Re: [PHP-DB] Compatibility with PHP and MySQL

2011-09-05 Thread Chris Stinemetz
On Mon, Sep 5, 2011 at 3:49 PM, Gabriel Solberg solbergdes...@gmail.com wrote:
 Will installing the most recent XMAPP to install PHP MySQL and Apache to
 create a development environment on my local computer affect how everything
 runs when I upload it to the server (My web host 1and1.com runs php 5.0 and
 MySQL 5.0) thanks


You may notice differences if your php.ini and http.conf files are not
the same in both development and production environments. I would
compare them first.

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[PHP-DB] foreign key

2011-08-09 Thread Chris Stinemetz
Okay. I am pretty new to mysql so this may seem like a ridiculous
question to some people.

I am trying to use a LEFT JOIN query, but the results I am finding
unusual. For every record occurrence there is for the query, the
results are duplicated by that amount.

So if there are 3 records from the query results, then the output is 3
times what I expect.. if that makes sense.

From what I have researched so far. I believe I may need to add a
foreign key to build the relations between the two tables.

Based on the query can any tell me the correct way of adding the
foreign key if ,in fact, that is what I need?

I can provide table structures and information if necessary.

The query is:

$posts_sql = SELECT
store_subject,
store_comments, 
store_date,
store_tptest,   
store_by,
users.user_id,
users.user_name,
users.first_name,
users.last_name
FROM
stores
LEFT JOIN
users
ON
stores.store_by = users.user_id
WHERE
stores.store_subject = ' . mysql_real_escape_string($_GET['id']).'
ORDER BY
stores.store_date DESC ;

The query dump is:

SELECT store_subject, store_comments, store_date, store_tptest,
store_by, users.user_id, users.user_name, users.first_name,
users.last_name FROM stores LEFT JOIN users ON stores.store_by =
users.user_id WHERE stores.store_subject = 'Noland Park Plaza 3509 S.
Noland Rd' ORDER BY stores.store_date DESC

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Re: [PHP-DB] foreign key

2011-08-09 Thread Chris Stinemetz

 Is users.user_id unique?


yes it is.

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Re: [PHP-DB] foreign key

2011-08-09 Thread Chris Stinemetz


 What does your result look like? Hard to say what the problem is
 without seeing the result.


I am echoing the query and printing the get array just for debugging
purposes, but below you can see how it is repeating its' self.

Thank you



Array
(
[id] = Bella Roe 4980 Roe Blvd
)

Bella Roe 4980 Roe BlvdSELECT stores.store_subject, stores.store_comments,
stores.store_date, stores.store_tptest, stores.store_by, users.user_id,
users.user_name, users.first_name, users.last_name FROM stores LEFT JOIN
users ON stores.store_by = users.user_id WHERE stores.store_subject = 'Bella
Roe 4980 Roe Blvd' ORDER BY stores.store_date DESC Chris Stinemetz
08-09-2011 02:08PM600kbps-3.8mbps
testChris Stinemetz
08-09-2011 02:07PM0-250kbps
test1Reply:


Bella Roe 4980 Roe BlvdSELECT stores.store_subject, stores.store_comments,
stores.store_date, stores.store_tptest, stores.store_by, users.user_id,
users.user_name, users.first_name, users.last_name FROM stores LEFT JOIN
users ON stores.store_by = users.user_id WHERE stores.store_subject = 'Bella
Roe 4980 Roe Blvd' ORDER BY stores.store_date DESC Chris Stinemetz
08-09-2011 02:08PM600kbps-3.8mbps
testChris Stinemetz
08-09-2011 02:07PM0-250kbps
test1Reply:


Re: [PHP-DB] foreign key

2011-08-09 Thread Chris Stinemetz
Okay. I just validated it is not in the left join query, but in my php. I
was able to build the correct relations.

Does anyone see any think in the php code below that may cause duplicate
table rows?

Thank you all.

?php
//store.php
include_once 'includes/connect.php';
include_once 'includes/header.php';
print(pre.print_r($_GET,true)./pre);
$sql = SELECT store_id, store_subject, store_comments, store_date,
store_tptest, store_by
 FROM stores
 WHERE store_subject = ' . mysql_real_escape_string($_GET['id']).';
$result = mysql_query($sql);
if(!$result)
{
 echo 'The latest post could not be displayed, please try again later.';
 //echo mysql_error(); //debugging purposes, uncomment when needed

}
else
{
 if(mysql_num_rows($result) == 0)
 {
  echo 'This store visit doesnprime;t exist.';
 }
 else
 {
  while($row = mysql_fetch_assoc($result))
  {
   //display post data
   echo 'table class=table1 border=1
 tr
  th colspan=2' . $row['store_subject'] . '/th
 /tr';

   //fetch the posts from the database
   $posts_sql = SELECT
  stores.store_subject,
  stores.store_comments,
  stores.store_date,
  stores.store_tptest,
  stores.store_by,
  users.user_id,
  users.user_name,
  users.first_name,
  users.last_name
 FROM
  stores
 LEFT JOIN
  users
 ON
  stores.store_by = users.user_id
 WHERE
  stores.store_subject = ' . mysql_real_escape_string($_GET['id']).'
 ORDER BY
  stores.store_date DESC ;

  //echo $posts_sql;

   $posts_result = mysql_query($posts_sql);

   if(!$posts_result)
   {
echo 'trtdThe posts could not be displayed, please try again
later./tr/td/table';
//echo mysql_error(); //debugging purposes, uncomment when needed
   }
   else
   {

while($posts_row = mysql_fetch_assoc($posts_result))
{
 echo 'tr class=topic-post
   td class=user-post' . $posts_row['first_name'] . ' ' .
$posts_row['last_name'] . 'br/' . date('m-d-Y h:iA',
strtotime($posts_row['store_date'])) . '/td
   td class=post-content' . $posts_row['store_tptest'] . 'br/' .
htmlentities(stripslashes($posts_row['store_comments'])) . '/td
/tr';
}
   }

   if(!$_SESSION['signed_in'])
   {
echo 'trtd colspan=2You must be a href=signin.phpsigned in/a
to reply. You can also a href=signup.phpsign up/a for an account.';
   }
   else
   {
//show reply box
echo 'trtd colspan=2h2Reply:/h2br /
 form method=post action=reply.php?id=' . $row['store_id'] . '
  textarea name=reply-content/textareabr /br /
  input type=submit value=Submit reply /
 /form/td/tr';
   }

   //finish the table
   echo '/table';
  }
 }
}
include_once 'includes/footer.php';
?


[PHP-DB] Re: php-db foreign key

2011-08-09 Thread Chris Stinemetz
On Tue, Aug 9, 2011 at 2:55 PM, Frank Flynn fr...@declan.com wrote:

 You already have a foreign key, that is stores.store_by references
users.user_id.  You might not have declared it (which is OK) but if that is
the key you want that is fine.
 I suspect you are seeing an inadvertent Cartesian product.  The way you
have written this query you will get one row from the stores table for each
row in the users table where a store_by = user_id - and because you said
LEFT JOIN you will get one row from the stores table even if there are no
matching rows in the users table.
 So you say you get 3 x the rows you're expecting; are there 3 users that
match that store_by?


No there is only 1 user that match the sotre_by. If the query is not written
correctly do you mind trying to show me how to correctly right it?

When I dump the query and run it in console I get the results I want. Not
sure what I am doing wrong.

mysql SELECT stores.store_subject, stores.store_comments,
stores.store_date, stores.store_tptest, stores.store_by, user
s.user_id, users.user_name, users.first_name, users.last_name FROM stores
LEFT JOIN users ON stores.store_by = users.use
r_id WHERE stores.store_subject = 'Bella Roe 4980 Roe Blvd' ORDER BY
stores.store_date DESC ;
+-++-+-+--+-+---
-++---+
| store_subject   | store_comments | store_date  |
store_tptest| store_by | user_id | user_name
| first_name | last_name |
+-++-+-+--+-+---
-++---+
| Bella Roe 4980 Roe Blvd | test   | 2011-08-09 14:08:05 |
600kbps-3.8mbps |1 |   1 | chrisstinemetz
| Chris  | Stinemetz |
| Bella Roe 4980 Roe Blvd | test1  | 2011-08-09 14:07:49 | 0-250kbps
  |1 |   1 | chrisstinemetz
| Chris  | Stinemetz |
+-++-+-+--+-+---
-++---+
2 rows in set (0.00 sec)


Re: [PHP-DB] Re: php-db foreign key

2011-08-09 Thread Chris Stinemetz

 Your php code had more than one query running (one inside the other).
 It's the outer query that runs twice, not the inner one returning
 double the results



Thanks Peter,

Do you have any suggestions on how to fix this?

Thank you,

Chris

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Re: [PHP-DB] Re: php-db foreign key

2011-08-09 Thread Chris Stinemetz

 Yes, debug your code and figure out why it's looping twice instead.
 For instance, try the other query in the mysql console.


Thank you! It was the first query. I put a LIMIT 1 on it and now it is
working correctly. I appreciate your help!

Thank you,

Chris

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[PHP-DB] Left Join

2011-08-07 Thread Chris Stinemetz
I am tyring to build a query that will take the most recent
stores.store_date column then join it with store_list.store_name where
store_list.store_name and
stores.store_subject match then return the most recent stores.store_date.
I am guessing this will require some sort of join. I have been tyring to
figure it
out but have had no luck.
Any help is greatly apprciated.
Thank you.

mysql select * from stores;
+--+-++-+---+--+-+--
---+
| store_id | store_subject   | store_type | store_date  | store_mar
| store_by | store_tptest| store_comment
s  |
+--+-++-+---+--+-+--
---+
|   78 | Bella Roe   | corporate  | 2011-06-28 15:01:02 | 0
|1 | |
  |
|   79 | Bella   | corporate  | 2011-08-06 08:48:26 | 0
|1 | 600kbps-3.8mbps | test
  |
|   80 | Brittney~2120   | corporate  | 2011-08-06 08:48:50 | 1
|1 | 600kbps-3.8mbps | should post t
o Wichita! |
|   81 | Motor   | premier| 2011-08-06 14:52:55 | 1
|1 | 600kbps-3.8mbps | test
  |
|   82 | Liberty | corporate  | 2011-08-06 14:54:41 | 0
|1 | 0-250kbps   | test
  |
|   83 | Seneca~3165 | corporate  | 2011-08-06 14:58:47 | 0
|1 | 600kbps-3.8mbps | test
  |
|   84 | Liberty | corporate  | 2011-08-06 14:59:32 | 0
|1 | 400-600kbps | test
  |
|   85 | Brittney~2120   | corporate  | 2011-08-06 15:00:43 | 0
|1 | 600kbps-3.8mbps | test
  |
|   86 | Liberty | corporate  | 2011-08-06 15:01:11 | 0
|1 | 300-400kbps | test
  |
|   87 | Brittney~2120   | corporate  | 2011-08-06 15:11:06 | 0
|1 | 250-300kbps | test
  |
|   88 | Brittney~2120   | corporate  | 2011-08-06 15:23:53 | 1
|1 | 600kbps-3.8mbps | test
  |
|   89 | Bella   | corporate  | 2011-08-06 15:31:49 | 0
|1 | 600kbps-3.8mbps | test
  |
|   90 | Cleartalk~10221 | premier| 2011-08-06 15:32:54 | 0
|1 | 250-300kbps | test
  |
|   91 | Chit| premier| 2011-08-06 15:33:50 | 1
|1 | 250-300kbps | test
  |
|   92 | || 2011-08-06 15:34:21 | 2
|1 | 300-400kbps | test
  |
|   93 | Bella   | corporate  | 2011-08-07 11:26:13 | 0
|1 | 600kbps-3.8mbps | test
  |
+--+-++-+---+--+-+--
---+
16 rows in set (0.00 sec)
mysql

mysql select * from store_list LIMIT 15;'
++---+++-+---+
| id | market_prefix | store_name | store_type |
market_name | id_market |
++---+++-+---+
|  1 | MCI   | Bella Roe~4980 Roe Blvd| Corporate  |
Kansas City | 0 |
|  2 | MCI   | Cleartalk~4635 Shawnee Dr  | Premier|
Kansas City | 0 |
|  3 | MCI   | Cleartalk~3612 State Avenue| Premier|
Kansas City | 0 |
|  4 | MCI   | Endless Wireless~1620 Central Avenue   | Premier|
Kansas City | 0 |
|  5 | MCI   | Get Wireless~840 Minnesota | Premier|
Kansas City | 0 |
|  6 | MCI   | Ring Ring Wireless~7559 State Avenue   | Premier|
Kansas City | 0 |
|  7 | MCI   | Cleartalk~1212 Sante Fe| Premier|
Kansas City | 0 |
|  8 | MCI   | Cleartalk~10221 W 75th Street  | Premier|
Kansas City | 0 |
|  9 | MCI   | Free Talk~10830 Shawnee Mission Pkwy   | Premier|
Kansas City | 0 |
| 10 | MCI   | Loma Vista~8712 Blue Ridge Blvd| Corporate  |
Kansas City | 0 |
| 11 | MCI   | Ring Ring Wireless~25 W. 39th Street   | Premier|
Kansas City | 0 |
| 12 | MCI   | Ring Ring Wireless~3039 Prospect Ave   | Premier|
Kansas City | 0 |
| 13 | MCI   | Ring Ring Wireless~1201 E Linwood Blvd | Premier|
Kansas City | 0 |
| 14 | MCI   | Ring Ring Wireless~4314 Rainbow Blvd   | Premier|
Kansas City | 0 |
| 15 | MCI   | Ring Ring Wireless~7445 Prospect Ave.  | Premier|
Kansas City | 0 |
++---+++-+---+
15 rows in set (0.00 sec)


Re: [PHP-DB] Left Join

2011-08-07 Thread Chris Stinemetz
On Sun, Aug 7, 2011 at 3:00 PM, Peter Lind peter.e.l...@gmail.com wrote:

 Maybe it's just me, but I can't see anything that would work as

foreign key for you to join on - neither table seems to have a foreign
 key


 Sorry for my ignorance. How do I create the foreign key? The two columns
from each table that have a similar relationship are stores.store_mar and
store_list.id_market. Once the foreign key is build what would be the
correct syntax to achieve my query?

Thank you very much,

  Chris






[PHP-DB] Insert query error

2011-08-05 Thread Chris Stinemetz
I am getting the following error trying to run the below query. Any
suggestions on what I am doing wrong?

Thank you,

Something went wrong while inserting your store visitCannot add or
update a child row: a foreign key constraint fails (`store`.`posts`,
CONSTRAINT `posts_ibfk_1` FOREIGN KEY (`post_store`) REFERENCES
`stores` (`store_id`) ON DELETE CASCADE ON UPDATE CASCADE)

$sql = INSERT INTO
posts(market, type, post_store, post_tptest, post_content, post_by, post_date)
VALUES(' . mysql_real_escape_string($_POST['market']) . ',
' . mysql_real_escape_string($_POST['type']) . ',
' . mysql_real_escape_string($_POST['post_store']) . ',   

' . sha1($_POST['post_tptest']) . ',
' . mysql_real_escape_string($_POST['post_content']) . ',
  . $_SESSION['user_id'] . ,
 NOW());

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[PHP-DB] cascading select

2011-07-14 Thread Chris Stinemetz
I am trying to create a cascading seletct with 3 menu choices.
For some reason my third select menu is not populating. It does not
seem like my ajax is correctly sending $_post values to the final
query in my PHP class I built.
By the time I make it to the final (third) select menu there are no choices.

