On Thu, Oct 25, 2012 at 5:35 PM, Jeff Burcher j...@allredmetal.com wrote:
Hi,
I can't remember if this is the PHP list for RPG programmers or not, so
apologize if this is the wrong one.
This is just a general PHP mailing list. Guessing you need the other one.
--
/Daniel P. Brown
On 25 Oct 2012, at 22:35, Jeff Burcher j...@allredmetal.com wrote:
I can't remember if this is the PHP list for RPG programmers or not, so
apologize if this is the wrong one.
Not an RPG list, but your question is PHP-related more than it's RPG-related.
Is there an equivalent command in PHP
-Original Message-
From: Stuart Dallas [mailto:stu...@3ft9.com]
Sent: 25 October 2012 22:48
Aw, nuts! Stuart, you just beat me to it! I was half way through writing an
almost identical post when yours popped into my Inbox
Cheers!
Mike
--
Mike Ford,
Electronic Information
On Fri, 2010-07-02 at 14:32 -0600, Ben Miller wrote:
Hi - I have a MySQL table full of product reviews and I'm trying to select
info for only the top 5 rated products. The only way I can figure out how
to do it so far is something like:
$query1 = mysql_query(SELECT * FROM products);
-Original Message-
From: Ashley Sheridan [mailto:a...@ashleysheridan.co.uk]
Sent: Friday, July 02, 2010 2:43 PM
To: b...@tottd.com
Cc: php-general@lists.php.net
Subject: Re: [PHP] SELECT AVG(rating)
On Fri, 2010-07-02 at 14:32 -0600, Ben Miller wrote:
Hi - I have a MySQL table full
At 7:23 PM -0400 5/30/10, Alice Wei wrote:
Tedd,
Looks like I finally found the answer to my question, and the key
is the term, dependent drop down menu. There is an example that I
found here,
http://www.huanix.com/files/dependent_select/dependent_select.txt,
and after editing everything,
Date: Mon, 31 May 2010 11:56:38 -0400
To: php-general@lists.php.net; aj...@alumni.iu.edu
From: tedd.sperl...@gmail.com
Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different
Forms
At 7:23 PM -0400 5/30/10, Alice Wei wrote:
Tedd,
Looks like I finally found
At 12:08 PM -0400 5/29/10, Alice Wei wrote:
At the time of writing this, I got all the functionality I wanted,
only that it takes 3 submits, which is 4 pages in total, which
includes two dependent select menus based on user input by clicking
on the radio button and some other static drop
Date: Sun, 30 May 2010 11:53:44 -0400
To: php-general@lists.php.net; aj...@alumni.iu.edu
From: tedd.sperl...@gmail.com
Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different
Forms
At 12:08 PM -0400 5/29/10, Alice Wei wrote:
At the time of writing this, I got all
At 7:31 PM -0400 5/28/10, Alice Wei wrote:
Anything I want?
Seriously, I do know how to pass a non-dynamic element from one
page to another page, but when I started researching on how to
utilize dynamic menus based on user input, I found Ajax, until this
problem that I am running into hits
Date: Sat, 29 May 2010 11:50:50 -0400
To: php-general@lists.php.net; aj...@alumni.iu.edu
From: tedd.sperl...@gmail.com
Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different
Forms
At 7:31 PM -0400 5/28/10, Alice Wei wrote:
Anything I want?
Seriously, I do know
At 9:19 PM -0400 5/27/10, Alice Wei wrote:
I am not sure how to add to the page you have set up, but here is
the code with ther portion you have set up:
?php
$start = isset($_POST['start']) ? $_POST['start'] : null;
?
