[PHP] stripping spaces from a string
Hi, What's the best and easiest way to strip all the spaces from a string? do i use regular expressions for it? TIA, J. Jule Slootbeek [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: stripping spaces from a string
perfect, exactly what i needed thanks J. On Friday, Dec 6, 2002, at 16:38 US/Eastern, J Smith wrote: Regular expressions would be overkill. Try $newString = str_replace( , , $oldString); J Jule Slootbeek wrote: Hi, What's the best and easiest way to strip all the spaces from a string? do i use regular expressions for it? TIA, J. Jule Slootbeek [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Jule Slootbeek [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] MySQL-port question
I have a problem, i know this is not the MySQL mailinglist, but i hope you guys can help me. when i type mysqladmin variables the port comes up as 0 and doesn't let people connect to my db remotely. does anyone know why this problem is, and how i can change my port? TIA Jule Jule Slootbeek [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] ftp file exists
if there's no function to check (which i can;t find real quick) do
soething like this:
if (!ftp_mdtm($conn_id, $file) {
echo File doesn't exist;
} else {
echo File exist;
}
On Friday, Nov 8, 2002, at 12:01 US/Eastern, Fifield, Mike wrote:
How do you check if a file exists a remote ftp site.
Jule Slootbeek
[EMAIL PROTECTED]
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[PHP] filemtime() error
Hi,
i'm writing a piece of code that allows me to upload the updated
version of my website from the local tree, to the server.
I do this by comparing the linux timestamps on the local and remote
files.
printing a table of the remote files works fine, but when i do it for
my local files, i get an error for every file:
Warning: stat failed for bandhistory.html (errno=2 - No such file or
directory) in /Users/jslootbe/Sites/upload.php on line 71
except for the index.php which just gives me a normal timestamp.
this is a dump of the dir:
total 232
drwxr-xr-x 25 jslootbe staff850 Nov 6 11:20 .
drwxr-xr-x 11 jslootbe staff374 Nov 6 13:59 ..
-rwxr-xr-x 1 jslootbe staff 15364 Nov 2 16:11 .DS_Store
-rwxr-xr-x 1 jslootbe staff519 Oct 20 20:15 band.php
-rwxr-xr-x 1 jslootbe staff 2034 Oct 23 00:56 bandhistory.html
-rwxr-xr-x 1 jslootbe staff 1021 Nov 5 21:50 blindtheory.sql
-rwxr-xr-x 1 jslootbe staff 1016 Nov 5 21:32 blindthoery.sql
-rwxr-xr-x 1 jslootbe staff322 Oct 8 19:08 colors.inc.php
-rwxr-xr-x 1 jslootbe staff146 Oct 8 19:08 contact.php
-rwxr-xr-x 1 jslootbe staff 2266 Nov 5 00:13 dates.php
-rwxr-xr-x 1 jslootbe staff188 Oct 8 19:08 globals.inc.php
-rwxr-xr-x 1 jslootbe staff194 Oct 9 20:35
globals.inc.php-online
-rwxr-xr-x 1 jslootbe staff 4 Oct 9 20:32 home.php
-rwxr-xr-x 1 jslootbe staff 3376 Oct 30 21:21 index.php
-rwxr-xr-x 1 jslootbe staff 5851 Nov 6 11:20 interaction.php
-rwxr-xr-x 1 jslootbe staff 2958 Nov 5 00:16 layout.php
drwxr-xr-x 18 jslootbe staff612 Oct 19 13:55 lyrics
-rwxr-xr-x 1 jslootbe staff 1457 Oct 25 20:42 lyrics.php
-rwxr-xr-x 1 jslootbe staff 2578 Oct 25 20:32 media.php
-rwxr-xr-x 1 jslootbe staff815 Nov 5 00:18 misc.inc.php
-rwxr-xr-x 1 jslootbe staff 1370 Oct 20 19:39 news.php
-rwxr-xr-x 1 jslootbe staff 21 Oct 8 22:39 phpinfo.php
drwxr-xr-x 7 jslootbe staff238 Oct 10 12:38 pics
-rwxr-xr-x 1 jslootbe staff148 Oct 8 19:08 template.php
-rwxr-xr-x 1 jslootbe staff 1064 Nov 3 18:53 todo.list
and here's the code.
$localDir = /Users/jslootbe/Sites/blindtheory;
if ($opendir = opendir($localDir)) {
while ($localList = readdir($opendir))
{
if ($localList != . $localList != ..) {
echo tr
td.$localList./td
tdmodified/td
td.filemtime($localList)./td
/tr;
}
}
closedir($opendir);
}
does anyone have any idea why it won't show a stamp for every file?
TIA,
Jule
Jule Slootbeek
[EMAIL PROTECTED]
[PHP] sql error
I know this is the wrong mailinglist, but i don't want to subscribe to a second one for one random question. when trying to enter this into my db: DROP TABLE IF EXISTS dates; CREATE TABLE dates ( id int(10) unsigned NOT NULL auto_increment, date varchar(50) NOT NULL default '', at varchar(50) NOT NULL default '', where varchar(255) NOT NULL default '', with varchar(255) NOT NULL default '', whereURL varchar(100) NOT NULL default '', info varchar(255) NOT NULL default '', PRIMARY KEY (id) ) TYPE=MyISAM; (this is generated by phpMyAdmin) i get this error: ERROR 1064 at line 18: You have an error in your SQL syntax near 'where varchar(255) NOT NULL default '', with varchar(255) NOT NULL default '',' at line 5 where's the error? i don't see anything wrong.. TIA, Jule Jule Slootbeek [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] sql error
Ah i see, but then why will phpMyAdmin let me use it? it works fine on my local db with these names, but on my remote server it refuses to create the table. Jule On Tuesday, Nov 5, 2002, at 21:47 US/Eastern, Marco Tabini wrote: where is a reserved keyword in SQL--try changing the name of that column to something else. Marco --- php|architect -- The Monthly Magazine For PHP Professionals Visit us on the web at http://www.phparch.com! On Tue, 5 Nov 2002, Jule Slootbeek wrote: I know this is the wrong mailinglist, but i don't want to subscribe to a second one for one random question. when trying to enter this into my db: DROP TABLE IF EXISTS dates; CREATE TABLE dates ( id int(10) unsigned NOT NULL auto_increment, date varchar(50) NOT NULL default '', at varchar(50) NOT NULL default '', where varchar(255) NOT NULL default '', with varchar(255) NOT NULL default '', whereURL varchar(100) NOT NULL default '', info varchar(255) NOT NULL default '', PRIMARY KEY (id) ) TYPE=MyISAM; (this is generated by phpMyAdmin) i get this error: ERROR 1064 at line 18: You have an error in your SQL syntax near 'where varchar(255) NOT NULL default '', with varchar(255) NOT NULL default '',' at line 5 where's the error? i don't see anything wrong.. TIA, Jule Jule Slootbeek [EMAIL PROTECTED] Jule Slootbeek [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] sql error
apparently 'where' and 'with' are keywords in Java, i've changed them and now it works fine. thanks! Jule On Tuesday, Nov 5, 2002, at 21:53 US/Eastern, Marco Tabini wrote: I'm not entirely sure... different configurations perhaps? Have you verified that that's indeed the problem? Marco --- php|architect -- The Monthly Magazine For PHP Professionals Visit us on the web at http://www.phparch.com! On Tue, 5 Nov 2002, Jule Slootbeek wrote: Ah i see, but then why will phpMyAdmin let me use it? it works fine on my local db with these names, but on my remote server it refuses to create the table. Jule On Tuesday, Nov 5, 2002, at 21:47 US/Eastern, Marco Tabini wrote: where is a reserved keyword in SQL--try changing the name of that column to something else. Marco --- php|architect -- The Monthly Magazine For PHP Professionals Visit us on the web at http://www.phparch.com! On Tue, 5 Nov 2002, Jule Slootbeek wrote: I know this is the wrong mailinglist, but i don't want to subscribe to a second one for one random question. when trying to enter this into my db: DROP TABLE IF EXISTS dates; CREATE TABLE dates ( id int(10) unsigned NOT NULL auto_increment, date varchar(50) NOT NULL default '', at varchar(50) NOT NULL default '', where varchar(255) NOT NULL default '', with varchar(255) NOT NULL default '', whereURL varchar(100) NOT NULL default '', info varchar(255) NOT NULL default '', PRIMARY KEY (id) ) TYPE=MyISAM; (this is generated by phpMyAdmin) i get this error: ERROR 1064 at line 18: You have an error in your SQL syntax near 'where varchar(255) NOT NULL default '', with varchar(255) NOT NULL default '',' at line 5 where's the error? i don't see anything wrong.. TIA, Jule Jule Slootbeek [EMAIL PROTECTED] Jule Slootbeek [EMAIL PROTECTED] Jule Slootbeek [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] sql error
