[PHP] Undefined index....
I have inherited a mess of a home-grown PHP framework that literally
fills the error_log with 100's of thousands of messages each day. First
order of business was rotating the logs, now we are working through each
error to solve them. This is a fairly basic error, but I for the life of
me cannot remember what the solution is.
I have a recursive function that reads from XML files and replaces xi:
include directives. It looks like this -
function includeXML($file, $locale, $url, $level = 1) {
// stuff
while(($line = fgets($fp)) !== false) {
if($pos === false) {
$xml .= $line;
} else {
includeXML('repository/' . $included, $locale, (int)$level
+ $pos - 1);
}
}
}
Why do I get the notice that $xml is an undefined index? I do not want
to suppress the notice, I just want to take care of it properly. I
attempted setting $xml within the function but then the whole function
fails for some reason in the depths of this hideous framework. Can
anyone provide any insight? TVMIA!
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Re: [PHP] Undefined index....
Hi,
Two questions:
Where is $xml defined and where is $pos defined?
HTH
Kind regards/met vriendelijke groet,
Serge Fonville
http://www.sergefonville.nl
Convince Microsoft!
They need to add TRUNCATE PARTITION in SQL Server
https://connect.microsoft.com/SQLServer/feedback/details/417926/truncate-partition-of-partitioned-table
2013/3/15 Jay Blanchard jay.blanch...@sigmaphinothing.org
I have inherited a mess of a home-grown PHP framework that literally fills
the error_log with 100's of thousands of messages each day. First order of
business was rotating the logs, now we are working through each error to
solve them. This is a fairly basic error, but I for the life of me cannot
remember what the solution is.
I have a recursive function that reads from XML files and replaces xi:
include directives. It looks like this -
function includeXML($file, $locale, $url, $level = 1) {
// stuff
while(($line = fgets($fp)) !== false) {
if($pos === false) {
$xml .= $line;
} else {
includeXML('repository/' . $included, $locale, (int)$level +
$pos - 1);
}
}
}
Why do I get the notice that $xml is an undefined index? I do not want to
suppress the notice, I just want to take care of it properly. I attempted
setting $xml within the function but then the whole function fails for some
reason in the depths of this hideous framework. Can anyone provide any
insight? TVMIA!
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Re: [PHP] Undefined index....
[snip] Two questions: Where is $xml defined and where is $pos defined? [/snip] $xml is defined in other functions, just not in this function. $pos is irrelevant to the question - it is just the string position within the file. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Undefined index....
So basically, $xml is out of scope for this function and you are appending to a nonexisting variable? Kind regards/met vriendelijke groet, Serge Fonville http://www.sergefonville.nl Convince Microsoft! They need to add TRUNCATE PARTITION in SQL Server https://connect.microsoft.com/SQLServer/feedback/details/417926/truncate-partition-of-partitioned-table 2013/3/15 Jay Blanchard jay.blanch...@sigmaphinothing.org [snip] Two questions: Where is $xml defined and where is $pos defined? [/snip] $xml is defined in other functions, just not in this function. $pos is irrelevant to the question - it is just the string position within the file. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Undefined index....
Jay Blanchard wrote:
I have inherited a mess of a home-grown PHP framework that literally fills the
error_log with 100's of thousands of messages each day. First order of business
was rotating the logs, now we are working through each error to solve them. This
is a fairly basic error, but I for the life of me cannot remember what the
solution is.
I have a recursive function that reads from XML files and replaces xi: include
directives. It looks like this -
function includeXML($file, $locale, $url, $level = 1) {
// stuff
$xml = '';
Should work here ...
Since the call below is ADDING to $xml you do need something existing to add to
so what does that give?
while(($line = fgets($fp)) !== false) {
if($pos === false) {
$xml .= $line;
} else {
includeXML('repository/' . $included, $locale, (int)$level + $pos -
1);
}
}
}
Why do I get the notice that $xml is an undefined index? I do not want to
suppress the notice, I just want to take care of it properly. I attempted
setting $xml within the function but then the whole function fails for some
reason in the depths of this hideous framework. Can anyone provide any insight?
TVMIA!
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Re: [PHP] Undefined index....
[snip]
function includeXML($file, $locale, $url, $level = 1) {
// stuff
$xml = '';
Should work here ...
Since the call below is ADDING to $xml you do need something existing
to add to so what does that give?
[/snip]
Thanks Lester, that worked. I had just put that in the wrong place.
*slaps forehead*
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[PHP] Undefined Index ...confusion
I keep getting this error while trying to use the field 'ID' to pass in a url.. And it's odd because the query is pulling everything BUT the ID which is the first field... code: a href=view.php?ID=?php echo $_SESSION['fullRestaurantList']['ID']??php echo htmlspecialchars(stripslashes($_SESSION['fullRestaurantList'][$i]['name'])); ? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Undefined Index ...confusion
Miller, Terion wrote: I keep getting this error while trying to use the field 'ID' to pass in a url.. And it's odd because the query is pulling everything BUT the ID which is the first field... code: a href=view.php?ID=?php echo $_SESSION['fullRestaurantList']['ID']??php echo htmlspecialchars(stripslashes($_SESSION['fullRestaurantList'][$i]['name'])); ? We're going to need to know how the $_SESSION['fullRestaurantList'] gets populated. Also, where do you define $i? Is $i the ID? Seemed like you've built an array of arrays and you may want $_SESSION['fullRestaurantList'][$i]['ID'], or just $i. This is all speculation from the 2 lines of code I've seen though. - Kyle
Re: [PHP] Undefined Index ...confusion
On 7/23/09 9:24 AM, Kyle Smith kyle.sm...@inforonics.com wrote:
Miller, Terion wrote:
I keep getting this error while trying to use the field 'ID' to pass in a url..
And it's odd because the query is pulling everything BUT the ID which is the
first field...
code:
a href=view.php?ID=?php echo $_SESSION['fullRestaurantList']['ID']??php
echo
htmlspecialchars(stripslashes($_SESSION['fullRestaurantList'][$i]['name'])); ?
We're going to need to know how the $_SESSION['fullRestaurantList'] gets
populated. Also, where do you define $i? Is $i the ID? Seemed like you've
built an array of arrays and you may want
$_SESSION['fullRestaurantList'][$i]['ID'], or just $i. This is all speculation
from the 2 lines of code I've seen though.
- Kyle
The full script is (I have my Entourage email settings on html so I hope this
displays ok for you all---seems I've been told it turns into a mess in some
views) :
?php
// Check
if page is set to show all
if(isset($_GET['show']) $_GET['show'] == 'all')
{ unset($_SESSION['results']);
unset($_SESSION['searchname']);
unset($_SESSION['address']);
}//
Check if there was an empty search sent
if(isset($_SESSION['noVarsSent'])){
echo pbNo values were submitted for the
search./b/p; // Unset it so a reload
of page doesn't redisplay the error
unset($_SESSION['noVarsSent']); //
unset($_SESSION['results']);}
// Check if full list of restaurants has been created and stored
yet// Store full results in $_SESSION to
limit database hits
if(!isset($_SESSION['fullRestaurantList']))
{ // List not grabbed yet, so run query
and store in $_SESSION
//check for rangeif
(!(isset($rangenum))) {
$rangenum = 1; }
// Grab all restaurants in alphabetical order
$sql = SELECT restaurants.ID, name, address,
inDate, inType, notes, critical, cviolations, noncritical FROM restaurants,
inspections WHERE restaurants.name != '' AND restaurants.ID = inspections.ID
ORDER BY name;; $result =
mysql_query($sql) or die(mysql_error());
//trying to grab it by ranges from the db?