form action= method=post
p
Select the type of your
Date: Fri, 28 May 2010 12:34:55 -0400
To: aj...@alumni.iu.edu; php-general@lists.php.net
From: tedd.sperl...@gmail.com
Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different
Forms
At 9:19 PM -0400 5/27/10, Alice Wei wrote:
I am not sure how to add to the page
On Fri, 2010-05-28 at 15:00 -0400, Alice Wei wrote:
Date: Fri, 28 May 2010 12:34:55 -0400
To: aj...@alumni.iu.edu; php-general@lists.php.net
From: tedd.sperl...@gmail.com
Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different
Forms
At 9:19 PM -0400 5/27/10
Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different Forms
From: a...@ashleysheridan.co.uk
To: aj...@alumni.iu.edu
CC: tedd.sperl...@gmail.com; php-general@lists.php.net
Date: Fri, 28 May 2010 20:05:29 +0100
On Fri, 2010-05-28 at 15:00 -0400, Alice Wei wrote
On Fri, 2010-05-28 at 15:12 -0400, Alice Wei wrote:
Subject: RE: [PHP] Select Values Didn't Get Passed in From Two
Different Forms
From: a...@ashleysheridan.co.uk
To: aj...@alumni.iu.edu
CC: tedd.sperl...@gmail.com; php-general@lists.php.net
Date: Fri, 28 May 2010 20:05:29 +0100
On Fri
Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different Forms
From: a...@ashleysheridan.co.uk
To: aj...@alumni.iu.edu
CC: tedd.sperl...@gmail.com; php-general@lists.php.net
Date: Fri, 28 May 2010 20:14:06 +0100
On Fri, 2010-05-28 at 15:12 -0400, Alice Wei wrote
On Fri, 2010-05-28 at 15:12 -0400, Alice Wei wrote:
What I am trying to find out is, when I have my form with a
dependent select menu, how can I pass the value of the select menu
to another page? I have mentioned in the initial email that if I
just allow users to type stuff, it passes the
Date: Fri, 28 May 2010 17:18:21 -0400
To: aj...@alumni.iu.edu
From: tedd.sperl...@gmail.com
Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different
Forms
CC: php-general@lists.php.net
On Fri, 2010-05-28 at 15:12 -0400, Alice Wei wrote:
What I am trying to find out
From: aj...@alumni.iu.edu
To: tedd.sperl...@gmail.com
CC: php-general@lists.php.net
Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different Forms
Date: Fri, 28 May 2010 19:31:10 -0400
Date: Fri, 28 May 2010 17:18:21 -0400
To: aj...@alumni.iu.edu
From: tedd.sperl
On Fri, May 28, 2010 at 8:01 PM, Alice Wei aj...@alumni.iu.edu wrote:
From: aj...@alumni.iu.edu
To: tedd.sperl...@gmail.com
CC: php-general@lists.php.net
Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different
Forms
Date: Fri, 28 May 2010 19:31:10 -0400
Date
At 3:50 PM -0400 5/26/10, Alice Wei wrote:
My bad, I cannot imagine I sent that stuff. To answer your
question, here it is,
form action= method=post
pSelect the type of your starting point of interest:br/
input type=text name=start
Date: Thu, 27 May 2010 12:23:46 -0400
To: aj...@alumni.iu.edu; php-general@lists.php.net
From: tedd.sperl...@gmail.com
Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different Forms
At 3:50 PM -0400 5/26/10, Alice Wei wrote:
My bad, I cannot imagine I sent that stuff
On Tue, 2010-05-25 at 15:41 -0400, Alice Wei wrote:
Date: Tue, 25 May 2010 13:40:44 -0400
Subject: Re: [PHP]
Select Values Didn't Get Passed in From Two Different Forms
From: marc.g...@gmail.com
To: aj...@alumni.iu.edu
I would like to take those values away into my third form, which
On Wed, 2010-05-26 at 08:28 -0400, Alice Wei wrote:
On Tue, 2010-05-25 at 15:41 -0400, Alice Wei wrote:
Date: Tue, 25 May 2010 13:40:44 -0400
Subject: Re: [PHP]
Select Values Didn't Get Passed in From Two Different Forms
From: marc.g...@gmail.com
To: aj...@alumni.iu.edu
I
From: Alice Wei
On Tue, 2010-05-25 at 15:41 -0400, Alice Wei wrote:
Date: Tue, 25 May 2010 13:40:44 -0400
Subject: Re: [PHP]
Select Values Didn't Get Passed in From Two Different Forms
From: marc.g...@gmail.com
To: aj...@alumni.iu.edu
I would like to take those values away into my
At 9:17 PM -0400 5/25/10, Alice Wei wrote:
No, the fields are populated in the first and second
form, form1 and form2. What I want to do is to get the selections from
both forms and pass them on to the third. Does this make sense? For some
reason, the text input and the semester drop down menu
Date: Wed, 26 May 2010 09:19:26 -0400
To: php-general@lists.php.net; aj...@alumni.iu.edu
From: tedd.sperl...@gmail.com
Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different
Forms
At 9:17 PM -0400 5/25/10, Alice Wei wrote:
No, the fields are populated in the first
Alice:
You provide:
ul
form action= method=post
liSelect the type of your starting point of interest:br/
div id=start_menuform
action=test_getrss.php name=form1 method=post
spaninput
Date: Wed, 26 May 2010 15:36:18 -0400
To: php-general@lists.php.net; aj...@alumni.iu.edu
From: tedd.sperl...@gmail.com
Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different Forms
Alice:
You provide:
ul
form action= method=post
liSelect the type of your
On 5/26/2010 3:50 PM, Alice Wei wrote:
Date: Wed, 26 May 2010 15:36:18 -0400
To: php-general@lists.php.net; aj...@alumni.iu.edu
From: tedd.sperl...@gmail.com
Subject: RE: [PHP] Select Values Didn't Get Passed in From Two Different Forms
Alice:
You provide:
ul
form action= method=post
On Wed, 26 May 2010 11:02:10 -0400, Alice Wei wrote:
[De-indented to preserve sanity]
ul
form action= method=post
Bzzt. Only li elements can be children of ul.
