Hi Bruno,
Apropos of ls-means ...
I have tried help.search and RSiteSearch with several terms including
standard errors, least square means, adjusted means.
And ls-means, which is what you call them?
There are many threads on this, spanning many years. The following,
RSiteSearch(ls-means)
Hi Alina,
You can always write a loop in R to do this:
# A function to shift values in an vector
shift = function(y) {
cnt = length(y) - 1
m=vector(mode = numeric,length = cnt)
for (j in 1:cnt) {
m[j] = y[j+1]}
m
}
Regards,
Indrajit
From: Alina
Hello R Experts,
does anyone know how to run R programs automatically using the window
scheduler?
I want to run some R programs automatically and make the results available
via web.
Mit freundlichen GrüÃen / Best Regards / С наилÑÑÑими
пожеланиÑми /
üdvözlettel
Hi all,
I got one problem with compating charecterstrings with using ==
can anyone suggest if any other way to compare two charecterstrings
thanks in advance
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Hi
I have a data frame with timeseries information like this:
year cell Q1Q2 Q3 Q4
1940 1 1.2 1.4 1.41.9
1941 1 2.9 2.1 3.4 2.4
1942 1 2.7 3.2 1.52.6
1940 2 1.4 2.1 2.62.4
1941 2 2.4 1.4 1.4
Thorsten Muehge wrote:
Hello R Experts,
does anyone know how to run R programs automatically using the window
scheduler?
I want to run some R programs automatically and make the results available
via web.
Write some Windows command script (also referred to as batch file) that
calls
an example would be helpful ...
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
venkata kirankumar wrote:
Hi all,
I got one problem with compating charecterstrings with using ==
can anyone
Dear Robin,
It is rather easy if you combine melt() and cast() from the reshape
package.
dataset - expand.grid(year = 1940:1942, cell = 1:2)
dataset$Q1 - rnorm(nrow(dataset))
dataset$Q2 - rnorm(nrow(dataset))
dataset$Q3 - rnorm(nrow(dataset))
dataset$Q4 - rnorm(nrow(dataset))
library(reshape)
Try this also:
x - seq(as.Date(2008-01-01), as.Date(2008-12-31), l = 10)
as.Date(embed(matrix(x), 2)[,1], origin = 1970-01-01)
On Wed, Jan 21, 2009 at 7:18 PM, Alina Sheyman alina...@gmail.com wrote:
I am working with a list of dates and I would like to replace each date
with
the one that
Hi
r-help-boun...@r-project.org napsal dne 22.01.2009 10:49:26:
Hi all,
I got one problem with compating charecterstrings with using ==
can anyone suggest if any other way to compare two charecterstrings
Works for me
a-letters
b-letters[1:10]
a==b
[1] TRUE TRUE TRUE TRUE TRUE
Hi Roland,
thanks for your answere. I actually tried out a different, smaller
Latex-header and the sweave-process suddenly worked. So I copied parts
of the old header into the new one, to check what part is causing the
trouble. In the end I had two documents with identical content. The new
Hi!
Within the lm function I can address and summarize columns like that:
lm1-lm(I(rowSums(spec[,5:81]))~pH)
If I want to do the same in nlme package I get the following error:
lme1-lme(I(rowSums(spec[,5:81]))~pH,random=~1|site)
Error in model.frame.default(formula = ~spec + pH + site, data
Hi,
I get following error when trying to plot a heatmap on a very large matrix
(808 x5000).
heatmap(ctab)
Error: evaluation nested too deeply: infinite recursion /
options(expressions=)?
Call to heatmap function is not contained within any other function or so.
Upon searching the R mailing
Hi,
I am a new user of R using R 2.8.1 in windows 2003. I have a csv file with
single column which contain the 30,000 students names. There were typo
errors while entering this student names. The actual list of names is
1000. However we dont have that list for keyword search.
I am interested
Dear Bruno,
See the effects package (on CRAN) for a generalization of adjusted means.
