Axil Axil <[email protected]> wrote:
> When an electric arc is applied to water, the water is decomposed into > oxygen and hydrogen. But hydrogen is excited to high energy levels. When > the hydrogen is absorbed by palladium, the hydrogen carries the high energy > of excitation into the hydride. The Palladium retains that energy of > excitation through increased dipole vibrations in the lattice of that metal > as well as increased free electrons at high energy in the form of plasmons > on the surface of the metal > > The electric arc has increased the energy level of the entire system and > that level of excitation is retained while the electric arcing continues. > The entire system is storing the energy of excitation until the arc is > discontinued. > Have you confirmed this with the kind of calorimeter Piantelli uses? Is it possible to measure this effect with that calorimeter? If it is not possible to measure this effect with this calorimeter then there is no point in discussing it. We can eliminate this without a test. If you are correct, I suppose a person could devise an instrument to measure this briefly stored energy. However the cell that Piantelli uses does not have electric arc in it. It could not have one, and even if it did, the rest of the calorimeter could not withstand the heat from an electric arc. So the entire discussion is moot. If you were to place the cell close to a neutron star there might be some exotic effects that would allow extreme energy storage. I would not know about that. However, it is not possible to place the cell near a neutron star, and it is definitely not near one at this time, so I see no point to discussing this hypothetical situation. We should only discuss actual experimental conditions, not hypothetical ones that are obviously not present in this case. To take another example, perhaps if you put the cell in the core of a fission reactor the radiation might produce some unexpected storage effects. That would be interesting but it has nothing to do with this experiment because the cell is not in the core of a fission reactor. Piantelli does not need to consider this possibility when examining the energy balance. - Jed
