Re: [PHP] refernces, arrays, and why does it take up so much memory?
On 3 Sep 2013, at 02:30, Daevid Vincent dae...@daevid.com wrote:
I'm confused on how a reference works I think.
I have a DB result set in an array I'm looping over. All I simply want to do
is make the array key the id of the result set row.
This is the basic gist of it:
private function _normalize_result_set()
{
foreach($this-tmp_results as $k = $v)
{
$id = $v['id'];
$new_tmp_results[$id] = $v; //2013-08-29 [dv] using a
reference here cuts the memory usage in half!
You are assigning a reference to $v. In the next iteration of the loop, $v will
be pointing at the next item in the array, as will the reference you're storing
here. With this code I'd expect $new_tmp_results to be an array where the keys
(i.e. the IDs) are correct, but the data in each item matches the data in the
last item from the original array, which appears to be what you describe.
unset($this-tmp_results[$k]);
Doing this for every loop is likely very inefficient. I don't know how the
inner workings of PHP process something like this, but I wouldn't be surprised
if it's allocating a new chunk of memory for a version of the array without
this element. You may find it better to not unset anything until the loop has
finished, at which point you can just unset($this-tmp_results).
/*
if ($i++ % 1000 == 0)
{
gc_enable(); // Enable Garbage Collector
var_dump(gc_enabled()); // true
var_dump(gc_collect_cycles()); // # of elements
cleaned up
gc_disable(); // Disable Garbage Collector
}
*/
}
$this-tmp_results = $new_tmp_results;
//var_dump($this-tmp_results); exit;
unset($new_tmp_results);
}
Try this:
private function _normalize_result_set()
{
// Initialise the temporary variable.
$new_tmp_results = array();
// Loop around just the keys in the array.
foreach (array_keys($this-tmp_results) as $k)
{
// Store the item in the temporary array with the ID as the key.
// Note no pointless variable for the ID, and no use of !
$new_tmp_results[$this-tmp_results[$k]['id']] = $this-tmp_results[$k];
}
// Assign the temporary variable to the original variable.
$this-tmp_results = $new_tmp_results;
}
I'd appreciate it if you could plug this in and see what your memory usage
reports say. In most cases, trying to control the garbage collection through
the use of references is the worst way to go about optimising your code. In my
code above I'm relying on PHPs copy-on-write feature where data is only
duplicated when assigned if it changes. No unsets, just using scope to mark a
variable as able to be cleaned up.
Where is this result set coming from? You'd save yourself a lot of memory/time
by putting the data in to this format when you read it from the source. For
example, if reading it from MySQL, $this-tmp_results[$row['id']] = $row when
looping around the result set.
Also, is there any reason why you need to process this full set of data in one
go? Can you not break it up in to smaller pieces that won't put as much strain
on resources?
-Stuart
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RE: [PHP] refernces, arrays, and why does it take up so much memory? [SOLVED]
EUREKA!
-Original Message-
From: Stuart Dallas [mailto:stu...@3ft9.com]
Sent: Tuesday, September 03, 2013 6:31 AM
To: Daevid Vincent
Cc: php-general@lists.php.net
Subject: Re: [PHP] refernces, arrays, and why does it take up so much
memory?
On 3 Sep 2013, at 02:30, Daevid Vincent dae...@daevid.com wrote:
I'm confused on how a reference works I think.
I have a DB result set in an array I'm looping over. All I simply want
to
do
is make the array key the id of the result set row.
This is the basic gist of it:
private function _normalize_result_set()
{
foreach($this-tmp_results as $k = $v)
{
$id = $v['id'];
$new_tmp_results[$id] = $v; //2013-08-29 [dv] using
a
reference here cuts the memory usage in half!
You are assigning a reference to $v. In the next iteration of the loop, $v
will be pointing at the next item in the array, as will the reference
you're
storing here. With this code I'd expect $new_tmp_results to be an array
where the keys (i.e. the IDs) are correct, but the data in each item
matches
the data in the last item from the original array, which appears to be
what
you describe.
unset($this-tmp_results[$k]);
Doing this for every loop is likely very inefficient. I don't know how the
inner workings of PHP process something like this, but I wouldn't be
surprised if it's allocating a new chunk of memory for a version of the
array without this element. You may find it better to not unset anything
until the loop has finished, at which point you can just unset($this-
tmp_results).
/*
if ($i++ % 1000 == 0)
{
gc_enable(); // Enable Garbage Collector
var_dump(gc_enabled()); // true
var_dump(gc_collect_cycles()); // # of
elements
cleaned up
gc_disable(); // Disable Garbage Collector
}
*/
}
$this-tmp_results = $new_tmp_results;
//var_dump($this-tmp_results); exit;
unset($new_tmp_results);
}
Try this:
private function _normalize_result_set()
{
// Initialise the temporary variable.
$new_tmp_results = array();
// Loop around just the keys in the array.
foreach (array_keys($this-tmp_results) as $k)
{
// Store the item in the temporary array with the ID as the key.
// Note no pointless variable for the ID, and no use of !
$new_tmp_results[$this-tmp_results[$k]['id']] =
$this-tmp_results[$k];
}
// Assign the temporary variable to the original variable.
$this-tmp_results = $new_tmp_results;
}
I'd appreciate it if you could plug this in and see what your memory usage
reports say. In most cases, trying to control the garbage collection
through
the use of references is the worst way to go about optimising your code.
In
my code above I'm relying on PHPs copy-on-write feature where data is only
duplicated when assigned if it changes. No unsets, just using scope to
mark
a variable as able to be cleaned up.
Where is this result set coming from? You'd save yourself a lot of
memory/time by putting the data in to this format when you read it from
the
source. For example, if reading it from MySQL, $this-
tmp_results[$row['id']] = $row when looping around the result set.
Also, is there any reason why you need to process this full set of data in
one go? Can you not break it up in to smaller pieces that won't put as
much
strain on resources?
-Stuart
There were reasons I had the $id -- I only showed the relevant parts of the
code for sake of not overly complicating what I was trying to illustrate.
There is other processing that had to be done too in the loop and that is
also what I illustrated.
Here is your version effectively:
private function _normalize_result_set() //Stuart
{
if (!$this-tmp_results || count($this-tmp_results) 1)
return;
$new_tmp_results = array();
// Loop around just the keys in the array.
$D_start_mem_usage = memory_get_usage();
foreach (array_keys($this-tmp_results) as $k)
{
/*
if ($this-tmp_results[$k]['genres'])
{
// rip through each scene's `genres` and
store them as an array since we'll need'em later too
$g = explode('|',
$this-tmp_results[$k]['genres']);
array_pop($g); // there is an extra ''
element due to the final | character. :-\
$this-tmp_results[$k]['g'] = $g;
}
*/
// Store
Re: [PHP] refernces, arrays, and why does it take up so much memory? [SOLVED]
On 3 Sep 2013, at 21:47, Daevid Vincent dae...@daevid.com wrote:
There were reasons I had the $id -- I only showed the relevant parts of the
code for sake of not overly complicating what I was trying to illustrate.
There is other processing that had to be done too in the loop and that is
also what I illustrated.
Here is your version effectively:
private function _normalize_result_set() //Stuart
{
if (!$this-tmp_results || count($this-tmp_results) 1)
return;
$new_tmp_results = array();
// Loop around just the keys in the array.
$D_start_mem_usage = memory_get_usage();
foreach (array_keys($this-tmp_results) as $k)
{
You could save another, relatively small, chunk of memory by crafting your loop
with the rewind, key, current and next methods (look them up to see what they
do). Using those you won't need to make a copy of the array keys as done in the
above line. When you've got the amount of data you're dealing with it may be
worth investing that time.
/*
if ($this-tmp_results[$k]['genres'])
{
// rip through each scene's `genres` and
store them as an array since we'll need'em later too
$g = explode('|',
$this-tmp_results[$k]['genres']);
array_pop($g); // there is an extra ''
element due to the final | character. :-\
Then remove that from the string before you explode. Munging arrays is
expensive, both computationally and in terms of memory usage.
$this-tmp_results[$k]['g'] = $g;
Get rid of the temporary variable again - there's no need for it.
$this-tmp_results[$k]['g'] = explode('|',
trim($this-tmp_results[$k]['genres'], '|'));
If this is going in to a class, and you have control over how it's accessed,
you have the ability to do this when the value is accessed. This means you
won't need to
}
*/
// Store the item in the temporary array with the ID
as the key.
// Note no pointless variable for the ID, and no use of
!
$new_tmp_results[$this-tmp_results[$k]['id']] =
$this-tmp_results[$k];
}
// Assign the temporary variable to the original variable.
$this-tmp_results = $new_tmp_results;
echo \nMEMORY USED FOR STUART's version:
.number_format(memory_get_usage() - $D_start_mem_usage). PEAK:
(.number_format(memory_get_peak_usage(true)).)br\n;
var_dump($this-tmp_results);
exit();
}
MEMORY USED FOR STUART's version: -128 PEAK: (90,439,680)
With the processing in the genres block
MEMORY USED FOR STUART's version: 97,264,368 PEAK: (187,695,104)
So a slight improvement from the original of -28,573,696
MEMORY USED FOR _normalize_result_set(): 97,264,912 PEAK: (216,268,800)
Awesome.
No matter what I tried however it seems that frustratingly just the simple
act of adding a new hash to the array is causing a significant memory jump.
That really blows! Therefore my solution was to not store the $g as ['g'] --
which would seem to be the more efficient way of doing this once and re-use
the array over and over, but instead I am forced to inline rip through and
explode() in three different places of my code.
Consider what you're asking PHP to do. You're taking an element in the middle
of an array structure in memory and asking PHP to make it bigger. What's PHP
going to do? It's going to copy the entire array to a new location in memory
with an additional amount reserved for what you're adding. Note that this is
just a guess - it's entirely possible that PHP manages it's memory better than
that, but I wouldn't count on it.
We get over 30,000 hits per second, and even with lots of caching, 216MB vs
70-96MB is significant and the speed hit is only about 1.5 seconds more per
page.
Here are three distinctly different example pages that exercise different
parts of the code path:
PAGE RENDERED IN 7.0466279983521 SECONDS
MEMORY USED @START: 262,144 - @END: 26,738,688 = 26,476,544 BYTES
MEMORY PEAK USAGE: 69,730,304 BYTES
PAGE RENDERED IN 6.9327299594879 SECONDS
MEMORY USED @START: 262,144 - @END: 53,739,520 = 53,477,376 BYTES
MEMORY PEAK USAGE: 79,167,488 BYTES
PAGE RENDERED IN 7.55816092 SECONDS
MEMORY USED @START: 262,144 - @END: 50,855,936 = 50,593,792 BYTES
MEMORY PEAK USAGE: 96,206,848 BYTES
Knowing nothing about your application I'm obviously not in a strong position
to comment, but seven seconds to generate a page would be unacceptable to me
and any of my clients. I'll put money on it being possible to cut that time by
changing your caching strategy. The memory usage is also ridiculous - does a
single page really
RE: [PHP] refernces, arrays, and why does it take up so much memory? [SOLVED]
-Original Message-
From: Stuart Dallas [mailto:stu...@3ft9.com]
Sent: Tuesday, September 03, 2013 2:37 PM
To: Daevid Vincent
Cc: php-general@lists.php.net; 'Jim Giner'
Subject: Re: [PHP] refernces, arrays, and why does it take up so much
memory? [SOLVED]
On 3 Sep 2013, at 21:47, Daevid Vincent dae...@daevid.com wrote:
There were reasons I had the $id -- I only showed the relevant parts of
the
code for sake of not overly complicating what I was trying to
illustrate.
There is other processing that had to be done too in the loop and that
is
also what I illustrated.
Here is your version effectively:
private function _normalize_result_set() //Stuart
{
if (!$this-tmp_results || count($this-tmp_results) 1)
return;
$new_tmp_results = array();
// Loop around just the keys in the array.
$D_start_mem_usage = memory_get_usage();
foreach (array_keys($this-tmp_results) as $k)
{
You could save another, relatively small, chunk of memory by crafting your
loop with the rewind, key, current and next methods (look them up to see
what they do). Using those you won't need to make a copy of the array keys
as done in the above line. When you've got the amount of data you're
dealing
with it may be worth investing that time.
/*
if ($this-tmp_results[$k]['genres'])
{
// rip through each scene's `genres` and
store them as an array since we'll need'em later too
$g = explode('|',
$this-tmp_results[$k]['genres']);
array_pop($g); // there is an extra ''
element due to the final | character. :-\
Then remove that from the string before you explode.
Munging arrays is
expensive, both computationally and in terms of memory usage.
$this-tmp_results[$k]['g'] = $g;
Get rid of the temporary variable again - there's no need for it.
$this-tmp_results[$k]['g'] = explode('|', trim($this-
tmp_results[$k]['genres'], '|'));
Maybe an option. I'll look into trim() the last | off the tmp_results in a
loop at the top. Not sure if changing the variable will have the same effect
as adding one does. Interesting to see...
If this is going in to a class, and you have control over how it's
accessed,
you have the ability to do this when the value is accessed. This means you
won't need to
}
*/
// Store the item in the temporary array with the ID
as the key.
// Note no pointless variable for the ID, and no use of
!
$new_tmp_results[$this-tmp_results[$k]['id']] =
$this-tmp_results[$k];
}
// Assign the temporary variable to the original variable.
$this-tmp_results = $new_tmp_results;
echo \nMEMORY USED FOR STUART's version:
.number_format(memory_get_usage() - $D_start_mem_usage). PEAK:
(.number_format(memory_get_peak_usage(true)).)br\n;
var_dump($this-tmp_results);
exit();
}
MEMORY USED FOR STUART's version: -128 PEAK: (90,439,680)
With the processing in the genres block
MEMORY USED FOR STUART's version: 97,264,368 PEAK: (187,695,104)
So a slight improvement from the original of -28,573,696
MEMORY USED FOR _normalize_result_set(): 97,264,912 PEAK: (216,268,800)
Awesome.
No matter what I tried however it seems that frustratingly just the
simple
act of adding a new hash to the array is causing a significant memory
jump.
That really blows! Therefore my solution was to not store the $g as
['g']
--
which would seem to be the more efficient way of doing this once and re-
use
the array over and over, but instead I am forced to inline rip through
and
explode() in three different places of my code.
Consider what you're asking PHP to do. You're taking an element in the
middle of an array structure in memory and asking PHP to make it bigger.
What's PHP going to do? It's going to copy the entire array to a new
location in memory with an additional amount reserved for what you're
adding. Note that this is just a guess - it's entirely possible that PHP
manages it's memory better than that, but I wouldn't count on it.
We get over 30,000 hits per second, and even with lots of caching, 216MB
vs
70-96MB is significant and the speed hit is only about 1.5 seconds more
per
page.
Here are three distinctly different example pages that exercise
different
parts of the code path:
PAGE RENDERED IN 7.0466279983521 SECONDS
MEMORY USED @START: 262,144 - @END: 26,738,688 = 26,476,544 BYTES
MEMORY PEAK USAGE: 69,730,304 BYTES
PAGE RENDERED IN 6.9327299594879 SECONDS
MEMORY USED @START: 262,144 - @END: 53,739,520 = 53,477,376 BYTES
MEMORY PEAK
RE: [PHP] refernces, arrays, and why does it take up so much memory? [SOLVED]
-Original Message-
From: Daevid Vincent [mailto:dae...@daevid.com]
Sent: Tuesday, September 03, 2013 4:03 PM
To: php-general@lists.php.net
Cc: 'Stuart Dallas'
Subject: RE: [PHP] refernces, arrays, and why does it take up so much
memory? [SOLVED]
$this-tmp_results[$k]['g'] = explode('|', trim($this-
tmp_results[$k]['genres'], '|'));
Maybe an option. I'll look into trim() the last | off the tmp_results in
a
loop at the top. Not sure if changing the variable will have the same
effect
as adding one does. Interesting to see...
Here are the results of that. Interesting changes. Overall it's a slight
improvement, but most significant on the middle one, so still a worthy
keeper. Odd that it wouldn't be improvement across the board though. PHP is
kookie.
PAGE RENDERED IN 7.1903319358826 SECONDS
MEMORY USED @START: 262,144 - @END: 27,000,832 = 26,738,688 BYTES
MEMORY PEAK USAGE: 69,992,448 BYTES
PAGE RENDERED IN 6.5189208984375 SECONDS
MEMORY USED @START: 262,144 - @END: 42,729,472 = 42,467,328 BYTES
MEMORY PEAK USAGE: 78,905,344 BYTES
PAGE RENDERED IN 7.5954079627991 SECONDS
MEMORY USED @START: 262,144 - @END: 50,331,648 = 50,069,504 BYTES
MEMORY PEAK USAGE: 96,206,848 BYTES
Old.
PAGE RENDERED IN 7.0466279983521 SECONDS
MEMORY USED @START: 262,144 - @END: 26,738,688 = 26,476,544 BYTES
MEMORY PEAK USAGE: 69,730,304 BYTES
PAGE RENDERED IN 6.9327299594879 SECONDS
MEMORY USED @START: 262,144 - @END: 53,739,520 = 53,477,376 BYTES
MEMORY PEAK USAGE: 79,167,488 BYTES
PAGE RENDERED IN 7.55816092 SECONDS
MEMORY USED @START: 262,144 - @END: 50,855,936 = 50,593,792 BYTES
MEMORY PEAK USAGE: 96,206,848 BYTES
Re: [PHP] Re: PHP-5.5.2 +opcache segfaults with Piwik
Just so that you know, I've posted in the forum topic as well:
http://forum.piwik.org/read.php?2,105879
Regards,
Daniel Fenn
On Tue, Sep 3, 2013 at 12:42 AM, Lester Caine les...@lsces.co.uk wrote:
Jan Ehrhardt wrote:
Could you try to add a function_exists check to
libs/upgradephp/upgrade.php?
This at the function declaration of _json_encode:
if (!function_exists('_json_encode')) { function _json_encode($var, ...
And a extra } at the end.
This patch, together with upgrading to the latest OPcache from github
solved my segfaults and fatal errors.
Jan - could you post the solution on http://dev.piwik.org/trac/ticket/4093
- better that you get the credit than one of us pinch it ;)
--
Lester Caine - G8HFL
-
Contact - http://lsces.co.uk/wiki/?page=contact
L.S.Caine Electronic Services - http://lsces.co.uk
EnquirySolve - http://enquirysolve.com/
Model Engineers Digital Workshop - http://medw.co.uk
Rainbow Digital Media - http://rainbowdigitalmedia.co.uk
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php-general Digest 2 Sep 2013 08:57:25 -0000 Issue 8352
php-general Digest 2 Sep 2013 08:57:25 - Issue 8352
Topics (messages 322017 through 322020):
Re: PHP-5.5.2 +opcache segfaults with Piwik
322017 by: Lester Caine
322018 by: Jan Ehrhardt
322019 by: Jan Ehrhardt
322020 by: Jan Ehrhardt
Administrivia:
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---BeginMessage---
Grant wrote:
I've tried php-5.5.2 and 5.5.3 but both segfault with piwik unless the
opcache is disabled. Someone filed a piwik bug but was told it's a
php bug:
http://dev.piwik.org/trac/ticket/4093
Is this a known issue?
I'm running my own port of piwik in production with eaccelerator on 5.4 but I've
made the decision not to move any of the machines to 5.5 until all of the legacy
5.2 machines have been brought up to 5.4. Not an answer, but explains perhaps
why the problem is not being seen by others.
--
Lester Caine - G8HFL
-
Contact - http://lsces.co.uk/wiki/?page=contact
L.S.Caine Electronic Services - http://lsces.co.uk
EnquirySolve - http://enquirysolve.com/
Model Engineers Digital Workshop - http://medw.co.uk
Rainbow Digital Media - http://rainbowdigitalmedia.co.uk
---End Message---
---BeginMessage---
Lester Caine in php.general (Sun, 01 Sep 2013 12:59:18 +0100):
Grant wrote:
I've tried php-5.5.2 and 5.5.3 but both segfault with piwik unless the
opcache is disabled. Someone filed a piwik bug but was told it's a
php bug:
http://dev.piwik.org/trac/ticket/4093
Is this a known issue?
