In reply to Horace Heffner's message of Fri, 5 Dec 2008 08:42:53 -0900: Hi, [snip] >I think it is entirely possible that, except for trace amounts, *all* >the 13C is actually CH.
I agree. One would need to determine the resolving power of the actual MS used, as it may not have been adequate to the task of discriminating between the two. There is also another possibility. Mizuno is a physicist (I believe), and may simply have assumed that a reported mass of 13 implied C13, while the lab that did the work may simply have reported a mass of 13, assuming that Mizuno would realize it was CH, as any chemist would have assumed. >The only thing anomalous about the >experiment so far, beyond any reasonable doubt, is the presence of >gammas. The gammas are associated with the Pt catalyst heat, and >that is because (unfortunately) the thermocouple was placed right up >against the catalyst. Why do you consider this unfortunate? >The gammas and "excess heat" primarily >materialize when the temperature of the cell is dropped. Though the >numbers don't show it, I would expect the pressure in the cell to >drop as temperature drops, and this would cause a maximal rate of >hydrogen degassing, i.e. inter-site tunneling, which is conducive to >fusion, or at least formation of high energy electron containing pre- >fusion nuclei. I assume you are proposing that the electron enters the nucleus first. An interesting idea. It would (temporarily) lower the atomic number of the nucleus by 1, making the tunneling of the proton far more likely. This would have huge consequences for fusion between Hydrogen isotopes, where it would temporarily result in the complete disappearance of the Coulomb barrier. If we further assume that the chance of a Hydrino's shrunken electron ending up in the target nucleus is greater than in the case of normal ground state Hydrogen, combined with the shorter tunneling distance in the Hydrino case, then Hydrino fusion becomes almost "easy". ;) > >Under the inflation fusion model I would in fact expect that most of >the "13C" is in fact CH, because the heat released and total gamma >energy can not account for the actual fusion of so much 13C. >Further, the C+p reaction is weak, and thus should have a very small >cross section. Just because the deflated hydrogen can tunnel into >the C nucleus with significant probability doesn't mean fusion >actually occurs. The energy released by a slow process of "re- >inflating" would in fact produce gammas, and the source for that >energy is the zero point field. This is one reason I suggested using >D instead of H. That should really increase the nuclear signature, >and it should produce C14, which is readily assayed with great >accuracy by liquid scintillation counting. I would expect C12 + D -> N14, particularly since C14 normally decays to N14, hence I wouldn't expect the reverse process to occur. [snip] Regards, Robin van Spaandonk <[EMAIL PROTECTED]>