possible, but wouldn't phpMyAdmin export the name with the tick marks?? CREATE TABLE foo (`where` varchar(255) NOT NULL); Jule On Tuesday, Nov 5, 2002, at 21:51 US/Eastern, John W. Holmes wrote: PHPMyAdmin may put tick marks around the name, which will get rid of the error. `where` varchar(255) not null ... ---John Holmes... -Original Message- From: Jule Slootbeek [mailto:jslootbeek;clarku.edu] Sent: Tuesday, November 05, 2002 9:43 PM To: Marco Tabini Cc: [EMAIL PROTECTED] Subject: Re: [PHP] sql error Ah i see, but then why will phpMyAdmin let me use it? it works fine on my local db with these names, but on my remote server it refuses to create the table. Jule On Tuesday, Nov 5, 2002, at 21:47 US/Eastern, Marco Tabini wrote: where is a reserved keyword in SQL--try changing the name of that column to something else. Marco --- php|architect -- The Monthly Magazine For PHP Professionals Visit us on the web at http://www.phparch.com! On Tue, 5 Nov 2002, Jule Slootbeek wrote: I know this is the wrong mailinglist, but i don't want to subscribe to a second one for one random question. when trying to enter this into my db: DROP TABLE IF EXISTS dates; CREATE TABLE dates ( id int(10) unsigned NOT NULL auto_increment, date varchar(50) NOT NULL default '', at varchar(50) NOT NULL default '', where varchar(255) NOT NULL default '', with varchar(255) NOT NULL default '', whereURL varchar(100) NOT NULL default '', info varchar(255) NOT NULL default '', PRIMARY KEY (id) ) TYPE=MyISAM; (this is generated by phpMyAdmin) i get this error: ERROR 1064 at line 18: You have an error in your SQL syntax near 'where varchar(255) NOT NULL default '', with varchar(255) NOT NULL default '',' at line 5 where's the error? i don't see anything wrong.. TIA, Jule Jule Slootbeek [EMAIL PROTECTED] Jule Slootbeek [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Jule Slootbeek [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] sql error
did I say Java? oops, i meant SQLlearning Java in my comp sci class..(= forgive me. Jule On Tuesday, Nov 5, 2002, at 21:54 US/Eastern, Martin Towell wrote: where is a java keyword ? have you got an example ? It's been _ages_ since I've done any code in java :( -Original Message- From: Jule Slootbeek [mailto:jslootbeek;clarku.edu] Sent: Wednesday, November 06, 2002 1:52 PM To: Marco Tabini Cc: [EMAIL PROTECTED] Subject: Re: [PHP] sql error apparently 'where' and 'with' are keywords in Java, i've changed them and now it works fine. thanks! Jule On Tuesday, Nov 5, 2002, at 21:53 US/Eastern, Marco Tabini wrote: I'm not entirely sure... different configurations perhaps? Have you verified that that's indeed the problem? Marco --- php|architect -- The Monthly Magazine For PHP Professionals Visit us on the web at http://www.phparch.com! On Tue, 5 Nov 2002, Jule Slootbeek wrote: Ah i see, but then why will phpMyAdmin let me use it? it works fine on my local db with these names, but on my remote server it refuses to create the table. Jule On Tuesday, Nov 5, 2002, at 21:47 US/Eastern, Marco Tabini wrote: where is a reserved keyword in SQL--try changing the name of that column to something else. Marco --- php|architect -- The Monthly Magazine For PHP Professionals Visit us on the web at http://www.phparch.com! On Tue, 5 Nov 2002, Jule Slootbeek wrote: I know this is the wrong mailinglist, but i don't want to subscribe to a second one for one random question. when trying to enter this into my db: DROP TABLE IF EXISTS dates; CREATE TABLE dates ( id int(10) unsigned NOT NULL auto_increment, date varchar(50) NOT NULL default '', at varchar(50) NOT NULL default '', where varchar(255) NOT NULL default '', with varchar(255) NOT NULL default '', whereURL varchar(100) NOT NULL default '', info varchar(255) NOT NULL default '', PRIMARY KEY (id) ) TYPE=MyISAM; (this is generated by phpMyAdmin) i get this error: ERROR 1064 at line 18: You have an error in your SQL syntax near 'where varchar(255) NOT NULL default '', with varchar(255) NOT NULL default '',' at line 5 where's the error? i don't see anything wrong.. TIA, Jule Jule Slootbeek [EMAIL PROTECTED] Jule Slootbeek [EMAIL PROTECTED] Jule Slootbeek [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Jule Slootbeek [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] getting HTML header from URL
hey is there a way to get the URL header? the title meta tags etc? i couldn't find any function in the docs, but maybe i just don't know where to look. if there's a function that pulls in an entire page that;s fine too i can work with that.. any help appreciated TIA Jule Jule Slootbeek [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] getting HTML header from URL
i thought fopen() was only for local files, didn't even bother looking, but now i think about it..it makes perfect sence to open url's as well, thanks a lot! Jule On Friday, Nov 1, 2002, at 17:42 US/Eastern, John Nichel wrote: Docs - Function Reference - Filesystem Functions - fopen() It was hidden. Jule Slootbeek wrote: hey is there a way to get the URL header? the title meta tags etc? i couldn't find any function in the docs, but maybe i just don't know where to look. if there's a function that pulls in an entire page that;s fine too i can work with that.. any help appreciated TIA Jule Jule Slootbeek [EMAIL PROTECTED] Jule Slootbeek [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] getting HTML header from URL
well, i got it to read a html file, but the problem is that it reads it after it loads it, so it doesn't read the tags, and i'm looking for the string in between title and /title is there a way using fopen() or something similar to read an html/php file before it's loaded? Jule On Friday, Nov 1, 2002, at 17:45 US/Eastern, Jule Slootbeek wrote: i thought fopen() was only for local files, didn't even bother looking, but now i think about it..it makes perfect sence to open url's as well, thanks a lot! Jule On Friday, Nov 1, 2002, at 17:42 US/Eastern, John Nichel wrote: Docs - Function Reference - Filesystem Functions - fopen() It was hidden. Jule Slootbeek wrote: hey is there a way to get the URL header? the title meta tags etc? i couldn't find any function in the docs, but maybe i just don't know where to look. if there's a function that pulls in an entire page that;s fine too i can work with that.. any help appreciated TIA Jule Jule Slootbeek [EMAIL PROTECTED] Jule Slootbeek [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Jule Slootbeek [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] getting HTML header from URL [solved]
hmm, figured it out...all of a sudden it did work:
here's the code, it loads a URL and returns the title...
dunno what it would be used for, but it aught we some more about php..
i'll probbly implement it on a link page ir something
Jule
function getTitle($url)
{
$file = @fopen($url, 'r');
if(!$file) {
$rline = Error, contact webmaster;
} else {
while (!feof ($file)) {
$line = fgets($file);
if (substr_count(strtoupper($line), TITLE) = 1) {
$rline = strip_tags($line);
return $rline;
fclose($file);
break;
}
}
fclose($file);
}
On Friday, Nov 1, 2002, at 20:26 US/Eastern, Jule Slootbeek wrote:
well, i got it to read a html file, but the problem is that it reads
it after it loads it, so it doesn't read the tags, and i'm looking for
the string in between title and /title
is there a way using fopen() or something similar to read an html/php
file before it's loaded?
Jule
On Friday, Nov 1, 2002, at 17:45 US/Eastern, Jule Slootbeek wrote:
i thought fopen() was only for local files, didn't even bother
looking, but now i think about it..it makes perfect sence to open
url's as well, thanks a lot!
Jule
On Friday, Nov 1, 2002, at 17:42 US/Eastern, John Nichel wrote:
Docs - Function Reference - Filesystem Functions - fopen()
It was hidden.
Jule Slootbeek wrote:
hey
is there a way to get the URL header? the title meta tags etc?
i couldn't find any function in the docs, but maybe i just don't
know where to look.
if there's a function that pulls in an entire page that;s fine too
i can work with that..
any help appreciated
TIA
Jule
Jule Slootbeek
[EMAIL PROTECTED]
Jule Slootbeek
[EMAIL PROTECTED]
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Jule Slootbeek
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Re: [PHP] getting HTML header from URL [solved]
oops didn't catch two little bugs
Jule
function getTitle($url)
{
$file = @fopen($url, 'r');
if(!$file) {
$rline = Error, contact webmaster;
} else {
while (!feof ($file)) {
$line = fgets($file);
if (substr_count(strtoupper($line), TITLE) = 1) {
$rline = strip_tags($line);
//return $rline;
//fclose($file);
break;
}
}
return $rline;
}
fclose($file);
}
On Friday, Nov 1, 2002, at 20:35 US/Eastern, Jule Slootbeek wrote:
hmm, figured it out...all of a sudden it did work:
here's the code, it loads a URL and returns the title...
dunno what it would be used for, but it aught we some more about php..
i'll probbly implement it on a link page ir something
Jule
function getTitle($url)
{
$file = @fopen($url, 'r');
if(!$file) {
$rline = Error, contact webmaster;
} else {
while (!feof ($file)) {
$line = fgets($file);
if (substr_count(strtoupper($line), TITLE) = 1) {
$rline = strip_tags($line);
return $rline;
fclose($file);
break;
}
}
fclose($file);
}
On Friday, Nov 1, 2002, at 20:26 US/Eastern, Jule Slootbeek wrote:
well, i got it to read a html file, but the problem is that it reads
it after it loads it, so it doesn't read the tags, and i'm looking
for the string in between title and /title
is there a way using fopen() or something similar to read an
html/php file before it's loaded?