$rows = mysql_num_rows($result);
$page_rows = 100;
$last_row = ceil($rows/$page_rows);
if ($rangenum 1)
{ $rangenum = 1;
} elseif ($rangenum
$last_row) {
$rangenum = $last_row; }
//This sets the
range to display in our query $max =
'limit ' .($rangenum - 1) * $page_rows .',' .$page_rows;
// Process all results into
$_SESSION array
$position = 1;
Re: [PHP] Undefined Index ...confusion
Miller, Terion wrote: On 7/23/09 9:24 AM, Kyle Smith kyle.sm...@inforonics.com wrote: Miller, Terion wrote: I keep getting this error while trying to use the field 'ID' to pass in a url.. And it's odd because the query is pulling everything BUT the ID which is the first field... code: a href=view.php?ID=?php echo $_SESSION['fullRestaurantList']['ID']??php echo htmlspecialchars(stripslashes($_SESSION['fullRestaurantList'][$i]['name'])); ? We're going to need to know how the $_SESSION['fullRestaurantList'] gets populated. Also, where do you define $i? Is $i the ID? Seemed like you've built an array of arrays and you may want $_SESSION['fullRestaurantList'][$i]['ID'], or just $i. This is all speculation from the 2 lines of code I've seen though. - Kyle The full script is (I have my Entourage email settings on html so I hope this displays ok for you all---seems I've been told it turns into a mess in some views) : It sure did turn into a big mess. Could you try using a pastebin service? You should do this as a general best-practice anyway. Long email threads tend to turn people off to helping you. Go here: http://pastebin.ca/ Paste your code and select PHP for Syntax Highlighting, then click submit. You'll be given a short URL to share with the thread that will bring us to an easy-to-read version of your code. - Kyle
[Fwd: Re: [PHP] Undefined Index ...confusion]
Sorry, list, I did a reply instead of a reply-to-all. This is what I
sent to Miller, Terion
Miller, Terion wrote:
Thanks for the link Kyle!! Great thing there...(seriously I didn't know...I
learn something everyday)
Anyways the link to my script is: http://pastebin.ca/1504393
Your email client is annoying, it doesn't quote. Haha.
Anyway, so, you're loading up that array with arrays of arrays, here:
1.
$position = 1;
2.
3.
while ($row = mysql_fetch_array
http://www.php.net/mysql_fetch_array($result))
4.
{
5.
$_SESSION['fullRestaurantList'][$position] = $row;
6.
$position++;
7.
}
8.
9.
$_SESSION['totalNumberOfRestaurants'] = $position;
So, if you get 7 rows. Your array will have:
Array = (Row 1 Data)
Array = (Row 2 Data)
.. etc
You do not have ['fullRestaurantList']['ID']. In the page you're
referencing you use something like
$_SESSION['fullRestaurantList'][$i]['SomeValue']. I assume $i is the
Position in the array, so you likely want to use
$_SESSION['fullRestaurantList'][$i]['ID'] to get the ID field from that row.
If you need a quick dump to better understand what data you have in your
session, try making a page called session_dump.php in the same directory
with this source:
pre? print_r($_SESSION) ?/pre
That will give you a good idea of what your session array looks like,
and you should see clearly that ['fullRestaurantList']['ID'] does not exist.
Hope this helps!
- Kyle
Re: [Fwd: Re: [PHP] Undefined Index ...confusion] (RESOLVED)
Thanks
On 7/23/09 9:52 AM, Kyle Smith kyle.sm...@inforonics.com wrote:
Sorry, list, I did a reply instead of a reply-to-all. This is what I
sent to Miller, Terion
Miller, Terion wrote:
Thanks for the link Kyle!! Great thing there...(seriously I didn't know...I
learn something everyday)
Anyways the link to my script is: http://pastebin.ca/1504393
Your email client is annoying, it doesn't quote. Haha.
Anyway, so, you're loading up that array with arrays of arrays, here:
1.
$position = 1;
2.
3.
while ($row = mysql_fetch_array
http://www.php.net/mysql_fetch_arrayhttp://www.php.net/mysql_fetch_array($result))
4.
{
5.
$_SESSION['fullRestaurantList'][$position] = $row;
6.
$position++;
7.
}
8.
9.
$_SESSION['totalNumberOfRestaurants'] = $position;
So, if you get 7 rows. Your array will have:
Array = (Row 1 Data)
Array = (Row 2 Data)
.. etc
You do not have ['fullRestaurantList']['ID']. In the page you're
referencing you use something like
$_SESSION['fullRestaurantList'][$i]['SomeValue']. I assume $i is the
Position in the array, so you likely want to use
$_SESSION['fullRestaurantList'][$i]['ID'] to get the ID field from that row.
If you need a quick dump to better understand what data you have in your
session, try making a page called session_dump.php in the same directory
with this source:
pre? print_r($_SESSION) ?/pre
That will give you a good idea of what your session array looks like,
and you should see clearly that ['fullRestaurantList']['ID'] does not exist.
Hope this helps!
- Kyle
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[PHP] Undefined index error
So sometimes I end up with issues that are so simple I should be able to fix it but for some reason I end up asking a stupid question to the list... So... Here goes :) Here is the error: Notice: Undefined index: 2 in /home/raosetc/public_html/purl/p.php on line 19 and here is Line 19: $data = explode(/, $_SERVER['REQUEST_URI']); When you first hit the site you to go something like: purl.mysupersite.com/YourNameHere If you went to: purl.mysupersite.com/YourNameHere/ (Notice the trailing /) there would be no error... Now I know it's just a undefined index error and I can safely ignore it since it works just fine. All I have to do is turn off the error reporting and it's gone... But I want to write good code... Any Suggestions? -- Jason Pruim japr...@raoset.com 616.399.2355
Re: [PHP] Undefined index error
Notice: Undefined index: 2 in /home/raosetc/public_html/purl/p.php on line 19 and here is Line 19: $data = explode(/, $_SERVER['REQUEST_URI']); Hi, Are you sure it's an array? Use print_r() or var_dump() on $_SERVER['REQUEST_URI'] on the preceding line. Just for testing, you could do this too: $_SERVER['REQUEST_URI'] = 'It/Works'; ...on the preceding line. -- Richard Heyes HTML5 Graphing for Firefox, Chrome, Opera and Safari: http://www.rgraph.org (Updated January 17th) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Undefined index error
On Jan 19, 2009, at 2:32 PM, Richard Heyes wrote: Notice: Undefined index: 2 in /home/raosetc/public_html/purl/p.php on line 19 and here is Line 19: $data = explode(/, $_SERVER['REQUEST_URI']); Hi, Are you sure it's an array? Use print_r() or var_dump() on $_SERVER['REQUEST_URI'] on the preceding line. Just for testing, you could do this too: $_SERVER['REQUEST_URI'] = 'It/Works'; ...on the preceding line. actually at that point it's not an array... it's just loading purl.mysupersite.com/test so REQUEST_URI just contains test I just want to squash that error until they go to a page in the site :) I'm thinking I just need to think this one through a little bit and I'm sure the solution ill come to me. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Undefined index error
On Mon, Jan 19, 2009 at 14:32, Richard Heyes rich...@php.net wrote:
Notice: Undefined index: 2 in /home/raosetc/public_html/purl/p.php on line
19
and here is Line 19:
$data = explode(/, $_SERVER['REQUEST_URI']);
When I view that file, on line 19, I see:
echo HTML
Are you sure it's an array? Use print_r() or var_dump() on
$_SERVER['REQUEST_URI'] on the preceding line. Just for testing, you
could do this too:
$_SERVER['REQUEST_URI'] = 'It/Works';
...on the preceding line.
Well, that wouldn't address the issue of the code he gave on the
line reported, but I know what you mean, Richy. He's turning
$_SERVER['REQUEST_URI'] into an array with explode() if it contains a
forward-slash (/).
What would be better in that case would be:
?php
$data = isset($_SERVER['REQUEST_URI'])
strlen($_SERVER['REQUEST_URI']) 0 ?
explode('/',$_SERVER['REQUEST_URI']) : $_SERVER['REQUEST_URI'];
if(is_array($data)) {
// Handle as appropriate.
}
?
However, that's not the best option as:
1.) REQUEST_URI may not (though it should) have *any* forward
slashes in the URI passed to PHP by the HTTP server.
2.) It leaves too much other stuff to be done.
Instead, check out:
?php
$data = basename($_SERVER['REQUEST_URI']);
echo $data; // In case you're not yet aware of what you'll receive
from the use of basename()
?
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Re: [PHP] Undefined index error
There is no reference to index '2' in that line 19. What is the next line? Something which expects at least 3 elements in the URI, perhaps?... [Hint, hint] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Undefined index error
On Jan 19, 2009, at 3:28 PM, Daniel Brown wrote:
On Mon, Jan 19, 2009 at 14:32, Richard Heyes rich...@php.net wrote:
Notice: Undefined index: 2 in /home/raosetc/public_html/purl/p.php
on line
19
and here is Line 19:
$data = explode(/, $_SERVER['REQUEST_URI']);
When I view that file, on line 19, I see:
echo HTML
Only when you log into certain accounts and view the file after I had
made changes :P
Are you sure it's an array? Use print_r() or var_dump() on
$_SERVER['REQUEST_URI'] on the preceding line. Just for testing, you
could do this too:
$_SERVER['REQUEST_URI'] = 'It/Works';
...on the preceding line.
Well, that wouldn't address the issue of the code he gave on the
line reported, but I know what you mean, Richy. He's turning
$_SERVER['REQUEST_URI'] into an array with explode() if it contains a
forward-slash (/).