liSelect the type of your starting point of interest:br/
div id=start_menu
form action=test_getrss.php name=form1
Date: Tue, 25 May 2010 13:40:44 -0400
Subject: Re: [PHP]
Select Values Didn't Get Passed in From Two Different Forms
From: marc.g...@gmail.com
To: aj...@alumni.iu.edu
I would like to take those values away into my third form, which
is what you
see with the hidden
,
Edwin.
-Original Message-
From: Adam Richardson [mailto:simples...@gmail.com]
Sent: Wednesday, May 26, 2010 1:31 AM
To: php-general@lists.php.net
Subject: Re: [PHP] Select Values Didn't Get Passed in From Two Different
Forms
On Tue, May 25, 2010 at 1:17 PM, Alice Wei aj...@alumni.iu.edu
On Jul 1, 2009, at 10:56 AM, Miller, Terion tmil...@springfi.gannett.com
wrote:
Why doesn't this work?
$query = SELECT * FROM `restaurants` WHERE name ='$ucName' AND
address = '$ucAddress' ;
$result = mysql_query($query) or die(mysql_error());
echo $result;
$row =
On Wed, Jul 1, 2009 at 10:56 AM, Miller,
Teriontmil...@springfi.gannett.com wrote:
Why doesn't this work?
$query = SELECT * FROM `restaurants` WHERE name ='$ucName' AND
address = '$ucAddress' ;
$result = mysql_query($query) or die(mysql_error());
echo $result;
$row =
On 7/1/09 10:06 AM, Phpster phps...@gmail.com wrote:
On Jul 1, 2009, at 10:56 AM, Miller, Terion tmil...@springfi.gannett.com
wrote:
Why doesn't this work?
$query = SELECT * FROM `restaurants` WHERE name ='$ucName' AND
address = '$ucAddress' ;
$result = mysql_query($query)
On Wed, Jul 1, 2009 at 11:23 AM, Andrew Ballardaball...@gmail.com wrote:
On Wed, Jul 1, 2009 at 10:56 AM, Miller,
Teriontmil...@springfi.gannett.com wrote:
Why doesn't this work?
$query = SELECT * FROM `restaurants` WHERE name ='$ucName' AND
address = '$ucAddress' ;
$result =
in VBSCRIPT
In what?
Use [] at the end of your selects name:
select name=mySelect[]
...
/select
--
Richard Heyes
HTML5 Canvas graphing for Firefox, Chrome, Opera and Safari:
http://www.rgraph.net (Updated April 11th)
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe,
On Sun, 2009-03-22 at 09:22 +0800, Virgilio Quilario wrote:
Trying to find best way to accomplish following scenario. Looking to
search
inventory through a POST form, have the following optional fields to search
by: Product Name, Color, Size, and Status. Search maybe for the Product
On Sat, 2009-03-21 at 10:30 -0700, ben...@gmail.com wrote:
Trying to find best way to accomplish following scenario. Looking to search
inventory through a POST form, have the following optional fields to search
by: Product Name, Color, Size, and Status. Search maybe for the Product
Name
Trying to find best way to accomplish following scenario. Looking to search
inventory through a POST form, have the following optional fields to search
by: Product Name, Color, Size, and Status. Search maybe for the Product
Name and/or Color or they may search for just the Color or all 4
How should I proceed? Thanks in advance for any suggestions.