(...) Not an answer, but explains perhaps why the problem is not being
seen by others.
It is more likely that users do not notice it. I have Piwik running with
PHP 5.3 and php_opcache.dll (Centos 5) and it segfaults:
[Sun Sep 01 17:06:53.131410 2013] [core:notice] [pid 25411] AH00052:
child pid 25451 exit signal Segmentation fault (11)
[Sun Sep 01 17:08:18.561917 2013] [core:notice] [pid 25411] AH00052:
child pid 25453 exit signal Segmentation fault (11)
[Sun Sep 01 17:08:19.569714 2013] [core:notice] [pid 25411] AH00052:
child pid 25450 exit signal Segmentation fault (11)
However, nothing special is displaying on the page. You have to grep
your Apache error_log to know that it happens. How did you notice?
Jan
---End Message---
---BeginMessage---
Grant in php.general (Sun, 1 Sep 2013 02:13:54 -0700):
I've tried php-5.5.2 and 5.5.3 but both segfault with piwik unless the
opcache is disabled. Someone filed a piwik bug but was told it's a
php bug:
http://dev.piwik.org/trac/ticket/4093
Is this a known issue?
I changed the PHP on my (dev) Centos5 server to PHP 5.5.3, pulled the
latest OPcache from Github and tried to get a segfault. That was clearly
visible when I tried to access the Goals tab in the dashboard of one of
my websites. The page never got further than 'Loading data...' and my
Apache log showed a segfault.
So, if it was no known issue it is confirmed now.
Jan
---End Message---
---BeginMessage---
Grant in php.general (Sun, 25 Aug 2013 02:31:29 -0700):
I've tried php-5.5.2 and 5.5.3 but both segfault with piwik unless the
opcache is disabled. Someone filed a piwik bug but was told it's a
php bug:
http://dev.piwik.org/trac/ticket/4093
Could you try to add a function_exists check to
libs/upgradephp/upgrade.php?
This at the function declaration of _json_encode:
if (!function_exists('_json_encode')) { function _json_encode($var, ...
And a extra } at the end.
This seemed to correct this fatal error on my side:
[02-Sep-2013 10:35:40 Europe/Paris] PHP Fatal error: Cannot redeclare
_json_encode() (previously declared in
/usr/local/lib/php/share/piwik/libs/upgradephp/upgrade.php:109) in
/usr/local/lib/php/share/piwik/libs/upgradephp/upgrade.php on line 109
I do not know what opcache has to do with it, although I suspect that
Piwik is calling itself a lot of times and that opcache is trailing
behind (or something like that).
Jan
---End Message---
php-general Digest 3 Sep 2013 01:31:03 -0000 Issue 8353
php-general Digest 3 Sep 2013 01:31:03 - Issue 8353
Topics (messages 322021 through 322023):
Re: PHP-5.5.2 +opcache segfaults with Piwik
322021 by: Jan Ehrhardt
322022 by: Lester Caine
refernces, arrays, and why does it take up so much memory?
322023 by: Daevid Vincent
Administrivia:
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---BeginMessage---
Jan Ehrhardt in php.general (Mon, 02 Sep 2013 10:57:14 +0200):
Could you try to add a function_exists check to
libs/upgradephp/upgrade.php?
This at the function declaration of _json_encode:
if (!function_exists('_json_encode')) { function _json_encode($var, ...
And a extra } at the end.
This patch, together with upgrading to the latest OPcache from github
solved my segfaults and fatal errors.
Jan
---End Message---
---BeginMessage---
Jan Ehrhardt wrote:
Could you try to add a function_exists check to
libs/upgradephp/upgrade.php?
This at the function declaration of _json_encode:
if (!function_exists('_json_encode')) { function _json_encode($var, ...
And a extra } at the end.
This patch, together with upgrading to the latest OPcache from github
solved my segfaults and fatal errors.
Jan - could you post the solution on http://dev.piwik.org/trac/ticket/4093 -
better that you get the credit than one of us pinch it ;)
--
Lester Caine - G8HFL
-
Contact - http://lsces.co.uk/wiki/?page=contact
L.S.Caine Electronic Services - http://lsces.co.uk
EnquirySolve - http://enquirysolve.com/
Model Engineers Digital Workshop - http://medw.co.uk
Rainbow Digital Media - http://rainbowdigitalmedia.co.uk
---End Message---
---BeginMessage---
I'm confused on how a reference works I think.
I have a DB result set in an array I'm looping over. All I simply want to do
is make the array key the id of the result set row.
This is the basic gist of it:
private function _normalize_result_set()
{
foreach($this-tmp_results as $k = $v)
{
$id = $v['id'];
$new_tmp_results[$id] = $v; //2013-08-29 [dv] using a
reference here cuts the memory usage in half!
unset($this-tmp_results[$k]);
/*
if ($i++ % 1000 == 0)
{
gc_enable(); // Enable Garbage Collector
var_dump(gc_enabled()); // true
var_dump(gc_collect_cycles()); // # of elements
cleaned up
gc_disable(); // Disable Garbage Collector
}
*/
}
$this-tmp_results = $new_tmp_results;
//var_dump($this-tmp_results); exit;
unset($new_tmp_results);
}
Without using the = reference, my data works great:
$new_tmp_results[$id] = $v;
array (size=79552)
6904 =
array (size=4)
'id' = string '6904' (length=4)
'studio_id' = string '5' (length=1)
'genres' = string '34|' (length=3)
6905 =
array (size=4)
'id' = string '6905' (length=4)
'studio_id' = string '5' (length=1)
'genres' = string '6|37|' (length=5)
However it takes a stupid amount of memory for some unknown reason.
MEMORY USED @START: 262,144 - @END: 42,729,472 = 42,467,328 BYTES
MEMORY PEAK USAGE: 216,530,944 BYTES
When using the reference the memory drastically goes down to what I'd EXPECT
it to be (and actually the problem I'm trying to solve).
MEMORY USED @START: 262,144 - @END: 6,029,312 = 5,767,168 BYTES
MEMORY PEAK USAGE: 82,051,072 BYTES
However my array is all kinds of wrong:
array (size=79552)
6904 =
array (size=4)
'id' = string '86260' (length=5)
'studio_id' = string '210' (length=3)
'genres' = string '8|9|10|29|58|' (length=13)
6905 =
array (size=4)
'id' = string '86260' (length=5)
'studio_id' = string '210' (length=3)
'genres' = string '8|9|10|29|58|' (length=13)
Notice that they're all the same values, although the keys seem right. I
don't understand why that happens because
foreach($this-tmp_results as $k = $v)
Should be changing $v each iteration I'd think.
Honestly, I am baffled as to why those unsets() make no difference. All I
can think is that the garbage collector doesn't run. But then I had also
tried to force gc() and that still made no difference. *sigh*
I had some other cockamamie idea where I'd use the same tmp_results array in
a tricky way to avoid a second array. The concept being I'd add 1 million
to the ['id'] (which we want as the new array key), then unset the existing
sequential key, then when all done, loop through and shift all the keys by 1
[PHP] Re: PHP-5.5.2 +opcache segfaults with Piwik
Grant in php.general (Sun, 25 Aug 2013 02:31:29 -0700):
I've tried php-5.5.2 and 5.5.3 but both segfault with piwik unless the
opcache is disabled. Someone filed a piwik bug but was told it's a
php bug:
http://dev.piwik.org/trac/ticket/4093
Could you try to add a function_exists check to
libs/upgradephp/upgrade.php?
This at the function declaration of _json_encode:
if (!function_exists('_json_encode')) { function _json_encode($var, ...
And a extra } at the end.
This seemed to correct this fatal error on my side:
[02-Sep-2013 10:35:40 Europe/Paris] PHP Fatal error: Cannot redeclare
_json_encode() (previously declared in
/usr/local/lib/php/share/piwik/libs/upgradephp/upgrade.php:109) in
/usr/local/lib/php/share/piwik/libs/upgradephp/upgrade.php on line 109
I do not know what opcache has to do with it, although I suspect that
Piwik is calling itself a lot of times and that opcache is trailing
behind (or something like that).
Jan
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[PHP] Re: PHP-5.5.2 +opcache segfaults with Piwik
Jan Ehrhardt in php.general (Mon, 02 Sep 2013 10:57:14 +0200):
Could you try to add a function_exists check to
libs/upgradephp/upgrade.php?
This at the function declaration of _json_encode:
if (!function_exists('_json_encode')) { function _json_encode($var, ...
And a extra } at the end.
This patch, together with upgrading to the latest OPcache from github
solved my segfaults and fatal errors.
Jan
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Re: [PHP] Re: PHP-5.5.2 +opcache segfaults with Piwik
Jan Ehrhardt wrote:
Could you try to add a function_exists check to
libs/upgradephp/upgrade.php?
This at the function declaration of _json_encode:
if (!function_exists('_json_encode')) { function _json_encode($var, ...
And a extra } at the end.
This patch, together with upgrading to the latest OPcache from github
solved my segfaults and fatal errors.
Jan - could you post the solution on http://dev.piwik.org/trac/ticket/4093 -
better that you get the credit than one of us pinch it ;)
--
Lester Caine - G8HFL
-
Contact - http://lsces.co.uk/wiki/?page=contact
L.S.Caine Electronic Services - http://lsces.co.uk
EnquirySolve - http://enquirysolve.com/
Model Engineers Digital Workshop - http://medw.co.uk
Rainbow Digital Media - http://rainbowdigitalmedia.co.uk
--
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[PHP] refernces, arrays, and why does it take up so much memory?
: 8,050,456 PEAK: (78,118,912) MEMORY USED FOR array_combine: 8,050,376 PEAK: (86,507,520) Just as a wild guess, I also added 'g' to my SQL so that PHP would already have a placeholder variable there in tmp_results, but that made no difference. And still used up nearly double the memory as above. SELECT DISTINCT `id`, sag.`genres`, 'g' FROM.
[PHP] Re: refernces, arrays, and why does it take up so much memory?
the $this-tmp_results[$k]['g'] = $g; Results in MEMORY USED BEFORE array_combine: 8,050,456 PEAK: (78,118,912) MEMORY USED FOR array_combine: 8,050,376 PEAK: (86,507,520) Just as a wild guess, I also added 'g' to my SQL so that PHP would already have a placeholder variable there in tmp_results, but that made no difference. And still used up nearly double the memory as above. SELECT DISTINCT `id`, sag.`genres`, 'g' FROM. Are you sure that the data is what you expect? I've never used an object to hold the results of a query, but I'm picturing that your foreach may not be working at all unless an object as a result is totally different than the type of query results I always process. You're taking each object of the query results and assigning the key and value to vars. But aren't query results 'keyless'? So what are you actually assigning to $k and $v? If I'm wrong and using an object is quite different, forget I said anything. :) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Re: refernces, arrays, and why does it take up so much memory?
-Original Message-
From: Jim Giner [mailto:jim.gi...@albanyhandball.com]
Sent: Monday, September 02, 2013 8:14 PM
To: php-general@lists.php.net
Subject: [PHP] Re: refernces, arrays, and why does it take up so much
memory?
On 9/2/2013 9:30 PM, Daevid Vincent wrote:
I'm confused on how a reference works I think.
I have a DB result set in an array I'm looping over. All I simply want
to
do
is make the array key the id of the result set row.
This is the basic gist of it:
private function _normalize_result_set()
{
foreach($this-tmp_results as $k = $v)
{
$id = $v['id'];
$new_tmp_results[$id] = $v; //2013-08-29 [dv]
using
a
reference here cuts the memory usage in half!
unset($this-tmp_results[$k]);
/*
if ($i++ % 1000 == 0)
{
gc_enable(); // Enable Garbage Collector
var_dump(gc_enabled()); // true
var_dump(gc_collect_cycles()); // # of
elements
cleaned up
gc_disable(); // Disable Garbage Collector
}
*/
}
$this-tmp_results = $new_tmp_results;
//var_dump($this-tmp_results); exit;
unset($new_tmp_results);
}
Without using the = reference, my data works great:
$new_tmp_results[$id] = $v;
array (size=79552)
6904 =
array (size=4)
'id' = string '6904' (length=4)
'studio_id' = string '5' (length=1)
'genres' = string '34|' (length=3)
6905 =
array (size=4)
'id' = string '6905' (length=4)
'studio_id' = string '5' (length=1)
'genres' = string '6|37|' (length=5)
However it takes a stupid amount of memory for some unknown reason.
MEMORY USED @START: 262,144 - @END: 42,729,472 = 42,467,328 BYTES
MEMORY PEAK USAGE: 216,530,944 BYTES
When using the reference the memory drastically goes down to what I'd
EXPECT
it to be (and actually the problem I'm trying to solve).
MEMORY USED @START: 262,144 - @END: 6,029,312 = 5,767,168 BYTES
MEMORY PEAK USAGE: 82,051,072 BYTES
However my array is all kinds of wrong:
array (size=79552)
6904 =
array (size=4)
'id' = string '86260' (length=5)
'studio_id' = string '210' (length=3)
'genres' = string '8|9|10|29|58|' (length=13)
6905 =
array (size=4)
'id' = string '86260' (length=5)
'studio_id' = string '210' (length=3)
'genres' = string '8|9|10|29|58|' (length=13)
Notice that they're all the same values, although the keys seem right. I
don't understand why that happens because
foreach($this-tmp_results as $k = $v)
Should be changing $v each iteration I'd think.
Honestly, I am baffled as to why those unsets() make no difference. All
I
can think is that the garbage collector doesn't run. But then I had also
tried to force gc() and that still made no difference. *sigh*
I had some other cockamamie idea where I'd use the same tmp_results
array
in
a tricky way to avoid a second array. The concept being I'd add 1
million
to the ['id'] (which we want as the new array key), then unset the
existing
sequential key, then when all done, loop through and shift all the keys
by
1
million thereby they'd be the right index ID. So add one and unset one
immediately after. Clever right? 'cept it too made no difference on
memory.
Same thing is happening as above where the gc() isn't running or
something
is holding all that memory until the end. *sigh*
Then I tried a different way using array_combine() and noticed something
very disturbing.
http://www.php.net/manual/en/function.array-combine.php
private function _normalize_result_set()
{
if (!$this-tmp_results || count($this-tmp_results) 1)
return;
$D_start_mem_usage = memory_get_usage();
foreach($this-tmp_results as $k = $v)
{
$id = $v['id'];
$tmp_keys[] = $id;
if ($v['genres'])
{
$g = explode('|', $v['genres']);
$this-tmp_results[$k]['g'] = $g; //this
causes a
massive spike in memory usage
}
}
//var_dump($tmp_keys, $this-tmp_results); exit;
echo \nMEMORY USED BEFORE array_combine:
.number_format(memory_get_usage() - $D_start_mem_usage). PEAK:
(.number_format(memory_get_peak_usage(true)).)br\n;
$this-tmp_results = array_combine($tmp_keys,
$this-tmp_results);
echo \nMEMORY USED
php-general Digest 1 Sep 2013 09:14:01 -0000 Issue 8351
php-general Digest 1 Sep 2013 09:14:01 - Issue 8351 Topics (messages 322016 through 322016): Re: PHP-5.5.2 +opcache segfaults with Piwik 322016 by: Grant Administrivia: To subscribe to the digest, e-mail: php-general-digest-subscr...@lists.php.net To unsubscribe from the digest, e-mail: php-general-digest-unsubscr...@lists.php.net To post to the list, e-mail: php-gene...@lists.php.net -- ---BeginMessage--- I've tried php-5.5.2 and 5.5.3 but both segfault with piwik unless the opcache is disabled. Someone filed a piwik bug but was told it's a php bug: http://dev.piwik.org/trac/ticket/4093 - Grant Is this a known issue? - Grant ---End Message---
[PHP] Re: PHP-5.5.2 +opcache segfaults with Piwik
I've tried php-5.5.2 and 5.5.3 but both segfault with piwik unless the opcache is disabled. Someone filed a piwik bug but was told it's a php bug: http://dev.piwik.org/trac/ticket/4093 - Grant Is this a known issue? - Grant -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: PHP-5.5.2 +opcache segfaults with Piwik
Grant wrote: I've tried php-5.5.2 and 5.5.3 but both segfault with piwik unless the opcache is disabled. Someone filed a piwik bug but was told it's a php bug: http://dev.piwik.org/trac/ticket/4093 Is this a known issue? I'm running my own port of piwik in production with eaccelerator on 5.4 but I've made the decision not to move any of the machines to 5.5 until all of the legacy 5.2 machines have been brought up to 5.4. Not an answer, but explains perhaps why the problem is not being seen by others. -- Lester Caine - G8HFL - Contact - http://lsces.co.uk/wiki/?page=contact L.S.Caine Electronic Services - http://lsces.co.uk EnquirySolve - http://enquirysolve.com/ Model Engineers Digital Workshop - http://medw.co.uk Rainbow Digital Media - http://rainbowdigitalmedia.co.uk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: PHP-5.5.2 +opcache segfaults with Piwik
Lester Caine in php.general (Sun, 01 Sep 2013 12:59:18 +0100): Grant wrote: I've tried php-5.5.2 and 5.5.3 but both segfault with piwik unless the opcache is disabled. Someone filed a piwik bug but was told it's a php bug: http://dev.piwik.org/trac/ticket/4093 Is this a known issue? (...) Not an answer, but explains perhaps why the problem is not being seen by others. It is more likely that users do not notice it. I have Piwik running with PHP 5.3 and php_opcache.dll (Centos 5) and it segfaults: [Sun Sep 01 17:06:53.131410 2013] [core:notice] [pid 25411] AH00052: child pid 25451 exit signal Segmentation fault (11) [Sun Sep 01 17:08:18.561917 2013] [core:notice] [pid 25411] AH00052: child pid 25453 exit signal Segmentation fault (11) [Sun Sep 01 17:08:19.569714 2013] [core:notice] [pid 25411] AH00052: child pid 25450 exit signal Segmentation fault (11) However, nothing special is displaying on the page. You have to grep your Apache error_log to know that it happens. How did you notice? Jan -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: PHP-5.5.2 +opcache segfaults with Piwik
Grant in php.general (Sun, 1 Sep 2013 02:13:54 -0700): I've tried php-5.5.2 and 5.5.3 but both segfault with piwik unless the opcache is disabled. Someone filed a piwik bug but was told it's a php bug: http://dev.piwik.org/trac/ticket/4093 Is this a known issue? I changed the PHP on my (dev) Centos5 server to PHP 5.5.3, pulled the latest OPcache from Github and tried to get a segfault. That was clearly visible when I tried to access the Goals tab in the dashboard of one of my websites. The page never got further than 'Loading data...' and my Apache log showed a segfault. So, if it was no known issue it is confirmed now. Jan -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
php-general Digest 30 Aug 2013 21:00:13 -0000 Issue 8350
php-general Digest 30 Aug 2013 21:00:13 - Issue 8350 Topics (messages 322015 through 322015): Strange url session behavior after upgrade to 4.3 322015 by: Tobiah Administrivia: To subscribe to the digest, e-mail: php-general-digest-subscr...@lists.php.net To unsubscribe from the digest, e-mail: php-general-digest-unsubscr...@lists.php.net To post to the list, e-mail: php-gene...@lists.php.net -- ---BeginMessage--- I have a page that needs to get another page on the fly, using the same session. I figured out how to stop my session and set the cookie on the CURL handler, and everything was cool. The curled page had my same session available as the calling page. Life was good. Now something has changed after upgrading from 5.2.4 to 5.3.10. My session was no longer available on the curled page. What's strange is that the PHPSESSID cookie was still being set, and hit had the correct value. Here is the weirdest part. If I do this: session_id($_COOKIE['PHPSESSID']); session_start(); The session is there! But why isn't php taking the cookie as the id all by itself? Regular pages (not curled) all work as before. All of our websites work fine on the new version, except for this one curl call. I could update 100's of websites to fix them with the added lines, but I'd really rather find out why the curled page is not taking the session_id from the PHPSESSID cookie. Thanks! Toby ---End Message---
[PHP] Strange url session behavior after upgrade to 4.3
I have a page that needs to get another page on the fly, using the same session. I figured out how to stop my session and set the cookie on the CURL handler, and everything was cool. The curled page had my same session available as the calling page. Life was good. Now something has changed after upgrading from 5.2.4 to 5.3.10. My session was no longer available on the curled page. What's strange is that the PHPSESSID cookie was still being set, and hit had the correct value. Here is the weirdest part. If I do this: session_id($_COOKIE['PHPSESSID']); session_start(); The session is there! But why isn't php taking the cookie as the id all by itself? Regular pages (not curled) all work as before. All of our websites work fine on the new version, except for this one curl call. I could update 100's of websites to fix them with the added lines, but I'd really rather find out why the curled page is not taking the session_id from the PHPSESSID cookie. Thanks! Toby -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
