 completely arbitrary label.  Any definition for natural number which is 
 finite in scope refers to a different concept than the one we mean when we 
 say natural number.  Any finite subset of N is less useful for 
 mathematical proofs (and in some cases, much harder to define--not all 
 subsets of N are definable in the structure {N: +, *}, after all) than the 
 whole shebang, which is why we immediately prefer the infinite definition.
 
 Anna
 
 
  
 


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Re: The seven step-Mathematical preliminaries

2009-06-10 Thread Torgny Tholerus

Jesse Mazer skrev:


  Date: Tue, 9 Jun 2009 18:38:23 +0200
  From: tor...@dsv.su.se
  To: everything-list@googlegroups.com
  Subject: Re: The seven step-Mathematical preliminaries
 
  For you to be able to use the word all, you must define the domain
  of that word. If you do not define the domain, then it will be
  impossible for me and all other humans to understand what you are
  talking about.

 OK, so how do you say I should define this type of universe? Unless 
 you are demanding that I actually give you a list which spells out 
 every symbol-string that qualifies as a member, can't I simply provide 
 an abstract *rule* that would allow someone to determine in principle 
 if a particular symbol-string they are given qualifies? Or do you have 
 a third alternative besides spelling out every member or giving an 
 abstract rule?

You have to spell out every member.  Because in a *rule* you are 
(implicitely) using this type of universe, and you will then get a 
circular definition.  When you say that *every* number have a successor, 
you are presupposing that you already know what *every* means.

-- 
Torgny Tholerus

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Re: The seven step-Mathematical preliminaries

2009-06-10 Thread John Mikes
Torgny,
your par. 1:
I like your including all universes into *UNIVERSE*  if you talk about
it. WE, here in this universe think about them. No contact, no lead, just
our mental efforts. It all occurs in our prceived reality by thinking about
more.

your par.2:
domain is tricky. I like to write about 'totality' vs 'models i.e. the
identified cuts of it for our interest (other lists, other topics) and a
smart fellow (NZ) replied: your 'totality' IS a model. You identified it as
'all' (we can imagine) - which is not all that can, or cannot
exist. Possible, or impossible in our present views.

BTW to 'understand' what somebody talks about is also tricky: we can only
translate the 3rd pers. communication into our 1st pers. mindset so what we
understand is not (necessarily) what the other said. Or wanted to say.
Mindset is individual, no two persons can match in genetic origin (DNA,
input of lineage, circumstances in gestational development, plus plus plus),
AND the accumulated (personal) experience-material as applied to the
individual life-history and emotional responses.
Duo si faciunt idem, non est idem valid in ideation as well.

I once wrote a sci-fi with an intelligent alien society where the
communication consisted of direct transfer of ideas.
There was NO discussion.
Respectfully
John Mikes
On Tue, Jun 9, 2009 at 12:38 PM, Torgny Tholerus tor...@dsv.su.se wrote:


 Jesse Mazer skrev:
 
 
   Date: Sat, 6 Jun 2009 21:17:03 +0200
   From: tor...@dsv.su.se
   To: everything-list@googlegroups.com
   Subject: Re: The seven step-Mathematical preliminaries
  
   My philosophical argument is about the mening of the word all. To be
   able to use that word, you must associate it with a value set.
 
  What's a value set? And why do you say we must associate it in
  this way? Do you have a philosophical argument for this must, or is
  it just an edict that reflects your personal aesthetic preferences?
 
   Mostly that set is all objects in the universe, and if you stay
  inside the
   universe, there is no problems.
 
  *I* certainly don't define numbers in terms of any specific mapping
  between numbers and objects in the universe, it seems like a rather
  strange notion--shall we have arguments over whether the number 113485
  should be associated with this specific shoelace or this specific
  kangaroo?

 When I talk about universe here, I do not mean our physical universe.
 What I mean is something that can be called everything.  It includes
 all objects in our physical universe, as well as all symbols and all
 words and all numbers and all sets and all other universes.  It includes
 everything you can use the word all about.

 For you to be able to use the word all, you must define the domain
 of that word.  If you do not define the domain, then it will be
 impossible for me and all other humans to understand what you are
 talking about.

 --
 Torgny Tholerus

 


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Re: The seven step-Mathematical preliminaries

2009-06-10 Thread Bruno Marchal

On 10 Jun 2009, at 01:50, Jesse Mazer wrote:


 Isn't this based on the idea that there should be an objective truth  
 about every well-formed proposition about the natural numbers even  
 if the Peano axioms cannot decide the truth about all propositions?  
 I think that the statements that cannot be proved are disproved  
 would all be ones of the type for all numbers with property X, Y is  
 true or there exists a number (or some finite group of numbers)  
 with property X (i.e. propositions using either the 'for all' or  
 'there exists' universal quantifiers in logic, with variables  
 representing specific numbers or groups of numbers). So to believe  
 these statements are objectively true basically means there would be  
 a unique way to extend our judgment of the truth-values of  
 propositions from the judgments already given by the Peano axioms,  
 in such a way that if we could flip through all the infinite  
 propositions judged true by the Peano axioms, we would *not* find an  
 example of a proposition like for this specific number N with  
 property X, Y is false (which would disprove the 'for all'  
 proposition above), and likewise we would not find that for every  
 possible number (or group of numbers) N, the Peano axioms proved a  
 proposition like number N does not have property X (which would  
 disprove the 'there exists' proposition above).

 We can't actual flip through an infinite number of propositions in a  
 finite time of course, but if we had a hypercomputer that could do  
 so (which is equivalent to the notion of a hypercomputer that can  
 decide in finite time if any given Turing program halts or not),

Such an hypercomputer is just what Turing called an oracle. And the  
haslting oracle is very low in the hierarchy of possible oracles.
And Turing results is that even a transfinite ladder of more and more  
powerful oracles that you can add on Peano Arithmetic,  will not give  
you a complete theory. Hypercomputing by constructive extension of PA,  
with more and more powerful oracles does not help to overcome  
incompleteness, unless you add non constructive ordinal extension of  
hypercomputation.
This is the obeject of the study of the degrees of unsolvability,  
originated by Emil Post.
Arithmetical truth is big. No notion of hypercomputing can really  
help. Yet, the notion of arithmetical truth is well understood by  
everybody, and is easily definable (as opposed to effectively  
decidable or computable) in usual set theory. That is why logician  
have no problem with the notion of standrd model of Peano Arithmetic,  
for example.




 then I think we'd have a well-defined notion of how to program it to  
 decide the truth of every for all or there exists proposition in  
 a way that's compatible with the propositions already proved by the  
 Peano axioms.

Hypercomputation will not help. Unless you go to the higher non  
constructive transfinite. But of course, in that case you are using a  
theory much more powerful than peano Arithmetic and its extension by  
constructive ordinal. You have to already believe in the notion of  
truth on numbers to do that.




 If I'm right about that, it would lead naturally to the idea of  
 something like a unique consistent extension of the Peano axioms  
 (not a real technical term, I just made up this phrase, but unless  
 there's an error in my reasoning I imagine mathematicians have some  
 analogous notion...maybe Bruno knows?)


Just go to set theory. Arithmetical truth, or standard model of PA,  
can play that role. It is not effective (constructive) but it is well  
defined. Mathematicians used such notions everyday. If you belive in  
the excluded middle principle on closed arithmetical sentences, you  
are using implictly such notions.



 which assigns truth values to all the well-formed propositions that  
 are undecidable by the Peano axioms themselves.

You can do that in set theory. Of course, this is not an effective way  
to do it, but we know, by Godel, that completeness can never be given  
in any effective way. Set theory can define the standard model (your  
unique extension) of PA, but it is not a constructive object. In set  
theory, few object are constructive.



 So this would be a natural way of understanding the idea of truths  
 about the natural numbers that are not decidable by the Peano  
 axioms.

After Godel, truth, even on numbers can be well defined, in richer  
theory, but have to be non effective, non mechanical. It is not a  
reason to doubt about the truth of the arithmetical propositions. On  
the contrary it shows that such truth kicks back and refiute all  
effective definition we could belive in about that whole truth.



 Of course even if the notion of a unique consistent extension of  
 certain types of axiomatic systems is well-defined, it would only  
 make sense for axiomatic systems that are consistent in the first  
 place. I guess in judging the question of the 

Re: The seven step-Mathematical preliminaries

2009-06-10 Thread Bruno Marchal


On 10 Jun 2009, at 02:20, Brent Meeker wrote:



 I think Godel's imcompleteness theorem already implies that there must
 be non-unique extensions, (e.g. maybe you can add an axiom either that
 there are infinitely many pairs of primes differing by two or the
 negative of that).  That would seem to be a reductio against the
 existence of a hypercomputer that could decide these propositions by
 inspection.


Not at all. Gödel's theorem implies that there must be non-unique  
*consistent* extensions. But there is only one sound extension. The  
unsound consistent extensions, somehow, does no more talk about  
natural numbers.

Typical example: take the proposition that PA is inconsistant. By  
Gödel's second incompletenss theorem, we have that PA+PA is  
inconsistent is a consistent extension of PA. But it is not a sound  
one. It affirms the existence of a number which is a Gödel number of a  
proof of 0=1. But such a number is not a usual number at all.

An oracle for the whole arithmetical truth is well defined in set  
theory, even if it is a non effective object.

Bruno

http://iridia.ulb.ac.be/~marchal/




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Re: The seven step-Mathematical preliminaries

2009-06-10 Thread Bruno Marchal

On 10 Jun 2009, at 04:14, Jesse Mazer wrote:



 I think I remember reading in one of Roger Penrose's books that  
 there is a difference between an ordinary consistency condition  
 (which just means that no two propositions explicitly contradict  
 each other) and omega-consistency--see 
 http://en.wikipedia.org/wiki/Omega-consistent_theory 
  . I can't quite follow the details, but I'm guessing the condition  
 means (or at least includes) something like the idea that if you  
 have a statement of the form there exists a number (or set of  
 numbers) with property X then there must actually be some other  
 proposition describing a particular number (or set of numbers) does  
 in fact have this property. The fact that you can add either a Godel  
 statement or its negation to the Peano axioms without creating a  
 contradiction (as long as the Peano axioms are not inconsistent) may  
 not mean you can add either one and still have an omega-consistent  
 theory; if that's true, would there be a unique omega-consistent way  
 to set the truth value of all well-formed propositions about  
 arithmetic which are undecidable by the Peano axioms? Again, Bruno  
 might know...



The notion of omega-consistency is a red-herring. The notion exists  
only for technical reason. Gödel did not succeed in proving the  
undecidability of its Gödel-sentences without using it, but this  
will be done succesfully by Rosser.  Smullyan introduced better notion  
than omega-consistency, like his notion of stability, but personaly I  
prefer to use the (non effective, ok) notion of soundness, and use the  
notion of stability only latter in more advanced course. The notion of  
arithmetical soundness was not well seen at the time of Gödel, due to  
historical circumstances. That's all.

But the answer is no. There are non unique omega-consistent  
extension of PA. Omega-consistency is just a bit more powerful than  
consistency for proviong undecidability, but Rosser has been able to  
replace omega-consistency by consistency in the proof of the existence  
of undecidable statements. Would Gödel have seen Rosser point before  
Rosser, the notion of omega-consistency could have not appeared at all.

I will probably come back on stability, consistency and soundness when  
we arrive at the AUDA part. This is not for tomorrow. I can give  
references, well see my URL.

Bruno


http://iridia.ulb.ac.be/~marchal/




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Re: The seven step-Mathematical preliminaries

2009-06-10 Thread Brent Meeker

Bruno Marchal wrote:
 
 On 10 Jun 2009, at 02:20, Brent Meeker wrote:
 
 
 
 I think Godel's imcompleteness theorem already implies that there must
 be non-unique extensions, (e.g. maybe you can add an axiom either that
 there are infinitely many pairs of primes differing by two or the
 negative of that).  That would seem to be a reductio against the
 existence of a hypercomputer that could decide these propositions by
 inspection.
 
 
 Not at all. Gödel's theorem implies that there must be non-unique  
 *consistent* extensions. But there is only one sound extension. The  
 unsound consistent extensions, somehow, does no more talk about  
 natural numbers.

OK. But ISTM that statement implies that we are relying on an intuitive notion 
as our conception of natural numbers, rather than a formal definition. I guess 
I 
don't understand unsound in this context.

 
 Typical example: take the proposition that PA is inconsistant. By  
 Gödel's second incompletenss theorem, we have that PA+PA is  
 inconsistent is a consistent extension of PA. But it is not a sound  
 one. It affirms the existence of a number which is a Gödel number of a  
 proof of 0=1. But such a number is not a usual number at all.

Suppose, for example, that the twin primes conjecture is undecidable in PA. Are 
you saying that either PA+TP or PA+~TP must be unsound?  And what exactly does 
unsound mean?  Does it have a formal definition or does it just mean 
violating our intuition about numbers?

Brent

 
 An oracle for the whole arithmetical truth is well defined in set  
 theory, even if it is a non effective object.
 
 Bruno
 
 http://iridia.ulb.ac.be/~marchal/
 
 
 
 
  
 


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RE: The seven step-Mathematical preliminaries

2009-06-10 Thread Jesse Mazer



 Date: Wed, 10 Jun 2009 09:18:10 +0200
 From: tor...@dsv.su.se
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries
 
 
 Jesse Mazer skrev:


 Date: Tue, 9 Jun 2009 18:38:23 +0200
 From: tor...@dsv.su.se
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries

 For you to be able to use the word all, you must define the domain
 of that word. If you do not define the domain, then it will be
 impossible for me and all other humans to understand what you are
 talking about.

 OK, so how do you say I should define this type of universe? Unless 
 you are demanding that I actually give you a list which spells out 
 every symbol-string that qualifies as a member, can't I simply provide 
 an abstract *rule* that would allow someone to determine in principle 
 if a particular symbol-string they are given qualifies? Or do you have 
 a third alternative besides spelling out every member or giving an 
 abstract rule?
 
 You have to spell out every member.  
Where does this have to come from? Again, is it something you have a 
philosophical or logical definition for, or is it just your aesthetic 
preference?
Because in a *rule* you are 
 (implicitely) using this type of universe, and you will then get a 
 circular definition.
A good rule (as opposed to a 'bad' rule like 'the set of all sets that do not 
contain themselves') gives a perfectly well-defined criteria for what is 
contained in the universe, such that no one will ever have cause to be unsure 
about whether some particular symbol-string they're given at belongs in this 
universe. It's only circular if you say in advance that there is something 
problematic about rules which define infinite universes, but again this just 
seems like your aesthetic preference and not something you have given any 
philosophical/logical justification for.
Jesse
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RE: The seven step-Mathematical preliminaries

2009-06-10 Thread Jesse Mazer



From: marc...@ulb.ac.be
To: everything-list@googlegroups.com
Subject: Re: The seven step-Mathematical preliminaries
Date: Wed, 10 Jun 2009 18:03:26 +0200


On 10 Jun 2009, at 01:50, Jesse Mazer wrote:

Isn't this based on the idea that there should be an objective truth about 
every well-formed proposition about the natural numbers even if the Peano 
axioms cannot decide the truth about all propositions? I think that the 
statements that cannot be proved are disproved would all be ones of the type 
for all numbers with property X, Y is true or there exists a number (or some 
finite group of numbers) with property X (i.e. propositions using either the 
'for all' or 'there exists' universal quantifiers in logic, with variables 
representing specific numbers or groups of numbers). So to believe these 
statements are objectively true basically means there would be a unique way to 
extend our judgment of the truth-values of propositions from the judgments 
already given by the Peano axioms, in such a way that if we could flip through 
all the infinite propositions judged true by the Peano axioms, we would *not* 
find an example of a proposition like for this specific number N with property 
X, Y is false (which would disprove the 'for all' proposition above), and 
likewise we would not find that for every possible number (or group of numbers) 
N, the Peano axioms proved a proposition like number N does not have property 
X (which would disprove the 'there exists' proposition above). 
We can't actual flip through an infinite number of propositions in a finite 
time of course, but if we had a hypercomputer that could do so (which is 
equivalent to the notion of a hypercomputer that can decide in finite time if 
any given Turing program halts or not), 
Such an hypercomputer is just what Turing called an oracle. And the haslting 
oracle is very low in the hierarchy of possible oracles.And Turing results is 
that even a transfinite ladder of more and more powerful oracles that you can 
add on Peano Arithmetic,  will not give you a complete theory. Hypercomputing 
by constructive extension of PA, with more and more powerful oracles does not 
help to overcome incompleteness, unless you add non constructive ordinal 
extension of hypercomputation.This is the obeject of the study of the 
degrees of unsolvability, originated by Emil Post.

Interesting, thanks. But I find it hard to imagine what kind of finite 
proposition about natural numbers could not be checked simply by plugging in 
every possible value for whatever variables appear in the 
proposition...certainly as long as the number of variables appearing in the 
proposition is finite, the number of possible ways of substituting specific 
values for those variables is countably infinite and a hypercomputer should be 
able to check every case in a finite time. Does what you're saying imply you 
can you have a proposition which somehow implicitly involves an infinite number 
of distinct variables even though it doesn't actually write them all out? Can 
all propositions about arbitrary *real* numbers (which are of course 
uncountably infinite) be translated into equivalent propositions about whole 
numbers in arithmetic? Or am I taking the wrong approach here, and the reason a 
hypercomputer can't decide every proposition about arithmetic unrelated to the 
issue of how many distinct variables can appear in a proposition? 
Jesse
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Re: The seven step-Mathematical preliminaries

2009-06-10 Thread Bruno Marchal

Of course, Torgny stops, in the UD Argument, at step 0. He disbelieves  
classical computationalism.

The yes doctor is made senseless; because he is a zombie, and  
Church thesis becomes senseless, because he is ultrafinitist, and  
Church thesis concerns functions from N to N, or from N to 2, and NXN  
to N, ... It concerns those computable and non computable objects. N=   
{0, 1, 2, 3, ...}.

But yes, we need N, and its structure (N,+,x). We cannot prove that N  
exists. But we can postulate its existence, give it a recursive name,  
and generate and develop more and more simple and powerful theories  
about it and its structure. Usual math use N, and its images all the  
times. Only a philosopher can be paid to doubt N. A good thing!

Without N, no universal machine, no universal person.

And no Mandelbrot Set M is available for an ultrafinitist, given the  
bijection between N and the little Mandelbrots (those the M set is  
made of!).

Here
http://www.youtube.com/watch?v=1l9N5a0nxuQfeature=channel
A beautiful illustration that the M set summarizes its histories, 2  
times, 4 times, 8 times 16 times, 32 times ... around its little  
Mandelbrot sets, (or around its histories ...).  In the zoom here, a  
feature of the history is going near the tail of a little Mandelbrot  
set, and both the music and image coloring (different in the zoom in  
and the zoom out) illustrates that Hopf bifurcation where the  
neighborhoods are multiplied by two, iteratively, and with an  
accelerating frequence, so that the limit (of 2^n) gives a little  
mandelbrot set (or ...).

Bruno



On 10 Jun 2009, at 18:24, Bruno Marchal wrote:



 On 10 Jun 2009, at 02:20, Brent Meeker wrote:




 So we believe in the consistency of Peano's arithmetic because we
 have a
 physical model.

 Why physical? And do we have a physical model? I would say we belive
 in the consistency (and soundness) of PA because we have a model of
 PA, the well known structure (N, 0, +, *).

 If comp is true, there is no physical model at all. (But this is not
 something on which I want to insist for now).

 Bruno



 http://iridia.ulb.ac.be/~marchal/




 

http://iridia.ulb.ac.be/~marchal/




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Re: The seven step-Mathematical preliminaries

2009-06-09 Thread Torgny Tholerus

Jesse Mazer skrev:


  Date: Sat, 6 Jun 2009 21:17:03 +0200
  From: tor...@dsv.su.se
  To: everything-list@googlegroups.com
  Subject: Re: The seven step-Mathematical preliminaries
 
  My philosophical argument is about the mening of the word all. To be
  able to use that word, you must associate it with a value set.

 What's a value set? And why do you say we must associate it in 
 this way? Do you have a philosophical argument for this must, or is 
 it just an edict that reflects your personal aesthetic preferences?

  Mostly that set is all objects in the universe, and if you stay 
 inside the
  universe, there is no problems.

 *I* certainly don't define numbers in terms of any specific mapping 
 between numbers and objects in the universe, it seems like a rather 
 strange notion--shall we have arguments over whether the number 113485 
 should be associated with this specific shoelace or this specific 
 kangaroo?

When I talk about universe here, I do not mean our physical universe.  
What I mean is something that can be called everything.  It includes 
all objects in our physical universe, as well as all symbols and all 
words and all numbers and all sets and all other universes.  It includes 
everything you can use the word all about.

For you to be able to use the word all, you must define the domain 
of that word.  If you do not define the domain, then it will be 
impossible for me and all other humans to understand what you are 
talking about.

-- 
Torgny Tholerus

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Re: The seven step-Mathematical preliminaries

2009-06-09 Thread Quentin Anciaux

2009/6/9 Torgny Tholerus tor...@dsv.su.se:

 Jesse Mazer skrev:


  Date: Sat, 6 Jun 2009 21:17:03 +0200
  From: tor...@dsv.su.se
  To: everything-list@googlegroups.com
  Subject: Re: The seven step-Mathematical preliminaries
 
  My philosophical argument is about the mening of the word all. To be
  able to use that word, you must associate it with a value set.

 What's a value set? And why do you say we must associate it in
 this way? Do you have a philosophical argument for this must, or is
 it just an edict that reflects your personal aesthetic preferences?

  Mostly that set is all objects in the universe, and if you stay
 inside the
  universe, there is no problems.

 *I* certainly don't define numbers in terms of any specific mapping
 between numbers and objects in the universe, it seems like a rather
 strange notion--shall we have arguments over whether the number 113485
 should be associated with this specific shoelace or this specific
 kangaroo?

 When I talk about universe here, I do not mean our physical universe.
 What I mean is something that can be called everything.  It includes
 all objects in our physical universe, as well as all symbols and all
 words and all numbers and all sets and all other universes.  It includes
 everything you can use the word all about.

It includes all set, but no all set as it N includes all natural
number but not all natural number... excuse-me but this is non-sense.
Either N exists and has an infinite number of member and is
incompatible with an ultrafinitist view or N does not exists because
obviously N cannot be defined in an ultra-finitist way, any set that
contains a finite number of natural number (and still you haven't
defined what it is in an ultrafinitist way) are not the set N.

Also any operation involving two number (addition/multiplication) can
yield as result a number which has the same property as the departing
number (being a natural number) but is not natural number... Also
induction and inference cannot work in such a context.

 For you to be able to use the word all, you must define the domain
 of that word.  If you do not define the domain, then it will be
 impossible for me and all other humans to understand what you are
 talking about.

Well you are the first and only human I know who don't understand
all as everybody else does.

Quentin Anciaux


 --
 Torgny Tholerus

 




-- 
All those moments will be lost in time, like tears in rain.

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Re: The seven step-Mathematical preliminaries

2009-06-09 Thread Brent Meeker

Quentin Anciaux wrote:
 2009/6/9 Torgny Tholerus tor...@dsv.su.se:
   
 Jesse Mazer skrev:
 
   
 Date: Sat, 6 Jun 2009 21:17:03 +0200
 From: tor...@dsv.su.se
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries

 My philosophical argument is about the mening of the word all. To be
 able to use that word, you must associate it with a value set.
 