Since you are looping through the result already, why not do it this way ..
$combinedArray = array();
for ($i=0;$icount($myArray);$i++) {
$sql = SELECT study,symbol FROM test WHERE study IN ('$myArray[$i]');
$result =
Correcting myself now ..
$myArray = array('b2005', 'b2008');
$sql = SELECT study,symbol FROM test WHERE study IN ('$myArray[$i]');
$result = mysql_query($sql);
if(mysql_num_rows($result) 0) {
while ($myrow = mysql_fetch_array($result)) {
if (in_array($myrow['study'], $myArray))
Thanks Yeti, it works.
Best, Andrej
Yeti wrote:
Correcting myself now ..
$myArray = array('b2005', 'b2008');
$sql = SELECT study,symbol FROM test WHERE study IN ('$myArray[$i]');
$result = mysql_query($sql);
if(mysql_num_rows($result) 0) {
while ($myrow = mysql_fetch_array($result)) {
I actually would do more like:
$myArray[$study][$symbol] = true;
No need to call in_array.
Probably won't matter, really, but it's a good practice for when you end up
doing the same kind of code for an array with thousands of elements.
--
PHP General Mailing List
And yet another thing i have overseen in my statement ..
If you remove the first for loop, also change the sql query. But I'm
sure you saw that already
NEW QUERY:
$sql = SELECT study,symbol FROM test WHERE study IN ('.implode(', ',
$myArray).');
--
PHP General Mailing List (http://www.php.net/)
VamVan wrote:
Please apologize for sending this question to PHP forums.
If you know this already why ask the question here? Also, this is not a
forum.
But I would appreciate it very much if some could please help me styling
select mutiple in HTMl with CSS?
I have .selectmulti { border:
On Tuesday 18 December 2007 20:03:53 Stut wrote:
VamVan wrote:
Please apologize for sending this question to PHP forums.
If you know this already why ask the question here? Also, this is not a
forum.
But I would appreciate it very much if some could please help me styling
select mutiple
Why not try a css list? css-discuss for example?
On Dec 18, 2007 8:06 PM, Børge Holen [EMAIL PROTECTED] wrote:
On Tuesday 18 December 2007 20:03:53 Stut wrote:
VamVan wrote:
Please apologize for sending this question to PHP forums.
If you know this already why ask the question here?
On Tuesday 18 December 2007 21:16:46 you wrote:
Why not try a css list? css-discuss for example?
Yes why not?
On Dec 18, 2007 8:06 PM, Børge Holen [EMAIL PROTECTED] wrote:
On Tuesday 18 December 2007 20:03:53 Stut wrote:
VamVan wrote:
Please apologize for sending this question to PHP
On Tue, December 18, 2007 2:06 pm, Børge Holen wrote:
On Tuesday 18 December 2007 20:03:53 Stut wrote:
VamVan wrote:
Please apologize for sending this question to PHP forums.
If you know this already why ask the question here? Also, this is
not a
forum.
But I would appreciate it very
On Wednesday 19 December 2007 03:59:11 Richard Lynch wrote:
On Tue, December 18, 2007 2:06 pm, Børge Holen wrote:
On Tuesday 18 December 2007 20:03:53 Stut wrote:
VamVan wrote:
Please apologize for sending this question to PHP forums.
If you know this already why ask the question here?
On Tue, January 30, 2007 4:14 pm, nitrox . wrote:
Richard, ive included your suggested code and now my php script is
working
properly. But I dont want to be a php copy/paste newb who has no clue
of how
things are working. If its not too much would you (or anybody) give a
brief
explanation
On Tue, January 30, 2007 7:23 pm, Craige Leeder wrote:
atleast this part: $user_id = mysql_real_escape_string((int)
$_GET['user_id']);
I'm not sure who put this in there, but you don't need to use
mysql_real_escape_string() on that value if you're type casting it. If
you are forcing it to be
Thanks to all who have replied. As you probably have noticed im a total
novice to php who is trying to achieve big things.