Jule
On Friday, Nov 1, 2002, at 17:45 US/Eastern, Jule Slootbeek wrote:
i thought fopen() was only for local files, didn't even bother
looking, but now i think about it..it makes perfect sence to open
url's as well, thanks a lot!
Jule
On Friday, Nov 1, 2002, at 17:42 US/Eastern, John Nichel wrote:
Docs - Function Reference - Filesystem Functions - fopen()
It was hidden.
Jule Slootbeek wrote:
hey
is there a way to get the URL header? the title meta tags etc?
i couldn't find any function in the docs, but maybe i just don't
know where to look.
if there's a function that pulls in an entire page that;s fine too
i can work with that..
any help appreciated
TIA
Jule
Jule Slootbeek
[EMAIL PROTECTED]
Jule Slootbeek
[EMAIL PROTECTED]
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Jule Slootbeek
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Jule Slootbeek
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Re: [PHP] Re: getting HTML header from URL [solved]
yeah i just noticed that myself too,
and unfortunatly people do code their html like that..
J
On Friday, Nov 1, 2002, at 21:44 US/Eastern, David U. wrote:
Jule Slootbeek wrote:
oops didn't catch two little bugs
Jule
function getTitle($url)
{
$file = @fopen($url, 'r');
if(!$file) {
$rline = Error, contact webmaster;
} else {
while (!feof ($file)) {
$line = fgets($file);
if (substr_count(strtoupper($line), TITLE) = 1) {
$rline = strip_tags($line);
//return $rline;
//fclose($file);
break;
}
}
return $rline;
}
fclose($file);
}
1) What if this line looks like:
htmlheadtitlefoo/title/headbodybar/body/html
Wont' $rline == foobar ?
2) Can't you use a socket and read until the first TITLEstart saving
until
the /TITLE and close the socket?
-davidu
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Re: [PHP] Best way to put layout, code on pages?
What i usually do, is make a file layout.php with a couple of
functions, header() footer() etc.
then i include ('layout.php') and call the functions when i need them
and i can send things to the header, like the page title etc.
include ('layout.php');
header(Home);
blablablab
footer();
i hope this is about what you mean
Jule
On Thursday, Oct 10, 2002, at 23:00 US/Eastern, Leif K-Brooks wrote:
I've been using php for a while now, and I've made plenty of web sites
in that time. But there's been a nagging problem: the best way to put
a
layout and global code on each page. My first site had two .txt files
with header and footer code which were fopen()ed (with absolute
paths!) and eval()ed on each page at the top and bottom - not the best
option! Even if I include()d them and made them .php, that approach
would still
have some problems. No way to get the global code without the layout,
and no way to die() and use the layout in functions without knowing
what
variables it needs (for globalizing them). Right now, I'm doing
something like this:
?php
include(include.php); //This contains the database connection code
and whatever other global code, as well as the layout functions.
doheader(); //This function contains the top of the layout.
//Do whatever the page does
dofooter(); //This function contains the bottom of the layout
?
There are still problems with this, though. No way to use global code
at the bottom of the page, for one thing. I've also considered
something like:
?php
$uselayout = true; //Set whether this page wants the layout or not.
include(include.php);
headercode(); //Database connection and whatever other global code
that goes at the top, as well as the layout if $uselayout is true.
//Whatever this page does goes here.
footercode(); //Whatever global code that goes at the bottom goes
here, as well as the layout if $uselayout is true.
?
I can't find any problems with this approach, what are everyone;'s
thoughts on this?
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extent
of the law.
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[PHP] register_global variables on Mac OS X
Hi, i just installed PHP under Mac OS X and now i was looking around trying to find the php.ini file, or its equivalent, in order to turn register_globals to on, so i don't have to go through 15 pages of code and change all my variables to $_POST['foo'] but i couldn't find anywhere where this action could be done. So i was wondering if anybody had experience with PHP under Jaguar, and could lend me a hand. TIA, Jule Slootbeek [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] register_global variables on Mac OS X
Yeah that's the path to where php.ini should be (/usr/local/lib, in my case, but the Jaguar version of PHP doesn't use a php.ini file, so there's nothing there. Jule On Tuesday, Oct 8, 2002, at 22:34 US/Eastern, Timothy J Hitchens wrote: Make a page with ?php phpinfo(); ? then display the page threw the server into the browser... and it should like the location in the top area. Timothy Hitchens (HITCHO) [EMAIL PROTECTED] HITCHO has Spoken! -Original Message- From: Jule Slootbeek [mailto:[EMAIL PROTECTED]] Sent: Wednesday, 9 October 2002 12:32 PM To: [EMAIL PROTECTED] Subject: [PHP] register_global variables on Mac OS X Hi, i just installed PHP under Mac OS X and now i was looking around trying to find the php.ini file, or its equivalent, in order to turn register_globals to on, so i don't have to go through 15 pages of code and change all my variables to $_POST['foo'] but i couldn't find anywhere where this action could be done. So i was wondering if anybody had experience with PHP under Jaguar, and could lend me a hand. TIA, Jule Slootbeek [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Jule Slootbeek [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] register_global variables on Mac OS X
well, there is no such file, i searched all over my drive, and there is no php-ini.* php_ini.* i guess i could try getting a php.ini file from somewhere and putting it in the /usr/local/lib dir but i wouldn't know where to get a 'standard' php.ini file Jule On Tuesday, Oct 8, 2002, at 22:43 US/Eastern, John W. Holmes wrote: You may not have one right now and PHP is using it's defaults. Look for a php-ini.dist or php-ini.recommended in the php folder. Modify one of those and save it as php.ini. But, I have no idea where to save it on a Mac. Like the other poster said, load up a ? phpinfo(); ? page through your browser and PHP may tell you where it thinks php.ini should be. It'll be in the first block that appears on the page created by phpinfo(). ---John Holmes... -Original Message- From: Jule Slootbeek [mailto:[EMAIL PROTECTED]] Sent: Tuesday, October 08, 2002 10:32 PM To: [EMAIL PROTECTED] Subject: [PHP] register_global variables on Mac OS X Hi, i just installed PHP under Mac OS X and now i was looking around trying to find the php.ini file, or its equivalent, in order to turn register_globals to on, so i don't have to go through 15 pages of code and change all my variables to $_POST['foo'] but i couldn't find anywhere where this action could be done. So i was wondering if anybody had experience with PHP under Jaguar, and could lend me a hand. TIA, Jule Slootbeek [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Jule Slootbeek [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] register_global variables on Mac OS X
i didn't install from source, i installed from an OS X binary i found in the php website, i got a php.ini from someone else which i 'm suing, thanks guys! Jule On Tuesday, Oct 8, 2002, at 23:54 US/Eastern, CC Zona wrote: In article [EMAIL PROTECTED], [EMAIL PROTECTED] (Jule Slootbeek) wrote: Yeah that's the path to where php.ini should be (/usr/local/lib, in my case, but the Jaguar version of PHP doesn't use a php.ini file, so there's nothing there. Jaguar uses php.ini if it's in the expected location. That you don't have one yet is a matter easily resolved. You can use an ASCII text editor (BBEdit Lite, for instance http://www.bbedit.com/products/bbedit_lite/lite-download.html) to create a new document and fill it with your favorite options. Or do as others have recommended and download a prewritten one from php.net and place it in the designated location (renamed to php.ini if necessary). Or see the configuration page http://php.net/configuration for descriptions of other alternatives (ini_set(), .htaccess). -- CC -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Jule Slootbeek [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] check if a foreach loop has successfully run
Hey list,
How do i check if my script has successfully run through an entire foreach() loop
do i just go
if (foreach ($answer as $a) { echo $a })
{
return TRUE;
} else {
return FALSE;
}
thanks in advance.
Jule
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[PHP] simplicity with 2 queries..
Hey guys and gals,
I have the following function which accesses the following tables, now i want to
know if there is a way to get the quiz_id from table quiz without runnning both
these queries...
thanks,
Jule
--tables--
mysql describe user;
++--+--+-+-++
| Field | Type | Null | Key | Default | Extra |
++--+--+-+-++
| user_id| int(10) unsigned | | PRI | NULL| auto_increment |
| first_name | varchar(10) | | | ||
| last_name | varchar(20) | | | ||
| email | varchar(100) | | | ||
| username | varchar(16) | | | ||
| password | varchar(32) | | | ||
++--+--+-+-++
mysql describe quiz;
+-+--+--+-+-++
| Field | Type | Null | Key | Default | Extra |
+-+--+--+-+-++
| quiz_id | int(10) unsigned | | PRI | NULL| auto_increment |
| user_id | int(10) unsigned | | | 0 ||
| title | varchar(255) | | | ||
| noa | tinyint(2) | | | 0 ||
+-+--+--+-+-++
--function--
function addquiz_get_quiz_id() {
global $valid_user, $valid_password;
mysql_select_db($db_glob, $link_glob);
$table_user = user;
$table_quiz = quiz;
$query = SELECT * FROM $table_user WHERE username='$valid_user' AND
password='$valid_password';
$result = mysql_query($query);
$user_info = mysql_fetch_array($result);
$user_id = $user_info[user_id];
$query = SELECT * FROM $table_quiz WHERE user_id='$user_id';
$result = mysql_query($query);
$user_info = mysql_fetch_array($result);
$quiz_id = $user_info[quiz_id];
mysql_close($link_glob);
return $quiz_id;
}
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[PHP] return array
Hey guys and gals,
if i have a function
and i return an array from it
function my_function() {
blabla;
return array ($array['name'], $array['password']);
}
how do i get this into an array on the page i call the function?
