I have 5 SELECT for Department, Manager, supervisor, Group Leader and
Employees
I want to every SELECT list narrow down for an upper SELECT.
For example, once user select Department then all Manager, Supervisor, Group
Leader and Employee list will be narrow down by department and same for
manag
> -Original Message-
> From: Stuart Dallas [mailto:stu...@3ft9.com]
> Sent: 25 October 2012 22:48
Aw, nuts! Stuart, you just beat me to it! I was half way through writing an
almost identical post when yours popped into my Inbox
Cheers!
Mike
--
Mike Ford,
Electronic Information Dev
On 25 Oct 2012, at 22:35, "Jeff Burcher" wrote:
> I can't remember if this is the PHP list for RPG programmers or not, so
> apologize if this is the wrong one.
Not an RPG list, but your question is PHP-related more than it's RPG-related.
> Is there an equivalent command in PHP for the SELECT sta
On Thu, Oct 25, 2012 at 5:35 PM, Jeff Burcher wrote:
> Hi,
>
>
>
> I can't remember if this is the PHP list for RPG programmers or not, so
> apologize if this is the wrong one.
This is just a general PHP mailing list. Guessing you need the other one.
--
Network Infrastructure Manager
http
Hi,
I can't remember if this is the PHP list for RPG programmers or not, so
apologize if this is the wrong one.
Is there an equivalent command in PHP for the SELECT statement in RPG? I see
switch, which is a little similar, but far from how it actually functions.
For those not familiar
-Original Message-
From: Ashley Sheridan [mailto:a...@ashleysheridan.co.uk]
Sent: Friday, July 02, 2010 2:43 PM
To: b...@tottd.com
Cc: php-general@lists.php.net
Subject: Re: [PHP] SELECT AVG(rating)
On Fri, 2010-07-02 at 14:32 -0600, Ben Miller wrote:
> Hi - I have a MySQL table f
On Fri, 2010-07-02 at 14:32 -0600, Ben Miller wrote:
> Hi - I have a MySQL table full of product reviews and I'm trying to select
> info for only the top 5 rated products. The only way I can figure out how
> to do it so far is something like:
>
> $query1 = mysql_query("SELECT * FROM products");
Hi - I have a MySQL table full of product reviews and I'm trying to select
info for only the top 5 rated products. The only way I can figure out how
to do it so far is something like:
$query1 = mysql_query("SELECT * FROM products");
for($i=1;$i<=mysql_num_rows($query1);$i++) {
$row1 = mys
> Date: Mon, 31 May 2010 11:56:38 -0400
> To: php-general@lists.php.net; aj...@alumni.iu.edu
> From: tedd.sperl...@gmail.com
> Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different
> Forms
>
> At 7:23 PM -0400 5/30/10, Alice Wei wrote:
>
At 7:23 PM -0400 5/30/10, Alice Wei wrote:
Tedd,
Looks like I finally found the answer to my question, and the key
is the term, dependent drop down menu. There is an example that I
found here,
http://www.huanix.com/files/dependent_select/dependent_select.txt,
and after editing everything,
> Date: Sun, 30 May 2010 11:53:44 -0400
> To: php-general@lists.php.net; aj...@alumni.iu.edu
> From: tedd.sperl...@gmail.com
> Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different
> Forms
>
> At 12:08 PM -0400 5/29/10, Alice Wei wrote:
> >
At 12:08 PM -0400 5/29/10, Alice Wei wrote:
At the time of writing this, I got all the functionality I wanted,
only that it takes 3 submits, which is 4 pages in total, which
includes two dependent select menus based on user input by clicking
on the radio button and some other static drop down
> Date: Sat, 29 May 2010 11:50:50 -0400
> To: php-general@lists.php.net; aj...@alumni.iu.edu
> From: tedd.sperl...@gmail.com
> Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different
> Forms
>
> At 7:31 PM -0400 5/28/10, Alice Wei wro
At 7:31 PM -0400 5/28/10, Alice Wei wrote:
Anything I want?