What would be better in that case would be:
?php
$data = isset($_SERVER['REQUEST_URI'])
strlen($_SERVER['REQUEST_URI']) 0 ?
explode('/',$_SERVER['REQUEST_URI']) : $_SERVER['REQUEST_URI'];
if(is_array($data)) {
// Handle as appropriate.
}
?
However, that's not the best option as:
1.) REQUEST_URI may not (though it should) have *any* forward
slashes in the URI passed to PHP by the HTTP server.
2.) It leaves too much other stuff to be done.
Instead, check out:
?php
$data = basename($_SERVER['REQUEST_URI']);
echo $data; // In case you're not yet aware of what you'll receive
from the use of basename()
?
I'm not positive that does exactly what I want... What I'm really
going for is given this URL:
purl.mysupersite.com/test/mail
test refers to a record in the database.
mail refers to a file on the server which is included when mail is
present. Otherwise the main page is used.
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Re: [PHP] Undefined index error
On Mon, Jan 19, 2009 at 15:39, Jason Pruim japr...@raoset.com wrote:
Only when you log into certain accounts and view the file after I had made
changes :P
I figured you had already changed it, but when you're root, you
don't have to log in to other accounts. ;-P
What I'm really going for is given this URL:
purl.mysupersite.com/test/mail
test refers to a record in the database.
mail refers to a file on the server which is included when mail is
present. Otherwise the main page is used.
So then you'll use mod_rewrite, since Apache needs to tell PHP how
to parse it. Otherwise, Apache is going to be looking for /test/mail.
#.htaccess:
#
Options -MultiViews
RewriteEngine On
#
## Redirect to remove trailing slashes on extensionless URL requests
# If requested URL ending with slash does not resolve to an existing
directory
RewriteCond %{REQUEST_FILENAME} !-d
# externally redirect to remove trailing slash.
RewriteRule ^(.+)/$ /index.php?s=$1 [QSA,L]
#
## Externally redirect clients directly requesting .php page URIs to
extensionless URIs
# If client request header contains php file extension
RewriteCond %{THE_REQUEST} ^[A-Z]{3,9}\ /[^.]+\.php\ HTTP
# externally redirect to extensionless URI.
RewriteRule ^([^.]+)\.php$ /index.php?s=$1 [QSA,R=301,L]
#
## Internally rewrite extensionless file requests to .php files ##
# If the requested URI does not contain a period in the final path-part
RewriteCond %{REQUEST_URI} !(\.[^./]+)$
# and if it does not exist as a directory
RewriteCond %{REQUEST_FILENAME} !-d
# and if it does not exist as a file
RewriteCond %{REQUEST_FILENAME} !-f
# then add .php to get the actual filename.
RewriteRule (.+) /index.php?s=$1 [QSA,L]
# End .htaccess
You can figure out the rest yourself. ;-P
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[PHP] Undefined index:
I'm using this code to check if a cookie has a value : If(!IsSet($HTTP_COOKIE_VARS[LoggedIn])) In case that this cookie is not set, how can i avoid the Undefined index: line in the error log? berber
Re: [PHP] Undefined index:
At 2:37 PM +0200 6/16/07, WeberSites LTD wrote: I'm using this code to check if a cookie has a value : If(!IsSet($HTTP_COOKIE_VARS[LoggedIn])) In case that this cookie is not set, how can i avoid the Undefined index: line in the error log? berber berber: Try this: $loggedIn = isset($HTTP_COOKIE_VARS[LoggedIn]) ? ($HTTP_COOKIE_VARS[LoggedIn]) : not logged in; echo($loggedIn); Cheers, tedd -- --- http://sperling.com http://ancientstones.com http://earthstones.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Undefined index:
WeberSites LTD wrote: I'm using this code to check if a cookie has a value : If(!IsSet($HTTP_COOKIE_VARS[LoggedIn])) In case that this cookie is not set, how can i avoid the Undefined index: line in the error log? The isset function does not give an error if you pass it a non-existant variable. Are you sure it's this line that's causing the undefined index error? -Stut -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Undefined index error
On 6/10/07, Christian Cantrell [EMAIL PROTECTED] wrote: I'm getting this error in my Apache log file, and I can't figure out why: Undefined index: password in /path/to/file.php on line 82 Some searching on Google turned up a bunch of questions, but no answers. Any idea what this warning message is referring to? Thanks, Christian Yes, you're probably trying to get a value from an array by using a key that isn't in the array. Something like this: ?php $array = array( user= test, foo=bar); $value = $array['password']; // Key password doesn't exist! ? Check the line number and print out the array with var_dump/print_r to see what's in the array.. Tijnema -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Undefined index error
Ah, you're right. Thanks, Tijnema. I'm just getting my feet wet with PHP, and you guys are a great help! Christian On 6/10/07, Tijnema [EMAIL PROTECTED] wrote: On 6/10/07, Christian Cantrell [EMAIL PROTECTED] wrote: I'm getting this error in my Apache log file, and I can't figure out why: Undefined index: password in /path/to/file.php on line 82 Some searching on Google turned up a bunch of questions, but no answers. Any idea what this warning message is referring to? Thanks, Christian Yes, you're probably trying to get a value from an array by using a key that isn't in the array. Something like this: ?php $array = array( user= test, foo=bar); $value = $array['password']; // Key password doesn't exist! ? Check the line number and print out the array with var_dump/print_r to see what's in the array.. Tijnema
Re: [PHP] Undefined index error
On Sat, June 9, 2007 11:53 pm, Christian Cantrell wrote:
I'm getting this error in my Apache log file, and I can't figure out
why:
Undefined index: password in /path/to/file.php on line 82
Some searching on Google turned up a bunch of questions, but no
answers.
Any idea what this warning message is referring to?
If you use something like:
$_POST['password']
$_COOKIE['password'] // this is a REALLY Bad Idea
$_GET['password'] //bad idea
$_SESSION['password']
.
.
.
but you don't actually *HAVE* a 'password' in the array, then you will
get that error message.
Your assumption that you have some kind of password is invalid.
Check first:
if (isset($whatever['password'])){
//rest of your code in here.
}
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[PHP] Undefined index error
I'm getting this error in my Apache log file, and I can't figure out why: Undefined index: password in /path/to/file.php on line 82 Some searching on Google turned up a bunch of questions, but no answers. Any idea what this warning message is referring to? Thanks, Christian
Re: [PHP] Undefined index error
On Sun, 2007-06-10 at 00:53 -0400, Christian Cantrell wrote: I'm getting this error in my Apache log file, and I can't figure out why: Undefined index: password in /path/to/file.php on line 82 Please post the code on that line of the file indicated. Cheers, Rob. -- .. | InterJinn Application Framework - http://www.interjinn.com | :: | An application and templating framework for PHP. Boasting | | a powerful, scalable system for accessing system services | | such as forms, properties, sessions, and caches. InterJinn | | also provides an extremely flexible architecture for | | creating re-usable components quickly and easily. | `' -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] undefined index and php
Before someone advises me to 'google' my question. I have and can't find a
PHP.net example either.
I have turned off registered globals and am updating my scripts so they work
but I keep getting an undefined index problem using $_POST
I tried this to set the value...
if (!isset($_POST['heading'])) {
$_POST ['heading'] = ;
}
because the following line give the notice 'undefined index' BEFORE the
submit button has been pressed..
? $heading_insert= stripslashes($_POST['heading']);?
R.
