On Saturday, October 26, 2019 at 5:57:57 PM UTC-6, Philip Thrift wrote:
>
>
>
> On Saturday, October 26, 2019 at 4:19:06 PM UTC-5, Alan Grayson wrote:
>>
>>
>>
>> On Saturday, October 26, 2019 at 3:15:21 PM UTC-6, Philip Thrift wrote:
>>>
>>>
>>>
>>> On Saturday, October 26, 2019 at 4:09:08 PM UTC-5, Alan Grayson wrote:
>>>>
>>>>
>>>>
>>>> On Saturday, October 26, 2019 at 3:03:20 PM UTC-6, Philip Thrift wrote:
>>>>>
>>>>>
>>>>>
>>>>> On Saturday, October 26, 2019 at 3:42:58 PM UTC-5, Alan Grayson wrote:
>>>>>>
>>>>>>
>>>>>>
>>>>>> Why not make your point with waves so at least it's intelligible? You 
>>>>>> can get the same results in the Heisenberg Picture, but to understand 
>>>>>> "interference" you need to at least start with waves. AG 
>>>>>>
>>>>>
>>>>>
>>>>>
>>>>> But that premise (*to understand "interference" you need to at least 
>>>>> start with waves*) is simply wrong, and perhaps is the root of your 
>>>>> misunderstanding.
>>>>>
>>>>> @philipthrift 
>>>>>
>>>>
>>>> No, it's just a convenient, intuitive starting pont. That's all. I 
>>>> conclude you can't do it. Thanks for the effort. AG 
>>>>
>>>
>>>
>>> I conclude you will never understand any answer to your question: "what 
>>> does *interference* mean".
>>>
>>> @philipthrift
>>>
>>
>> You could start with S's equation and use waves in your explanation, and 
>> then generalize it. But the fact that you refuse to do so, and instead rely 
>> on other interpretations, such as Heisenberg's, suggests you don't 
>> understand "interference". AG 
>>
>
>
>
> *You could start with S's equation and use waves in your explanation, and 
> then generalize it.*
>
> OK. When you find an explanation in these terms, let us know.
>
> @philipthrift
>

I don't have one. That's why I asked. One can show that Heisenberg's 
Picture, which doesn't use waves, gives the same results as Scroedinger's 
Picture, which uses waves, but that's no explanation of "interference". AG 

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