php-general Digest 29 Aug 2013 23:30:10 -0000 Issue 8349
php-general Digest 29 Aug 2013 23:30:10 - Issue 8349 Topics (messages 322012 through 322014): Re: Basic Auth 322012 by: Jim Giner 322013 by: Stuart Dallas IMAP Metadata support 322014 by: list.airstreamcomm.net Administrivia: To subscribe to the digest, e-mail: php-general-digest-subscr...@lists.php.net To unsubscribe from the digest, e-mail: php-general-digest-unsubscr...@lists.php.net To post to the list, e-mail: php-gene...@lists.php.net -- ---BeginMessage--- Stuart, Just wanted to follow up with my thanks for your excellent help in providing understanding of how to generate the 401 error page and getting me thru the process of performing a sign-out from basic auth. Without your patience it never would have happened. Also wanted to tell you that I've scrapped it all. Keeping the code for a rainy day of course, but giving up on using it (as well as the basic auth signon process) to use my own 'roll-your-own' code. Since IE insisted on presenting multiple credentials during the signon process it was a futile effort to be doing a signoff. And yes - I've taken the proper precautions to hash the incoming password value before submission and storing in my db that way. Thanks again. It's help like this that makes this group such a great resource. ---End Message--- ---BeginMessage--- On 27 Aug 2013, at 18:45, Jim Giner jim.gi...@albanyhandball.com wrote: From your latest missive I gleaned that I needed to have a script on my server One last time: YOU DON'T NEED TO CHANGE ANYTHING ON THE SERVER-SIDE! Ok, I see that you've decided to use another method, which is great; HTTP auth is a pretty antiquated way to handle authentication these days. Whatever you're using, I wish you all the best with it. -Stuart -- Stuart Dallas 3ft9 Ltd http://3ft9.com/---End Message--- ---BeginMessage--- Does PHP IMAP have any support for Metadata? Thanks. ---End Message---
[PHP] IMAP Metadata support
Does PHP IMAP have any support for Metadata? Thanks. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
php-general Digest 28 Aug 2013 10:15:58 -0000 Issue 8348
php-general Digest 28 Aug 2013 10:15:58 - Issue 8348 Topics (messages 322011 through 322011): Re: php seg faults on creation pdf 322011 by: KAs Coenen Administrivia: To subscribe to the digest, e-mail: php-general-digest-subscr...@lists.php.net To unsubscribe from the digest, e-mail: php-general-digest-unsubscr...@lists.php.net To post to the list, e-mail: php-gene...@lists.php.net -- ---BeginMessage--- Hi, Some more info. I ran gdb on the core file (after reinstalling with debug mode): # /usr/local/gdb/bin/gdb /usr/local/php5/bin/php-cgi /opt/apache/htdocs/wachtlijst/core GNU gdb (GDB) 7.6 Copyright (C) 2013 Free Software Foundation, Inc. License GPLv3+: GNU GPL version 3 or later http://gnu.org/licenses/gpl.html This is free software: you are free to change and redistribute it. There is NO WARRANTY, to the extent permitted by law. Type show copying and show warranty for details. This GDB was configured as i386-pc-solaris2.10. For bug reporting instructions, please see: http://www.gnu.org/software/gdb/bugs/... Reading symbols from /usr/local/php5/bin/php-cgi...done. [New LWP 1] [Thread debugging using libthread_db enabled] [New Thread 1 (LWP 1)] Core was generated by `/usr/local/php5/bin/php-cgi /opt/apache/htdocs/wachtlijst/test.php'. Program terminated with signal 11, Segmentation fault. #0 0x0093baa4 in _object_and_properties_init (arg=error reading variable: Cannot access memory at address 0xffd8, arg@entry=error reading variable: Cannot access memory at address 0x8, class_type=error reading variable: Cannot access memory at address 0xffd0, class_type@entry=error reading variable: Cannot access memory at address 0x8, properties=error reading variable: Cannot access memory at address 0xffc8, properties@entry=error reading variable: Cannot access memory at address 0x8) at /export/home/coenenka/php-5.5.1/Zend/zend_API.c:1200 1200 Z_OBJVAL_P(arg) = class_type-create_object(class_type TSRMLS_CC); Does anyone see anything in this? The dir /export/home/coenenka is not the install dir (but my home drive) and I have no clue why it is referencing to that dir (it is the location of the source). Greetings, Kas From: kascoe...@hotmail.com To: php-gene...@lists.php.net Subject: php seg faults on creation pdf Date: Wed, 28 Aug 2013 10:00:29 +0200 Hi, When surfing to a website that generates a pdf the apache server segfaults. This made me run the script (that generates the pdf) with the php cli command. The php also segfaults with the same error: # /usr/local/php5/bin/php-cgi test.php Segmentation Fault (core dumped) Pstack output: # pstack core core 'core' of 726: /usr/local/php5/bin/php-cgi test.php 00960af5 _object_and_properties_init () + 111 I attached the truss output to the mail. I am running this on a solaris server: # uname -a SunOS zone-eu4 5.10 Generic_142910-17 i86pc i386 i86pc # cat /etc/release Oracle Solaris 10 9/10 s10x_u9wos_14a X86 Copyright (c) 2010, Oracle and/or its affiliates. All rights reserved. Assembled 11 August 2010 pdflib module is 2.1.10. PDFlib lite is version 7.0.5. I tried to compile everything in 64 bit. I suspect the problem is that somewhere a 32bit lib or executable is being used instead of a 64bit. Can anyone help me out on this? Kind regards, Kas ---End Message---
[PHP] RE: php seg faults on creation pdf
Hi, Some more info. I ran gdb on the core file (after reinstalling with debug mode): # /usr/local/gdb/bin/gdb /usr/local/php5/bin/php-cgi /opt/apache/htdocs/wachtlijst/core GNU gdb (GDB) 7.6 Copyright (C) 2013 Free Software Foundation, Inc. License GPLv3+: GNU GPL version 3 or later http://gnu.org/licenses/gpl.html This is free software: you are free to change and redistribute it. There is NO WARRANTY, to the extent permitted by law. Type show copying and show warranty for details. This GDB was configured as i386-pc-solaris2.10. For bug reporting instructions, please see: http://www.gnu.org/software/gdb/bugs/... Reading symbols from /usr/local/php5/bin/php-cgi...done. [New LWP 1] [Thread debugging using libthread_db enabled] [New Thread 1 (LWP 1)] Core was generated by `/usr/local/php5/bin/php-cgi /opt/apache/htdocs/wachtlijst/test.php'. Program terminated with signal 11, Segmentation fault. #0 0x0093baa4 in _object_and_properties_init (arg=error reading variable: Cannot access memory at address 0xffd8, arg@entry=error reading variable: Cannot access memory at address 0x8, class_type=error reading variable: Cannot access memory at address 0xffd0, class_type@entry=error reading variable: Cannot access memory at address 0x8, properties=error reading variable: Cannot access memory at address 0xffc8, properties@entry=error reading variable: Cannot access memory at address 0x8) at /export/home/coenenka/php-5.5.1/Zend/zend_API.c:1200 1200 Z_OBJVAL_P(arg) = class_type-create_object(class_type TSRMLS_CC); Does anyone see anything in this? The dir /export/home/coenenka is not the install dir (but my home drive) and I have no clue why it is referencing to that dir (it is the location of the source). Greetings, Kas From: kascoe...@hotmail.com To: php-general@lists.php.net Subject: php seg faults on creation pdf Date: Wed, 28 Aug 2013 10:00:29 +0200 Hi, When surfing to a website that generates a pdf the apache server segfaults. This made me run the script (that generates the pdf) with the php cli command. The php also segfaults with the same error: # /usr/local/php5/bin/php-cgi test.php Segmentation Fault (core dumped) Pstack output: # pstack core core 'core' of 726: /usr/local/php5/bin/php-cgi test.php 00960af5 _object_and_properties_init () + 111 I attached the truss output to the mail. I am running this on a solaris server: # uname -a SunOS zone-eu4 5.10 Generic_142910-17 i86pc i386 i86pc # cat /etc/release Oracle Solaris 10 9/10 s10x_u9wos_14a X86 Copyright (c) 2010, Oracle and/or its affiliates. All rights reserved. Assembled 11 August 2010 pdflib module is 2.1.10. PDFlib lite is version 7.0.5. I tried to compile everything in 64 bit. I suspect the problem is that somewhere a 32bit lib or executable is being used instead of a 64bit. Can anyone help me out on this? Kind regards, Kas -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Basic Auth
Stuart, Just wanted to follow up with my thanks for your excellent help in providing understanding of how to generate the 401 error page and getting me thru the process of performing a sign-out from basic auth. Without your patience it never would have happened. Also wanted to tell you that I've scrapped it all. Keeping the code for a rainy day of course, but giving up on using it (as well as the basic auth signon process) to use my own 'roll-your-own' code. Since IE insisted on presenting multiple credentials during the signon process it was a futile effort to be doing a signoff. And yes - I've taken the proper precautions to hash the incoming password value before submission and storing in my db that way. Thanks again. It's help like this that makes this group such a great resource. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Basic Auth
On 27 Aug 2013, at 18:45, Jim Giner jim.gi...@albanyhandball.com wrote: From your latest missive I gleaned that I needed to have a script on my server One last time: YOU DON'T NEED TO CHANGE ANYTHING ON THE SERVER-SIDE! Ok, I see that you've decided to use another method, which is great; HTTP auth is a pretty antiquated way to handle authentication these days. Whatever you're using, I wish you all the best with it. -Stuart -- Stuart Dallas 3ft9 Ltd http://3ft9.com/
php-general Digest 27 Aug 2013 06:45:12 -0000 Issue 8346
php-general Digest 27 Aug 2013 06:45:12 - Issue 8346
Topics (messages 321971 through 321985):
Re: exec and system do not work
321971 by: Jim Giner
321973 by: marco.behnke.biz
321976 by: Tamara Temple
321978 by: Ethan Rosenberg, PhD
321979 by: Tim Streater
321980 by: David Robley
321981 by: Ethan Rosenberg, PhD
321982 by: Jasper Kips
321983 by: David Robley
How to send post-variables in a Location header
321972 by: Ajay Garg
321974 by: marco.behnke.biz
321975 by: Matijn Woudt
321977 by: Tamara Temple
Permissions
321984 by: Ethan Rosenberg, PhD
321985 by: David Robley
Administrivia:
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---BeginMessage---
On 8/26/2013 2:41 PM, Ethan Rosenberg wrote:
On 08/26/2013 11:36 AM, ma...@behnke.biz wrote:
Tamara Temple tamouse.li...@gmail.com hat am 26. August 2013 um 08:33
geschrieben:
On Aug 25, 2013, at 10:41 PM, Ethan Rosenberg
erosenb...@hygeiabiomedical.com wrote:
Dear List -
I'm lost on this one -
This works -
$out = system(ls -l ,$retvals);
printf(%s, $out);
This does -
echo exec(ls -l);
Please show the output of the directory listing.
Please us ls -la
This does not -
if( !file_exists(/var/www/orders.txt));
{
$out = system(touch /var/www/orders.txt, $ret);
Maybe you don't have write permissions on the folder?
$out2 = system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
and this does not -
if( !file_exists(/var/www/orders.txt));
{
exec(touch /var/www/orders.txt);
exec(chmod 766 /var/www/orders.txt);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
Ethan
When you say does not work, can you show what is actually not
working? I
believe the exec and system functions are likely working just fine,
but that
the commands you've passed to them may not be.
--
Marco Behnke
Dipl. Informatiker (FH), SAE Audio Engineer Diploma
Zend Certified Engineer PHP 5.3
Tel.: 0174 / 9722336
e-Mail: ma...@behnke.biz
Softwaretechnik Behnke
Heinrich-Heine-Str. 7D
21218 Seevetal
http://www.behnke.biz
Tamara -
Please show the output of the directory listing.
Please us ls -la
echo exec('ls -la orders.txt');
-rw-rw-rw- 1 ethan ethan 43 Aug 25 23:50 orders.txt
Maybe you don't have write permissions on the folder?
If I perform the touch and chmod from the command line, everything works.
When you say does not work, can you show what is actually not
working? I
believe the exec and system functions are likely working just fine,
but that
the commands you've passed to them may not be.
Here are my commands.
if( !file_exists(/var/www/orders.txt));
{
echo system(touch /var/www/orders.txt, $ret);
echo system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
If I now try a ls from the command line, the return is
cannot access /var/www/orders.txt: No such file or directory
The ls -la works because the file was created from the command line.
TIA
Ethan
Ethan - YOU'RE DOING IT AGAIN!!!
Either you are not using error checking AGAIN!!
OR
You are showing us re-typed in code that YOU DIDNT ACTUALLY RUN.
I've told you multiple times that you need to do these two things and
you are back at it again.
The sample php above has plain simple syntax errors that would keep it
from running, which error checking would tell you IF YOU RAN IT.
---End Message---
---BeginMessage---
Ethan Rosenberg erosenb...@hygeiabiomedical.com hat am 26. August 2013 um
20:41 geschrieben:
Please show the output of the directory listing.
Please us ls -la
echo exec('ls -la orders.txt');
-rw-rw-rw- 1 ethan ethan 43 Aug 25 23:50 orders.txt
Please supply the complete output. Especially the rights for . and ..
Maybe you don't have write permissions on the folder?
If I perform the touch and chmod from the command line, everything works.
cli and ww are different users.
---End Message---
---BeginMessage---
On Aug 26, 2013, at 1:41 PM, Ethan Rosenberg erosenb...@hygeiabiomedical.com
wrote:
On 08/26/2013 11:36 AM, ma...@behnke.biz wrote:
Tamara Temple tamouse.li...@gmail.com hat am 26. August 2013 um 08:33
geschrieben:
On Aug 25, 2013, at 10:41 PM, Ethan Rosenberg
erosenb...@hygeiabiomedical.com wrote:
Dear List -
I'm lost on this one -
This works -
$out = system(ls -l ,$retvals);
printf(%s, $out);
This does -
echo exec(ls -l);
Please show the output of the directory listing.
Please us ls -la
This does not -
if( !file_exists(/var/www/orders.txt));
{
$out = system(touch /var/www
[PHP] Re: Permissions
Ethan Rosenberg wrote: Dear List - Tried to run the program, that we have been discussing, and received a 403 error. rosenberg:/var/www# ls -la StoreInventory.php -rwxrwxrw- 1 ethan ethan 4188 Aug 26 20:26 StoreInventory.php rosenberg:/var# ls -ld www drwxrwxrw- 37 ethan ethan 20480 Aug 26 20:26 www I had set the S bit [probably a nasty mistake] and I thought I was able to remove the bit. [it doesn't show above] How do I extricate myself from the hole into which I have planted myself? TIA Ethan This is in no way a php question, as the same result will happen no matter what you ask apache to serve from that directory. You have the directory permissions set to 776 not 777. -- Cheers David Robley Steal this tagline and I'll tie-dye your cat! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Permissions
On Tue, 2013-08-27 at 16:16 +0930, David Robley wrote: Ethan Rosenberg wrote: Dear List - Tried to run the program, that we have been discussing, and received a 403 error. rosenberg:/var/www# ls -la StoreInventory.php -rwxrwxrw- 1 ethan ethan 4188 Aug 26 20:26 StoreInventory.php rosenberg:/var# ls -ld www drwxrwxrw- 37 ethan ethan 20480 Aug 26 20:26 www I had set the S bit [probably a nasty mistake] and I thought I was able to remove the bit. [it doesn't show above] How do I extricate myself from the hole into which I have planted myself? TIA Ethan This is in no way a php question, as the same result will happen no matter what you ask apache to serve from that directory. You have the directory permissions set to 776 not 777. -- Cheers David Robley Steal this tagline and I'll tie-dye your cat! 776 won't matter in the case of a directory, as the last bit is for the eXecute permissions, which aren't applicable to a directory. What It's possible that this is an SELinux issue, which adds an extra layer of permissions over files. To see what those permissions are, use the -Z flag for ls. Also, check the SELinux logs (assuming that it's running and it is causing a problem) to see if it brings up anything. It's typically found on RedHat-based distros. Thanks, Ash http://www.ashleysheridan.co.uk
Re: [PHP] Re: Permissions
Ashley Sheridan wrote: On Tue, 2013-08-27 at 16:16 +0930, David Robley wrote: Ethan Rosenberg wrote: Dear List - Tried to run the program, that we have been discussing, and received a 403 error. rosenberg:/var/www# ls -la StoreInventory.php -rwxrwxrw- 1 ethan ethan 4188 Aug 26 20:26 StoreInventory.php rosenberg:/var# ls -ld www drwxrwxrw- 37 ethan ethan 20480 Aug 26 20:26 www I had set the S bit [probably a nasty mistake] and I thought I was able to remove the bit. [it doesn't show above] How do I extricate myself from the hole into which I have planted myself? TIA Ethan This is in no way a php question, as the same result will happen no matter what you ask apache to serve from that directory. You have the directory permissions set to 776 not 777. -- Cheers David Robley Steal this tagline and I'll tie-dye your cat! 776 won't matter in the case of a directory, as the last bit is for the eXecute permissions, which aren't applicable to a directory. What I beg to differ here. If the x bit isn't set on a directory, that will prevent scanning of the directory; in this case apache will be prevented from scanning the directory and will return a 403. It's possible that this is an SELinux issue, which adds an extra layer of permissions over files. To see what those permissions are, use the -Z flag for ls. Also, check the SELinux logs (assuming that it's running and it is causing a problem) to see if it brings up anything. It's typically found on RedHat-based distros. Thanks, Ash http://www.ashleysheridan.co.uk -- Cheers David Robley Artificial Intelligence is no match for natural stupidity. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] How to do PHP build test
Hi, Can anybody help me answering my doubt. I wanted to check if there are any errors with the php compilation and build. I have ran make, make test. make test didnt give any errors to me. Is there any other method or command to run through which we can see if there are any errors in building the php source code. Thanks, Shahina Rabbani
Re: [PHP] exec and system do not work
On 8/26/2013 5:01 PM, Ethan Rosenberg, PhD wrote:
On 08/26/2013 03:28 PM, Jim Giner wrote:
On 8/26/2013 2:41 PM, Ethan Rosenberg wrote:
On 08/26/2013 11:36 AM, ma...@behnke.biz wrote:
Tamara Temple tamouse.li...@gmail.com hat am 26. August 2013 um
08:33
geschrieben:
On Aug 25, 2013, at 10:41 PM, Ethan Rosenberg
erosenb...@hygeiabiomedical.com wrote:
Dear List -
I'm lost on this one -
This works -
$out = system(ls -l ,$retvals);
printf(%s, $out);
This does -
echo exec(ls -l);
Please show the output of the directory listing.
Please us ls -la
This does not -
if( !file_exists(/var/www/orders.txt));
{
$out = system(touch /var/www/orders.txt, $ret);
Maybe you don't have write permissions on the folder?
$out2 = system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
and this does not -
if( !file_exists(/var/www/orders.txt));
{
exec(touch /var/www/orders.txt);
exec(chmod 766 /var/www/orders.txt);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
Ethan
When you say does not work, can you show what is actually not
working? I
believe the exec and system functions are likely working just fine,
but that
the commands you've passed to them may not be.
--
Marco Behnke
Dipl. Informatiker (FH), SAE Audio Engineer Diploma
Zend Certified Engineer PHP 5.3
Tel.: 0174 / 9722336
e-Mail: ma...@behnke.biz
Softwaretechnik Behnke
Heinrich-Heine-Str. 7D
21218 Seevetal
http://www.behnke.biz
Tamara -
Please show the output of the directory listing.
