If host is standing at a podium away from the three doors and opens
them by means of a hidden switch, you don't have this additional
information. This is supposed to be a probability problem; stop
turning it into something it's not.

Shelley


--- In [email protected], Rune Wesström
<[EMAIL PROTECTED]> wrote:
>
> A lot of  intuition!
> You guess on door #1. The host is staying in front of door #3. Door
#2 is 2 meters away from him, nevertheless he opens that door. What
would you expect to find behind door #3? A goat?! (Let us exclude
double-crossing!).
> ----- Original Message ----- 
> From: "Stefan Pochmann" <[EMAIL PROTECTED]>
> To: <[email protected]>
> Sent: Wednesday, December 28, 2005 3:47 PM
> Subject: [Speed cubing group] Re: (Off topic)3 doors...
> 
> 
> Changing wins if and only if you initially chose the wrong door, i.e. 
> two times of three.
> 
> Can you explain why your suggestion makes this wrong?
> 
> Cheers!
> Stefan
> 
>  --- In [email protected], Rune Wesström <rune.
> [EMAIL PROTECTED]> wrote:
> >
> > In real life the host is Not staying totally symmetrically in 
> relation to the doors. (He is right-handed Or left-handed. Maybe he 
> has to take a halfstep to open a certain door etc.). If he now opens 
> the "easiest" door, Not changing wins more often than one time of 
> three. If he opens the other door, changing will win more often than 
> two times of three.
> 
> 
> 
> 
> 
> 
> 
>  
> Yahoo! Groups Links
>






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