I hope this helps,
John
--
John Fox, Professor
Department of Sociology
McMaster University
Hamilton, Ontario, Canada
web: socserv.mcmaster.ca/jfox
-Original Message-
Hi
R-2.8.1, Suse 11.1
I'm having problems with pdf(). In the following
transcript, file 'f.pdf' does not use the expected symbols for the plot.
It uses a 'q' letter instead of the open circle I get when
viewing the graphics window.
I also get the same under r47678.
Does anyone else get
Hello helpers,
This is probably quite simple, but I'm stuck.
I want to create a summary statistics table with frequencies and summary
statistics for a large number of variables. The problem here is that (1)
there are two different classes of categories (sex, type of substance abuse
and type of
Since %male is basically the mean if you code male=1 and female=0,
which is more informative than absolute frequency. So, you may want to
have a glance at doBy package, especially the summaryBy function.
All the best
On Thu, Jan 22, 2009 at 7:17 PM, Stefan Björk stefan.bj...@gmail.com wrote:
On Thu, 22 Jan 2009, Robin Hankin wrote:
Hi
R-2.8.1, Suse 11.1
I'm having problems with pdf(). In the following
transcript, file 'f.pdf' does not use the expected symbols for the plot.
It uses a 'q' letter instead of the open circle I get when
viewing the graphics window.
I also get the
aiminy wrote:
de Jong, S. (1993) SIMPLS: an alternative approach to partial least
squares
regression. Chemometrics and Intelligent Laboratory Systems, 18, 251263
Yes, the publishers do, you can purchase it from
http://dx.doi.org/10.1016/0169-7439(93)85002-X
Its a shame that not all
Gerrit Voigt wrote:
Hi Roland,
thanks for your answere. I actually tried out a different, smaller
Latex-header and the sweave-process suddenly worked. So I copied parts
of the old header into the new one, to check what part is causing the
trouble. In the end I had two documents with
pdewitt wrote:
I read the posting about opening .R files in windows with the Rgui and was
wondering if anything has changed for R-2.8.1 and Windows Vista? I have not
yet been able to get the files to open in the Rgui, the association works
enough to open R but that is about it. Thanks for
Duncan Murdoch wrote:
I'd suggest doing a binary compare on the two files to see what the
differences are. I think you are on Windows (but I may be misreading
the quotes below); I recommend Beyond Compare (a shareware compare
utility). It has a hex viewer plug-in that could show you a
One of the various tabulation functions would seem to be the most
appropriate for getting frequency summaries:
?table
?xtabs
On Jan 22, 2009, at 6:17 AM, Stefan Björk wrote:
Hello helpers,
This is probably quite simple, but I'm stuck.
I want to create a summary statistics table with
-begin included message
However, as.Date encounters an error when the string does not represent an
actual date.
eg:
date1 - 2009-02-29 # Note: 2009 not a leap year
as.Date(date1)
Error in fromchar(x) :
character string is not in a standard unambiguous format
As I have many
Hello List,
I`m trying to make prediction using a bagged tree with the package ipred. I
tried to follow the manual but I`m getting an error message. Also browsing
through the list-archive I didn`t find any hint.
Maybe someone can help me?
selbag - bagging(SOIL_UNIT ~.,
On Thu, 22 Jan 2009, Terry Therneau wrote:
-begin included message
However, as.Date encounters an error when the string does not represent an
actual date.
eg:
date1 - 2009-02-29 # Note: 2009 not a leap year
as.Date(date1)
Error in fromchar(x) :
character string is not in a
Quoting Brian D Ripley rip...@stats.ox.ac.uk:
On Thu, 22 Jan 2009, Robin Hankin wrote:
Hi
R-2.8.1, Suse 11.1
I'm having problems with pdf(). In the following
transcript, file 'f.pdf' does not use the expected symbols for the plot.