Please us ls -la
echo exec('ls -la orders.txt');
-rw-rw-rw- 1 ethan ethan 43 Aug 25 23:50 orders.txt
Maybe you don't have write permissions on the folder?
If I perform the touch and chmod from the command line, everything
works.
When you say does not work, can you show what is actually not
working? I
believe the exec and system functions are likely working just fine,
but that
the commands you've passed to them may not be.
Here are my commands.
if( !file_exists(/var/www/orders.txt));
{
echo system(touch /var/www/orders.txt, $ret);
echo system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
If I now try a ls from the command line, the return is
cannot access /var/www/orders.txt: No such file or directory
The ls -la works because the file was created from the command line.
TIA
Ethan
Ethan - YOU'RE DOING IT AGAIN!!!
Either you are not using error checking AGAIN!!
OR
You are showing us re-typed in code that YOU DIDNT ACTUALLY RUN.
I've told you multiple times that you need to do these two things and
you are back at it again.
The sample php above has plain simple syntax errors that would keep it
from running, which error checking would tell you IF YOU RAN IT.
Jim -
Thank you.
I don't totally understand your reply ...
but I will try to answer
The code is taken from an operating program. My error checking is set
to maximum sensitivity.
If you would point out my syntax errors, I will fix them.
TIA
Ethan
you have semis after your if lines - therefore no logic gets executed.
--
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[PHP] Basic Auth
Im using basic auth for a few of my pages that I want to limit access to - nothing of a sensitive nature, but simply want to limit access to. Want to implement a signoff process, but can't figure it out. From the comments in the manual I take it one can't do this by simply unsetting the PHP_AUTH_USER and _PW vars. Can someone explain to me why this doesn't suffice? The signon process expects them to be there, so when they are not (after the 'unset'), how come my signon process still detects them and their values? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Basic Auth
On 27 Aug 2013, at 14:37, Jim Giner jim.gi...@albanyhandball.com wrote: Im using basic auth for a few of my pages that I want to limit access to - nothing of a sensitive nature, but simply want to limit access to. Want to implement a signoff process, but can't figure it out. From the comments in the manual I take it one can't do this by simply unsetting the PHP_AUTH_USER and _PW vars. Can someone explain to me why this doesn't suffice? The signon process expects them to be there, so when they are not (after the 'unset'), how come my signon process still detects them and their values? The global variables you're referring to are just that, global variables; changing them will have no effect on the browser. Basic Auth was not designed to allow users to log out, but you can make it happen with some Javascript. Have your log out link call a Javascript function which sends an XMLHttpRequest with an invalid username and password. The server will return a 401 which you ignore and then take the user to whatever URL you want them to see after they log off. Not pretty, but it works. -Stuart -- Stuart Dallas 3ft9 Ltd http://3ft9.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Basic Auth
On 8/27/2013 9:46 AM, Stuart Dallas wrote: On 27 Aug 2013, at 14:37, Jim Giner jim.gi...@albanyhandball.com wrote: Im using basic auth for a few of my pages that I want to limit access to - nothing of a sensitive nature, but simply want to limit access to. Want to implement a signoff process, but can't figure it out. From the comments in the manual I take it one can't do this by simply unsetting the PHP_AUTH_USER and _PW vars. Can someone explain to me why this doesn't suffice? The signon process expects them to be there, so when they are not (after the 'unset'), how come my signon process still detects them and their values? The global variables you're referring to are just that, global variables; changing them will have no effect on the browser. Basic Auth was not designed to allow users to log out, but you can make it happen with some Javascript. Have your log out link call a Javascript function which sends an XMLHttpRequest with an invalid username and password. The server will return a 401 which you ignore and then take the user to whatever URL you want them to see after they log off. Not pretty, but it works. -Stuart Thanks for the timely response! Before I try your suggestion - one question. Since when is a global variable not changeable? Doesn't the fact that it reflects a modified value when I do change it tell me it worked? I change the value to 'xxx' and show it having that value, but when the script is called again the old value appears. Very confusing! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Basic Auth
On 27 Aug 2013, at 15:06, Jim Giner jim.gi...@albanyhandball.com wrote: On 8/27/2013 9:46 AM, Stuart Dallas wrote: On 27 Aug 2013, at 14:37, Jim Giner jim.gi...@albanyhandball.com wrote: Im using basic auth for a few of my pages that I want to limit access to - nothing of a sensitive nature, but simply want to limit access to. Want to implement a signoff process, but can't figure it out. From the comments in the manual I take it one can't do this by simply unsetting the PHP_AUTH_USER and _PW vars. Can someone explain to me why this doesn't suffice? The signon process expects them to be there, so when they are not (after the 'unset'), how come my signon process still detects them and their values? The global variables you're referring to are just that, global variables; changing them will have no effect on the browser. Basic Auth was not designed to allow users to log out, but you can make it happen with some Javascript. Have your log out link call a Javascript function which sends an XMLHttpRequest with an invalid username and password. The server will return a 401 which you ignore and then take the user to whatever URL you want them to see after they log off. Not pretty, but it works. -Stuart Thanks for the timely response! Before I try your suggestion - one question. Since when is a global variable not changeable? Doesn't the fact that it reflects a modified value when I do change it tell me it worked? I change the value to 'xxx' and show it having that value, but when the script is called again the old value appears. Very confusing! I didn't say you couldn't change it, I said doing so will have no effect on the browser. It's not really confusing so long as you understand how PHP works. Each request is brand new - nothing is retained from previous requests. The two variable you're changing are set by PHP when the request comes in from the browser. The fact you changed them in a previous request is irrelevant because 1) that change was not communicated to the browser in any way, and 2) PHP doesn't retain any data between requests [1]. If you've been coding assuming that changes you make to global variables are retained between requests you must have been having some pretty frustrating times! -Stuart [1] The one exception to this is $_SESSION, but it's important to know how that works. The $_SESSION array is populated when you call session_start(). It's loaded from some form of storage (files by default) and unserialised in to $_SESSION. When the session is closed, either implicitly by the request ending or by a call to one of the methods that explicitly do it, the contents are serialised to the storage system. Once closed, any changes to $_SESSION will not be stored; it becomes just another superglobal (not that it was ever anything else). -- Stuart Dallas 3ft9 Ltd http://3ft9.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Basic Auth
On 8/27/2013 10:14 AM, Stuart Dallas wrote: It's not really confusing so long as you understand how PHP works. Each request is brand new - nothing is retained from previous requests. The two variable you're changing are set by PHP when the request comes in from the browser. The fact you changed them in a previous request is irrelevant because 1) that change was not communicated to the browser in any way, and 2) PHP doesn't retain any data between requests [1]. If you've been coding assuming that changes you make to global variables are retained between requests you must have been having some pretty frustrating times! -Stuart Not really - this is the first time I've had something not work as expected. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Basic Auth
On 27 Aug 2013, at 15:18, Jim Giner jim.gi...@albanyhandball.com wrote: On 8/27/2013 10:14 AM, Stuart Dallas wrote: It's not really confusing so long as you understand how PHP works. Each request is brand new - nothing is retained from previous requests. The two variable you're changing are set by PHP when the request comes in from the browser. The fact you changed them in a previous request is irrelevant because 1) that change was not communicated to the browser in any way, and 2) PHP doesn't retain any data between requests [1]. If you've been coding assuming that changes you make to global variables are retained between requests you must have been having some pretty frustrating times! -Stuart Not really - this is the first time I've had something not work as expected. That was said with my tongue very much firmly in my cheek, and so is this: I've been playing with dynamite since I was 4 - hey, it must be a safe, proper thing to do! Just because nothing has blown up in your face yet doesn't mean it won't, and I'm concerned that you might not actually see how important it is to make sure you're using the tool correctly. -Stuart -- Stuart Dallas 3ft9 Ltd http://3ft9.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Basic Auth
On 8/27/2013 10:39 AM, Stuart Dallas wrote:
On 27 Aug 2013, at 15:18, Jim Giner jim.gi...@albanyhandball.com wrote:
On 8/27/2013 10:14 AM, Stuart Dallas wrote:
It's not really confusing so long as you understand how PHP works. Each request
is brand new - nothing is retained from previous requests. The two variable
you're changing are set by PHP when the request comes in from the browser. The
fact you changed them in a previous request is irrelevant because 1) that
change was not communicated to the browser in any way, and 2) PHP doesn't
retain any data between requests [1].
If you've been coding assuming that changes you make to global variables are
retained between requests you must have been having some pretty frustrating
times!
-Stuart
Not really - this is the first time I've had something not work as expected.
That was said with my tongue very much firmly in my cheek, and so is this:
I've been playing with dynamite since I was 4 - hey, it must be a safe,
proper thing to do!
Just because nothing has blown up in your face yet doesn't mean it won't, and
I'm concerned that you might not actually see how important it is to make sure
you're using the tool correctly.
-Stuart
This may very well be the first time with this problem because I haven't
tried anything like this before.
That said - can you give me some pointers on how to do the JS solution?
I'm calling a script that is similar to the one I used to signon. It
sends out something like:
header(WWW-Authenticate: Basic realm=$realm);
header('HTTP/1.0 401 Unauthorized');
echo h3You have entered invalid credentialsbr;
echo Click a href='$return_url' here /a to return to the
menu.;
exit();
when it doesn't detect the PHP_AUTH_USER or it is an invalid value.
So - to effect a signoff, what does one do? You said to use an invalid
value, but what do I do with that? How do I ignore the 401? Now I'm
getting the signin dialog and I'm stuck.
--
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Re: [PHP] Basic Auth
On 27 Aug 2013, at 15:51, Jim Giner jim.gi...@albanyhandball.com wrote:
On 8/27/2013 10:39 AM, Stuart Dallas wrote:
On 27 Aug 2013, at 15:18, Jim Giner jim.gi...@albanyhandball.com wrote:
On 8/27/2013 10:14 AM, Stuart Dallas wrote:
It's not really confusing so long as you understand how PHP works. Each
request is brand new - nothing is retained from previous requests. The two
variable you're changing are set by PHP when the request comes in from the
browser. The fact you changed them in a previous request is irrelevant
because 1) that change was not communicated to the browser in any way, and
2) PHP doesn't retain any data between requests [1].
If you've been coding assuming that changes you make to global variables
are retained between requests you must have been having some pretty
frustrating times!
-Stuart
Not really - this is the first time I've had something not work as expected.
That was said with my tongue very much firmly in my cheek, and so is this:
I've been playing with dynamite since I was 4 - hey, it must be a safe,
proper thing to do!
Just because nothing has blown up in your face yet doesn't mean it won't,
and I'm concerned that you might not actually see how important it is to
make sure you're using the tool correctly.
-Stuart
This may very well be the first time with this problem because I haven't
tried anything like this before.
That said - can you give me some pointers on how to do the JS solution? I'm
calling a script that is similar to the one I used to signon. It sends out
something like:
header(WWW-Authenticate: Basic realm=$realm);
header('HTTP/1.0 401 Unauthorized');
echo h3You have entered invalid credentialsbr;
echo Click a href='$return_url' here /a to return to the menu.;
exit();
when it doesn't detect the PHP_AUTH_USER or it is an invalid value.
So - to effect a signoff, what does one do? You said to use an invalid
value, but what do I do with that? How do I ignore the 401? Now I'm
getting the signin dialog and I'm stuck.
You don't need to do anything on the server-side. You simply need a JS function
that sends a request to a URL that requires basic auth, with an Authenticate
header that contains an invalid username and password. Then, when your server
responds with a 401 Authentication required (which it should already do for an
invalid request) you can set location.href to whatever URL you want the logged
out user to see.
If you don't know how to make a request from Javascript -- commonly known as an
AJAX request -- then google for it. I'd recommend the jquery library if you
want a very easy way to do it.
-Stuart
--
Stuart Dallas
3ft9 Ltd
http://3ft9.com/
--
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Re: [PHP] Basic Auth
On 8/27/2013 10:55 AM, Stuart Dallas wrote:
On 27 Aug 2013, at 15:51, Jim Giner jim.gi...@albanyhandball.com wrote:
On 8/27/2013 10:39 AM, Stuart Dallas wrote:
On 27 Aug 2013, at 15:18, Jim Giner jim.gi...@albanyhandball.com wrote:
On 8/27/2013 10:14 AM, Stuart Dallas wrote:
It's not really confusing so long as you understand how PHP works. Each request
is brand new - nothing is retained from previous requests. The two variable
you're changing are set by PHP when the request comes in from the browser. The
fact you changed them in a previous request is irrelevant because 1) that
change was not communicated to the browser in any way, and 2) PHP doesn't
retain any data between requests [1].
If you've been coding assuming that changes you make to global variables are
retained between requests you must have been having some pretty frustrating
times!
-Stuart
Not really - this is the first time I've had something not work as expected.
That was said with my tongue very much firmly in my cheek, and so is this:
I've been playing with dynamite since I was 4 - hey, it must be a safe,
proper thing to do!
Just because nothing has blown up in your face yet doesn't mean it won't, and
I'm concerned that you might not actually see how important it is to make sure
you're using the tool correctly.
-Stuart
This may very well be the first time with this problem because I haven't tried
anything like this before.
That said - can you give me some pointers on how to do the JS solution? I'm
calling a script that is similar to the one I used to signon. It sends out
something like:
header(WWW-Authenticate: Basic realm=$realm);
header('HTTP/1.0 401 Unauthorized');
echo h3You have entered invalid credentialsbr;
echo Click a href='$return_url' here /a to return to the menu.;
exit();
when it doesn't detect the PHP_AUTH_USER or it is an invalid value.
So - to effect a signoff, what does one do? You said to use an invalid value,
but what do I do with that? How do I ignore the 401? Now I'm getting the
signin dialog and I'm stuck.
You don't need to do anything on the server-side. You simply need a JS function
that sends a request to a URL that requires basic auth, with an Authenticate
header that contains an invalid username and password. Then, when your server
responds with a 401 Authentication required (which it should already do for an
invalid request) you can set location.href to whatever URL you want the logged
out user to see.
If you don't know how to make a request from Javascript -- commonly known as an
AJAX request -- then google for it. I'd recommend the jquery library if you
want a very easy way to do it.
-Stuart
I am familiar with an ajax request (xmlhttprequest) and I have a
function ready to call a script to effect this signoff. I just don't
know what to put in that php script I'm calling. From what you just
wrote I'm guessing that my headers as shown previously may be close -
Im confused about your mention of contains an invalid username
As you can see from my sample I don't include such a thing.
--
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Re: [PHP] Off the wall - sub-domain question
On Wed, Aug 21, 2013 at 5:16 PM, Jim Giner jim.gi...@albanyhandball.com wrote: I have a main domain (of course) and a sub domain. I'm really trying to steer my personal stuff away from the main one and have focused all of my php development to the sub-domain. Lately I noticed that google catalogs my sub-domain site stuff under the main domain name and the links that come up lead to that domain name with the path that takes the user to the sub-domain's home folder and beyond. Is there something that php (apache??) can do to control either google's robots or the user's view (url) so that it appears as a page of my sub-domain? I'm really new at this stuff and know nothing. I'm lucky that google is even finding my site! You'd probably want to do some 301 redirects with mod_rewrite to force the domain over to the subdomain if under that directory. In so doing, Google (and other search engines) will drop the /subdomain folder, and index only the destination. -- /Daniel P. Brown Network Infrastructure Manager http://www.php.net/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Fwd: [PHP] Basic Auth
Oops, sent this message from the wrong email address, so the list rejected it.
Begin forwarded message:
From: Stuart Dallas stu...@3ft9.com
Subject: Re: [PHP] Basic Auth
Date: 27 August 2013 16:36:27 BST
To: jim.gi...@albanyhandball.com
Cc: php-general@lists.php.net
On 27 Aug 2013, at 15:59, Jim Giner jim.gi...@albanyhandball.com wrote:
On 8/27/2013 10:55 AM, Stuart Dallas wrote:
On 27 Aug 2013, at 15:51, Jim Giner jim.gi...@albanyhandball.com wrote:
On 8/27/2013 10:39 AM, Stuart Dallas wrote:
On 27 Aug 2013, at 15:18, Jim Giner jim.gi...@albanyhandball.com wrote:
On 8/27/2013 10:14 AM, Stuart Dallas wrote:
It's not really confusing so long as you understand how PHP works. Each
request is brand new - nothing is retained from previous requests. The
two variable you're changing are set by PHP when the request comes in
from the browser. The fact you changed them in a previous request is
irrelevant because 1) that change was not communicated to the browser
in any way, and 2) PHP doesn't retain any data between requests [1].
If you've been coding assuming that changes you make to global
variables are retained between requests you must have been having some
pretty frustrating times!
-Stuart
Not really - this is the first time I've had something not work as
expected.
That was said with my tongue very much firmly in my cheek, and so is this:
I've been playing with dynamite since I was 4 - hey, it must be a safe,
proper thing to do!
Just because nothing has blown up in your face yet doesn't mean it won't,
and I'm concerned that you might not actually see how important it is to
make sure you're using the tool correctly.
-Stuart
This may very well be the first time with this problem because I haven't
tried anything like this before.
That said - can you give me some pointers on how to do the JS solution?
I'm calling a script that is similar to the one I used to signon. It
sends out something like:
header(WWW-Authenticate: Basic realm=$realm);
header('HTTP/1.0 401 Unauthorized');
echo h3You have entered invalid credentialsbr;
echo Click a href='$return_url' here /a to return to the menu.;
exit();
when it doesn't detect the PHP_AUTH_USER or it is an invalid value.
So - to effect a signoff, what does one do? You said to use an invalid
value, but what do I do with that? How do I ignore the 401? Now I'm
getting the signin dialog and I'm stuck.
You don't need to do anything on the server-side. You simply need a JS
function that sends a request to a URL that requires basic auth, with an
Authenticate header that contains an invalid username and password. Then,
when your server responds with a 401 Authentication required (which it
should already do for an invalid request) you can set location.href to
whatever URL you want the logged out user to see.
If you don't know how to make a request from Javascript -- commonly known
as an AJAX request -- then google for it. I'd recommend the jquery library
if you want a very easy way to do it.
-Stuart
I am familiar with an ajax request (xmlhttprequest) and I have a function
ready to call a script to effect this signoff. I just don't know what to
put in that php script I'm calling. From what you just wrote I'm guessing
that my headers as shown previously may be close - Im confused about your
mention of contains an invalid username As you can see from my sample
I don't include such a thing.
For the last time: YOU DO NOT NEED TO MAKE ANY CHANGES SERVER-SIDE.
From the Javascript, request any URL that requires authentication - it
doesn't matter. When you make the AJAX request, pass an Authentication header
that contains an invalid username and password. If you don't know what I mean
by that, please google how HTTP Basic Auth works.
-Stuart
--
Stuart Dallas
3ft9 Ltd
http://3ft9.com/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Permissions
On Tue, Aug 27, 2013 at 3:07 AM, David Robley robl...@zoho.com wrote: I beg to differ here. If the x bit isn't set on a directory, that will prevent scanning of the directory; in this case apache will be prevented from scanning the directory and will return a 403. Well, that's partially correct. If a directory is owned by someone other than the current user (for example, root) and is 0776, you can list the directory content from outside of the directory to get a basic file listing. What you won't get by doing that, however, is anything other than the file name and type, because the kernel is forbidden from executing mtime, ctime, and owner/group queries on the files. In addition, you won't be able to enter the directory (cd). That said, if Ethan is running his Apache server as the user 'ethan' (which isn't mentioned) then it would be fine regardless. As for the 's' notation, that's either a bitmask of 0400 or 0200, which are for setuid and setgid, respectively. -- /Daniel P. Brown Network Infrastructure Manager http://www.php.net/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: Fwd: [PHP] Basic Auth
On 8/27/2013 11:56 AM, Stuart Dallas wrote:
Oops, sent this message from the wrong email address, so the list rejected it.