 What's a value set? And why do you say we must associate it in
 this way? Do you have a philosophical argument for this must, or is
 it just an edict that reflects your personal aesthetic preferences?

   
 Mostly that set is all objects in the universe, and if you stay
 
 inside the
   
 universe, there is no problems.
 
 *I* certainly don't define numbers in terms of any specific mapping
 between numbers and objects in the universe, it seems like a rather
 strange notion--shall we have arguments over whether the number 113485
 should be associated with this specific shoelace or this specific
 kangaroo?
   
 When I talk about universe here, I do not mean our physical universe.
 What I mean is something that can be called everything.  It includes
 all objects in our physical universe, as well as all symbols and all
 words and all numbers and all sets and all other universes.  It includes
 everything you can use the word all about.
 

 It includes all set, but no all set as it N includes all natural
 number but not all natural number... excuse-me but this is non-sense.
 Either N exists and has an infinite number of member and is
 incompatible with an ultrafinitist view or N does not exists because
 obviously N cannot be defined in an ultra-finitist way, 

That's not obvious to me.  You're assuming that N exists apart from 
whatever definition of it is given and that it is the infinite set 
described by the Peano axioms or equivalent.  But that's begging the 
question of whether a finite set of numbers that we would call natural 
numbers can be defined.  To avoid begging the question we need some 
definition of natural that doesn't a priori assume the set is finite 
or infinite; something like, A set of numbers adequate to do all 
arithmetic we'll ever need (unfortunately not very definite).  The 
problem is the successor axiom, if we modify it to S{n}=n+1 for n e N 
except for the case n=N where S{N}=0 and choose sufficiently large N it 
might satisfy the natural criteria.

Brent


 any set that
 contains a finite number of natural number (and still you haven't
 defined what it is in an ultrafinitist way) are not the set N.

 Also any operation involving two number (addition/multiplication) can
 yield as result a number which has the same property as the departing
 number (being a natural number) but is not natural number... Also
 induction and inference cannot work in such a context.

   
 For you to be able to use the word all, you must define the domain
 of that word.  If you do not define the domain, then it will be
 impossible for me and all other humans to understand what you are
 talking about.
 

 Well you are the first and only human I know who don't understand
 all as everybody else does.

 Quentin Anciaux

   
 --
 Torgny Tholerus

 



   


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Re: The seven step-Mathematical preliminaries

2009-06-09 Thread Quentin Anciaux

You have to explain why the exception is needed in the first place...

The rule is true until the rule is not true anymore, ok but you have
to explain for what sufficiently large N the successor function would
yield next 0 and why or to add that N and that exception to the
successor function as axiom, if not you can't avoid N+1. But torgny
doesn't evacuate N+1, merely it allows his set to grows undefinitelly
as when he has defined BIGGEST, he still argues BIGGEST+1 makes sense
, is a natural number but not part of the set of natural number, this
is non-sense, assuming your special successor rule BIGGEST+1 simply
does not exists at all.

I can understand this overflow successor function for a finite data
type or a real machine registe but not for N. The successor function
is simple, if you want it to have an exception at biggest you should
justify it.

Regards,
Quentin

2009/6/9 Brent Meeker meeke...@dslextreme.com:

 Quentin Anciaux wrote:
 2009/6/9 Torgny Tholerus tor...@dsv.su.se:

 Jesse Mazer skrev:


 Date: Sat, 6 Jun 2009 21:17:03 +0200
 From: tor...@dsv.su.se
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries

 My philosophical argument is about the mening of the word all. To be
 able to use that word, you must associate it with a value set.

 What's a value set? And why do you say we must associate it in
 this way? Do you have a philosophical argument for this must, or is
 it just an edict that reflects your personal aesthetic preferences?


 Mostly that set is all objects in the universe, and if you stay

 inside the

 universe, there is no problems.

 *I* certainly don't define numbers in terms of any specific mapping
 between numbers and objects in the universe, it seems like a rather
 strange notion--shall we have arguments over whether the number 113485
 should be associated with this specific shoelace or this specific
 kangaroo?

 When I talk about universe here, I do not mean our physical universe.
 What I mean is something that can be called everything.  It includes
 all objects in our physical universe, as well as all symbols and all
 words and all numbers and all sets and all other universes.  It includes
 everything you can use the word all about.


 It includes all set, but no all set as it N includes all natural
 number but not all natural number... excuse-me but this is non-sense.
 Either N exists and has an infinite number of member and is
 incompatible with an ultrafinitist view or N does not exists because
 obviously N cannot be defined in an ultra-finitist way,

 That's not obvious to me.  You're assuming that N exists apart from
 whatever definition of it is given and that it is the infinite set
 described by the Peano axioms or equivalent.  But that's begging the
 question of whether a finite set of numbers that we would call natural
 numbers can be defined.  To avoid begging the question we need some
 definition of natural that doesn't a priori assume the set is finite
 or infinite; something like, A set of numbers adequate to do all
 arithmetic we'll ever need (unfortunately not very definite).  The
 problem is the successor axiom, if we modify it to S{n}=n+1 for n e N
 except for the case n=N where S{N}=0 and choose sufficiently large N it
 might satisfy the natural criteria.

 Brent


 any set that
 contains a finite number of natural number (and still you haven't
 defined what it is in an ultrafinitist way) are not the set N.

 Also any operation involving two number (addition/multiplication) can
 yield as result a number which has the same property as the departing
 number (being a natural number) but is not natural number... Also
 induction and inference cannot work in such a context.


 For you to be able to use the word all, you must define the domain
 of that word.  If you do not define the domain, then it will be
 impossible for me and all other humans to understand what you are
 talking about.


 Well you are the first and only human I know who don't understand
 all as everybody else does.

 Quentin Anciaux


 --
 Torgny Tholerus








 




-- 
All those moments will be lost in time, like tears in rain.

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Re: The seven step-Mathematical preliminaries

2009-06-09 Thread Brian Tenneson
I think that resorting to calling the biggest natural number BIGGEST, 
rather than specifying exactly what that number is, is a tell-tale sign 
that the ultrafinitist knows that any specification for BIGGEST will 
immediately reveal that it is not the biggest because one could always 
add one more.

Quentin Anciaux wrote:
 You have to explain why the exception is needed in the first place...

 The rule is true until the rule is not true anymore, ok but you have
 to explain for what sufficiently large N the successor function would
 yield next 0 and why or to add that N and that exception to the
 successor function as axiom, if not you can't avoid N+1. But torgny
 doesn't evacuate N+1, merely it allows his set to grows undefinitelly
 as when he has defined BIGGEST, he still argues BIGGEST+1 makes sense
 , is a natural number but not part of the set of natural number, this
 is non-sense, assuming your special successor rule BIGGEST+1 simply
 does not exists at all.

 I can understand this overflow successor function for a finite data
 type or a real machine registe but not for N. The successor function
 is simple, if you want it to have an exception at biggest you should
 justify it.

 Regards,
 Quentin

 2009/6/9 Brent Meeker meeke...@dslextreme.com:
   
 Quentin Anciaux wrote:
 
 2009/6/9 Torgny Tholerus tor...@dsv.su.se:

   
 Jesse Mazer skrev:

 
 Date: Sat, 6 Jun 2009 21:17:03 +0200
 From: tor...@dsv.su.se
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries

 My philosophical argument is about the mening of the word all. To be
 able to use that word, you must associate it with a value set.

 
 What's a value set? And why do you say we must associate it in
 this way? Do you have a philosophical argument for this must, or is
 it just an edict that reflects your personal aesthetic preferences?


   
 Mostly that set is all objects in the universe, and if you stay

 
 inside the

   
 universe, there is no problems.

 
 *I* certainly don't define numbers in terms of any specific mapping
 between numbers and objects in the universe, it seems like a rather
 strange notion--shall we have arguments over whether the number 113485
 should be associated with this specific shoelace or this specific
 kangaroo?

   
 When I talk about universe here, I do not mean our physical universe.
 What I mean is something that can be called everything.  It includes
 all objects in our physical universe, as well as all symbols and all
 words and all numbers and all sets and all other universes.  It includes
 everything you can use the word all about.

 
 It includes all set, but no all set as it N includes all natural
 number but not all natural number... excuse-me but this is non-sense.
 Either N exists and has an infinite number of member and is
 incompatible with an ultrafinitist view or N does not exists because
 obviously N cannot be defined in an ultra-finitist way,
   
 That's not obvious to me.  You're assuming that N exists apart from
 whatever definition of it is given and that it is the infinite set
 described by the Peano axioms or equivalent.  But that's begging the
 question of whether a finite set of numbers that we would call natural
 numbers can be defined.  To avoid begging the question we need some
 definition of natural that doesn't a priori assume the set is finite
 or infinite; something like, A set of numbers adequate to do all
 arithmetic we'll ever need (unfortunately not very definite).  The
 problem is the successor axiom, if we modify it to S{n}=n+1 for n e N
 except for the case n=N where S{N}=0 and choose sufficiently large N it
 might satisfy the natural criteria.

 Brent


 
 any set that
 contains a finite number of natural number (and still you haven't
 defined what it is in an ultrafinitist way) are not the set N.

 Also any operation involving two number (addition/multiplication) can
 yield as result a number which has the same property as the departing
 number (being a natural number) but is not natural number... Also
 induction and inference cannot work in such a context.


   
 For you to be able to use the word all, you must define the domain
 of that word.  If you do not define the domain, then it will be
 impossible for me and all other humans to understand what you are
 talking about.

 
 Well you are the first and only human I know who don't understand
 all as everybody else does.

 Quentin Anciaux


   
 --
 Torgny Tholerus


 


   
 



   

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Re: The seven step-Mathematical preliminaries

2009-06-09 Thread Quentin Anciaux

Let me correct...

Assuming your special successor rule BIGGEST+1 simply is 0 and is well
defined and *is part* of the previously defined set of natural number
(defined as 0,...,BIGGEST) unlike what Torgny argues.

Regards,
Quentin

2009/6/9 Quentin Anciaux allco...@gmail.com:
 You have to explain why the exception is needed in the first place...

 The rule is true until the rule is not true anymore, ok but you have
 to explain for what sufficiently large N the successor function would
 yield next 0 and why or to add that N and that exception to the
 successor function as axiom, if not you can't avoid N+1. But torgny
 doesn't evacuate N+1, merely it allows his set to grows undefinitelly
 as when he has defined BIGGEST, he still argues BIGGEST+1 makes sense
 , is a natural number but not part of the set of natural number, this
 is non-sense, assuming your special successor rule BIGGEST+1 simply
 does not exists at all.

 I can understand this overflow successor function for a finite data
 type or a real machine registe but not for N. The successor function
 is simple, if you want it to have an exception at biggest you should
 justify it.

 Regards,
 Quentin

 2009/6/9 Brent Meeker meeke...@dslextreme.com:

 Quentin Anciaux wrote:
 2009/6/9 Torgny Tholerus tor...@dsv.su.se:

 Jesse Mazer skrev:


 Date: Sat, 6 Jun 2009 21:17:03 +0200
 From: tor...@dsv.su.se
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries

 My philosophical argument is about the mening of the word all. To be
 able to use that word, you must associate it with a value set.

 What's a value set? And why do you say we must associate it in
 this way? Do you have a philosophical argument for this must, or is
 it just an edict that reflects your personal aesthetic preferences?


 Mostly that set is all objects in the universe, and if you stay

 inside the

 universe, there is no problems.

 *I* certainly don't define numbers in terms of any specific mapping
 between numbers and objects in the universe, it seems like a rather
 strange notion--shall we have arguments over whether the number 113485
 should be associated with this specific shoelace or this specific
 kangaroo?

 When I talk about universe here, I do not mean our physical universe.
 What I mean is something that can be called everything.  It includes
 all objects in our physical universe, as well as all symbols and all
 words and all numbers and all sets and all other universes.  It includes
 everything you can use the word all about.


 It includes all set, but no all set as it N includes all natural
 number but not all natural number... excuse-me but this is non-sense.
 Either N exists and has an infinite number of member and is
 incompatible with an ultrafinitist view or N does not exists because
 obviously N cannot be defined in an ultra-finitist way,

 That's not obvious to me.  You're assuming that N exists apart from
 whatever definition of it is given and that it is the infinite set
 described by the Peano axioms or equivalent.  But that's begging the
 question of whether a finite set of numbers that we would call natural
 numbers can be defined.  To avoid begging the question we need some
 definition of natural that doesn't a priori assume the set is finite
 or infinite; something like, A set of numbers adequate to do all
 arithmetic we'll ever need (unfortunately not very definite).  The
 problem is the successor axiom, if we modify it to S{n}=n+1 for n e N
 except for the case n=N where S{N}=0 and choose sufficiently large N it
 might satisfy the natural criteria.

 Brent


 any set that
 contains a finite number of natural number (and still you haven't
 defined what it is in an ultrafinitist way) are not the set N.

 Also any operation involving two number (addition/multiplication) can
 yield as result a number which has the same property as the departing
 number (being a natural number) but is not natural number... Also
 induction and inference cannot work in such a context.


 For you to be able to use the word all, you must define the domain
 of that word.  If you do not define the domain, then it will be
 impossible for me and all other humans to understand what you are
 talking about.


 Well you are the first and only human I know who don't understand
 all as everybody else does.

 Quentin Anciaux


 --
 Torgny Tholerus








 




 --
 All those moments will be lost in time, like tears in rain.




-- 
All those moments will be lost in time, like tears in rain.

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Re: The seven step-Mathematical preliminaries

2009-06-09 Thread Brent Meeker

Quentin Anciaux wrote:
 You have to explain why the exception is needed in the first place...
 
 The rule is true until the rule is not true anymore, ok but you have
 to explain for what sufficiently large N the successor function would
 yield next 0 and why or to add that N and that exception to the
 successor function as axiom, if not you can't avoid N+1. But torgny
 doesn't evacuate N+1, merely it allows his set to grows undefinitelly
 as when he has defined BIGGEST, he still argues BIGGEST+1 makes sense
 , is a natural number but not part of the set of natural number, this
 is non-sense, assuming your special successor rule BIGGEST+1 simply
 does not exists at all.
 
 I can understand this overflow successor function for a finite data
 type or a real machine registe but not for N. The successor function
 is simple, if you want it to have an exception at biggest you should
 justify it.

You don't justify definitions.  How would you justify Peano's axioms as being 
the right ones?  You are just confirming my point that you are begging the 
question by assuming there is a set called the natural numbers that exists 
independently of it's definition and it satisfies Peano's axioms.  Torgny is 
denying that and pointing out that we cannot know of infinite sets that exist 
independent of their definition because we cannot extensively define an 
infinite 
set, we can only know about it what we can prove from its definition.

So the numbers modulo BIGGEST+1 and Peano's numbers are both mathematical 
objects.  The first however is more definite than the second, since Godel's 
theorems don't apply.  Which one is called the *natural* numbers is a 
convention 
which might not have any practical consequences for sufficiently large BIGGEST.

Brent


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RE: The seven step-Mathematical preliminaries

2009-06-09 Thread Jesse Mazer



 Date: Tue, 9 Jun 2009 18:38:23 +0200
 From: tor...@dsv.su.se
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries
 
 
 Jesse Mazer skrev:


 Date: Sat, 6 Jun 2009 21:17:03 +0200
 From: tor...@dsv.su.se
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries

 My philosophical argument is about the mening of the word all. To be
 able to use that word, you must associate it with a value set.

 What's a value set? And why do you say we must associate it in 
 this way? Do you have a philosophical argument for this must, or is 
 it just an edict that reflects your personal aesthetic preferences?

 Mostly that set is all objects in the universe, and if you stay 
 inside the
 universe, there is no problems.

 *I* certainly don't define numbers in terms of any specific mapping 
 between numbers and objects in the universe, it seems like a rather 
 strange notion--shall we have arguments over whether the number 113485 
 should be associated with this specific shoelace or this specific 
 kangaroo?
 
 When I talk about universe here, I do not mean our physical universe.  
 What I mean is something that can be called everything.  It includes 
 all objects in our physical universe, as well as all symbols and all 
 words and all numbers and all sets and all other universes.  It includes 
 everything you can use the word all about.
 
 For you to be able to use the word all, you must define the domain 
 of that word.  If you do not define the domain, then it will be 
 impossible for me and all other humans to understand what you are 
 talking about.

OK, so how do you say I should define this type of universe? Unless you are 
demanding that I actually give you a list which spells out every symbol-string 
that qualifies as a member, can't I simply provide an abstract *rule* that 
would allow someone to determine in principle if a particular symbol-string 
they are given qualifies? Or do you have a third alternative besides spelling 
out every member or giving an abstract rule?

Jesse
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Re: The seven step-Mathematical preliminaries

2009-06-09 Thread Quentin Anciaux

2009/6/9 Brent Meeker meeke...@dslextreme.com:

 Quentin Anciaux wrote:
 You have to explain why the exception is needed in the first place...

 The rule is true until the rule is not true anymore, ok but you have
 to explain for what sufficiently large N the successor function would
 yield next 0 and why or to add that N and that exception to the
 successor function as axiom, if not you can't avoid N+1. But torgny
 doesn't evacuate N+1, merely it allows his set to grows undefinitelly
 as when he has defined BIGGEST, he still argues BIGGEST+1 makes sense
 , is a natural number but not part of the set of natural number, this
 is non-sense, assuming your special successor rule BIGGEST+1 simply
 does not exists at all.

 I can understand this overflow successor function for a finite data
 type or a real machine registe but not for N. The successor function
 is simple, if you want it to have an exception at biggest you should
 justify it.

 You don't justify definitions.

then you say it is an axiom, no problem with that.

 How would you justify Peano's axioms as being the right ones?

You don't, and either I misexpressed myself or you did not understood.

 You are just confirming my point that you are begging the
 question by assuming there is a set called the natural numbers that exists
 independently of it's definition and it satisfies Peano's axioms.

No, I have a definition for a set called the set of natural number,
this set is defined by the peano's axioms and the set defined by these
axioms is unbounded and it is called the set of natural number. Any
upper limit bounded set containing natural number is not N but a
subset of N.

http://en.wikipedia.org/wiki/Natural_number#Formal_definitions

The set Torgny is talking about is not N, like a dog is not a cat, he
can call it whatever he likes but not N.
But merely what I want to point out is that the definition he use is
inconsistent unlike yours which is simply modulo arithmetics.

http://en.wikipedia.org/wiki/Modular_arithmetic



 Torgny is
 denying that and pointing out that we cannot know of infinite sets that exist
 independent of their definition because we cannot extensively define an 
 infinite
 set, we can only know about it what we can prove from its definition.

 So the numbers modulo BIGGEST+1 and Peano's numbers are both mathematical
 objects.  The first however is more definite than the second, since Godel's
 theorems don't apply.  Which one is called the *natural* numbers is a 
 convention
 which might not have any practical consequences for sufficiently large 
 BIGGEST.

 Brent


 




-- 
All those moments will be lost in time, like tears in rain.

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Re: The seven step-Mathematical preliminaries

2009-06-09 Thread Quentin Anciaux

2009/6/9 Quentin Anciaux allco...@gmail.com:
 2009/6/9 Brent Meeker meeke...@dslextreme.com:

 Quentin Anciaux wrote:
 You have to explain why the exception is needed in the first place...

 The rule is true until the rule is not true anymore, ok but you have
 to explain for what sufficiently large N the successor function would
 yield next 0 and why or to add that N and that exception to the
 successor function as axiom, if not you can't avoid N+1. But torgny
 doesn't evacuate N+1, merely it allows his set to grows undefinitelly
 as when he has defined BIGGEST, he still argues BIGGEST+1 makes sense
 , is a natural number but not part of the set of natural number, this
 is non-sense, assuming your special successor rule BIGGEST+1 simply
 does not exists at all.

 I can understand this overflow successor function for a finite data
 type or a real machine registe but not for N. The successor function
 is simple, if you want it to have an exception at biggest you should
 justify it.

 You don't justify definitions.

 then you say it is an axiom, no problem with that.

And your axiom can't just say there is a BIGGEST number without having
a rule to either find it or discriminate it or setting the value
arbitrarily.

BIGGEST must be a well defined number not a boundary that you can't
reach... because if it was the case you're no more an ultrafinitist
and N is not a problem.

 How would you justify Peano's axioms as being the right ones?

 You don't, and either I misexpressed myself or you did not understood.

 You are just confirming my point that you are begging the
 question by assuming there is a set called the natural numbers that exists
 independently of it's definition and it satisfies Peano's axioms.

 No, I have a definition for a set called the set of natural number,
 this set is defined by the peano's axioms and the set defined by these
 axioms is unbounded and it is called the set of natural number. Any
 upper limit bounded set containing natural number is not N but a
 subset of N.

 http://en.wikipedia.org/wiki/Natural_number#Formal_definitions

 The set Torgny is talking about is not N, like a dog is not a cat, he
 can call it whatever he likes but not N.
 But merely what I want to point out is that the definition he use is
 inconsistent unlike yours which is simply modulo arithmetics.

 http://en.wikipedia.org/wiki/Modular_arithmetic



 Torgny is
 denying that and pointing out that we cannot know of infinite sets that exist
 independent of their definition because we cannot extensively define an 
 infinite
 set, we can only know about it what we can prove from its definition.

 So the numbers modulo BIGGEST+1 and Peano's numbers are both mathematical
 objects.  The first however is more definite than the second, since Godel's
 theorems don't apply.  Which one is called the *natural* numbers is a 
 convention
 which might not have any practical consequences for sufficiently large 
 BIGGEST.

 Brent


 




 --
 All those moments will be lost in time, like tears in rain.




-- 
All those moments will be lost in time, like tears in rain.

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Re: The seven step-Mathematical preliminaries

2009-06-09 Thread George Levy
A good model of the naturalist math that Torgny is talking about is the 
overflow mechanism in computers.
For example in a 64 bit machine you may define overflow for positive 
integers as  2^^64 -1. If negative integers are included then the 
biggest positive could be 2^^32-1.
Torgny would also have to define the operations +, - x / with specific 
exceptions for overflow.
The concept of BIGGEST needs to be tied with _the kind of operations you 
want to apply to_ the numbers.

George

Brent Meeker wrote:
 Quentin Anciaux wrote:
   
 You have to explain why the exception is needed in the first place...

 The rule is true until the rule is not true anymore, ok but you have
 to explain for what sufficiently large N the successor function would
 yield next 0 and why or to add that N and that exception to the
 successor function as axiom, if not you can't avoid N+1. But torgny
 doesn't evacuate N+1, merely it allows his set to grows undefinitelly
 as when he has defined BIGGEST, he still argues BIGGEST+1 makes sense
 , is a natural number but not part of the set of natural number, this
 is non-sense, assuming your special successor rule BIGGEST+1 simply
 does not exists at all.

 I can understand this overflow successor function for a finite data
 type or a real machine registe but not for N. The successor function
 is simple, if you want it to have an exception at biggest you should
 justify it.
 