$array = my_function() doesn't work?
any ideas?
thanks
Jule
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Re: [PHP] return array
try: list($doo, $dah) = my_function(); thanks alot that was it list ($array['name'], $array['password']); Jule -- Jule Slootbeek [EMAIL PROTECTED] http://blindtheory.cjb.net -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] User Authentication
Hey guys, What is the best way for user authentication (now i'm talking about the most secure and easiest way). Now i've been using sessions, and i was wondering if cookies were better and easier... any thoughts? thanks, Jule -- Jule Slootbeek [EMAIL PROTECTED] http://blindtheory.cjb.net -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] User Authentication
John Holmes wrote: Sessions use cookies as it is...so what do you really want to do...what do you want to protect? ---John Holmes... Oh ok, that explains it then... Well thanks for the info anyway. I was basically just wondering which method was reccommended.. Jule -- Jule Slootbeek [EMAIL PROTECTED] http://blindtheory.cjb.net -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] stupid error, please kick me (and send me a solution)
Hey guys,
i'm getting this error with the following sql script using php:
--error--
Warning: Supplied argument is not a valid MySQL-Link resource in
/var/www/phpquiz/register_user.php on line 12
--error--
--script--
$link_glob = mysql_connect('$host_glob', '$un_glob', '$pw_glob');
$query = INSERT INTO user values('0', '$fname', '$lname', '$email',
'$username', PASSWORD('$password');
$result = mysql_db_query('$db_glob', '$query', $link_glob');
if (!$result) {
echo font size=+1Your Information could not be
entered into the database,
Please contact the a
href=mailto:$webmasterwebmaster/a./fontbrbr . mysql_errno() .
: . mysql_error() . brbr;
} else {
echo font size=+1Your Information has successfully
been entered into the
database!/fontbr;
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Re: [PHP] Re: stupid error, please kick me (and send me a solution)
[EMAIL PROTECTED] wrote:
Do not use double kotes here.
$link_glob = \mysql_connect(\'$host_glob\', \'$un_glob\',
\'$pw_glob\')\;
mysql_connect is a function.
Regards,
Laercio Fortes
Citando Jason Soza [EMAIL PROTECTED]:
If this is truly the code you\'re using, you\'re missing the closing
curly-brace after the else statement. I.e. this:
} else {
echo \font size=+1Your Information has successfully been
entered into the database!/fontbr\;
Should be this:
} else {
echo \font size=+1Your Information has successfully been
entered into the database!/fontbr\;
}
HTH,
Jason Soza
- Original Message -
From: Jule Slootbeek [EMAIL PROTECTED]
Date: Monday, June 3, 2002 2:09 pm
Subject: stupid error, please kick me (and send me a solution)
Hey guys,
i\'m getting this error with the following sql script using php:
--error--
Warning: Supplied argument is not a valid MySQL-Link resource in
/var/www/phpquiz/register_user.php on line 12
--error--
--script--
$link_glob = \mysql_connect(\'$host_glob\', \'$un_glob\', \'$pw_glob\')\;
$query = \INSERT INTO user values(\'0\', \'$fname\', \'$lname\',
\'$email\',
\'$username\', PASSWORD(\'$password\')\;
$result = mysql_db_query(\'$db_glob\', \'$query\',
$link_glob\'); if (!$result) {
echo \font size=+1Your Information
could not be entered into the database,
Please contact the
href=mailto:$webmasterwebmaster./fontbrbr\ . mysql_errno()
.
\: \ . mysql_error() . \brbr\;
} else {
echo \font size=+1Your Information
has
successfully been entered into the
database!/fontbr\;
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changing that line to this:
$link_glob = mysql_connect($host_glob, $un_glob, $pw_glob);
doesn't make any difference...
i still get the error..
could it be my setup?
the $link_glob var is in globals.inc.php and i use this through
require('globals.inc.php'); which has worked great in the past...
the other two lines.
Now:
$query = INSERT INTO user values('0', '$fname', '$lname', '$email',
'$username', PASSWORD('$password');
$result = mysql_db_query($db_glob, $query, $link_gob);
are in register_user.php in which the first line is
require('globals.inc.php');
I've used this method in the past also, and i've never experienced
problems with it...
thanks,
Jule
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[PHP] Re: stupid error, please kick me (and send me a solution)
G r e g L a w r i e wrote:
It would also appear you are missing a closing ) at the end of the
'$query=...' line. You have two opening backets and only one closing.
Greg
-Original Message-
From: Bruce Lewis [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, 4 June 2002 7:50
To: [EMAIL PROTECTED]; mysql; php-general
Subject: Re: stupid error, please kick me (and send me a solution)
Your missing your closing } at the end of the else statement.
- Original Message -
From: Jule Slootbeek [EMAIL PROTECTED]
To: mysql [EMAIL PROTECTED]; php-general
[EMAIL PROTECTED]
Sent: Monday, June 03, 2002 5:09 PM
Subject: stupid error, please kick me (and send me a solution)
Hey guys,
i'm getting this error with the following sql script using php:
--error--
Warning: Supplied argument is not a valid MySQL-Link resource in
/var/www/phpquiz/register_user.php on line 12
--error--
--script--
$link_glob = mysql_connect('$host_glob', '$un_glob', '$pw_glob');
$query = INSERT INTO user values('0', '$fname', '$lname', '$email',
'$username', PASSWORD('$password');
$result = mysql_db_query('$db_glob', '$query', $link_glob');
if (!$result) {
echo font size=+1Your Information could not be entered into the
database,
Please contact the a
href=mailto:$webmasterwebmaster/a./fontbrbr . mysql_errno() .
: . mysql_error() . brbr;
} else {
echo font size=+1Your Information has successfully been entered into
the
database!/fontbr;
--
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[EMAIL PROTECTED]
http://blindtheory.cjb.net
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$query = INSERT INTO user values('0', '$fname', '$lname', '$email',
'$username', PASSWORD('$password');
that should be all closed shouldn't it?
my text editor colors code, and it doesn't show any mistakes..
thanks though
Jule
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[PHP] Re: stupid error, please kick me (and send me a solution)
Jule Slootbeek wrote:
G r e g L a w r i e wrote:
It would also appear you are missing a closing ) at the end of the
'$query=...' line. You have two opening backets and only one closing.
Greg
-Original Message-
From: Bruce Lewis [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, 4 June 2002 7:50
To: [EMAIL PROTECTED]; mysql; php-general
Subject: Re: stupid error, please kick me (and send me a solution)
Your missing your closing } at the end of the else statement.
- Original Message -
From: Jule Slootbeek [EMAIL PROTECTED]
To: mysql [EMAIL PROTECTED]; php-general
[EMAIL PROTECTED]
Sent: Monday, June 03, 2002 5:09 PM
Subject: stupid error, please kick me (and send me a solution)
Hey guys,
i'm getting this error with the following sql script using php:
--error--
Warning: Supplied argument is not a valid MySQL-Link resource in
/var/www/phpquiz/register_user.php on line 12
--error--
--script--
$link_glob = mysql_connect('$host_glob', '$un_glob', '$pw_glob');
$query = INSERT INTO user values('0', '$fname', '$lname', '$email',
'$username', PASSWORD('$password');
$result = mysql_db_query('$db_glob', '$query', $link_glob');
if (!$result) {
echo font size=+1Your Information could not be entered into the
database,
Please contact the a
href=mailto:$webmasterwebmaster/a./fontbrbr . mysql_errno() .
: . mysql_error() . brbr;
} else {
echo font size=+1Your Information has successfully been entered into
the
database!/fontbr;
--
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[EMAIL PROTECTED]
http://blindtheory.cjb.net
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$query = INSERT INTO user values('0', '$fname', '$lname', '$email',
'$username', PASSWORD('$password');
that should be all closed shouldn't it?
my text editor colors code, and it doesn't show any mistakes..
thanks though
Jule
well it didn't fix it, but still thanks,
Jule
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[PHP] HUGE ERROR (was: [PHP] stupid error, please kick me (and send mea solution))
ok, i think i fixed up everything everybody told me (although some
answers did contradict) and here is the entire script...
Jule
--script (globals.inc.php)--
?php
$host_glob = localhost;
$db_glob = phpquiz;
$un_glob = phpquiz;
$pw_glob = phpquiz;
$link_glob = mysql_connect($host_glob, $un_glob, $pw_glob);
$webmaster = [EMAIL PROTECTED];
?
--script (globals.inc.php)--
--script (register_user.php)--
?php
session_start();
require(globals.inc.php);
require(layout.fnct.php);
html_header(Register a New User, Enter Information);
/**/
if ($fname $lname $email $username $password $vpassword) {
if ($password != $vpassword) {
echo font size = +1 color = \#FF\Your passwords do
not match,
please try again/fontbr;
} else {
if (!$link_glob) {
echo font size=+1 color=\#FF\You could not
connect to the
database.brPlease contact the a
href=mailto:$webmasterwebmaster/a.brbr/font . mysql_errno() .