Begin forwarded message:
From: Stuart Dallas stu...@3ft9.com
Subject: Re: [PHP] Basic Auth
Date: 27 August 2013 16:36:27 BST
To: jim.gi...@albanyhandball.com
Cc: php-general@lists.php.net
On 27 Aug 2013, at 15:59, Jim Giner jim.gi...@albanyhandball.com wrote:
On 8/27/2013 10:55 AM, Stuart Dallas wrote:
On 27 Aug 2013, at 15:51, Jim Giner jim.gi...@albanyhandball.com wrote:
On 8/27/2013 10:39 AM, Stuart Dallas wrote:
On 27 Aug 2013, at 15:18, Jim Giner jim.gi...@albanyhandball.com wrote:
On 8/27/2013 10:14 AM, Stuart Dallas wrote:
It's not really confusing so long as you understand how PHP works. Each request
is brand new - nothing is retained from previous requests. The two variable
you're changing are set by PHP when the request comes in from the browser. The
fact you changed them in a previous request is irrelevant because 1) that
change was not communicated to the browser in any way, and 2) PHP doesn't
retain any data between requests [1].
If you've been coding assuming that changes you make to global variables are
retained between requests you must have been having some pretty frustrating
times!
-Stuart
Not really - this is the first time I've had something not work as expected.
That was said with my tongue very much firmly in my cheek, and so is this:
I've been playing with dynamite since I was 4 - hey, it must be a safe,
proper thing to do!
Just because nothing has blown up in your face yet doesn't mean it won't, and
I'm concerned that you might not actually see how important it is to make sure
you're using the tool correctly.
-Stuart
This may very well be the first time with this problem because I haven't tried
anything like this before.
That said - can you give me some pointers on how to do the JS solution? I'm
calling a script that is similar to the one I used to signon. It sends out
something like:
header(WWW-Authenticate: Basic realm=$realm);
header('HTTP/1.0 401 Unauthorized');
echo h3You have entered invalid credentialsbr;
echo Click a href='$return_url' here /a to return to the menu.;
exit();
when it doesn't detect the PHP_AUTH_USER or it is an invalid value.
So - to effect a signoff, what does one do? You said to use an invalid value,
but what do I do with that? How do I ignore the 401? Now I'm getting the
signin dialog and I'm stuck.
You don't need to do anything on the server-side. You simply need a JS function
that sends a request to a URL that requires basic auth, with an Authenticate
header that contains an invalid username and password. Then, when your server
responds with a 401 Authentication required (which it should already do for an
invalid request) you can set location.href to whatever URL you want the logged
out user to see.
If you don't know how to make a request from Javascript -- commonly known as an
AJAX request -- then google for it. I'd recommend the jquery library if you
want a very easy way to do it.
-Stuart
I am familiar with an ajax request (xmlhttprequest) and I have a function ready to call a
script to effect this signoff. I just don't know what to put in that php script I'm calling.
From what you just wrote I'm guessing that my headers as shown previously may be close -
Im confused about your mention of contains an invalid username As you
can see from my sample I don't include such a thing.
For the last time: YOU DO NOT NEED TO MAKE ANY CHANGES SERVER-SIDE.
From the Javascript, request any URL that requires authentication - it doesn't
matter. When you make the AJAX request, pass an Authentication header that
contains an invalid username and password. If you don't know what I mean by
that, please google how HTTP Basic Auth works.
-Stuart
--
Stuart Dallas
3ft9 Ltd
http://3ft9.com/
It's not the basic auth that I'm having the issue with - it's the
'header' thing and understanding what a 401 is doing and how I'm to
ignore it. Never had to play with these things before and this part is
all new. Let's face it - I'm an applications guy, not a systems guy.
All this talk of headers and such is greek to me.
I have spent the last hour googling away on this topic - still no
understanding.
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] How to send post-variables in a Location header
On Mon, Aug 26, 2013 at 3:48 PM, Ajay Garg ajaygargn...@gmail.com wrote:
Hi all.
I have a scenario, wherein I need to do something like this ::
###
$original_url = /autologin.php;
$username = ajay;
$password = garg;
header('Location: ' . $original_url);
###
As can be seen, I wish to redirect to the URL autologin.php.
Additionally, I wish to pass two POST key-value pairs :: user=ajay and
password=garg (I understand that passing GET key-value pairs is trivial).
Is it even possible?
If yes, I will be grateful if someone could let me know how to redirect to
a URL, passing the POST key-value pairs as necessary.
No. Sending a 'Location:' header issues an HTTP 301 by default,
which means the browser will follow it using a GET request. If you
can't pass the information from one location to another using sessions
or (less ideally) cookies, you might consider doing a cURL POST
request in the background and passing the session ID back to the
browser, and having it handle it appropriately (read: session
hijack).
--
/Daniel P. Brown
Network Infrastructure Manager
http://www.php.net/
--
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[PHP] Re: Basic Auth
On 27/08/13 15:37, Jim Giner wrote: Im using basic auth for a few of my pages that I want to limit access to - nothing of a sensitive nature, but simply want to limit access to. Want to implement a signoff process, but can't figure it out. From the comments in the manual I take it one can't do this by simply unsetting the PHP_AUTH_USER and _PW vars. Can someone explain to me why this doesn't suffice? The signon process expects them to be there, so when they are not (after the 'unset'), how come my signon process still detects them and their values? Hello Jim, at the risk of under-estimating your knowledge (and over-estimating mine) of HTTP-requests in PHP - but here it goes. I see two options of bypassing the JavaScript option. The first one is to use the default authorization, and error pages of your HTTP server. (For example, in Apache: http://httpd.apache.org/docs/2.2/custom-error.html) This is for a login with invalid credentials. For some-one to leave the protected site, a HTTP-request without credentials, and to a URI outside the protected domain, should do (as every HTTP request into the protected domain should repeat the Authorisation header). The second one is to leave header(), and go down one level, to the likes of fsockopen() or stream_socket_server() - though personally, I've only limited knowledge of a bit of client-side programming. Unless I've completely misunderstood your question, Hope this helps, Bert -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] exec and system do not work
On Sun, Aug 25, 2013 at 11:41 PM, Ethan Rosenberg
erosenb...@hygeiabiomedical.com wrote:
Dear List -
I'm lost on this one -
This works -
$out = system(ls -l ,$retvals);
printf(%s, $out);
This does -
echo exec(ls -l);
This does not -
if( !file_exists(/var/www/orders.txt));
{
$out = system(touch /var/www/orders.txt, $ret);
$out2 = system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
?php echo `whoami`; ?
--
/Daniel P. Brown
Network Infrastructure Manager
http://www.php.net/
--
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To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Basic Auth
On 27 Aug 2013, at 17:28, Jim Giner jim.gi...@albanyhandball.com wrote:
On 8/27/2013 11:56 AM, Stuart Dallas wrote:
Oops, sent this message from the wrong email address, so the list rejected
it.
Begin forwarded message:
From: Stuart Dallas stu...@3ft9.com
Subject: Re: [PHP] Basic Auth
Date: 27 August 2013 16:36:27 BST
To: jim.gi...@albanyhandball.com
Cc: php-general@lists.php.net
On 27 Aug 2013, at 15:59, Jim Giner jim.gi...@albanyhandball.com wrote:
On 8/27/2013 10:55 AM, Stuart Dallas wrote:
On 27 Aug 2013, at 15:51, Jim Giner jim.gi...@albanyhandball.com wrote:
On 8/27/2013 10:39 AM, Stuart Dallas wrote:
On 27 Aug 2013, at 15:18, Jim Giner jim.gi...@albanyhandball.com
wrote:
On 8/27/2013 10:14 AM, Stuart Dallas wrote:
It's not really confusing so long as you understand how PHP works.
Each request is brand new - nothing is retained from previous
requests. The two variable you're changing are set by PHP when the
request comes in from the browser. The fact you changed them in a
previous request is irrelevant because 1) that change was not
communicated to the browser in any way, and 2) PHP doesn't retain any
data between requests [1].
If you've been coding assuming that changes you make to global
variables are retained between requests you must have been having
some pretty frustrating times!
-Stuart
Not really - this is the first time I've had something not work as
expected.
That was said with my tongue very much firmly in my cheek, and so is
this:
I've been playing with dynamite since I was 4 - hey, it must be a
safe, proper thing to do!
Just because nothing has blown up in your face yet doesn't mean it
won't, and I'm concerned that you might not actually see how important
it is to make sure you're using the tool correctly.
-Stuart
This may very well be the first time with this problem because I haven't
tried anything like this before.
That said - can you give me some pointers on how to do the JS solution?
I'm calling a script that is similar to the one I used to signon. It
sends out something like:
header(WWW-Authenticate: Basic realm=$realm);
header('HTTP/1.0 401 Unauthorized');
echo h3You have entered invalid credentialsbr;
echo Click a href='$return_url' here /a to return to the
menu.;
exit();
when it doesn't detect the PHP_AUTH_USER or it is an invalid value.
So - to effect a signoff, what does one do? You said to use an invalid
value, but what do I do with that? How do I ignore the 401? Now I'm
getting the signin dialog and I'm stuck.
You don't need to do anything on the server-side. You simply need a JS
function that sends a request to a URL that requires basic auth, with an
Authenticate header that contains an invalid username and password. Then,
when your server responds with a 401 Authentication required (which it
should already do for an invalid request) you can set location.href to
whatever URL you want the logged out user to see.
If you don't know how to make a request from Javascript -- commonly known
as an AJAX request -- then google for it. I'd recommend the jquery
library if you want a very easy way to do it.
-Stuart
I am familiar with an ajax request (xmlhttprequest) and I have a function
ready to call a script to effect this signoff. I just don't know what to
put in that php script I'm calling. From what you just wrote I'm guessing
that my headers as shown previously may be close - Im confused about
your mention of contains an invalid username As you can see from my
sample I don't include such a thing.
For the last time: YOU DO NOT NEED TO MAKE ANY CHANGES SERVER-SIDE.
From the Javascript, request any URL that requires authentication - it
doesn't matter. When you make the AJAX request, pass an Authentication
header that contains an invalid username and password. If you don't know
what I mean by that, please google how HTTP Basic Auth works.
-Stuart
It's not the basic auth that I'm having the issue with - it's the 'header'
thing and understanding what a 401 is doing and how I'm to ignore it. Never
had to play with these things before and this part is all new. Let's face it
- I'm an applications guy, not a systems guy. All this talk of headers and
such is greek to me.
HTTP headers are as important for application guys as they are for systems
guys. I appreciate that this may be new to you, but it's pretty basic knowledge
about how HTTP works.
Basic auth is simple, and you need to understand how it works to understand
what I've been trying to say. Here's how HTTP auth works:
1) Browser hits page.
2) The PHP script knows this page requires HTTP Auth, checks the
PHP_AUTH_[USER|PW] variables but doesn't find anything, so it responds with an
HTTP status of 401 Unauthorised.
3) The browser gets the 401 response and displays the login box.
4) User enters username and password
Re: [PHP] Basic Auth
On 8/27/2013 12:53 PM, Stuart Dallas wrote:
On 27 Aug 2013, at 17:28, Jim Giner jim.gi...@albanyhandball.com wrote:
On 8/27/2013 11:56 AM, Stuart Dallas wrote:
Oops, sent this message from the wrong email address, so the list rejected it.
Begin forwarded message:
From: Stuart Dallas stu...@3ft9.com
Subject: Re: [PHP] Basic Auth
Date: 27 August 2013 16:36:27 BST
To: jim.gi...@albanyhandball.com
Cc: php-general@lists.php.net
On 27 Aug 2013, at 15:59, Jim Giner jim.gi...@albanyhandball.com wrote:
On 8/27/2013 10:55 AM, Stuart Dallas wrote:
On 27 Aug 2013, at 15:51, Jim Giner jim.gi...@albanyhandball.com wrote:
On 8/27/2013 10:39 AM, Stuart Dallas wrote:
On 27 Aug 2013, at 15:18, Jim Giner jim.gi...@albanyhandball.com wrote:
On 8/27/2013 10:14 AM, Stuart Dallas wrote:
It's not really confusing so long as you understand how PHP works. Each request
is brand new - nothing is retained from previous requests. The two variable
you're changing are set by PHP when the request comes in from the browser. The
fact you changed them in a previous request is irrelevant because 1) that
change was not communicated to the browser in any way, and 2) PHP doesn't
retain any data between requests [1].
If you've been coding assuming that changes you make to global variables are
retained between requests you must have been having some pretty frustrating
times!
-Stuart
Not really - this is the first time I've had something not work as expected.
That was said with my tongue very much firmly in my cheek, and so is this:
I've been playing with dynamite since I was 4 - hey, it must be a safe,
proper thing to do!
Just because nothing has blown up in your face yet doesn't mean it won't, and
I'm concerned that you might not actually see how important it is to make sure
you're using the tool correctly.
-Stuart
This may very well be the first time with this problem because I haven't tried
anything like this before.
That said - can you give me some pointers on how to do the JS solution? I'm
calling a script that is similar to the one I used to signon. It sends out
something like:
header(WWW-Authenticate: Basic realm=$realm);
header('HTTP/1.0 401 Unauthorized');
echo h3You have entered invalid credentialsbr;
echo Click a href='$return_url' here /a to return to the menu.;
exit();
when it doesn't detect the PHP_AUTH_USER or it is an invalid value.
So - to effect a signoff, what does one do? You said to use an invalid value,
but what do I do with that? How do I ignore the 401? Now I'm getting the
signin dialog and I'm stuck.
You don't need to do anything on the server-side. You simply need a JS function
that sends a request to a URL that requires basic auth, with an Authenticate
header that contains an invalid username and password. Then, when your server
responds with a 401 Authentication required (which it should already do for an
invalid request) you can set location.href to whatever URL you want the logged
out user to see.
If you don't know how to make a request from Javascript -- commonly known as an
AJAX request -- then google for it. I'd recommend the jquery library if you
want a very easy way to do it.
-Stuart
I am familiar with an ajax request (xmlhttprequest) and I have a function ready to call a
script to effect this signoff. I just don't know what to put in that php script I'm calling.
From what you just wrote I'm guessing that my headers as shown previously may be close -
Im confused about your mention of contains an invalid username As you
can see from my sample I don't include such a thing.
For the last time: YOU DO NOT NEED TO MAKE ANY CHANGES SERVER-SIDE.
From the Javascript, request any URL that requires authentication - it doesn't
matter. When you make the AJAX request, pass an Authentication header that
contains an invalid username and password. If you don't know what I mean by
that, please google how HTTP Basic Auth works.
-Stuart
It's not the basic auth that I'm having the issue with - it's the 'header'
thing and understanding what a 401 is doing and how I'm to ignore it. Never
had to play with these things before and this part is all new. Let's face it -
I'm an applications guy, not a systems guy. All this talk of headers and such
is greek to me.
HTTP headers are as important for application guys as they are for systems
guys. I appreciate that this may be new to you, but it's pretty basic knowledge
about how HTTP works.
Basic auth is simple, and you need to understand how it works to understand
what I've been trying to say. Here's how HTTP auth works:
1) Browser hits page.
2) The PHP script knows this page requires HTTP Auth, checks the
PHP_AUTH_[USER|PW] variables but doesn't find anything, so it responds with an
HTTP status of 401 Unauthorised.
3) The browser gets the 401 response and displays the login box.
4) User enters username and password.
5) Browser sends the request again
Re: [PHP] Re: Permissions
On 08/27/2013 03:07 AM, David Robley wrote: Ashley Sheridan wrote: On Tue, 2013-08-27 at 16:16 +0930, David Robley wrote: Ethan Rosenberg wrote: Dear List - Tried to run the program, that we have been discussing, and received a 403 error. rosenberg:/var/www# ls -la StoreInventory.php -rwxrwxrw- 1 ethan ethan 4188 Aug 26 20:26 StoreInventory.php rosenberg:/var# ls -ld www drwxrwxrw- 37 ethan ethan 20480 Aug 26 20:26 www I had set the S bit [probably a nasty mistake] and I thought I was able to remove the bit. [it doesn't show above] How do I extricate myself from the hole into which I have planted myself? TIA Ethan This is in no way a php question, as the same result will happen no matter what you ask apache to serve from that directory. You have the directory permissions set to 776 not 777. -- Cheers David Robley Steal this tagline and I'll tie-dye your cat! 776 won't matter in the case of a directory, as the last bit is for the eXecute permissions, which aren't applicable to a directory. What I beg to differ here. If the x bit isn't set on a directory, that will prevent scanning of the directory; in this case apache will be prevented from scanning the directory and will return a 403. It's possible that this is an SELinux issue, which adds an extra layer of permissions over files. To see what those permissions are, use the -Z flag for ls. Also, check the SELinux logs (assuming that it's running and it is causing a problem) to see if it brings up anything. It's typically found on RedHat-based distros. Thanks, Ash http://www.ashleysheridan.co.uk I checked with the -Z option ethan@rosenberg:/var/www$ ls -lZ StoreInventory.php -rwxrwsr-t 1 ethan ethan ? 4232 Aug 27 00:18 StoreInventory.php Ethan PS David- I promise that I will not steal your tag line. My short hair American tabby cat [Gingy Feline Rosenberg]is too nice to have anything done to her. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Permissions
On 08/27/2013 01:52 PM, Ethan Rosenberg wrote: On 08/27/2013 03:07 AM, David Robley wrote: Ashley Sheridan wrote: On Tue, 2013-08-27 at 16:16 +0930, David Robley wrote: Ethan Rosenberg wrote: Dear List - Tried to run the program, that we have been discussing, and received a 403 error. rosenberg:/var/www# ls -la StoreInventory.php -rwxrwxrw- 1 ethan ethan 4188 Aug 26 20:26 StoreInventory.php rosenberg:/var# ls -ld www drwxrwxrw- 37 ethan ethan 20480 Aug 26 20:26 www I had set the S bit [probably a nasty mistake] and I thought I was able to remove the bit. [it doesn't show above] How do I extricate myself from the hole into which I have planted myself? TIA Ethan This is in no way a php question, as the same result will happen no matter what you ask apache to serve from that directory. You have the directory permissions set to 776 not 777. -- Cheers David Robley Steal this tagline and I'll tie-dye your cat! 776 won't matter in the case of a directory, as the last bit is for the eXecute permissions, which aren't applicable to a directory. What I beg to differ here. If the x bit isn't set on a directory, that will prevent scanning of the directory; in this case apache will be prevented from scanning the directory and will return a 403. It's possible that this is an SELinux issue, which adds an extra layer of permissions over files. To see what those permissions are, use the -Z flag for ls. Also, check the SELinux logs (assuming that it's running and it is causing a problem) to see if it brings up anything. It's typically found on RedHat-based distros. Thanks, Ash http://www.ashleysheridan.co.uk I checked with the -Z option ethan@rosenberg:/var/www$ ls -lZ StoreInventory.php -rwxrwsr-t 1 ethan ethan ? 4232 Aug 27 00:18 StoreInventory.php Ethan PS David- I promise that I will not steal your tag line. My short hair American tabby cat [Gingy Feline Rosenberg]is too nice to have anything done to her. This has really morphed into a Debian issue. I have sent it to the Debian list. I will keep you informed. Ethan -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Permissions
On 08/27/2013 03:31 PM, Steven Post wrote:
On Tue, 2013-08-27 at 13:43 -0400, Ethan Rosenberg wrote:
Dear List -
I apologize for this needle in a haystack but...
This was originally posted on the PHP list, but has changed into a
Debian question...
Tried to run the program, that we have been discussing,{on the PHP list}
and received a 403 error.
rosenberg:/var/www# ls -la StoreInventory.php
-rwxrwxrw- 1 ethan ethan 4188 Aug 26 20:26 StoreInventory.php
rosenberg:/var# ls -ld www
drwxrwxrw- 37 ethan ethan 20480 Aug 26 20:26 www
I had set the S bit [probably a nasty mistake] and I thought I was able
to remove the bit. [it doesn't show above]
I made the following stupid mistakes...
note commands from the root prompt have a su appended
467 chown -R ethan:www-data wwwsu
469 chown -R ethan:www-data wwwsu
470 chmod -R g+s www su
471 chgrp -R www su
477 chgrp -R ethan www su
480 chmod -R 766 www su
482 chmod g-S www su
485 chmod -S www su
486 chmod g S www su
487 chmod gS www su
488 chmod S wwwsu
489 chmod 776 www su
492 chmod 776 -R www su
494 chmod -s -R wwwsu
504 chmod 666 StoreInventory.php
512 chmod 3775 StoreInventory.php
I now have
ethan@rosenberg:/var/www$ ls -la StoreInventory.php
-rwxrwsr-t 1 ethan ethan 4232 Aug 27 00:18 StoreInventory.php
ethan@rosenberg:/var$ ls -ld www
drwxrwxrw- 37 ethan ethan 20480 Aug 26 20:26 www
and still have the 403 error.