 You don't justify definitions.  How would you justify Peano's axioms as being 
 the right ones?  You are just confirming my point that you are begging the 
 question by assuming there is a set called the natural numbers that exists 
 independently of it's definition and it satisfies Peano's axioms.  Torgny is 
 denying that and pointing out that we cannot know of infinite sets that exist 
 independent of their definition because we cannot extensively define an 
 infinite 
 set, we can only know about it what we can prove from its definition.

 So the numbers modulo BIGGEST+1 and Peano's numbers are both mathematical 
 objects.  The first however is more definite than the second, since Godel's 
 theorems don't apply.  Which one is called the *natural* numbers is a 
 convention 
 which might not have any practical consequences for sufficiently large 
 BIGGEST.

 Brent


 

   


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RE: The seven step-Mathematical preliminaries

2009-06-09 Thread Jesse Mazer



 Date: Tue, 9 Jun 2009 12:54:16 -0700
 From: meeke...@dslextreme.com
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries
 

 You don't justify definitions.  How would you justify Peano's axioms as being 
 the right ones?  You are just confirming my point that you are begging the 
 question by assuming there is a set called the natural numbers that exists 
 independently of it's definition and it satisfies Peano's axioms. 
What do you mean by exists in this context? What would it mean to have a 
well-defined, non-contradictory definition of some mathematical objects, and 
yet for those mathematical objects not to exist? 

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Re: The seven step-Mathematical preliminaries

2009-06-09 Thread Brent Meeker

Jesse Mazer wrote:


  Date: Tue, 9 Jun 2009 12:54:16 -0700
  From: meeke...@dslextreme.com
  To: everything-list@googlegroups.com
  Subject: Re: The seven step-Mathematical preliminaries
 

  You don't justify definitions. How would you justify Peano's axioms 
 as being
  the right ones? You are just confirming my point that you are 
 begging the
  question by assuming there is a set called the natural numbers 
 that exists
  independently of it's definition and it satisfies Peano's axioms. 

 What do you mean by exists in this context? What would it mean to 
 have a well-defined, non-contradictory definition of some mathematical 
 objects, and yet for those mathematical objects not to exist?

A good question.  But if one talks about some mathematical object, like 
the natural numbers, having properties that are unprovable from their 
defining set of axioms then it seems that one has assumed some kind of 
existence apart from the particular definition.  Everybody believes 
arithmetic, per Peano's axioms, is consistent, but we know that can't be 
proved from Peano's axioms.  So it seems we are assigning (or betting 
on, as Bruno might say) more existence than is implied by the definition.

When Quentin insists that Peano's axioms are the right ones for the 
natural numbers, he is either just making a statement about language 
conventions, or he has an idea of the natural numbers that is 
independent of the axioms and is saying the axioms pick out the right 
set of natural numbers.

Brent

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Re: The seven step-Mathematical preliminaries

2009-06-09 Thread Quentin Anciaux

2009/6/10 Brent Meeker meeke...@dslextreme.com:

 Jesse Mazer wrote:


  Date: Tue, 9 Jun 2009 12:54:16 -0700
  From: meeke...@dslextreme.com
  To: everything-list@googlegroups.com
  Subject: Re: The seven step-Mathematical preliminaries
 

  You don't justify definitions. How would you justify Peano's axioms
 as being
  the right ones? You are just confirming my point that you are
 begging the
  question by assuming there is a set called the natural numbers
 that exists
  independently of it's definition and it satisfies Peano's axioms.

 What do you mean by exists in this context? What would it mean to
 have a well-defined, non-contradictory definition of some mathematical
 objects, and yet for those mathematical objects not to exist?

 A good question.  But if one talks about some mathematical object, like
 the natural numbers, having properties that are unprovable from their
 defining set of axioms then it seems that one has assumed some kind of
 existence apart from the particular definition.  Everybody believes
 arithmetic, per Peano's axioms, is consistent, but we know that can't be
 proved from Peano's axioms.  So it seems we are assigning (or betting
 on, as Bruno might say) more existence than is implied by the definition.

 When Quentin insists that Peano's axioms are the right ones for the
 natural numbers, he is either just making a statement about language
 conventions, or he has an idea of the natural numbers that is
 independent of the axioms and is saying the axioms pick out the right
 set of natural numbers.

 Brent

No I'm actually saying that peano's axiom define the abstract rules
which permits to know if a number is a natural number or not. A number
is a natural number if it satisfies peano's axiom... so by definition
the set created by the numbers satisfying these rules is the set of
all natural numbers. So if you change the rules, you change the set
hence the new set(s) created by your new rules (axiom) is(are) not the
same set(s) than the one denoted by peano's axioms hence it is not N
and can't be by definition. The mathematical object you define with
your new rules is not the same.

And please note that modulo arithmetic is not the problem here. Torgny
is not talking about that, he said BIGGEST+1 is not in the set N, but
BIGGEST+1 is a natural number (Question1: What is a natural number ?,
Question2: How can a natural number not be in the set of **all**
natural numbers ?). With your version with modulo(BIGGEST), BIGGEST+1
is in the previously defined set, it is '0'. And in your version
BIGGEST+1 doesn't satisfy that it is strictly bigger than BIGGEST, but
in Torgny version it does.

Regards,
Quentin





 




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RE: The seven step-Mathematical preliminaries

2009-06-09 Thread Jesse Mazer



 Date: Tue, 9 Jun 2009 15:22:10 -0700
 From: meeke...@dslextreme.com
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries
 
 
 Jesse Mazer wrote:


 Date: Tue, 9 Jun 2009 12:54:16 -0700
 From: meeke...@dslextreme.com
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries


 You don't justify definitions. How would you justify Peano's axioms 
 as being
 the right ones? You are just confirming my point that you are 
 begging the
 question by assuming there is a set called the natural numbers 
 that exists
 independently of it's definition and it satisfies Peano's axioms. 

 What do you mean by exists in this context? What would it mean to 
 have a well-defined, non-contradictory definition of some mathematical 
 objects, and yet for those mathematical objects not to exist?
 
 A good question.  But if one talks about some mathematical object, like 
 the natural numbers, having properties that are unprovable from their 
 defining set of axioms then it seems that one has assumed some kind of 
 existence apart from the particular definition.
Isn't this based on the idea that there should be an objective truth about 
every well-formed proposition about the natural numbers even if the Peano 
axioms cannot decide the truth about all propositions? I think that the 
statements that cannot be proved are disproved would all be ones of the type 
for all numbers with property X, Y is true or there exists a number (or some 
finite group of numbers) with property X (i.e. propositions using either the 
'for all' or 'there exists' universal quantifiers in logic, with variables 
representing specific numbers or groups of numbers). So to believe these 
statements are objectively true basically means there would be a unique way to 
extend our judgment of the truth-values of propositions from the judgments 
already given by the Peano axioms, in such a way that if we could flip through 
all the infinite propositions judged true by the Peano axioms, we would *not* 
find an example of a proposition like for this specific number N with property 
X, Y is false (which would disprove the 'for all' proposition above), and 
likewise we would not find that for every possible number (or group of numbers) 
N, the Peano axioms proved a proposition like number N does not have property 
X (which would disprove the 'there exists' proposition above). 
We can't actual flip through an infinite number of propositions in a finite 
time of course, but if we had a hypercomputer that could do so (which is 
equivalent to the notion of a hypercomputer that can decide in finite time if 
any given Turing program halts or not), then I think we'd have a well-defined 
notion of how to program it to decide the truth of every for all or there 
exists proposition in a way that's compatible with the propositions already 
proved by the Peano axioms. If I'm right about that, it would lead naturally to 
the idea of something like a unique consistent extension of the Peano axioms 
(not a real technical term, I just made up this phrase, but unless there's an 
error in my reasoning I imagine mathematicians have some analogous 
notion...maybe Bruno knows?) which assigns truth values to all the well-formed 
propositions that are undecidable by the Peano axioms themselves. So this would 
be a natural way of understanding the idea of truths about the natural 
numbers that are not decidable by the Peano axioms.
Of course even if the notion of a unique consistent extension of certain 
types of axiomatic systems is well-defined, it would only make sense for 
axiomatic systems that are consistent in the first place. I guess in judging 
the question of the consistency of the Peano axioms, we must rely on some sort 
of ill-defined notion of our understanding of how the axioms should represent 
true statements about things like counting discrete objects. For example, we 
understand that the order you count a group of discrete objects doesn't affect 
the total number, which is a convincing argument for believing that A + B = B + 
A regardless of what numbers you choose for A and B. Likewise, we understand 
that multiplying A * B can be thought of in terms of a square array of discrete 
objects with the horizontal side having A objects and the vertical side having 
B objects, and we can see that just by rotating this you get a square array 
with B on the horizontal side and A on the vertical side, so if we believe that 
just mentally rotating an array of discrete objects won't change the number in 
the array that's a good argument for believing A * B = B * A. So thinking along 
these lines, as long as we don't believe that true statements about counting 
collections of discrete objects could ever lead to logical contradictions, we 
should believe the same for the Peano axioms.
Jesse
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Re: The seven step-Mathematical preliminaries

2009-06-09 Thread Brent Meeker

Jesse Mazer wrote:


  Date: Tue, 9 Jun 2009 15:22:10 -0700
  From: meeke...@dslextreme.com
  To: everything-list@googlegroups.com
  Subject: Re: The seven step-Mathematical preliminaries
 
 
  Jesse Mazer wrote:
 
 
  Date: Tue, 9 Jun 2009 12:54:16 -0700
  From: meeke...@dslextreme.com
  To: everything-list@googlegroups.com
  Subject: Re: The seven step-Mathematical preliminaries
 
 
  You don't justify definitions. How would you justify Peano's axioms
  as being
  the right ones? You are just confirming my point that you are
  begging the
  question by assuming there is a set called the natural numbers
  that exists
  independently of it's definition and it satisfies Peano's axioms.
 
  What do you mean by exists in this context? What would it mean to
  have a well-defined, non-contradictory definition of some mathematical
  objects, and yet for those mathematical objects not to exist?
 
  A good question. But if one talks about some mathematical object, like
  the natural numbers, having properties that are unprovable from their
  defining set of axioms then it seems that one has assumed some kind of
  existence apart from the particular definition.

 Isn't this based on the idea that there should be an objective truth 
 about every well-formed proposition about the natural numbers even if 
 the Peano axioms cannot decide the truth about all propositions? I 
 think that the statements that cannot be proved are disproved would 
 all be ones of the type for all numbers with property X, Y is true 
 or there exists a number (or some finite group of numbers) with 
 property X (i.e. propositions using either the 'for all' or 'there 
 exists' universal quantifiers in logic, with variables representing 
 specific numbers or groups of numbers). So to believe these statements 
 are objectively true basically means there would be a unique way to 
 extend our judgment of the truth-values of propositions from the 
 judgments already given by the Peano axioms, in such a way that if we 
 could flip through all the infinite propositions judged true by the 
 Peano axioms, we would *not* find an example of a proposition like 
 for this specific number N with property X, Y is false (which would 
 disprove the 'for all' proposition above), and likewise we would not 
 find that for every possible number (or group of numbers) N, the Peano 
 axioms proved a proposition like number N does not have property X 
 (which would disprove the 'there exists' proposition above). 

 We can't actual flip through an infinite number of propositions in a 
 finite time of course, but if we had a hypercomputer that could do 
 so (which is equivalent to the notion of a hypercomputer that can 
 decide in finite time if any given Turing program halts or not), then 
 I think we'd have a well-defined notion of how to program it to decide 
 the truth of every for all or there exists proposition in a way 
 that's compatible with the propositions already proved by the Peano 
 axioms. If I'm right about that, it would lead naturally to the idea 
 of something like a unique consistent extension of the Peano axioms 
 (not a real technical term, I just made up this phrase, but unless 
 there's an error in my reasoning I imagine mathematicians have some 
 analogous notion...maybe Bruno knows?) which assigns truth values to 
 all the well-formed propositions that are undecidable by the Peano 
 axioms themselves. So this would be a natural way of understanding the 
 idea of truths about the natural numbers that are not decidable by 
 the Peano axioms.

I think Godel's imcompleteness theorem already implies that there must 
be non-unique extensions, (e.g. maybe you can add an axiom either that 
there are infinitely many pairs of primes differing by two or the 
negative of that).  That would seem to be a reductio against the 
existence of a hypercomputer that could decide these propositions by 
inspection.

 Of course even if the notion of a unique consistent extension of 
 certain types of axiomatic systems is well-defined, it would only make 
 sense for axiomatic systems that are consistent in the first place. I 
 guess in judging the question of the consistency of the Peano axioms, 
 we must rely on some sort of ill-defined notion of our understanding 
 of how the axioms should represent true statements about things like 
 counting discrete objects. For example, we understand that the order 
 you count a group of discrete objects doesn't affect the total number, 
 which is a convincing argument for believing that A + B = B + A 
 regardless of what numbers you choose for A and B. Likewise, we 
 understand that multiplying A * B can be thought of in terms of a 
 square array of discrete objects with the horizontal side having A 
 objects and the vertical side having B objects, and we can see that 
 just by rotating this you get a square array with B on the horizontal 
 side and A on the vertical side, so if we believe that just mentally 
 rotating an array

RE: The seven step-Mathematical preliminaries

2009-06-09 Thread Jesse Mazer



 Date: Tue, 9 Jun 2009 17:20:39 -0700
 From: meeke...@dslextreme.com
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries
 
 
 Jesse Mazer wrote:


 Date: Tue, 9 Jun 2009 15:22:10 -0700
 From: meeke...@dslextreme.com
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries


 Jesse Mazer wrote:


 Date: Tue, 9 Jun 2009 12:54:16 -0700
 From: meeke...@dslextreme.com
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries


 You don't justify definitions. How would you justify Peano's axioms
 as being
 the right ones? You are just confirming my point that you are
 begging the
 question by assuming there is a set called the natural numbers
 that exists
 independently of it's definition and it satisfies Peano's axioms.

 What do you mean by exists in this context? What would it mean to
 have a well-defined, non-contradictory definition of some mathematical
 objects, and yet for those mathematical objects not to exist?

 A good question. But if one talks about some mathematical object, like
 the natural numbers, having properties that are unprovable from their
 defining set of axioms then it seems that one has assumed some kind of
 existence apart from the particular definition.

 Isn't this based on the idea that there should be an objective truth 
 about every well-formed proposition about the natural numbers even if 
 the Peano axioms cannot decide the truth about all propositions? I 
 think that the statements that cannot be proved are disproved would 
 all be ones of the type for all numbers with property X, Y is true 
 or there exists a number (or some finite group of numbers) with 
 property X (i.e. propositions using either the 'for all' or 'there 
 exists' universal quantifiers in logic, with variables representing 
 specific numbers or groups of numbers). So to believe these statements 
 are objectively true basically means there would be a unique way to 
 extend our judgment of the truth-values of propositions from the 
 judgments already given by the Peano axioms, in such a way that if we 
 could flip through all the infinite propositions judged true by the 
 Peano axioms, we would *not* find an example of a proposition like 
 for this specific number N with property X, Y is false (which would 
 disprove the 'for all' proposition above), and likewise we would not 
 find that for every possible number (or group of numbers) N, the Peano 
 axioms proved a proposition like number N does not have property X 
 (which would disprove the 'there exists' proposition above). 

 We can't actual flip through an infinite number of propositions in a 
 finite time of course, but if we had a hypercomputer that could do 
 so (which is equivalent to the notion of a hypercomputer that can 
 decide in finite time if any given Turing program halts or not), then 
 I think we'd have a well-defined notion of how to program it to decide 
 the truth of every for all or there exists proposition in a way 
 that's compatible with the propositions already proved by the Peano 
 axioms. If I'm right about that, it would lead naturally to the idea 
 of something like a unique consistent extension of the Peano axioms 
 (not a real technical term, I just made up this phrase, but unless 
 there's an error in my reasoning I imagine mathematicians have some 
 analogous notion...maybe Bruno knows?) which assigns truth values to 
 all the well-formed propositions that are undecidable by the Peano 
 axioms themselves. So this would be a natural way of understanding the 
 idea of truths about the natural numbers that are not decidable by 
 the Peano axioms.
 
 I think Godel's imcompleteness theorem already implies that there must 
 be non-unique extensions, (e.g. maybe you can add an axiom either that 
 there are infinitely many pairs of primes differing by two or the 
 negative of that).  That would seem to be a reductio against the 
 existence of a hypercomputer that could decide these propositions by 
 inspection.
I think I remember reading in one of Roger Penrose's books that there is a 
difference between an ordinary consistency condition (which just means that no 
two propositions explicitly contradict each other) and omega-consistency--see 
http://en.wikipedia.org/wiki/Omega-consistent_theory . I can't quite follow the 
details, but I'm guessing the condition means (or at least includes) something 
like the idea that if you have a statement of the form there exists a number 
(or set of numbers) with property X then there must actually be some other 
proposition describing a particular number (or set of numbers) does in fact 
have this property. The fact that you can add either a Godel statement or its 
negation to the Peano axioms without creating a contradiction (as long as the 
Peano axioms are not inconsistent) may not mean you can add either one and 
still have an omega-consistent theory; if that's true, would

Re: The seven step-Mathematical preliminaries

2009-06-07 Thread russell standish

On Sat, Jun 06, 2009 at 10:22:11AM -0700, Brent Meeker wrote:
 I wonder if anyone has tried work with a theory of finite numbers: where 
 BIGGEST+1=BIGGEST or BIGGEST+1=-BIGGEST as in some computers?
 
 Brent
 

The numbers {0,...,p-1} with p prime, and addition and multiplication
given modulo p (ie

a plus b = (a+b) mod p
a times b = (ab) mod p

)

is an interesting mathematical object known as a finite field (or
Galois field) - 
http://en.wikipedia.org/wiki/Finite_field

Interesting examples of infinite fields are those quite familiar to
you: rational, real and complex numbers.

It might make sense for Torgny to work with a Galois field for some
large but unnamed prime :)

Cheers

-- 


Prof Russell Standish  Phone 0425 253119 (mobile)
Mathematics  
UNSW SYDNEY 2052 hpco...@hpcoders.com.au
Australiahttp://www.hpcoders.com.au


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Re: The seven step-Mathematical preliminaries 2

2009-06-07 Thread Bruno Marchal

Marty,

On 07 Jun 2009, at 02:03, Brent Meeker wrote:


 m.a. wrote:
 *Okay, so is it true to say that things written in EXTENSION are  
 never
 in formula style but are translated into formulas when we put them
 into  INTENSION   form?  You can see that my difficulty with math
 arises from an inability to master even the simplest definitions.
 marty a.*

 It's not that technical.  I could define the set of books on my  
 shelf by
 giving a list of titles: The Comprehensible Cosmos, Set Theory and
 It's Philosophy, Overshoot, Quintessence.  That would be a
 definition by extension.  Or I could point to them in succession and
 say, That and that and that and that. which would be a definition by
 ostension. Or I could just say, The books on my shelf. which is a
 definition by intension.  An intensional definition is a descriptive
 phrase with an implicit variable, which in logic you might write as:  
 The
 set of things x such that x is a book and x is on my shelf.


This is a good point. A set is just a collection of objects seen as a  
whole.

A definition in extension of a set is just a listing, finite or  
infinite, of its elements.
Like in A = {1, 3, 5}, or B = {2, 4, 6, 8, 10, ...}.

A definition in intension of a set consists in giving the typical  
defining property of the elements of the set.
Like in C= the set of odd numbers which are smaller than 6. Or D =  
the set of even numbers.

In this case you see that A is the same set as C? And B is the same  
set as D.

Now in mathematics we often use abbreviation. So, for example, instead  
of saying: the set of even numbers, we will write
{x such-that x is even}.

OK?

Bruno




Suppose,





http://iridia.ulb.ac.be/~marchal/




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Re: The seven step-Mathematical preliminaries 2

2009-06-07 Thread m.a.
Thank you, Brent,
 This is quite clear. Hopefully I can apply it as 
clearly to Bruno's examples.marty a.


- Original Message - 
From: Brent Meeker meeke...@dslextreme.com
To: everything-list@googlegroups.com
Sent: Saturday, June 06, 2009 8:03 PM
Subject: Re: The seven step-Mathematical preliminaries 2


 
 m.a. wrote:
 *Okay, so is it true to say that things written in EXTENSION are never 
 in formula style but are translated into formulas when we put them 
 into  INTENSION   form?  You can see that my difficulty with math 
 arises from an inability to master even the simplest definitions.
 marty a.*
 
 It's not that technical.  I could define the set of books on my shelf by 
 giving a list of titles: The Comprehensible Cosmos, Set Theory and 
 It's Philosophy, Overshoot, Quintessence.  That would be a 
 definition by extension.  Or I could point to them in succession and 
 say, That and that and that and that. which would be a definition by 
 ostension. Or I could just say, The books on my shelf. which is a 
 definition by intension.  An intensional definition is a descriptive 
 phrase with an implicit variable, which in logic you might write as: The 
 set of things x such that x is a book and x is on my shelf.
 
 Brent
 
 
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Re: The seven step-Mathematical preliminaries 2

2009-06-07 Thread m.a.
Bruno,
Yes, this seems very clear and will be helpful to refer back to if 
necessary. m.a.



- Original Message - 
From: Bruno Marchal marc...@ulb.ac.be
To: everything-list@googlegroups.com
Sent: Sunday, June 07, 2009 4:33 AM
Subject: Re: The seven step-Mathematical preliminaries 2


 
 Marty,
 
 On 07 Jun 2009, at 02:03, Brent Meeker wrote:
 

 m.a. wrote:
 *Okay, so is it true to say that things written in EXTENSION are  
 never
 in formula style but are translated into formulas when we put them
 into  INTENSION   form?  You can see that my difficulty with math
 arises from an inability to master even the simplest definitions.
 marty a.*

 It's not that technical.  I could define the set of books on my  
 shelf by
 giving a list of titles: The Comprehensible Cosmos, Set Theory and
 It's Philosophy, Overshoot, Quintessence.  That would be a
 definition by extension.  Or I could point to them in succession and
 say, That and that and that and that. which would be a definition by
 ostension. Or I could just say, The books on my shelf. which is a
 definition by intension.  An intensional definition is a descriptive
 phrase with an implicit variable, which in logic you might write as:  
 The
 set of things x such that x is a book and x is on my shelf.
 
 
 This is a good point. A set is just a collection of objects seen as a  
 whole.
 
 A definition in extension of a set is just a listing, finite or  
 infinite, of its elements.
 Like in A = {1, 3, 5}, or B = {2, 4, 6, 8, 10, ...}.
 
 A definition in intension of a set consists in giving the typical  
 defining property of the elements of the set.
 Like in C= the set of odd numbers which are smaller than 6. Or D =  
 the set of even numbers.
 
 In this case you see that A is the same set as C? And B is the same  
 set as D.
 
 Now in mathematics we often use abbreviation. So, for example, instead  
 of saying: the set of even numbers, we will write
 {x such-that x is even}.
 
 OK?
 