: . mysql_error() . br;
} else {
if (!mysql_select_db($db_glob, $link_glob)) {
echo font size=+1 color=\#FF\The
Database could not be selectedbr
Please contact the a
href=mailto:$webmasterwebmaster/a.brbr/font . mysql_errno() .
: . mysql_error() . br;
} else {
$table_user = user;
$query = INSERT INTO $table_user values('0',
'$fname', '$lname', '$email',
'$username', PASSWORD('$password'));
$result = mysql_query('$query', '$link_glob');
if (!$result) {
echo font size=+1
color=\#FF\Your Information could not be entered
into the database.br Please contact the a
href=mailto:$webmasterwebmaster/a./fontbrbr . mysql_errno() .
: . mysql_error() . br;
} else {
echo font size = +1
color=\#FF\Your Information has successfully been
entered into the database!/fontbr;
echo click a
href=\manage_account.php\here/a to change your personal
options and to add your first quiz!;
html_footer();
exit;
}
}
}
}
}
echo font size=+1Please enter the required information/font;
echo form method=post action=register_user.php
Name: input type=text name=fname size=10 maxlength=10
input type=text name=lname size=20 maxlength=20br
Email: input type=text name=email size=30 maxlength=100br
UserName: input type=text name=username size=16
maclength=16br
Password: input type=password name=password size=8
maxlength=8br
Verify Password: input type=password name=vpassword size=8
maxlength=8brbr
input type=submit value=\Register\input type=reset
value=\Clear\
/form;
/**/
html_footer();
?
--script (register_user.php)--
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[PHP] HUGE ERROR (was: [PHP] stupid error, please kick me (and sendme a solution))
ps: it was still not working.. -- Jule Slootbeek [EMAIL PROTECTED] http://blindtheory.cjb.net -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] HUGE ERROR (was: [PHP] stupid error, please kick me (andsend me a solution))
Philip Olson wrote:
Please post:
a) the error
b) if the error is line #5, just post related lines line 4-6.
I did see this:
$result = mysql_query('$query', '$link_glob');
Which should be:
$result = mysql_query($query, $link_glob);
OK that did fix the problem...:)
I am now going to sit in a corner and be ashamed of myself
thanks Philip and and everybody else...
Jule
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Re: [PHP] Time release type question
I think that is right Jay,
you can use mktime() to change the date into unix time and then create the if
statement
if ((mktime([current])) == (mktime([date of assignment])) {
echo link to assignment
}
something along those lines..
you can easily check it by setting the system clock forward
Jule
On Wednesday 29 May 2002 00:14, you wrote:
On Wednesday 29 May 2002 11:52, Dr. Indera wrote:
I am in the planning stage of building an online course room. Each week I
need to upload pages for that weeks lesson and assignments. What I want
to know is if there is a way for me to have all 8 weeks of the course
pages created and upload them all at one time, but only have certain
pages 'visible' based on the current date.
This is an example of what I'm talking about.
Week 1 pages would be visible starting June 3rd
Week 2 pages would be visible starting June 10th
Week 3 pages would be visible starting June 17th
Am I missing something? It's just a simple matter of checking the current
date and if it exceeds defined threshold (say June 3rd) then display the
page otherwise display an error message or redirect or whatever.
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Re: [PHP] Login determines content on page
That's all possible using an SQL database (www.mysql.com) just think about the databnse first before you actually make it, i ran into a lot of problems because i just kept adding tables whenever i needed them a good hint is to write scemes of your script and what ylu want to achieve on paper before actually starting coding.. see www.php.net and www.mysql.com for all the docs you need. They really helped me along, so did the this list. Jule On Wednesday 29 May 2002 00:24, Dr. Indera wrote: Hello, I'd to know how difficult it is to achieve the following: Create login page, when the submit button is clicked, the user info is checked against a database as to whether is login info is valid. if it is valid, a page is displayed that lists all of the classes that the user has registered for, meaning each user will see a different list of classes. Thanks Indera -- |\/\__/\/| | Jule Slootbeek | | [EMAIL PROTECTED]| | http://blindtheory.cjb.net | | __ | |/\/ \/\| -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Time release type question
actually that should be
for ($n = 1; $n = $number_of_assignments; $n++) {
if (mktime($current) = mktime($assignment[$n]) {
echo assignment[$n]br\n;
}
}
Jule
On Wednesday 29 May 2002 00:31, Jule wrote:
I think that is right Jay,
you can use mktime() to change the date into unix time and then create the
if statement
if ((mktime([current])) == (mktime([date of assignment])) {
echo link to assignment
}
something along those lines..
you can easily check it by setting the system clock forward
Jule
On Wednesday 29 May 2002 00:14, you wrote:
On Wednesday 29 May 2002 11:52, Dr. Indera wrote:
I am in the planning stage of building an online course room. Each week
I need to upload pages for that weeks lesson and assignments. What I
want to know is if there is a way for me to have all 8 weeks of the
course pages created and upload them all at one time, but only have
certain pages 'visible' based on the current date.
This is an example of what I'm talking about.
Week 1 pages would be visible starting June 3rd
Week 2 pages would be visible starting June 10th
Week 3 pages would be visible starting June 17th
Am I missing something? It's just a simple matter of checking the current
date and if it exceeds defined threshold (say June 3rd) then display the
page otherwise display an error message or redirect or whatever.
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Re: [PHP] Is this a bug?
Dunno if it's a bug, but it's 2147483648 to max for an integer? doesn't bigint support higher numbers than that? i'm not sure but i think that's why your number gor cut down. Jule On Monday 27 May 2002 22:36, zhaoxd wrote: Hello all: Not long ago I wrote some php code in my computer which had a apache server,and my php version is 4.0.5.The code as followed: $num = 2886732778; settype($num, integer); echo $num; And I found the num is -2147483648.attention,please:the version of php is 4.0.5. When I installed php-4.2.0 in my computer,however,I found the output of result is -1408234499. Why did the difference between the two version php happen?Is this a bug??? Any help is appreciated! zhaoxd -- |\/\__/\/| | Jule Slootbeek | | [EMAIL PROTECTED]| | http://blindtheory.cjb.net | | __ | |/\/ \/\| -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Is this a bug?
ps: sorry for all the typos... Jule On Monday 27 May 2002 22:51, Jule wrote: Dunno if it's a bug, but it's 2147483648 to max for an integer? doesn't bigint support higher numbers than that? i'm not sure but i think that's why your number gor cut down. Jule On Monday 27 May 2002 22:36, zhaoxd wrote: Hello all: Not long ago I wrote some php code in my computer which had a apache server,and my php version is 4.0.5.The code as followed: $num = 2886732778; settype($num, integer); echo $num; And I found the num is -2147483648.attention,please:the version of php is 4.0.5. When I installed php-4.2.0 in my computer,however,I found the output of result is -1408234499. Why did the difference between the two version php happen?Is this a bug??? Any help is appreciated! zhaoxd -- |\/\__/\/| | Jule Slootbeek | | [EMAIL PROTECTED]| | http://blindtheory.cjb.net | | __ | |/\/ \/\| -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Is this a bug?
see this page: http://www.php.net/manual/en/language.types.integer.php Jule On Monday 27 May 2002 22:52, Jule wrote: ps: sorry for all the typos... Jule On Monday 27 May 2002 22:51, Jule wrote: Dunno if it's a bug, but it's 2147483648 to max for an integer? doesn't bigint support higher numbers than that? i'm not sure but i think that's why your number gor cut down. Jule On Monday 27 May 2002 22:36, zhaoxd wrote: Hello all: Not long ago I wrote some php code in my computer which had a apache server,and my php version is 4.0.5.The code as followed: $num = 2886732778; settype($num, integer); echo $num; And I found the num is -2147483648.attention,please:the version of php is 4.0.5. When I installed php-4.2.0 in my computer,however,I found the output of result is -1408234499. Why did the difference between the two version php happen?Is this a bug??? Any help is appreciated! zhaoxd -- |\/\__/\/| | Jule Slootbeek | | [EMAIL PROTECTED]| | http://blindtheory.cjb.net | | __ | |/\/ \/\| -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] job payment.
Hey guys, I got an offer to do some php/mysql design for a local company, basically what it's going to be is to take the current Access DB and make it acessible through a webpage (that's the basic info they gave me). How much should i except to get paid for this, and what is an acceptable amount, for the completion of this project, or per hour? Jule -- |\/\__/\/| | Jule Slootbeek | | [EMAIL PROTECTED]| | http://blindtheory.cjb.net | | __ | |/\/ \/\| --- -- |\/\__/\/| | Jule Slootbeek | | [EMAIL PROTECTED]| | http://blindtheory.cjb.net | | __ | |/\/ \/\| -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: job payment.
