In message <[email protected]>,
dated Wed, 22 Jul 2015, "ce-test, qualified testing bv - Gert Gremmen"
<[email protected]> writes:
· For the same L value(s) the capacitors of the T-config are
divided by 2, so half the touch current.
That filter requires twice the source and load impedances and the C
value is the same as in the Pi filter, not halved. We have two Ls, value
2, in parallel with a C, value 1, so LC = 1.
--
OOO - Own Opinions Only. With best wishes. See www.jmwa.demon.co.uk
When I turn my back on the sun, it's to look for a rainbow
John Woodgate, J M Woodgate and Associates, Rayleigh, Essex UK
-
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