It uses a 'q' letter instead of the open circle I get when
I have a data frame that is the result of a cast (reshape) operation. I
deleted the variable column and tried to melt the resulting data frame.
Depending on which method I use to delete the column I get different
error messages when melting:
head(tinfos)
vpn group trial_no item
On Thu, Jan 22, 2009 at 8:01 AM, Titus von der Malsburg
malsb...@gmail.com wrote:
I have a data frame that is the result of a cast (reshape) operation. I
deleted the variable column and tried to melt the resulting data frame.
Depending on which method I use to delete the column I get different
TZ == T Zumbrunn t.zumbr...@unibas.ch
on Thu, 22 Jan 2009 14:52:37 +0100 writes:
TZ Quoting Brian D Ripley rip...@stats.ox.ac.uk:
On Thu, 22 Jan 2009, Robin Hankin wrote:
Hi
R-2.8.1, Suse 11.1
I'm having problems with pdf(). In the following
Dear R mailing list,
I have a dataset with genotypes from trios and I would like to infer
haplotypes for each mother, father and child. The package that I could
find that can do this is tdthap.
But when the mother is homozygous (e.g., 2/2) the haplotype is called as
not possible to infer
Hi Thorsten, the way i do this (on Windows Vista Ultimate, SP1) is to
create a batch file and then have windows task scheduler call it at a
specific time. For example, to create my batch file i open up Notepad
and type the following single line into it:
C:\Program Files\R\R-2.8.1\bin\R.exe CMD
Hi,
I think in such cases you need to use the 'wave' parameter (wave = Date),
but I must admit I found contradictory comments on how missing values are
treated in geepack. Does someone know what geepack is doing with missing
values?
Popko
Giacomo Santini wrote:
Hi all
I am analyzing a
Hi Michael,
Can you also build the PMML model on the cloud with R, paying for the
processor ,memory usage. Any plans to extend the abilty to model, or is it
just deploy PMML models on the cloud servers.
Regards,
Ajay
http://www.decisionstats.com
On Thu, Jan 22, 2009 at 4:29 AM, MZ
Use either the 'clip' function from the graphics package, or the 'clipplot'
function from the TeachingDemos package.
Hope this helps,
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From:
I am relatively new to R, so maybe I am miss something, but I now
tried the as.Date now and have problems understanding how it works (or
don't work as it seem).
Brian D Ripley wrote:
On Thu, 22 Jan 2009, Terry Therneau wrote:
One idea is to use the as.date function, for the older (and less
I'm stuck on how best to of find the distance between ordered integers
(presented below as a birthday problem). Given the vector x, how do I
most efficiently generate the vector x[i+1] - x[i]? Thanks. --Dale
For example...
set.seed(555)
x - sample(1:365, 10, replace=TRUE)
x - sort(x)
x
Simply doing a tabulation and isolating the cases with only one entry
might have been a possibility if the count discrepancy weren't so
high. It appears you have a greater degree of corruption than would be
expected just from typos.
Have you looked at the packages referenced at:
Dear Dale,
Try this:
set.seed(555)
x - sample(1:365, 10, replace=TRUE)
x - sort(x)
diff(x)
HTH,
Jorge
On Thu, Jan 22, 2009 at 10:07 AM, Dale Steele dale.w.ste...@gmail.comwrote:
I'm stuck on how best to of find the distance between ordered integers
(presented below as a birthday problem).
Dear Michael,
David Ruelle wrote a very interesting paper on Recurrence plots of
dynamical Systems that you should read, and I remember of simples lead/lags
methods to detect random or determinist systems.
I think that you should take a look at this very interesting paper on
Lead-lag
On Thu, Jan 22, 2009 at 9:09 AM, Christopher W. Ryan
cr...@binghamton.edu wrote:
I probably did not explain my data clearly. I am starting with a
dataframe with three columns:
redlognumb radiologistbarrtotal
where the entries in the variable radiologist are either 1 or 2,
indicating
Hi all,
I have been trying to use zeroinfl() with the pscl package with R version
2.1.1. and with the newest versions of the contrib packages compatible with R
2.1.1.