Hopefully someone can find something I missed in the following code snippits.

Any help is greatly appreciated.

Please excuse the incorrect indentions. For some reason gmail changes it.

Thanks,

Chris

ajax code...

   script
   $(document).ready(function(){
   $(select#type).attr(disabled,disabled);
   $(select#store).attr(disabled,disabled);
   $(select#market).change(function(){
   $(select#type).attr(disabled,disabled);
   $(select#type).html(optionplease wait.../option);
   var id = $(select#market option:selected).attr('value');
   $.post(select_type.php, {id:id}, function(data){
   $(select#type).removeAttr(disabled);
   $(select#type).html(data);
   });
   });

   $(select#type).change(function(){
   $(select#store).attr(disabled,disabled);
   $(select#store).html(optionplease
wait.../option);
   var id = $(select#type option:selected).attr('value');
   $.post(select_store.php, {id:id}, function(data){
   $(select#store).removeAttr(disabled);
   $(select#store).html(data);
   });
   });




   $(form#select_form).submit(function(){
   var market = $(select#market option:selected).attr('value');
   var type = $(select#type option:selected).attr('value');
   var store = $(select#store
option:selected).attr('value');
   if(market0  type0  store0)
   {
   var market = $(select#market option:selected).html();
   var type = $(select#type
option:selected).html();
   var store = $(select#store
option:selected).html();
   $(#result).html('your choices were: '+market +' ,
'+type +' and '+store);
   }
   else
   {
   $(#result).html(you must choose three options!);
   }
   return false;
   });
   });
   /script


php class for populating select menus

?php
class SelectList
{
   protected $conn;
   public function __construct()
   {
   $this-DbConnect();
   }
   protected function DbConnect()
   {
   include db_config.php;
   $this-conn =
mysql_connect($host,$user,$password) OR die(Unable to connect to the
database);
   mysql_select_db($db,$this-conn) OR die(can
not select the database $db);
   return TRUE;
   }
   public function ShowMarket()
   {
   $sql = SELECT DISTINCT id_markets FROM store_list;
   $res = mysql_query($sql,$this-conn);
   $market = 'option value=0market.../option';
   while($row = mysql_fetch_array($res))
   {
   $market .= 'option value=' .
$row['id'] . '' . $row['id_markets'] . '/option';
   }
   return $market;
   }

   public function ShowType()
   {
   $sql = SELECT DISTINCT store_type FROM store_list;
   $res = mysql_query($sql,$this-conn);
   $type = 'option value=0store type.../option';
   while($row = mysql_fetch_array($res))
   {
   $type .= 'option value=' . $row['id']
. '' . $row['store_type'] . '/option';
   }
   return $type;
   }

   public function ShowStore()
   {
   $sql = SELECT store_name FROM store_list WHERE
id_markets=$_POST[id] AND store_type=$_POST[id];
   $res = mysql_query($sql,$this-conn);
   $Store = 'option value=0stores.../option';
   while($row = mysql_fetch_array($res))
   {
   $Store .= 'option value=' .
$row['id'] . '' . $row['store_name'] . '/option';
   }
   return $Store;
   }
}

$opt = new SelectList();

?

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Re: [PHP-DB] Re: radio form submission

2011-06-24 Thread Chris Stinemetz
Thanks everyone.

 If there is no purpose, I would make the values of the inputs the values you
 want to store in your database.
 Muuch easier..


So I am trying to keep this simple and just assign the value with the
radio button and then insert it into mysql database, but with the
following code I am getting the mysql error: Unknown column '250kbps'
in 'field list' when I choose the first radio button.

I think it has to do with the value being a string, but I haven't been
able to figure out the fix.

Thanks everyone for your help in accomplishing one thing with many
differnt techniques. It is greatly appreciated.

Chris

 Form 

echo 'form method=post action=
Store name: input type=text 
name=store_subject /br /br /
Market:';

echo 'select name=store_mar';
while($row = mysql_fetch_assoc($result))
{
echo 'option value=' . 
$row['mar_id'] . '' .
$row['mar_name'] . '/option';
}
echo '/selectbr /br /';   

echo 'Broadband speed test results: br /br /
0-250kbpsinput type=radio 
name=post_tptest value=0-250kbps /|
250-300kbpsinput type=radio 
name=post_tptest value=250-300kbps /|
300-400kbpsinput type=radio 
name=post_tptest value=300-400kbps /|
400-600kbpsinput type=radio 
name=post_tptest value=400-600kbps /|
600kbps-3.8mbpsinput type=radio 
name=post_tptest
value=600kbps-3.8mbps /br /br /
Store visit details: br /br /
textarea name=post_content 
//textareabr /br /
input type=submit value=Add a store 
visit /
 /form';
}
}
}


 Insert Code 

$sql = INSERT INTO
posts(post_content, 

  post_date,
  post_tptest,
  post_store,
  post_by)
VALUES
(' . 
mysql_real_escape_string($_POST['post_content']) . ',
  NOW(),
   . 
$_POST['post_tptest'] . ,
   . $storeid 
. ,
   . 
$_SESSION['user_id'] . 
);
$result = mysql_query($sql);

if(!$result)
{
//something went wrong, display the 
error
echo 'An error occured while inserting 
your post. Please try
again later.br /br /' . mysql_error();
$sql = ROLLBACK;;
$result = mysql_query($sql);
}
else
{
$sql = COMMIT;;
$result = mysql_query($sql);

//after a lot of work, the query 
succeeded!
echo 'You have succesfully created a 
href=store.php?id='.
$storeid . 'your new store visit/a.';
}
}
}
}
}

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[PHP-DB] radio form submission

2011-06-23 Thread Chris Stinemetz
So far I am good on creating the form and  submitting it to mysql
database and calling the submitting value from a different script.

My question is: How can I make it so when a user selects radio option
value 1 it will then be displayed as 0-250kbps when I call it the
value in the bottom script?

forgive my indention. Gmail messes it up.


 My Form 


echo 'form method=post action=
Store name: input type=text 
name=store_subject /br /br /
Market:';

echo 'select name=store_mar';
while($row = mysql_fetch_assoc($result))
{
echo 'option value=' . 
$row['mar_id'] . '' .
$row['mar_name'] . '/option';
}
echo '/selectbr /br /';   

echo 'Broadband speed test results: br /br /
0-250kbpsinput type=radio 
name=post_tptest value=1 /|
250-300kbpsinput type=radio 
name=post_tptest value=2 /|
300-400kbpsinput type=radio 
name=post_tptest value=3 /|
400-600kbpsinput type=radio 
name=post_tptest value=4 /|
600kbps-3.8mbpsinput type=radio 
name=post_tptest value=5
/br /br /
Store visit details: br /br /
textarea name=post_content 
//textareabr /br /
input type=submit value=Add a store 
visit /
 /form';

 My display script 

$posts_sql = SELECT
posts.post_store,
posts.post_content,
posts.post_tptest,
posts.post_date,
posts.post_by,
users.user_id,
users.user_name,
users.first_name,
users.last_name
FROM
posts
LEFT JOIN
users
ON
posts.post_by = users.user_id
WHERE
posts.post_store =  . 
mysql_real_escape_string($_GET['id']) . 
ORDER BY
posts.post_date DESC ; 


$posts_result = mysql_query($posts_sql);

if(!$posts_result)
{
echo 'trtdThe posts could not be displayed, 
please try again
later./tr/td/table';
}
else
{

while($posts_row = 
mysql_fetch_assoc($posts_result))
{
echo 'tr class=topic-post
td class=user-post' 
. $posts_row['first_name'] . ' ' .
$posts_row['last_name'] . 'br/' . date('m-d-Y h:iA',
strtotime($posts_row['post_date'])) . '/td
td 
class=post-content' . $posts_row['post_tptest'] .
'br/' . htmlentities(stripslashes($posts_row['post_content'])) .
'/td
  /tr';
}
}

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Re: [PHP-DB] radio form submission

2011-06-23 Thread Chris Stinemetz
On Thu, Jun 23, 2011 at 2:49 PM, Daniel P. Brown
daniel.br...@parasane.net wrote:
 On Thu, Jun 23, 2011 at 15:46, Chris Stinemetz chrisstinem...@gmail.com 
 wrote:

    Use an if or a switch.  For example:


 I think your suggestions are exactly what I am looking for. I am not
 sure exactly where to place it. Do I insert it after the query
 statment?

    During your while() loop.  This line here:

        td class=post-content' . $posts_row['post_tptest'] .

    If you convert it to a function as Karl suggested, you could do
 something like this:

        td class=post-content' . getSpeed($posts_row['post_tptest']) .


I must be missing something. I am just getting a blank page. Your help
is greatly apprecieated.

The function and query statement is:

function getSpeed($val) {
if($val != 'undefined') {
switch ($val){
   case 1:
$post_tptest = 0-250kbps;
break;
   case 2:
$post_tptest = 250-300kbps;
break;
   case 3:
$post_tptest = 300-400kbps;
break;
   case 4:
$post_tptest = 400-600kbps;
break;
   case 5:
$post_tptest = 600kbps-3.8mbps;
break;
   default:
$post_tptest = Speed Undetected; // or 0-250kbps
break;
   }
} else {
   return(Error, no speed value set);
}
}
}

$post_speed = getSpeed($post_tptest);

//fetch the posts from the database
$posts_sql = SELECT
posts.post_store,
posts.post_content,
posts.post_speed,   

posts.post_date,
posts.post_by,
users.user_id,
users.user_name,
users.first_name,
users.last_name
FROM
posts
LEFT JOIN
users
ON
posts.post_by = users.user_id
WHERE
posts.post_store =  . 
mysql_real_escape_string($_GET['id']) . 
ORDER BY
posts.post_date DESC ; 



The call:

while($posts_row = 
mysql_fetch_assoc($posts_result))
{
echo 'tr class=topic-post
td class=user-post' 
. $posts_row['first_name'] . ' ' .
$posts_row['last_name'] . 'br/' . date('m-d-Y h:iA',
strtotime($posts_row['post_date'])) . '/td
td 
class=post-content' .
getSpeed($posts_row['post_tptest']) . 'br/' .
htmlentities(stripslashes($posts_row['post_content'])) . '/td
  /tr';
}
}


Thank you!

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Re: [PHP-DB] radio form submission

2011-06-23 Thread Chris Stinemetz

    Use an if or a switch.  For example:


I think your suggestions are exactly what I am looking for. I am not
sure exactly where to place it. Do I insert it after the query
statment?

Thank you,

Chris

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[PHP-DB] ORDER BY DESC

2011-06-20 Thread Chris Stinemetz
I have the bellow sql query. What is the correct way to add ORDER BY
posts.post_date DESC

I would like to add it to the end of my query, but I am just getting a
blank page or my added query doesn't work echo:

The posts could not be displayed, please try again later.

The query is:

//fetch the posts from the database
$posts_sql = SELECT
posts.post_store,
posts.post_content,
posts.post_date,
posts.post_by,
users.user_id,
users.user_name
FROM
posts
LEFT JOIN
users
ON
posts.post_by = users.user_id
WHERE
posts.post_store =  . 
mysql_real_escape_string($_GET['id']);   



Thank you in advance for your help.

Chris

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Re: [PHP-DB] ORDER BY DESC

2011-06-20 Thread Chris Stinemetz
On Mon, Jun 20, 2011 at 3:49 PM, Karl DeSaulniers k...@designdrumm.com wrote:
 Try..

 $posts_sql = SELECT posts.post_store, posts.post_content, posts.post_date,
 posts.post_by, users.user_id, users.user_name FROM posts LEFT JOIN users ON
 osts.post_by = users.user_id WHERE posts.post_store = 
 .mysql_real_escape_string($_GET['id']). ORDER BY posts.post_date DESC;


Got it working thanks everyone who responded.

Working query:

$posts_sql = SELECT
posts.post_store,
posts.post_content,
posts.post_date,
posts.post_by,
users.user_id,
users.user_name
FROM
posts
LEFT JOIN
users
ON
posts.post_by = users.user_id
WHERE
posts.post_store =  . 
mysql_real_escape_string($_GET['id']) . 
ORDER BY
posts.post_date DESC ;

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[PHP-DB] delete message function

2011-06-13 Thread Chris Stinemetz
I created the below delete function, but it doesn't seem to be working
correctly. When I enter the correct password it get my echo Incorrect
Password Did not Delete! When I leave the password blank the message
will delete from mysql table.

Am I missing something??

Thanks in advance,

Chris

function delete_message($msg) {
extract($msg, EXTR_PREFIX_ALL, 'row');
$result = mysql_query(SELECT ID FROM mbmsgs WHERE Parent = $row_ID;);

while ($row = mysql_fetch_array($result)) {
delete_message($row);
}
mysql_query(DELETE FROM mbmsgs WHERE ID = $row_ID;);
}

$result = mysql_query(SELECT Title, Password FROM mbmsgs WHERE ID
= {$_REQUEST['Msg']};);
if (!$result) exit;
if (!mysql_num_rows($result)) exit;
extract(mysql_fetch_array($result), EXTR_PREFIX_ALL, 'msg');

if (isset($_POST['Password'])) {
if (sha1($_POST['Password']) != $msg_Password) {
echo Incorrect password did not delete!;
exit;

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[PHP-DB] Re: delete message function

2011-06-13 Thread Chris Stinemetz
On Tue, Jun 14, 2011 at 12:31 AM, Chris Stinemetz
chrisstinem...@gmail.com wrote:
 I created the below delete function, but it doesn't seem to be working
 correctly. When I enter the correct password it get my echo Incorrect
 Password Did not Delete! When I leave the password blank the message
 will delete from mysql table.

 Am I missing something??

 Thanks in advance,

 Chris

Sorry. I left out the call to the function. Below is the whole snippit
for the function and call.

function delete_message($msg) {
extract($msg, EXTR_PREFIX_ALL, 'row');
$result = mysql_query(SELECT ID FROM mbmsgs WHERE Parent = $row_ID;);

while ($row = mysql_fetch_array($result)) {
delete_message($row);
}
mysql_query(DELETE FROM mbmsgs WHERE ID = $row_ID;);
}

$result = mysql_query(SELECT Title, Password FROM mbmsgs WHERE ID
= {$_REQUEST['Msg']};);
if (!$result) exit;
if (!mysql_num_rows($result)) exit;
extract(mysql_fetch_array($result), EXTR_PREFIX_ALL, 'msg');

if (isset($_POST['Password'])) {
if (sha1($_POST['Password']) != $msg_Password) {
echo Incorrect password did not delete!;
exit;
}
$result = mysql_query(SELECT ID FROM mbmsgs WHERE Parent =
{$_POST['Msg']};);

while ($row = mysql_fetch_array($result)) {
delete_message($row);
}

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[PHP-DB] mysql_query

2011-06-06 Thread Chris Stinemetz
Hello all,

Not sure what I am doing wrong.

