Re: [Vo]:Okay, suppose there is only 800 W input with no anomalous heat

2011-06-26 Thread Joshua Cude
On Sat, Jun 25, 2011 at 9:11 PM, Jeff Driscoll hcarb...@gmail.com wrote: On Sat, Jun 25, 2011 at 8:58 PM, mix...@bigpond.com wrote: In reply to Joshua Cude's message of Fri, 24 Jun 2011 16:20:48 -0500: Hi, [snip] I was talking about running it above boiling, but way below the level

Re: [Vo]:Okay, suppose there is only 800 W input with no anomalous heat

2011-06-26 Thread Jeff Driscoll
On Sun, Jun 26, 2011 at 3:23 AM, Joshua Cude joshua.c...@gmail.com wrote: On Sat, Jun 25, 2011 at 9:11 PM, Jeff Driscoll hcarb...@gmail.com wrote: On Sat, Jun 25, 2011 at 8:58 PM,  mix...@bigpond.com wrote: In reply to  Joshua Cude's message of Fri, 24 Jun 2011 16:20:48 -0500: Hi,

Re: [Vo]:Okay, suppose there is only 800 W input with no anomalous heat

2011-06-26 Thread Joshua Cude
On Sun, Jun 26, 2011 at 10:02 AM, Jeff Driscoll hcarb...@gmail.com wrote: Why would you divide the energy to vaporize 1 g of water (starting at 10 C) by the energy to heat it from 10 C to 100 C (liquid)? Seems random to me. Because those are the two extremes of a situation that results in

Re: [Vo]:Okay, suppose there is only 800 W input with no anomalous heat

2011-06-25 Thread mixent
In reply to Joshua Cude's message of Fri, 24 Jun 2011 16:20:48 -0500: Hi, [snip] I was talking about running it above boiling, but way below the level needed to boil it all. Different thing. And it's easy. The power can range within a factor of 7. In this case, anywhere between 600W and about 5

Re: [Vo]:Okay, suppose there is only 800 W input with no anomalous heat

2011-06-25 Thread Rich Murray
Yep...

Re: [Vo]:Okay, suppose there is only 800 W input with no anomalous heat

2011-06-25 Thread Jeff Driscoll
On Sat, Jun 25, 2011 at 8:58 PM, mix...@bigpond.com wrote: In reply to  Joshua Cude's message of Fri, 24 Jun 2011 16:20:48 -0500: Hi, [snip] I was talking about running it above boiling, but way below the level needed to boil it all. Different thing. And it's easy. The power can range within a

Re: [Vo]:Okay, suppose there is only 800 W input with no anomalous heat

2011-06-25 Thread Rich Murray
Nice... well, high time for a few of Rossi's trusted friends to ensure that he is alerted quickly...

Re: [Vo]:Okay, suppose there is only 800 W input with no anomalous heat

2011-06-25 Thread Daniel Rocha
Not convincing calculations. What is the density of water that can be sustained in droplets and what is the size of the droplets before they coalesce and rain back?

Re: [Vo]:Okay, suppose there is only 800 W input with no anomalous heat

2011-06-24 Thread Joshua Cude
On Fri, Jun 24, 2011 at 8:19 PM, Jed Rothwell jedrothw...@gmail.com wrote: Joshua Cude joshua.c...@gmail.com wrote: Nope. When you put 800 W into something like this, a large fraction of it radiates from the cell into the surroundings. The cell is insulated. It is too hot to touch

[Vo]:Okay, suppose there is only 800 W input with no anomalous heat

2011-06-24 Thread Jed Rothwell
Joshua Cude wrote: You only get a stable water/steam mixture in a closed vessel (a teapot). Why? If it takes say 1 kW to raise the temperature of the flowing water to 100C, and then you supply 1.5 kW (using only and electric heater), then only part of the flowing water will get