I have read the examples, the vignette and all the posts relating to zeroinfl()
but I am still confused as to how to structure
Hi folks,
I am currently having the problem with using R 2.8.1 that I cannot install
some of packages from CRAN or local drive and somebody may be able to help
me.
ex) faraway package and lme4 package. I have downloaded them in my hard
drive as local, but still R was unable to find the package
Dear Miss R,
I have a large dataset that is skewed and would like to calculate
confidence intervals for my regression line. Unfortunately I have trouble
finding commands for rubust regression and in particular for the confidence
intervals... Can you possibly give a hint?
Thank you and best
Hope one of you could help with the following question/problem:
We would like to explain the spatial
distribution of juvenile fish. We have 2135 records, from 75 vessels
(code_tripnr) and 7 to 39 observations for each vessel, hence the random effect
for code_tripnr. The offset (offsetter)
You should look at how summary.data.frame does it. (You are, of
course, re-inventing the wheel.)
You probably ought to also look at the doBy package with its summaryBy
function. The help page example uses the length function for counts.
I often prefer the output of describe() in Hmisc.
--
With respect to scripts in the tests directory of a package:
Can they depend on data sets found in the 'data' directory of said package?
-available by default
- need to use a data() call
- need to explicitly attach?
This isn't clear to me from reading the documentation
On Thu, 22 Jan 2009, Simon Pickett wrote:
Hi all,
I have been trying to use zeroinfl() with the pscl package with R
version 2.1.1.
That version is ancient, please upgrade.
and with the newest versions of the contrib packages
compatible with R 2.1.1.
A version number for pscl would have
Odette Gaston wrote:
Hi folks,
I am currently having the problem with using R 2.8.1 that I cannot install
some of packages from CRAN or local drive and somebody may be able to help
me.
ex) faraway package and lme4 package. I have downloaded them in my hard
drive as local, but still R was
The following code used to work on an earlier version of ggplot2. But it gives
me an error now.
qplot(Year,CDR,data=b3,colour=Phase,geom=c(point,line))-p
p+scale_colour_gradient2(limits=c(1,3), midpoint=2,low=magenta,
mid=darkgreen, high=blue)-p
(print(p,pretty=F)-p)
print(p,pretty=F)-p
The
Terry Therneau wrote:
With respect to scripts in the tests directory of a package:
Can they depend on data sets found in the 'data' directory of said package?
-available by default
- need to use a data() call
- need to explicitly attach?
Terry,
you need to load
I posted the question below about a month ago but received no response.
I still have not been able to figure out what is happening.
I also noticed another oddity. When the data part of the object is a
multivariate time series, it doesn't show up in the structure, but it
can be treated as a
Hi,
I'd like to blow up portions of my graph and put it in boxes beside the
graph.Is there an addon to do this?
--
Rajesh.J
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Hi,
A simple quantile question:
I need to calculate the 95% and 5% quantiles (aka percentiles) for the
following data:
67.12
64.51
62.06
55.45
51.41
43.78
10.74
10.14
if I use the formula: 95% quantile point= 95 (8+1)/100, I get the 8.55th
point as the 95% quantile. Which does not make too much
On Jan 22, 2009, at 11:06 AM, Georg Ehret wrote:
Dear Miss R,
I have a large dataset that is skewed and would like to calculate
confidence intervals for my regression line. Unfortunately I have
trouble
finding commands for rubust regression and in particular for the
confidence
I have been struggling to get the legends in ggplot2 right or do away with them
altogether (on which I have already sent a post).
In the following code, the labels argument in the scale_colour_gradient2 does
not give me the desired labels in the legend. Could someone explain?