 Bruno
 
 
 
 
 Suppose,
 
 
 
 
 
 http://iridia.ulb.ac.be/~marchal/
 
 
 
 
 
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Re: The seven step-Mathematical preliminaries

2009-06-07 Thread John Mikes
On Sat, Jun 6, 2009 at 4:20 PM, Jesse Mazer laserma...@hotmail.com wrote:



  Date: Sat, 6 Jun 2009 21:17:03 +0200

  From: tor...@dsv.su.se
  To: everything-list@googlegroups.com
  Subject: Re: The seven step-Mathematical preliminaries
 
 
  Jesse Mazer skrev:
 [[[
 
  Date: Sat, 6 Jun 2009 16:48:21 +0200
  From: tor...@dsv.su.se
  To: everything-list@googlegroups.com
  Subject: Re: The seven step-Mathematical preliminaries
 
  Jesse Mazer skrev:
 
  Here you're just contradicting yourself. If you say BIGGEST+1 is then
  a natural number, that just proves that the set N was not in fact the
  set of all natural numbers. The alternative would be to say
  BIGGEST+1 is *not* a natural number, but then you need to provide a
  definition of natural number that would explain why this is the
 case.
 
  It depends upon how you define natural number. If you define it by: n
  is a natural number if and only if n belongs to N, the set of all
  natural numbers, then of course BIGGEST+1 is *not* a natural number. In
  that case you have to call BIGGEST+1 something else, maybe unnatural
  number.
 
  OK, but then you need to define what you mean by N, the set of all
  natural numbers. Specifically you need to say what number is
  BIGGEST. Is it arbitrary? Can I set BIGGEST = 3, for example? Or do
  you have some philosophical ideas related to what BIGGEST is, like the
  number of particles in the universe or the largest number any human
  can conceptualize?
 
  It is rather the last, the largest number any human can conceptualize.
  More natural numbers are not needed.]]]

 Why humans, specifically? What if an alien could conceptualize a larger
 number? For that matter, since you deny any special role to consciousness,
 why should it have anything to do with the conceptualizations of beings with
 brains? A volume of space isn't normally said to conceptualize the number
 of atoms contained in that volume, but why should that number be any less
 real than the largest number that's been conceptualized by a biological
 brain?


*JohnM:*
*Jesse, *
*you don't have to go out to 'aliens', just eliminate the format possible
as of 2009. Our un-alien species is well capable of learning (compare to
2000BC) and whatever is restricted today as 'impossible' may be everyday's
bread after tomorrow. You are absolutely right - even as of today. *
*Especially in your next reply-par below.*


  
  Also, any comment on my point about there being an infinite number of
  possible propositions about even a finite set,
 
  There is not an infinite number of possible proposition. You can only
  create a finite number of proposition with finite length during your
  lifetime. Just like the number of natural numbers are unlimited but
  finite, so are the possible propositions unlimited but finte.

 But you said earlier that as long as we admit only a finite collection of
 numbers, we can prove the consistency of mathematics involving only those
 numbers. Well, how can we prove that? If we only show that all the
 propositions we have generated to date are consistent, how do we know the
 next proposition we generate won't involve an inconsistency? Presumably you
 are implicitly suggesting there should be some upper limit on the number of
 propositions about the numbers as well as on the numbers themselves, but if
 you define this limit in terms of how many a human could generate in their
 lifetime, we get back to problems like what if some other being (genetically
 engineered humans, say) would have a longer lifetime, or what if we built a
 computer that generated propositions much faster than a human could and
 checked their consistency automatically, etc.

  or about my question about whether you have any philosophical/logical
  argument for saying all sets must be finite,
 
  My philosophical argument is about the mening of the word all. To be
  able to use that word, you must associate it with a value set.

 What's a value set? And why do you say we must associate it in this
 way? Do you have a philosophical argument for this must, or is it just an
 edict that reflects your personal aesthetic preferences?

  Mostly
  that set is all objects in the universe, and if you stay inside the
  universe, there is no problems.

 *I* certainly don't define numbers in terms of any specific mapping between
 numbers and objects in the universe, it seems like a rather strange
 notion--shall we have arguments over whether the number 113485 should be
 associated with this specific shoelace or this specific kangaroo? One of the
 first thing kids learn about number is that if you count some collection of
 objects, it doesn't matter what order you count them in, the final number
 you get will be the same regardless of the order (i.e. it doesn't matter
 which you point to when you say 1 and which you point to when you say 2,
 as long as you point to each object exactly once).

 Also, am I understanding correctly in thinking you don't believe there can

Re: The seven step-Mathematical preliminaries 2

2009-06-07 Thread m.a.

 *Bruno et. al.,
Good news! I have discovered that the math 
 symbols copy faithfully here in my Thunderbird email.* *Henceforth, I 
 will open all list letters here. Please refresh my memory for the 
 following symbols:*
 *
 1. The   ***?**  *is called_and 
 means__

 2. The***?**  *is called___*_*and 
 means__

 3. The   ***?   is called__and 
 means


 **
 -* Original Message -
   From: Bruno Marchal
   To: everything-list@googlegroups.com
   Sent: Wednesday, June 03, 2009 1:15 PM
   Subject: Re: The seven step-Mathematical preliminaries 2


   ? ? A =
   ? ? B =
   A ? ? =
   B ? ? =
   N ? ? =
   B ? ? =
   ? ? B =
   ? ? ? =
   ? ? ? =
 *

   


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Re: The seven step-Mathematical preliminaries 2

2009-06-07 Thread Bruno Marchal
Bravo Thunderbird!


On 07 Jun 2009, at 18:39, m.a. wrote:


 Bruno et. al.,
Good news! I have discovered that the math  
 symbols copy faithfully here in my Thunderbird email. Henceforth, I  
 will open all list letters here. Please refresh my memory for the  
 following symbols:




 1. The   ∅  is called___THE EMPTY SET_and means__THE SET  
 WITH NO ELEMENTS

The empty set described in extension: { }
The empty set described in intension. Well, let me think. The set of  
french which are bigger than 42 km tall.
A cynical definition would be: the set of honest politicians.
A mathematical one: the set of x such that x is different from x.
It is just the set which has no elements. It is empty.


 2. The∪  is calledUNION__and means: A ∪ B__= {x  
 such-that x belongs to A  or x belongs to B};

 A u B is the set obtained by doing the union of A and B.



 3. The   ∩   is called_INTERSECTIONand means__A ∩ B__=   
 {x such-that x belongs to A  andr x belongs to B}; A u B is the  
 set obtained by doing the intersection of A and B. It is the set of  
 elements which are in both A and B._

Examples:

{1, 2, 3} ∩ {2, 4, 3} = {2, 3}
{1, 2, 3} u {2, 4, 3} = {1, 2, 3, 4}

{1, 2, 3} ∩ {4, 5, 6} =   ∅
{1, 2, 3} u {4, 5, 6} = {1, 2, 3, 4, 5, 6}

OK?


Bruno




  - Original Message -
   From: Bruno Marchal
   To: everything-list@googlegroups.com
   Sent: Wednesday, June 03, 2009 1:15 PM
   Subject: Re: The seven step-Mathematical preliminaries 2


   ∅ ∪ A =
   ∅ ∪ B =
   A ∪ ∅ =
   B ∪ ∅ =
   N ∩ ∅ =
   B ∩ ∅ =
   ∅ ∩ B =
   ∅ ∩ ∅ =
   ∅ ∪ ∅ =





 

http://iridia.ulb.ac.be/~marchal/




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Re: The seven step-Mathematical preliminaries 2

2009-06-07 Thread Bruno Marchal
Marty, Kim,

I realize that, now, the message I have just sent does not have the  
right symbols. Apparently my computer does not understand the  
Thunderbird!

 From now on I will use capital words for the mathematical symbols.  
And I will write mathematical expression in bold.

For examples:

{1, 2, 3}  INTERSECTION  {2, 4, 3}   =   {2, 3}
{1, 2, 3}  UNION  {2, 4, 3}   =   {1, 2, 3, 4}

{1, 2, 3}  INTERSECTION  {4, 5, 6}   =   EMPTY
{1, 2, 3}  UNION   {4, 5, 6}   =   {1, 2, 3, 4, 5, 6}

All right? Mathematics will get a FORTRAN look but this is not  
important, OK? It is just the look. I will do a summary of what we  
have seen so far.

With those notions you should be able to invent exercises by yourself.  
Invent simple sets and compute their union, and intersection.

Remenber that the goal consists in building a mathematical shortcut  
toward a thorugh understanding of step seven. In particular the goal  
will be to get an idea of a computation is, and what is the difference  
between a mathemarical computation and a mathematical description of a  
computation. It helps for the step 8 too.

Marty, have a nice holiday,

Kim, ah ah ... we have two weeks to digest what has been said so far  
(which is not enormous), OK?

Bruno


http://iridia.ulb.ac.be/~marchal/




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Re: The seven step-Mathematical preliminaries

2009-06-06 Thread Torgny Tholerus

Jesse Mazer skrev:


  Date: Fri, 5 Jun 2009 08:33:47 +0200
  From: tor...@dsv.su.se
  To: everything-list@googlegroups.com
  Subject: Re: The seven step-Mathematical preliminaries
 
 
  Brian Tenneson skrev:
 
  How can BIGGEST+1 be a natural number but not belong to the set of all
  natural numbers?
 
  One way to represent natural number as sets is:
 
  0 = {}
  1 = {0} = {{}}
  2 = {0, 1} = 1 union {1} = {{}, {{}}}
  3 = {0, 1, 2} = 2 union {2} = ...
  . . .
  n+1 = {0, 1, 2, ..., n} = n union {n}
  . . .
 
  Here you can then define that a is less then b if and only if a belongs
  to b.
 
  With this notation you get the set N of all natural numbers as {0, 
 1, 2,
  ...}. But the remarkable thing is that N is exactly the same as
  BIGGEST+1. BIGGEST+1 is a set with the same structure as all the other
  natural numbers, so it is then a natural number. But BIGGEST+1 is not a
  member of N, the set of all natural numbers.

 Here you're just contradicting yourself. If you say BIGGEST+1 is then 
 a natural number, that just proves that the set N was not in fact the 
 set of all natural numbers. The alternative would be to say 
 BIGGEST+1 is *not* a natural number, but then you need to provide a 
 definition of natural number that would explain why this is the case.

It depends upon how you define natural number.  If you define it by: n 
is a natural number if and only if n belongs to N, the set of all 
natural numbers, then of course BIGGEST+1 is *not* a natural number.  In 
that case you have to call BIGGEST+1 something else, maybe unnatural 
number.

-- 
Torgny Tholerus

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RE: The seven step-Mathematical preliminaries

2009-06-06 Thread Jesse Mazer



 Date: Sat, 6 Jun 2009 16:48:21 +0200
 From: tor...@dsv.su.se
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries
 
 
 Jesse Mazer skrev:


 Date: Fri, 5 Jun 2009 08:33:47 +0200
 From: tor...@dsv.su.se
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries


 Brian Tenneson skrev:

 How can BIGGEST+1 be a natural number but not belong to the set of all
 natural numbers?

 One way to represent natural number as sets is:

 0 = {}
 1 = {0} = {{}}
 2 = {0, 1} = 1 union {1} = {{}, {{}}}
 3 = {0, 1, 2} = 2 union {2} = ...
 . . .
 n+1 = {0, 1, 2, ..., n} = n union {n}
 . . .

 Here you can then define that a is less then b if and only if a belongs
 to b.

 With this notation you get the set N of all natural numbers as {0, 
 1, 2,
 ...}. But the remarkable thing is that N is exactly the same as
 BIGGEST+1. BIGGEST+1 is a set with the same structure as all the other
 natural numbers, so it is then a natural number. But BIGGEST+1 is not a
 member of N, the set of all natural numbers.

 Here you're just contradicting yourself. If you say BIGGEST+1 is then 
 a natural number, that just proves that the set N was not in fact the 
 set of all natural numbers. The alternative would be to say 
 BIGGEST+1 is *not* a natural number, but then you need to provide a 
 definition of natural number that would explain why this is the case.
 
 It depends upon how you define natural number.  If you define it by: n 
 is a natural number if and only if n belongs to N, the set of all 
 natural numbers, then of course BIGGEST+1 is *not* a natural number.  In 
 that case you have to call BIGGEST+1 something else, maybe unnatural 
 number.

OK, but then you need to define what you mean by N, the set of all natural 
numbers. Specifically you need to say what number is BIGGEST. Is it 
arbitrary? Can I set BIGGEST = 3, for example? Or do you have some 
philosophical ideas related to what BIGGEST is, like the number of particles in 
the universe or the largest number any human can conceptualize?
Also, any comment on my point about there being an infinite number of possible 
propositions about even a finite set, or about my question about whether you 
have any philosophical/logical argument for saying all sets must be finite, as 
opposed to it just being a sort of aesthetic preference on your part? Do you 
think there is anything illogical or incoherent about defining a set in terms 
of a rule that takes any input and decides whether it's a member of the set or 
not, such that there may be no upper limit on the number of possible inputs 
that the rule would define as being members? (such as would be the case for the 
rule 'n is a natural number if n=1 or if n is equal to some other natural 
number+1')
Jesse
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Re: The seven step-Mathematical preliminaries

2009-06-06 Thread Brent Meeker

Torgny Tholerus wrote:
 Jesse Mazer skrev:
   
 
 Date: Fri, 5 Jun 2009 08:33:47 +0200
 From: tor...@dsv.su.se
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries


 Brian Tenneson skrev:
   
 How can BIGGEST+1 be a natural number but not belong to the set of all
 natural numbers?
 
 One way to represent natural number as sets is:

 0 = {}
 1 = {0} = {{}}
 2 = {0, 1} = 1 union {1} = {{}, {{}}}
 3 = {0, 1, 2} = 2 union {2} = ...
 . . .
 n+1 = {0, 1, 2, ..., n} = n union {n}
 . . .

 Here you can then define that a is less then b if and only if a belongs
 to b.

 With this notation you get the set N of all natural numbers as {0, 
   
 1, 2,
 
 ...}. But the remarkable thing is that N is exactly the same as
 BIGGEST+1. BIGGEST+1 is a set with the same structure as all the other
 natural numbers, so it is then a natural number. But BIGGEST+1 is not a
 member of N, the set of all natural numbers.
   
 Here you're just contradicting yourself. If you say BIGGEST+1 is then 
 a natural number, that just proves that the set N was not in fact the 
 set of all natural numbers. The alternative would be to say 
 BIGGEST+1 is *not* a natural number, but then you need to provide a 
 definition of natural number that would explain why this is the case.
 

 It depends upon how you define natural number.  If you define it by: n 
 is a natural number if and only if n belongs to N, the set of all 
 natural numbers, then of course BIGGEST+1 is *not* a natural number.  In 
 that case you have to call BIGGEST+1 something else, maybe unnatural 
 number.

   
I wonder if anyone has tried work with a theory of finite numbers: where 
BIGGEST+1=BIGGEST or BIGGEST+1=-BIGGEST as in some computers?

Brent

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Re: The seven step-Mathematical preliminaries

2009-06-06 Thread A. Wolf

 I wonder if anyone has tried work with a theory of finite numbers: where
 BIGGEST+1=BIGGEST or BIGGEST+1=-BIGGEST as in some computers?

There is a group of faculty who address this problem directly in my 
department.  But any general-purpose computer can emulate true, unlimited 
natural numbers (which is what people often do, rather than relying on 
bounded ints).  The only real limitations that make computer not-equal-to 
Turing machine are memory and the limited patience of humans.  This is one 
reason why people spend more time researching P vs. NP than 
artificially-imposed limits.

When you add bounds to numbers it requires additional proof obligations, 
which makes it more difficult to prove things.  And you can't directly prove 
anything about numbers that exist outside the bounds under which you're 
working.

Anna


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Re: The seven step-Mathematical preliminaries 2

2009-06-06 Thread m.a.
Bruno,
   Before I leave on holiday, I am following your advice to make my own 
table of symbols. Let me ask first whether the smaller rectangles have a 
different reference from the larger ones as seen in your example below?

  - Original Message - 
  From: Bruno Marchal 
  To: everything-list@googlegroups.com 
  Sent: Wednesday, June 03, 2009 1:15 PM
  Subject: Re: The seven step-Mathematical preliminaries 2


  ∅ ∪ A =
  ∅ ∪ B =
  A ∪ ∅ =
  B ∪ ∅ =
  N ∩ ∅ =
  B ∩ ∅ =
  ∅ ∩ B =
  ∅ ∩ ∅ =
  ∅ ∪ ∅ =




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Re: The seven step-Mathematical preliminaries

2009-06-06 Thread Torgny Tholerus

Jesse Mazer skrev:


  Date: Sat, 6 Jun 2009 16:48:21 +0200
  From: tor...@dsv.su.se
  To: everything-list@googlegroups.com
  Subject: Re: The seven step-Mathematical preliminaries
 
  Jesse Mazer skrev:
 
  Here you're just contradicting yourself. If you say BIGGEST+1 is then
  a natural number, that just proves that the set N was not in fact the
  set of all natural numbers. The alternative would be to say
  BIGGEST+1 is *not* a natural number, but then you need to provide a
  definition of natural number that would explain why this is the case.
 
  It depends upon how you define natural number. If you define it by: n
  is a natural number if and only if n belongs to N, the set of all
  natural numbers, then of course BIGGEST+1 is *not* a natural number. In
  that case you have to call BIGGEST+1 something else, maybe unnatural
  number.

 OK, but then you need to define what you mean by N, the set of all 
 natural numbers. Specifically you need to say what number is 
 BIGGEST. Is it arbitrary? Can I set BIGGEST = 3, for example? Or do 
 you have some philosophical ideas related to what BIGGEST is, like the 
 number of particles in the universe or the largest number any human 
 can conceptualize?

It is rather the last, the largest number any human can conceptualize.  
More natural numbers are not needed.


 Also, any comment on my point about there being an infinite number of 
 possible propositions about even a finite set,

There is not an infinite number of possible proposition.  You can only 
create a finite number of proposition with finite length during your 
lifetime.  Just like the number of natural numbers are unlimited but 
finite, so are the possible propositions unlimited but finte.

 or about my question about whether you have any philosophical/logical 
 argument for saying all sets must be finite,

My philosophical argument is about the mening of the word all.  To be 
able to use that word, you must associate it with a value set.  Mostly 
that set is all objects in the universe, and if you stay inside the 
universe, there is no problems.  But as soon you go outside universe, 
you must be carefull with what substitutions you do.  If you have all 
quantified with all object inside the universe, you can not substitute 
it with an object outside the universe, because that object was not 
included in the original statement.

 as opposed to it just being a sort of aesthetic preference on your 
 part? Do you think there is anything illogical or incoherent about 
 defining a set in terms of a rule that takes any input and decides 
 whether it's a member of the set or not, such that there may be no 
 upper limit on the number of possible inputs that the rule would 
 define as being members? (such as would be the case for the rule 'n is 
 a natural number if n=1 or if n is equal to some other natural number+1')

In the last sentence you have an implicite all:  The full sentence 
would be: For all n in the universe hold that n is a natural number if 
n=1 or if n is equal to some other natural number+1.  And you may now be 
able to understand, that if the number of objects in the universe is 
finite, then this sentence will just define a finite set.

-- 
Torgny Tholerus

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RE: The seven step-Mathematical preliminaries

2009-06-06 Thread Jesse Mazer



 Date: Sat, 6 Jun 2009 21:17:03 +0200
 From: tor...@dsv.su.se
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries
 
 
 Jesse Mazer skrev:


 Date: Sat, 6 Jun 2009 16:48:21 +0200
 From: tor...@dsv.su.se
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries

 Jesse Mazer skrev:

 Here you're just contradicting yourself. If you say BIGGEST+1 is then
 a natural number, that just proves that the set N was not in fact the
 set of all natural numbers. The alternative would be to say
 BIGGEST+1 is *not* a natural number, but then you need to provide a
 definition of natural number that would explain why this is the case.

 It depends upon how you define natural number. If you define it by: n
 is a natural number if and only if n belongs to N, the set of all
 natural numbers, then of course BIGGEST+1 is *not* a natural number. In
 that case you have to call BIGGEST+1 something else, maybe unnatural
 number.

 OK, but then you need to define what you mean by N, the set of all 
 natural numbers. Specifically you need to say what number is 
 BIGGEST. Is it arbitrary? Can I set BIGGEST = 3, for example? Or do 
 you have some philosophical ideas related to what BIGGEST is, like the 
 number of particles in the universe or the largest number any human 
 can conceptualize?
 
 It is rather the last, the largest number any human can conceptualize.  
 More natural numbers are not needed.

Why humans, specifically? What if an alien could conceptualize a larger number? 
For that matter, since you deny any special role to consciousness, why should 
it have anything to do with the conceptualizations of beings with brains? A 
volume of space isn't normally said to conceptualize the number of atoms 
contained in that volume, but why should that number be any less real than the 
largest number that's been conceptualized by a biological brain?

 Also, any comment on my point about there being an infinite number of 
 possible propositions about even a finite set,
 
 There is not an infinite number of possible proposition.  You can only 
 create a finite number of proposition with finite length during your 
 lifetime.  Just like the number of natural numbers are unlimited but 
 finite, so are the possible propositions unlimited but finte.

But you said earlier that as long as we admit only a finite collection of 
numbers, we can prove the consistency of mathematics involving only those 
numbers. Well, how can we prove that? If we only show that all the 
propositions we have generated to date are consistent, how do we know the next 
proposition we generate won't involve an inconsistency? Presumably you are 
implicitly suggesting there should be some upper limit on the number of 
propositions about the numbers as well as on the numbers themselves, but if you 
define this limit in terms of how many a human could generate in their 
lifetime, we get back to problems like what if some other being (genetically 
engineered humans, say) would have a longer lifetime, or what if we built a 
computer that generated propositions much faster than a human could and checked 
their consistency automatically, etc. 
 or about my question about whether you have any philosophical/logical 
 argument for saying all sets must be finite,
 
 My philosophical argument is about the mening of the word all.  To be 
 able to use that word, you must associate it with a value set.
What's a value set? And why do you say we must associate it in this way? Do 
you have a philosophical argument for this must, or is it just an edict that 
reflects your personal aesthetic preferences?
 Mostly 
 that set is all objects in the universe, and if you stay inside the 
 universe, there is no problems.
*I* certainly don't define numbers in terms of any specific mapping between 
numbers and objects in the universe, it seems like a rather strange 
notion--shall we have arguments over whether the number 113485 should be 
associated with this specific shoelace or this specific kangaroo? One of the 
first thing kids learn about number is that if you count some collection of 
objects, it doesn't matter what order you count them in, the final number you 
get will be the same regardless of the order (i.e. it doesn't matter which you 
point to when you say 1 and which you point to when you say 2, as long as 
you point to each object exactly once).
Also, am I understanding correctly in thinking you don't believe there can be 
truths about numbers independent of what humans actually know about them (i.e. 
there is no truth about the sum of two very large numbers unless some human has 
actually calculated that sum at one point)? If in fact you don't believe there 
are truths about numbers independent of human thoughts about them, why do you 
think there can be truths about the physical universe which humans don't know 
about? For example, is there a truth about the surface topography of some 
planet

Re: The seven step-Mathematical preliminaries 2

2009-06-06 Thread Bruno Marchal
Marty,

 Bruno,
Before I leave on holiday, I am following your advice to  
 make my own table of symbols. Let me ask first whether the smaller  
 rectangles have a different reference from the larger ones as seen  
 in your example below?