Hey everybody, thanks a lot for all the info i got, i know it's kindof a stragne question, but i really had no idea to expect what to earn or to be offered in a situation like the one i'm in now. Now i know what to compare with and how to deal with everything and i think i'm set on job-instructions for the rest of my life. thanks a lot i really appreciate it. Jule On Sunday 19 May 2002 20:46, Doug Riddle wrote: --- Jule [EMAIL PROTECTED] wrote: Hey guys, I got an offer to do some php/mysql design for a local company, basically what it's going to be is to take the current Access DB and make it acessible through a webpage (that's the basic info they gave me). How much should i except to get paid for this, and what is an acceptable amount, for the completion of this project, or per hour? Jule -- Jule: I cannot guess what the going rate in New England is for DB programming. A few years ago I was getting $20.00 US for work like it. I have made a lot more too, it sort of depends on what the market will bear. I suspect they are not sure themselves. I can offer a few things to think about... Things to consider: 1) Task Creep/Function creep/add-in bloat/design creep/ etc. Get it clear up front what it is they expect and what constitutes a completed project. If there is not a clear design and task list, then even they are not sure what they want. They want someone to figure that out for them, and are probably not fully aware of the effort involved, or the cost. In that case I would ask for hourly wages. That way, changes to the project in mid-stream do not require negotiations about cost and pay. 2) Deliverables. Make sure you get a schedule of when they want what. You will need time to figure out the DB, and work with them on the front-end the client will see, not to mention the nuts and bolts of the job. Break the project into bite-sized pieces and get their buy-in on each stage. Get the guidlines in writing and a firm definition of what they consider a completed project in the contract. 3) Coordination. If at all possible, get one, or at the most two, people to act as coordinators. These should be people able to approve designs, make decisions and preferably write checks. Avoid designing by committee wherever possible. 4) Contract. Get it in writing. Unless they are offering you a position with their company, they will expect a contract. It doesn't have to be a complicated formal affair. Just discuss the job, write down their expectations and convert that into a for the completion of this project as outlined herein, the company of I've-got-your-wallet agrees to pay my company, and-all-your-money, X dollars per hour for the building of this web site. The company agrees to provide ample opportunity to discuss the deliverables as outlined and tender approval in a timely basis, etc. That's it, save your receipts and keep good notes. That will allow you to be sure you own any code you write, not them. They are buying the use of the code, not the code. Make sure you work that in somewhere. After that, just enjoy yourself. = Warmest Regards, Doug Riddle http://www.dougriddle.com ## If they do discover life on other planets, who will get to them first, The Democrats, the Republicans, Avon, or the Latter Day Saints? ## __ Do You Yahoo!? LAUNCH - Your Yahoo! Music Experience http://launch.yahoo.com -- |\/\__/\/| | Jule Slootbeek | | [EMAIL PROTECTED]| | http://blindtheory.cjb.net | | __ | |/\/ \/\| -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] random order by id
Hey guys, i have a db and a table with id and questions now i want these questions to be listed in a random order, is there a way to format my SQL query or do i need some PHP work to? i can ofcourse select a random one, that's no problem, but how do i make sure that that one does not get chosen again. and that after it has printed all the records it stops any ideas? Jule -- |\/\__/\/| | Jule Slootbeek | | [EMAIL PROTECTED]| | http://blindtheory.cjb.net | | __ | |/\/ \/\| -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] $answers[answer$n]
Hey guys,
i'm getting this error whe i try to access this variable. $answers[answer$n]
Parse error: parse error, expecting `']'' in
/home/blindtheory/web/quiz/add_quiz/add_quiz_process_2.php on line 36
the variable $answer[answers$n] comes from a form on the preceding page in
which a number of answers has been entered. the number of answers is up to
the user and can vary from 2 to 15. not the $n comes from a for loop whcih
enteres the answers into a database since i do not know how many answers each
user has used.
why am i getting this error?
and is there a way around it?
following is the for() loop in which this story takes place.
thanks
Jule
--SCRIPT--
for ($n = 1; $n = $quiz[number_answers]; $n++) {
$table = $quiz[code]_answers;
$value = $answers[answer$n];
$query_alter_table = ALTER table $table ADD answer$n TEXT NUT
NULL;
$query_add_answers = INSERT INTO $table (answer$n)
VALUES($value);
if (mysql_db_query($database_glob, $query_alter_table,
$link_glob) AND
(mysql_db_query($database_glob, $query_add_answer, $link_glob));
echo Answer $n has successfully been added to the
Quizbr\n;
} else {
echo mysql_error();
}
echo Click here to continue;
}
--SCRIPT--
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[PHP] Alter table and add cell at a time.
a question:
if i have this:
for ($n = 1; $n = $quiz[number_answers]; $n++) {
$table = $qcode._answers;
$value = $answers[answer.$n];
$value2 = answer.$n;
$query_alter_table = ALTER TABLE $table ADD $value2 TEXT NOT NULL;
$query_add_answers = INSERT INTO $table ($value2) VALUES('$value');
if (mysql_db_query($database_glob, $query_alter_table, $link_glob)) {
if (mysql_db_query($database_glob, $query_add_answers, $link_glob)) {
echo Answer $n: $value has successfully been added to the
Quizbr\n;
} else {
echo mysql_error() . 1br;
}
} else {
echo mysql_error(). 2br;
}
}
How do I get the $value to be in the same row as the preceding one?
now it comes like this:
++-+-+-+-+
| id | answer1 | answer2 | answer3 | answer4 |
++-+-+-+-+
| 1 | answer1 | | | |
| 2 | | answer2 | | |
| 3 | | | answer3 | |
| 4 | | | | answer4 |
++-+-+-+-+
so it's like this?
++-+-+-+-+
| id | answer1 | answer2 | answer3 | answer4 |
++-+-+-+-+
| 1 | answer1 | answer2 | answer3 | answer4 |
++-+-+-+-+
thanks,
Jule
On Friday 17 May 2002 19:17, you wrote:
Hello,
Try using NOT NULL. As weird as MySQL can be, don't think it is that
NUTty. =)
Harrison
- Original Message -
From: Jule [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, May 17, 2002 7:00 PM
Subject: ALTER TABLE $table ADD $value2 TEXT NUT NULL
Hey i'm getting this error:
You have an error in your SQL syntax near 'NUT NULL' at line 1
when i run this query,
ALTER TABLE $table ADD $value2 TEXT NUT NULL
from the documentation i understood that this was the correct notation.
any ideas?
thanks
Jule
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Re: [PHP] Feelin' dumb...
try,
for ($i=1; $i=$num_pages; $i = $i + 20) {
}
or try,
$i = 1;
while ($i=$num_pages) {
//text here
$i = $i + 20;
}
I got those little problems too all the time..
and the boards/lists always help.
Jule
On Friday 17 May 2002 23:19, you wrote:
Okay, I'm apologizing right now for this, but I hope it's at least
tolerable. I have this:
for ($i=1; $i=$num_pages; $i++) {
// print stuff here
}
For each loop, I want to add 20 to $i, so after the first iteration, I have
21, then 41, 61, etc. I've tried $i+20, $i + 20, I've tried looking in the
manual, but I assume this is some C-type function, and I'm not familiar
with C!
Any helpers?
Jason Soza
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Re: [PHP] Feelin' dumb...
would that work?
isn't $i++; abbr. for $i = $i + 1;
so now the $i + 20; doens't declare anything.
just like $i += $b; is abbr. $i = $i + $b;
Jule.
On Friday 17 May 2002 23:14, you wrote:
Hmm... Wouldn¹t you just do this?:
for ($i=1; $i=$num_pages; $i+20) {
// print stuff here
}
Rick
The vision must be followed by the venture. It is not enough to stare up
the steps - we must step up the stairs. - Vance Havner
From: Jason Soza [EMAIL PROTECTED]
Date: Fri, 17 May 2002 19:19:28 -0800
To: [EMAIL PROTECTED]
Subject: [PHP] Feelin' dumb...
Okay, I'm apologizing right now for this, but I hope it's at least
tolerable. I have this:
for ($i=1; $i=$num_pages; $i++) {
// print stuff here
}
For each loop, I want to add 20 to $i, so after the first iteration, I
have 21, then 41, 61, etc. I've tried $i+20, $i + 20, I've tried looking
in the manual, but I assume this is some C-type function, and I'm not
familiar with C!
Any helpers?