Seriously, I do know how to pass a "non-dynamic" element from one
page to another page, but when I started researching on how to
utilize dynamic menus based on user input, I found Ajax, until this
problem that I am running into hits
On Fri, May 28, 2010 at 8:01 PM, Alice Wei wrote:
>
>
> From: aj...@alumni.iu.edu
> To: tedd.sperl...@gmail.com
> CC: php-general@lists.php.net
> Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different
> Forms
> Date: Fri, 28 May 2010 19:31:10 -04
From: aj...@alumni.iu.edu
To: tedd.sperl...@gmail.com
CC: php-general@lists.php.net
Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different Forms
Date: Fri, 28 May 2010 19:31:10 -0400
> Date: Fri, 28 May 2010 17:18:21 -0400
> To: aj...@alumni.iu.edu
> Fr
> Date: Fri, 28 May 2010 17:18:21 -0400
> To: aj...@alumni.iu.edu
> From: tedd.sperl...@gmail.com
> Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different
> Forms
> CC: php-general@lists.php.net
>
> >On Fri, 2010-05-28 at 15:12 -0400, Alice W
On Fri, 2010-05-28 at 15:12 -0400, Alice Wei wrote:
What I am trying to find out is, when I have my form with a
dependent select menu, how can I pass the value of the select menu
to another page? I have mentioned in the initial email that if I
just allow users to type stuff, it passes the for
Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different Forms
From: a...@ashleysheridan.co.uk
To: aj...@alumni.iu.edu
CC: tedd.sperl...@gmail.com; php-general@lists.php.net
Date: Fri, 28 May 2010 20:14:06 +0100
On Fri, 2010-05-28 at 15:12 -0400, Alice Wei
On Fri, 2010-05-28 at 15:12 -0400, Alice Wei wrote:
> Subject: RE: [PHP] Select Values Didn't Get Passed in From Two
> Different Forms
> From: a...@ashleysheridan.co.uk
> To: aj...@alumni.iu.edu
> CC: tedd.sperl...@gmail.com; php-general@lists.php.net
> Date: Fri, 28
Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different Forms
From: a...@ashleysheridan.co.uk
To: aj...@alumni.iu.edu
CC: tedd.sperl...@gmail.com; php-general@lists.php.net
Date: Fri, 28 May 2010 20:05:29 +0100
On Fri, 2010-05-28 at 15:00 -0400, Alice Wei
On Fri, 2010-05-28 at 15:00 -0400, Alice Wei wrote:
>
> Date: Fri, 28 May 2010 12:34:55 -0400
> > To: aj...@alumni.iu.edu; php-general@lists.php.net
> > From: tedd.sperl...@gmail.com
> > Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different
&
Date: Fri, 28 May 2010 12:34:55 -0400
> To: aj...@alumni.iu.edu; php-general@lists.php.net
> From: tedd.sperl...@gmail.com
> Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different
> Forms
>
> At 9:19 PM -0400 5/27/10, Alice Wei wrote:
> >
&
At 9:19 PM -0400 5/27/10, Alice Wei wrote:
I am not sure how to add to the page you have set up, but here is
the code with ther portion you have set up:
Select the type of your starting point of interest:
Which Semster is this:
> Date: Thu, 27 May 2010 12:23:46 -0400
> To: aj...@alumni.iu.edu; php-general@lists.php.net
> From: tedd.sperl...@gmail.com
> Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different Forms
>
> At 3:50 PM -0400 5/26/10, Alice Wei wrote:
> >
> &
At 3:50 PM -0400 5/26/10, Alice Wei wrote:
My bad, I cannot imagine I sent that stuff. To answer your
question, here it is,
Select the type of your starting point of interest:
maxlength="50"/>
Thi
On Wed, 26 May 2010 11:02:10 -0400, Alice Wei wrote:
[De-indented to preserve sanity]
>
>
Bzzt. Only elements can be children of .
> Select the type of your starting point of interest:
>
>
Bzzt. You didn't close the previous . You can *not*
have nested elements.
>
On 5/26/2010 3:50 PM, Alice Wei wrote:
Date: Wed, 26 May 2010 15:36:18 -0400
To: php-general@lists.php.net; aj...@alumni.iu.edu
From: tedd.sperl...@gmail.com
Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different Forms
Alice:
You provide:
Select the type of
> Date: Wed, 26 May 2010 15:36:18 -0400
> To: php-general@lists.php.net; aj...@alumni.iu.edu
> From: tedd.sperl...@gmail.com
> Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different Forms
>
> Alice:
>
> You provide:
>
> >
> >
&
Alice:
You provide:
Select the type of your starting point of interest:
action="test_getrss.php" name="form1" method="post">
value="Apartment" name="start"
onclick="check(document.form1.
> Date: Wed, 26 May 2010 09:19:26 -0400
> To: php-general@lists.php.net; aj...@alumni.iu.edu
> From: tedd.sperl...@gmail.com
> Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different
> Forms
>
> At 9:17 PM -0400 5/25/10, Alice Wei wrote:
> >No,
At 9:17 PM -0400 5/25/10, Alice Wei wrote:
No, the fields are populated in the first and second
form, form1 and form2. What I want to do is to get the selections from
both forms and pass them on to the third. Does this make sense? For some
reason, the text input and the semester drop down menu r
From: Alice Wei
> On Tue, 2010-05-25 at 15:41 -0400, Alice Wei wrote:
>
>> Date: Tue, 25 May 2010 13:40:44 -0400
>> Subject: Re: [PHP]
> Select Values Didn't Get Passed in From Two Different Forms
>>
> From: marc.g...@gmail.com
>> To: aj...@alumni.iu.
On Wed, 2010-05-26 at 08:28 -0400, Alice Wei wrote:
> On Tue, 2010-05-25 at 15:41 -0400, Alice Wei wrote:
>
> > Date: Tue, 25 May 2010 13:40:44 -0400
> > Subject: Re: [PHP]
> Select Values Didn't Get Passed in From Two Different Forms
> >
> From: marc.g...@gm
On Tue, 2010-05-25 at 15:41 -0400, Alice Wei wrote:
> Date: Tue, 25 May 2010 13:40:44 -0400
> Subject: Re: [PHP]
Select Values Didn't Get Passed in From Two Different Forms
>
From: marc.g...@gmail.com
> To: aj...@alumni.iu.edu
>
>
> I would like to take those valu
age-
From: Adam Richardson [mailto:simples...@gmail.com]
Sent: Wednesday, May 26, 2010 1:31 AM
To: php-general@lists.php.net
Subject: Re: [PHP] Select Values Didn't Get Passed in From Two Different
Forms
On Tue, May 25, 2010 at 1:17 PM, Alice Wei wrote:
>
> Hi,
>
> It is kind
On Tue, 2010-05-25 at 21:17 -0400, Alice Wei wrote:
>
> Subject: Re: [PHP] Select Values Didn't Get Passed in From Two Different Forms
> From: a...@ashleysheridan.co.uk
> To: aj...@alumni.iu.edu
> CC: php-general@lists.php.net
> Date: Tue, 25
Subject: Re: [PHP] Select Values Didn't Get Passed in From Two Different Forms
From: a...@ashleysheridan.co.uk
To: aj...@alumni.iu.edu
CC: php-general@lists.php.net
Date: Tue, 25 May 2010 20:37:29 +0100
On Tue, 2010-05-25 at 15:41 -0400, Alice Wei wrote:
> Date: Tue, 25
On Tue, 2010-05-25 at 15:41 -0400, Alice Wei wrote:
> > Date: Tue, 25 May 2010 13:40:44 -0400
> > Subject: Re: [PHP]
> Select Values Didn't Get Passed in From Two Different Forms
> >
> From: marc.g...@gmail.com
> > To: aj...@alumni.iu.edu
> >
> &
> Date: Tue, 25 May 2010 13:40:44 -0400
> Subject: Re: [PHP]
Select Values Didn't Get Passed in From Two Different Forms
>
From: marc.g...@gmail.com
> To: aj...@alumni.iu.edu
>
>
> I would like to take those values away into my third form, which
is what you
> &
>> > I would like to take those values away into my third form, which is what
>> > you
>> > see with the hidden. If they are not populated, then how come I could
>> > see
>> > the drop down menus?
>>
>> So you're expecting the values selected in the first two forms to
>> populate the values of the
On Tue, May 25, 2010 at 1:17 PM, Alice Wei wrote:
>
> Hi,
>
> It is kind of difficult to explain what I am trying to do here, I will
> provide the form here to give a better idea.
>
>
>Select the type of your starting point of
> interest:
>
Hi,
It is kind of difficult to explain what I am trying to do here, I will
provide the form here to give a better idea.
Select the type of your starting point of
interest:
Apartment
On 7/1/09 10:29 AM, "Andrew Ballard" wrote:
$data = array($ucName, $ucAddress, $inDate, $inType, $notes,
> $critical, $cleanViolations, $noncritical);
>
> $sql = vprintf("INSERT INTO `restaurants` (name, address, inDate,
> inType, notes, critical, cviolations, noncritical) VALUES ('%s', '%s',
On Wed, Jul 1, 2009 at 11:23 AM, Andrew Ballard wrote:
> On Wed, Jul 1, 2009 at 10:56 AM, Miller,
> Terion wrote:
>> Why doesn't this work?
>>
>>
>> $query = "SELECT * FROM `restaurants` WHERE name ='$ucName' AND
>> address = '$ucAddress' " ;
>>
>> $result = mysql_query($query) or die(mysql_err
On 7/1/09 10:06 AM, "Phpster" wrote:
On Jul 1, 2009, at 10:56 AM, "Miller, Terion" wrote:
> Why doesn't this work?
>
>
>$query = "SELECT * FROM `restaurants` WHERE name ='$ucName' AND
> address = '$ucAddress' " ;
>
> $result = mysql_query($query) or die(mysql_error());
>
>
> echo
On Wed, Jul 1, 2009 at 10:56 AM, Miller,
Terion wrote:
> Why doesn't this work?
>
>
> $query = "SELECT * FROM `restaurants` WHERE name ='$ucName' AND
> address = '$ucAddress' " ;
>
> $result = mysql_query($query) or die(mysql_error());
>
>
> echo $result;
> $row = mysql_fetch_array ($resul
On Jul 1, 2009, at 10:56 AM, "Miller, Terion" > wrote:
Why doesn't this work?
$query = "SELECT * FROM `restaurants` WHERE name ='$ucName' AND
address = '$ucAddress' " ;
$result = mysql_query($query) or die(mysql_error());
echo $result;
$row = mysql_fetch_array ($result);
$s
Why doesn't this work?
$query = "SELECT * FROM `restaurants` WHERE name ='$ucName' AND
address = '$ucAddress' " ;
$result = mysql_query($query) or die(mysql_error());
echo $result;
$row = mysql_fetch_array ($result);
$sql = "INSERT INTO `restaurants` (name, address, in
> in VBSCRIPT
In what?
Use [] at the end of your selects name:
...
--
Richard Heyes
HTML5 Canvas graphing for Firefox, Chrome, Opera and Safari:
http://www.rgraph.net (Updated April 11th)
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.
If I allow multiple selections in a MENU LIST, in VBSCRIPT it comes
through with each selection being separated by a comma, in the same
variable...ie.:
myVal = request("mySelectmenu")
myVal could equal -> "selection 1, selection 2, selection 3"
But in PHP, I capture it as:
$mySelectMenu = $_POS
On Sun, 2009-03-22 at 09:22 +0800, Virgilio Quilario wrote:
> >> Trying to find best way to accomplish following scenario. Looking to
> >> search
> >> inventory through a POST form, have the following optional fields to search
> >> by: Product Name, Color, Size, and Status. Search maybe for the
>> Trying to find best way to accomplish following scenario. Looking to search
>> inventory through a POST form, have the following optional fields to search
>> by: Product Name, Color, Size, and Status. Search maybe for the Product
>> Name and/or Color or they may search for just the Color or al
On Sat, 2009-03-21 at 10:30 -0700, ben...@gmail.com wrote:
> Trying to find best way to accomplish following scenario. Looking to search
> inventory through a POST form, have the following optional fields to search
> by: Product Name, Color, Size, and Status. Search maybe for the Product
> Name a
Trying to find best way to accomplish following scenario. Looking to search
inventory through a POST form, have the following optional fields to search
by: Product Name, Color, Size, and Status. Search maybe for the Product
Name and/or Color or they may search for just the Color or all 4 fields.
And yet another thing i have overseen in my statement ..
If you remove the first for loop, also change the sql query. But I'm
sure you saw that already
NEW QUERY:
$sql = "SELECT study,symbol FROM test WHERE study IN ('".implode(', ',
$myArray)."')";
--
PHP General Mailing List (http://www.php.ne
I actually would do more like:
$myArray[$study][$symbol] = true;
No need to call in_array.
Probably won't matter, really, but it's a good practice for when you end up
doing the same kind of code for an array with thousands of elements.
--
PHP General Mailing List (http://www.php.net/
Thanks Yeti, it works.
Best, Andrej
Yeti wrote:
Correcting myself now ..
$myArray = array('b2005', 'b2008');
$sql = "SELECT study,symbol FROM test WHERE study IN ('$myArray[$i]')";
$result = mysql_query($sql);
if(mysql_num_rows($result) > 0) {
while ($myrow = mysql_fetch_array($result)) {
Correcting myself now ..
$myArray = array('b2005', 'b2008');
$sql = "SELECT study,symbol FROM test WHERE study IN ('$myArray[$i]')";
$result = mysql_query($sql);
if(mysql_num_rows($result) > 0) {
while ($myrow = mysql_fetch_array($result)) {
if (in_array($myrow['study'], $myArray))
$combi
> How should I proceed? Thanks in advance for any suggestions.
Since you are looping through the result already, why not do it this way ..
$combinedArray = array();
for ($i=0;$i 0) {
while ($myrow = mysql_fetch_array($result)) {
if (in_array($myrow['study'], $myArray))
$combinedArray[$m
Dear all,
I have a MySQL table 'test' which includes two columns: 'study' and
'symbol':
study symbol
a2008 A
a2008 B
a2008 C
a2008 D
b2005 A
b2005 B
b2005 E
Using POST variable I passed 'study' values into $myArray:
// $myArray is variable length; used only two values in example
$myArray =
On Wednesday 19 December 2007 03:59:11 Richard Lynch wrote:
> On Tue, December 18, 2007 2:06 pm, Børge Holen wrote:
> > On Tuesday 18 December 2007 20:03:53 Stut wrote:
> >> VamVan wrote:
> >> > Please apologize for sending this question to PHP forums.
> >>
> >> If you know this already why ask the
On Tue, December 18, 2007 2:06 pm, Børge Holen wrote:
> On Tuesday 18 December 2007 20:03:53 Stut wrote:
>> VamVan wrote:
>> > Please apologize for sending this question to PHP forums.
>>
>> If you know this already why ask the question here? Also, this is
>> not a
>> forum.
>>
>> > But I would app
On Tuesday 18 December 2007 21:16:46 you wrote:
> Why not try a css list? css-discuss for example?
Yes why not?
>
> On Dec 18, 2007 8:06 PM, Børge Holen <[EMAIL PROTECTED]> wrote:
> > On Tuesday 18 December 2007 20:03:53 Stut wrote:
> > > VamVan wrote:
> > > > Please apologize for sending this qu
Why not try a css list? css-discuss for example?
On Dec 18, 2007 8:06 PM, Børge Holen <[EMAIL PROTECTED]> wrote:
> On Tuesday 18 December 2007 20:03:53 Stut wrote:
> > VamVan wrote:
> > > Please apologize for sending this question to PHP forums.
> >
> > If you know this already why ask the questi
On Tuesday 18 December 2007 20:03:53 Stut wrote:
> VamVan wrote:
> > Please apologize for sending this question to PHP forums.
>
> If you know this already why ask the question here? Also, this is not a
> forum.
>
> > But I would appreciate it very much if some could please help me styling
> > in
VamVan wrote:
Please apologize for sending this question to PHP forums.
If you know this already why ask the question here? Also, this is not a
forum.
But I would appreciate it very much if some could please help me styling
in HTMl with CSS?
I have .selectmulti { border: 1px solid #c9c9c9
Hi All,
Please apologize for sending this question to PHP forums.
But I would appreciate it very much if some could please help me styling
in HTMl with CSS?
I have .selectmulti { border: 1px solid #c9c9c9 } this code but it only
works in firefox How can I make this work in IE?
And also I want
On Tue, January 30, 2007 7:23 pm, Craige Leeder wrote:
>> atleast this part: $user_id = mysql_real_escape_string((int)
>> $_GET['user_id']);
>
> I'm not sure who put this in there, but you don't need to use
> mysql_real_escape_string() on that value if you're type casting it. If
> you are forcing i
On Tue, January 30, 2007 4:14 pm, nitrox . wrote:
> Richard, ive included your suggested code and now my php script is
> working
> properly. But I dont want to be a php copy/paste newb who has no clue
> of how
> things are working. If its not too much would you (or anybody) give a
> brief
> explana
atleast this part: $user_id = mysql_real_escape_string((int)
$_GET['user_id']);
I'm not sure who put this in there, but you don't need to use
mysql_real_escape_string() on that value if you're type casting it. If
you are forcing it to be an integer, there is nothing to escape.
Integers are perfe
At 1/30/2007 02:14 PM, nitrox . wrote:
If its not too much would you (or anybody) give a brief explanation
of what this code is doing? Or are there any tutorials online that I
can read that will educate me on this? Thanks again to all for your
replies. Ive saved them all for future reference.
Thanks to all who have replied. As you probably have noticed im a total
novice to php who is trying to achieve big things.
Richard, ive included your suggested code and now my php script is working
properly. But I dont want to be a php copy/paste newb who has no clue of how
things are working.
On Mon, January 29, 2007 7:43 pm, Larry Garfield wrote:
> On Monday 29 January 2007 7:19 pm, Richard Lynch wrote:
>
>> Looks like PostgreSQL caved in to the unwashed masses of MySQL users
>> who couldn't handle not putting apostrophes around everything to
>> me...
>> [sigh]
>>
>> :-) :-) :-)
>>
>>
On Monday 29 January 2007 7:19 pm, Richard Lynch wrote:
> Looks like PostgreSQL caved in to the unwashed masses of MySQL users
> who couldn't handle not putting apostrophes around everything to me...
> [sigh]
>
> :-) :-) :-)
>
> Oh well.
>
> I personally would prefer that the DB not accept bogus i
On Mon, January 29, 2007 6:55 pm, Roman Neuhauser wrote:
> # [EMAIL PROTECTED] / 2007-01-29 17:54:03 -0600:
>> MySQL is the *only* db engine that lets you get away with [bleep]
>> like
>> apostrophes around numbers.
>
> Actually, these are examples of valid SQL: INTEGER '1', FLOAT '13.5'.
> test=#
# [EMAIL PROTECTED] / 2007-01-29 17:54:03 -0600:
> MySQL is the *only* db engine that lets you get away with [bleep] like
> apostrophes around numbers.
Actually, these are examples of valid SQL: INTEGER '1', FLOAT '13.5'.
test=# select version();
versi
On Sun, January 28, 2007 6:20 pm, Larry Garfield wrote:
> On Sunday 28 January 2007 5:54 pm, Francisco M. Marzoa Alonso wrote:
>> On dom, 2007-01-28 at 18:51 -0500, nitrox . wrote:
>> > I took the quotes off. I thought that quotes around numbers was
>> wrong
>> > also.
>>
>> Quotes are no necessary
> January 28, 2007 6:20 pm, Larry Garfield wrote:
> On Sunday 28 January 2007 5:54 pm, Francisco M. Marzoa Alonso wrote:
>> On dom, 2007-01-28 at 18:51 -0500, nitrox . wrote:
>> > I took the quotes off. I thought that quotes around numbers was
>> wrong
>> > also.
>>
>> Quotes are no necessary aroun
On Sun, January 28, 2007 5:21 pm, nitrox . wrote:
> Im trying to display one record at a time by ID. Well im getting a
> blank
> page. Ive looked over my code and tried 20 different ways to get it to
> work
> to no avail. So any pointers on what Im doing wrong would be great.
> here is
> the code i
On Sun, 2007-01-28 at 21:12 -0500, Craige Leeder wrote:
> As someone else already stated, my best guess according to that error
> is that $user_id has a null, or inappropriate value. The error occurs
> at the last character of the query, so it has to be something like
> hat. Echo the query and let
As someone else already stated, my best guess according to that error
is that $user_id has a null, or inappropriate value. The error occurs
at the last character of the query, so it has to be something like
hat. Echo the query and let us know what it outputs.
- Craige
On 1/28/07, Francisco M. Ma
On dom, 2007-01-28 at 18:20 -0600, Larry Garfield wrote:
> On Sunday 28 January 2007 5:54 pm, Francisco M. Marzoa Alonso wrote:
> > On dom, 2007-01-28 at 18:51 -0500, nitrox . wrote:
> > > I took the quotes off. I thought that quotes around numbers was wrong
> > > also.
> >
> > Quotes are no necess
On Sunday 28 January 2007 5:54 pm, Francisco M. Marzoa Alonso wrote:
> On dom, 2007-01-28 at 18:51 -0500, nitrox . wrote:
> > I took the quotes off. I thought that quotes around numbers was wrong
> > also.
>
> Quotes are no necessary around numeric values, but they aren't wrong
> neither, simply op
On dom, 2007-01-28 at 18:51 -0500, nitrox . wrote:
> I took the quotes off. I thought that quotes around numbers was wrong also.
Quotes are no necessary around numeric values, but they aren't wrong
neither, simply optional.
> I added the error checking and this is the error:
>
> Could not perfo
At 1/28/2007 03:21 PM, nitrox . wrote:
Im trying to display one record at a time by ID. Well im getting a
blank page. Ive looked over my code and tried 20 different ways to
get it to work to no avail. So any pointers on what Im doing wrong
would be great. here is the code im working with so far
Ops!, Better this one:
$query = "SELECT inf_member WHERE user_id='$user_id' ";
$result = mysql_query($query);
if ( ! $result ) {
die ("Could not perform query $query: ".mysql_error()."\n");
}
I did copy and paste from my own code and you've not $que
I took the quotes off. I thought that quotes around numbers was wrong also.
I added the error checking and this is the error:
Could not perform query : You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for the right syntax to
use near '' at li
The first thing that I probably do is to check for possible errors from
DB:
$result = mysql_query("SELECT * FROM inf_member WHERE
user_id='$user_id' ");
if ( ! $result ) {
die ("Could not perform query $query: ".mysql_error()."\n");
}
Regards,
On dom, 200
Before I ask my next question I just wanted to thank you all for being in
this mailing community and sharing your knowledge. Its communitys like this
that make life easier for all of us. Ok enough with the mushy stuff
Im trying to display one record at a time by ID. Well im getting a blank
pag
2006/11/24, Richard Lynch <[EMAIL PROTECTED]>:
On Fri, November 24, 2006 10:27 am, Yves Tannier wrote:
> First, sorry for my bad english ;)
>
> I'm looking for a simple way to provide query with two table like this
> :
>
> SELECT t1.idperson, t1.lastname FROM table1 t1, table2 t2 WHERE
> t1.idpe
On Fri, November 24, 2006 10:27 am, Yves Tannier wrote:
> First, sorry for my bad english ;)
>
> I'm looking for a simple way to provide query with two table like this
> :
>
> SELECT t1.idperson, t1.lastname FROM table1 t1, table2 t2 WHERE
> t1.idperson=t2.idperson AND t1.idperson=2
>
> I try with
Hi,
First, sorry for my bad english ;)
I'm looking for a simple way to provide query with two table like this :
SELECT t1.idperson, t1.lastname FROM table1 t1, table2 t2 WHERE
t1.idperson=t2.idperson AND t1.idperson=2
I try with joinAdd and selectAs but its always complexe query like :
SELECT
Richard Lynch wrote:
On Thu, August 17, 2006 9:02 am, João Cândido de Souza Neto wrote:
I´m not sure if it´s the right place to get such answer, but if
someone
know, please, help me.
In a select id,name,picture1,picture2,picture3 from product where
id="10" i
get an array with each colum in each
On Fri, August 18, 2006 1:32 pm, Adam Zey wrote:
> I must say, I'm of the opinion that as much data processing should be
> done in the database server possible.
I agree with you 100% in principle...
But in this case, we're talking about structuring the data in a
PHP-specific data structure for ea
On Thu, August 17, 2006 9:02 am, João Cândido de Souza Neto wrote:
> I´m not sure if it´s the right place to get such answer, but if
> someone
> know, please, help me.
>
> In a select id,name,picture1,picture2,picture3 from product where
> id="10" i
> get an array with each colum in each element li
Adam Zey wrote:
I must say
So you've said. Three times now. ;)
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Programmer/System Admin (ÜberGeek)
Dot Com Holdings of Buffalo
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On Thu, 2006-08-17 at 11:02 -0300, João Cândido de Souza Neto wrote:
> Hi everyone,
>
> Im not sure if its the right place to get such answer, but if someone
> know, please, help me.
>
> In a select id,name,picture1,picture2,picture3 from product where id="10" i
> get an array with each colum i
Hi everyone,
I´m not sure if it´s the right place to get such answer, but if someone
know, please, help me.
In a select id,name,picture1,picture2,picture3 from product where id="10" i
get an array with each colum in each element like this $result ("id" =>
"10", "name" => "name of product", "
Roel Dillen wrote:
> I have a xhtml form with a with options
>
> if I click submit the processing page is loaded and the result of the form is
> shown.
> The option given to the processing page however is always the same: the first
> in the list. It doesn't matter what I select in the drop down
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