On Dec 5, 2008, at 9:40 AM, OrionWorks wrote:
From Horace,
...
Under the inflation fusion model I would in fact expect that most
of the
"13C" is in fact CH, because the heat released and total gamma
energy can
not account for the actual fusion of so much 13C. Further, the C
+p reaction
is weak, and thus should have a very small cross section. Just
because the
deflated hydrogen can tunnel into the C nucleus with significant
probability
doesn't mean fusion actually occurs. The energy released by a
slow process
of "re-inflating" would in fact produce gammas, and the source for
that
energy is the zero point field. This is one reason I suggested
using D
instead of H. That should really increase the nuclear signature,
and it
should produce C14, which is readily assayed with great accuracy
by liquid
scintillation counting.
...
Just trying to understand this theoretical model...
The term "CH" implies, at least to me, that the individual hydrogen
atom must still posses a single electron shell regardless of what
"ground state" that electron shell is conjectured to exist as.
Otherwise it's just a proton - and therefore C would have to
"transmute" to the next element in the periodic table: Nitrogen.
In the deflation fusion model the electron has brief (attosecond
order) periodic existence within or very close to the nucleus in a
high kinetic energy small wavelength state. Though the effective
duration of the state is short, the probability of the state can be
fairly high (in water it is about about 0.25) due to a high
repetition rate. See:
http://www.mtaonline.net/~hheffner/DeflationFusion2.pdf
I guess one of the 64 dollar questions might be: exactly WHERE is this
altered hydrogen atom residing in this theorized model.
The hydrogen nucleus resides exactly where it resides any other
models. The only difference between the deflation fusion model and
others is the electron has a periodic existence (probability of
existence) in a very small wavelength form close to the nucleus.
Is it
theorized to reside really close to the 12C nucleus, or perhaps
farther out, hanging about near one of the electron inner orbital
shells.
The nucleus resides right where ordinary QM predicts it to reside.
What is significant about the deflation fusion model is that it
demonstrates there is a significant probability of simultaneous
tunneling of the hydrogen nucleus plus electron (i.e. the deflated
state hydrogen - which has a picosecond order existence, but
effectively a high repetition rate of existence) to adjacent nuclei
because the deflated state hydrogen has zero net charge. This
tunneling to adjacent nuclei over angstrom order distances is made
feasible by the fact the deflated state is neutral, and thus there is
no Coulomb barrier. The deflated state hydrogen magnetic moment is
non-zero, so magnetic dipole forces, i.e. magnetic gradients, are key
to making deflated-nucleus-to-nucleus tunneling events energetically
feasible. Because distance and energy barrier quantities reside in
an exponential term in the tunneling rate function, very small
changes in distance or energy have a very large effect on tunneling
probabilities when the tunneling distance is near molecular bond
size. Molecule kinetics (e.g. CH collisions) can have an effect on
both the inter-nuclear distance as well as orbital deformation
(alternatively nucleus dislocation from the center of charge) and
thus the near nucleus electron density and thus the probability of
the deflated state. For some discussion regarding orbital stressing
effects see:
http://mtaonline.net/~hheffner/Ostressing.pdf
It may be of interest that orbital stressing present in
sonoluminescence producing compression regimes may give rise to a
high probability of a deflated state just prior to molecular ionization.
I would imagine that at present most traditional physicists would not
bother to give any of this conjecture the slightest bit of attention.
This is certainly true.
Regards
Steven Vincent Johnson
www.OrionWorks.com
www.zazzle.com/orionworks
Best regards,
Horace Heffner
http://www.mtaonline.net/~hheffner/