Here is one way:
tmpmat - cbind( c(1,1), c(1,1), c(2,3) )
layout(tmpmat)
with(iris, plot(Sepal.Width, Sepal.Length,
col=c('red','green','blue')[Species]))
with(iris, plot(Sepal.Width, Sepal.Length, col=c('red','green','blue')[Species],
xlim=c(2.5,3), ylim=c(6,6.5)))
Read the help page for the quantile function (the whole page, there is a lot of
good detail in there), the 2nd reference on the page should also be a helpful
read.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
have a look at the online help file of ?quantile(); check also:
x - c(67.12, 64.51, 62.06, 55.45, 51.41, 43.78, 10.74, 10.14)
sapply(1:9, function (i) quantile(x, c(0.05, 0.95), type = i))
I hope it helps.
Best,
Dimitris
ANJAN PURKAYASTHA wrote:
Hi,
A simple quantile question:
I need to
Hi,
It seems there is no straightforward way to carry out in R the loess
fitting with bisquare, as given by William Cleveland in his
Visualizing Data. Am I right?
Thanks in advance,
Marcin
--
Build up your weaknesses until they become your strong points -- Knute Rockne
Hi
I would like to use 'write.fasta(sequences, names, nbchar = 60, file.out, open
= w)' to convert a DNA sequence in a text file to fasta format.
How do I read the the text file to prepare the argument 'sequences' of the
function.
The DNA sequence in the text file is one line as below:
Thanks all for your prompt and helpful replies!
Anjan
On Thu, Jan 22, 2009 at 11:52 AM, ANJAN PURKAYASTHA
anjan.purkayas...@gmail.com wrote:
Hi,
A simple quantile question:
I need to calculate the 95% and 5% quantiles (aka percentiles) for the
following data:
67.12
64.51
62.06
55.45
Suppose X and Y are two data frames with the same structures, variable
names and dimensions but with different data and different patterns of
missing. I want to replace missing values in Y with corresponding values
from X. I'll construct a simple two-by-two case:
X -
The loess function in R uses the tricube weights that are described in my copy
of Cleveland, so that may do what you want. If you really want to do the same
general idea but with a different weight function, then it is not that hard to
write your own function to do the estimating (but I doubt
Hi,
doing a search in R gives
help.search(loess)
?loess
Look out for the family argument in the help page.
Christian
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Here's my version of the technicolor title function:
multiTitle - function(...){
###
### multi-coloured title
###
### examples:
### multiTitle(color=red,Traffic,
### color=orange, light ,
### color=green,signal)
###
### - note triple backslashes needed for embedding
Häring, Tim (LWF) wrote:
Hello List,
I`m trying to make prediction using a bagged tree with the package ipred. I tried to follow the manual but I`m getting an error message. Also browsing through the list-archive I didn`t find any hint.
Maybe someone can help me?
selbag -
Dear Tiago,
I received this message from r-help. I should say I have limited experiences
with tdthap so David should have the final say about it? Alternatively, you may
wish to use independent programs as listed in the linkage server at Rockefeller?
I would of course find out if I have
Dear all,
I was wondering whether anyone knows about a program which converts
(part of) a data definition file (such as a .dct file for stata, or
.sas file for sas) into an R-script.
Here is an example with a .sas file:
-- snipp
VALUE HTYPE (default=32)
0 = Not in
Dear Brian,
I dont understand what you mean. The thread was about the as.Date which you
suggested to be used instead of the as.date. Following your advice I tried
the as.Date and have questions about the observed behaviour, which was
surprising to me. Is this what you call hijacking? Do you
The sas.get function in the Hmisc package, or the sasxport.get function,
will do what you want by a different approach.
Frank
Stephan Lindner wrote:
Dear all,
I was wondering whether anyone knows about a program which converts
(part of) a data definition file (such as a .dct file for stata,
If you you use robust fitting (family = symmetric), there are (at least)
two sets of weights used (and documented in the Help file): tricube weights
are used to weight the points by their distances from the current point
being estimated; bisquare weights are used in the robust fit to weight by
Hi Stephan,
Does the foreign package help?