Jason Soza
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[PHP] method=post problem
Hey guys and gals,
i have a form with method=post which sends
input type=hidden name=quiz[quiz_title] value=$quiz[quiz_title]
input type=hidden name=quiz[owner_name] value=$quiz[owner_name]
input type=hidden name=quiz[owner_email] value=$quiz[owner_email]
input type=hidden name=quiz[number_answers] value=$quiz[number_answers]
input type=hidden name=submitted value=TRUE
to the same page, and picks it up in an
if ($submitted) {} loop.
but now here's the problem:
when it comes back and goes into the loop. Only the first name from
$quiz[owner_name] is left, so where it used to be John Doe, is now only Joe.
how do i fix this?
thanks
Jule
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[PHP] random order
Hey guys and gals, I have a problem: I have a mysql databse with 4 rows, and each row (row1, row2, row3, and row4) contains a sentence. now i want these sentences to appear in random order: instance: 1 2etc. row2 row4 row4 row2 row1 row1 row3 row3 how do i go about that?? any ideas apreciated. thanks Jule -- |\/\__/\/| | Jule Slootbeek | | [EMAIL PROTECTED]| | http://blindtheory.cjb.net | | __ | |/\/ \/\| -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] random order
hmm it got a little more complicated now, i have a table with: id title question answer1 answer2 answer3 answer4. how can i use all of those in a php page but only randomize the answers? so i get title title questionquestion answer3 answer4 answer2 answer1 answer4 answer3 answer1 answer2 any ideas? thanks, Jule On Sunday 12 May 2002 17:30, you wrote: Add on a LIMIT to restrict it to return a certain number of rows. If you had a table of say, 100 rows, and you wanted four random ones out of the 100, then you'd use this: SELECT * FROM table ORDER BY RAND() LIMIT 4; ---John Holmes... -Original Message- From: Jule [mailto:[EMAIL PROTECTED]] Sent: Sunday, May 12, 2002 11:22 AM To: [EMAIL PROTECTED] Subject: Re: [PHP] random order Thanks John, I thought that that command only selected a random row.. must've read wrong. thanks. Jule On Sunday 12 May 2002 17:21, you wrote: Nothing to do with PHP... SELECT * FROM table ORDER BY RAND(); ---John Holmes... -Original Message- From: Jule [mailto:[EMAIL PROTECTED]] Sent: Sunday, May 12, 2002 9:49 AM To: [EMAIL PROTECTED] Subject: [PHP] random order Hey guys and gals, I have a problem: I have a mysql databse with 4 rows, and each row (row1, row2, row3, and row4) contains a sentence. now i want these sentences to appear in random order: instance: 1 2etc. row2 row4 row4 row2 row1 row1 row3 row3 how do i go about that?? any ideas apreciated. thanks Jule -- |\/\__/\/| | Jule Slootbeek | | [EMAIL PROTECTED]| | http://blindtheory.cjb.net | | __ | |/\/ \/\| -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- |\/\__/\/| | Jule Slootbeek | | [EMAIL PROTECTED]| | http://blindtheory.cjb.net | | __ | |/\/ \/\| -- |\/\__/\/| | Jule Slootbeek | | [EMAIL PROTECTED]| | http://blindtheory.cjb.net | | __ | |/\/ \/\| -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] global variables
Hey, i'm just wondering if there is another way to write global variables to a global.php, now i just the whole fopen etc script, where i open a file and write the sctring $number_right = [whatever number it is] to the file, but is there a different way to write it to the file with one simple command? i could use cookies, but i prefer a simpler way. thanks Jule -- Jule Slootbeek [EMAIL PROTECTED] http://blindtheory.cjb.net -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] variables over 2 pages w/ a table.
Hey, i've got a little problem: I have two php pages index.php and news/index.php now in index.php there is a table which shows news/index.php $left = news; $ltitle = index; $lext= php; include ($left/$ltitle.$lext); now this allows me to keep the layout the same, but change the pages within the table using URL commands index.php?left=newsltitle=indexlext=php now news/index.php takes a variable: $start if (empty($start)) $start= 0; $end = $start+8; $Query = SELECT * from $TableName ORDER BY postdate DESC LIMIT $start, $end; this is to show eight(8) news articles at a time. now also on the news/index.php page there is a link next to show the next 8 articles. a href=index.php?lext=php?start=8next/a so this should link to the index page, which calls upon news/index.php, opens it in the left column of the table, and gives $start the value of 8. but it gives me this error: Warning: Failed opening 'news/index.php?start=8' for inclusion (include_path='') in /home/blindtheory/web/newweb/index.php on line 31 so how can i solve this and get the articles to show in groups of 8? thanks in advance. Jule -- Jule Slootbeek [EMAIL PROTECTED] http://blindtheory.cjb.net -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] parse error
Hey guys, i'm writing this guestbook script for my site, and i'm getting a
random parse error where i think everything is normal, it gives it on line 26
which is
echo Your entry will be posted!;
my script follows
Jule
--SCRIPT--
?php
$Guestbook[dateadd] = date(F j, Y H:i:s);
$Guestbook[name] = trim($Guestbook[name]);
$Guestbook[town] = trim($Guestbook[town]);
$Guestbook[email] = trim($Guestbook[email]);
$Guestbook[website] = trim($Guestbook[website]);
$Guestbook[favsong] = trim($Guestbook[favsong]);
$Guestbook[comments] = trim($Guestbook[comments]);
$Guestbook[mailinglist] = trim($Guestbook[mailinglist]);
$Host = localhost;
$User = ;
$Password = *;
$DBName = blindtheory;
$TableName = guestbook;
$TableName2 = mailinglist;
$Pattern = .+@.+..+;
$Pattern2 = (http://)?([^[:space:]]+)([[:alnum:]\.,-_?/=]);
$Link = mysql_connect ($Host, $User, $Password);
$Query = INSERT into $TableName values('0', '$Guestbook[dateadd]',
'$Guestbook[name]', '$Guestbook[town]', '$Guestbook[email]',
'$Guestbook[website]','$Guestbook[favsong]', '$Guestbook[comments]');
$Link2 = mysql_connect ($Host, $User, $Password);
$Query2 = INSERT into $TableName2 values('0', '$Guestbook[dateadd]',
'$Guestbook[name]', '$Guestbook[email]');
if (mysql_db_query ($DBName, $Query, $Link)) {
echo Your entry will be added;
} else {
echo There was an error in during the posting, please contact
a
href=\mailto:[EMAIL PROTECTED]\;me/a and I will fix the
problem.br;
}
if (isset($Guestbook[mailinglist])) {
if (mysql_db_query ($DBName, $Query2, $Link2)) {
echo Your e-mail address was sucessfully added to our
mailinglist;
} else {
echo There was an error in during the posting, please
contact a
href=\mailto:[EMAIL PROTECTED]\;me/a and I will fix the
problem.br;
}
}
mysql_close ($Link);
mysql_close ($Link2);
?
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Re: [PHP] parse error
Thanks for that, yeah i should be more carefull before going to the list..
i'll watch out for it next time.
Jule
On Tuesday 30 April 2002 13:54, Miguel Cruz wrote:
You're missing a closing quote on the assignment for $Query2.
Come on people, keep your eyes open. This is basic stuff. Doesn't take
any special genius to count quotes and braces.
miguel
On Tue, 30 Apr 2002, Jule wrote:
Hey guys, i'm writing this guestbook script for my site, and i'm getting
a random parse error where i think everything is normal, it gives it on
line 26 which is
echo Your entry will be posted!;
my script follows
Jule
--SCRIPT--
?php
$Guestbook[dateadd] = date(F j, Y H:i:s);
$Guestbook[name] = trim($Guestbook[name]);
$Guestbook[town] = trim($Guestbook[town]);
$Guestbook[email] = trim($Guestbook[email]);
$Guestbook[website] = trim($Guestbook[website]);
$Guestbook[favsong] = trim($Guestbook[favsong]);
$Guestbook[comments] = trim($Guestbook[comments]);
$Guestbook[mailinglist] = trim($Guestbook[mailinglist]);
$Host = localhost;
$User = ;
$Password = *;
$DBName = blindtheory;
$TableName = guestbook;
$TableName2 = mailinglist;
$Pattern = .+@.+..+;
$Pattern2 = (http://)?([^[:space:]]+)([[:alnum:]\.,-_?/=]);
$Link = mysql_connect ($Host, $User, $Password);
$Query = INSERT into $TableName values('0', '$Guestbook[dateadd]',
'$Guestbook[name]', '$Guestbook[town]', '$Guestbook[email]',
'$Guestbook[website]','$Guestbook[favsong]', '$Guestbook[comments]');
$Link2 = mysql_connect ($Host, $User, $Password);
$Query2 = INSERT into $TableName2 values('0', '$Guestbook[dateadd]',
'$Guestbook[name]', '$Guestbook[email]');
if (mysql_db_query ($DBName, $Query, $Link)) {
echo Your entry will be added;
} else {
echo There was an error in during the posting, please contact
a
href=\mailto:[EMAIL PROTECTED]\;me/a and I will fix the
problem.br;
}
if (isset($Guestbook[mailinglist])) {
if (mysql_db_query ($DBName, $Query2, $Link2)) {
echo Your e-mail address was sucessfully added to our
mailinglist;
} else {
echo There was an error in during the posting, please
contact a
href=\mailto:[EMAIL PROTECTED]\;me/a and I will fix the
problem.br;
}
}
mysql_close ($Link);
mysql_close ($Link2);
?
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[PHP] sending data to two tables.
Hey,
This time it's not about missing quotes or parenthasies i hope.
I'm trying to make a form which sends name, email, website, favsong and
comments to table guestbook, but when the checkbox mailinglist is checked it
should send the name and email to table mailinglist, but it doesn;t seem to
work.
any pointers?