We do have problem of symbols, with the mail. I don't see any  
rectangle in the message below!

Take it easy and . We will go very slowly. It will also be the exam  
periods. There is no rush ...

Have a good holiday

Bruno


 - Original Message -
 From: Bruno Marchal
 To: everything-list@googlegroups.com
 Sent: Wednesday, June 03, 2009 1:15 PM
 Subject: Re: The seven step-Mathematical preliminaries 2

 ∅ ∪ A =
 ∅ ∪ B =
 A ∪ ∅ =
 B ∪ ∅ =
 N ∩ ∅ =
 B ∩ ∅ =
 ∅ ∩ B =
 ∅ ∩ ∅ =
 ∅ ∪ ∅ =


 ---
 To unsubscribe from this group, send email to 
 everything-list+unsubscr...@googlegroups.com
 For more options, visit this group at 
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http://iridia.ulb.ac.be/~marchal/




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Re: The seven step-Mathematical preliminaries

2009-06-06 Thread Brent Meeker

Jesse Mazer wrote:


  Date: Sat, 6 Jun 2009 21:17:03 +0200
  From: tor...@dsv.su.se
  To: everything-list@googlegroups.com
  Subject: Re: The seven step-Mathematical preliminaries
 
 
  Jesse Mazer skrev:
 
 
  Date: Sat, 6 Jun 2009 16:48:21 +0200
  From: tor...@dsv.su.se
  To: everything-list@googlegroups.com
  Subject: Re: The seven step-Mathematical preliminaries
 
  Jesse Mazer skrev:
 
  Here you're just contradicting yourself. If you say BIGGEST+1 is 
 then
  a natural number, that just proves that the set N was not in 
 fact the
  set of all natural numbers. The alternative would be to say
  BIGGEST+1 is *not* a natural number, but then you need to provide a
  definition of natural number that would explain why this is the 
 case.
 
  It depends upon how you define natural number. If you define it 
 by: n
  is a natural number if and only if n belongs to N, the set of all
  natural numbers, then of course BIGGEST+1 is *not* a natural 
 number. In
  that case you have to call BIGGEST+1 something else, maybe unnatural
  number.
 
  OK, but then you need to define what you mean by N, the set of all
  natural numbers. Specifically you need to say what number is
  BIGGEST. Is it arbitrary? Can I set BIGGEST = 3, for example? Or do
  you have some philosophical ideas related to what BIGGEST is, like the
  number of particles in the universe or the largest number any human
  can conceptualize?
 
  It is rather the last, the largest number any human can conceptualize.
  More natural numbers are not needed.

 Why humans, specifically? What if an alien could conceptualize a 
 larger number? For that matter, since you deny any special role to 
 consciousness, why should it have anything to do with the 
 conceptualizations of beings with brains? A volume of space isn't 
 normally said to conceptualize the number of atoms contained in that 
 volume, but why should that number be any less real than the largest 
 number that's been conceptualized by a biological brain?

 
  Also, any comment on my point about there being an infinite number of
  possible propositions about even a finite set,
 
  There is not an infinite number of possible proposition. You can only
  create a finite number of proposition with finite length during your
  lifetime. Just like the number of natural numbers are unlimited but
  finite, so are the possible propositions unlimited but finte.

 But you said earlier that as long as we admit only a finite collection 
 of numbers, we can prove the consistency of mathematics involving 
 only those numbers. Well, how can we prove that? If we only show 
 that all the propositions we have generated to date are consistent, 
 how do we know the next proposition we generate won't involve an 
 inconsistency? Presumably you are implicitly suggesting there should 
 be some upper limit on the number of propositions about the numbers as 
 well as on the numbers themselves, but if you define this limit in 
 terms of how many a human could generate in their lifetime, we get 
 back to problems like what if some other being (genetically engineered 
 humans, say) would have a longer lifetime, or what if we built a 
 computer that generated propositions much faster than a human could 
 and checked their consistency automatically, etc.
  
  or about my question about whether you have any philosophical/logical
  argument for saying all sets must be finite,
 
  My philosophical argument is about the mening of the word all. To be
  able to use that word, you must associate it with a value set.

 What's a value set? And why do you say we must associate it in 
 this way? Do you have a philosophical argument for this must, or is 
 it just an edict that reflects your personal aesthetic preferences?

  Mostly
  that set is all objects in the universe, and if you stay inside the
  universe, there is no problems.

 *I* certainly don't define numbers in terms of any specific mapping 
 between numbers and objects in the universe, it seems like a rather 
 strange notion--shall we have arguments over whether the number 113485 
 should be associated with this specific shoelace or this specific 
 kangaroo? One of the first thing kids learn about number is that if 
 you count some collection of objects, it doesn't matter what order you 
 count them in, the final number you get will be the same regardless of 
 the order (i.e. it doesn't matter which you point to when you say 1 
 and which you point to when you say 2, as long as you point to each 
 object exactly once).

 Also, am I understanding correctly in thinking you don't believe there 
 can be truths about numbers independent of what humans actually know 
 about them (i.e. there is no truth about the sum of two very large 
 numbers unless some human has actually calculated that sum at one 
 point)? If in fact you don't believe there are truths about numbers 
 independent of human thoughts about them, why do you think there can 
 be truths about the physical universe which

RE: The seven step-Mathematical preliminaries 2

2009-06-06 Thread Jesse Mazer

If it helps, here's a screenshot of how the symbols are supposed to look:
http://img34.imageshack.us/img34/3345/picture2uzk.png

From: marc...@ulb.ac.be
To: everything-list@googlegroups.com
Subject: Re: The seven step-Mathematical preliminaries 2
Date: Sat, 6 Jun 2009 22:36:01 +0200

Marty,
Bruno,   Before I leave on holiday, I am following your advice to make 
my own table of symbols. Let me ask first whether the smaller rectangles have a 
different reference from the larger ones as seen in your example below?

We do have problem of symbols, with the mail. I don't see any rectangle in the 
message below!
Take it easy and . We will go very slowly. It will also be the exam periods. 
There is no rush ...
Have a good holiday
Bruno
 - Original Message -From: Bruno MarchalTo: 
everything-l...@googlegroups.comsent: Wednesday, June 03, 2009 1:15 PMSubject: 
Re: The seven step-Mathematical preliminaries 2
∅ ∪ A =∅ ∪ B =A ∪ ∅ =B ∪ ∅ =N ∩ ∅ =B ∩ ∅ =∅ ∩ B =∅ ∩ ∅ =∅ ∪ ∅ =

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Re: The seven step-Mathematical preliminaries 2

2009-06-06 Thread m.a.
(I'll be here till Tuesday.) Evidently, the symbol you are using for such 
that is being shown on my screen as a small rectangle. In the copy below, I 
see two rectangles before the A=, two before the B=, two after the A, two after 
the B. The  UNION symbol (inverted  U) shows up but is followed by a 
rectangle in the next two examples and preceded by a rectangle in the last 
three. In checking a table of logic notaion, I find that the relation such 
that is designated by a reversed capital  E.   Is this the symbol you are 
using? m.a.
  - Original Message - 
  From: Bruno Marchal 
  To: everything-list@googlegroups.com 
  Sent: Saturday, June 06, 2009 4:36 PM
  Subject: Re: The seven step-Mathematical preliminaries 2





  We do have problem of symbols, with the mail. I don't see any rectangle in 
the message below!


  Take it easy and . We will go very slowly. It will also be the exam periods. 
There is no rush ...


  Have a good holiday


  Bruno



  - Original Message -
  From: Bruno Marchal
  To: everything-list@googlegroups.com
  Sent: Wednesday, June 03, 2009 1:15 PM
  Subject: Re: The seven step-Mathematical preliminaries 2


  ∅ ∪ A =
  ∅ ∪ B =
  A ∪ ∅ =
  B ∪ ∅ =
  N ∩ ∅ =
  B ∩ ∅ =
  ∅ ∩ B =
  ∅ ∩ ∅ =
  ∅ ∪ ∅ =




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  http://iridia.ulb.ac.be/~marchal/






  

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Re: The seven step-Mathematical preliminaries 2

2009-06-06 Thread m.a.
Bruno,
   I've encountered some difficulty with the examples below. You say 
that  in extension describes  exhaustion or quasi-exhaustion. And you give 
the example:  B = {3, 6, 9, 12, ... 99}.
   Then you define in intension with exactly the same type of set: 
Example: Let A be the set {2, 4, 6, 8, 10, ... 100}.
   Can you see the cause of my confusion? Incidentally, may I suggest 
you use smaller than rather than  more little than. Your English is 
generally too good to include that kind of error.   marty a.




  - Original Message - 
  From: Bruno Marchal 
  To: everything-list@googlegroups.com 
  Sent: Wednesday, June 03, 2009 1:15 PM
  Subject: Re: The seven step-Mathematical preliminaries 2



  === Intension and extension 





  In the case of finite and little set we have seen that we can define them 
by exhaustion. This means we can give an explicit complete description of all 
element of the set. 
  Example. A = {0, 1, 2, 77, 98, 5}


  When the set is still finite and too big, or if we are lazy, we can sometimes 
define the set by quasi exhaustion. This means we describe enough elements of 
the set in a manner which, by requiring some good will and some imagination, we 
can estimate having define the set.


  Example. B = {3, 6, 9, 12, ... 99}. We can understand in this case that we 
meant the set of multiple of the number three, below 100.


  A fortiori, when a set in not finite, that is, when the set is infinite, we 
have to use either quasi-exhaustion, or we have to use some sentence or phrase 
or proposition describing the elements of the set.


  Definition.
  I will say that a set is defined IN EXTENSIO, or simply, in extension, when 
it is defined in exhaustion or quasi-exhaustion.
  I will say that a set is defined IN INTENSIO, or simply in intension, with a 
s, when it is defined by a sentence explaining the typical attribute of the 
elements.


  Example: Let A be the set {2, 4, 6, 8, 10, ... 100}. We can easily define A 
in intension:  A = the set of numbers which are even and more little than 100. 
mathematician will condense this by the following:


  A = {x such that x is even and little than 100}  = {x ⎮ x is even  x  100}. 
⎮ is a special character, abbreviating such that, and I hope it goes 
through the mail. If not I will use such that, or s.t., or things like that.
  The expression {x ⎮ x is even} is literally read as:  the set of object x, 
(or number x if we are in a context where we talk about number) such that x is 
even.


  Exercise 1: Could you define in intension the following infinite set C = 
{101, 103, 105, ...}
  C = ?


  Exercise 2: I will say that a natural number is a multiple of 4 if it can be 
written as 4*y, for some y. For example 0 is a multiple of 4, (0 = 4*0), but 
also 28, 400, 404, ...  Could you define in extension the following set D = {x 
⎮ x  10x is a multiple of 4}. 


  A last notational, but important symbol. Sets have elements. For example the 
set A = {1, 2, 3} has three elements 1, 2 and 3. For saying that 3 is an 
element of A in an a short way, we usually write 3 ∈ A.  this is read as 3 
belongs to A, or 3 is in A. Now 4 does not belong to A. To write this in a 
short way, we will write 4 ∉ A, or we will write ¬ (4 ∈ A) or sometimes just 
NOT(4 ∈ A). It is read: 4 does not belong to A, or: it is not the case that 4 
belongs to A.


  Having those notions and notations at our disposition we can speed up on the 
notion of union and intersection.


  The intersection of the sets A and B is the (new) set of those elements which 
belongs to both A and B. Put in another way: 
  The intersection of the sets A with the set B is the set of those elements 
which belongs to A and which belongs to B. 
  This new set, obtained from A and B is written A ∩ B, or A inter. B (in case 
the special character doesn't go through).
  With our notations we can write or define the intersection A ∩ B directly


  A ∩ B = {x ⎮ x ∈ A and x ∈ B}.


  Example {3, 4, 5, 6, 8} ∩ {5, 6, 7, 9} = {5, 6}


  Similarly, we can directly define the union of two sets A and B, written A ∪ 
B in the following way:


  A ∪ B = {x ⎮ x ∈ A or x ∈ B}.Here we use the usual logical or. p or q 
is suppose to be true if p is true or q is true (or both are true). It is not 
the exclusive or.


  Example {3, 4, 5, 6, 8} ∪ {5, 6, 7, 9} = {3, 4, 5, 6, 7, 8}.


  Exercice 3. 
  Let N = {0, 1, 2, 3, ...}
  Let A = {x ⎮ x  10}
  Let B = {x ⎮ x is even}
  Describe in extension (that is: exhaustion or quasi-exhaustion) the following 
sets:


  N ∪ A =
  N ∪ B =
  A ∪ B =
  B ∪ A =
  N ∩ A =
  B ∩ A =
  N ∩ B =
  A ∩ B =


  Exercice 4


  Is it true that A ∩ B = B ∩ A, whatever A and B are? 
  Is it true that A ∪ B = B ∪ A, whatever A and B are?


  Now, I could give you exercise so that you would be lead to discoveries, but 
I prefer to be as simple and approachable as possible, and my goal is not even 
to give you

Re: The seven step-Mathematical preliminaries

2009-06-06 Thread Quentin Anciaux

2009/6/6 Torgny Tholerus tor...@dsv.su.se:

 Jesse Mazer skrev:


  Date: Sat, 6 Jun 2009 16:48:21 +0200
  From: tor...@dsv.su.se
  To: everything-list@googlegroups.com
  Subject: Re: The seven step-Mathematical preliminaries
 
  Jesse Mazer skrev:
 
  Here you're just contradicting yourself. If you say BIGGEST+1 is then
  a natural number, that just proves that the set N was not in fact the
  set of all natural numbers. The alternative would be to say
  BIGGEST+1 is *not* a natural number, but then you need to provide a
  definition of natural number that would explain why this is the case.
 
  It depends upon how you define natural number. If you define it by: n
  is a natural number if and only if n belongs to N, the set of all
  natural numbers, then of course BIGGEST+1 is *not* a natural number. In
  that case you have to call BIGGEST+1 something else, maybe unnatural
  number.

 OK, but then you need to define what you mean by N, the set of all
 natural numbers. Specifically you need to say what number is
 BIGGEST. Is it arbitrary? Can I set BIGGEST = 3, for example? Or do
 you have some philosophical ideas related to what BIGGEST is, like the
 number of particles in the universe or the largest number any human
 can conceptualize?

 It is rather the last, the largest number any human can conceptualize.
 More natural numbers are not needed.

What is the last number human can invent ? Your theory can't explain
why addition works... If N is limited, then addition can and will (in
human lifetime) create number which are still finite and not in N.

N can be defined solelly as the successor function, you don't need
anything else. You just have to assert that the function is true
always.


 Also, any comment on my point about there being an infinite number of
 possible propositions about even a finite set,

 There is not an infinite number of possible proposition.

Prove it please.

 You can only
 create a finite number of proposition with finite length during your
 lifetime.

What is a lifetime . What is truth ? Either you CAN*** define a
limit or you ***CAN'T***.

 Just like the number of natural numbers are unlimited but
 finite, so are the possible propositions unlimited but finte.

EVERY*** ***MEMBER*** of the set ***N*** is
FINITE*

 or about my question about whether you have any philosophical/logical
 argument for saying all sets must be finite,

 My philosophical argument is about the mening of the word all.  To be
 able to use that word, you must associate it with a value set.  Mostly
 that set is all objects in the universe, and if you stay inside the
 universe, there is no problems.  But as soon you go outside universe,
 you must be carefull with what substitutions you do.  If you have all
 quantified with all object inside the universe, you can not substitute
 it with an object outside the universe, because that object was not
 included in the original statement.

 as opposed to it just being a sort of aesthetic preference on your
 part? Do you think there is anything illogical or incoherent about
 defining a set in terms of a rule that takes any input and decides
 whether it's a member of the set or not, such that there may be no
 upper limit on the number of possible inputs that the rule would
 define as being members? (such as would be the case for the rule 'n is
 a natural number if n=1 or if n is equal to some other natural number+1')

 In the last sentence you have an implicite all:  The full sentence
 would be: For all n in the universe hold that n is a natural number if
 n=1 or if n is equal to some other natural number+1.  And you may now be
 able to understand, that if the number of objects in the universe is
 finite, then this sentence will just define a finite set.

 --
 Torgny Tholerus

 



I will read the rest (and others) email later unfortunatelly.

-- 
All those moments will be lost in time, like tears in rain.

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Re: The seven step-Mathematical preliminaries 2

2009-06-06 Thread Bruno Marchal

On 06 Jun 2009, at 23:54, m.a. wrote:

 (I'll be here till Tuesday.) Evidently, the symbol you are using for  
 such that is being shown on my screen as a small rectangle. In the  
 copy below, I see two rectangles before the A=, two before the B=,  
 two after the A, two after the B. The  UNION symbol (inverted  U)  
 shows up but is followed by a rectangle in the next two examples and  
 preceded by a rectangle in the last three. In checking a table of  
 logic notaion, I find that the relation such that is designated by  
 a reversed capital  E.   Is this the symbol you are using? m.a.


Yes, we have a problem. There should be no rectangles at all. We have  
to switch on english abbreviations. This explains the difficulty you  
did have with the union ...

You could look on the archive, from here,

http://www.mail-archive.com/everything-list@googlegroups.com/msg16531.html

the symbols are correct on my computer, but we will think on easier  
mail symbols. Tell me if you see different symbols in the archive.

Best,

Bruno





 - Original Message -
 From: Bruno Marchal
 To: everything-list@googlegroups.com
 Sent: Saturday, June 06, 2009 4:36 PM
 Subject: Re: The seven step-Mathematical preliminaries 2



 We do have problem of symbols, with the mail. I don't see any  
 rectangle in the message below!

 Take it easy and . We will go very slowly. It will also be the exam  
 periods. There is no rush ...

 Have a good holiday

 Bruno


 - Original Message -
 From: Bruno Marchal
 To: everything-list@googlegroups.com
 Sent: Wednesday, June 03, 2009 1:15 PM
 Subject: Re: The seven step-Mathematical preliminaries 2

 ∅ ∪ A =
 ∅ ∪ B =
 A ∪ ∅ =
 B ∪ ∅ =
 N ∩ ∅ =
 B ∩ ∅ =
 ∅ ∩ B =
 ∅ ∩ ∅ =
 ∅ ∪ ∅ =


 ---
 To unsubscribe from this group, send email to 
 everything-list+unsubscr...@googlegroups.com
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 http://iridia.ulb.ac.be/~marchal/





 

http://iridia.ulb.ac.be/~marchal/




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Re: The seven step-Mathematical preliminaries 2

2009-06-06 Thread Bruno Marchal


I've encountered some difficulty with the examples below.  
 You say that  in extension describes  exhaustion or quasi- 
 exhaustion. And you give the example:  B = {3, 6, 9, 12, ... 99}.
Then you define in intension with exactly the same type  
 of set: Example: Let A be the set {2, 4, 6, 8, 10, ... 100}.


I give A in extension there, but just to define it in intension after.  
It is always the same set there. But I show its definition in  
extension, to show the definition in intension after. You have to read  
the to sentences.


Can you see the cause of my confusion?


It is always the same set. I give it in extension, and then in  
intension.



 Incidentally, may I suggest you use smaller than rather than   
 more little than. Your English is generally too good to include  
 that kind of error.   marty a.

Well sure. Sometimes the correct expression just slip out from my  
mind. smaller than  is much better! Thanks for helping,

Bruno








 - Original Message -
 From: Bruno Marchal
 To: everything-list@googlegroups.com
 Sent: Wednesday, June 03, 2009 1:15 PM
 Subject: Re: The seven step-Mathematical preliminaries 2


 === Intension and extension 



 In the case of finite and little set we have seen that we can  
 define them by exhaustion. This means we can give an explicit  
 complete description of all element of the set.
 Example. A = {0, 1, 2, 77, 98, 5}

 When the set is still finite and too big, or if we are lazy, we can  
 sometimes define the set by quasi exhaustion. This means we describe  
 enough elements of the set in a manner which, by requiring some good  
 will and some imagination, we can estimate having define the set.

 Example. B = {3, 6, 9, 12, ... 99}. We can understand in this case  
 that we meant the set of multiple of the number three, below 100.

 A fortiori, when a set in not finite, that is, when the set is  
 infinite, we have to use either quasi-exhaustion, or we have to use  
 some sentence or phrase or proposition describing the elements of  
 the set.

 Definition.
 I will say that a set is defined IN EXTENSIO, or simply, in  
 extension, when it is defined in exhaustion or quasi-exhaustion.
 I will say that a set is defined IN INTENSIO, or simply in  
 intension, with a s, when it is defined by a sentence explaining  
 the typical attribute of the elements.

 Example: Let A be the set {2, 4, 6, 8, 10, ... 100}. We can easily  
 define A in intension:  A = the set of numbers which are even and  
 more little than 100. mathematician will condense this by the  
 following:

 A = {x such that x is even and little than 100}  = {x ⎮ x is even   
 x  100}. ⎮ is a special character, abbreviating such that, and  
 I hope it goes through the mail. If not I will use such that, or  
 s.t., or things like that.
 The expression {x ⎮ x is even} is literally read as:  the set of  
 object x, (or number x if we are in a context where we talk about  
 number) such that x is even.

 Exercise 1: Could you define in intension the following infinite set  
 C = {101, 103, 105, ...}
 C = ?

 Exercise 2: I will say that a natural number is a multiple of 4 if  
 it can be written as 4*y, for some y. For example 0 is a multiple of  
 4, (0 = 4*0), but also 28, 400, 404, ...  Could you define in  
 extension the following set D = {x ⎮ x  10x is a multiple of  
 4}.

 A last notational, but important symbol. Sets have elements. For  
 example the set A = {1, 2, 3} has three elements 1, 2 and 3. For  
 saying that 3 is an element of A in an a short way, we usually write  
 3 ∈ A.  this is read as 3 belongs to A, or 3 is in A. Now 4  
 does not belong to A. To write this in a short way, we will write 4  
 ∉ A, or we will write ¬ (4 ∈ A) or sometimes just NOT(4 ∈ A).  
 It is read: 4 does not belong to A, or: it is not the case that 4  
 belongs to A.

 Having those notions and notations at our disposition we can speed  
 up on the notion of union and intersection.

 The intersection of the sets A and B is the (new) set of those  
 elements which belongs to both A and B. Put in another way:
 The intersection of the sets A with the set B is the set of those  
 elements which belongs to A and which belongs to B.
 This new set, obtained from A and B is written A ∩ B, or A inter. B  
 (in case the special character doesn't go through).
 With our notations we can write or define the intersection A ∩ B  
 directly

 A ∩ B = {x ⎮ x ∈ A and x ∈ B}.

 Example {3, 4, 5, 6, 8} ∩ {5, 6, 7, 9} = {5, 6}

 Similarly, we can directly define the union of two sets A and B,  
 written A ∪ B in the following way:

 A ∪ B = {x ⎮ x ∈ A or x ∈ B}.Here we use the usual  
 logical or. p or q is suppose to be true if p is true or q is true  
 (or both are true). It is not the exclusive or.

 Example {3, 4, 5, 6, 8} ∪ {5, 6, 7, 9} = {3, 4, 5, 6, 7, 8}.

