Le 30-oct.-08, à 23:47, Kory Heath a écrit :

>
>
> On Oct 30, 2008, at 10:06 AM, Bruno Marchal wrote:
>> But ok, perhaps I have make some progress lately, and I will answer
>> that the probability remains invariant for that too. The probability
>> remains equal to 1/2 in the imperfect duplication (assuming 1/2 is
>> the perfect one).
>> But of course you have to accept that if a simple teleportation is
>> done imperfectly (without duplication), but without killing you, the
>> probability of surviving is one (despite you get blind, deaf,
>> amnesic and paralytic, for example).
>
> This is the position I was arguing against in my earlier post. Let's
> stick with simple teleportation, without duplication. If the data is
> scrambled so much that the thing that ends up on the other side is
> just a puddle of goo, then my probability of surviving the
> teleportation is 0%. It's functionally equivalent to just killing me
> at the first teleporter and not sending any data over. (Do you agree?)

OK. (in this context).


> If the probability of me surviving when an imperfect copy is made is
> still 100%, then there's some point of "imperfection" at which my
> chances of surviving suddenly shift from 100% to 0%. This change will
> be marked by (say) the difference of a single molecule (or bit of
> data, or whatever). I don't see how that can be correct.

That's why I do suppose that the doctor is perfect, that he chooses the 
right level, etc. It is for avoiding a discussion of what "survive" 
means. I can go through the reasoning without using that word. You have 
the same problem with comatose patient, abortion, etc. It is another 
thread.
All what you need for UDA like reasoning is that if you survive 
(whatever the change is made on you) you will survive with some 
corresponding  probabilities/credibilities in the case of 
self-multiplication.
*After* the reasoning is done, you will believe that you survive in all 
case, or you will reject comp. It is the comp-immortality.

Bruno
http://iridia.ulb.ac.be/~marchal/


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