Re: [Vo]:Okay, suppose there is only 800 W input with no anomalous heat

2011-06-24 Thread Joshua Cude
On Fri, Jun 24, 2011 at 3:20 PM, Jed Rothwell jedrothw...@gmail.com wrote: ** Joshua Cude wrote: You only get a stable water/steam mixture in a closed vessel (a teapot). Why? If it takes say 1 kW to raise the temperature of the flowing water to 100C, and then you supply 1.5 kW (using

Re: [Vo]:Okay, suppose there is only 800 W input with no anomalous heat

2011-06-24 Thread Daniel Rocha
While I am also a skeptical, even rough approximation gives a huge output gain. Above 100 degrees means gas, and pumping a mixture would require either another pump, by means of ventilation. Ventilation is noisy and would require a large opening. Even 1% of liquid is a thick fog, which is not the

Re: [Vo]:Okay, suppose there is only 800 W input with no anomalous heat

2011-06-24 Thread Jed Rothwell
Joshua Cude wrote: There is no chance any of the water would vaporize with only ~800 W input. You would not any steam at all. Even with this high input power, any steam at all is proof there is anomalous heat. What are you talking about. You just did the calculation yourself

Re: [Vo]:Okay, suppose there is only 800 W input with no anomalous heat

2011-06-24 Thread Joshua Cude
On Fri, Jun 24, 2011 at 4:35 PM, Daniel Rocha danieldi...@gmail.com wrote: While I am also a skeptical, even rough approximation gives a huge output gain. Above 100 degrees means gas, A temperature reading within a degree or two of 100C is consistent with a mixture of gas and liquid. and

Re: [Vo]:Okay, suppose there is only 800 W input with no anomalous heat

2011-06-24 Thread Daniel Rocha
This is going into an infinite loop. Trying to explain that with only 800 is just too hard for me. Thanks for trying.

Re: [Vo]:Okay, suppose there is only 800 W input with no anomalous heat

2011-06-24 Thread Joshua Cude
On Fri, Jun 24, 2011 at 4:49 PM, Jed Rothwell jedrothw...@gmail.com wrote: ** Joshua Cude wrote: There is no chance any of the water would vaporize with only ~800 W input. You would not any steam at all. Even with this high input power, any steam at all is proof there is anomalous

Re: [Vo]:Okay, suppose there is only 800 W input with no anomalous heat

2011-06-24 Thread Stephen A. Lawrence
YOW -- WHAT YOU JUST SAID On 11-06-24 04:20 PM, Jed Rothwell wrote: So the only way for Rossi to make it produce a little steam and a lot of hot water would be for him to adjust the anomalous heat output. It would be a miracle if Rossi has such good control over the anomalous heat that

Re: [Vo]:Okay, suppose there is only 800 W input with no anomalous heat

2011-06-24 Thread Joshua Cude
On Fri, Jun 24, 2011 at 5:36 PM, Stephen A. Lawrence sa...@pobox.comwrote: YOW -- WHAT YOU JUST SAID On 11-06-24 04:20 PM, Jed Rothwell wrote: So the only way for Rossi to make it produce a little steam and a lot of hot water would be for him to adjust the anomalous heat output. It

Re: [Vo]:Okay, suppose there is only 800 W input with no anomalous heat

2011-06-24 Thread Horace Heffner
On Jun 24, 2011, at 2:36 PM, Stephen A. Lawrence wrote: YOW -- WHAT YOU JUST SAID On 11-06-24 04:20 PM, Jed Rothwell wrote: So the only way for Rossi to make it produce a little steam and a lot of hot water would be for him to adjust the anomalous heat output. It would be a miracle

Re: [Vo]:Okay, suppose there is only 800 W input with no anomalous heat

2011-06-24 Thread Jed Rothwell
Joshua Cude joshua.c...@gmail.com wrote: Nope. When you put 800 W into something like this, a large fraction of it radiates from the cell into the surroundings. The cell is insulated. It is too hot to touch according to witnesses. The insulation means it takes longer to get hot on the