 Exercice 3.
 Let N = {0, 1, 2, 3, ...}
 Let A = {x ⎮ x  10}
 Let B = {x ⎮ x

Re: The seven step-Mathematical preliminaries 2

2009-06-06 Thread m.a.
On this date, you made the following correction:  You cannot write D = 4*x 
...,  But you wrote   D= 4*x   in the exercise just above it. I don't get 
the distinction between your use of the equation and mine.
  - Original Message - 
  From: Bruno Marchal 




  Exercise 2: I will say that a natural number is a multiple of 4 if it can 
be written as 4*y, for some y. For example 0 is a multiple of 4, (0 = 4*0), but 
also 28, 400, 404, ...  Could you define in extension the following set D = {x 
⎮ x  10x is a multiple of 4}.D=4*x  where x = 0 (but also 1,2,3...10)


  You cannot write D = 4*x ..., given that D is a set, and 4*x is a (unknown) 
number (a multiple of four when x is a natural number).

  Read carefully the problem. I gave the set in intension, and the exercise 
consisted in writing the set in extension. Let us translate in english the 
definition of the set D = {x ⎮ x  10x is a multiple of 4}: it means that 
D is the set of numbers, x, such that x is little than 10, and x is a multiple 
of four. So D = {0, 4, 8}.



  SEE BELOW





  Example: the set of multiple of 4 is {0, 4, 8, 12, 16, 20, 24, 28, 32, 36, 
...}, all have the shape 4*x, with x = to 0, 1, 2, 3, ...
  The set of multiple of 5 is {0, 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 
...}
  Etc.












  A ∩ B = {x ⎮ x ∈ A and x ∈ B}.


  Example {3, 4, 5, 6, 8} ∩ {5, 6, 7, 9} = {5, 6}


  Similarly, we can directly define the union of two sets A and B, written 
A ∪ B in the following way:


  A ∪ B = {x ⎮ x ∈ A or x ∈ B}.Here we use the usual logical or. p or 
q is suppose to be true if p is true or q is true (or both are true). It is not 
the exclusive or.


  Example {3, 4, 5, 6, 8} ∪ {5, 6, 7, 9} = {3, 4, 5, 6, 7, 8}.   Question: 
In the example above, 5,6 were the intersection because they were the (only) 
two numbers BOTH groups had in common. But in this example, 7 is only in the 
second group yet it is included in the answer. Please explain.




  In the example above (that is {3, 4, 5, 6, 8} ∩ {5, 6, 7, 9} = {5, 6}) we 
were taking the INTERSECTION of the two sets.
  But after that, may be too quickly (and I should have made a title perhaps) I 
was introducing the UNION of the two sets.


  If you read carefully the definition in intension, you should see that the 
intersection of A and B is defined with an and. The definition of union is 
defined with a or. Do you see that? It is just above in the quote.




  I hope that your computer can distinguish A ∩ B  (A intersection B) and A ∪ B 
 (A union B).
  In the union of two sets, you put all the elements of the two sets together. 
In the intersection of two sets, you take only those elements which belongs to 
the two sets.


  It seems you have not seen the difference between intersection and union. 
 

  This has indeed been the case. My usual math disabilities have been 
exacerbated by the confusion of symbols due to E-mail limitations. The 
profusion of little rectangles replacing the UNION symbol make the formulae 
difficult to follow. 























  

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Re: The seven step-Mathematical preliminaries 2

2009-06-06 Thread Brent Meeker

m.a. wrote:
 *Bruno,*
 *   I've encountered some difficulty with the examples below. 
 You say that  in extension describes  exhaustion or 
 quasi-exhaustion. And you give the example:  **B = {3, 6, 9, 12, ... 
 99}.*
 *   Then you define in intension with exactly the same type 
 of set: Example: Let A be the set {2, 4, 6, 8, 10, ... 100}.*

No, that's not the intensional definition.  This We can easily define A 
in intension:  A = the set of numbers which are even and more little 
than 100. is the intensional definition.

Brent

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Re: The seven step-Mathematical preliminaries 2

2009-06-06 Thread m.a.
  Bruno,
   When I tried to copy the symbols from the URL cited below, I 
found that my email server was not able to reproproduce the intersection or the 
union symbol. See below:

   From: Bruno Marchal
  To: everything-list@googlegroups.com
  

  ∅ ∪ A = I see two rectangles and  A
  ∅ ∪ B = I see two rectangles and B
  A ∪ ∅ = I see A and two rectangles
  B ∪ ∅ = I see B and two rectangles
  N ∩ ∅ = I see N  Inverted U  and a rectangle
  B ∩ ∅ = I see B  Inverted U  and a rectangle
  ∅ ∩ B = I see a rectangle  an inverted U  and B
  ∅ ∩ ∅ = I see a rectangle  an inverted U  and a rectangle
  ∅ ∪ ∅ = I see three rectangles
 - Original Message - 
  From: Bruno Marchal 


  You could look on the archive, from here, 


  http://www.mail-archive.com/everything-list@googlegroups.com/msg16531.html














  

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Re: The seven step-Mathematical preliminaries

2009-06-06 Thread Brent Meeker

Quentin Anciaux wrote:
 2009/6/6 Torgny Tholerus tor...@dsv.su.se:
   
 Jesse Mazer skrev:
 
   
 Date: Sat, 6 Jun 2009 16:48:21 +0200
 From: tor...@dsv.su.se
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries

 Jesse Mazer skrev:
 
 Here you're just contradicting yourself. If you say BIGGEST+1 is then
 a natural number, that just proves that the set N was not in fact the
 set of all natural numbers. The alternative would be to say
 BIGGEST+1 is *not* a natural number, but then you need to provide a
 definition of natural number that would explain why this is the case.
   
 It depends upon how you define natural number. If you define it by: n
 is a natural number if and only if n belongs to N, the set of all
 natural numbers, then of course BIGGEST+1 is *not* a natural number. In
 that case you have to call BIGGEST+1 something else, maybe unnatural
 number.
 
 OK, but then you need to define what you mean by N, the set of all
 natural numbers. Specifically you need to say what number is
 BIGGEST. Is it arbitrary? Can I set BIGGEST = 3, for example? Or do
 you have some philosophical ideas related to what BIGGEST is, like the
 number of particles in the universe or the largest number any human
 can conceptualize?
   
 It is rather the last, the largest number any human can conceptualize.
 More natural numbers are not needed.
 

 What is the last number human can invent ? Your theory can't explain
 why addition works... If N is limited, then addition can and will (in
 human lifetime) create number which are still finite and not in N.
   

It is very unlikely that anyone will get to the number 10^10^100 by 
addition.  :-)

Would agree that a any given time there is a largest number which has 
been conceived by a human being?

 N can be defined solelly as the successor function, you don't need
 anything else. You just have to assert that the function is true
 always.

   
 Also, any comment on my point about there being an infinite number of
 possible propositions about even a finite set,
   
 There is not an infinite number of possible proposition.
 

 Prove it please.
   

That would seem to turn on the meaning of possible.  Many (dare I say 
infinitely many) things are logically possible which are not 
nomologically possible (although the posters on this list seem to doubt 
that).

Brent

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Re: The seven step-Mathematical preliminaries 2

2009-06-06 Thread m.a.
Okay, so is it true to say that things written in EXTENSION are never in 
formula style but are translated into formulas when we put them into  INTENSION 
  form?  You can see that my difficulty with math arises from an inability to 
master even the simplest definitions.marty a.


  - Original Message - 
  From: Bruno Marchal 





   I've encountered some difficulty with the examples below. You 
say that  in extension describes  exhaustion or quasi-exhaustion. And you 
give the example:  B = {3, 6, 9, 12, ... 99}.
   Then you define in intension with exactly the same type of 
set: Example: Let A be the set {2, 4, 6, 8, 10, ... 100}.




  I give A in extension there, but just to define it in intension after. It is 
always the same set there. But I show its definition in extension, to show the 
definition in intension after. You have to read the to sentences.




   Can you see the cause of my confusion? 




  It is always the same set. I give it in extension, and then in intension.










  http://iridia.ulb.ac.be/~marchal/






  

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Re: The seven step-Mathematical preliminaries 2

2009-06-06 Thread Brent Meeker

m.a. wrote:
 *Okay, so is it true to say that things written in EXTENSION are never 
 in formula style but are translated into formulas when we put them 
 into  INTENSION   form?  You can see that my difficulty with math 
 arises from an inability to master even the simplest definitions.
 marty a.*

It's not that technical.  I could define the set of books on my shelf by 
giving a list of titles: The Comprehensible Cosmos, Set Theory and 
It's Philosophy, Overshoot, Quintessence.  That would be a 
definition by extension.  Or I could point to them in succession and 
say, That and that and that and that. which would be a definition by 
ostension. Or I could just say, The books on my shelf. which is a 
definition by intension.  An intensional definition is a descriptive 
phrase with an implicit variable, which in logic you might write as: The 
set of things x such that x is a book and x is on my shelf.

Brent

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Re: The seven step-Mathematical preliminaries

2009-06-05 Thread Torgny Tholerus

Brian Tenneson skrev:


 On Thu, Jun 4, 2009 at 8:27 AM, Torgny Tholerus tor...@dsv.su.se 
 mailto:tor...@dsv.su.se wrote:


 Brian Tenneson skrev:
 
 
  Torgny Tholerus wrote:
  It is impossible to create a set where the successor of every
 element is
  inside the set, there must always be an element where the
 successor of
  that element is outside the set.
 
  I disagree.  Can you prove this?
  Once again, I think the debate ultimately is about whether or not to
  adopt the axiom of infinity.
  I think everyone can agree without that axiom, you cannot build or
  construct an infinite set.
  There's nothing right or wrong with adopting any axioms.  What
 results
  is either interesting or not, relevant or not.

 How do you handle the Russell paradox with the set of all sets
 that does
 not contain itself?  Does that set contain itself or not?

  
 If we're talking about ZFC set theory, then the axiom of foundation 
 prohibits sets from being elements of themselves.
 I think we agree that in ZFC, there is no set of all sets.

But there is a set of all sets.  You can construct it by taking all 
sets, and from them doing a new set, the set of all sets.  But note, 
this set will not contain itself, because that set did not exist before.

  



 My answer is that that set does not contain itself, because no set can
 contain itself.  So the set of all sets that does not contain
 itself, is
 the same as the set of all sets.  And that set does not contain
 itself.
 This set is a set, but it does not contain itself.  It is exactly the
 same with the natural numbers, *BIGGEST+1 is a natural number, but it
 does not belong to the set of all natural numbers.  *The set of
 all sets
 is a set, but it does not belong to the set of all sets.

 How can BIGGEST+1 be a natural number but not belong to the set of all 
 natural numbers?

One way to represent natural number as sets is:

0 = {}
1 = {0} = {{}}
2 = {0, 1} = 1 union {1} = {{}, {{}}}
3 = {0, 1, 2} = 2 union {2} = ...
. . .
n+1 = {0, 1, 2, ..., n} = n union {n}
. . .

Here you can then define that a is less then b if and only if a belongs 
to b.

With this notation you get the set N of all natural numbers as {0, 1, 2, 
...}.  But the remarkable thing is that N is exactly the same as 
BIGGEST+1.  BIGGEST+1 is a set with the same structure as all the other 
natural numbers, so it is then a natural number.  But BIGGEST+1 is not a 
member of N, the set of all natural numbers.  BIGGEST+1 is bigger than 
all natural numbers, because all natural numbers belongs to BIGGEST+1.

  


 
  What the largest number is depends on how you define natural
 number.
  One possible definition is that N contains all explicit numbers
  expressed by a human being, or will be expressed by a human
 being in the
  future.  Amongst all those explicit numbers there will be one
 that is
  the largest.  But this largest number is not an explicit number.
 
 
  This raises a deeper question which is this: is mathematics
 dependent
  on humanity or is mathematics independent of humanity?
  I wonder what would happen to that human being who finally expresses
  the largest number in the future.  What happens to him when he wakes
  up the next day and considers adding one to yesterday's number?

 This is no problem.  If he adds one to the explicit number he
 expressed
 yesterday, then this new number is an explicit number, and the number
 expressed yesterday was not the largest number.  Both 17 and 17+1 are
 explicit numbers.

 This goes back to my earlier comment that it's hard for me to believe 
 that the following statement is false:
 every natural number has a natural number successor
 We -must- be talking about different things, then, when we use the 
 phrase natural number.
 I can't say your definition of natural numbers is right and mine is 
 wrong, or vice versa.  I do wonder what advantages there are to the 
 ultrafinitist approach compared to the math I'm familiar with. 

The biggest advantage is that everything is finite, and you can then 
really know that the mathematical theory you get is consistent, it does 
not contain any contradictions.

-- 
Torgny Tholerus

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Re: The seven step-Mathematical preliminaries

2009-06-05 Thread Torgny Tholerus

Kory Heath skrev:
 On Jun 4, 2009, at 8:27 AM, Torgny Tholerus wrote:
   
 How do you handle the Russell paradox with the set of all sets that  
 does
 not contain itself?  Does that set contain itself or not?

 My answer is that that set does not contain itself, because no set can
 contain itself.  So the set of all sets that does not contain  
 itself, is
 the same as the set of all sets.  And that set does not contain  
 itself.
 This set is a set, but it does not contain itself.  It is exactly the
 same with the natural numbers, BIGGEST+1 is a natural number, but it
 does not belong to the set of all natural numbers.  The set of all  
 sets
 is a set, but it does not belong to the set of all sets.
 

 So you're saying that the set of all sets doesn't contain all sets.  
 How is that any less paradoxical than the Russell paradox you're  
 trying to avoid?
   

The secret is the little word all.  To be able to use that word, you 
have to define it.  You can define it by saying: By 'all sets' I mean 
that set and that set and that set and   When you have made that 
definition, you are then able to create a new set, the set of all sets.  
But you must be carefull with what you do with that set.  That set does 
not contain itself, because it was not included in your definition of 
all sets.

If you call the set of all sets for A, then you have:

For all x such that x is a set, then x belongs to A.
A is a set.

But it is illegal to substitute A for x, so you can not deduce:

A is a set, then A belongs to A.

This deductuion is illegal, because A is not included in the definition 
of all x.

-- 
Torgny Tholerus

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Re: The seven step-Mathematical preliminaries

2009-06-05 Thread Quentin Anciaux

2009/6/5 Torgny Tholerus tor...@dsv.su.se:

 Kory Heath skrev:
 On Jun 4, 2009, at 8:27 AM, Torgny Tholerus wrote:

 How do you handle the Russell paradox with the set of all sets that
 does
 not contain itself?  Does that set contain itself or not?

 My answer is that that set does not contain itself, because no set can
 contain itself.  So the set of all sets that does not contain
 itself, is
 the same as the set of all sets.  And that set does not contain
 itself.
 This set is a set, but it does not contain itself.  It is exactly the
 same with the natural numbers, BIGGEST+1 is a natural number, but it
 does not belong to the set of all natural numbers.  The set of all
 sets
 is a set, but it does not belong to the set of all sets.


 So you're saying that the set of all sets doesn't contain all sets.
 How is that any less paradoxical than the Russell paradox you're
 trying to avoid?


 The secret is the little word all.  To be able to use that word, you
 have to define it.

I call that secret bullshit, and to understand that word (bullshit),
you have to define it.

Sorry but I think we're talking in english here, all means all not
what you decide it means.

Quentin.

 You can define it by saying: By 'all sets' I mean
 that set and that set and that set and   When you have made that
 definition, you are then able to create a new set, the set of all sets.
 But you must be carefull with what you do with that set.  That set does
 not contain itself, because it was not included in your definition of
 all sets.

 If you call the set of all sets for A, then you have:

 For all x such that x is a set, then x belongs to A.
 A is a set.

 But it is illegal to substitute A for x, so you can not deduce:

 A is a set, then A belongs to A.

 This deductuion is illegal, because A is not included in the definition
 of all x.

 --
 Torgny Tholerus

 




-- 
All those moments will be lost in time, like tears in rain.

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RE: The seven step-Mathematical preliminaries

2009-06-05 Thread Jesse Mazer



 Date: Fri, 5 Jun 2009 08:33:47 +0200
 From: tor...@dsv.su.se
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries
 
 
 Brian Tenneson skrev:


 On Thu, Jun 4, 2009 at 8:27 AM, Torgny Tholerus tor...@dsv.su.se 
 mailto:tor...@dsv.su.se wrote:


 Brian Tenneson skrev:


 Torgny Tholerus wrote:
 It is impossible to create a set where the successor of every
 element is
 inside the set, there must always be an element where the
 successor of
 that element is outside the set.

 I disagree.  Can you prove this?
 Once again, I think the debate ultimately is about whether or not to
 adopt the axiom of infinity.
 I think everyone can agree without that axiom, you cannot build or
 construct an infinite set.
 There's nothing right or wrong with adopting any axioms.  What
 results
 is either interesting or not, relevant or not.

 How do you handle the Russell paradox with the set of all sets
 that does
 not contain itself?  Does that set contain itself or not?

  
 If we're talking about ZFC set theory, then the axiom of foundation 
 prohibits sets from being elements of themselves.
 I think we agree that in ZFC, there is no set of all sets.
 
 But there is a set of all sets.  You can construct it by taking all 
 sets, and from them doing a new set, the set of all sets.  But note, 
 this set will not contain itself, because that set did not exist before.
 
  



 My answer is that that set does not contain itself, because no set can
 contain itself.  So the set of all sets that does not contain
 itself, is
 the same as the set of all sets.  And that set does not contain
 itself.
 This set is a set, but it does not contain itself.  It is exactly the
 same with the natural numbers, *BIGGEST+1 is a natural number, but it
 does not belong to the set of all natural numbers.  *The set of
 all sets
 is a set, but it does not belong to the set of all sets.

 How can BIGGEST+1 be a natural number but not belong to the set of all 
 natural numbers?
 
 One way to represent natural number as sets is:
 
 0 = {}
 1 = {0} = {{}}
 2 = {0, 1} = 1 union {1} = {{}, {{}}}
 3 = {0, 1, 2} = 2 union {2} = ...
 . . .
 n+1 = {0, 1, 2, ..., n} = n union {n}
 . . .
 
 Here you can then define that a is less then b if and only if a belongs 
 to b.
 
 With this notation you get the set N of all natural numbers as {0, 1, 2, 
 ...}.  But the remarkable thing is that N is exactly the same as 
 BIGGEST+1.  BIGGEST+1 is a set with the same structure as all the other 
 natural numbers, so it is then a natural number.  But BIGGEST+1 is not a 
 member of N, the set of all natural numbers.
Here you're just contradicting yourself. If you say BIGGEST+1 is then a 
natural number, that just proves that the set N was not in fact the set of 
all natural numbers. The alternative would be to say BIGGEST+1 is *not* a 
natural number, but then you need to provide a definition of natural number 
that would explain why this is the case.
 The biggest advantage is that everything is finite, and you can then 
 really know that the mathematical theory you get is consistent, it does 
 not contain any contradictions.

Even if you define natural number in such a way that there are only a finite 
number of them (which you haven't actually done, you've just asserted it 
without providing any specific definition), you still could have an infinite 
number of *propositions* about them if you allow each proposition to contain an 
unlimited number of AND and OR operators. For example, even if I say that the 
only natural numbers are 1,2,3, I can still make arbitrarily long propositions 
like ((31) AND (21)) OR (31)) AND ((23) OR (31)) AND ((23) OR ((13) OR 
((21) OR ((13) OR (31). Of course a non-finitist would be able to prove 
that these infinite number of propositions are consistent, but I don't know if 
an ultrafinitist would (likewise a non-finitist can accept a proof that 
something like the Peano axioms are consistent based on an understanding of 
their application to a model dealing with rows of dots, even if the Peano 
axioms cannot be used to formally prove their own consistency).
Jesse
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Re: The seven step-Mathematical preliminaries

2009-06-05 Thread Brian Tenneson


Torgny Tholerus wrote:
 Brian Tenneson skrev:
   
 On Thu, Jun 4, 2009 at 8:27 AM, Torgny Tholerus tor...@dsv.su.se 
 mailto:tor...@dsv.su.se wrote:


 Brian Tenneson skrev:
 
 
  Torgny Tholerus wrote:
  It is impossible to create a set where the successor of every
 element is
  inside the set, there must always be an element where the
 successor of
  that element is outside the set.
 
  I disagree.  Can you prove this?
  Once again, I think the debate ultimately is about whether or not to
  adopt the axiom of infinity.
  I think everyone can agree without that axiom, you cannot build or
  construct an infinite set.
  There's nothing right or wrong with adopting any axioms.  What
 results
  is either interesting or not, relevant or not.

 How do you handle the Russell paradox with the set of all sets
 that does
 not contain itself?  Does that set contain itself or not?

  
 If we're talking about ZFC set theory, then the axiom of foundation 
 prohibits sets from being elements of themselves.
 I think we agree that in ZFC, there is no set of all sets.
 

 But there is a set of all sets.  You can construct it by taking all 
 sets, and from them doing a new set, the set of all sets.  But note, 
 this set will not contain itself, because that set did not exist before.
   
If that set does not contain itself then it is not a set of all sets.

   
  



 My answer is that that set does not contain itself, because no set can
 contain itself.  So the set of all sets that does not contain
 itself, is
 the same as the set of all sets.  And that set does not contain
 itself.
 This set is a set, but it does not contain itself.  It is exactly the
 same with the natural numbers, *BIGGEST+1 is a natural number, but it
 does not belong to the set of all natural numbers.  *The set of
 all sets
 is a set, but it does not belong to the set of all sets.

 How can BIGGEST+1 be a natural number but not belong to the set of all 
 natural numbers?
 

 One way to represent natural number as sets is:

 0 = {}
 1 = {0} = {{}}
 2 = {0, 1} = 1 union {1} = {{}, {{}}}
 3 = {0, 1, 2} = 2 union {2} = ...
 . . .
 n+1 = {0, 1, 2, ..., n} = n union {n}
 . . .

 Here you can then define that a is less then b if and only if a belongs 
 to b.

 With this notation you get the set N of all natural numbers as {0, 1, 2, 
 ...}.  But the remarkable thing is that N is exactly the same as 
 BIGGEST+1.  BIGGEST+1 is a set with the same structure as all the other 
 natural numbers, so it is then a natural number.  But BIGGEST+1 is not a 
 member of N, the set of all natural numbers.  BIGGEST+1 is bigger than 
 all natural numbers, because all natural numbers belongs to BIGGEST+1.
   
Right, so n+1 is a natural number whenever n is. 
   
  


 
  What the largest number is depends on how you define natural
 number.
  One possible definition is that N contains all explicit numbers
  expressed by a human being, or will be expressed by a human
 being in the
  future.  Amongst all those explicit numbers there will be one
 that is
  the largest.  But this largest number is not an explicit number.
 
 
  This raises a deeper question which is this: is mathematics
 dependent
  on humanity or is mathematics independent of humanity?
  I wonder what would happen to that human being who finally expresses
  the largest number in the future.  What happens to him when he wakes
  up the next day and considers adding one to yesterday's number?

 This is no problem.  If he adds one to the explicit number he
 expressed
 yesterday, then this new number is an explicit number, and the number
 expressed yesterday was not the largest number.  Both 17 and 17+1 are
 explicit numbers.

 This goes back to my earlier comment that it's hard for me to believe 
 that the following statement is false:
 every natural number has a natural number successor
 We -must- be talking about different things, then, when we use the 
 phrase natural number.
 I can't say your definition of natural numbers is right and mine is 
 wrong, or vice versa.  I do wonder what advantages there are to the 
 ultrafinitist approach compared to the math I'm familiar with. 
 

 The biggest advantage is that everything is finite, and you can then 
 really know that the mathematical theory you get is consistent, it does 
 not contain any contradictions.

   
 From what you said earlier, BIGGEST={0,1,...,BIGGEST-1}.  Then 
BIGGEST+1={0,1,...,BIGGEST-1} union {BIGGEST} = {0,1,...,BIGGEST}.
Why would {0,1,...BIGGEST} not be a natural number while 
{0,1,...,BIGGEST-1} is?

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Re: The seven step-Mathematical preliminaries

2009-06-05 Thread A. Wolf

 From what you said earlier, BIGGEST={0,1,...,BIGGEST-1}.  Then
 BIGGEST+1={0,1,...,BIGGEST-1} union {BIGGEST} = {0,1,...,BIGGEST}.
 Why would {0,1,...BIGGEST} not be a natural number while
 {0,1,...,BIGGEST-1} is?

If {0, 1, ... , BIGGEST-1} is a natural number, then {0,1,...,BIGGEST} is 
too, and then so is {0, 1, ... , BIGGEST+1}, etc.  There's no such thing as 
a largest natural number: that's the whole point of the construction.  The 
set of all natural numbers is an infinite set, unbounded above.  The set N 
has no largest element within it: it is the set of all finite ordinals.  N 
(usually called omega when treated as an ordinal) has no predecessor, 
because it is formed by taking the limit of all the ordinals below it, *not* 
by applying the successor function x+ = x U {x}.  This is the way 
well-ordering works...it's not symmetric.  So any set described {a, b, ... , 
z} in the standard way is not N.

N is not the successor of any natural number; rather, it contains them all. 
This allows us to talk about (and prove things about) all natural numbers. 
This isn't an arbitrary mathematical choice.  Without infinite sets, we 
would be unable to rigorously prove things by induction, which is necessary 
for a wide array of basic arithmetical proofs.  This is because a finite set 
of natural numbers cannot be closed under successor (or addition or 
multiplication, for that matter).  If you relied on only finitely many 
numbers, your functions could take natural numbers and hand you back 
something that isn't a number at all.  This makes even basic math untenable. 
Taking the closure of {} under successor is the solution.

(There are non-standard models of the natural numbers that contain numbers 
other than the elements of N, but these are not well-ordered.)

Anna


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Re: The seven step-Mathematical preliminaries 2

2009-06-05 Thread m.a.
Bruno,
   Thanks for the encouragement. I intend to follow your instructions 
and it's a relief to know that some of my answers were correct. However, I will 
be away for two weeks and unable to work on the lessons. I'll try to make up 
for it when I return. Best,   


marty a.


  - Original Message - 
  From: Bruno Marchal 
  To: everything-list@googlegroups.com 
  Sent: Friday, June 05, 2009 10:03 AM
  Subject: Re: The seven step-Mathematical preliminaries 2


  Hi Marty,


  On 05 Jun 2009, at 00:30, m.a. wrote:






Bruno,
   I don't have dyslexia 






  Good news.










but my keyboard doesn't contain either the UNION symbol or the INTERSECTION 
symbol 




  Nor do mine!








(unless I want to go into an INSERT pull down menu every time I use those 
symbols). 




  Like I have to do too.








I don't need you to switch to English symbols, but I would like to see the 
English equivalents of the symbols you use (so that I can use them). 




  I gave them.








I would also like a reference table defining each term in both your symbols 
and their English equivalents which I could look back to when I get confused. 




  I suggest you do this by yourself. It is a good exercise and it will help you 
not only in the understanding, but in the memorizing. Then you submit it to the 
list, and I can verify the understanding. 










Please include examples.


  Up to now, I did it for any notions introduced. Just ask me one or two or 
(name your number) examples more in case you have a doubt. If I send too much 
posts, and if there are too long, people will dismiss them. try to ask explicit 
question, like you did, actually.






I tend to be somewhat careless when dealing  with very fine distinctions 




  This means that a lot of work is awaiting for you. It is normal. Everyone can 
understand what I explain, but some have more work to do.








and may type the wrong symbol while intending to type the correct one. 




  That is unimportant. I am used to do typo errors too. One of my favorite book 
on self-reference (the one by Smorynski) contains an average of two or three 
typo error per page. Of course, once a typo error is found, it is better to 
correct it. 










Also, I must admit that the lessons are going too fast for me and are 
moving ahead before I've mastered the previous material.




  We have all the time, and up to now I did not proceed without having the 
answer of all exercises. You make no faults in the first set of seven exercise, 
and that is why I have quickly proceed to the second round. For that one, you 
make just one error, + the dismiss of a paragraph on UNION.  To slow me down 
it is enough to tell me things like I don't understand what you mean by this 
or that and you quote the unclear passage. If you can't do an exercise, just 
wait for some other (Kim?) to propose a solution. Or try to guess one and 
submit, or just ask. I will not proceed to new matters before I am sure you 
grasp all what has been already presented.
  What is possible is that you understand, but fail ti memorize. This will lead 
to problems later. So you have to make your own summary and be sure you can 
easily revise the definition.








If I'm requesting too much simplification, please let me know because I'm 
quite well adjusted to my math disabilities and won't take offence at all. 
Thanks,  marty a.






  I think that there is no problem at all. I am just waiting for explicit 
question from the second round. You can ask any question, and slow me down as 
much as you want so that we proceed at your own rhythm. 
  Don't ask me to slow down in any abstract way. You are the one who have to 
slow me down by pointing on what you don't understand in a post.
  take it easy, and take all your time. Don't try to understand the more 
advanced replies I give to people who have a bigger baggage.


  You did show me that you have understood the notion of set, and the notion of 
intersection of sets. Have you a problem with the notion of union of sets? If 
that is the case, just quote the passage of my post that you don't understand, 
or the example that I gave, and I will explain. Try to keep those post in some 
well ranged place so as to re-access them easily.


  I ask this to Kim too, and any one interested: just let me know what you 
don't understand, so that I can explain, give other examples, etc. 


  Take it easy, you seem quite good, you suffer just of a problem of 
familiarity with notations. You read the post too quickly, I suspect also.


  Are you OK? I can understand you could be afraid of the amount of work, but 
given that we have all the time, there is no exams, nor deadline, I am not sure 
there is any problem

Re: The seven step-Mathematical preliminaries

2009-06-04 Thread Torgny Tholerus

Brian Tenneson skrev:
   
 How do you know that there is no biggest number?  Have you examined all 
 the natural numbers?  How do you prove that there is no biggest number?

   
 
 In my opinion those are excellent questions.  I will attempt to answer 
 them.  The intended audience of my answer is everyone, so please forgive 
 me if I say something you already know.

 Firstly, no one has or can examine all the natural numbers.  By that I 
 mean no human.  Maybe there is an omniscient machine (or a maximally 
 knowledgeable in some paraconsistent way)  who can examine all numbers 
 but that is definitely putting the cart before the horse.

 Secondly, the question boils down to a difference in philosophy: 
 mathematicians would say that it is not necessary to examine all natural 
 numbers.  The mathematician would argue that it suffices to examine all 
 essential properties of natural numbers, rather than all natural numbers.

 There are a variety of equivalent ways to define a natural number but 
 the essential features of natural numbers are that
 (a) there is an ordering on the set of natural numbers, a well 
 ordering.  To say a set is well ordered entails that every =nonempty= 
 subset of it has a least element.
 (b) the set of natural numbers has a least element (note that it is 
 customary to either say 0 is this least element or say 1 is this least 
 element--in some sense it does not matter what the starting point is)
 (c) every natural number has a natural number successor.  By successor 
 of a natural number, I mean anything for which the well ordering always 
 places the successor as larger than the predecessor.

 Then the set of natural numbers, N, is the set containing the least 
 element (0 or 1) and every successor of the least element, and only 
 successors of the least element.

 There is nothing wrong with a proof by contradiction but I think a 
 forward proof might just be more convincing.

 Consider the following statement:
 Whenever S is a subset of N, S has a largest element if, and only if, 
 the complement of S has a least element.

 By complement of S, I mean the set of all elements of N that are not 
 elements of S.

 Before I give a longer argument, would you agree that statement is 
 true?  One can actually be arbitrarily explicit: M is the largest 
 element of S if, and only if, the successor of M is the least element of 
 the compliment of S.
   

I do not agree that statement is true.  Because if you call the Biggest 
natural number B, then you can describe N as = {1, 2, 3, ..., B}.  If 
you take the complement of N you will get the empty set.  This set have 
no least element, but still N has a biggest element.

In your statement you are presupposing that N has no biggest element, 
and from that axiom you can trivially deduce that there is no biggest 
element.

-- 
Torgny Tholerus

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Re: The seven step-Mathematical preliminaries

2009-06-04 Thread Quentin Anciaux

If you are ultrafinitist then by definition the set N does not
exist... (nor any infinite set countably or not).

If you pose the assumption of a biggest number for N, you come to a
contradiction because you use the successor operation which cannot
admit a biggest number.(because N is well ordered any successor is
strictly bigger and the successor operation is always valid *by
definition of the operation*)

So either the set N does not exists in which case it makes no sense to
talk about the biggest number in N, or the set N does indeed exists
and it makes no sense to talk about the biggest number in N (while it
makes sense to talk about a number which is strictly bigger than any
natural number).

To come back to the proof by contradiction you gave, the assumption
(2) which is that BIGGEST+1 is in N, is completely defined by the mere
existence of BIGGEST. If BIGGEST exists and well defined it entails
that BIGGEST+1 is not in N (but this invalidate the successor
operation and hence the mere existence of N). If BIGGEST in contrary
does not exist (as such, means it is not the biggest) then BIGGEST+1
is in N by definition of N.

Regards,
Quentin

2009/6/4 Torgny Tholerus tor...@dsv.su.se:

 Brian Tenneson skrev:

 How do you know that there is no biggest number?  Have you examined all
 the natural numbers?  How do you prove that there is no biggest number?



 In my opinion those are excellent questions.  I will attempt to answer
 them.  The intended audience of my answer is everyone, so please forgive
 me if I say something you already know.

 Firstly, no one has or can examine all the natural numbers.  By that I
 mean no human.  Maybe there is an omniscient machine (or a maximally
 knowledgeable in some paraconsistent way)  who can examine all numbers
 but that is definitely putting the cart before the horse.

 Secondly, the question boils down to a difference in philosophy:
 mathematicians would say that it is not necessary to examine all natural
 numbers.  The mathematician would argue that it suffices to examine all
 essential properties of natural numbers, rather than all natural numbers.

 There are a variety of equivalent ways to define a natural number but
 the essential features of natural numbers are that
 (a) there is an ordering on the set of natural numbers, a well
 ordering.  To say a set is well ordered entails that every =nonempty=
 subset of it has a least element.
 (b) the set of natural numbers has a least element (note that it is
 customary to either say 0 is this least element or say 1 is this least
 element--in some sense it does not matter what the starting point is)
 (c) every natural number has a natural number successor.  By successor
 of a natural number, I mean anything for which the well ordering always
 places the successor as larger than the predecessor.

 Then the set of natural numbers, N, is the set containing the least
 element (0 or 1) and every successor of the least element, and only
 successors of the least element.

 There is nothing wrong with a proof by contradiction but I think a
 forward proof might just be more convincing.

 Consider the following statement:
 Whenever S is a subset of N, S has a largest element if, and only if,
 the complement of S has a least element.

 By complement of S, I mean the set of all elements of N that are not
 elements of S.

 Before I give a longer argument, would you agree that statement is
 true?  One can actually be arbitrarily explicit: M is the largest
 element of S if, and only if, the successor of M is the least element of
 the compliment of S.


 I do not agree that statement is true.  Because if you call the Biggest
 natural number B, then you can describe N as = {1, 2, 3, ..., B}.  If
 you take the complement of N you will get the empty set.  This set have
 no least element, but still N has a biggest element.

 In your statement you are presupposing that N has no biggest element,
 and from that axiom you can trivially deduce that there is no biggest
 element.

 --
 Torgny Tholerus

 




-- 
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Re: The seven step-Mathematical preliminaries 2

2009-06-04 Thread kimjo...@ozemail.com.au







On Thu Jun  4  1:15 , Bruno Marchal  sent:

Very good answer, Kim, 
Just a few comments. and then the sequel.
Exercice 4: does the real number square-root(2) belongs to {0, 1, 2,  
3, ...}?


No idea what square-root(2) means. When I said I was innumerate I wasn't 
kidding! I 
could of course look 
it up or ask my mathematics teacher friends but I just know your explanation 
will make 
theirs seem trite.

Well thanks. The square root of 2 is a number x, such that x*x (x times x, x 
multiplied by 
itself) gives 2.For example, the square root of 4 is 2, because 2*2 is 4. The 
square root of 
9 is 3, because 3*3 is 9. Her by square root I mean the positive square root, 
because we 
will see (more later that soon) that numbers can have negative square root, but 
please 
forget this. At this stage, with this definition, you can guess that the square 
root of 2 
cannot be a natural number. 1*1 = 1, and 2*2 = 4, and it would be astonishing 
that x 
could be bigger than 2. So if there is number x such that x*x is 2, we can 
guess that such 
a x cannot be a natural number, that is an element of {0, 1, 2, 3 ...}, and the 
answer of 
exercise 4 is no. The square root of two will reappear recurrently, but more 
in examples, 
than in the sequence of notions which are strictly needed for UDA-7.


OK - I find this quite mind-blowing; probably because I now understand it for 
the first 
time in my life. So how did it get this rather ridiculous name of square 
root? What's it 
called in French?

(snip)

=== Intension and extension 

Before defining intersection, union and the notion of subset, I would like to 
come back 
on the ways we can define some specific sets.
In the case of finite and little set we have seen that we can define them by 
exhaustion. 
This means we can give an explicit complete description of all element of the 
set. Example. A = {0, 1, 2, 77, 98, 5}
When the set is still finite and too big, or if we are lazy, we can sometimes 
define the set 
by quasi exhaustion. This means we describe enough elements of the set in a 
manner 
which, by requiring some good will and some imagination, we can estimate having 
define 
the set.
Example. B = {3, 6, 9, 12, ... 99}. We can understand in this case that we 
meant the set of 
multiple of the number three, below 100.

A fortiori, when a set in not finite, that is, when the set is infinite, we 
have to use either 
quasi-exhaustion, or we have to use some sentence or phrase or proposition 
describing 
the elements of the set.

Definition. I will say that a set is defined IN EXTENSIO, or simply, in 
extension, when it is 
defined in exhaustion or quasi-exhaustion. I will say that a set is defined IN 
INTENSIO, or 
simply in intension, with an s, when it is defined by a sentence explaining 
the typical 
attribute of the elements.

Example: Let A be the set {2, 4, 6, 8, 10, ... 100}. We can easily define A in 
intension:  A 
= the set of numbers which are even and smaller than 100. Mathematicians will 
condense 
this by the following:
A = {x such that x is even and smaller than 100}  = {x ⎮ x is even  x 
special character, abbreviating such that, and I hope it goes through the 
mail.




Just an upright line? It comes through as that. I can't seem to get this symbol 
happening so I will 
use such that




 If not I will use such that, or s.t., or things like that.The expression 
{x ⎮ x is even} is 
literally read as:  the set of objects x, (or number x if we are in a context 
where we talk 
about numbers) such that x is even.

Exercise 1: Could you define in intension the following infinite set C = {101, 
103, 105, 
...}C = ?


C = {x such that x is odd and x  101}


Exercise 2: I will say that a natural number is a multiple of 4 if it can be 
written as 4*y, 
for some y. For example 0 is a multiple of 4, (0 = 4*0), but also 28, 400, 404, 
...  Could 
you define in extension the following set D = {x ⎮ x  10 and x is a multiple 
of 4}?

D = 4*x where x = 0 but also { 1, 2, 3, 4, 8 }


I now realise I am doomed for the next set of exercises because I cannot get to 
the special 
symbols required (yet). As I am adding Internet Phone to my system, I am 
currently using an 
ancient Mac without the correct symbol pallette while somebody spends a few 
days to flip a single 
switch...as soon as I can get back to my regular machine I will complete the 
rest.

In the meantime I am enjoying the N+1 disagreement - how refreshing it is to 
see that classical 
mathematics remains somewhat controversial!


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Re: The seven step-Mathematical preliminaries

2009-06-04 Thread Torgny Tholerus

Quentin Anciaux skrev:
 If you are ultrafinitist then by definition the set N does not
 exist... (nor any infinite set countably or not).
   

All sets are finite.  It it (logically) impossible to construct an 
infinite set.

You can construct the set N of all natural numbers.  But that set must 
be finite.  What the set N contains depends on how you have defined 
natural number.

 If you pose the assumption of a biggest number for N, you come to a
 contradiction because you use the successor operation which cannot
 admit a biggest number.(because N is well ordered any successor is
 strictly bigger and the successor operation is always valid *by
 definition of the operation*)
   

You have to define the successor operation.  And to do that you have to 
define the definition set for that operation.  So first you have to 
define the set N of natural numbers.  And from that you can define the 
successor operator.  The value set of the successor operator will be a 
new set, that contains one more element than the set N of natural 
numbers.  This new element is BIGGEST+1, that is strictly bigger than 
all natural numbers.

-- 
Torgny Tholerus

 So either the set N does not exists in which case it makes no sense to
 talk about the biggest number in N, or the set N does indeed exists
 and it makes no sense to talk about the biggest number in N (while it
 makes sense to talk about a number which is strictly bigger than any
 natural number).

 To come back to the proof by contradiction you gave, the assumption
 (2) which is that BIGGEST+1 is in N, is completely defined by the mere
 existence of BIGGEST. If BIGGEST exists and well defined it entails
 that BIGGEST+1 is not in N (but this invalidate the successor
 operation and hence the mere existence of N). If BIGGEST in contrary
 does not exist (as such, means it is not the biggest) then BIGGEST+1
 is in N by definition of N.

 Regards,
 Quentin

   


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Re: The seven step-Mathematical preliminaries

2009-06-04 Thread Brian Tenneson
This is a denial of the axiom of infinity.  I think a foundational set 
theorist might agree that it is impossible to -construct- an infinite 
set from scratch which is why they use the axiom of infinity.
People are free to deny axioms, of course, though the result will not be 
like ZFC set theory.  The denial of axiom of foundation is one I've come 
across; I've never met anyone who denies the axiom of infinity.

For me it is strange that the following statement is false: every 
natural number has a natural number successor.  To me it seems quite 
arbitrary for the ultrafinitist's statement: every natural number has a 
natural number successor UNTIL we reach some natural number which does 
not have a natural number successor.  I'm left wondering what the 
largest ultrafinist's number is.

Torgny Tholerus wrote:
 Quentin Anciaux skrev:
   
 If you are ultrafinitist then by definition the set N does not
 exist... (nor any infinite set countably or not).
   
 

 All sets are finite.  It it (logically) impossible to construct an 
 infinite set.

 You can construct the set N of all natural numbers.  But that set must 
 be finite.  What the set N contains depends on how you have defined 
 natural number.

   
 If you pose the assumption of a biggest number for N, you come to a
 contradiction because you use the successor operation which cannot
 admit a biggest number.(because N is well ordered any successor is
 strictly bigger and the successor operation is always valid *by
 definition of the operation*)
   
 

 You have to define the successor operation.  And to do that you have to 
 define the definition set for that operation.  So first you have to 
 define the set N of natural numbers.  And from that you can define the 
 successor operator.  The value set of the successor operator will be a 
 new set, that contains one more element than the set N of natural 
 numbers.  This new element is BIGGEST+1, that is strictly bigger than 
 all natural numbers.

   

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Re: The seven step-Mathematical preliminaries

2009-06-04 Thread Torgny Tholerus

Brian Tenneson skrev:
 This is a denial of the axiom of infinity.  I think a foundational set 
 theorist might agree that it is impossible to -construct- an infinite 
 set from scratch which is why they use the axiom of infinity.
 People are free to deny axioms, of course, though the result will not 
 be like ZFC set theory.  The denial of axiom of foundation is one I've 
 come across; I've never met anyone who denies the axiom of infinity.

 For me it is strange that the following statement is false: every 
 natural number has a natural number successor.  To me it seems quite 
 arbitrary for the ultrafinitist's statement: every natural number has 
 a natural number successor UNTIL we reach some natural number which 
 does not have a natural number successor.  I'm left wondering what the 
 largest ultrafinist's number is.

It is impossible to lock a box, and quickly throw the key inside the box 
before you lock it.
It is impossible to create a set and put the set itself inside the set, 
i.e. no set can contain itself.
It is impossible to create a set where the successor of every element is 
inside the set, there must always be an element where the successor of 
that element is outside the set.

What the largest number is depends on how you define natural number.  
One possible definition is that N contains all explicit numbers 
expressed by a human being, or will be expressed by a human being in the 
future.  Amongst all those explicit numbers there will be one that is 
the largest.  But this largest number is not an explicit number.

-- 
Torgny Tholerus

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Re: The seven step-Mathematical preliminaries

2009-06-04 Thread Brian Tenneson


Torgny Tholerus wrote:
 Brian Tenneson skrev:
   
 This is a denial of the axiom of infinity.  I think a foundational set 
 theorist might agree that it is impossible to -construct- an infinite 
 set from scratch which is why they use the axiom of infinity.
 People are free to deny axioms, of course, though the result will not 
 be like ZFC set theory.  The denial of axiom of foundation is one I've 
 come across; I've never met anyone who denies the axiom of infinity.

 For me it is strange that the following statement is false: every 
 natural number has a natural number successor.  To me it seems quite 
 arbitrary for the ultrafinitist's statement: every natural number has 
 a natural number successor UNTIL we reach some natural number which 
 does not have a natural number successor.  I'm left wondering what the 
 largest ultrafinist's number is.
 

 It is impossible to lock a box, and quickly throw the key inside the box 
 before you lock it.
   
I disagree.
 It is impossible to create a set and put the set itself inside the set, 
 i.e. no set can contain itself.
   
No one here is suggesting that you can with regards to natural numbers.

 It is impossible to create a set where the successor of every element is 
 inside the set, there must always be an element where the successor of 
 that element is outside the set.
   
I disagree.  Can you prove this?
Once again, I think the debate ultimately is about whether or not to 
adopt the axiom of infinity.
I think everyone can agree without that axiom, you cannot build or 
construct an infinite set.
There's nothing right or wrong with adopting any axioms.  What results 
is either interesting or not, relevant or not.

 What the largest number is depends on how you define natural number.  
 One possible definition is that N contains all explicit numbers 
 expressed by a human being, or will be expressed by a human being in the 
 future.  Amongst all those explicit numbers there will be one that is 
 the largest.  But this largest number is not an explicit number.

   
This raises a deeper question which is this: is mathematics dependent on 
humanity or is mathematics independent of humanity?
I wonder what would happen to that human being who finally expresses the 
largest number in the future.  What happens to him when he wakes up the 
next day and considers adding one to yesterday's number?

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Re: The seven step-Mathematical preliminaries 2

2009-06-04 Thread Bruno Marchal
Hi Marty,


On 04 Jun 2009, at 01:11, m.a. wrote:

 Bruno,
I stopped half-way through because I'm not at all sure of  
 my answers and would like to have them confirmed or corrected, if  
 necessary, rather than go on giving wrong answers.   marty a.


No problem.



 Exercise 1: Could you define in intension the following infinite set  
 C = {101, 103, 105, ...}
 C = ?  C={x such that x is odd  x 101}


I guess you meant C = {x such that x is odd and x  101}.   means  
bigger than, and  means little than. OK.





 Exercise 2: I will say that a natural number is a multiple of 4 if  
 it can be written as 4*y, for some y. For example 0 is a multiple of  
 4, (0 = 4*0), but also 28, 400, 404, ...  Could you define in  
 extension the following set D = {x ⎮ x  10x is a multiple of  
 4}.D=4*x  where x = 0 (but also 1,2,3...10)

You cannot write D = 4*x ..., given that D is a set, and 4*x is a  
(unknown) number (a multiple of four when x is a natural number).
Read carefully the problem. I gave the set in intension, and the  
exercise consisted in writing the set in extension. Let us translate  
in english the definition of the set D = {x ⎮ x  10x is a  
multiple of 4}: it means that D is the set of numbers, x, such that x  
is little than 10, and x is a multiple of four. So D = {0, 4, 8}.

Indeed 0 is little than 10, and 0 is a multiple of four (because 0 =  
4*0), and
4  is little than 10, and 4 is a multiple of four (because 4 = 4*1)
8 is little than 10, and 8 is a multiple of 4 (because 8 = 4*2)
The next mutiple of 4 is 12. It cannot be in the set because 12 is  
bigger than 10.
The numbers 1, 2, 3, 5, 7, 9 cannot be in D, because they are not  
multiple of 4. You cannot write 1 = 4 * (some natural numbers), nor  
can you write 3 or 5, or 7 or 9 =  4 * x with x a natural number.

Example: the set of multiple of 4 is {0, 4, 8, 12, 16, 20, 24, 28, 32,  
36, ...}, all have the shape 4*x, with x = to 0, 1, 2, 3, ...
The set of multiple of 5 is {0, 5, 10, 15, 20, 25, 30, 35, 40, 45, 50,  
55, ...}
Etc.






 A ∩ B = {x ⎮ x ∈ A and x ∈ B}.

 Example {3, 4, 5, 6, 8} ∩ {5, 6, 7, 9} = {5, 6}

 Similarly, we can directly define the union of two sets A and B,  
 written A ∪ B in the following way:

 A ∪ B = {x ⎮ x ∈ A or x ∈ B}.Here we use the usual  
 logical or. p or q is suppose to be true if p is true or q is true  
 (or both are true). It is not the exclusive or.

 Example {3, 4, 5, 6, 8} ∪ {5, 6, 7, 9} = {3, 4, 5, 6, 7, 8}.
 Question: In the example above, 5,6 were the intersection because  
 they were the (only) two numbers BOTH groups had in common. But in  
 this example, 7 is only in the second group yet it is included in  
 the answer. Please explain.


In the example above (that is {3, 4, 5, 6, 8} ∩ {5, 6, 7, 9} = {5,  
6}) we were taking the INTERSECTION of the two sets.
But after that, may be too quickly (and I should have made a title  
perhaps) I was introducing the UNION of the two sets.

If you read carefully the definition in intension, you should see that  
the intersection of A and B is defined with an and. The definition  
of union is defined with a or. Do you see that? It is just above in  
the quote.


I hope that your computer can distinguish A ∩ B  (A intersection B)  
and A ∪ B  (A union B).
In the union of two sets, you put all the elements of the two sets  
together. In the intersection of two sets, you take only those  
elements which belongs to the two sets.

It seems you have not seen the difference between intersection and  
union.  I guess you try to go to much quickly, or that the font of  
your computer are too little, or that you have eyesight problems, or  
that you have some dyslexia.









 Exercice 3.
 Let N = {0, 1, 2, 3, ...}
 Let A = {x ⎮ x  10}
 Let B = {x ⎮ x is even}
 Describe in extension (that is: exhaustion or quasi-exhaustion) the  
 following sets:

 N ∪ A = {0,1,2,3...} inter {x inter x10}= {0,1,2,3...9}
 N ∪ B = {0,1,2,3} inter {x inter x is even}= {0,2,4,6...}
 A ∪ B = {x inter x 10} inter {x inter x is even}= {0,2,4,6,8}
 B ∪ A = {x inter x is even} inter {x inter x  10}= {0,2,4,6,8}

All that would be correct if you were searching the intersection, but  
∪ is the UNION symbol. (and ∩ is the INTERSECTION symbol).

also you wrote the ⎮ as inter, instead of such that.




 N ∩ A = {0,1,2,3...} inter {x inter x10}= {0,1,2,3...9}
 B ∩ A =  {x inter x is even} inter {x inter x  10}= {0,2,4,6,8}
 N ∩ B =  {0,1,2,3} inter {x inter x is even}= {0,2,4,6...}
 A ∩ B =   {x inter x 10} inter {x inter x is even}= {0,2,4,6,8}


All that is correct. Careful you were still using inter in place of  
such that. Your last line should be

A ∩ B =   {x such that x 10} inter {x such that x is even}=  
{0,2,4,6,8}




 Exercice 4

 Is it true that A ∩ B = B ∩ A, whatever A and B are?   yes
 Is it true that A ∪ B = B ∪ A, whatever A and B are?  yes


Both are correct.

Not bad Marty!  Just read carefully. I 

Re: The seven step-Mathematical preliminaries 2

2009-06-04 Thread Jason Resch

On Thu, Jun 4, 2009 at 7:28 AM, kimjo...@ozemail.com.au
kimjo...@ozemail.com.au wrote:







 On Thu Jun  4  1:15 , Bruno Marchal  sent:

Very good answer, Kim,
Just a few comments. and then the sequel.
Exercice 4: does the real number square-root(2) belongs to {0, 1, 2,
3, ...}?


No idea what square-root(2) means. When I said I was innumerate I wasn't 
kidding! I
 could of course look
it up or ask my mathematics teacher friends but I just know your explanation 
will make
 theirs seem trite.

Well thanks. The square root of 2 is a number x, such that x*x (x times x, x 
multiplied by
 itself) gives 2.For example, the square root of 4 is 2, because 2*2 is 4. The 
 square root of
 9 is 3, because 3*3 is 9. Her by square root I mean the positive square 
 root, because we
 will see (more later that soon) that numbers can have negative square root, 
 but please
 forget this. At this stage, with this definition, you can guess that the 
 square root of 2
 cannot be a natural number. 1*1 = 1, and 2*2 = 4, and it would be astonishing 
 that x
 could be bigger than 2. So if there is number x such that x*x is 2, we can 
 guess that such
 a x cannot be a natural number, that is an element of {0, 1, 2, 3 ...}, and 
 the answer of
 exercise 4 is no. The square root of two will reappear recurrently, but 
 more in examples,
 than in the sequence of notions which are strictly needed for UDA-7.


 OK - I find this quite mind-blowing; probably because I now understand it for 
 the first
 time in my life. So how did it get this rather ridiculous name of square 
 root? What's it
 called in French?


I don't know what it is called in French, but I can answer the first
part.  I remember the day I first figured out where the term came
from.

When you have a number multiplied by itself, the result is called a
square.  3*3 = 9, so 9 is a square.  Imagine arranging a set of peas,
if you can arrange them in a square (the four cornered kind) with the
same number of rows as columns, then that number is a square.  Some
examples of squares are: 4, 9, 16, 25, 36, 49, 64, 81, see the
pattern?  And the roots of those squares are 2, 3, 4, 5, 6, 7, 8,
and 9.  The square root is equal to the number of items in a row, or
column when you arrange them in a square.

This is a completely extraneous fact, but one I consider to be very
interesting: Multiply any 4 consecutive positive whole numbers and the
result will always be 1 less than a square number.  For example,
5*6*7*8 = 1680, which is 1 less than 1681, which is 41*41.  Isn't that
neat?

Jason

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Re: The seven step-Mathematical preliminaries

2009-06-04 Thread Brent Meeker

I've never seen an ultrafinitist definition of  the natural numbers.  
The usual definition via Peano's axioms obviously rules out there being 
a largest number.  I would suppose that an ultrafinitist definition of 
the natural numbers would be something like seen in a computer (which is 
necessarily finite). The successor operation would be defined such that 
Successor (Biggest) = 0 or -Biggest.

Brent

Quentin Anciaux wrote:
 If you are ultrafinitist then by definition the set N does not
 exist... (nor any infinite set countably or not).

 If you pose the assumption of a biggest number for N, you come to a
 contradiction because you use the successor operation which cannot
 admit a biggest number.(because N is well ordered any successor is
 strictly bigger and the successor operation is always valid *by
 definition of the operation*)

 So either the set N does not exists in which case it makes no sense to
 talk about the biggest number in N, or the set N does indeed exists
 and it makes no sense to talk about the biggest number in N (while it
 makes sense to talk about a number which is strictly bigger than any
 natural number).

 To come back to the proof by contradiction you gave, the assumption
 (2) which is that BIGGEST+1 is in N, is completely defined by the mere
 existence of BIGGEST. If BIGGEST exists and well defined it entails
 that BIGGEST+1 is not in N (but this invalidate the successor
 operation and hence the mere existence of N). If BIGGEST in contrary
 does not exist (as such, means it is not the biggest) then BIGGEST+1
 is in N by definition of N.

 Regards,
 Quentin

 2009/6/4 Torgny Tholerus tor...@dsv.su.se:
   
 Brian Tenneson skrev:
 
 How do you know that there is no biggest number?  Have you examined all
 the natural numbers?  How do you prove that there is no biggest number?



 
 In my opinion those are excellent questions.  I will attempt to answer
 them.  The intended audience of my answer is everyone, so please forgive
 me if I say something you already know.

 Firstly, no one has or can examine all the natural numbers.  By that I
 mean no human.  Maybe there is an omniscient machine (or a maximally
 knowledgeable in some paraconsistent way)  who can examine all numbers
 but that is definitely putting the cart before the horse.

 Secondly, the question boils down to a difference in philosophy:
 mathematicians would say that it is not necessary to examine all natural
 numbers.  The mathematician would argue that it suffices to examine all
 essential properties of natural numbers, rather than all natural numbers.

 There are a variety of equivalent ways to define a natural number but
 the essential features of natural numbers are that
 (a) there is an ordering on the set of natural numbers, a well
 ordering.  To say a set is well ordered entails that every =nonempty=
 subset of it has a least element.
 (b) the set of natural numbers has a least element (note that it is
 customary to either say 0 is this least element or say 1 is this least
 element--in some sense it does not matter what the starting point is)
 (c) every natural number has a natural number successor.  By successor
 of a natural number, I mean anything for which the well ordering always
 places the successor as larger than the predecessor.

 Then the set of natural numbers, N, is the set containing the least
 element (0 or 1) and every successor of the least element, and only
 successors of the least element.

 There is nothing wrong with a proof by contradiction but I think a
 forward proof might just be more convincing.

 Consider the following statement:
 Whenever S is a subset of N, S has a largest element if, and only if,
 the complement of S has a least element.

 By complement of S, I mean the set of all elements of N that are not
 elements of S.

 Before I give a longer argument, would you agree that statement is
 true?  One can actually be arbitrarily explicit: M is the largest
 element of S if, and only if, the successor of M is the least element of
 the compliment of S.

   
 I do not agree that statement is true.  Because if you call the Biggest
 natural number B, then you can describe N as = {1, 2, 3, ..., B}.  If
 you take the complement of N you will get the empty set.  This set have
 no least element, but still N has a biggest element.

 In your statement you are presupposing that N has no biggest element,
 and from that axiom you can trivially deduce that there is no biggest
 element.

 --
 Torgny Tholerus

 



   


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Re: The seven step-Mathematical preliminaries

2009-06-04 Thread Brent Meeker

Torgny Tholerus wrote:
 Brian Tenneson skrev:
   
 This is a denial of the axiom of infinity.  I think a foundational set 
 theorist might agree that it is impossible to -construct- an infinite 
 set from scratch which is why they use the axiom of infinity.
 People are free to deny axioms, of course, though the result will not 
 be like ZFC set theory.  The denial of axiom of foundation is one I've 
 come across; I've never met anyone who denies the axiom of infinity.

 For me it is strange that the following statement is false: every 
 natural number has a natural number successor.  To me it seems quite 
 arbitrary for the ultrafinitist's statement: every natural number has 
 a natural number successor UNTIL we reach some natural number which 
 does not have a natural number successor.  I'm left wondering what the 
 largest ultrafinist's number is.
 

 It is impossible to lock a box, and quickly throw the key inside the box 
 before you lock it.
 It is impossible to create a set and put the set itself inside the set, 
 i.e. no set can contain itself.
 It is impossible to create a set where the successor of every element is 
 inside the set, there must always be an element where the successor of 
 that element is outside the set.
   

Depends on how you define successor.

Brent

 What the largest number is depends on how you define natural number.  
 One possible definition is that N contains all explicit numbers 
 expressed by a human being, or will be expressed by a human being in the 
 future.  Amongst all those explicit numbers there will be one that is 
 the largest.  But this largest number is not an explicit number.

   


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Re: The seven step-Mathematical preliminaries

2009-06-04 Thread Bruno Marchal


On 04 Jun 2009, at 15:40, Brian Tenneson wrote:

 This is a denial of the axiom of infinity.  I think a foundational  
 set theorist might agree that it is impossible to -construct- an  
 infinite set from scratch which is why they use the axiom of infinity.
 People are free to deny axioms, of course, though the result will  
 not be like ZFC set theory.  The denial of axiom of foundation is  
 one I've come across; I've never met anyone who denies the axiom of  
 infinity.

Among mathematicians nobody denies the axiom of infinity, but many  
philosopher of mathematics are attracted by finitism.
But Torgny is ultrafinitist. That is much rare. he denies the  
existence of natural numbers above some rather putative biggest  
natural number.




 For me it is strange that the following statement is false: every  
 natural number has a natural number successor.

I thought he would have said this, and accepted that the successor of  
its N is equal to N+1. Nut in a reply he says that N+1 exists but is  
not a natural number, which I think should not be consistent.




 To me it seems quite arbitrary for the ultrafinitist's statement:  
 every natural number has a natural number successor UNTIL we reach  
 some natural number which does not have a natural number successor.   
 I'm left wondering what the largest ultrafinist's number is.

It cannot be a constructive object. It is a number which is so big  
that if you add 1 to it, the everything explodes!
I dunno. I still suspect that ultrafinitism in math cannot be  
consistent, unlike the many variate form of finitism. Comp is arguably  
a form of finitism at the ontological level, yet an ultra-infinitism,  
if I can say, at the epistemological level.

Bruno

http://iridia.ulb.ac.be/~marchal/




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Re: The seven step-Mathematical preliminaries

2009-06-04 Thread Jason Resch

Torngy,

How many numbers do you think exist between 0 and 1?  Certainly not
only the ones we define, for then there would be a different quantity
of numbers between 1 and 2, or 2 and 3.

Jason

On Thu, Jun 4, 2009 at 10:27 AM, Torgny Tholerus tor...@dsv.su.se wrote:

 Brian Tenneson skrev:


 Torgny Tholerus wrote:
 It is impossible to create a set where the successor of every element is
 inside the set, there must always be an element where the successor of
 that element is outside the set.

 I disagree.  Can you prove this?
 Once again, I think the debate ultimately is about whether or not to
 adopt the axiom of infinity.
 I think everyone can agree without that axiom, you cannot build or
 construct an infinite set.
 There's nothing right or wrong with adopting any axioms.  What results
 is either interesting or not, relevant or not.

 How do you handle the Russell paradox with the set of all sets that does
 not contain itself?  Does that set contain itself or not?

 My answer is that that set does not contain itself, because no set can
 contain itself.  So the set of all sets that does not contain itself, is
 the same as the set of all sets.  And that set does not contain itself.
 This set is a set, but it does not contain itself.  It is exactly the
 same with the natural numbers, BIGGEST+1 is a natural number, but it
 does not belong to the set of all natural numbers.  The set of all sets
 is a set, but it does not belong to the set of all sets.


 What the largest number is depends on how you define natural number.
 One possible definition is that N contains all explicit numbers
 expressed by a human being, or will be expressed by a human being in the
 future.  Amongst all those explicit numbers there will be one that is
 the largest.  But this largest number is not an explicit number.


 This raises a deeper question which is this: is mathematics dependent
 on humanity or is mathematics independent of humanity?
 I wonder what would happen to that human being who finally expresses
 the largest number in the future.  What happens to him when he wakes
 up the next day and considers adding one to yesterday's number?

 This is no problem.  If he adds one to the explicit number he expressed
 yesterday, then this new number is an explicit number, and the number
 expressed yesterday was not the largest number.  Both 17 and 17+1 are
 explicit numbers.

 --
 Torgny Tholerus

 


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Re: The seven step-Mathematical preliminaries 2

2009-06-04 Thread Bruno Marchal
Hi Kim,


On 04 Jun 2009, at 14:28, kimjo...@ozemail.com.au wrote:



 OK - I find this quite mind-blowing; probably because I now  
 understand it for the first
 time in my life. So how did it get this rather ridiculous name of  
 square root? What's it
 called in French?

Racine carrée. Literally square root.

It comes from the fact that in elementary geometry the surface or area  
of a square which sides have length x, is given by x*x, also written  
x^2, which is then called the  square of x. Taking the square root  
of a number, consists in doing the inverse of taking the square of a  
number. It consists in finding the length of a square knowing its area.

Mathematician and especially logician *can* use arbitrary vocabulary.  
It is the essence of the axiomatic method in pure mathematics that  
what is conveying does not depend on the term which are used. Hilbert  
said once that he could have use the term glass of bear instead of  
line in his work in geometry.



 A = {x such that x is even and smaller than 100}  = {x ⎮ x is even  
  x
 special character, abbreviating such that, and I hope it goes  
 through the mail.


 Just an upright line? It comes through as that. I can't seem to get  
 this symbol happening so I will
 use such that

Yes, such that is abbreviated by an upright line. Sometimes also by  
a half circle followed by a little line, but I don't find it on my  
palette!










 If not I will use such that, or s.t., or things like that.The  
 expression {x ⎮ x is even} is
 literally read as:  the set of objects x, (or number x if we are in  
 a context where we talk
 about numbers) such that x is even.

 Exercise 1: Could you define in intension the following infinite  
 set C = {101, 103, 105,
 ...}C = ?


 C = {x such that x is odd and x  101}


Correct.





 Exercise 2: I will say that a natural number is a multiple of 4 if  
 it can be written as 4*y,
 for some y. For example 0 is a multiple of 4, (0 = 4*0), but also  
 28, 400, 404, ...  Could
 you define in extension the following set D = {x ⎮ x  10 and x is  
 a multiple of 4}?

 D = 4*x where x = 0 but also { 1, 2, 3, 4, 8 }


Hmm...
Marty made a similar error. D is a set. May be you wanted to say:

D = {4*x where x = 0 but also { 1, 2, 3, 4, 8 }}. But this does not  
make much sense. Even if I try to imagine favorably some meaning, I  
would say that it would mean that D is the set of numbers having the  
shape 4*x (that is capable of being written as equal to 4*x for some  
x), and such that x belongs to {0, 1, 2, 3, 4, 8}.
A proper way to describe that set would be

D = {y such that y = 4x and x belongs-to {0, 1, 2, 3, 4, 8}}.

But that would makes D = {0, 4, 8, 12, 32}.

The set D = {x ⎮ x  10 and x is a multiple of 4} is just, in  
english, the set of natural numbers which are little than 10 and which  
are a multiple of 4. The only numbers which are little than 10, and  
multiple of 4 are the numbers 0, 4, and 8.  D = {0, 4, 8}.








 I now realise I am doomed for the next set of exercises because I  
 cannot get to the special
 symbols required (yet). As I am adding Internet Phone to my system,  
 I am currently using an
 ancient Mac without the correct symbol pallette while somebody  
 spends a few days to flip a single
 switch...as soon as I can get back to my regular machine I will  
 complete the rest.


Take it easy. No problem.





 In the meantime I am enjoying the N+1 disagreement - how refreshing  
 it is to see that classical
 mathematics remains somewhat controversial!



The term is a bit too strong. It is a bit like if I told you that I  
am Napoleon, and you conclude that the question of the death of  
Napoleon is still controversial. I exaggerate a little bit to make my  
point, but I know only two ultrafinitists *in math*, and I have never  
understood what they mean by number, nor did I ever met someone  
understanding them.

What makes just a little bit more sense (and I guess that's what  
Torgny really is) is being ultrafinitist *in physics*, and being  
physicalist. You postulate there is a physical universe, made of a  
finite number of particles, occupying a finite volume in space-time,  
etc. Everything is finite, including the everything.
Then  by using the unintelligible identity thesis (and thus  
reintroducing the mind-body problem), you can prevent the comp white  
rabbits inflation. Like all form of materialism, this leads to  
eliminating the person soon or later (by the unsolvability of the mind- 
body problem by finite means). Ultrafinitist physicalism eliminates  
also mathematics and all immaterial notions, including all universal  
machines. Brrr...

The real question is do *you* think that there is a biggest natural  
number? Just tell me at once, because if you really believe that  
there is a biggest natural number, I have no more clues at all how you  
could believe in any of computer science nor UDA.

Remember that Thorgny pretends also to be a zombie. It has already  

RE: The seven step-Mathematical preliminaries

2009-06-04 Thread Jesse Mazer



 Date: Thu, 4 Jun 2009 15:23:04 +0200
 From: tor...@dsv.su.se
 To: everything-list@googlegroups.com
 Subject: Re: The seven step-Mathematical preliminaries
 
 
 Quentin Anciaux skrev:
 If you are ultrafinitist then by definition the set N does not
 exist... (nor any infinite set countably or not).
   
 
 All sets are finite.  It it (logically) impossible to construct an 
 infinite set.
What do you mean by construct? Do we have to actually write out or otherwise 
physically embody every element? Why can't we think of a particular set as 
just a type of rule that, given any possible element, tells you whether or not 
that element is a member or not? In this case there's no reason the rule 
couldn't be such that there are an infinite number of possible inputs that the 
rule would identify as valid members.
 
 You can construct the set N of all natural numbers.  But that set must 
 be finite.  What the set N contains depends on how you have defined 
 natural number.

How do *you* define natural number, if not according to the usual recursive 
rule that 1 is a natural number and that if N is a natural number, N+1 is also 
a natural number? Hopefully you agree that there can be no finite upper limit 
on possible inputs you could give this rule that the rule would identify as 
valid natural numbers? I think your claim would be that simply describing the 
rule is not a valid way of constructing the set of natural numbers. If so, 
why *isn't* it valid? *You* may prefer to adopt the rule that we should only be 
allowed to call something a set if we can actually write out every member, 
but do you have any argument as to why it's invalid for the rest of us to 
define sets simply as general rules that decide whether a given input is a 
member or not? This seems more like an aesthetic preference on your part rather 
than something you have a compelling philosophical argument for (or at least if 
you have such an argument you haven't provided it).
Jesse
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