HTH,
(another) Stephan
Stephan Lindner schrieb:
Dear all,
I was wondering whether anyone knows about a program which converts
(part of) a data definition file (such as a .dct file for stata, or
.sas file for sas) into an R-script.
Here is an
The first number is the year,
the second is the month and the third is the day.
It ignores trailing characters.
library(chron)
f - function(x) str(month.day.year(as.Date(x)))
f(2001/1/1)
List of 3
$ month: num 1
$ day : num 1
$ year : num 2001
f(1/1/2001)
List of 3
$ month: num 1
$
I believe the original thread was about whether the function returns NA or
stops with an error when given an invalid date (such as Feb 29 in a non-leap
year). Your question was about how as.Date returned something different from
what you expected. Related, but different enough that it
Hi list,
I'm using R 2.8.1 under Windows vista. I have the following problem:
First of all I create a string-vector. Then I convert these strings
into variables and assign a vector of numeric values. So far
everything's fine.
Now I want to do nearly the same again: I create another
ggplot2 should make legends automatically if the data is in the
correct format. If you could send a reproducible example, that would
help detect the error.
Take the following two plots. The first one produces a broken line. In the
second one, the variable Phase is numeric and therefore it
Hi,
I want to create an alias for the - function and then later
overwrite it. Any idea how I can get the - function object? I know
for other functions it's easy, something like f - seq will do; how
really no clue for this one. Thanks!
__
Is there many functions:
See:
grep(-, ls(package:base), value = TRUE)
For 'substring-':
type `substring-` in R
On Thu, Jan 22, 2009 at 5:41 PM, Yi Zhang yizhan...@gmail.com wrote:
Hi,
I want to create an alias for the - function and then later
overwrite it. Any idea how I can get the -
On 1/22/2009 2:41 PM, Yi Zhang wrote:
Hi,
I want to create an alias for the - function and then later
overwrite it. Any idea how I can get the - function object? I know
for other functions it's easy, something like f - seq will do; how
really no clue for this one. Thanks!
get(-) will give it
I don't see right off why the one works and the other doesn't, but this looks
like one of those cases that would be better done using a list rather than
global variables.
Instead of assigning the variables in the global workspace, create a list and
assign them there. Then you can use lapply
On 23/01/2009, at 12:49 AM, Neil Shephard wrote:
aiminy wrote:
de Jong, S. (1993) SIMPLS: an alternative approach to partial least
squares
regression. Chemometrics and Intelligent Laboratory Systems, 18,
251263
Yes, the publishers do, you can purchase it from
Thank you Greg and Gabor for explanations. I have some further question
below.
On Thu, Jan 22, 2009 at 8:16 PM, Greg Snow greg.s...@imail.org wrote:
I believe the original thread was about whether the function returns NA or
stops with an error when given an invalid date (such as Feb 29 in a
Greg Snow schrieb:
I don't see right off why the one works and the other doesn't, but this looks
like one of those cases that would be better done using a list rather than
global variables.
Instead of assigning the variables in the global workspace, create a list and
assign them there. Then
On Thu, Jan 22, 2009 at 3:06 PM, Duncan Murdoch murd...@stats.uwo.ca wrote:
get(-) will give it to you, and
`-` - function(x, y) cat(x=, x, y=, y, \n)
will change it -- and will probably be the last effective thing you do in
that session, unless you're really careful:
x - 1
x
[1] 1
`-`
I am using RDCOM as a data-transfer between R and C#.net.
I got a question on datasets with missing data.
For instance, if list = c(1,2,3,NA,5), in R, typeof(list) is integer
but, in C#, I did not see a suitable data type for (1,2,3,NA,5).