Jule
--SCRIPT--
?php
$Guestbook[dateadd] = date(F j, Y);
$Guestbook[name] = trim($Guestbook[name]);
$Guestbook[town] = trim($Guestbook[town]);
$Guestbook[email] = trim($Guestbook[email]);
$Guestbook[website] = trim($Guestbook[website]);
$Guestbook[favsong] = trim($Guestbook[favsong]);
$Guestbook[comments] = trim($Guestbook[comments]);
$Guestbook[mailinglist] = trim($Guestbook[mailinglist]);
$Host = localhost;
$User = ;
$Password = *;
$DBName = blindtheory;
$TableName = guestbook;
$TableName2 = mailinglist;
$Pattern = .+@.+..+;
$Pattern2 = (http://)?([^[:space:]]+)([[:alnum:]\.,-_?/=]);
$Link = mysql_connect ($Host, $User, $Password);
$Query = INSERT into $TableName values('0', '$Guestbook[dateadd]',
'$Guestbook[name]', '$Guestbook[town]', '$Guestbook[email]',
'$Guestbook[website]','$Guestbook[favsong]', '$Guestbook[comments]');
$Query2 = INSERT into $TableName2 values('0', '$Guestbook[dateadd]',
'$Guestbook[name]', '$Guestbook[email]');
if (mysql_db_query ($DBName, $Query, $Link)) {
echo Your entry will be addedbrClick a
href=../index.php?left=guestbookrighttop=guestbookrightbottom=guestbookrttitle=mailinglistrbtitle=gbaddhere/a
to go back.;
} else {
echo There was an error in during the posting, please contact
a
href=\mailto:[EMAIL PROTECTED]\;the webmaster/a and he will
fix the problem.br;
}
mysql_close ($Link);
if (isset($Guestbook[mailinglist])) {
if (mysql_db_query ($DBName, $Query2, $Link)) {
echo Your e-mail address was sucessfully added to our
mailinglist;
} else {
echo Your e-mail address will not be added to the
mailinglist;
}
}
mysql_close ($Link);
?
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Jule Slootbeek
[EMAIL PROTECTED]
http://blindtheory.cjb.net
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Re: [PHP] sending data to two tables.
I don't know, every time i submit the form w/ the checkbox checked. it gives me the echo string which comes when the if is not executed..it adds the entries from the form to the guestbook table, but doesn't add the name and email to the mailinglist table. it doesn't give me any php or mysql errors. Jule On Tuesday 30 April 2002 23:35, you wrote: On Wednesday 01 May 2002 07:34, Jule wrote: Hey, This time it's not about missing quotes or parenthasies i hope. I'm trying to make a form which sends name, email, website, favsong and comments to table guestbook, but when the checkbox mailinglist is checked it should send the name and email to table mailinglist, but it doesn;t seem to work. We're not physic! How doesn't it work? -- Jule Slootbeek [EMAIL PROTECTED] http://blindtheory.cjb.net -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] sending data to two tables.
So it executed the first if:
if (mysql_db_query ($DBName, $Query, $Link)) {
echo Your entry will be addedbrClick
a
href=../index.php?left=guestbookrighttop=guestbookrightbottom=guestbookrttitle=mailinglistrbtitle=gbaddhere/a
to go back.;
} else {
echo There was an error in during the posting,
please contact a
href=\mailto:[EMAIL PROTECTED]\;the webmaster/a and he will
fix the problem.br;
}
mysql_close ($Link);
but not the second one:
if (isset($Guestbook[mailinglist])) {
if (mysql_db_query ($DBName, $Query2, $Link)) {
echo Your e-mail address was sucessfully
added to our mailinglist;
} else {
echo Your e-mail address will not be added
to the mailinglist;
}
}
mysql_close ($Link);
and yes, i am sure the checkbox is checked.
Jule
On Tuesday 30 April 2002 23:43, you wrote:
I don't know, every time i submit the form w/ the checkbox checked. it
gives me the echo string which comes when the if is not executed..it adds
the entries from the form to the guestbook table, but doesn't add the name
and email to the mailinglist table. it doesn't give me any php or mysql
errors.
Jule
On Tuesday 30 April 2002 23:35, you wrote:
On Wednesday 01 May 2002 07:34, Jule wrote:
Hey,
This time it's not about missing quotes or parenthasies i hope.
I'm trying to make a form which sends name, email, website, favsong and
comments to table guestbook, but when the checkbox mailinglist is
checked it should send the name and email to table mailinglist, but it
doesn;t seem to work.
We're not physic! How doesn't it work?
--
Jule Slootbeek
[EMAIL PROTECTED]
http://blindtheory.cjb.net
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Re: [PHP] sending data to two tables.
Alright i'll take care of that, thanks a lot!
Jule
On Wednesday 01 May 2002 00:26, you wrote:
On Wednesday 01 May 2002 11:48, Jule wrote:
but not the second one:
if (isset($Guestbook[mailinglist])) {
You should be using:
if (isset($Guestbook['mailinglist'])) {
if (mysql_db_query ($DBName, $Query2, $Link)) {
echo Your e-mail address was
sucessfully added to our mailinglist;
} else {
echo Your e-mail address will not be
added to the mailinglist;
}
Are you saying that the else clause gets executed, so you get Your e-mail
address will not be added to the mailinglist?
If so then your error is within:
if (mysql_db_query ($DBName, $Query2, $Link))
Therefore:
1) add some error checking code -- see examples in manual and also
mysql_error().
2) echo your queries ($Query2)
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Jule Slootbeek
[EMAIL PROTECTED]
http://blindtheory.cjb.net
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[PHP] $server_path
Hey guys, i'm trying to write a script that gets a path for a pic from mysql and then shows the picture. so i added the data in teh database like so $server_path/pics/pic001.jpg and then when i get the final oputput the HTML says: img src=$server_path/pics/pic001.jpg and it won't show the picture, is this because i'm using Mozilla 0.9.9 or is it from something else? Jule -- Jule Slootbeek [EMAIL PROTECTED] http://blindtheory.cjb.net -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] variables
Hey guys, i have this script that changes pages in a table with the include() command, but i ran into trouble when i tried to change the pages by linking to index.php?left=theband because it would feed it to the index.php, but index.php would just change left back to news which is the default, how do i make it that it opens the theband page in stead of the default, and when i go to plain index.php the defaults come back? any help apreciated thanks Jule ---SCRIPT--- ?php $top = navbar; $left = news; $righttop = welcome; $rightbottom = pic; $toptitle = index; $lefttitle = index; $righttoptitle = index; $rightbottomtitle =index; $extention = .php; print (table border=0); print (tr); print (td align=center colspan=3); include ($top/$toptitle$extention); print (/td); print (/tr); print (tr); print (td rowspan=2 align=center width=40%); include ($left/$lefttitle$extention); print (/td); print (td align=center width=60% height=40%); include ($righttop/$title$righttoptitle$extention); print (/td); print (/tr); print (tr); print (td align=center width=60% height=55%); include (rightbottom/$rightbottomtitle$extention); print (/td); print (/tr); print (/table); ? ---SCRIPT--- -- Jule Slootbeek [EMAIL PROTECTED] http://blindtheory.cjb.net -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Images don't save
I'm not sure of it'll work, never tried it, but you might be able to show the pics using a Java applet..that way one cannot copy them. Jule. On Thursday 18 April 2002 14:17, Gunther E. Biernat typed on his or her keyboard, and sent me the following: You can't. Period. Simple as that. Oh, and BTW, it's not even a PHP question... On Thu, 18 Apr 2002 20:10:13 +0200, Manu Verhaegen wrote: Hi, You can right click on a image on your browser and choose save. I want to disable this option, how can i do this Greetings, Manu -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Regards, Gunther E. Biernat -- Jule Slootbeek [EMAIL PROTECTED] http://blindtheory.cjb.net -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] print on top
Hey guys and gals,
I'm writing this script for my new webpage, and i'm using MySQL to read and
add news articles to a page, but everytime i add a new article it puts it
under the older one, how can i get it on top?
thanks
Jule
$Link = mysql_connect ($Host, $User, $Password);
$Query = SELECT * from $TableName;
$Result = mysql_db_query ($DBName, $Query, $Link);
while ($Array = mysql_fetch_array ($Result)) {
print (table border=0 align=center valign=top width=100%);
print (tr align=center valign=top\n);
print (td align=left valign=topbi$Array[header]/i/b/td\n);
print (/tr\n);
print (tr align=center valign=top\n);
print (td align=left valign=top$Array[article]/td\n);
print (/tr\n);
print (tr align=center valign=top\n);
print (td align=right valign=topfont size=-2Posted by: $Array[name] on
$Array[postdate]/font/td\n);
print (/tr\n);
print (/table);
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Jule Slootbeek
[EMAIL PROTECTED]
http://blindtheory.cjb.net
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[PHP] variable question
Hey Guys and Gals, I'm writing this little script that takes two inputs: $name and $welcomemssg from a form and puts them in a text file. Now i only want to extract one of those variables open it with welcome.php, how do i go about this? when i just do fopen and fwrite it prints both variables. any thoughts? thanks, Jule -- Jule Slootbeek [EMAIL PROTECTED] http://blindtheory.cjb.net -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] variable question
Here's my code, teh $welcomemssg is one of the two variable store in
index.php the other one is $name
?php
$File = welcome/index.php;
$Open = fopen ($File, r);
if ($Open) {
print ($welcomemssg);
}
fclose ($Open);
?
Jule
On Monday 15 April 2002 13:49, you typed on your keyboard, and you sent me
the following:
On Tuesday 16 April 2002 00:41, Jule Slootbeek wrote:
Hey Guys and Gals,
I'm writing this little script that takes two inputs: $name and
$welcomemssg from a form and puts them in a text file. Now i only want to
extract one of those variables open it with welcome.php, how do i go
about this? when i just do fopen and fwrite it prints both variables.
any thoughts?
Show us your code.
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Jule Slootbeek
[EMAIL PROTECTED]
http://blindtheory.cjb.net
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