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Re: [PHP] undefined index and php
Ross wrote: because the following line give the notice 'undefined index' BEFORE the submit button has been pressed.. ? $heading_insert= stripslashes($_POST['heading']);? That's because before the submit button has been pressed, $_POST is empty and so 'heading' is indeed an undefined index. Try: $heading_insert = isset( $_POST['heading'] ) ? stripslashes( $_POST['heading'] ) : ''; By the way, while you're switching register_globals off, it might be a good idea to also switch off magic_quotes_gpc (the reason you need stripslashes() above) and short_open_tag (judging by your use of the non-portable ? open tag rather than ?php). Jasper -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] undefined index and php
I have never really used this abreviated format before why the question mark and the colon? What is the long hang eqivalent. I turned magic quotes off too. thanks. R. - Original Message - From: Jasper Bryant-Greene [EMAIL PROTECTED] To: Ross [EMAIL PROTECTED] Cc: php-general@lists.php.net Sent: Thursday, November 10, 2005 12:19 PM Subject: Re: [PHP] undefined index and php Ross wrote: because the following line give the notice 'undefined index' BEFORE the submit button has been pressed.. ? $heading_insert= stripslashes($_POST['heading']);? That's because before the submit button has been pressed, $_POST is empty and so 'heading' is indeed an undefined index. Try: $heading_insert = isset( $_POST['heading'] ) ? stripslashes( $_POST['heading'] ) : ''; By the way, while you're switching register_globals off, it might be a good idea to also switch off magic_quotes_gpc (the reason you need stripslashes() above) and short_open_tag (judging by your use of the non-portable ? open tag rather than ?php). Jasper -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] undefined index and php
The question mark and colon is the equivalent for the iif function. It's a short hand for if/else. You start with the expression, and if true, do what's after the question mark and if false, after the column. Robbert -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Sent: Thursday, November 10, 2005 4:58 AM To: php-general@lists.php.net Subject: Re: [PHP] undefined index and php I have never really used this abreviated format before why the question mark and the colon? What is the long hang eqivalent. I turned magic quotes off too. thanks. R. - Original Message - From: Jasper Bryant-Greene [EMAIL PROTECTED] To: Ross [EMAIL PROTECTED] Cc: php-general@lists.php.net Sent: Thursday, November 10, 2005 12:19 PM Subject: Re: [PHP] undefined index and php Ross wrote: because the following line give the notice 'undefined index' BEFORE the submit button has been pressed.. ? $heading_insert= stripslashes($_POST['heading']);? That's because before the submit button has been pressed, $_POST is empty and so 'heading' is indeed an undefined index. Try: $heading_insert = isset( $_POST['heading'] ) ? stripslashes( $_POST['heading'] ) : ''; By the way, while you're switching register_globals off, it might be a good idea to also switch off magic_quotes_gpc (the reason you need stripslashes() above) and short_open_tag (judging by your use of the non-portable ? open tag rather than ?php). Jasper -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] undefined index and php
Robbert van Andel wrote: The question mark and colon is the equivalent for the iif function. It's a 'if () ...' is not a function it's a language construct. they are different :-) for instance 'echo' is also a language construct which is why it does not require brackets e.g. $space = ' '; echo hello,$space,world; short hand for if/else. You start with the expression, and if true, do what's after the question mark and if false, after the column. Robbert -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Sent: Thursday, November 10, 2005 4:58 AM To: php-general@lists.php.net Subject: Re: [PHP] undefined index and php I have never really used this abreviated format before why the question mark and the colon? What is the long hang eqivalent. I turned magic quotes off too. thanks. R. - Original Message - From: Jasper Bryant-Greene [EMAIL PROTECTED] To: Ross [EMAIL PROTECTED] Cc: php-general@lists.php.net Sent: Thursday, November 10, 2005 12:19 PM Subject: Re: [PHP] undefined index and php Ross wrote: because the following line give the notice 'undefined index' BEFORE the submit button has been pressed.. ? $heading_insert= stripslashes($_POST['heading']);? That's because before the submit button has been pressed, $_POST is empty and so 'heading' is indeed an undefined index. Try: $heading_insert = isset( $_POST['heading'] ) ? stripslashes( $_POST['heading'] ) : ''; By the way, while you're switching register_globals off, it might be a good idea to also switch off magic_quotes_gpc (the reason you need stripslashes() above) and short_open_tag (judging by your use of the non-portable ? open tag rather than ?php). Jasper -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] undefined index and php
Hello. [EMAIL PROTECTED] wrote: why the question mark and the colon? What is the long hang eqivalent. That's the Ternary operator. Whether you want to get further information, go to: http://php.net/manual/en/language.operators.comparison.php Regards. -- Gustavo Narea. PHP Documentation - Spanish Translation Team. Valencia, Venezuela. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] undefined index and php
On Thu, November 10, 2005 5:54 am, Ross wrote:
Before someone advises me to 'google' my question. I have and can't
find a
PHP.net example either.
I have turned off registered globals and am updating my scripts so
they work
but I keep getting an undefined index problem using $_POST
I tried this to set the value...
if (!isset($_POST['heading'])) {
$_POST ['heading'] = ;
}
because the following line give the notice 'undefined index' BEFORE
the
submit button has been pressed..
? $heading_insert= stripslashes($_POST['heading']);?
This bit of code is getting run BEFORE the submit button has been
pressed.
In that case, $_POST itself is not defined, much less $_POST['heading']
You really shouldn't be stuffing values into $_POST. Think of it as a
read-only variable that the browser sends TO you.
Here are some options:
OPTION 1:
?php
$heading_insert = '';
if (isset($_POST['heading'])){
$heading_insert = stripslashes($_POST['heading']);
}
?
OPTION 2:
?php
$heading_insert = isset($_POST['heading']) ?
stripslashes($_POST['heading']) : '';
?
Some people think the ternary operator is confusing or obscure or
whatever. Others think it's a perfectly natural operator. YMMV
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RE: [PHP] undefined index
-Original Message-
From: Ross [mailto:[EMAIL PROTECTED]
Sent: Thursday, June 16, 2005 8:51 PM
if ($quantity == 0){
}
else {
$pieces = explode( , $quantity);
$formatted_price = sprintf('%0.2f', $pricecode);
echo table width=\240\ border=\0\ cellpadding=\2\
cellspacing=\5\trtd valign=\top\ align=\right\
width=\40\$pieces[0]/tdtd align=\left\ width=\60\/tdtd
align=\left\ width=\200\$pieces[1] $pieces[2] $pieces[3]
$pieces[4]/tdtd valign=\top\ align=\left\
width=\80\$formatted_price/td/tr/table;
}
}
The trouble is I get a NOTICE that tells me the indexes 1 to 4 have
not
been defined. how do I do this.
Probably because $quantity IS 0, then the vars used in the else {} is
never set, but still in the script.
Try setting these before the if statement:
$pieces = array();
$formatted_price = 0;
$pricecode = 0; // this one is never set? Or set earlier in the script?
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Re: [PHP] undefined index
I have a bit of code that splices up a cookie into 4 bits so the information
can be displayedin a neat way in a table
if ($quantity == 0){
}
else {
$pieces = explode( , $quantity);
$formatted_price = sprintf('%0.2f', $pricecode);
echo table width=\240\ border=\0\ cellpadding=\2\
cellspacing=\5\trtd valign=\top\ align=\right\
width=\40\$pieces[0]/tdtd align=\left\ width=\60\/tdtd
align=\left\ width=\200\$pieces[1] $pieces[2] $pieces[3]
$pieces[4]/tdtd valign=\top\ align=\left\
width=\80\$formatted_price/td/tr/table;
}
}
The trouble is I get a NOTICE that tells me the indexes 1 to 4 have not been
defined. how do I do this.
What is the output of:
print_r($pieces) if placed right after the explode() line? Maybe
$quantity isn't what you think it is...
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[PHP] undefined index: $_FILES || $HTTP_POST_FILES
Hello! I have the same script on two webservers with php 4.3.9 and apache 2, both with the same php configurations. On one server I can not access $_FILES or $HTTP_POST_FILES, although a form with a file has been correctly submitted. apache_request_headers() contains: [Content-Type] = multipart/form-data; boundary=---207315575716727585901748724465 [Content-Length] = 5779 So php should have received the form data. I can access $_GET and $_POST without any problem. $_FILES and $HTTP_POST_FILES do simply not exist, and when I try to access them I just get an undefined index error, or with print_r() an empty array. Regards, Tobias Neumann -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] undefined index: $_FILES || $HTTP_POST_FILES
Tobias Neumann wrote: Hello! I have the same script on two webservers with php 4.3.9 and apache 2, both with the same php configurations. On one server I can not access $_FILES or $HTTP_POST_FILES, although a form with a file has been correctly submitted. apache_request_headers() contains: [Content-Type] = multipart/form-data; boundary=---207315575716727585901748724465 [Content-Length] = 5779 So php should have received the form data. I can access $_GET and $_POST without any problem. $_FILES and $HTTP_POST_FILES do simply not exist, and when I try to access them I just get an undefined index error, or with print_r() an empty array. Regards, Tobias Neumann http://sk2.php.net/manual/en/features.file-upload.php Read the Related Configurations Note and also check enctype attribute of your form -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] undefined index: $_FILES || $HTTP_POST_FILES
Tobias Neumann wrote: Hello! I have the same script on two webservers with php 4.3.9 and apache 2, both with the same php configurations. On one server I can not access $_FILES or $HTTP_POST_FILES, although a form with a file has been correctly submitted. Quick question: is file uploads enabled on this server and is the temporary directory writable? apache_request_headers() contains: [Content-Type] = multipart/form-data; boundary=---207315575716727585901748724465 [Content-Length] = 5779 So php should have received the form data. I can access $_GET and $_POST without any problem. $_FILES and $HTTP_POST_FILES do simply not exist, and when I try to access them I just get an undefined index error, or with print_r() an empty array. Regards, Tobias Neumann -- Raditha Dissanayake. http://www.radinks.com/sftp/ | http://www.raditha.com/megaupload Lean and mean Secure FTP applet with | Mega Upload - PHP file uploader Graphical User Inteface. Just 128 KB | with progress bar. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] undefined index: $_FILES || $HTTP_POST_FILES
On Monday 08 November 2004 09:07, Tobias Neumann wrote: I have the same script on two webservers with php 4.3.9 and apache 2, both with the same php configurations. On one server I can not access $_FILES or $HTTP_POST_FILES, although a form with a file has been correctly submitted. Are the httpd.conf config the same as well? -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * -- Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general -- /* I go on working for the same reason a hen goes on laying eggs. - H. L. Mencken */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] undefined index: $_FILES || $HTTP_POST_FILES
On Mon, 08 Nov 2004 15:52:53 +0600, Raditha Dissanayake wrote: Quick question: is file uploads enabled on this server and is the temporary directory writable? Hmm. upload_tmp_dir was unset. The php.ini says that in this case the systems default tempoary directory is used. So I guessed it would be /tmp, because php also saves the session data there. Now I set the upload_tmp_dir explicit to /tmp and it works. So where on linux systems is the default tempoary directory set? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Undefined index ???
