On Monday, December 25, 2017 at 8:44:42 PM UTC, Russell Standish wrote:
>
> On Mon, Dec 25, 2017 at 12:32:26PM -0800, [email protected] 
> <javascript:> wrote: 
> > > 
> > > *Not linear in t, but also named "unitary operator", not to be 
> confused 
> > > with the operator by the same name that preserves inner products. AG* 
> > > 
> > 
> > 
> > *Another correction: the time evolution operator is a unitary operator 
> > since it preserves inner products, but it is NOT NAMED a unitary 
> operator. 
> > AG * 
> > 
>
> That doesn't make sense. The evolution operator is of the form 
> exp(-i/ℏ Ht), where the H, the Hamiltonian operator, is assumed to 
> be Hermitian. It is a relatively trivial exercise to prove that any 
> operator of the form exp(iA) is unitary,


I didn't write it isn't unitary. I just corrected my earlier error 
concerning
its NAME. Its name is the *time evolution operator.* It is unitary but
NOT linear in t. AG
 

> where A is Hermitian. Trivial 
> when you see how to do it, but nevertheless I had to seek help from my 
> college tutor when I first encountered this :). 
>
> Cheers 
> -- 
>
> ---------------------------------------------------------------------------- 
>
> Dr Russell Standish                    Phone 0425 253119 (mobile) 
> Principal, High Performance Coders 
> Visiting Senior Research Fellow        [email protected] 
> <javascript:> 
> Economics, Kingston University         http://www.hpcoders.com.au 
> ---------------------------------------------------------------------------- 
>
>

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