Of course, one can use is.na to transfer (1,2,3,NA,5) into
Rolf Turner wrote:
On 23/01/2009, at 12:49 AM, Neil Shephard wrote:
s
Is this really a violation of copyright? If I have a copy of a
journal I believe
it is within the compass of ``fair practice'' (or some such jargon) to
make a photocopy
of a particular article and give this copy to a
Dear R-users,
[Sorry to have to send this again but my former posts were trimmed
because of some embedded HTML code]
readline is a nice function to get user input when one is working with
the terminal. This function does not allow any interaction with the user
when a script in batch mode (I
Dear R-Users
I sincerely apologise for the multiple posts yesterday afternoon. Apparently
there was an error in the server here at work which resulted in the message
being sent eight times. I am new to R, as you can probably tell from the
majority of my posts, and I really appreciate all the
Duncan Murdoch wrote:
On 1/22/2009 2:41 PM, Yi Zhang wrote:
Hi,
I want to create an alias for the - function and then later
overwrite it. Any idea how I can get the - function object? I know
for other functions it's easy, something like f - seq will do; how
really no clue for this one.
Comments interspersed below
From: Marie Sivertsen [mailto:mariesiv...@gmail.com]
Sent: Thursday, January 22, 2009 1:17 PM
To: Greg Snow
Cc: r-h...@stat.math.ethz.ch
Subject: Re: [R] Unexpected behaviour of the as.Date (was: Error as.Date on
Invalid Dates)
[snip]
For your question, the help
Hello,
I have the following csv file
n, n_red
1, 0
1, 1
2, 1
2, 1
3, 0
4, 1
4, 2
4, 3
I would like to plot this data. On the x-axis there should be n and on
the y-axis the mean of all n_red where n is the according value on the
x-axis. The plot
On Thu, Jan 22, 2009 at 4:17 PM, Wacek Kusnierczyk
waclaw.marcin.kusnierc...@idi.ntnu.no wrote:
Duncan Murdoch wrote:
On 1/22/2009 2:41 PM, Yi Zhang wrote:
Hi,
I want to create an alias for the - function and then later
overwrite it. Any idea how I can get the - function object? I know
for
Ah, I missed that. You can get the value from the string by using paste to
create the name of the variable (as you already did), then use the 'get'
function to get its value (the other direction of assign). But I would still
suggest trying to use lists, then you can just use mylist[[ i ]] or
n.means = with(my.data,aggregate(n_red,list(n=n),mean))
plot(n.means)
On Thu, Jan 22, 2009 at 5:17 PM, o...@gmx.de wrote:
Hello,
I have the following csv file
n, n_red
1, 0
1, 1
2, 1
2, 1
3, 0
4, 1
4, 2
4, 3
I would like to plot this
Yi Zhang wrote:
# now what?? %#*
now you are really motivated to use '=' instead of '-':
x = 3
x
# 3
vQ
Thanks. That certainly is an option. But I want to preserve `-`'s
functionality because I'm writing a package and I don't want to limit
the package user's freedom
I have read in a file (call it myData). The actual file is about
3000x30,000 columns and object.size() says myData takes:
737910472/(1024^2)
[1] 703.7263
Unfortunately, my program ends up using 40GB as indicated by maxvmem
on Unix, which causes my department's cluster to stop working.
Perhaps,
i was sort-of joking, though it's a real option if you want it.
but seriously, there's no reason for the %#* lamenting:
x - 1
'-' = function(x,y) 0
x - 2
# 0
.Primitive('-')(x,2)
x
# 2
base::'-'(x, 3)
x
# 3
base::'-'('-', base::'-')
x - 4
x
# 4
vQ
I'm still not sure if
And to do the input section of the task, you should first read an
introductory text and then refer to the help pages:
?read.table
?read.csv # same page
And don't forget:
http://www.R-project.org/posting-guide.html
--
David Winsemius
On Jan 22, 2009, at 4:33 PM, Mike Lawrence wrote:
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