Hi Why do I get an error if the $_SESSION['user_status'] is NULL ??? Script## session_start(); echo $_SESSION['user_status']; #error## Notice: Undefined index: user_status in /var/www/itmdata/include/include.php on line 13 Regards Micke -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Undefined index ???
Michael Jonsson wrote:
Hi
Why do I get an error if the $_SESSION['user_status'] is NULL ???
Script##
session_start();
echo $_SESSION['user_status'];
#error##
Notice: Undefined index: user_status in
/var/www/itmdata/include/include.php on line 13
Regards
Micke
That's not an error. Three ways to solve this...
1) Turn down your error reporting level.
2) Declare your variables before using them
$_SESSION['user_status'] = NULL;
echo ( $_SESSION['user_status'] );
3) Code for variables that may not exist
if ( isset ( $_SESSION['user_status'] ) ) {
echo ( $_SESSION['user_status'] );
}
Or any combination of the three.
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716.856.9675
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Re: [PHP] Undefined index ???
John Nichel [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Michael Jonsson wrote:
Hi
Why do I get an error if the $_SESSION['user_status'] is NULL ???
Script##
session_start();
echo $_SESSION['user_status'];
#error##
Notice: Undefined index: user_status in
/var/www/itmdata/include/include.php on line 13
Regards
Micke
That's not an error. Three ways to solve this...
1) Turn down your error reporting level.
2) Declare your variables before using them
$_SESSION['user_status'] = NULL;
echo ( $_SESSION['user_status'] );
3) Code for variables that may not exist
if ( isset ( $_SESSION['user_status'] ) ) {
echo ( $_SESSION['user_status'] );
}
Or any combination of the three.
I would not recommend turning down the error reporting level. This might
lead to unexpected behaviour in your application and makes it hard to back
track errors.
Always develop with error reporting set to E_ALL. You may set a lower level
for your production environment and disable the display of errors:
ini_set('display_errors', 0);
Regards, Torsten Roehr
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[PHP] Undefined index ????
Hi Why do I get an error if the $_SESSION['user_status'] is emty (it's not set to anything) ??? in my redhat 9 it did mork, but when I moved to Fedora Core 2 it's not working... Script## session_start(); echo $_SESSION['user_status']; #error## Notice: Undefined index: user_status in /var/www/itmdata/include/include.php on line 13 Regards Micke -- -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] undefined index -------- please help !!!!!!!!
OK, but when i use isset my request is not executed normally.
I wonder if the fact i use the frames is the problem because with no
changement and without using isset
my request run correctly.
Thanks !
- Original Message -
From: John Nichel [EMAIL PROTECTED]
To: Dominique ANOKRE [EMAIL PROTECTED]
Cc: Php List [EMAIL PROTECTED]
Sent: Saturday, March 06, 2004 12:15 PM
Subject: Re: [PHP] undefined index please help
Dominique ANOKRE wrote:
on line 66 there is :
$date=$_POST[date];
Thanks
$_POST['date'] isn't set.
if ( isset ( $_POST['date'] ) ) {
$date = $_POST['date'];
}
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Re: [PHP] undefined index -------- please help !!!!!!!!
on line 66 there is : $date=$_POST[date]; Thanks - Original Message - From: Chris W. Parker [EMAIL PROTECTED] To: Dominique ANOKRE [EMAIL PROTECTED]; Php List [EMAIL PROTECTED] Sent: Friday, March 05, 2004 8:20 PM Subject: RE: [PHP] undefined index please help Dominique ANOKRE mailto:[EMAIL PROTECTED] on Friday, March 05, 2004 12:19 PM said: Undefined index: numcpte in c:\inetpub\wwwroot\rech_haut.php on line 66 For information, i have not this error when the file recherche.php is a simple file without frames !!! Please help!! what is on line 66!?!? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] undefined index -------- please help !!!!!!!!
Dominique ANOKRE wrote:
on line 66 there is :
$date=$_POST[date];
Thanks
$_POST['date'] isn't set.
if ( isset ( $_POST['date'] ) ) {
$date = $_POST['date'];
}
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[PHP] undefined index -------- please help !!!!!!!!
I have a form which call a php file when click on the submit button : form name=form method=post action=recherche.php language=JavaScript onSubmit=return TestSaisie() First this runs correctly when i click on the submit buttom then the file recherche.php is executed and the result is displayed. I modify the design of my pages in order to display result into frames. So i create a frameset named recherche.php which contains two frames rech_haut.php and rech_bas.php. And when i click on buttom submit in order to display the result i have this notice message : Undefined index: numcpte in c:\inetpub\wwwroot\rech_haut.php on line 66 For information, i have not this error when the file recherche.php is a simple file without frames !!! Please help!!
RE: [PHP] undefined index -------- please help !!!!!!!!