How do I extricate myself from the hole into which I have planted myself?
The problem appears to be that Apache does not have access to the file.
Looking at the permissions of the file it should work, however, apache
is not able to go into your /var/www folder. Either you need to set
www-data as the owner of the directory, or as the group owner, or,
possibility number 3, give execute rights to 'others' on that folder.
Pick one (you might need to be root for the first 2 in your situation):
1) chown www-data /var/www
2) chgrp www-data /var/www
3) chmod -R o+X /var/www
Note the capital 'X' on option 3, this gives execute permissions on
folders only, not files, as the -R means all files and subdirectories as
well.
The 't' is known as the sticky bit if I recall correctly, set with 1 on
the first number in a 4 number chmod command, for details see [1].
I guess in your case you can use 0664 for the files and 0775 for
directories (or 0640 and 0750 if you set owner or group back to
www-data)
Best regards,
Steven
you wrote about a 403 error, so I assume you invoke the script by
calling a webserver via browser.
In that case the webserver needs the permission to access /var/www and
to read StoreInventory.php.
By default the webserver runs as user/group www-data (it can be changed
in the webservers config-file(s)).
Try this:
#chown -R ethan:www-data /var/www
#chmod 775 /var/www
#chmod 640 /var/www/StoreInventory.php
Your ls should return something like this:
$ls -hal /var/www
drwxr-x--- 1 ethan www-data 4.0K Jun 3 20:35 .
-rw-r- 1 ethan www-data 623 Jun 3 20:35 StoreInventory.php
If that does not work you might check the configuration- and log-files
of your webserver.
Dear List -
I had to go to a meeting but before I left I tried one last thing -
chmod 000 www
chmod 0777 www
rosenberg:/var# ls -ld www
drwxrwxrwx 37 ethan ethan 20480 Aug 27 17:30 www
chown ethan StoreInventory.php
chgrp ethan StoreInventory.php
chmod 000 StoreInventory.php
chmod 777 StoreInventory.php
ethan@rosenberg:/var/www$ ls -la StoreInventory.php
-rwxrwxrwx 1 ethan ethan 4232 Aug 27 17:25 StoreInventory.php
when I returned...
IT WORKS!!!
Thanks to all.
Ethan
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php-general Digest 26 Aug 2013 18:41:27 -0000 Issue 8345
php-general Digest 26 Aug 2013 18:41:27 - Issue 8345
Topics (messages 321966 through 321970):
Re: exec and system do not work
321966 by: Sorin Badea
321967 by: Robert Cummings
321968 by: Tamara Temple
321969 by: marco.behnke.biz
321970 by: Ethan Rosenberg
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---BeginMessage---
*/var/www* is usually under *www* user. It may be a permissions problem.
On Mon, Aug 26, 2013 at 6:41 AM, Ethan Rosenberg
erosenb...@hygeiabiomedical.com wrote:
Dear List -
I'm lost on this one -
This works -
$out = system(ls -l ,$retvals);
printf(%s, $out);
This does -
echo exec(ls -l);
This does not -
if( !file_exists(/var/www/orders.**txt));
{
$out = system(touch /var/www/orders.txt, $ret);
$out2 = system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.**txt);
}
and this does not -
if( !file_exists(/var/www/orders.**txt));
{
exec(touch /var/www/orders.txt);
exec(chmod 766 /var/www/orders.txt);
echo 'file2br /';
echo file_exists(/var/www/orders.**txt);
}
Ethan
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Sorin Badea - Software Engineer
---End Message---
---BeginMessage---
On 13-08-25 11:41 PM, Ethan Rosenberg wrote:
Dear List -
I'm lost on this one -
This works -
$out = system(ls -l ,$retvals);
printf(%s, $out);
This does -
echo exec(ls -l);
This does not -
if( !file_exists(/var/www/orders.txt));
{
$out = system(touch /var/www/orders.txt, $ret);
$out2 = system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
and this does not -
if( !file_exists(/var/www/orders.txt));
{
exec(touch /var/www/orders.txt);
exec(chmod 766 /var/www/orders.txt);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
Ethan
Hi Ethan,
Is there a reason you're using shell commands to achieve the following:
?php
$path = '/var/www/orders.txt';
if( !file_exists( $path ) )
{
if( !touch( $path ) )
{
echo 'Failed to touch file into existence: '.$path.\n;
}
else
{
if( !chmod( $path, 0766 ) )
{
echo 'Failed to update file permissions: '.$path.\n;
}
}
}
?
Also, why are you setting the executable bit on a text file? :)
Cheers,
Rob.
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This message is intended solely for the addressee(s). Disclosure,
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---End Message---
---BeginMessage---
On Aug 25, 2013, at 10:41 PM, Ethan Rosenberg erosenb...@hygeiabiomedical.com
wrote:
Dear List -
I'm lost on this one -
This works -
$out = system(ls -l ,$retvals);
printf(%s, $out);
This does -
echo exec(ls -l);
This does not -
if( !file_exists(/var/www/orders.txt));
{
$out = system(touch /var/www/orders.txt, $ret);
$out2 = system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
and this does not -
if( !file_exists(/var/www/orders.txt));
{
exec(touch /var/www/orders.txt);
exec(chmod 766 /var/www/orders.txt);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
Ethan
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When you say does not work, can you show what is actually not working? I
believe the exec and system functions are likely working just fine, but that
the commands you've passed to them may not be.
---End Message---
---BeginMessage---
Tamara Temple tamouse.li...@gmail.com hat am 26. August 2013 um 08:33
geschrieben:
On Aug 25, 2013, at 10:41 PM, Ethan Rosenberg
erosenb...@hygeiabiomedical.com wrote:
Dear List -
I'm lost on this one -
This works -
$out = system(ls -l ,$retvals);
printf(%s, $out);
This does -
echo exec(ls -l);
Please show the output of the directory listing.
Please us ls -la
This does not -
if( !file_exists(/var/www/orders.txt));
{
$out = system(touch /var/www/orders.txt, $ret);
Maybe you don't have write permissions on the folder?
$out2 = system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
and this does not -
if( !file_exists(/var/www/orders.txt));
{
exec(touch /var/www/orders.txt);
exec(chmod 766 /var/www/orders.txt);
echo
Re: [PHP] exec and system do not work
On 13-08-25 11:41 PM, Ethan Rosenberg wrote:
Dear List -
I'm lost on this one -
This works -
$out = system(ls -l ,$retvals);
printf(%s, $out);
This does -
echo exec(ls -l);
This does not -
if( !file_exists(/var/www/orders.txt));
{
$out = system(touch /var/www/orders.txt, $ret);
$out2 = system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
and this does not -
if( !file_exists(/var/www/orders.txt));
{
exec(touch /var/www/orders.txt);
exec(chmod 766 /var/www/orders.txt);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
Ethan
Hi Ethan,
Is there a reason you're using shell commands to achieve the following:
?php
$path = '/var/www/orders.txt';
if( !file_exists( $path ) )
{
if( !touch( $path ) )
{
echo 'Failed to touch file into existence: '.$path.\n;
}
else
{
if( !chmod( $path, 0766 ) )
{
echo 'Failed to update file permissions: '.$path.\n;
}
}
}
?
Also, why are you setting the executable bit on a text file? :)
Cheers,
Rob.
--
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Re: [PHP] exec and system do not work
On Aug 25, 2013, at 10:41 PM, Ethan Rosenberg erosenb...@hygeiabiomedical.com
wrote:
Dear List -
I'm lost on this one -
This works -
$out = system(ls -l ,$retvals);
printf(%s, $out);
This does -
echo exec(ls -l);
This does not -
if( !file_exists(/var/www/orders.txt));
{
$out = system(touch /var/www/orders.txt, $ret);
$out2 = system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
and this does not -
if( !file_exists(/var/www/orders.txt));
{
exec(touch /var/www/orders.txt);
exec(chmod 766 /var/www/orders.txt);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
Ethan
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When you say does not work, can you show what is actually not working? I
believe the exec and system functions are likely working just fine, but that
the commands you've passed to them may not be.
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Re: [PHP] exec and system do not work
Tamara Temple tamouse.li...@gmail.com hat am 26. August 2013 um 08:33
geschrieben:
On Aug 25, 2013, at 10:41 PM, Ethan Rosenberg
erosenb...@hygeiabiomedical.com wrote:
Dear List -
I'm lost on this one -
This works -
$out = system(ls -l ,$retvals);
printf(%s, $out);
This does -
echo exec(ls -l);
Please show the output of the directory listing.
Please us ls -la
This does not -
if( !file_exists(/var/www/orders.txt));
{
$out = system(touch /var/www/orders.txt, $ret);
Maybe you don't have write permissions on the folder?
$out2 = system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
and this does not -
if( !file_exists(/var/www/orders.txt));
{
exec(touch /var/www/orders.txt);
exec(chmod 766 /var/www/orders.txt);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
Ethan
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When you say does not work, can you show what is actually not working? I
believe the exec and system functions are likely working just fine, but that
the commands you've passed to them may not be.
--
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Marco Behnke
Dipl. Informatiker (FH), SAE Audio Engineer Diploma
Zend Certified Engineer PHP 5.3
Tel.: 0174 / 9722336
e-Mail: ma...@behnke.biz
Softwaretechnik Behnke
Heinrich-Heine-Str. 7D
21218 Seevetal
http://www.behnke.biz
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Re: [PHP] exec and system do not work
On 08/26/2013 11:36 AM, ma...@behnke.biz wrote:
Tamara Temple tamouse.li...@gmail.com hat am 26. August 2013 um 08:33
geschrieben:
On Aug 25, 2013, at 10:41 PM, Ethan Rosenberg
erosenb...@hygeiabiomedical.com wrote:
Dear List -
I'm lost on this one -
This works -
$out = system(ls -l ,$retvals);
printf(%s, $out);
This does -
echo exec(ls -l);
Please show the output of the directory listing.
Please us ls -la
This does not -
if( !file_exists(/var/www/orders.txt));
{
$out = system(touch /var/www/orders.txt, $ret);
Maybe you don't have write permissions on the folder?
$out2 = system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
and this does not -
if( !file_exists(/var/www/orders.txt));
{
exec(touch /var/www/orders.txt);
exec(chmod 766 /var/www/orders.txt);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
Ethan
When you say does not work, can you show what is actually not working? I
believe the exec and system functions are likely working just fine, but that
the commands you've passed to them may not be.
--
Marco Behnke
Dipl. Informatiker (FH), SAE Audio Engineer Diploma
Zend Certified Engineer PHP 5.3
Tel.: 0174 / 9722336
e-Mail: ma...@behnke.biz
Softwaretechnik Behnke
Heinrich-Heine-Str. 7D
21218 Seevetal
http://www.behnke.biz
Tamara -
Please show the output of the directory listing.
Please us ls -la
echo exec('ls -la orders.txt');
-rw-rw-rw- 1 ethan ethan 43 Aug 25 23:50 orders.txt
Maybe you don't have write permissions on the folder?
If I perform the touch and chmod from the command line, everything works.
When you say does not work, can you show what is actually not
working? I
believe the exec and system functions are likely working just fine,
but that
the commands you've passed to them may not be.
Here are my commands.
if( !file_exists(/var/www/orders.txt));
{
echo system(touch /var/www/orders.txt, $ret);
echo system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
If I now try a ls from the command line, the return is
cannot access /var/www/orders.txt: No such file or directory
The ls -la works because the file was created from the command line.
TIA
Ethan
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Re: [PHP] exec and system do not work
On 8/26/2013 2:41 PM, Ethan Rosenberg wrote:
On 08/26/2013 11:36 AM, ma...@behnke.biz wrote:
Tamara Temple tamouse.li...@gmail.com hat am 26. August 2013 um 08:33
geschrieben:
On Aug 25, 2013, at 10:41 PM, Ethan Rosenberg
erosenb...@hygeiabiomedical.com wrote:
Dear List -
I'm lost on this one -
This works -
$out = system(ls -l ,$retvals);
printf(%s, $out);
This does -
echo exec(ls -l);
Please show the output of the directory listing.
Please us ls -la
This does not -
if( !file_exists(/var/www/orders.txt));
{
$out = system(touch /var/www/orders.txt, $ret);
Maybe you don't have write permissions on the folder?
$out2 = system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
and this does not -
if( !file_exists(/var/www/orders.txt));
{
exec(touch /var/www/orders.txt);
exec(chmod 766 /var/www/orders.txt);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
Ethan
When you say does not work, can you show what is actually not
working? I
believe the exec and system functions are likely working just fine,
but that
the commands you've passed to them may not be.
--
Marco Behnke
Dipl. Informatiker (FH), SAE Audio Engineer Diploma
Zend Certified Engineer PHP 5.3
Tel.: 0174 / 9722336
e-Mail: ma...@behnke.biz
Softwaretechnik Behnke
Heinrich-Heine-Str. 7D
21218 Seevetal
http://www.behnke.biz
Tamara -
Please show the output of the directory listing.
Please us ls -la
echo exec('ls -la orders.txt');
-rw-rw-rw- 1 ethan ethan 43 Aug 25 23:50 orders.txt
Maybe you don't have write permissions on the folder?
If I perform the touch and chmod from the command line, everything works.
When you say does not work, can you show what is actually not
working? I
believe the exec and system functions are likely working just fine,
but that
the commands you've passed to them may not be.
Here are my commands.
if( !file_exists(/var/www/orders.txt));
{
echo system(touch /var/www/orders.txt, $ret);
echo system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
If I now try a ls from the command line, the return is
cannot access /var/www/orders.txt: No such file or directory
The ls -la works because the file was created from the command line.
TIA
Ethan
Ethan - YOU'RE DOING IT AGAIN!!!
Either you are not using error checking AGAIN!!
OR
You are showing us re-typed in code that YOU DIDNT ACTUALLY RUN.
I've told you multiple times that you need to do these two things and
you are back at it again.
The sample php above has plain simple syntax errors that would keep it
from running, which error checking would tell you IF YOU RAN IT.
--
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[PHP] How to send post-variables in a Location header
Hi all.
I have a scenario, wherein I need to do something like this ::
###
$original_url = /autologin.php;
$username = ajay;
$password = garg;
header('Location: ' . $original_url);
###
As can be seen, I wish to redirect to the URL autologin.php.
Additionally, I wish to pass two POST key-value pairs :: user=ajay and
password=garg (I understand that passing GET key-value pairs is trivial).
Is it even possible?
If yes, I will be grateful if someone could let me know how to redirect to
a URL, passing the POST key-value pairs as necessary.
Looking forward to a reply :)
--
Regards,
Ajay
Re: [PHP] exec and system do not work
Ethan Rosenberg erosenb...@hygeiabiomedical.com hat am 26. August 2013 um
20:41 geschrieben:
Please show the output of the directory listing.
Please us ls -la
echo exec('ls -la orders.txt');
-rw-rw-rw- 1 ethan ethan 43 Aug 25 23:50 orders.txt
Please supply the complete output. Especially the rights for . and ..
Maybe you don't have write permissions on the folder?
If I perform the touch and chmod from the command line, everything works.
cli and ww are different users.
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Re: [PHP] How to send post-variables in a Location header
Ajay Garg ajaygargn...@gmail.com hat am 26. August 2013 um 21:48
geschrieben:
Hi all.
I have a scenario, wherein I need to do something like this ::
###
$original_url = /autologin.php;
$username = ajay;
$password = garg;
header('Location: ' . $original_url);
###
As can be seen, I wish to redirect to the URL autologin.php.
Additionally, I wish to pass two POST key-value pairs :: user=ajay and
password=garg (I understand that passing GET key-value pairs is trivial).
Is it even possible?
If yes, I will be grateful if someone could let me know how to redirect to
a URL, passing the POST key-value pairs as necessary.
Iirc it is not possible to pass post body content via location redirect.
What you can do: Set auth headers
http://forums.phpfreaks.com/topic/84480-solved-how-to-send-authorization-basic-header/
Looking forward to a reply :)
--
Regards,
Ajay
--
Marco Behnke
Dipl. Informatiker (FH), SAE Audio Engineer Diploma
Zend Certified Engineer PHP 5.3
Tel.: 0174 / 9722336
e-Mail: ma...@behnke.biz
Softwaretechnik Behnke
Heinrich-Heine-Str. 7D
21218 Seevetal
http://www.behnke.biz
--
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Re: [PHP] How to send post-variables in a Location header
On Mon, Aug 26, 2013 at 9:48 PM, Ajay Garg ajaygargn...@gmail.com wrote:
Hi all.
I have a scenario, wherein I need to do something like this ::
###
$original_url = /autologin.php;
$username = ajay;
$password = garg;
header('Location: ' . $original_url);
###
As can be seen, I wish to redirect to the URL autologin.php.
Additionally, I wish to pass two POST key-value pairs :: user=ajay and
password=garg (I understand that passing GET key-value pairs is trivial).
Is it even possible?
If yes, I will be grateful if someone could let me know how to redirect to
a URL, passing the POST key-value pairs as necessary.
Looking forward to a reply :)
Usually you would pass this around in sessions. If you must however use
post, you can only do so with using some javascript magic. Write a form
with hidden input and auto submit it.
- Matijn
Re: [PHP] exec and system do not work
On Aug 26, 2013, at 1:41 PM, Ethan Rosenberg erosenb...@hygeiabiomedical.com
wrote:
On 08/26/2013 11:36 AM, ma...@behnke.biz wrote:
Tamara Temple tamouse.li...@gmail.com hat am 26. August 2013 um 08:33
geschrieben:
On Aug 25, 2013, at 10:41 PM, Ethan Rosenberg
erosenb...@hygeiabiomedical.com wrote:
Dear List -
I'm lost on this one -
This works -
$out = system(ls -l ,$retvals);
printf(%s, $out);
This does -
echo exec(ls -l);
Please show the output of the directory listing.
Please us ls -la
This does not -
if( !file_exists(/var/www/orders.txt));
{
$out = system(touch /var/www/orders.txt, $ret);
Maybe you don't have write permissions on the folder?
$out2 = system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
and this does not -
if( !file_exists(/var/www/orders.txt));
{
exec(touch /var/www/orders.txt);
exec(chmod 766 /var/www/orders.txt);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
Ethan
When you say does not work, can you show what is actually not working? I
believe the exec and system functions are likely working just fine, but that
the commands you've passed to them may not be.
--
Marco Behnke
Dipl. Informatiker (FH), SAE Audio Engineer Diploma
Zend Certified Engineer PHP 5.3
Tel.: 0174 / 9722336
e-Mail: ma...@behnke.biz
Softwaretechnik Behnke
Heinrich-Heine-Str. 7D
21218 Seevetal
http://www.behnke.biz
Tamara -
You're replying to me about something someone else asked you.
Please show the output of the directory listing.
Please us ls -la
echo exec('ls -la orders.txt');
-rw-rw-rw- 1 ethan ethan 43 Aug 25 23:50 orders.txt
Maybe you don't have write permissions on the folder?
If I perform the touch and chmod from the command line, everything works.
When you say does not work, can you show what is actually not working? I
believe the exec and system functions are likely working just fine, but
that
the commands you've passed to them may not be.
Here are my commands.
if( !file_exists(/var/www/orders.txt));
{
echo system(touch /var/www/orders.txt, $ret);
echo system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
If I now try a ls from the command line, the return is
cannot access /var/www/orders.txt: No such file or directory
The ls -la works because the file was created from the command line.
TIA
Ethan
--
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--
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Re: [PHP] How to send post-variables in a Location header
On Aug 26, 2013, at 2:48 PM, Ajay Garg ajaygargn...@gmail.com wrote:
Hi all.