I have a simple form that populate the variables in a mysql query. I
know the selected values are making it to the form porcessing script
because I can echo them on the processing script as indicated below.

You Selected Cell_Sect = 1_1
You Selected Date = 03/10/11 18:15
You Selected Market = MCI

For some reason the above is all I am getting when I submit my form.

I beleive it has somthing to do with my results query below.

$result = mysql_query(select * FROM evdo WHERE Market like '%$term'
and Cell_Sect = '$cat' and Date = '$subcat' LIMIT 10);

Beow is my whole script for processing the form in case it maybe something else.

Thanks,

Chris


!doctype html public -//w3c//dtd html 3.2//en

html
?php

// database access parameters
$dbservertype='mysql';
$servername= left out for privacy;
// username and password to log onto db server
$dbusername='';
$dbpassword='';
// name of database
$dbname='pcmd';

connecttodb($servername,$dbname,$dbusername,$dbpassword);
function connecttodb($servername,$dbname,$dbuser,$dbpassword)
{
global $link;
$link=mysql_connect ($servername,$dbuser,$dbpassword);
if(!$link){
die('Could not conect: ' . mysql_error());
}
echo 'YOU ARE CONNECTED TO PCMD DATABASE';

mysql_select_db($dbname,$link) or die (could not open db.mysql_error());
}
 End of connecting to database 
?
!!DOCTYPE HTML PUBLIC '-//W3C//DTD XHTML 1.0 Transitional//EN'
'http://www.w3.org/TR/xhtml1-transitional.dtd'
head
titleDemo Multiple drop down list box for PCMD data/title
style type=text/css 
  TABLE {
 border: 1px solid #98bf21;
 border-collapse:collapse;
  }

  TH {
 border: 1px solid #98bf21;
 padding-bottom: 4px;
 padding-left: 7px:
 padding-right: 7px;
 padding-top: 5px;
 font-size: 1.2em;
 background-color:limegreen;
 color: white;
 text-align: left;
  }

  TD {
 border: 1px solid #98bf21;
 padding-bottom: 2px;
 padding-left: 7px:
 padding-right: 7px;
 padding-top: 3px;
 font-size: 1.0em;
  }

  TR.alt TD {
  background-color: #eaf2d3;

  }

/style
meta name=GENERATOR content=Arachnophilia 4.0
meta name=FORMATTER content=Arachnophilia 4.0
/head

body
?php
$cat=$_POST['cat'];
$subcat=$_POST['subcat'];
$term=$_POST['term'];

$result = mysql_query(select * FROM evdo WHERE Market like '%$term'
and Cell_Sect = '$cat' and Date = '$subcat' LIMIT 10);


$firstRow=1;
$rowNum = 0;
echo table;
while($row = mysql_fetch_assoc($result)) {
   if($firstRow == 1) {
  echo tr;

  foreach($row as $key = $value) {
  echo th . $key . /th;
  }
  echo /trtr;
  $firstRow=0;
  $rowNum++;
   }
   else {
  if(  ($rowNum++ % 2) == 1) {
 echo tr class=\alt\;
  } else {
 echo tr;
  }
   }
   foreach($row as $key = $value ) {
   echo td . $value . /td  ;
   }
   echo /tr;
}
echo /table;

echo You Selected Cell_Sect = $cat brYou Selected Date =
$subcatbrYou Selected Market = $term;


?

/body

/html

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[PHP-DB] Event Calendar tutorial

2011-05-31 Thread Chris Stinemetz
Hello all,

I am curious if anyone knows of a good tutorial to build an event calendar?

Thank you,

Chris

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[PHP-DB] PHP Delete confirmation

2011-04-28 Thread Chris Stinemetz
I have been trying to figure out how to add delete confirmation for
the bellow snippet of code. I would prefer not to use javascript. Can
anyone offer any advise on how to right the delete confirmation in
PHP?

Thank you in advance.

P.S. I apologize for the indention. For some reason gmail messes it up.

?php
// loop through results of database query, displaying them in the table
while($row = mysql_fetch_array( $result )) {

// echo out the contents of each row into a table
echo tr;
echo 'td' . $row['Name'] . '/td';
echo 'td' . $row['Date'] . '/td';   

echo 'td' . $row['StoreInfo'] . '/td';
echo 'td' . $row['Address'] . '/td';
echo 'td' . $row['Type'] . '/td';
echo 'td' . $row['EngTech'] . '/td';
echo 'td' . $row['StoreManager'] . '/td';
echo 'td' . $row['BBtime'] . '/td';
echo 'td' . $row['BBup'] . '/td';
echo 'td' . $row['BBdown'] . '/td';
echo 'td' . $row['SiteSect'] . '/td';
echo 'td' . $row['VoiceCall'] . '/td';
echo 'td' . $row['Comments'] . '/td';
echo 'tda href=edit.php?id=' . $row['id']
.'Edit/a/td';
echo 'tda href=delete.php?id=' . $row['id']
.'Delete/a/td';
echo /tr;
}

// close table
echo /table;
?

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[PHP-DB] automactic email notification

2011-04-13 Thread Chris Stinemetz
I have an all-in-one form which allows record edits, adds and deletes
in a mysql table.

I would like to add the ability to automatically send email update to
a distribution list whenever a record is edited, deleted, or added.

I won't be hosting my own mail server so instead I will be using remote SMTP.

The mail script I created works just fine I am just not sure how to
put this all together for the notifications when the table is altered.

Thank you in advance!

Mail Script:

?php
 require_once Mail.php;

 $from = Someone email@.com;
 $to = Someone Recipient email@.com;
 $subject = Hi!;
 $body = Hi,\n\nHow are you?;

 $host = example.com;
 $port = 587;
 $username = example;
 $password = example;

 $headers = array ('From' = $from,
   'To' = $to,
   'Subject' = $subject);
 $smtp = Mail::factory('smtp',
   array ('host' = $host,
 'port' = $port,
 'auth' = true,
 'username' = $username,
 'password' = $password));

 $mail = $smtp-send($to, $headers, $body);

 if (PEAR::isError($mail)) {
   echo(p . $mail-getMessage() . /p);
  } else {
   echo(pMessage successfully sent!/p);
  }
 ?



Form Script:

!DOCTYPE HTML PUBLIC -//W3C//DTD HTML 4.01//EN
http://www.w3.org/TR/html4/strict.dtd;
html
head
titleATC West Swap/title
script type='text/javascript' src='../js/jquery-1.2.3.js'/script
script type='text/javascript' src='../js/menu.js'/script

link rel=stylesheet href=../css/style.css type=text/css media=screen /


/style
/head
body
div id=boundary
h1West RF Engineering Dashboard/h1
ul id=nav
lia href=../index.phpHome/a/li
lia href=#ATC West Swap/a
  ul
lia href=atcswap.phpExpiring Leases/a/li
lia href=lowmou.phpLow MOU/a/li
  /ul
/li
/ul
div id=content

/div
p id=footerLow MOU WEST/p
HR
?
$objConnect = mysql_connect(localhost,cstine,cstine) or
die(mysql_error());
$objDB = mysql_select_db(atc);

//*** Add Condition ***//
if($_POST[hdnCmd] == Add)
{
$strSQL = INSERT INTO lowmou ;
$strSQL .=(SiteID,NewSiterraSiteID,ATCSiteID,CricketRegion,Comments,
Progress,willsitebedecom,relocationTowerVendor) 
;
$strSQL .=VALUES ;
$strSQL 
.=('.$_POST[txtAddSiteID].','.$_POST[txtAddNewSiterraSiteID].'
;
$strSQL .=,'.$_POST[txtAddATCSiteID].' ;
$strSQL 
.=,'.$_POST[txtAddCricketRegion].','.$_POST[txtAddComments].'
;
$strSQL .=,'.$_POST[txtAddProgress].' ;
$strSQL 
.=,'.$_POST[txtAddwillsitebedecom].','.$_POST[txtAddrelocationTowerVendor].')
;
$objQuery = mysql_query($strSQL);

if(!$objQuery)
{
echo Error Save [.mysql_error().];
}
//header(location:$_SERVER[PHP_SELF]);
//exit();
}

//*** Update Condition ***//
if($_POST[hdnCmd] == Update)
{
$strSQL = UPDATE lowmou SET ;
$strSQL .=SiteID = '.$_POST[txtEditSiteID].' ;
$strSQL .=,NewSiterraSiteID = '.$_POST[txtEditNewSiterraSiteID].' 
;
$strSQL .=,ATCSiteID = '.$_POST[txtEditATCSiteID].' ;
$strSQL .=,CricketRegion = '.$_POST[txtEditCricketRegion].' ;
$strSQL .=,Comments = '.$_POST[txtEditComments].' ;
$strSQL .=,Progress = '.$_POST[txtEditProgress].' ;
$strSQL .=,willsitebedecom = '.$_POST[txtEditwillsitebedecom].' ; 
$strSQL .=,relocationTowerVendor =
'.$_POST[txtEditrelocationTowerVendor].' ;
$strSQL .=WHERE SiteID = '.$_POST[hdnEditSiteID].' ;
$objQuery = mysql_query($strSQL);
if(!$objQuery)
{
echo Error Update [.mysql_error().];
}
//header(location:$_SERVER[PHP_SELF]);
//exit();
}

//*** Delete Condition ***//
if($_GET[Action] == Del)
{
$strSQL = DELETE FROM lowmou ;
$strSQL .=WHERE SiteID = '.$_GET[srID].' ;
$objQuery = mysql_query($strSQL);
if(!$objQuery)
{
echo Error Delete [.mysql_error().];
}
//header(location:$_SERVER[PHP_SELF]);
//exit();
}

$strSQL = SELECT * FROM lowmou;
$objQuery = mysql_query($strSQL) or die (Error Query [.$strSQL.]);
?
form name=frmMain method=post action=?=$_SERVER[PHP_SELF];?
input type=hidden name=hdnCmd value=
table
  tr
thSiteID /th
thNewSiterraSiteID /th
thATCSiteID /th
thCricketRegion /th
thComments /th
thProgress/th
thWill site be decom?/th
thRelocation Tower Vendor/th
thEdit /th
thDelete /th
  /tr

?
while($objResult = mysql_fetch_array($objQuery))
{
?

  ?
if($objResult[SiteID] == $_GET[srID] and $_GET[Action] == Edit)
{
  ?
  tr
tddiv align=center
input type=text name=txtEditSiteID size=5
value=?=$objResult[SiteID];?
input type=hidden name=hdnEditSiteID size=5
value=?=$objResult[SiteID];?
/div/td
tdinput type=text name=txtEditNewSiterraSiteID size=10
value=?=$objResult[NewSiterraSiteID];?/td
tdinput type=text name=txtEditATCSiteID size=10

Re: [PHP-DB] Re: automactic email notification

2011-04-13 Thread Chris Stinemetz
On Wed, Apr 13, 2011 at 11:08 AM, Jim Giner
jim.gi...@albanyhandball.com wrote:
 Without looking at your HUGE code stream, I'm curious what your question
 really is.  If you know how to send an email, and you know how to update
 your table, then isn't your task simply to send an email after updating the
 table?

Yes.

 I would make the email a function to get it out of the way and
 then add a call to it right after I did an update.  The user probably gets a
 message of the successful update, so when you do that, that's when you call
 your email function.  Maybe have a couple of arguments in the function to
 pass some specifics and that's that.


Could you possbily show me an example? I am a newby when it comes to PHP.
Thank you!




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[PHP-DB] error

2011-04-07 Thread Chris Stinemetz
I am getting the following error when I try to use my edit.php script:

You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near '' at line 1

I can't seem to find anything wrong with my syntax below.

Has anyone ever had this issue?

I have been googling it for a couple hours now.

Thank you in advance!

Chris

?php
error_reporting(E_ALL);
ini_set('display_errors', '1');
/*
 EDIT.PHP
 Allows user to edit specific entry in database
*/

 // creates the edit record form
 // since this form is used multiple times in this file, I have made
it a function that is easily reusable
 function renderForm($id, $Cricket_Region, $Market, $error)
 {
 ?
 !DOCTYPE HTML PUBLIC -//W3C//DTD HTML 4.01//EN
http://www.w3.org/TR/html4/strict.dtd;
 html
 head
 titleEdit Record/title
 /head
 body
 ?php
 // if there are any errors, display them
 if ($error != '')
 {
 echo 'div style=padding:4px; border:1px solid red;
color:red;'.$error.'/div';
 }
 ?

 form action= method=post
 input type=hidden name=id value=?php echo $id; ?/
 div
 pstrongID:/strong ?php echo $id; ?/p
 strongCricket Region: */strong input type=text name=Cricket
Region value=?php echo $Cricket_Region; ?/br/
 strongMarket: */strong input type=text name=Market
value=?php echo $Market; ?/br/
 p* Required/p
 input type=submit name=submit value=Submit
 /div
 /form
 /body
 /html
 ?php
 }



 // connect to the database
 include('../PHP_Scripts/connect-db.php');


 // check if the form has been submitted. If it has, process the form
and save it to the database
 if (isset($_POST['submit']))
 {
 // confirm that the 'id' value is a valid integer before getting the form data
 if (is_numeric($_POST['id']))
 {
 // get form data, making sure it is valid
 $id = $_POST['id'];
 $Cricket_Region =
mysql_real_escape_string(htmlspecialchars($_POST['Cricket_Region']));
 $Market = mysql_real_escape_string(htmlspecialchars($_POST['Market']));

 // check that firstname/lastname fields are both filled in
 if ($Cricket_Region == '' || $Market == '')
 {
 // generate error message
 $error = 'ERROR: Please fill in all required fields!';

 //error, display form
 renderForm($id, $Cricket_Region, $Market, $error);
 }
 else
 {
 // save the data to the database
 mysql_query(UPDATE expiringleases SET
Cricket_Region='$Cricket_Region', Market='$Market' WHERE id='$id')
 or die(mysql_error());

 // once saved, redirect back to the view page
 header(Location: view.php);
 }
 }
 else
 {
 // if the 'id' isn't valid, display an error
 echo 'Error!';
 }
 }
 else
 // if the form hasn't been submitted, get the data from the db and
display the form
 {

 // get the 'id' value from the URL (if it exists), making sure that
it is valid (checking that it is numeric/larger than 0)
 if (isset($_GET['id']))
 {
 // query db
 $id = $_GET['id'];
 $result = mysql_query(SELECT * FROM expiringleases WHERE id=$id)
 or die(mysql_error());
 $row = mysql_fetch_array($result);

 // check that the 'id' matches up with a row in the databse
 if($row)
 {

 // get data from db
 $Cricket_Region = $row['Cricket_Region'];
 $Market = $row['Market'];

 // show form
 renderForm($id, $Cricket_Region, $Market, '');
 }
 else
 // if no match, display result
 {
 echo No results!;
 }
 }
 else
 // if the 'id' in the URL isn't valid, or if there is no 'id' value,
display an error
 {
 echo 'Error!';
 }
 }
?

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Re: [PHP-DB] error

2011-04-07 Thread Chris Stinemetz
I am pretty sure it is in my code. I am just getting an error form one
of my echoes. Still can't get it to work correctly though. Any help is
greatly appreciated.

Thank you,

Chris

?php
/*
 EDIT.PHP
 Allows user to edit specific entry in database
*/

 // creates the edit record form
 // since this form is used multiple times in this file, I have made
it a function that is easily reusable
 function renderForm($id, $Cricket_Region, $Market, $error)
 {
 ?
 !DOCTYPE HTML PUBLIC -//W3C//DTD HTML 4.01//EN
http://www.w3.org/TR/html4/strict.dtd;
 html
 head
 titleEdit Record/title
 /head
 body
 ?php
 // if there are any errors, display them
 if ($error != '')
 {
 echo 'div style=padding:4px; border:1px solid red;
color:red;'.$error.'/div';
 }
 ?

 form action= method=post
 input type=hidden name=id value=?php echo $id; ?/
 div
 pstrongID:/strong ?php echo $id; ?/p
 strongFirst Name: */strong input type=text
name=Cricket_Region value=?php echo $Cricket_Region; ?/br/
 strongLast Name: */strong input type=text name=Market
value=?php echo $Market; ?/br/
 p* Required/p
 input type=submit name=submit value=Submit
 /div
 /form
 /body
 /html
 ?php
 }



 // connect to the database
 include('../PHP_Scripts/connect-db.php');

 // check if the form has been submitted. If it has, process the form
and save it to the database
 if (isset($_POST['submit']))
 {
 // confirm that the 'id' value is a valid integer before getting the form data
 if (is_string($_POST['Search_Ring']))
 {
 // get form data, making sure it is valid
 $id = $_POST['Search_Ring'];
 $Cricket_Region =
mysql_real_escape_string(htmlspecialchars($_POST['Cricket_Region']));
 $Market = mysql_real_escape_string(htmlspecialchars($_POST['Market']));

 // check that Cricket_Region/Market fields are both filled in
 if ($Cricket_Region == '' || $Market == '')
 {
 // generate error message
 $error = 'ERROR: Please fill in all required fields!';

 //error, display form
 renderForm($id, $Cricket_Region, $Market, $error);
 }
 else
 {
 // save the data to the database
 mysql_query(UPDATE expiringleases SET
Cricket_Region='$Cricket_Region', Market='$Market' WHERE
Search_Ring='$id')
 or die(mysql_error());

 // once saved, redirect back to the view page
 header(Location: ATC.php);
 }
 }
 else
 {
 // if the 'id' isn't valid, display an error
 echo 'Error!';
 }
 }
 else
 // if the form hasn't been submitted, get the data from the db and
display the form
 {

 // get the 'id' value from the URL (if it exists), making sure that
it is valid (checing that it is numeric/larger than 0)
 if (isset($_GET['Search_Ring']))
 {
 // query db
 $id = $_GET['Search_Ring'];
 $result = mysql_query(SELECT * FROM expiringleases WHERE Search_Ring=$id)
 or die(mysql_error());
 $row = mysql_fetch_array($result);

 // check that the 'id' matches up with a row in the databse
 if($row)
 {

 // get data from db
 $Cricket_Region = $row['Cricket_Region'];
 $Market = $row['Market'];

 // show form
 renderForm($id, $Cricket_Region, $Market, '');
 }
 else
 // if no match, display result
 {
 echo No results!;
 }
 }
 else
 // if the 'id' in the URL isn't valid, or if there is no 'id' value,
display an error
 {
 echo 'Error!';
 }
 }

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Re: [PHP-DB] Re: jpgraph and mysql passing array

2011-03-27 Thread Chris Stinemetz
On Sat, Mar 26, 2011 at 9:44 PM, Brian Smither bhsmit...@gmail.com wrote:
 Would you try an experiment?

Thanks for for the suggestion but this didn't seem to work. I beleive
it is a header conflict based on what I have researched.
I just can't seem to find a solution.


 In this line:
 $sql = (SELECT * FROM evdobanding WHERE Market like '%$term' and Cell_Sect = 
 '$term2' and Date = '$term3' ORDER BY distance asc);

 Change to:
 $sql = SELECT * FROM evdobanding WHERE Market like '%.$term.' and 
 Cell_Sect = '.$term2.' and Date = '.$term3.' ORDER BY distance asc;

 That is, remove the parenthesis and concatenate the variables into the string.


The code in the PHP block:

  echo TEST DATA PRINT;
  print_r($datay,false);

is passing all the values from the sql query because I can see them on
the page with the jpgraph error.

For example:

TEST DATA PRINTArray ( [0] = 665 [1] = 7093 [2] = 3 [3] =
45816 [4] = 70848 [5] = 41365 [6] = 35676 [7] = 22434 [8] = 5450
[9] = 29131 [10] = 35244 [11] = 48614 [12] = 51748 [13] = 55497
[14] = 79042 [15] = 732 [16] = 1375 [17] = 1094 [18] = 897 [19]
= 1122 [20] = 3059 [21] = 5350 [22] = 5080 [23] = 3082 [24] =
2737 [25] = 326 [26] = 1334 [27] = 736 [28] = 469 [29] = 127 [30]
= 105 [31] = 111 [32] = 197 [33] = 208 [34] = 950 [35] = 9 [36]
= 9 [37] = 19 [38] = 8 [39] = 17 [40] = 90 [41] = 1917 [42] =
1289 [43] = 2051 [44] = 1534 [45] = 1 [46] = 2 [47] = 4 [48] = 4
[49] = 7 [50] = 8 [51] = 9 [52] = 18 [53] = 22 [54] = 5 [55] =
3 [56] = 1 [57] = 1 [58] = 2 )

JpGraph ERROR 25121



From the research I have done so far using Jpgraph I have found this
link to a similar issue:

http://ubuntuincident.wordpress.com/tag/jpgraph/

but I am unable to get my arrays from the sql query to populate the graph.

Thank you in advance,

Chris

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[PHP-DB] jpgraph and mysql passing array

2011-03-23 Thread Chris Stinemetz
Hello,



I hope you can help me. The Jpgraph forum seems to be pretty
uneventful with participation.

I am trying to pass arrays through the image tag to populate my
variables for my graph.

I keep getting an error that there is no input. Do you have any suggestions?

I would greatly appreciate it! I have been trying to figure this out
for several hours.



Below is my code:



I need some help with finding a solution. For some reason my graph is
not showing up when it evident that my arrays are being passed.



When I use:



echo TEST DATA PRINT;

print_r($datay,false);



---



I keep getting the error:

Empty input data array specified for plot.



---



My php script is as follows:

---



!DOCTYPE html PUBLIC -//W3C//DTD XHTML 1.0 Transitional//EN
http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd;

html xmlns=http://www.w3.org/1999/xhtml;



head

titleKCRF Dashboard/title

?php

ini_set('display_errors', 1);

error_reporting(E_ALL);



$term=$_POST['term'];

$term2=$_POST['term2'];

$term3=$_POST['term3'];



//include ('err_reporting.php');

require ('PHP_Scripts/config.php');

require_once ('jpgraph/jpgraph.php');

require_once ('jpgraph/jpgraph_line.php');



   $sql = (SELECT * FROM evdobanding WHERE Market like '%$term' and
Cell_Sect = '$term2' and Date = '$term3' ORDER BY distance asc);

   $result = mysql_query($sql);



   while($row = mysql_fetch_array($result))

   {

   $datay[] = $row[MBusage];

   $datax[] = $row[Distance];

   }

  echo TEST DATA PRINT;

  print_r($datay,false);

?





style type=text/css

!--



 #navbar ul {

    margin: 0;

    padding: 5px;

    list-style-type: none;

    text-align: center;

    background-color: #000;

    }



#navbar ul li {

    display: inline;

    }



#navbar ul li a {

    text-decoration: none;

    padding: .2em 1em;

    color: #fff;

    background-color: #000;

    }



#navbar ul li a:hover {

    color: #000;

    background-color: #fff;

    }



--

/style



/head



fieldset style=border: 1px ridge limegreen; color: limegreen;
legend style=color: #000; font-family: verdana; font-size:
14pt;EVDO PCMD BANDING/legend body div id=navbar

  ul

    lia href=index.phpHome/a/li

    lia href=dd3.phpEVDO PCMD KPI/a/li

    lia href=banding.phpEVDO Distance Banding/a/li

    lia href=test.phpTEST_BANDING/a/li

    lia href=LinkHere/a/li

  /ul

/div



/fieldset

?php

echo You Selected the following:brMarket = $term brCell_Sector =
$term2brTimestamp = $term3br; ?



img src=bandingGraph.php?$datax=$row[Distance]$datay=$row[MBusage];
// I think this is where I am having issues.





/body

/html

---



My graph script is:



?php // content=text/plain; charset=utf-8

require_once ('jpgraph/jpgraph.php');

require_once ('jpgraph/jpgraph_line.php');



   // Create the graph.

   $graph = new Graph(1024,450,auto);



   $graph-SetScale(textlin);

   $graph-SetShadow();



   // Slightly adjust the legend from it's default position

   $graph-legend-Pos(0.03,0.5,right,center);

   $graph-legend-SetFont(FF_FONT1,FS_BOLD);



   //Setup X-scale

 $graph-xaxis-SetTextTickInterval(10);

 $graph-xaxis-SetTickLabels($datax);

 //$graph-xtick_factor = 1;

    $graph-xaxis-SetLabelAngle(30);



   // Create the linear plot

   $lineplot= new LinePlot($datay);

   $p1 = new LinePlot($datay);

   $p1-mark-SetType(MARK_DIAMOND);

   $p1-mark-SetFillColor(blue);

   $p1-mark-SetWidth(;

   $p1-SetColor(blue);

   $p1-SetCenter();

   $p1-SetLegend(EVDO F1 Carrier);

   $graph-Add($p1);



   // Add the plot to the graph

   $graph-Add($lineplot);



   // Setup margin and titles

   $graph-img-SetMargin(40,40,50,60);

   $graph-title-SetMargin(10);

   $graph-title-Set(Distance in MIles);

   $graph-title-SetFont(FF_VERDANA,FS_BOLD,12);



   // set margin color

   $graph-SetMarginColor('#dcfade');

   // Use built in font

   $graph-title-SetFont(FF_ARIAL,FS_NORMAL,14);

   $graph-ygrid-SetFill(true,'#EFEFEF@0.6','#e5e5e5@0.6');



   $graph-xgrid-Show();

   $graph-SetBackgroundImageMix(15);

   $graph-legend-Pos(0.02,0.03,right,top);

   $graph-legend-SetFont(FF_FONT1,FS_BOLD);







   $graph-xaxis-title-Set(Miles);

   $graph-yaxis-title-Set(MBusage);

   $graph-SetAlphaBlending();



   // Display the graph

   $graph-Stroke();

?





Thank you,



Chris

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Re: [PHP-DB] SUM() Math in mySQL

2010-12-19 Thread Chris

On 20/12/10 15:38, Ron Piggott wrote:

I am working on the query below.  It’s purpose is to manage the RSS Feed for 
the site.

The part of the query I am struggling with is:

SUM(`include_in_rss_feed`) AS current_rss_feed

What I need is the total value of *ALL* the `include_in_rss_feed` , not the 
specific row.

`include_in_rss_feed` is an integer.  It only ever has a value of 1


Well you're going to get an error with your current attempt - but you 
know that already I assume. You have an aggregate function (sum) but no 
group by clause for the outer query.


I think you're better off just having 2 queries - one with the sum() and 
the group by include_in_rss_feed, and one with all of your other data. I 
don't think combining them will be very easy.


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Re: [PHP-DB] NULL to 0 result

2010-12-15 Thread Chris

On 15/12/10 21:42, Richard Quadling wrote:

On 14 December 2010 21:53, Ron Piggottron.pigg...@actsministries.org  wrote:


What change is needed to this query so if “currently_in_rss” is NULL it will be 
assigned a value of 0

SELECT `reference`, COUNT(`reference`) AS currently_in_rss FROM 
`ministry_profiles` WHERE `rss_feed_include` = 1 GROUP BY `rss_feed_include`

Ron


Doesn't that query give you an error saying that `reference` isn't in
the GROUP BY clause?


Nah mysql lets you do it. Other db's enforce it as you pointed out.

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Re: [PHP-DB] Reading from file

2010-11-01 Thread Chris

On 02/11/10 14:34, Ethan Rosenberg wrote:

Dear List -

Thank you for all your help. Here is another one.

I have a file [/home/ethan/PHP/RecNum] which consists of the number
1005. It also has been 1005. No matter how I do it, it is only
recognized as 1.

Here is the code. In this case, the file is 1005.

$fptr1 = fopen(/home/ethan/PHP/RecNum, r+);
$recNum = (int)fscanf($fptr1,%s);
echo $recNum; //which always is 1

If I do not typecast $recNum to int, the value is Array.


Right, which is what the manual says as well:

http://www.php.net/fscanf

If only two parameters were passed to this function, the values parsed 
will be returned as an array.


So you can either do:

$line = fscanf($fptr1, %s);
$recNum = $line[0]; // get the first element in the array as $recNum

or

while ($line = fscanf($fptr1, %s\n)) {
  $recNum = $line[0];
}

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Re: [PHP-DB] Variable Assignment

2010-10-28 Thread Chris



However, I am totally confused. All the texts state that to set a
variable, the code is: $st=100;


That's how you do it in php.

Doing it in the db is different and depends on the db you are using.

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Re: [PHP-DB] Creating an INDEX on multiple tables?

2010-10-24 Thread Chris

On 22/10/10 21:00, Ron Piggott wrote:

I have moved the GROUP BY outside now Chris.

In the queries that make up the UNION ALL (such as below) is there a way
to only SELECT matches that are 70% or greater based on the users input?
Right now each and every listing is a search result.


http://dev.mysql.com/doc/refman/5.0/en/fulltext-natural-language.html

has info about doing that sort of thing.

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Re: [PHP-DB] Creating an INDEX on multiple tables?

2010-10-21 Thread Chris

On 22/10/10 13:31, Ron Piggott wrote:

Bastien (and others) I am still having one problem with this query I
don't know how to resolve:

When I add the category column: `ministry_categories`.`category` as part
of the MATCH () I receive the error:
Incorrect arguments to MATCH

I create the LEFT OUTER JOINs to allow additional columns to be part of
the MATCH. I have made this category column a FULLTEXT index in the
ministry_categories table. The query that produces the error is below.


You can't do a full text match across tables.

One of the previous suggestions was to union the results, you end up 
with something like


select field from t1 where match(field1, field2) against ('search term')
union all
select field from t2 where match(field3, field4) against ('search term')

etc

though I don't know if that would work (I've never tried it).

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Re: [PHP-DB] Creating an INDEX on multiple tables?

2010-10-21 Thread Chris

On 22/10/10 15:24, Ron Piggott wrote:

The query works using UNION ALL and MATCH ( ) AGAINST --- one table at a
time for the MATCH. The down side is that each SELECT is giving it's own
search results. The directory listings are being displayed multiple
times when one of the SELECTS produces it as a result. How do I limit
the results? Can I do this some how with results.reference and
results.organization (I made the UNION ALLs sub queries)



Get rid of the group by references inside each bit and move it to the outer:

SELECT reference, organization FROM (

SELECT `ministry_profiles`.`reference`, 
`ministry_profiles`.`organization` FROM

...
UNION ALL
SELECT `ministry_profiles`.`reference`,
...
)
GROUP BY reference, organization;

You'll get one reference per organization.

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Re: [PHP-DB] RE: php-db Digest 19 Oct 2010 22:24:15 -0000 Issue 4629

2010-10-19 Thread Chris

On 20/10/10 09:55, Jimmy Sole wrote:

Hello everyone,

I'm having trouble executing a insert select query in PHP

Here is the code:

$exec = self::init()-prepare(INSERT INTO owners (f_name, l_name, username,
password, email, company, str_address,
city, state,
zip, phone, website, desc, categories)
SELECT f_name, l_name, username,
password, email, company, street_address,
   city, state, zip,
phone_number, website, description, categories FROM pending
WHERE pid  '0');


 if ($exec-execute() !== false) {
 return true;
 } else {
 throw new Exception(Error processing the query.);
 }

Any help would be appreciated, as PDO is not returning an error or anything.


Doesn't look like it should - it looks like a valid query.

Check your database logs or even run the query inside a transaction (and 
rollback) to see if it errors.


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Re: [PHP-DB] Query for duplicate records

2010-10-17 Thread Chris

On 18/10/10 06:55, Ron Piggott wrote:

Is there a query you could help me write a SELECT query that would search table 
`ministry_profiles` for where column `organization`  has the same organization 
more than once?  I am trying to delete the duplicate organization records, but 
I am working with 1,000+ businesses and I can't go through each record looking 
for duplicates.


select organization, count(*) from ministry_profiles group by 
organization having count(*)  1;


gives you which organization has more than 1 account (and how many 
duplicates you are dealing with).


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Re: [PHP-DB] Re: SOUNDS_LIKE, SOUNDEX

2010-10-11 Thread Chris

On 12/10/10 08:45, Ron Piggott wrote:

After looking at the response I tried to make 2 mySQL queries that I need
help with.  (I didn't use the PHP functions because I am trying to query
the database for results:

#1:
SELECT `word` FROM `bible_concordance_words` WHERE SOUNDEX('command')
ORDER BY `word` ASC
- There are no results, I don't understand because Commanded, Commander,
Commanding, Commandment, Commandments are all in the datase

#2:
SELECT `word` FROM `bible_concordance_words` WHERE command SOUNDS_LIKE
`word` ORDER BY `word` ASC
- I receive the error:
You have an error in your SQL syntax; check the manual that corresponds to
your MySQL server version for the right syntax to use near 'SOUNDS_LIKE
`word` ORDER BY `word` ASC


RTFM?

http://dev.mysql.com/doc/refman/5.0/en/string-functions.html#operator_sounds-like

This stuff isn't that difficult to find.

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Re: [PHP-DB] Slashes or no slashes

2010-08-24 Thread Chris


In the case that your comparing a field to a field in the database (the
field name)
do you escape that or because it is hardcoded you dont need to?
My thoughts are that you need to escape all data going in.


Correct. A field name is not data though. You've already validated it 
(somehow, either by hardcoding it, or checking it against field names to 
make sure it's a proper field and doesn't contain weird chars).



But I do not know if it will match.

EG:

/**
* updateProduct */
function updateProduct($ProductName, $field, $value){
$q = UPDATE .TBL_PRODUCTS. SET .$field. =
'.mysql_real_escape_string($value).' WHERE ProductName =
'.mysql_real_escape_string($ProductName).';
return $this-query($q);
}

Do I escape $field? mysql_real_escape_string($field)?


You can only escape data, not field or table (or database) names.

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Re: [PHP-DB] Slashes or no slashes

2010-08-23 Thread Chris



You use mysql_real_escape_string for queries on the way in.

$query = select * from table where
name='.mysql_real_escape_string($_POST['name']).';

You use htmlspecialchars on the way out:

$value = htmlspecialchars($row['name']);


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Ah.. thanks Chris.
If I want to compare that value I get from the database to what a user
entered,
do I escape the value they entered or add htmlspecialchars to it before
comparing it to what comes out of the database.
Sorry this is such a PHP 101 question. If you have time to respond,
please do, otherwise no worries, I am sure I will figure it out.


If you want to compare, you're doing a query - so use 
mysql_real_escape_string:


$query = select blah from table where name=' . 
mysql_real_escape_string($_POST['name']) . ';



When you print results, you use htmlspecialchars:

echo Your search for  . htmlspecialchars($_POST['name']) .  returned 
X resultsbr/;


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Re: [PHP-DB] Slashes or no slashes

2010-08-23 Thread Chris



To be more specific. Is this correct?

function confirmUP($username, $password){
$username = mysql_real_escape_string($username);

/* Verify that user is in database */
$q = SELECT password FROM TBL-U WHERE username = '$username';


I normally do it in the query in case you use the variable somewhere 
else but here it's ok because you don't use $username elsewhere. Be 
careful though, it may bite you and it will be difficult to track down.


eg

$q = select password from table where username=' . 
mysql_real_escape_string($username) . ';


echo You entered  . htmlspecialchars($username) . , either it was 
wrong or the password was wrong. Try again.;


Doing the escape_string before the query means you end up with (basically)

htmlspecialchars(mysql_real_escape_string($username));

which will cause weird characters to show up in certain cases.


$result = $this-query($q);
if(!$result || (mysql_numrows($result)  1)){
return 1; //Indicates username failure
}

/* Retrieve password from result */
$dbarray = mysql_fetch_array($result);
$dbarray['password'] = htmlspecialchars($dbarray['password']);
$password = mysql_real_escape_string(md5($password));
$password = htmlspecialchars($password);


You're not displaying the password so don't htmlspecialchars it.

Just:

if ($dbarray['password'] == md5($password)) {
  return 0; // success!
}

Only specialchars it when you display it (like the echo above).

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Re: [PHP-DB] Slashes or no slashes

2010-08-23 Thread Chris



Just to make sure, cause I am ready to get past this.
Is this correct?

function confirmUP($username, $password){
/* Verify that user is in database */
$q = SELECT password FROM .TBL_USERS. WHERE username =
'.mysql_real_escape_string($username).';


Perfect.


/* Retrieve password from result */
$dbarray = mysql_fetch_array($result);
$dbarray['password'] = htmlspecialchars($dbarray['password']); //Or is
this where I need to leave htmlspecialchars off too?


Leave it off.

You're not displaying $dbarray['password'] here - so you don't need to 
use htmlspecialchars.


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Re: [PHP-DB] Slashes or no slashes

2010-08-23 Thread Chris



Got it. So only when I am going to diplay the result from the database.
I see.


Or email (or otherwise present it to the user), yes.


But for comparing $dbarray['password'] to $password, don't I have to
escape $password and then md5 it?


Right.

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Re: [PHP-DB] Slashes or no slashes

2010-08-22 Thread Chris

On 20/08/10 08:05, Karl DeSaulniers wrote:


On Aug 19, 2010, at 4:44 PM, Karl DeSaulniers wrote:


On Aug 19, 2010, at 4:36 PM, Daevid Vincent wrote:


You should be using
http://us2.php.net/manual/en/function.mysql-escape-string.php

You don't need to search with extra slashes for retrieval.


-Original Message-
From: Karl DeSaulniers [mailto:k...@designdrumm.com]
Sent: Thursday, August 19, 2010 2:29 PM
To: php-db@lists.php.net
Subject: [PHP-DB] Slashes or no slashes

Hello,
When I add an item to my database and I use addslashes(),
do I have to use addslashes() to a query that looks for that item?
Or would I be adding double slashes and canceling my own result?
TIA

Karl DeSaulniers
Design Drumm
http://designdrumm.com





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Ah, but lets say I am using a character set utf-8, I should use
mysql_real_escape_string() instead?
Best,

Karl DeSaulniers
Design Drumm
http://designdrumm.com


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For a line like this..

return htmlspecialchars(stripslashes($this-values[$field]));

would I change this to?

return mysql_real_escape_string($this-values[$field]);

Or do I still need the htmlspecialchars? In that case would I change it to?

return htmlspecialchars(mysql_real_escape_string($this-values[$field]));


You use mysql_real_escape_string for queries on the way in.

$query = select * from table where 
name='.mysql_real_escape_string($_POST['name']).';


You use htmlspecialchars on the way out:

$value = htmlspecialchars($row['name']);


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Re: [PHP-DB] SELECT with ' in search term

2010-08-12 Thread Chris

On 13/08/10 13:26, Ron Piggott wrote:

If the variable $segment has an ' in it the $query won't work because of
having 3 ' 's.

Should I be using:

$segment = mysql_real_escape_string($segment);

before querying the database?


Use it in your query. Don't use it anywhere else. Your code may use it 
after the query and cause weird stuff, ala:


$segment = 'this is my segment';
$segment = mysql_real_escape_string($segment);
$query  = ;

echo 'My segment name is ' . htmlspecialchars($segment);

So it'll become:

$query=SELECT `reference` FROM `bible_concordance_words` WHERE `word` =
' . mysql_real_escape_string($segment) . ' LIMIT 1;



Please note:  $segment wasn't submitted through a form.


Doesn't matter.

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Re: [PHP-DB] Re: Stuck in apostrophe hell

2010-08-03 Thread Chris

On 03/08/10 23:04, paul_s_john...@mnb.uscourts.gov wrote:

Yes, I may have mixed up the input and output from different iterations of
running it. Let me try posting this again although it may not be an issue.
Once again if I enter two sequential apostrophes in the name (O''Brien)
the INSERT passes right through to MySQL without an error.

THE INPUT:

$sql_insert_registration = sprintf(INSERT INTO
   Registrations (
 Class_ID,
 prid,
 Registrant,
 Company,
 Phone,
 Email
   )
VALUES (
 $_POST[Class_ID],


^^ needs a mysql_real_escape_string or validation to make sure it's 
an integer



 $_POST[prid],


^^ needs a mysql_real_escape_string or validation to make sure it's 
an integer



 '%s',.


^^ has a mysql_real_escape_string, but it's the only one.


 parseNull($_POST['Company']).,


Without knowing what this function does, it's hard to say what this needs.


 '$_POST[Phone]',


^^ needs a mysql_real_escape_string


 '$_POST[Email]'


^^ needs a mysql_real_escape_string


), mysql_real_escape_string($_POST['Registrant']));



This has already all been pointed out previously.


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Re: [PHP-DB] calling a page for each row

2010-07-15 Thread Chris

On 16/07/10 09:38, listread wrote:

We need to load a page which performs some tasks specific to each
record, including writing some results to another table.

I have tried to place a page loading script within the while loop that
creates the table, but it seems to only load the page on the last record
in the table.

Is there a better way to do this?


Why does it need to call a page to do all the work? If it was just a 
function call you'd be off and racing already.


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Re: [PHP-DB] calling a page for each row

2010-07-15 Thread Chris

On 16/07/10 09:51, listread wrote:

On 7/15/2010 6:42 PM, Chris wrote:

On 16/07/10 09:38, listread wrote:

We need to load a page which performs some tasks specific to each
record, including writing some results to another table.

I have tried to place a page loading script within the while loop that
creates the table, but it seems to only load the page on the last record
in the table.

Is there a better way to do this?


Why does it need to call a page to do all the work? If it was just a
function call you'd be off and racing already.


The page I want to call is a little involved. It makes a geocode request
from Google Maps and then parses the resulting json code and then writes
the parsed data to another table. I guess it could be done with
functions, but the other page was already written... :-)


I guess you could do a file_get_contents on the url of the page.


If I call a function, will the while loop wait for the function to
complete before going to the next row?


Yes.

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Re: [PHP-DB] anyone has experience with pgslq Cybercluster 2 ?

2010-06-01 Thread Chris

On 02/06/10 04:34, Artur Ejsmont wrote:

Hi there i just noticed announcement of cybercluster 2 release for postgres.

http://www.cybertec.at/en/postgresql_news

they say its open source but did not find downloads on their site ; )

Anyone has experinece with it? i loved postgres and used to work with it for
a long time but lack of easy and reliable replication forced me to move back
to mysql. To be honest did not look at postgres for a few years now  : /

Anyone could share some tips on php-pgsql-replication experiences?


There are some comparisons here between the different postgres 
replication options:


http://wiki.postgresql.org/wiki/Replication%2C_Clustering%2C_and_Connection_Pooling

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Re: [PHP-DB] Need Simple PHP mysql search engine script

2010-05-24 Thread Chris

On 24/05/10 16:01, nagendra prasad wrote:

Hi Chaitanya,

I have used the below script but its not meeting my requirements. What I
need is that I have a database in which their are names which I wanted to
use as keywords. I want to  search with only one variable called Names. the
other stuff will come along with it. Please help me if anyone knows a good
script for it.


Requirements that specific won't have a generic script.

Start coding..

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Re: [PHP-DB] PHP / iODBC / PostGreSQL: running into a deadlock

2010-05-24 Thread Chris



To try to solve this issue, I grabed the sources for PHP (5.3.2) and
libiodbc (3.52.7). When ran under GDB, I can observe the following:
odbc_exec() [PHP code] calls SQLAllocStmt() [libiodbc code], which calls
some internal function that tries to call SQLAllocStmt(), in some indirect
recursive way. As SQLAllocStmt() is protected by a mutex, there's a
deadlock.
The BT is as follows:


Probably best to ask on the php-internals list, they write the C code 
behind php so will be best able to help you.


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Re: [PHP-DB] Call two class object failed

2010-05-23 Thread Chris

On 24/05/10 11:55, win.a wrote:

Hi my friend,i wrote two classed on is user,the other is db .The user
have a property which from the db class object .


When i writing my application have both class object invoked at the
same time ,just like
$user_a = new user($para);
$db_a = new db()

Then the problem occurs only one of the class object could work, or
$user_a or $db_a not both,What 's problem of my code




The two class works well in the single application when only of them
are invoked ,i cost me much time to deal it
Any advice and suggestions are thankful !


You'll need to include the 'db' class first if that's in a separate file 
before you include the 'user' class.


Apart from that, what's the error you're getting?

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Re: [PHP-DB] how to upgrade php in linux

2010-05-04 Thread Chris

On 05/05/10 15:02, Chaitanya Yanamadala wrote:

hai dan
thank you for your suggestion regarding the google thing..
thank god u said me that or else i could have never known that google will
get me all the results.
dude i just asked this question thinking that some one would help me find
the solution not for fun.
regarding the thing of compiling i require it to be done,

hai kesavan
  thank you for the help i have done that search and i found the things but
the thing is that it is an old version of the gcc that is still exisiting in
the yum repository.
i require one dependancy apr-1.3.3 for the compiling of httpd 2.3.5  which i
have found out, but the thing is that it requires two more dependancies
uname=2.6
and rpmlib=4.4.6 which are  not available in the yum repo..


Do you need to use centos? Maybe it'll be easier for you to use a more 
up to date operating system. Ubuntu 10 just came out and it has php 5.3 
available.


We can't teach you how to compile stuff, that's way outside what we're 
here to help you with. Don't forget everyone here is helping you in 
their own free time, so you may not get perfect answers but you will 
get pointers in the right direction (even if it is to google or 
tutorials on other websites).


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Re: [PHP-DB]how to handle exception in php

2010-05-02 Thread Chris

On 02/05/10 15:26, Bavithra R wrote:

hi friends

I am doing a simple student mark details project.
for calculating rank I need to compare the total marks one by one.
To do so i use *for loop.* so atlast while reaching the end of the table it
shows the following warning.
*
Warning*: mysql_result()
[function.mysql-resulthttp://127.0.0.1/pro/function.mysql-result]:
Unable to jump to row 18 on MySQL result index on line *50*

It is because it has no next value to compare.How to use try..catch
exception handling in this.?Or any other suggestion.
Can anybody help me


This isn't an exception, so a try catch won't work. (Exceptions are 
fatal and would say something like uncaught exception ...).


This is a warning about trying to read something that doesn't exist from 
mysql.


I'd do something like

$query = select blah;
$result = mysql_query($query);
while ($row = mysql_fetch_assoc($result)) {
  echo do stuff here;
}

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Re: [PHP-DB] Problem with pg_prepare - PostgresSQL

2010-04-26 Thread Chris

Giancarlo Boaron wrote:

Hi all.

I'm receiving the following message when I try to use
pg_prepare() function:

Call to undefined function pg_prepare().

My application works very well with others pg_*
commands...


What version of php do you have?

This came in with 5.1.0 according to the manual.

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Re: [PHP-DB] Sharing happiness!!

2010-04-21 Thread Chris

Chaitanya Yanamadala wrote:

Are promotional messages a part of the PHP-DB


No, it's spam that got through the filters.

Thankfully we don't get many of them.

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Re: [PHP-DB] Sharing happiness!!

2010-04-21 Thread Chris

Karl DeSaulniers wrote:
Well what's weird is that the person who it says sent it is someone who 
helped me with a PHP problem.
So that means the spammers are spoofing our email addresses to send 
their spam.


That's nothing new.


Not to mention this spam email had all our email addresses in the to field.
Anyone who got this email now has all the emails of the list or as many 
were in the To field.


I removed them all before replying - check again.

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Re: [PHP-DB] Sharing happiness!!

2010-04-21 Thread Chris



That's quick thinking, but they were still in the message they sent.
I know I have them all right here. My point being that anyone that got 
that message,

now has all our emails.


Your email is already available anyway. Everything posted here is 
archived at http://lists.php.net/ (http://news.php.net/php.db/47072) and 
 theaimsgroup.com (http://marc.info/?l=php-dbr=1b=201004w=2 - not as 
up to date but it'll find this convo eventually) and phpbuilder and 
other places too.


You're getting two emails because I habitually hit reply-all which will 
send you an email personally and one to the list.


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Re: [PHP-DB] Session Timeout question

2010-04-18 Thread Chris

Karl DeSaulniers wrote:

What is the best way to set a user timeout on a session?
Say if the user steps away from their computer for say 5 min,
and they come back to the page they were on, I want when the user clicks 
something
for the session to kick them off and redirect to login saying their 
session has timed out.

I have this code currently:


  /*Users timout*/
  function getIdle(){
  global $database;
  if($this-isGuest()) {
  if (!isset($_SESSION['timeout_idle'])) {
$_SESSION['timeout_idle'] = time() + GUEST_TIMEOUT;
} else {
if ($_SESSION['timeout_idle']  time()) {
//destroy session
return(true);
} else {
$_SESSION['timeout_idle'] = time() + GUEST_TIMEOUT;
return(false);
}
  }
  } else {
  if (!isset($_SESSION['timeout_idle'])) {
$_SESSION['timeout_idle'] = time() + USER_TIMEOUT;
} else {
if ($_SESSION['timeout_idle']  time()) {
//destroy session
return(true);
} else {
$_SESSION['timeout_idle'] = time() + USER_TIMEOUT;
return(false);
}
  }
  }
   }

But it doesn't time anything out.. I could walk away for an hour and 
come back and go to a link.

TIA,


Firstly - is it getting into this function (yep I ask stupid questions)? 
Which branch is it taking (guest or user)?


What values are USER_TIMEOUT and GUEST_TIMEOUT?

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Re: [PHP-DB] mySQL date query

2010-04-13 Thread Chris

Ron Piggott wrote:

I am trying to write a mySQL query on my stats table.  I am trying to
determine the number of records (users) during a 7 day period ending
yesterday.  I always to keep it current ... Yesterday will keep changing. 
In other words I want to know the number of users who accessed the web

site during seven full days.

This is the beginning of the query.  The date column is date.

SELECT count(`visits`) as users FROM `stats` WHERE `date`


The mysql manual is a good place to start.

http://dev.mysql.com/doc/refman/5.0/en/date-and-time-functions.html#function_date-sub

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Re: [PHP-DB] Postgres - how to skip 'sequence' columns

2010-04-12 Thread Chris

Gary . wrote:

Is it possible to skip column(s) in the target table when using
pg_copy_from? When I tried to bulk insert some data from a csv
file by way of pg_copy_from I received the error Warning:
pg_copy_from() [function.pg-copy-from]: Copy command failed:
ERROR: permission denied for relation xyz, pretty much as I
expected since things look like:

CREATE SEQUENCE xyz;
CREATE TABLE some_table (
  id int NOT NULL PRIMARY KEY DEFAULT nextval('xyz')
...
(i.e. the first column is automatically populated by the db itself).


It seems not from looking at the php manual.

You could use http://www.php.net/manual/en/function.pg-put-line.php instead.

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Re: [PHP-DB] phpmailer/mysql/ timout issues

2010-04-11 Thread Chris

ad wrote:

I'm running php 5.1.6 with mysql  5.0.45 on CentOS 5.3  box trying to
loop through a while statement to send about 3000 email using
phpmailer.  It's worked well in the past but after an upgrade it seems
to be timing out now


After an upgrade of what? php? mysql? phpmailer? the whole o/s?

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Re: [PHP-DB] Mysql completing Query fast but mysql-query() takes long time to return even single selects/updates

2010-04-11 Thread Chris

David Murphy wrote:

As you can see  PHP claims  it took 20 seconds for mysql-query() to return
but   mysql think is took around 1.0s

 
This is from our application 
I enabled profile in mysql to determine why an update took 20seconds.  As

you can see  MySQL reported no where near that amount of duration took
place. 
Is there any way I can dig into php and determine why  mysql client libs are

so slow (this is not using mysqlnd but  mysql-client-libs on CentOS using
5.3.2)


Is this a one-off thing or is it happening all the time?

If it's a one-off thing it could be a spurious result (maybe someone 
else was doing a mysqldump when your query ran, the dump blocks your 
query)..


What sort of mysql table is it? if it's innodb you can try it in a 
transaction and roll it back:


begin;
update blah;
rollback;

see how long it takes.

if it takes a short time in the mysql client, then try it in a php 
script from your other server.


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Re: [PHP-DB] reading PDF file into a DB

2010-04-07 Thread Chris

Vinay Kannan wrote:

Hello Guys,

I am working on a project, which requires a PDF file to be read page wise
into the DB, once it has been uploaded, the contents from the PDF would then
appear on a Flash screen.

I need help reading the contents of the PDF file into DB retaining the page
numbers, does anyone have an idea how this can be accomplished, i hope
someone here has done this before :)


http://www.php.net/manual/en/book.pdf.php

If there are no functions for reading a pdf, there are some links at the 
bottom of that page that might help.


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Re: [PHP-DB] Shopping cart application question

2010-04-03 Thread chris smith
 The  } else {  confuses PHP.  I am not sure what I should be doing.

You're missing at least one brace.

If the code you supplied is a copy of what you have, you're missing a
} for the end of the while loop and one for the end of the else
condition.

So it's treating } else { as part of the while construct (and while()
doesn't have anything like an else condition).

 if ( $_SESSION['user_reference']  0 ) {

snip

 $i=0;
 while ( $i  $cart_records_found ) {


} // end while


 } else {

 foreach ($_SESSION['order'] AS $key = $value ) {

 }


} // end else condition

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Re: [PHP-DB] Ldap sasl bind(gssapi problem)

2010-03-28 Thread Chris

???  wrote:

Hallo there everyone,
after finishing my server side configuration so as to have the
maximum security
i tried this morning to do a sasl bind with my ldap server ,
my file looks like that:

*$ldapbind=ldap_sasl_bind($ldapconn,NULL,NULL,GSSAPI,TEIPIR.GR
,ldapmaster,dn:cn=ldapmas...@teipir.gr,ou=kerberos,dc=teipir,dc=gr);*
*// verify binding*
*
*
*   ** ** if ($ldapbind) {*
*echo LDAP bind successful... . br /;*
* *
every other mech i use seems to work fine but only the gssapi is not
workign from what i can see on the log
i have tried most of the additional commands i found on the net like:

putenv(KRB5CCNAME={$_SERVER['KRB5CCNAME']});



*but still nothing *
*any idea to make the bind over gssapi so as to have the kerveros ticket
exchange actually working*


You may have better luck asking on the php-general mailing list, there 
are a lot more people subscribed to that.


I've never tried anything relating to kerberos so unfortunately I don't 
have any particular suggestions.


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Re: [PHP-DB] Building indexes

2010-03-18 Thread Chris

listread wrote:

Chris,

I just assumed that everyone on this list was using MySQL...  That's 
what we're using (v. 5.1.45 GA) with InnoDB as the engine.


Most people are but there are lots of types of databases out there :)

(I just read your tutorial at http://www.designmagick.com/article/16/  
It was very helpful - I look forward to checking out more of your 
articles.)


If it is just as efficient to use multiple separate indexes, that would 
make index building less complicated on our large db.


It is, though wildcard searches can't always use indexes.

If you do

field like 'abcdef%';

then an index can potentially be used because the db (mysql or 
otherwise) can look at the start of the string to see if it matches. The 
longer the string the more likely an index can be used (eg doing field 
like 'a%' probably won't use an index, it'll end up being quicker to 
scan the actual data).


If you do

field like '%abcdef%';

then an index can't be used since abcdef could appear anywhere in the 
string.


Without a large dataset, it hard to truly test a system and if you have 
a large dataset, like we do, it takes quite a while to build indexes.


Definitely, it's the best way to test and also the hardest since 
rebuilding the db takes so long.


Our project is a petition signature validation suite.  Since many of the 
handwritten names and addresses on petition sheets are difficult to 
read, the user needs to be able to do some fuzzy searching.   Sometimes 
it's easier to read the address than it is the name.   The zip code is 
usually easy to read.  We almost always need to use LIKE queries, since 
some part of the name or address is typically hard to read.  (We try to 
use as many of the leading characters as we can and wildcard the 
remaining.)


I'd suggest fulltext but that won't work with innodb, only myisam. You 
could do something like keep the addresses and names in a separate 
myisam table just for searching, though that means a whole new import 
process and also means you'd end up having to do two queries (maybe a 
subquery or join, you'd have to test) - one do to full text search and 
one to get the rest of the data based on the result of the first.


What do your queries end up looking like?

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Re: [PHP-DB] Building indexes

2010-03-17 Thread Chris

listread wrote:

Greetings!

We are working on a 4 million record db with about 55 fields.  We need 
to build indexes to speed queries, but it seems to take way too long.


I'm assuming your using mysql but that's just a guess.

What database? (mysql, oracle, postgres, firebird, sqlite, other)
If it's mysql, what db engine?


Here are some questions:

1) If a query uses two or three fields is it best to prepare an index 
with those two or three fields, or will the query be just as efficient 
if we build three separate index, one for each field?


Relates to above, but assuming mysql then it depends on what version.

multicolumn indexes work well in all mysql versions. separate indexes 
can be used and combined in newer versions (v5 I think it came in).


2) Is the index building process any slower, per index, if you are 
building more than one index at a time?


Most indexing I think takes an exclusive lock on the table, so index 1 
gets created, index 2 has to wait it's turn until index 1 finishes.


I wrote an article on this a while ago, might give you some more 
insights: http://www.designmagick.com/article/16/


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Re: [PHP-DB] oci_commit always returns true even when the transaction fails.

2010-03-16 Thread Chris

ZeYuan Zhang wrote:

Hi there.

Why oci_commit function always returns true even when the transaction fails.
I just copied the code in the php manual [Example 1636. oci_commit() example],
and runned it, the situation is as follows:

* The statements do commit at the moment when oci_commit executes.
* But some statements are committed to oracle successfully, when some fails.
  I think it cannot be called a transaction, and I did used
OCI_DEFAULT in the oci_execute function.

Code:
?php
$conn = oci_connect('scott', 'tiger');
$stmt = oci_parse($conn, INSERT INTO employees (name, surname) VALUES
('Maxim', 'Maletsky'));
oci_execute($stmt, OCI_DEFAULT);


Reading the docs (straight from 
http://www.php.net/manual/en/function.oci-commit.php).


A transaction begins when the first SQL statement that changes data is 
executed with oci_execute() using the OCI_NO_AUTO_COMMIT flag.


You need to

oci_execute($stmt, OCI_NO_AUTO_COMMIT);

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Re: [PHP-DB] oci_commit always returns true even when the transaction fails.

2010-03-16 Thread Chris

Christopher Jones wrote:



Chris wrote:
  ZeYuan Zhang wrote:
  Hi there.
 
  Why oci_commit function always returns true even when the transaction
  fails.
  I just copied the code in the php manual [Example 1636. oci_commit()
  example],
  and runned it, the situation is as follows:
 
  * The statements do commit at the moment when oci_commit executes.
  * But some statements are committed to oracle successfully, when some
  fails.
I think it cannot be called a transaction, and I did used
  OCI_DEFAULT in the oci_execute function.
 
  Code:
  ?php
  $conn = oci_connect('scott', 'tiger');
  $stmt = oci_parse($conn, INSERT INTO employees (name, surname) VALUES
  ('Maxim', 'Maletsky'));
  oci_execute($stmt, OCI_DEFAULT);
 
  Reading the docs (straight from
  http://www.php.net/manual/en/function.oci-commit.php).
 
  A transaction begins when the first SQL statement that changes data is
  executed with oci_execute() using the OCI_NO_AUTO_COMMIT flag.
 
  You need to
 
  oci_execute($stmt, OCI_NO_AUTO_COMMIT);
 

OCI_NO_AUTO_COMMIT is a recently introduced alias for OCI_DEFAULT, so
the original code is equivalent. This could be made clearer in the
oci_commit documentation, but is explained on
http://www.php.net/manual/en/function.oci-execute.php, which is where
the flag is actually used.


Fair enough, thanks for the clarification :)

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Re: [PHP-DB] Calculator

2010-03-16 Thread Chris

Karl DeSaulniers wrote:

Hello,
I have been asked to see if I can set up an online calculator.
I was wondering if anyone had some pointers on where I can lear/find
a script that calculates percentages.
The regular math part I think I can figure out.
Its not a complicated calc, just basic math and percentages calc, a 
payment calc if you will.


loan payments? a bank website should have something like that. search 
for loan payment calculator and you'll get tons of hits.


As for the maths behind it, I'm not sure.

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Re: [PHP-DB] 64-bit Linux -- Fatal ... undefined function mysql_connect()

2010-03-01 Thread Chris

andrew jarcho wrote:

Hello all,

I'm running Fedora 12 (64-bit), Apache 2.2.14, PHP 5.3.1, MySQL
5.1.42, on a Dell laptop.


snip


I get the message:

Fatal error: Call to undefined function mysql_connect()


snip


The output of my phpinfo() includes:


Is that from command line or webpage? They may read different php.ini files.

# php -i | grep mysql

return anything from the command line?

which config is it reading?

# php -i | grep php.ini

Is it the one you were editing previously?

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Re: [PHP-DB] Are join queries in phpMyAdmin a security hazard?

2010-02-28 Thread Chris

Ben Hubbell wrote:

Hello,

My web host does not have join queries in phpMyAdmin enabled. My web 
host is inexpensive, but their commitment to costumer service is 
inconsistent. They often dismiss bug reports as feature requests.


When pressed to enable join queries in phpMyAdmin several years ago, my 
web host stated that join queries in phpMyAdmin were a security hazard. 
Do you know if such a security hazard exists?


I've never used phpmyadmin as a query builder - can you really disable 
joins in there? Wow.


No way they are a security hazard.

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Re: [PHP-DB] Injection Attack?

2010-02-25 Thread Chris

Gary wrote:
I have a DB on a site that is not really up anymore (a redirect because of a 
merger), and it seems to have been attacked.


I always use REMOTE_IP so that I have a record and able to ban IP's of the 
endless form spammers, however on this attack, the IP listed is my local IP 
(actually my old one since I changed ISP's).


I was wondering how they did this and how do I protect on other DB's.

Some of the other injected text inot almost every field is.

1 AND USER_NAME() =

\'; DESC users; --

1\' OR \'1\'=\'1

There is plenty more, however they submitted the form about 12 times per 
second.


Any thoughts?


I guess you didn't use mysql_real_escape_string (or mysql_escape_string) 
in your queries.


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Re: [PHP-DB] Re: Need a tool for mysql file

2010-02-25 Thread Chris

Ferdi wrote:

-- Forwarded message --
From: nagendra prasad nagendra802...@gmail.com
To: PHP DB php-db@lists.php.net, phpexpe...@yahoogroups.com, php mysql 
php_mysql_usergr...@yahoogroups.com
Date: Thu, 25 Feb 2010 16:52:40 +0200
Subject: Need a tool for mysql file
Hi All,

I have a mysql database file of around 1 GB in size. Is their any tool which
which I can see all the database without uploading it on phpmyadmin on
localhost. I have tried to upload it on localhost but it said the file size
is too large  (I have changed the ini file as well but no luck ). I need a
tool with which I can see all the tables and the data in the file.

Best,

--
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Ubuntu Voice GTK+ Forum


Hi

Hove you made all the changes to the php.ini file?


That's pretty impractical for a 1g db.

Use rsync, scp or ftp which can handle large files.

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Re: [PHP-DB] Login query

2010-02-18 Thread Chris

Bastien Koert wrote:

On Thu, Feb 18, 2010 at 4:40 PM, Ron Piggott ron@actsministries.org wrote:

I am wondering what others do for a login query.  I think there could be
two results: correct e-mail  password; correct e-mail  wrong password

So far my login query is:

SELECT * FROM `member` WHERE `email` = '$my_email' AND `pass` LIKE
BINARY '$my_password' LIMIT 1

This wouldn't tell me if the user has the wrong password.  Is there a
better way to do this?

Ron






bad bad bad! never do a like on a password. If there are two passwords
that are close, the unauthorized user might get in when they
shouldn't.

There are two usual approaches:
1. Select the user (providing that the user is distinct) and compare
the password in PHP. On a match, allow access.
2. Select the user and password and see if the results return a row.
If no row is returned, then access is not granted. If there is a row,
then access is granted.


I'd also suggest that you don't distinguish between a correct username 
but wrong password and a correct username and right password.


If you say You got the right username but wrong password, a bad guy 
now has a point of attack .. If you say your username or password are 
incorrect you don't get that.


Check gmail or yahoo or even sourceforge for how they word such attempts.

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Re: [PHP-DB] php_warn

2010-02-16 Thread Chris

madunix wrote:

solved by setting error reporting to 0 in “configuration.php” file

$mosConfig_error_reporting = '0;


That hides the problem, it doesn't solve it.

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Re: [PHP-DB] IFNULL

2010-02-14 Thread Chris

Ron Piggott wrote:

How do I add  IFNULL  to the LEFT JOIN query?  I either want the result
from the database or a 0 instead of the word NULL

Ron

SELECT `store_product_profile`.`reference` , inventory.inventory, 
sold_1.quantity, sold_2.quantity, sold_3.quantity

FROM `store_product_profile`

LEFT JOIN (

SELECT `store_product_inventory_control`.`store_product_profile_reference`
, SUM( `store_product_inventory_control`.`quantity` ) AS inventory
FROM `store_product_inventory_control`
GROUP BY `store_product_inventory_control`.`store_product_profile_reference`
) AS inventory ON `store_product_profile`.`reference` =
`inventory`.`store_product_profile_reference`


You don't add it to the join, it goes on a field you're selecting.

select IFNULL(inventory.inventory, 0) AS blah, 

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Re: [PHP-DB] Getting total quantities

2010-02-14 Thread Chris

Karl DeSaulniers wrote:

Would it be?

$q = SUM(ProductStock) FROM products;

or

$q = SELECT SUM(ProductStock) AS ProductStock FROM products;

if I want to return $ProductStock as the value?


This one.

The AS gives it an alias (or shortcut) to make it easier to find in 
mysql_fetch_array etc.


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Re: [PHP-DB] Getting total quantities

2010-02-14 Thread Chris

Chaitanya Yanamadala wrote:

Have you tried using it like this

*select count(*) from products;*


This will give you the number of rows in the table, not what Karl wants.

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Re: [PHP-DB] Getting total quantities

2010-02-14 Thread Chris

Karl DeSaulniers wrote:

Ok, sweet, then I am on the right track.
Now I did notice that I forgot the SELECT in the first query, does that 
matter?

Can I just start out with SUM?


No - that's invalid sql.

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Re: [PHP-DB] upload multiple files and rename wih time()

2010-02-07 Thread Chris

Emiliano Boragina wrote:

Hello php fellows,

 


I have two codes to upload multiple files, works very well, but I cant
rename the files... really i dont know...


The code looks ok. Do you get an error message? If not, turn up 
error_reporting and enable display_errors:


error_reporting(E_ALL);
ini_set('display_errors', true);

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Re: [PHP-DB] Cross reference query help

2010-02-07 Thread Chris

Ron Piggott wrote:

The following is a query I am working on today.  I need help tweaking on it.

What I am trying to get for results from the query are where there are
rows in either table, not all 3 tables linked together.

In other words I am trying to INNER JOIN these two pairs of tables for
possible results:

`store_product_profile` and `paypal_cart_info`

OR

`store_product_profile` and `mail_order_cart`

SELECT `store_product_profile`.`product_name`
FROM (
`store_product_profile`
INNER JOIN `paypal_cart_info` ON `store_product_profile`.`reference` =
`paypal_cart_info`.`itemnumber`
)
INNER JOIN `mail_order_cart` ON `store_product_profile`.`reference` =
`mail_order_cart`.`store_product_profile_reference`
WHERE `store_product_profile`.`discontinued` =0
AND `store_product_profile`.`reference` =7

Finally I need help with the GROUP BY syntax also.  I only want the name
of the product once, not if it was in several previous purchases.

Any help is appreciated.


So a product is either in the paypal_cart_info table or it's in the 
mail_order_cart table ?


Though maybe this is a bad example - it's looking for reference=7 - you 
can check for that in your other tables since it seems to be a foreign 
key of some sort I'm guessing.


You could use a union (or union all is probably better in this case) to 
bring them together.



select itemnumber
from paypal_cart_info
where itemnumber=7
union all
select store_product_profile_reference
from mail_order_cart
where store_product_profile_reference=7

put that into your other query and add your group by:

select product_name
from store_product_profile
where
  reference in
  (
select itemnumber
from paypal_cart_info
where itemnumber=7
union all
select store_product_profile_reference
from mail_order_cart
where store_product_profile_reference=7
  )
  and
  discontinued=0
group by
  product_name;


If you put the check for '7' in the paypal and mail_order_cart tables 
it'll be faster than putting it in the bigger query.


The smaller subquery will return less results (I'm guessing 0,1, or 2 
results) and therefore the discontinued check will be quicker and so 
will the group by.


If you don't put the check for '7' in the subquery, then mysql will have 
to go through *all* entries in paypal_cart_info and mail_order_cart 
(which may or may not be big tables), then make sure there is a 
reference entry in product_profile (which could be a pretty big table) 
and finally at the end of all that, check if reference '7' is in that 
list and it's not discontinued (then the group by etc).


So in general, the further down the query chain you can put your where 
clauses to reduce the number of rows returned, the better.


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Re: [PHP-DB] Storing Images #2

2010-02-04 Thread Chris

elk dolk wrote:

On 3 February 2010 16:07,   wrote:


I currently have all my images referenced by url in my database and stored
in a folder/s and I think I will keep it that way...


..


If you put the images OUTSIDE of the webroot/docroot/public_html

folder (whatever you have), then a user cannot directly navigate to
the file.

e.g.
 /home/sites/your_site/public_html/images/image1.jpg

 http://www.yoursite.com/images/image1.jpg would probably work.

But ...

/home/sites/your_site/public_html/getImage.php
/home/sites/your_site/hidden_images/image1.jpg


Now, there is no way I can load image1.jpg from my browser. I have to

use getImage.php, which I assume would require me to login or
authenticate myself in some way.
--
I have my photos in /public_html/img/gid directory and with this path:
img src='http://www.mydomain.com/img/{$gid}/{$photoFileName}' in getImage.php 
the server displays the photos.

Now if I put my photos outside of the public_html like this: 


/hidden_images/img/gid

what would be the correct path to the photos in the getImage.php script?


Do you mean what url? You'll need a script to pull them from outside the 
document root. The advantage of this is you can do authentication checks 
before displaying the image. The disadvantage is the web-server isn't 
serving the images directly so there will be a slow down.


So you point your images to

getimage.php?image=123456

and getimage.php does your authentication checks if necessary then pulls 
the image back using something like http://www.php.net/fpassthru


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Re: [PHP-DB] PHP and MYSQL Update problem

2010-01-26 Thread Chris

Manu Gupta wrote:

try ..
$q = addslashes(UPDATE episodes SET episode_title = '$_POST[episode_title]'
,
episode_scheduleddate = .strtotime($_POST['episode_scheduleddate']).
, episode_description = '$_POST[episode_description]' WHERE episode_id
= $_POST[episode_id]);

or try

$q = UPDATE episodes SET episode_title = '{$_POST[episode_title]}' ,
episode_scheduleddate = {.strtotime($_POST['episode_scheduleddate'])}.
, episode_description = '{$_POST[episode_description]}' WHERE episode_id
= {$_POST[episode_id]};


Good idea but you don't addslashes the whole query (and addslashes is 
the wrong thing to use).


Use mysql_real_escape_string around bits and pieces you want to escape:

$q = update episodes set episode_title=' . 
mysql_real_escape_string($_POST['episode_title']) . ', ..


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Re: [PHP-DB] Automatic logoff

2010-01-26 Thread Chris

listread wrote:

Bruno,

Thanks for the heads up on the php configuration.  I'll check that out.

We also need to write some data to a database, things like logout time.  
That means running a script for some other php code.


There are probably a number of situations where the onUnload thing won't 
work including browser crashes, some browsers may not support it, will 
it work if you have multiple browser tabs open and close one (something 
you'll have to research) etc, so be aware that you're not going to get 
this 100% right.


If you just want the timing, I'd do it the other way.

Each time their session is checked (on page load), update the end 
time. In db terms:


update session set logout_time=NOW() where session_id='X';

That way you're always going to get at least an idea of how long their 
session lasts but you won't get reading time on the page (ie it takes 
me 2 mins to read something on the page, the logout_time will be 2 
minutes before I actually close it).


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Re: [PHP-DB] Procedure Parameter OUT values

2010-01-26 Thread Chris

WebPat wrote:

Chris wrote:

WebPat wrote:
I am surprised by the order of the data returned from my stored 
procedure, and that it appears associated with the incorrect variables.
Apparently the data is returned entirely positionally, without 
consideration for the variable names. So, the names of the OUT 
parameters in the procedure appear to be invisible outside of the 
procedure. Although I pass in variables with the same names as the 
Parameters, they are filled positionally - in the wrong variables - 
because in this case I had two variables reversed positionally.
When I retrieve them using fetch_assoc, the wrong data appears in the 
result.


I'd probably find a more targeted mailing list (a specialized one for 
your database - whatever it is) and see if they can offer any 
suggestions.




My database is Mysql. The data seems to display properly there. I'm 
accessing the database with procedures that are part of PHP and that is 
where I believe the problem is. That's why I asked it on this Newsgroup.


I got it to work by putting my parameters in the proper order. I know 
this is how function and procedure calls normally work, but the 
documentation of fetch_assoc() leads in another direction. It looks like 
the Associations are created within my php and not carried from the 
database for stored procedures. I wonder if PHP does this for all 
databases? I think this differs from Select * From Table. Certainly 
could use another sentence in the documentation.


You can submit documentation patches and/or submit a note for that 
situation on that page in the manual.


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Re: [PHP-DB] Procedure Parameter OUT values

2010-01-24 Thread Chris

WebPat wrote:
I am surprised by the order of the data returned from my stored 
procedure, and that it appears associated with the incorrect variables.
Apparently the data is returned entirely positionally, without 
consideration for the variable names. So, the names of the OUT 
parameters in the procedure appear to be invisible outside of the 
procedure. Although I pass in variables with the same names as the 
Parameters, they are filled positionally - in the wrong variables - 
because in this case I had two variables reversed positionally.
When I retrieve them using fetch_assoc, the wrong data appears in the 
result.


I'd probably find a more targeted mailing list (a specialized one for 
your database - whatever it is) and see if they can offer any suggestions.


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Re: [PHP-DB] result set in php pagination

2010-01-24 Thread Chris

Joe Keenan wrote:
Thanks very much Bastien. I haven't the faintest idea why but that 
simple change in the code sorted all of this. The pagination links now 
follow through with the complete result set of my query.


I will now have to read around this to discover why the change works.


By putting it in the url means it's not a POST variable any more, it is 
now a GET variable.


REQUEST covers both (and more) - so if it appears in GET, it will be set 
to that. If it appears in POST, it'll use that instead.


Also nobody's mentioned you should use mysql_real_escape_string when you 
do your query otherwise your site will (eventually) have problems with 
sql injection.


$query = SELECT article_id, author_name, category_name, title,
article_caption, date_format(magazine_date, '%M, %Y') as newdate
FROM articles WHERE author_name = '$author_name' ORDER BY
magazine_date ASC LIMIT $offset, $rowsperpage;

becomes:

$query = SELECT article_id, author_name, category_name, title,
article_caption, date_format(magazine_date, '%M, %Y') as newdate
FROM articles WHERE author_name = ' . 
mysql_real_escape_string($author_name) . ' ORDER BY

magazine_date ASC LIMIT $offset, $rowsperpage;

You won't see much difference if you print it out but if you put things 
like a single quote in your name search, it will be handled now and not 
cause a mysql error.



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Re: [PHP-DB] Transferring rows between 2 databases on 2 web servers

2010-01-17 Thread Chris

Ferdi wrote:

Hi Everybody,

There are n number of web servers all having the same Linux-Apache-MySQL-Php
setup, with identical databases. Each of these servers functions as a
billing server at a store of my company. Now I am required to set up a
master server that will copy all data from each of the store servers. All I
wish to know is:

How can a page on the master server obtain data from a store database by
calling a page located on the store server?

I do not wish to access a store database directly, but through a page on the
store server. Specifically, how can a web page get data from another web
page on another server.


wget (from linux command line)
curl (from linux command line or using the php curl functions)
file_get_contents (php function)
fopen (php function)

There are a number of ways but you'll most likely run into timeout issues.

I think you are much better off writing a script that does it 
command-line and connects to the remote database and pulls the data 
back. Then if the script takes an hour to run you won't have any 
problems - you definitely will if you do it through a web page.


I'd also say security would be easier to implement via direct database 
access (firewalls, mysql user limits, ssl-only connections).


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Re: [PHP-DB] printf and unsecable char

2010-01-04 Thread Chris

Jean-Philippe Battu wrote:

Hello

I would like  to print a string formatted on the right side and fill in 
the left side with the unsecable character [nbsp;]


I read in the printf command I could use : printf( %#30s , $mystring ) ;
to display $mystring string with the character # before (on the left)

and I try to replace # by nbsp; but I can't find a solution

Do you know the solution to write the command:  printf( 
%nbsp;30s , $mystring ) ;

or something like that !


echo str_repeat('nbsp;', 30);

(if I understand what you're trying to do correctly).

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Re: [PHP-DB] auto creation of email IDs

2009-12-16 Thread Chris

Vinay Kannan wrote:

Hey Guys,

I've been at this for couple of days now, and have no clue where to start,
and was almost thinking about scrapping the project, It would be great help
if anyone can give me some advice, or guide me in the right direction.

I have a portal, where users would come in and register and create an
account, as soon as an account is created, I want to be able to auto create
an email ID for them, the server would be Linux, any ideas on how this can
be done.

And also an option of creating a temporary email ID, upon creating a topic
or some kind of a post.

Could anyone guide me in the right direction or help me on this one, please
?


I assume email id means email address or email account.

Yes, you can do it - postfix supports talking to a database. Exim and 
sendmail might also support this, I don't have any experience with them 
though.


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Re: [PHP-DB] Hello

2009-12-15 Thread Chris

Karl DeSaulniers wrote:

What does this do exactly?
Documentation was a bit fuzzy for me.
Is it needed at all times to protect with?


Per the docs:

prepends backslashes to the following characters: \x00, \n, \r, \, ',  
and \x1a.


So anything that has a null character, a newline (windows/linux/mac), 
single and double quotes and \x1a (not sure what that is) is escaped and 
ready to be put in a query.


If you don't quote those characters someone could put one of those 
characters in a query and cause problems - starting off with an invalid 
query but possibly ending up worse.


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Re: [PHP-DB] Hello

2009-12-15 Thread Chris


addslashes doesn't take encoding's into account.

http://shiflett.org/blog/2006/jan/addslashes-versus-mysql-real-escape-string

goes into some details.

Karl DeSaulniers wrote:

So what's the difference with that and addslashes() ?

Karl

Sent from losPhone

On Dec 15, 2009, at 3:50 PM, Chris dmag...@gmail.com wrote:


Karl DeSaulniers wrote:

What does this do exactly?
Documentation was a bit fuzzy for me.
Is it needed at all times to protect with?


Per the docs:

prepends backslashes to the following characters: \x00, \n, \r, \, ', 
 and \x1a.


So anything that has a null character, a newline (windows/linux/mac), 
single and double quotes and \x1a (not sure what that is) is escaped 
and ready to be put in a query.


If you don't quote those characters someone could put one of those 
characters in a query and cause problems - starting off with an 
invalid query but possibly ending up worse.


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Re: [PHP-DB] Random pick

2009-12-14 Thread Chris

David McGlone wrote:

Hi everyone,

I've been lurking in the shadows on the list for quite some time and now I'm 
in need of a little info or advise.


I'm looking for a way to grab a record out of a database on a certain day each 
month and I'm wondering if this can be accomplished with just a mysql query or 
would I need to use PHP also?


A mysql query would do it but you'd use something to talk to mysql and 
process the results (whether it's php, perl, python, ruby etc depends on 
your other requirements).


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Re: [PHP-DB] Hello

2009-12-14 Thread Chris

Karl DeSaulniers wrote:

HI,
Thanks for your response. Here is my query. UserID is auto incrament and 
UserLastLogin is a current_timestamp.


$query_users = INSERT INTO users(UserID, Username, UserEmail, 
UserPassword, UserFirstName, UserLastName, UserCompany, UserAddress, 
UserAddress2, UserCity, UserState, UserCountry, UserZip, UserPhone, 
UserFax, UserEmailVerified, UserRegistrationDate, UserVerificationCode, 
UserIP, UserLastLogin)

VALUES('NULL','.$Username.','.$UserEmail.','.$UserPassword.','.$UserFirstName.','.$UserLastName.','.$UserCompany.','.$UserAddress.','.$UserAddress2.','.$UserCity.','.$UserState.','.$UserCountry.','.$UserZip.','.$UserPhone.','.$UserFax.','.$UserEmailVerified.','.$UserRegistrationDate.','.$UserVerificationCode.','.$UserIP.', 
now());


This works as far as populating the database, but my results page does 
not return anything.


Only if the VALUES is set like this:

VALUES('NULL','.$Username=$_POST['Username'].','.$UserEmail=$_POST['UserEmail'].','.$UserPassword=$_POST['UserPassword'].','.$UserFirstName=$_POST['UserFirstName'].','.$UserLastName=$_POST['UserLastName'].','.$UserCompany=$_POST[$UserCompany].','.$UserAddress=$_POST['UserAddress'].','.$UserAddress2=$_POST['UserAddress2'].','.$UserCity=$_POST['UserCity'].','.$UserState=$_POST['UserState'].','.$UserCountry=$_POST[$UserCountry].','.$UserZip=$_POST['UserZip'].','.$UserPhone=$_POST['UserPhone'].','.$UserFax=$_POST[$UserFax].','.$UserEmailVerified=$_POST[$UserEmailVerified].','.$UserRegistrationDate=$_POST[$UserRegistrationDate].','.$UserVerificationCode=$_POST['UserVerificationCode'].','.$UserIP=$_POST[$UserIP].', 
now());


but some do not work with this setup. variables like $UserEmailVerified, 
$UserRegistrationDate and $UserIP are not created from the form that was 
submitted.

for example, User IP date is created like this.

$UserIP = md5($_SERVER[REMOTE_ADDR]);


Problem 1 is sql injection. Wrap each variable in a 
mysql_real_escape_string call:


insert into table (...) values (' . mysql_real_escape_string($username) 
. ' 


also quoting 'NULL' means it will add 'NULL' as the id - not what you 
want. You can leave out the column to use the default from the database.


Any errors from mysql?

Add:
echo mysql_error();

after your insert call.


-

Below is a snip of how I retrieve the info on the result page (dont want 
to clutter with whole code. also $fieldOne etc are MySql wildcards '%' 
from some dropdown lists that show before this code is executed. The 
results from adding show up fine there.)


$query_users = SELECT * FROM users WHERE UserID LIKE '$fieldOne' AND 
Username LIKE '$fieldTwo' AND UserEmail LIKE '$fieldThree' AND 
UserPassword LIKE '$fieldFour' AND UserFirstName LIKE '$fieldFive' AND 
UserLastName LIKE '$fieldSix' AND UserCompany LIKE '$fieldSeven' AND 
UserAddress LIKE '$fieldEight' AND UserAddress2 LIKE '$fieldNine' AND 
UserCity LIKE '$fieldTen' AND UserState LIKE '$fieldEleven' AND 
UserCountry LIKE '$fieldTwelve' AND UserZip LIKE '$fieldThirteen' AND 
UserPhone LIKE '$fieldFourteen' AND UserFax LIKE '$fieldFifteen' AND 
UserEmailVerified LIKE '$fieldSixteen' AND UserRegistrationDate LIKE 
'$fieldSeventeen' AND UserVerificationCode LIKE '$fieldEighteen' AND 
UserIP LIKE '$fieldNineteen' AND UserLastLogin LIKE '$fieldTwenty' LIMIT 
$min, $max_results;


Again you need to escape all your data (except $min, $max_results - just 
make sure they are always integers).


I'm assuming there are no errors reported by mysql.

To debug this, I'd simplify the query and work out which bit isn't 
matching what you want (it could be $fieldOne isn't quite what you 
expect, or it could be $fieldEleven or $fieldEighteen or ..).


Start off with one field, then add another and go from there.

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Re: [PHP-DB] Mysql query

2009-12-14 Thread Chris

ron.pigg...@actsministries.org wrote:

The query from my previous post was only part of a larger query.  This is
the entire query:

SELECT GREATEST( IF( CURDATE( ) = DATE_SUB( DATE( FROM_UNIXTIME(
1239508800 ) ) , INTERVAL LEAST( 14, (

SELECT COUNT( * )
FROM `verse_of_the_day_Bible_verses`
WHERE seasonal_use =1 ) )
DAY )
AND CURDATE( ) = DATE( FROM_UNIXTIME( 1239508800 ) ) , 1, 0 ) , IF(
CURDATE( ) = DATE_SUB( DATE( 2009 -12 -25 ) , INTERVAL LEAST( 14, (

SELECT COUNT( * )
FROM `verse_of_the_day_Bible_verses`
WHERE seasonal_use =2 ) )
DAY )
AND CURDATE( ) = DATE( 2009 -12 -25 ) , 2, 0
)
) AS verse_application


It took me a while to work out what this was trying to do, that's 
complicated.


Reformatted a little:

SELECT
  GREATEST(
IF
(
  CURDATE() =
DATE_SUB(
DATE(FROM_UNIXTIME(1239508800)),
INTERVAL LEAST(14, (SELECT 1)) DAY)
  AND CURDATE() = DATE(FROM_UNIXTIME(1239508800)),
  1,
  0
),
IF
(
  CURDATE() =
DATE_SUB(
  DATE('2009-12-25'),
  INTERVAL LEAST(14, (SELECT 2)) DAY)
  AND CURDATE() = DATE('2009-12-25'),
  2,
  0
)
  ) AS verse_application;

(which isn't much better in email).

You're not getting '2' because the second part is returning 0.

I substituted dummy variables for your subqueries (select 1 and select 2).

SELECT COUNT( * )
FROM `verse_of_the_day_Bible_verses`
WHERE seasonal_use =2;

What does that return by itself?

that is what your query will run instead of my 'select 2'.

That in turn goes into the

select least(14, result_from_above_query);

and takes that away from date('2009-12-25');

If the current date is not in that range, it will return 0.

Here's the second part of your query isolated for you to test:

SELECT
  IF
(
  CURDATE() =
DATE_SUB(
  DATE('2009-12-25'),
  INTERVAL LEAST(14, (SELECT COUNT(*) FROM 
verse_of_the_day_Bible_verses WHERE seasonal_use=2)) DAY)

AND CURDATE() = DATE('2009-12-25'),
2,
0
  )
;


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Re: [PHP-DB] Hello

2009-12-14 Thread Chris

Karl DeSaulniers wrote:

Hi Chris,

On Dec 14, 2009, at 8:09 PM, Chris wrote:




Problem 1 is sql injection. Wrap each variable in a 
mysql_real_escape_string call:


insert into table (...) values (' . 
mysql_real_escape_string($username) . ' 


At one point I did have the mysql_real_escape_string() and it worked the 
same as without as far as populating the database.


Did you try names with single quotes? (Tim O'Reilly is a common example 
to try).



But when I would view results, it didnt read anything from the database.


Sure it went in? Did you see the data when you viewed the table in 
phpmyadmin or some other tool?




Again you need to escape all your data (except $min, $max_results - 
just make sure they are always integers).


Those are so I can control the number of items shown per page.


I realise that. mysql_real_escape_string is used for data in your query, 
and may cause problems if used in limit clauses. If you end up with this 
for example:


select * from table limit mysql_real_escape_string('blah');

of course it's not going work.

Hence the check to make sure $min and $max_results are int's before 
passing them to the query so if anyone messes with them it won't break 
your queries.


if (!is_int($min)) {
  $min = 0;
}

if (!is_int($max_results)) {
  $max_results = 5;
}

Basically the result page would not show anything in the database unless 
it was inserted in the database using the $_POST method.


That still suggests an error with the insert.

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Re: [PHP-DB] Random pick

2009-12-14 Thread Chris

David McGlone wrote:

On Monday 14 December 2009 21:02:37 Chris wrote:

David McGlone wrote:

Hi everyone,

I've been lurking in the shadows on the list for quite some time and now
I'm in need of a little info or advise.

I'm looking for a way to grab a record out of a database on a certain day
each month and I'm wondering if this can be accomplished with just a
mysql query or would I need to use PHP also?

A mysql query would do it but you'd use something to talk to mysql and
process the results (whether it's php, perl, python, ruby etc depends on
your other requirements).



What I'm trying to do is to have a record picked from the database at random 
on the 1st of every month and display it on the page. Here is some code I have 
been working with:


$query = SELECT DATEADD(mm, DATEDIFF(mm,0,getdate()), 0);
$result = @mysql_query($query);
if (!$result){

$query = SELECT * FROM monthlyPooch ORDER BY RAND() LIMIT 1;
$result = @mysql_query($query);

while ($row = mysql_fetch_array($result)){
echo $row[poochName] ;
echo $row[Birthdate];

}
}


You can check the day of the month in php then do your other query:

$today = date('j');

if ($today !== 1) {
  echo Today isn't the first. No need to continue.\n;
  exit;
}
..
random query etc here.

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