Dominique ANOKRE mailto:[EMAIL PROTECTED] on Friday, March 05, 2004 12:19 PM said: Undefined index: numcpte in c:\inetpub\wwwroot\rech_haut.php on line 66 For information, i have not this error when the file recherche.php is a simple file without frames !!! Please help!! what is on line 66!?!? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Undefined Index Errors
Hey guys, Here's a chunk of code from the top of a multi-function page I converted from Perl to PHP: $userid = $_REQUEST['USERID'];# USERID = selected userid $dlist= $_REQUEST['DLIST']; # DLIST = indicates who to display $action = $_REQUEST['ACTION'];# ACTION = indicates approval or denial $more = $_REQUEST['MORE']; # MORE = ID of person to show details $delete = $_REQUEST['DELETE'];# DELETE = indicates to delete user $ltr = $_REQUEST['LTR']; # LTR = start ltr of last name $modpwd = $_REQUEST['MODPWD'];# MODPWD = indicates modifying pwd $expire = $_REQUEST['EXPIRE'];# EXPIRE = indicates to expire pwd $upduser = $_REQUEST['UPDUSER']; # UPDUSER = indicates user info updated $denyuser = $_REQUEST['DENYUSER']; # DENYUSER = indicates user was denied $reason = $_REQUEST['REASON'];# REASON = Reason user was denied $adminID = $_ENV['HTTP_REMOTE_USER']; I'm creating some strings from array elements obviously. The issue is, the array elements don't always exist depending on which function you are running. And when they don't, the server log is full of undefined index errors. Is there a way I can avoid these errors without adding a if(isset(...)) around each one? Thanks, Cameron -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Undefined Index Errors
You can either: 1. put @ in front of each variable, e.g. $adminID = @$_ENV['HTTP_REMOTE_USER']; 2. change your error reporting level: error_reporting(E_ALL ^ E_NOTICE); Cameron B. Prince wrote: Hey guys, Here's a chunk of code from the top of a multi-function page I converted from Perl to PHP: $userid = $_REQUEST['USERID'];# USERID = selected userid $dlist= $_REQUEST['DLIST']; # DLIST = indicates who to display $action = $_REQUEST['ACTION'];# ACTION = indicates approval or denial $more = $_REQUEST['MORE']; # MORE = ID of person to show details $delete = $_REQUEST['DELETE'];# DELETE = indicates to delete user $ltr = $_REQUEST['LTR']; # LTR = start ltr of last name $modpwd = $_REQUEST['MODPWD'];# MODPWD = indicates modifying pwd $expire = $_REQUEST['EXPIRE'];# EXPIRE = indicates to expire pwd $upduser = $_REQUEST['UPDUSER']; # UPDUSER = indicates user info updated $denyuser = $_REQUEST['DENYUSER']; # DENYUSER = indicates user was denied $reason = $_REQUEST['REASON'];# REASON = Reason user was denied $adminID = $_ENV['HTTP_REMOTE_USER']; I'm creating some strings from array elements obviously. The issue is, the array elements don't always exist depending on which function you are running. And when they don't, the server log is full of undefined index errors. Is there a way I can avoid these errors without adding a if(isset(...)) around each one? Thanks, Cameron -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Undefined Index Errors
On Fri, 2004-02-06 at 10:51, Cameron B. Prince wrote: I'm creating some strings from array elements obviously. The issue is, the array elements don't always exist depending on which function you are running. And when they don't, the server log is full of undefined index errors. Is there a way I can avoid these errors without adding a if(isset(...)) around each one? If you know which variables are required per 'function' that is being called wrap an if around these variable declarations in blocks. You will still have ifs, but you should have a lot fewer. If by function you mean actual functions then you could move these lines to the top of their respective functions. -- Adam Bregenzer [EMAIL PROTECTED] http://adam.bregenzer.net/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Undefined Index Errors
From: Cameron B. Prince [EMAIL PROTECTED] I'm creating some strings from array elements obviously. The issue is, the array elements don't always exist depending on which function you are running. And when they don't, the server log is full of undefined index errors. Is there a way I can avoid these errors without adding a if(isset(...)) around each one? Adjust your error_reporting() level so these notices don't show up. ---John Holmes... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Undefined Index Errors
1. put @ in front of each variable, e.g. $adminID = @$_ENV['HTTP_REMOTE_USER']; This worked very nicely... Thank you! Hey guys, Here's a chunk of code from the top of a multi-function page I converted from Perl to PHP: $userid = $_REQUEST['USERID'];# USERID = selected userid $dlist= $_REQUEST['DLIST']; # DLIST = indicates who to display $action = $_REQUEST['ACTION'];# ACTION = indicates approval or denial $more = $_REQUEST['MORE']; # MORE = ID of person to show details $delete = $_REQUEST['DELETE'];# DELETE = indicates to delete user $ltr = $_REQUEST['LTR']; # LTR = start ltr of last name $modpwd = $_REQUEST['MODPWD'];# MODPWD = indicates modifying pwd $expire = $_REQUEST['EXPIRE'];# EXPIRE = indicates to expire pwd $upduser = $_REQUEST['UPDUSER']; # UPDUSER = indicates user info updated $denyuser = $_REQUEST['DENYUSER']; # DENYUSER = indicates user was denied $reason = $_REQUEST['REASON'];# REASON = Reason user was denied $adminID = $_ENV['HTTP_REMOTE_USER']; I'm creating some strings from array elements obviously. The issue is, the array elements don't always exist depending on which function you are running. And when they don't, the server log is full of undefined index errors. Is there a way I can avoid these errors without adding a if(isset(...)) around each one? Thanks, Cameron -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Undefined index???
Hi all,
I keep getting this error:
Notice: Undefined index: tutor_id in /usr/local/..
What does undefined index exactly mean?? I did a search on the web but
couldn't find any solutions.
The line that cause this error is as follow:
$tutor_id = $_POST[tutor_id];
.
.
.
.if($action == edit)
{
$sql = mysql_query (SELECT * FROM tutor WHERE tutor_id='$tutor_id');
$row = mysql_fetch_array($sql);
etc.
Hope to get some help here soon...thanks in advance.
Irin.
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Re: [PHP] Undefined index???
On Friday 12 December 2003 15:43, [EMAIL PROTECTED] wrote: I keep getting this error: Notice: Undefined index: tutor_id in /usr/local/.. What does undefined index exactly mean?? I did a search on the web but couldn't find any solutions. Basically it means you're trying to access a non-existent item in the array. The line that cause this error is as follow: $tutor_id = $_POST[tutor_id]; print_r($_POST) will show all the items in $_POST. Is your form set to use the post method? If not then look in $_GET for your form input data. -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * -- Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general -- /* No snowflake in an avalanche ever feels responsible. */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Undefined index???
On Friday 12 December 2003 15:43, [EMAIL PROTECTED] wrote:
I keep getting this error:
Notice: Undefined index: tutor_id in /usr/local/..
What does undefined index exactly mean?? I did a search on the web but
couldn't find any solutions.
Basically it means you're trying to access a non-existent item in the array.
The line that cause this error is as follow:
$tutor_id = $_POST[tutor_id];
print_r($_POST)
will show all the items in $_POST. Is your form set to use the post method?
If not then look in $_GET for your form input data.
---
yah my form has been set to use the POST method:
echo form name=\edit_tutor\ method=\post\ action=\edit2.php\;
What could be the problem???Or it could be related to quoting problem:
$sql = mysql_query (SELECT * FROM tutor WHERE tutor_id='$tutor_id');
or
$sql = mysql_query (SELECT * FROM tutor WHERE tutor_id=$tutor_id);
What is the right way to define the variable $tutor_id
--
For reference, I have copied the block of code below:
$dsn = mysql://root:[EMAIL PROTECTED]/tablename;
//connect to DB
$db = DB::connect ($dsn);
//check for any DB connection errors
if (DB::isError ($db))
die ($db-getMessage());
$action = $_GET[action];
$tutor_id = $_POST['tutor_id'];
print_r($_POST);
if($action == delete)
{
$sql = mysql_query (DELETE FROM tutor WHERE tutor_id='$tutor_id');
$result = $db-query($sql);
if( DB::isError($result) ) {
die ($result-getMessage());
}
echo a href='../index/timetable_main.php'Back to main/a;
}
if($action == edit)
{
$sql = mysql_query (SELECT * FROM tutor WHERE tutor_id='$tutor_id');
$row = mysql_fetch_array($sql);
echo form name=\edit_tutor\ method=\post\ action=\edit2.php\;
echo Tutor ID : .$row['tutor_id'].br;
echo input type=\hidden\ name=\tutor_id\ value=\.$row
['tutor_id'].\;
echo Name : input name=\tutor_name\ type=\text\ value=\.$row
['tutor_name'].\br;
echo Contact No : input type=\text\ name=\tutor_contact\ value=\.$row
['tutor_contact'].\br;
echo E-mail : input type=\text\ name=\tutor_email\ value=\.$row
['tutor_email'].\br;
echo Profile : input type=\text\ name=\tutor_profile\ value=\.$row
['tutor_profile'].\br;
echo input type=\submit\ name=\Submit\ value=\Update\;
echo /form;
}
?
echo The entry has been deleted brbr;
For reference, i have copied the block of code below:
Irin.
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Re: [PHP] Undefined index???
[EMAIL PROTECTED] wrote:
On Friday 12 December 2003 15:43, [EMAIL PROTECTED] wrote:
I keep getting this error:
Notice: Undefined index: tutor_id in /usr/local/..
What does undefined index exactly mean?? I did a search on the web but
couldn't find any solutions.
Basically it means you're trying to access a non-existent item in the array.
The line that cause this error is as follow:
$tutor_id = $_POST[tutor_id];
print_r($_POST)
will show all the items in $_POST. Is your form set to use the post method?
If not then look in $_GET for your form input data.
---
yah my form has been set to use the POST method:
Are you sure? You print out this form in this script, but that is not
how you got here.
echo form name=\edit_tutor\ method=\post\ action=\edit2.php\;
What could be the problem???Or it could be related to quoting problem:
Not at all, remember the notice is displayed before you run this query.
But always make sure user input is ALWAYS quoted and properly escaped in
sql queries. The second form is vulnerable in this case.
