Thanks John, 

 

Very good points added.

 

*         For the same L value(s) the capacitors of the T-config  are
divided by 2, so half the  touch current.

*         The input (mains side) capacitor of the PI shunts and
increases mains RF current, so contributes to parasitic RF current in
the mains , where the series L of the T filter attenuates any RF current
in the circuit.

*         The PI filter depends more on good ground quality as the T,
due to higher (short circuit) RF currents in the input cap, or it needs
2 grounds..

*         The capacitor of the T-filter is less prone to aging due to
reduced RF currents and reduces surge and peak voltages.

 

 

Gert

 

-----Original Message-----
From: John Woodgate [mailto:[email protected]] 
Sent: Wednesday 22 July 2015 11:39
To: [email protected]
Subject: Re: [PSES] GFCI Nuisance Tripping

 

In message <[email protected]
<mailto:[email protected]> >,

dated Wed, 22 Jul 2015, "ce-test, qualified testing bv - Gert Gremmen" 

<[email protected] <mailto:[email protected]> > writes:

 

>  Filter specifications should not be made in 50 ohm environments but 

>in much lower impedance ranges (0.5 -5 Ohms), so the product will 

>better fulfil the expectations of their users

 

See the less well-known CISPR 17 standard.

> 

>*         Filter manufacturers need to be aware of the existence of 

>emission and immunity regulations and create fully bi-directional 

>filters, for lower input currents (due to lower power consumptions of 

>modern devices)

> 

>*         Adequate input/output  filters do not need high value touch 

>current capacitors. By using T-type of filters (LCL) instead of 

>PI-types (CLC) the values of decoupling caps can be heavily reduced (no


>touch current), at increased cost of dual CM-inductors. But we are used


>to that aren?t we?

 

I did a quick simulation of T and Pi filters with 1 ohm impedance and
normalized frequency, and I can't confirm that the capacitor in the T is
smaller than those in the Pi. However, the inductors in the T are
smaller than the one in the Pi.

 

This seem logical to me, since at cut-off (-3 dB frequency) the T filter
'matches' zero impedance source and load, and the Pi filter 'matches' 

infinite impedances. So the T filter has a normalized C value of 2, with
two L values of 1 in parallel, so LC = 2 x 0.5 = 1. The Pi filter has an
L value 2 in series with two Cs of value 1, so LC is again 1.

> 

>*         Shunting a low impedance signal with high value capacitors is


>NOT the way to go. Attenuation needs a high series impedance followed 

>by a low ground path, I think we all agree about that.

 

This is a very important point.

--

OOO - Own Opinions Only. With best wishes. See www.jmwa.demon.co.uk
<http://www.jmwa.demon.co.uk>  When I turn my back on the sun, it's to
look for a rainbow John Woodgate, J M Woodgate and Associates, Rayleigh,
Essex UK

 

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