Let's say your power supply is giving out 4.7v and your power supply VDD pin is giving out 5.2v. If you connect them together, there is a difference of 0.5v so where does this current go?
Matt. On Mar 24, 4:04 am, Wayne <[email protected]> wrote: > Wayne wrote: > > mattschinkel wrote: > >>> Why would the ICSP need a reset switch? The one in the Tutorial does > >>> not have a connection on pin2 while the Microchip schematic I attached > >>> does. It seemed to me that a missing Vdd connection might interest you. > > >> Your right, ICSP does not need a reset switch, but it is nice to have > >> a push button to reset your PIC. > > >> I think the VDD connection is needed only if you are not supplying > >> power to your PIC via another source. This ICSP VDD supply's power to > >> the PIC during programming. In my tutorial, I tell the user to keep > >> there own 5v power supply on while programming via ICSP. > > >> I don't think it is a good idea to connect ICSP VDD to the 5V power > >> supply, unless you always switch off your power supply before > >> programming. Am I correct? > > > Well I do it both ways and have not had a problem. ie with and without > > my breadboard power on. I do not recall reading anything in the PicKit2 > > manual about it. I will check and get back to you though. > > >> I can update my tutorial to reflect the same connector as PIC KIT 2 > > Here is the information about the Vdd question you had. This is from > the PicKit2 Users Manual I had previously suggested you should review. > > Wayne > > PicKit2_vdd.png > 96KViewDownload -- You received this message because you are subscribed to the Google Groups "jallib" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/jallib?hl=en.