Richard, ive included your suggested code and now my php script is working
properly. But I dont want to be a php copy/paste newb who has no clue of how
things are
At 1/30/2007 02:14 PM, nitrox . wrote:
If its not too much would you (or anybody) give a brief explanation
of what this code is doing? Or are there any tutorials online that I
can read that will educate me on this? Thanks again to all for your
replies. Ive saved them all for future reference.
atleast this part: $user_id = mysql_real_escape_string((int)
$_GET['user_id']);
I'm not sure who put this in there, but you don't need to use
mysql_real_escape_string() on that value if you're type casting it. If
you are forcing it to be an integer, there is nothing to escape.
Integers are
On Sun, 2007-01-28 at 21:12 -0500, Craige Leeder wrote:
As someone else already stated, my best guess according to that error
is that $user_id has a null, or inappropriate value. The error occurs
at the last character of the query, so it has to be something like
hat. Echo the query and let us
On Sun, January 28, 2007 5:21 pm, nitrox . wrote:
Im trying to display one record at a time by ID. Well im getting a
blank
page. Ive looked over my code and tried 20 different ways to get it to
work
to no avail. So any pointers on what Im doing wrong would be great.
here is
the code im
January 28, 2007 6:20 pm, Larry Garfield wrote:
On Sunday 28 January 2007 5:54 pm, Francisco M. Marzoa Alonso wrote:
On dom, 2007-01-28 at 18:51 -0500, nitrox . wrote:
I took the quotes off. I thought that quotes around numbers was
wrong
also.
Quotes are no necessary around numeric
On Sun, January 28, 2007 6:20 pm, Larry Garfield wrote:
On Sunday 28 January 2007 5:54 pm, Francisco M. Marzoa Alonso wrote:
On dom, 2007-01-28 at 18:51 -0500, nitrox . wrote:
I took the quotes off. I thought that quotes around numbers was
wrong
also.
Quotes are no necessary around
# [EMAIL PROTECTED] / 2007-01-29 17:54:03 -0600:
MySQL is the *only* db engine that lets you get away with [bleep] like
apostrophes around numbers.
Actually, these are examples of valid SQL: INTEGER '1', FLOAT '13.5'.
test=# select version();
On Mon, January 29, 2007 6:55 pm, Roman Neuhauser wrote:
# [EMAIL PROTECTED] / 2007-01-29 17:54:03 -0600:
MySQL is the *only* db engine that lets you get away with [bleep]
like
apostrophes around numbers.
Actually, these are examples of valid SQL: INTEGER '1', FLOAT '13.5'.
test=# select
On Monday 29 January 2007 7:19 pm, Richard Lynch wrote:
Looks like PostgreSQL caved in to the unwashed masses of MySQL users
who couldn't handle not putting apostrophes around everything to me...
[sigh]
:-) :-) :-)
Oh well.
I personally would prefer that the DB not accept bogus input
On Mon, January 29, 2007 7:43 pm, Larry Garfield wrote:
On Monday 29 January 2007 7:19 pm, Richard Lynch wrote:
Looks like PostgreSQL caved in to the unwashed masses of MySQL users
who couldn't handle not putting apostrophes around everything to
me...
[sigh]
:-) :-) :-)
Oh well.
I
The first thing that I probably do is to check for possible errors from
DB:
$result = mysql_query(SELECT * FROM inf_member WHERE
user_id='$user_id' );
if ( ! $result ) {
die (Could not perform query $query: .mysql_error().\n);
}
Regards,
On dom,
I took the quotes off. I thought that quotes around numbers was wrong also.
I added the error checking and this is the error:
Could not perform query : You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for the right syntax to
use near '' at
Ops!, Better this one:
$query = SELECT inf_member WHERE user_id='$user_id' ;
$result = mysql_query($query);
if ( ! $result ) {
die (Could not perform query $query: .mysql_error().\n);
}
I did copy and paste from my own code and you've not $query
At 1/28/2007 03:21 PM, nitrox . wrote:
Im trying to display one record at a time by ID. Well im getting a
blank page. Ive looked over my code and tried 20 different ways to
get it to work to no avail. So any pointers on what Im doing wrong
would be great. here is the code im working with so
On dom, 2007-01-28 at 18:51 -0500, nitrox . wrote:
I took the quotes off. I thought that quotes around numbers was wrong also.