I have a scenario, wherein I need to do something like this ::
###
$original_url = /autologin.php;
$username = ajay;
$password = garg;
header('Location: ' . $original_url);
###
As can be seen, I wish to redirect to the URL autologin.php.
Additionally, I wish to pass two POST key-value pairs :: user=ajay and
password=garg (I understand that passing GET key-value pairs is trivial).
Is it even possible?
If yes, I will be grateful if someone could let me know how to redirect to
a URL, passing the POST key-value pairs as necessary.
Looking forward to a reply :)
Since this seems that it will not work, I'm wondering if you could take a step
back for us and say what is it you're hoping to accomplish by this. Maybe
there's a better way to get you what you need that is possible, and also will
be good PHP. Describe your scenario in higher level terms, not how you'd
implement it, but what the outcome you need is, and what the design goal is for
the user.
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Re: [PHP] exec and system do not work
On 08/26/2013 03:28 PM, Jim Giner wrote:
On 8/26/2013 2:41 PM, Ethan Rosenberg wrote:
On 08/26/2013 11:36 AM, ma...@behnke.biz wrote:
Tamara Temple tamouse.li...@gmail.com hat am 26. August 2013 um 08:33
geschrieben:
On Aug 25, 2013, at 10:41 PM, Ethan Rosenberg
erosenb...@hygeiabiomedical.com wrote:
Dear List -
I'm lost on this one -
This works -
$out = system(ls -l ,$retvals);
printf(%s, $out);
This does -
echo exec(ls -l);
Please show the output of the directory listing.
Please us ls -la
This does not -
if( !file_exists(/var/www/orders.txt));
{
$out = system(touch /var/www/orders.txt, $ret);
Maybe you don't have write permissions on the folder?
$out2 = system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
and this does not -
if( !file_exists(/var/www/orders.txt));
{
exec(touch /var/www/orders.txt);
exec(chmod 766 /var/www/orders.txt);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
Ethan
When you say does not work, can you show what is actually not
working? I
believe the exec and system functions are likely working just fine,
but that
the commands you've passed to them may not be.
--
Marco Behnke
Dipl. Informatiker (FH), SAE Audio Engineer Diploma
Zend Certified Engineer PHP 5.3
Tel.: 0174 / 9722336
e-Mail: ma...@behnke.biz
Softwaretechnik Behnke
Heinrich-Heine-Str. 7D
21218 Seevetal
http://www.behnke.biz
Tamara -
Please show the output of the directory listing.
Please us ls -la
echo exec('ls -la orders.txt');
-rw-rw-rw- 1 ethan ethan 43 Aug 25 23:50 orders.txt
Maybe you don't have write permissions on the folder?
If I perform the touch and chmod from the command line, everything works.
When you say does not work, can you show what is actually not
working? I
believe the exec and system functions are likely working just fine,
but that
the commands you've passed to them may not be.
Here are my commands.
if( !file_exists(/var/www/orders.txt));
{
echo system(touch /var/www/orders.txt, $ret);
echo system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
If I now try a ls from the command line, the return is
cannot access /var/www/orders.txt: No such file or directory
The ls -la works because the file was created from the command line.
TIA
Ethan
Ethan - YOU'RE DOING IT AGAIN!!!
Either you are not using error checking AGAIN!!
OR
You are showing us re-typed in code that YOU DIDNT ACTUALLY RUN.
I've told you multiple times that you need to do these two things and
you are back at it again.
The sample php above has plain simple syntax errors that would keep it
from running, which error checking would tell you IF YOU RAN IT.
Jim -
Thank you.
I don't totally understand your reply ...
but I will try to answer
The code is taken from an operating program. My error checking is set
to maximum sensitivity.
If you would point out my syntax errors, I will fix them.
TIA
Ethan
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[PHP] Re: exec and system do not work
On 26 Aug 2013 at 22:01, PhD Ethan Rosenberg erosenb...@hygeiabiomedical.com
wrote:
if( !file_exists(/var/www/orders.txt));
^
|
What's the semicolon doing there ---+
{
echo system(touch /var/www/orders.txt, $ret);
echo system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
If you would point out my syntax errors, I will fix them.
See above.
--
Cheers -- Tim
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Re: [PHP] exec and system do not work
Ethan Rosenberg wrote:
On 08/26/2013 11:36 AM, ma...@behnke.biz wrote:
Tamara Temple tamouse.li...@gmail.com hat am 26. August 2013 um 08:33
geschrieben:
On Aug 25, 2013, at 10:41 PM, Ethan Rosenberg
erosenb...@hygeiabiomedical.com wrote:
Dear List -
I'm lost on this one -
This works -
$out = system(ls -l ,$retvals);
printf(%s, $out);
This does -
echo exec(ls -l);
Please show the output of the directory listing.
Please us ls -la
This does not -
if( !file_exists(/var/www/orders.txt));
{
$out = system(touch /var/www/orders.txt, $ret);
Maybe you don't have write permissions on the folder?
$out2 = system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
and this does not -
if( !file_exists(/var/www/orders.txt));
{
exec(touch /var/www/orders.txt);
exec(chmod 766 /var/www/orders.txt);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
Ethan
When you say does not work, can you show what is actually not working?
I believe the exec and system functions are likely working just fine,
but that the commands you've passed to them may not be.
--
Marco Behnke
Dipl. Informatiker (FH), SAE Audio Engineer Diploma
Zend Certified Engineer PHP 5.3
Tel.: 0174 / 9722336
e-Mail: ma...@behnke.biz
Softwaretechnik Behnke
Heinrich-Heine-Str. 7D
21218 Seevetal
http://www.behnke.biz
Tamara -
Please show the output of the directory listing.
Please us ls -la
echo exec('ls -la orders.txt');
-rw-rw-rw- 1 ethan ethan 43 Aug 25 23:50 orders.txt
Maybe you don't have write permissions on the folder?
If I perform the touch and chmod from the command line, everything works.
When you say does not work, can you show what is actually not
working? I
believe the exec and system functions are likely working just fine,
but that
the commands you've passed to them may not be.
Here are my commands.
if( !file_exists(/var/www/orders.txt));
{
echo system(touch /var/www/orders.txt, $ret);
echo system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
If I now try a ls from the command line, the return is
cannot access /var/www/orders.txt: No such file or directory
The ls -la works because the file was created from the command line.
TIA
Ethan
Note that touch and chmod don't return any output, so echoing the result of
a system call for those commands will give an empty string.
You should be checking the values of $ret for each execution of system to
see whether the command was successful or not - the return status of the
executed command will be written to this variable. I'd guess that touch is
returning 13 - permission denied.
if( !file_exists(/var/www/orders.txt))
{
system(touch /var/www/orders.txt, $ret1);
echo 'touch returned '.$ret1.'br /';
system(chmod 766 /var/www/orders.txt, $ret2);
echo 'chmod returned ' .$ret2.'br /';
echo 'file2br /';
echo file_exists(/var/www/orders.txt); }
Check the permissions for directory /var/www; you'll probably find it is
writable by the user you log on as, but not by the user that apache/php runs
as, which is often www - a user with limited privileges.
As other(s) have pointed out, there are php functions to do what you want
without introducing the possible insecurities involved with system et al.
--
Cheers
David Robley
Don't try to pull the wool over my eyes, Tom said sheepishly.
--
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Re: [PHP] exec and system do not work
Ethan Rosenberg, PhD
/Pres/CEO/
*Hygeia Biomedical Research, Inc*
2 Cameo Ridge Road
Monsey, NY 10952
T: 845 352-3908
F: 845 352-7566
erosenb...@hygeiabiomedical.com
On 08/26/2013 07:33 PM, David Robley wrote:
Ethan Rosenberg wrote:
On 08/26/2013 11:36 AM, ma...@behnke.biz wrote:
Tamara Temple tamouse.li...@gmail.com hat am 26. August 2013 um 08:33
geschrieben:
On Aug 25, 2013, at 10:41 PM, Ethan Rosenberg
erosenb...@hygeiabiomedical.com wrote:
Dear List -
I'm lost on this one -
This works -
$out = system(ls -l ,$retvals);
printf(%s, $out);
This does -
echo exec(ls -l);
Please show the output of the directory listing.
Please us ls -la
This does not -
if( !file_exists(/var/www/orders.txt));
{
$out = system(touch /var/www/orders.txt, $ret);
Maybe you don't have write permissions on the folder?
$out2 = system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
and this does not -
if( !file_exists(/var/www/orders.txt));
{
exec(touch /var/www/orders.txt);
exec(chmod 766 /var/www/orders.txt);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
Ethan
When you say does not work, can you show what is actually not working?
I believe the exec and system functions are likely working just fine,
but that the commands you've passed to them may not be.
--
Marco Behnke
Dipl. Informatiker (FH), SAE Audio Engineer Diploma
Zend Certified Engineer PHP 5.3
Tel.: 0174 / 9722336
e-Mail: ma...@behnke.biz
Softwaretechnik Behnke
Heinrich-Heine-Str. 7D
21218 Seevetal
http://www.behnke.biz
Tamara -
Please show the output of the directory listing.
Please us ls -la
echo exec('ls -la orders.txt');
-rw-rw-rw- 1 ethan ethan 43 Aug 25 23:50 orders.txt
Maybe you don't have write permissions on the folder?
If I perform the touch and chmod from the command line, everything works.
When you say does not work, can you show what is actually not
working? I
believe the exec and system functions are likely working just fine,
but that
the commands you've passed to them may not be.
Here are my commands.
if( !file_exists(/var/www/orders.txt));
{
echo system(touch /var/www/orders.txt, $ret);
echo system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
If I now try a ls from the command line, the return is
cannot access /var/www/orders.txt: No such file or directory
The ls -la works because the file was created from the command line.
TIA
Ethan
Note that touch and chmod don't return any output, so echoing the result of
a system call for those commands will give an empty string.
You should be checking the values of $ret for each execution of system to
see whether the command was successful or not - the return status of the
executed command will be written to this variable. I'd guess that touch is
returning 13 - permission denied.
if( !file_exists(/var/www/orders.txt))
{
system(touch /var/www/orders.txt, $ret1);
echo 'touch returned '.$ret1.'br /';
system(chmod 766 /var/www/orders.txt, $ret2);
echo 'chmod returned ' .$ret2.'br /';
echo 'file2br /';
echo file_exists(/var/www/orders.txt); }
Check the permissions for directory /var/www; you'll probably find it is
writable by the user you log on as, but not by the user that apache/php runs
as, which is often www - a user with limited privileges.
As other(s) have pointed out, there are php functions to do what you want
without introducing the possible insecurities involved with system et al.
David -
touch returned 1
/chmod returned 1
rosenberg:/var/www# ls orders.txt
ls: cannot access orders.txt: No such file or directory
rosenberg:/var# ls -ld www
drwxr-xr-x 37 ethan ethan 20480 Aug 26 20:15 www
TIA
Ethan
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Re: [PHP] exec and system do not work
Ethan,
A return code of not 0 means an error occured.
Probably /var/www is not writable. Test that one by doing this:
$a = is_writable(/var/www);
var_dump($a);
If that says anything else than (boolean) TRUE, you can't write in the
directory.
Sincerely,
Jasper Kips
Op 27 aug. 2013, om 02:32 heeft Ethan Rosenberg, PhD
erosenb...@hygeiabiomedical.com het volgende geschreven:
Ethan Rosenberg, PhD
/Pres/CEO/
*Hygeia Biomedical Research, Inc*
2 Cameo Ridge Road
Monsey, NY 10952
T: 845 352-3908
F: 845 352-7566
erosenb...@hygeiabiomedical.com
On 08/26/2013 07:33 PM, David Robley wrote:
Ethan Rosenberg wrote:
On 08/26/2013 11:36 AM, ma...@behnke.biz wrote:
Tamara Temple tamouse.li...@gmail.com hat am 26. August 2013 um 08:33
geschrieben:
On Aug 25, 2013, at 10:41 PM, Ethan Rosenberg
erosenb...@hygeiabiomedical.com wrote:
Dear List -
I'm lost on this one -
This works -
$out = system(ls -l ,$retvals);
printf(%s, $out);
This does -
echo exec(ls -l);
Please show the output of the directory listing.
Please us ls -la
This does not -
if( !file_exists(/var/www/orders.txt));
{
$out = system(touch /var/www/orders.txt, $ret);
Maybe you don't have write permissions on the folder?
$out2 = system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
and this does not -
if( !file_exists(/var/www/orders.txt));
{
exec(touch /var/www/orders.txt);
exec(chmod 766 /var/www/orders.txt);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
Ethan
When you say does not work, can you show what is actually not working?
I believe the exec and system functions are likely working just fine,
but that the commands you've passed to them may not be.
--
Marco Behnke
Dipl. Informatiker (FH), SAE Audio Engineer Diploma
Zend Certified Engineer PHP 5.3
Tel.: 0174 / 9722336
e-Mail: ma...@behnke.biz
Softwaretechnik Behnke
Heinrich-Heine-Str. 7D
21218 Seevetal
http://www.behnke.biz
Tamara -
Please show the output of the directory listing.
Please us ls -la
echo exec('ls -la orders.txt');
-rw-rw-rw- 1 ethan ethan 43 Aug 25 23:50 orders.txt
Maybe you don't have write permissions on the folder?
If I perform the touch and chmod from the command line, everything works.
When you say does not work, can you show what is actually not
working? I
believe the exec and system functions are likely working just fine,
but that
the commands you've passed to them may not be.
Here are my commands.
if( !file_exists(/var/www/orders.txt));
{
echo system(touch /var/www/orders.txt, $ret);
echo system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
If I now try a ls from the command line, the return is
cannot access /var/www/orders.txt: No such file or directory
The ls -la works because the file was created from the command line.
TIA
Ethan
Note that touch and chmod don't return any output, so echoing the result of
a system call for those commands will give an empty string.
You should be checking the values of $ret for each execution of system to
see whether the command was successful or not - the return status of the
executed command will be written to this variable. I'd guess that touch is
returning 13 - permission denied.
if( !file_exists(/var/www/orders.txt))
{
system(touch /var/www/orders.txt, $ret1);
echo 'touch returned '.$ret1.'br /';
system(chmod 766 /var/www/orders.txt, $ret2);
echo 'chmod returned ' .$ret2.'br /';
echo 'file2br /';
echo file_exists(/var/www/orders.txt); }
Check the permissions for directory /var/www; you'll probably find it is
writable by the user you log on as, but not by the user that apache/php runs
as, which is often www - a user with limited privileges.
As other(s) have pointed out, there are php functions to do what you want
without introducing the possible insecurities involved with system et al.
David -
touch returned 1
/chmod returned 1
rosenberg:/var/www# ls orders.txt
ls: cannot access orders.txt: No such file or directory
rosenberg:/var# ls -ld www
drwxr-xr-x 37 ethan ethan 20480 Aug 26 20:15 www
TIA
Ethan
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Re: [PHP] exec and system do not work
Ethan Rosenberg, PhD wrote:
Ethan Rosenberg, PhD
/Pres/CEO/
*Hygeia Biomedical Research, Inc*
2 Cameo Ridge Road
Monsey, NY 10952
T: 845 352-3908
F: 845 352-7566
erosenb...@hygeiabiomedical.com
On 08/26/2013 07:33 PM, David Robley wrote:
Ethan Rosenberg wrote:
On 08/26/2013 11:36 AM, ma...@behnke.biz wrote:
Tamara Temple tamouse.li...@gmail.com hat am 26. August 2013 um
08:33 geschrieben:
On Aug 25, 2013, at 10:41 PM, Ethan Rosenberg
erosenb...@hygeiabiomedical.com wrote:
Dear List -
I'm lost on this one -
This works -
$out = system(ls -l ,$retvals);
printf(%s, $out);
This does -
echo exec(ls -l);
Please show the output of the directory listing.
Please us ls -la
This does not -
if( !file_exists(/var/www/orders.txt));
{
$out = system(touch /var/www/orders.txt, $ret);
Maybe you don't have write permissions on the folder?
$out2 = system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
and this does not -
if( !file_exists(/var/www/orders.txt));
{
exec(touch /var/www/orders.txt);
exec(chmod 766 /var/www/orders.txt);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
Ethan
When you say does not work, can you show what is actually not
working? I believe the exec and system functions are likely working
just fine, but that the commands you've passed to them may not be.
--
Marco Behnke
Dipl. Informatiker (FH), SAE Audio Engineer Diploma
Zend Certified Engineer PHP 5.3
Tel.: 0174 / 9722336
e-Mail: ma...@behnke.biz
Softwaretechnik Behnke
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Tamara -
Please show the output of the directory listing.
Please us ls -la
echo exec('ls -la orders.txt');
-rw-rw-rw- 1 ethan ethan 43 Aug 25 23:50 orders.txt
Maybe you don't have write permissions on the folder?
If I perform the touch and chmod from the command line, everything
works.
When you say does not work, can you show what is actually not
working? I
believe the exec and system functions are likely working just fine,
but that
the commands you've passed to them may not be.
Here are my commands.
if( !file_exists(/var/www/orders.txt));
{
echo system(touch /var/www/orders.txt, $ret);
echo system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
If I now try a ls from the command line, the return is
cannot access /var/www/orders.txt: No such file or directory
The ls -la works because the file was created from the command line.
TIA
Ethan
Note that touch and chmod don't return any output, so echoing the result
of a system call for those commands will give an empty string.
You should be checking the values of $ret for each execution of system to
see whether the command was successful or not - the return status of the
executed command will be written to this variable. I'd guess that touch
is returning 13 - permission denied.
if( !file_exists(/var/www/orders.txt))
{
system(touch /var/www/orders.txt, $ret1);
echo 'touch returned '.$ret1.'br /';
system(chmod 766 /var/www/orders.txt, $ret2);
echo 'chmod returned ' .$ret2.'br /';
echo 'file2br /';
echo file_exists(/var/www/orders.txt); }
Check the permissions for directory /var/www; you'll probably find it is
writable by the user you log on as, but not by the user that apache/php
runs as, which is often www - a user with limited privileges.
As other(s) have pointed out, there are php functions to do what you want
without introducing the possible insecurities involved with system et al.
David -
touch returned 1
/chmod returned 1
Non-zero return value indicates an error; touch failed and as a result there
is no file to chmod, hence chmod also failed.
rosenberg:/var/www# ls orders.txt
ls: cannot access orders.txt: No such file or directory
rosenberg:/var# ls -ld www
drwxr-xr-x 37 ethan ethan 20480 Aug 26 20:15 www
/var/www is only writeable by the user ethan
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David Robley
INTERLACE: To tie two boots together.
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[PHP] Permissions
Dear List - Tried to run the program, that we have been discussing, and received a 403 error. rosenberg:/var/www# ls -la StoreInventory.php -rwxrwxrw- 1 ethan ethan 4188 Aug 26 20:26 StoreInventory.php rosenberg:/var# ls -ld www drwxrwxrw- 37 ethan ethan 20480 Aug 26 20:26 www I had set the S bit [probably a nasty mistake] and I thought I was able to remove the bit. [it doesn't show above] How do I extricate myself from the hole into which I have planted myself? TIA Ethan -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
php-general Digest 25 Aug 2013 09:31:34 -0000 Issue 8343
php-general Digest 25 Aug 2013 09:31:34 - Issue 8343 Topics (messages 321960 through 321964): Re: Alternate list for eclipse ide support? 321960 by: Sebastian Krebs 321961 by: Lester Caine 321962 by: Sebastian Krebs 321963 by: Lester Caine PHP-5.5.2 +opcache segfaults with Piwik 321964 by: Grant Administrivia: To subscribe to the digest, e-mail: php-general-digest-subscr...@lists.php.net To unsubscribe from the digest, e-mail: php-general-digest-unsubscr...@lists.php.net To post to the list, e-mail: php-gene...@lists.php.net -- ---BeginMessage--- 2013/8/24 Lester Caine les...@lsces.co.uk With composer being pushed as the 'in way to go' and not being able to see how to get some code relating to bootstrap and smarty development because the links only show composer I've downloaded a plug-in for eclipse that is supposed to handle that. But it's not working as I expect, and while heading over to the plug-ins developers is the obvious step, what I'd actually prefer is a more general PHP/Eclipse list to discuss general IDE problems rather than even PDT biased discussions. Is there a suitable list? And if not is there any interest in setting one up? ... at the risk of proliferating even more lists ... Hi, I for myself switched over to PhpStorm from Eclipse/PDT and I fear meany hear use either PhpStorm, or Netbeans in the meantime. I'm not saying, that nobody is using Eclipse/PDT anymore, but I fear you wont find much interest here. Regards, Sebastian -- Lester Caine - G8HFL - Contact - http://lsces.co.uk/wiki/?page=**contacthttp://lsces.co.uk/wiki/?page=contact L.S.Caine Electronic Services - http://lsces.co.uk EnquirySolve - http://enquirysolve.com/ Model Engineers Digital Workshop - http://medw.co.uk Rainbow Digital Media - http://rainbowdigitalmedia.co.**ukhttp://rainbowdigitalmedia.co.uk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- github.com/KingCrunch ---End Message--- ---BeginMessage--- Sebastian Krebs wrote: With composer being pushed as the 'in way to go' and not being able to see how to get some code relating to bootstrap and smarty development because the links only show composer I've downloaded a plug-in for eclipse that is supposed to handle that. But it's not working as I expect, and while heading over to the plug-ins developers is the obvious step, what I'd actually prefer is a more general PHP/Eclipse list to discuss general IDE problems rather than even PDT biased discussions. Is there a suitable list? And if not is there any interest in setting one up? ... at the risk of proliferating even more lists ... I for myself switched over to PhpStorm from Eclipse/PDT and I fear meany hear use either PhpStorm, or Netbeans in the meantime. I'm not saying, that nobody is using Eclipse/PDT anymore, but I fear you wont find much interest here. I'm still on PHPEclipse for PHP. PDT just does not work for me, and neither did Netbeans for some of the other languages I have to live with, which is why PHPStorm is no use either. I need python in addition to C/C++ with document handling, and firebird which don't get any support from either so Eclipse is really my only option. -- Lester Caine - G8HFL - Contact - http://lsces.co.uk/wiki/?page=contact L.S.Caine Electronic Services - http://lsces.co.uk EnquirySolve - http://enquirysolve.com/ Model Engineers Digital Workshop - http://medw.co.uk Rainbow Digital Media - http://rainbowdigitalmedia.co.uk ---End Message--- ---BeginMessage--- 2013/8/24 Lester Caine les...@lsces.co.uk Sebastian Krebs wrote: With composer being pushed as the 'in way to go' and not being able to see how to get some code relating to bootstrap and smarty development because the links only show composer I've downloaded a plug-in for eclipse that is supposed to handle that. But it's not working as I expect, and while heading over to the plug-ins developers is the obvious step, what I'd actually prefer is a more general PHP/Eclipse list to discuss general IDE problems rather than even PDT biased discussions. Is there a suitable list? And if not is there any interest in setting one up? ... at the risk of proliferating even more lists ... I for myself switched over to PhpStorm from Eclipse/PDT and I fear meany hear use either PhpStorm, or Netbeans in the meantime. I'm not saying, that nobody is using Eclipse/PDT anymore, but I fear you wont find much interest here. I'm still on PHPEclipse for PHP. PDT just does not work for me, and neither did Netbeans for some of the other languages I have to live with, which is why PHPStorm is no use either. PHPEclipse is still in development? O_o The last time I noticed it, it looked abandoned. However, if it works for you
php-general Digest 26 Aug 2013 03:41:12 -0000 Issue 8344
php-general Digest 26 Aug 2013 03:41:12 - Issue 8344
Topics (messages 321965 through 321965):
exec and system do not work
321965 by: Ethan Rosenberg
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---BeginMessage---
Dear List -
I'm lost on this one -
This works -
$out = system(ls -l ,$retvals);
printf(%s, $out);
This does -
echo exec(ls -l);
This does not -
if( !file_exists(/var/www/orders.txt));
{
$out = system(touch /var/www/orders.txt, $ret);
$out2 = system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
and this does not -
if( !file_exists(/var/www/orders.txt));
{
exec(touch /var/www/orders.txt);
exec(chmod 766 /var/www/orders.txt);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
Ethan
---End Message---
[PHP] PHP-5.5.2 +opcache segfaults with Piwik
I've tried php-5.5.2 and 5.5.3 but both segfault with piwik unless the opcache is disabled. Someone filed a piwik bug but was told it's a php bug: http://dev.piwik.org/trac/ticket/4093 - Grant -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] exec and system do not work
Dear List -
I'm lost on this one -
This works -
$out = system(ls -l ,$retvals);
printf(%s, $out);
This does -
echo exec(ls -l);
This does not -
if( !file_exists(/var/www/orders.txt));
{
$out = system(touch /var/www/orders.txt, $ret);
$out2 = system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
and this does not -
if( !file_exists(/var/www/orders.txt));
{
exec(touch /var/www/orders.txt);
exec(chmod 766 /var/www/orders.txt);
echo 'file2br /';
echo file_exists(/var/www/orders.txt);
}
Ethan
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Re: [PHP] exec and system do not work
*/var/www* is usually under *www* user. It may be a permissions problem.
On Mon, Aug 26, 2013 at 6:41 AM, Ethan Rosenberg
erosenb...@hygeiabiomedical.com wrote:
Dear List -
I'm lost on this one -
This works -
$out = system(ls -l ,$retvals);
printf(%s, $out);
This does -
echo exec(ls -l);
This does not -
if( !file_exists(/var/www/orders.**txt));
{
$out = system(touch /var/www/orders.txt, $ret);
$out2 = system(chmod 766 /var/www/orders.txt, $ret);
echo 'file2br /';
echo file_exists(/var/www/orders.**txt);
}
and this does not -
if( !file_exists(/var/www/orders.**txt));
{
exec(touch /var/www/orders.txt);
exec(chmod 766 /var/www/orders.txt);
echo 'file2br /';
echo file_exists(/var/www/orders.**txt);
}
Ethan
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php-general Digest 24 Aug 2013 11:45:26 -0000 Issue 8342
php-general Digest 24 Aug 2013 11:45:26 - Issue 8342 Topics (messages 321955 through 321959): Re: windows files and folders permission 321955 by: Carlos Medina files and folders windows permission 321956 by: Emiliano Boragina 321957 by: Matijn Woudt 321958 by: Maciek Sokolewicz Alternate list for eclipse ide support? 321959 by: Lester Caine Administrivia: To subscribe to the digest, e-mail: php-general-digest-subscr...@lists.php.net To unsubscribe from the digest, e-mail: php-general-digest-unsubscr...@lists.php.net To post to the list, e-mail: php-gene...@lists.php.net -- ---BeginMessage--- Hola Emiliano, i think you should to redefine your question because i can not understand what you want. Please post parts of the code, examples, errors, etc. regards Carlos Medina Am 23.08.2013 06:28, schrieb Emiliano Boragina: Night everyone, I did a upload page and when upload a JPG file this is not available. Why this happens? Thanks a lot. Emiliano Boragina | gráfico + web desarrollos comunicación + 15 33 92 60 02 » emiliano.borag...@gmail.com © 2013 ---End Message--- ---BeginMessage--- Hi everyone, sorry my ugly english. I did an upload file form. Works very good. Upload the files in the right folder, with the right name. I use chmod 0644, and for try I use 0777. But always the files are copyed blocked. I cant see them with windows preview for example. I read in forums that is Windows fault. How can I fix this? Thanks a lot. -- Emiliano Boragina | gráfico + web desarrollos comunicación + 15 33 92 60 02 » emiliano.borag...@gmail.com © 2013 ---End Message--- ---BeginMessage--- On Fri, Aug 23, 2013 at 4:03 PM, Emiliano Boragina emiliano.borag...@gmail.com wrote: Hi everyone, sorry my ugly english. I did an upload file form. Works very good. Upload the files in the right folder, with the right name. I use chmod 0644, and for try I use 0777. But always the files are copyed blocked. I cant see them with windows preview for example. I read in forums that is Windows fault. How can I fix this? Thanks a lot. Code? ---End Message--- ---BeginMessage--- On 23-8-2013 16:37, Matijn Woudt wrote: On Fri, Aug 23, 2013 at 4:03 PM, Emiliano Boragina emiliano.borag...@gmail.com wrote: Hi everyone, sorry my ugly english. I did an upload file form. Works very good. Upload the files in the right folder, with the right name. I use chmod 0644, and for try I use 0777. But always the files are copyed blocked. I cant see them with windows preview for example. I read in forums that is Windows fault. How can I fix this? Thanks a lot. Code? On a sidenote, how the hell did you manage to chmod files on _windows_ ??? ---End Message--- ---BeginMessage--- With composer being pushed as the 'in way to go' and not being able to see how to get some code relating to bootstrap and smarty development because the links only show composer I've downloaded a plug-in for eclipse that is supposed to handle that. But it's not working as I expect, and while heading over to the plug-ins developers is the obvious step, what I'd actually prefer is a more general PHP/Eclipse list to discuss general IDE problems rather than even PDT biased discussions. Is there a suitable list? And if not is there any interest in setting one up? ... at the risk of proliferating even more lists ... -- Lester Caine - G8HFL - Contact - http://lsces.co.uk/wiki/?page=contact L.S.Caine Electronic Services - http://lsces.co.uk EnquirySolve - http://enquirysolve.com/ Model Engineers Digital Workshop - http://medw.co.uk Rainbow Digital Media - http://rainbowdigitalmedia.co.uk ---End Message---
[PHP] Alternate list for eclipse ide support?
With composer being pushed as the 'in way to go' and not being able to see how to get some code relating to bootstrap and smarty development because the links only show composer I've downloaded a plug-in for eclipse that is supposed to handle that. But it's not working as I expect, and while heading over to the plug-ins developers is the obvious step, what I'd actually prefer is a more general PHP/Eclipse list to discuss general IDE problems rather than even PDT biased discussions. Is there a suitable list? And if not is there any interest in setting one up? ... at the risk of proliferating even more lists ... -- Lester Caine - G8HFL - Contact - http://lsces.co.uk/wiki/?page=contact L.S.Caine Electronic Services - http://lsces.co.uk EnquirySolve - http://enquirysolve.com/ Model Engineers Digital Workshop - http://medw.co.uk Rainbow Digital Media - http://rainbowdigitalmedia.co.uk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Alternate list for eclipse ide support?
2013/8/24 Lester Caine les...@lsces.co.uk With composer being pushed as the 'in way to go' and not being able to see how to get some code relating to bootstrap and smarty development because the links only show composer I've downloaded a plug-in for eclipse that is supposed to handle that. But it's not working as I expect, and while heading over to the plug-ins developers is the obvious step, what I'd actually prefer is a more general PHP/Eclipse list to discuss general IDE problems rather than even PDT biased discussions. Is there a suitable list? And if not is there any interest in setting one up? ... at the risk of proliferating even more lists ... Hi, I for myself switched over to PhpStorm from Eclipse/PDT and I fear meany hear use either PhpStorm, or Netbeans in the meantime. I'm not saying, that nobody is using Eclipse/PDT anymore, but I fear you wont find much interest here. Regards, Sebastian -- Lester Caine - G8HFL - Contact - http://lsces.co.uk/wiki/?page=**contacthttp://lsces.co.uk/wiki/?page=contact L.S.Caine Electronic Services - http://lsces.co.uk EnquirySolve - http://enquirysolve.com/ Model Engineers Digital Workshop - http://medw.co.uk Rainbow Digital Media - http://rainbowdigitalmedia.co.**ukhttp://rainbowdigitalmedia.co.uk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- github.com/KingCrunch
Re: [PHP] Alternate list for eclipse ide support?
Sebastian Krebs wrote: With composer being pushed as the 'in way to go' and not being able to see how to get some code relating to bootstrap and smarty development because the links only show composer I've downloaded a plug-in for eclipse that is supposed to handle that. But it's not working as I expect, and while heading over to the plug-ins developers is the obvious step, what I'd actually prefer is a more general PHP/Eclipse list to discuss general IDE problems rather than even PDT biased discussions. Is there a suitable list? And if not is there any interest in setting one up? ... at the risk of proliferating even more lists ... I for myself switched over to PhpStorm from Eclipse/PDT and I fear meany hear use either PhpStorm, or Netbeans in the meantime. I'm not saying, that nobody is using Eclipse/PDT anymore, but I fear you wont find much interest here. I'm still on PHPEclipse for PHP. PDT just does not work for me, and neither did Netbeans for some of the other languages I have to live with, which is why PHPStorm is no use either. I need python in addition to C/C++ with document handling, and firebird which don't get any support from either so Eclipse is really my only option. -- Lester Caine - G8HFL - Contact - http://lsces.co.uk/wiki/?page=contact L.S.Caine Electronic Services - http://lsces.co.uk EnquirySolve - http://enquirysolve.com/ Model Engineers Digital Workshop - http://medw.co.uk Rainbow Digital Media - http://rainbowdigitalmedia.co.uk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Alternate list for eclipse ide support?
2013/8/24 Lester Caine les...@lsces.co.uk Sebastian Krebs wrote: With composer being pushed as the 'in way to go' and not being able to see how to get some code relating to bootstrap and smarty development because the links only show composer I've downloaded a plug-in for eclipse that is supposed to handle that. But it's not working as I expect, and while heading over to the plug-ins developers is the obvious step, what I'd actually prefer is a more general PHP/Eclipse list to discuss general IDE problems rather than even PDT biased discussions. Is there a suitable list? And if not is there any interest in setting one up? ... at the risk of proliferating even more lists ... I for myself switched over to PhpStorm from Eclipse/PDT and I fear meany hear use either PhpStorm, or Netbeans in the meantime. I'm not saying, that nobody is using Eclipse/PDT anymore, but I fear you wont find much interest here. I'm still on PHPEclipse for PHP. PDT just does not work for me, and neither did Netbeans for some of the other languages I have to live with, which is why PHPStorm is no use either. PHPEclipse is still in development? O_o The last time I noticed it, it looked abandoned. However, if it works for you, there is nothing wrong with it. (Just realized: There are really back in business. Interesting ^^) I need python in addition to C/C++ with document handling, and firebird which don't get any support from either so Eclipse is really my only option. Well, Firebird is quite specific (dont know if its supported bei the IntelliJ-platform), but for Python and C Jetbrains has other IDEs (PyCharm, AppCode) :D Just saying: There _are_ alternatives :) However, my last mail wasn't about telling you, that your IDE is bad. But I have the feeling, that this audience may be simply not interested. Regards, Sebastian -- Lester Caine - G8HFL - Contact - http://lsces.co.uk/wiki/?page=**contacthttp://lsces.co.uk/wiki/?page=contact L.S.Caine Electronic Services - http://lsces.co.uk EnquirySolve - http://enquirysolve.com/ Model Engineers Digital Workshop - http://medw.co.uk Rainbow Digital Media - http://rainbowdigitalmedia.co.**ukhttp://rainbowdigitalmedia.co.uk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- github.com/KingCrunch
Re: [PHP] Alternate list for eclipse ide support?
Sebastian Krebs wrote: However, my last mail wasn't about telling you, that your IDE is bad. But I have the feeling, that this audience may be simply not interested. I'm only using Java in order to make tweaks to PHPEclipse and and other support packages. ( and the same with python ). We could do with more support in these areas, and comments like yours don't help, but there IS enough interest from users dissatisfied with the alternatives ... The problem is that there are perhaps too many options and combining the activities of a few would create a more popular common base? The vast number of different 'frameworks' add further to the dilution of effort. It's a pity that there is not a single universally accepted development base in addition to a single IDE into which support could be pooled. It's not going to happen as PHP now has too many diverse ways of doing the same thing? :( -- Lester Caine - G8HFL - Contact - http://lsces.co.uk/wiki/?page=contact L.S.Caine Electronic Services - http://lsces.co.uk EnquirySolve - http://enquirysolve.com/ Model Engineers Digital Workshop - http://medw.co.uk Rainbow Digital Media - http://rainbowdigitalmedia.co.uk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: windows files and folders permission
Hola Emiliano, i think you should to redefine your question because i can not understand what you want. Please post parts of the code, examples, errors, etc. regards Carlos Medina Am 23.08.2013 06:28, schrieb Emiliano Boragina: Night everyone, I did a upload page and when upload a JPG file this is not available. Why this happens? Thanks a lot. Emiliano Boragina | gráfico + web desarrollos comunicación + 15 33 92 60 02 » emiliano.borag...@gmail.com © 2013 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] files and folders windows permission
Hi everyone, sorry my ugly english. I did an upload file form. Works very good. Upload the files in the right folder, with the right name. I use chmod 0644, and for try I use 0777. But always the files are copyed blocked. I cant see them with windows preview for example. I read in forums that is Windows fault. How can I fix this? Thanks a lot. -- Emiliano Boragina | gráfico + web desarrollos comunicación + 15 33 92 60 02 » emiliano.borag...@gmail.com © 2013 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] files and folders windows permission
On Fri, Aug 23, 2013 at 4:03 PM, Emiliano Boragina emiliano.borag...@gmail.com wrote: Hi everyone, sorry my ugly english. I did an upload file form. Works very good. Upload the files in the right folder, with the right name. I use chmod 0644, and for try I use 0777. But always the files are copyed blocked. I cant see them with windows preview for example. I read in forums that is Windows fault. How can I fix this? Thanks a lot. Code?
Re: [PHP] files and folders windows permission
On 23-8-2013 16:37, Matijn Woudt wrote: On Fri, Aug 23, 2013 at 4:03 PM, Emiliano Boragina emiliano.borag...@gmail.com wrote: Hi everyone, sorry my ugly english. I did an upload file form. Works very good. Upload the files in the right folder, with the right name. I use chmod 0644, and for try I use 0777. But always the files are copyed blocked. I cant see them with windows preview for example. I read in forums that is Windows fault. How can I fix this? Thanks a lot. Code? On a sidenote, how the hell did you manage to chmod files on _windows_ ??? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
php-general Digest 22 Aug 2013 15:34:18 -0000 Issue 8340
php-general Digest 22 Aug 2013 15:34:18 - Issue 8340 Topics (messages 321944 through 321952): Re: PHP vs JAVA 321944 by: David Harkness 321945 by: Sebastian Krebs 321952 by: David Harkness Re: Off the wall - sub-domain question 321946 by: Curtis Maurand 321947 by: Jim Giner 321948 by: Willie 321949 by: Jim Giner 321950 by: Dan McCullough 321951 by: Lester Caine Administrivia: To subscribe to the digest, e-mail: php-general-digest-subscr...@lists.php.net To unsubscribe from the digest, e-mail: php-general-digest-unsubscr...@lists.php.net To post to the list, e-mail: php-gene...@lists.php.net -- ---BeginMessage--- On Wed, Aug 21, 2013 at 7:56 PM, Curtis Maurand cur...@maurand.com wrote: Sebastian Krebs wrote: Actually the problem is, that the dot . is already in use. With $foo.bar() you cannot tell, if you want to call the method bar() on the object $foo, or if you want to concatenate the value of $foo to the result of the function bar(). There is no other way around this than a different operator for method calls. I didn't think of that. It seems to me there could be an easier operator than - which sometimes will make me stop and look at what keys I'm trying to hit. Just a thought. I forgot about the concatenation operator which is + in Java/C# The PHP language developers were pretty stuck. Because of automatic string-to-numeric-conversion, they couldn't use + for string concatenation. Sadly, they chose . rather than .. which I believe one or two other languages use. If they had, . would have been available once objects rolled around in PHP 4/5. I suspect they chose - since that's used in C and C++ to dereference a pointer. Ever tried the jetbrains products? :D (No, they don't pay me) I have not, but it looks interesting. I'll have to try it. Those are very good products which have had a strong following for a decade. The free IDE NetBeans also has quite good support for both Java and PHP, and the latest beta version provides a web project that provides front- and back-end debugging of PHP + JavaScript. You can be stepping through JS code and hit an AJAX call and then seamlessly step through the PHP code that handles it. I use NetBeans for PHP/HTML/JS (though I am evaluating JetBrains' PHPStorm now) and Eclipse for Java. You can't beat Eclipse's refactoring support in a free tool, though I think NetBeans is close to catching up. I would bet IntelliJ IDEA for Java by JetBrains is on par at least. