On Dec 5, 2008, at 7:31 AM, Jones Beene wrote:
Horace Heffner writes,
> Say, it may be that CH gas is being momentarily created in the
process. In any case, in CH or in other hydrocarbon forms, if the
H is periodically in the deflated state then stimulation by
polarized laser will greatly increase the probability of C+H fusion
by imposing a magnetic gradient.
Well, I am still of the opinion that the mass difference between CH
and 13C "should have" been noticed by the authors in the
spectrometry, since it so very critical to their conclusion, and so
obvious as an alternative ... should I say "alternative to the near-
miraculous conclusion" which the propose; and efforts are underway
to confirm this.
I think it is entirely possible that, except for trace amounts, *all*
the 13C is actually CH. The only thing anomalous about the
experiment so far, beyond any reasonable doubt, is the presence of
gammas. The gammas are associated with the Pt catalyst heat, and
that is because (unfortunately) the thermocouple was placed right up
against the catalyst. The gammas and "excess heat" primarily
materialize when the temperature of the cell is dropped. Though the
numbers don't show it, I would expect the pressure in the cell to
drop as temperature drops, and this would cause a maximal rate of
hydrogen degassing, i.e. inter-site tunneling, which is conducive to
fusion, or at least formation of high energy electron containing pre-
fusion nuclei.
Under the inflation fusion model I would in fact expect that most of
the "13C" is in fact CH, because the heat released and total gamma
energy can not account for the actual fusion of so much 13C.
Further, the C+p reaction is weak, and thus should have a very small
cross section. Just because the deflated hydrogen can tunnel into
the C nucleus with significant probability doesn't mean fusion
actually occurs. The energy released by a slow process of "re-
inflating" would in fact produce gammas, and the source for that
energy is the zero point field. This is one reason I suggested using
D instead of H. That should really increase the nuclear signature,
and it should produce C14, which is readily assayed with great
accuracy by liquid scintillation counting.
Actually, the above leads to an excellent suggestion that can still
be done after the fact. Assay the residue for C14. Some of the
hydrogen used was probably deuterium. It would cost a lot to obtain
pure protium and no mention was made regarding the use of pure
protium. It is possible some of the radiation came from a C+D reaction.
Best regards,
Horace Heffner
http://www.mtaonline.net/~hheffner/