Quotes are no necessary around numeric values, but they aren't wrong
neither, simply optional.
I added the error checking and this is the error:
Could not perform
On Sunday 28 January 2007 5:54 pm, Francisco M. Marzoa Alonso wrote:
On dom, 2007-01-28 at 18:51 -0500, nitrox . wrote:
I took the quotes off. I thought that quotes around numbers was wrong
also.
Quotes are no necessary around numeric values, but they aren't wrong
neither, simply optional.
On dom, 2007-01-28 at 18:20 -0600, Larry Garfield wrote:
On Sunday 28 January 2007 5:54 pm, Francisco M. Marzoa Alonso wrote:
On dom, 2007-01-28 at 18:51 -0500, nitrox . wrote:
I took the quotes off. I thought that quotes around numbers was wrong
also.
Quotes are no necessary around
As someone else already stated, my best guess according to that error
is that $user_id has a null, or inappropriate value. The error occurs
at the last character of the query, so it has to be something like
hat. Echo the query and let us know what it outputs.
- Craige
On 1/28/07, Francisco M.
On Fri, November 24, 2006 10:27 am, Yves Tannier wrote:
First, sorry for my bad english ;)
I'm looking for a simple way to provide query with two table like this
:
SELECT t1.idperson, t1.lastname FROM table1 t1, table2 t2 WHERE
t1.idperson=t2.idperson AND t1.idperson=2
I try with joinAdd
2006/11/24, Richard Lynch [EMAIL PROTECTED]:
On Fri, November 24, 2006 10:27 am, Yves Tannier wrote:
First, sorry for my bad english ;)
I'm looking for a simple way to provide query with two table like this
:
SELECT t1.idperson, t1.lastname FROM table1 t1, table2 t2 WHERE
Adam Zey wrote:
I must say
So you've said. Three times now. ;)
--
John C. Nichel IV
Programmer/System Admin (ÜberGeek)
Dot Com Holdings of Buffalo
716.856.9675
[EMAIL PROTECTED]
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To unsubscribe, visit: http://www.php.net/unsub.php
On Thu, August 17, 2006 9:02 am, João Cândido de Souza Neto wrote:
I´m not sure if it´s the right place to get such answer, but if
someone
know, please, help me.
In a select id,name,picture1,picture2,picture3 from product where
id=10 i
get an array with each colum in each element like this
On Fri, August 18, 2006 1:32 pm, Adam Zey wrote:
I must say, I'm of the opinion that as much data processing should be
done in the database server possible.
I agree with you 100% in principle...
But in this case, we're talking about structuring the data in a
PHP-specific data structure for
Richard Lynch wrote:
On Thu, August 17, 2006 9:02 am, João Cândido de Souza Neto wrote:
I´m not sure if it´s the right place to get such answer, but if
someone
know, please, help me.
In a select id,name,picture1,picture2,picture3 from product where
id=10 i
get an array with each colum in each
On Thu, 2006-08-17 at 11:02 -0300, João Cândido de Souza Neto wrote:
Hi everyone,
Im not sure if its the right place to get such answer, but if someone
know, please, help me.
In a select id,name,picture1,picture2,picture3 from product where id=10 i
get an array with each colum in each
Roel Dillen wrote:
I have a xhtml form with a select with options
if I click submit the processing page is loaded and the result of the form is
shown.
The option given to the processing page however is always the same: the first
in the list. It doesn't matter what I select in the drop down
weetat wrote:
Hi Jay ,
I am not in the javascript group.
'the javascript group' ??
document.forms['listfrm'].submit;
document.forms['listfrm'].submit();
^^--- i.e. actually call the method
--
PHP General Mailing List (http://www.php.net/)
To
[snip]
It will produce the html tag as shown below:
script language=JavaScript
function gotoPage(){
var urlpath = ../listflag.php?start=pageID=+3;
document.forms['listfrm'].method = 'post';
document.forms['listfrm'].action = urlpath;
document.forms['listfrm'].submit;
}
/script
form
Hi Jay ,
I am not in the javascript group.
Btw , i have added document.forms['listfrm'].pageid.value in the
page , but the form is not submitted ?
var pageid = document.forms['listfrm'].pageid.value;
var urlpath = ../listflag.php?start=pageID=+pageid;
weetat wrote:
Hi all ,
I have a SELECT for country in the php file . I would like to load
the country and city belong to the country dynamically from the database.
Anyone have ideas how to do it ?
below is a function that generates a select tag based on the
criteria you give it, the
On Wed, December 28, 2005 2:50 am, William Stokes wrote:
I have one MySQL table with about 500 rows. I need to read the table
one row
at a
time, make some changes to data in one field and then store the
changed data
to another table.
I'm using PHP to change the data but I have no idea how
On 12/30/05, Richard Lynch [EMAIL PROTECTED] wrote:
The suggestions so far are good, but watch out for this:
If you do one record at a time, and are using LIMIT, and then
something gets inserted into the original table...
Boom!
You could always lock the tables whilst performing the update -
From: William Stokes [mailto:[EMAIL PROTECTED]
I have one MySQL table with about 500 rows. I need to read the table one
row at a time, make some changes to data in one field and then store the
changed data to another table.
1. May be add a column, CHANGED_FL with default value N.
2. Select
William Stokes wrote:
I have one MySQL table with about 500 rows. I need to read the table one row
at a
time, make some changes to data in one field and then store the changed data
to another table.
I'm using PHP to change the data but I have no idea how to select one row at
a time from the DB
On 12/28/05, William Stokes [EMAIL PROTECTED] wrote:
I have one MySQL table with about 500 rows. I need to read the table one row
at a
time, make some changes to data in one field and then store the changed data
to another table.
I'm using PHP to change the data but I have no idea how to
Stokes' [EMAIL PROTECTED]; php-general@lists.php.net
Sent: Wednesday, December 28, 2005 3:57 AM
Subject: RE: [PHP] SELECT?
From: William Stokes [mailto:[EMAIL PROTECTED]
I have one MySQL table with about 500 rows. I need to read the table one
row at a time, make some changes to data in one
On 12/21/05, Anasta [EMAIL PROTECTED] wrote:
Can someone tell me why this select is wrong please---ive tried everything.
the $cat is the tablename .
You've tried *everything* ?
Why do you think it's wrong? Did you get an error message of some kind?
What do you see if you echo $query? Are the
Can someone tell me why this select is wrong please---ive
tried everything.
the $cat is the tablename .
$query= SELECT title FROM $cat WHERE id='$id';
Apparently, either $cat or $id is not the value you think it is. First, I
would try changing
$result=mysql_query($query);
to
[snip]
$query= SELECT title FROM $cat WHERE id='$id';
[/snip]
echo $query; // does it look right to you?
Alway throw an error when in question
if(!($result = mysql_query($query, $connection))){
echo mysql_error() . br\n;
exit();
}
My bet is that you need to concatenate
$query = SELECT
side-question
Jay how come you though concating would give
a different result to interpolation?
/side-question
Jay Blanchard wrote:
[snip]
$query= SELECT title FROM $cat WHERE id='$id';
[/snip]
echo $query; // does it look right to you?
Alway throw an error when in question
if(!($result =
[snip]
side-question
Jay how come you though concating would give
a different result to interpolation?
/side-question
[/snip]
It is not really a different result, it is just something that I am in the
habit of doing. The concat or not to concat question has fueled many a
holy war. I concat,
Jay Blanchard wrote:
[snip]
side-question
Jay how come you though concating would give
a different result to interpolation?
/side-question
[/snip]
It is not really a different result, it is just something that I am in the
habit of doing. The concat or not to concat question has fueled many a
On Wed, November 9, 2005 5:21 pm, Ross wrote:
$query = SELECT * FROM login where username='$_POST['username']' AND
pass
='$_POST['pass']';
In addition to the fine posts regarding SQL Injection and curly
braces, I'd like to provide one other alternative heretofore
unmentioned:
$query = SELECT
$query = SELECT * FROM login WHERE username = '.$_POST['username'].' AND
pass = '. $_POST['pass'].';
What is the correct syntax for
$query = SELECT * FROM login where
username='$_POST['username']' AND pass ='$_POST['pass']';
Thought this would work.
R.
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