$sql = mysql_query (SELECT * FROM tutor WHERE tutor_id='$tutor_id');
or
$sql = mysql_query (SELECT * FROM tutor WHERE tutor_id=$tutor_id);
What is the right way to define the variable $tutor_id
--
For reference, I have copied the block of code below:
$dsn = mysql://root:[EMAIL PROTECTED]/tablename;
//connect to DB
$db = DB::connect ($dsn);
//check for any DB connection errors
if (DB::isError ($db))
die ($db-getMessage());
$action = $_GET[action];
$tutor_id = $_POST['tutor_id'];
print_r($_POST);
if($action == delete)
{
$sql = mysql_query (DELETE FROM tutor WHERE tutor_id='$tutor_id');
$result = $db-query($sql);
if( DB::isError($result) ) {
die ($result-getMessage());
}
echo a href='../index/timetable_main.php'Back to main/a;
}
if($action == edit)
{
$sql = mysql_query (SELECT * FROM tutor WHERE tutor_id='$tutor_id');
$row = mysql_fetch_array($sql);
echo form name=\edit_tutor\ method=\post\ action=\edit2.php\;
echo Tutor ID : .$row['tutor_id'].br;
echo input type=\hidden\ name=\tutor_id\ value=\.$row
['tutor_id'].\;
echo Name : input name=\tutor_name\ type=\text\ value=\.$row
['tutor_name'].\br;
echo Contact No : input type=\text\ name=\tutor_contact\ value=\.$row
['tutor_contact'].\br;
echo E-mail : input type=\text\ name=\tutor_email\ value=\.$row
['tutor_email'].\br;
echo Profile : input type=\text\ name=\tutor_profile\ value=\.$row
['tutor_profile'].\br;
echo input type=\submit\ name=\Submit\ value=\Update\;
echo /form;
}
?
echo The entry has been deleted brbr;
For reference, i have copied the block of code below:
Irin.
Jason has explained it to you: you are accessing a variable or an array
index that has not been defined. Rethink your logic.
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[PHP] Undefined Index - is this how you declare get post?
Hi List,
Since I started using error_reporting(E_ALL), I havent found (in my opinion)
a good way to declare GET and POST variables when getting them from a form
or querystring. I have searched google and the docs for several hours now
without much luck.
?php
error_reporting(E_ALL);
// This line stops the error reporting, else I get - Notice: Undefined
index: i in.
$HTTP_GET_VARS[i]=;
if ($HTTP_GET_VARS[i] == ) {
include(myfile.php);
}
?
Is there a better way?
I have tried var $i (only for classes I've discovered)
settype($i, integer)
Thanks in advance.
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RE: [PHP] Undefined Index - is this how you declare get post?
Terence mailto:[EMAIL PROTECTED] on Wednesday, October 29, 2003 4:40 PM said: Since I started using error_reporting(E_ALL), I havent found (in my opinion) a good way to declare GET and POST variables when getting them from a form or querystring. I have searched google and the docs for several hours now without much luck. Why would you want to declare a GET or POST variable in the first place? You'd be overwriting whatever value was stored from the form. Also, depending on your version of PHP you should be using $_GET and $_POST and not $HTTP_GET_VARS or $HTTP_POST_VARS. hth, Chris. -- Don't like reformatting your Outlook replies? Now there's relief! http://home.in.tum.de/~jain/software/outlook-quotefix/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Undefined Index - is this how you declare get post?
- Original Message - From: Chris W. Parker [EMAIL PROTECTED] Terence mailto:[EMAIL PROTECTED] on Wednesday, October 29, 2003 4:40 PM said: Since I started using error_reporting(E_ALL), I havent found (in my opinion) a good way to declare GET and POST variables when getting them from a form or querystring. I have searched google and the docs for several hours now without much luck. Why would you want to declare a GET or POST variable in the first place? You'd be overwriting whatever value was stored from the form. error_reporting(E_ALL) tells me that I have an indefined index, but as Jon Kriek pointed out, perhaps reporting all the errors is not such a good thing. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Undefined Index - is this how you declare get post?
Terence wrote:
Since I started using error_reporting(E_ALL), I havent found (in my opinion)
a good way to declare GET and POST variables when getting them from a form
or querystring. I have searched google and the docs for several hours now
without much luck.
?php
error_reporting(E_ALL);
// This line stops the error reporting, else I get - Notice: Undefined
index: i in.
$HTTP_GET_VARS[i]=;
if ($HTTP_GET_VARS[i] == ) {
include(myfile.php);
}
?
Is there a better way?
I have tried var $i (only for classes I've discovered)
settype($i, integer)
Thanks in advance.
isset() is your friend.
if(isset($HTTP_GET_VARS['i']) $HTTP_GET_VARS['i'] == '')
{ include('myfile.php'); }
This will not trigger any warning, even under E_ALL.
In response to some of the other posts, developing at E_ALL is a good
idea as it'll help you spot potential problem areas.
Also, even though you have a form element defined, it may not always
appear in $HTTP_GET_VARS/$_GET (post, etc). One example are checkboxes.
If no boxes are checked, the variable is never created and this is the
way to check.
--
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[PHP] Undefined index a different problem
my problem is,
i have a script that works well before php 4.2.3
its sth like that
{..
for($i=0; $icount($line); $i++); // loop line numbers
...
}
//2nd part
{
echo ($i);
}
now i changed second part as;
echo($GLOBALS[i]);
and it gives me notice that undefined index i.
how can i solve this problem?
thanks
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Re: [PHP] Undefined index a different problem
Mekrand wrote:
my problem is,
i have a script that works well before php 4.2.3
its sth like that
{..
for($i=0; $icount($line); $i++); // loop line numbers
...
}
//2nd part
{
echo ($i);
}
now i changed second part as;
echo($GLOBALS[i]);
should not be
echo($GLOBALS[$i]);
and it gives me notice that undefined index i.
how can i solve this problem?
thanks
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Re: [PHP] Undefined index a different problem
thanks but this time it gives 2 error,
undefined variable i,
undefined index i for
$GLOBALS[$i]
Marek Kilimajer [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Mekrand wrote:
my problem is,
i have a script that works well before php 4.2.3
its sth like that
{..
for($i=0; $icount($line); $i++); // loop line numbers
...
}
//2nd part
{
echo ($i);
}
now i changed second part as;
echo($GLOBALS[i]);
should not be
echo($GLOBALS[$i]);
and it gives me notice that undefined index i.
how can i solve this problem?
thanks
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Re: [PHP] Undefined index a different problem
These are not errors, but notices, you can get around it using:
if(isset($i) array_key_exists($GLOBALS, $i)) echo $GLOBALS[$i];
or you might prefer setting error_reporting to not display notices
Mekrand wrote:
thanks but this time it gives 2 error,
undefined variable i,
undefined index i for
$GLOBALS[$i]
Marek Kilimajer [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Mekrand wrote:
my problem is,
i have a script that works well before php 4.2.3
its sth like that
{..
for($i=0; $icount($line); $i++); // loop line numbers
...
}
//2nd part
{
echo ($i);
}
now i changed second part as;
echo($GLOBALS[i]);
should not be
echo($GLOBALS[$i]);
and it gives me notice that undefined index i.
how can i solve this problem?
thanks
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RE: [PHP] Undefined index a different problem
Try:
echo($GLOBALS[$i]);
Or
echo {$GLOBALS[$i]};
This times it's the array in the double quoted strings ...
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[PHP] undefined index....property.
I have just setup my localmachine to see how our site runs on php 4.2.
It currently runs on 4.1 on the server. I am only fairly new to this so
I have come across a slight hurdle.
At first logging in as a user to the database was giving undefined
variable error. Have read up on this and fixed it by turning on
register_globals. So that's sweet. Although my other form page is for
joining up, which sends variables to another page and then in turn sends
the info to the database. The info that the user fills out gets passed
ok cept I get two errors output to the page.
//filled out info and clicked send.
Notice: Undefined index: license in c:\inetpub\wwwroot\php\config.php on
line 51
Notice: Undefined property: num_rows in
c:\inetpub\wwwroot\php\adcjoin.php on line 67
//
This is my action on the submit page
FORM action=php/adcjoin.php method=post
The undefined property is in the
adcjoinpage.php
$db-query(SELECT Username FROM global WHERE
(Username='.$Username.'));
if ($db-num_rows0){
array_push($error,Choose another busername/b, this
name is reservedbr\n);
$flag = 1;
}
///attatched to adcjoin.php
require(connect.php);
//
Config file called on by connect.php contains a license variable.
//
I Am not quite sure why it is outputting these two errors. I have not
changed anything from downloading it off the serverapart from
targeting the database on my local machine now. Is it possibly a session
error??
If anybody has any thoughts please pass them on.
Cheers Bruce
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[PHP] undefined index....property.
Sorry I did not mention. My local machine is WinXP pro, running php 4.2 and mysql 3.23. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] undefined index....property.
you didn't send the code snippet for Undefined index however, I think the reason you're getting these errors at home is because you have a different error_reporting level. HTH a bit Martin [snip] //filled out info and clicked send. Notice: Undefined index: license in c:\inetpub\wwwroot\php\config.php on line 51 Notice: Undefined property: num_rows in c:\inetpub\wwwroot\php\adcjoin.php on line 67 // [snip] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Undefined index:
Hi,
I'm learning php from a book but because of global off I have have
several Undefined index message! I don't want to change the default
setting in my php.ini because I want to learn the good way.
What I'm doing wrong?
Undefined index: categorie
if ($_POST['categorie'] == New) {
Undefined index: categorie
$query = SELECT DISTINCT animalName FROM animal WHERE
animalType='{$_REQUEST['categorie']}' ORDER BY animalName;
Undefined index: categorie
echo hrbNo name in {$_POST['categorie']}/bhr\n;
Undefined index: categorie
echo input type='hidden' name='categorie' value='$categorie'\n;
Regards!
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[PHP] Undefined index, Undefined variable, Undefined constant....
I'm having trouble with the newest version of PHP (4.2.2).
For example in a page I'm using the following code:
if ($_GET['action'] == logout) {
//do something
}
But I'm getting an error message that says:
...log_message reports: PHP Notice: Undefined index: action in
Ealier (other versions of PHP) I have succesfully used the above code, but do
I now have to rewrite the code like this:
if (isset($_GET['action']) AND $_GET['action'] == logout) {
//do something
}
Or am I totally wrong?
This was just one example when I'm getting the message Undefined index or
Undefined variable etc. A lot of code which has previously worked is now
giving me loads of headache since I have to rewrite everything.
Please, I need some help.
my email: [EMAIL PROTECTED]
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RE: [PHP] Undefined index, Undefined variable, Undefined constant....
[snip]
I'm having trouble with the newest version of PHP (4.2.2).
For example in a page I'm using the following code:
if ($_GET['action'] == logout) {
//do something
}
[/snip]
As a quick troubleshooting method echo or print $_GET['action'] to see what,
if anything, is contained there. I would also like to see more than;
...log_message reports: PHP Notice: Undefined index: action in
HTH!
Jay
Here I am. Now what were your other two wishes?
*
* Texas PHP Developers Conf Spring 2003*
* T Bar M Resort Conference Center*
* New Braunfels, Texas *
* Contact [EMAIL PROTECTED] *
* *
* Want to present a paper or workshop? Contact now! *
*
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Re: [PHP] Undefined index, Undefined variable, Undefined constant....
I had the say problem,
try this
if($_POST['update'] == Update)
{
someting to do...
}
- Original Message -
From: Jay Blanchard [EMAIL PROTECTED]
To: 'Jens Winberg' [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Friday, September 06, 2002 5:12 PM
Subject: RE: [PHP] Undefined index, Undefined variable, Undefined
constant
[snip]
I'm having trouble with the newest version of PHP (4.2.2).
For example in a page I'm using the following code:
if ($_GET['action'] == logout) {
file://do something
}
[/snip]
As a quick troubleshooting method echo or print $_GET['action'] to see
what,
if anything, is contained there. I would also like to see more than;
...log_message reports: PHP Notice: Undefined index: action in
HTH!
Jay
Here I am. Now what were your other two wishes?
*
* Texas PHP Developers Conf Spring 2003*
* T Bar M Resort Conference Center*
* New Braunfels, Texas *
* Contact [EMAIL PROTECTED] *
* *
* Want to present a paper or workshop? Contact now! *
*
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[PHP] Undefined index error
I'm using the superglobal $_POST array to access URL parameters passed to my page. I was getting undefined constant errors in my error_log file, and found that I needed to quote the variables in the array. $_POST['SortBy'] etc. Now, it appears that I've just traded the undefined constant errors for undefined index warnings. Everytime a page hits a page with url parameters, it triggers a warning in the error_log file. What's triggering these undefined index errors? I suppose I could lower the logging level in php.ini, but I'd rather code properly than to hide the problem. Thanks! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Undefined index error
If you try to access a form variable that hasn't been set, you get an
undefined index. Try checking with something like
if(isset($_POST['SortBy'])) {
// do something with 'SortBy'
}
In any case, you'll get the undefined index warning anytime you try to
read an array index that hasn't been set.
..michael..
On Mon, 2002-08-19 at 14:49, Shu Chow wrote:
I'm using the superglobal $_POST array to access URL
parameters passed to my page. I was getting undefined
constant errors in my error_log file, and found that I
needed to quote the variables in the array.
$_POST['SortBy'] etc. Now, it appears that I've just
traded the undefined constant errors for undefined index
warnings. Everytime a page hits a page with url
parameters, it triggers a warning in the error_log file.
What's triggering these undefined index errors? I suppose
I could lower the logging level in php.ini, but I'd rather
code properly than to hide the problem. Thanks!
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[PHP] Undefined Index
It's me again, i don't mean to be a bugger, but i really like to learn as
much as possible, that's why i ask (or will ask so many questions).
Consider the following (i shortened this a lot, but it will do the trick)
$op = $_GET['op'];
switch ( $op )
{
case admin:
DoLogin();
break;
default:
ShowHomepage();
break;
}
PHP shoots a Notice Message telling me that there is an undefined index
Undefined index: act in g:\apache_web\intern\looney\index.php on line 177
This accects the code shown above.
Ok, am i correct in assuming that it pops this message because $op is not
defined as anything yet?
If so,should i always just do this
$_POST['op'] = '';
$op = $_GET['op'];
switch ( $op )
{
//Code here
}
Or would it be better and more space efficient to do this
$op = isset($_GET['op']);
switch ( $op )
{
//Code here
}
Cause if i do that the Notice Message dissapears for some reason i yet fail
to grab.
I would really appreciate if somebody could explain to me why the Notice
dissapears when using isset(), and also what is the best method to use
rather then the two shown above?
How do you guysgirls handle this?
Thanks a lot in advance for your time and patience!
Best regards from Vienna,
Jürgen
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Re: [PHP] Undefined Index
Jrgen wrote:
$op = $_GET['op'];
switch ( $op )
PHP shoots a Notice Message telling me that there is an undefined index
Undefined index: act in g:\apache_web\intern\looney\index.php on line 177
If there is not a get variable in the url you will get the warning.
Ok, am i correct in assuming that it pops this message because $op is not
defined as anything yet?
Yes,
If so,should i always just do this
$_POST['op'] = '';
$op = $_GET['op'];
switch ( $op )
{
//Code here
}
If there is not a get variable callled op you should still get the
warning.
$op = isset($_GET['op']);
switch ( $op )
{
//Code here
}
Now $op will be a boolean assigned the value true (if there is a get
variable called op in the url) or false if not. As $op will have a
value then there is no warning.
What I tend to do when I have an optional item of data is:
if (isset($_GET[op])) [
$op = $_GET[op];
}
else
{
$op = no value;// set to something you can test for in
your switch statement.
}
though there may be a better way.
Best regards from Vienna,
Jrgen
.. thanks, and best regards to you from Essex, England.
HTH
Chris
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[PHP] Undefined index?
Hi everybody Does anybody knows what means Undefined index error? I couldn't find it in docs neither in php online doc site. Thank you Ivo -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] Undefined index?
If one has :
$arr = array('a','b','c');
And calls upon the following :
$arr[b] (as opposed to $arr['b'])
Then the following will result :
Warning: Use of undefined constant b - assumed 'b' in ./tmp.php on line 13
Warning: Undefined index: b in ./tmp.php on line 13
Always use quotes around the keys/indexes within associative arrays
otherwise the constant is looked for first and unexpected results are
possible. Now if we have (which you most likely did) :
$arr['d']
Then we get the following as index 'd' does not exist within the array :
Warning: Undefined index: d in ./tmp.php on line 13
A similar error is created when doing this :
echo $iamnotset;
if ($iamnotset) {
Which results in :
Warning: Undefined variable: iamnotset in ./tmp.php on line 11
Using something similar to isset() helps combat that :
if (isset($iamnotset)) {
All of the above errors (Notices) are of the E_NOTICE type. If E_NOTICE
is turned on within the error_reporting setting within php.ini (or via a
call to the error_reporting() function or ...), then you'll see it
otherwise you will not. I'm not sure why Notices say Warning: ... but
they do :-)
Typically one turns errors up during development, and down during
production use. And, it's not uncommon to see this question come about
within various support forums/lists for various PHP applications.
Regards,
Philip
-Original Message-
From: Ivo Stoykov [mailto:[EMAIL PROTECTED]]
Sent: 11 iulie 2001 17:21
To: [EMAIL PROTECTED]
Subject: [PHP] Undefined index?
Hi everybody
Does anybody knows what means Undefined index error? I
couldn't find it in
docs neither in php online doc site.
Thank you
Ivo
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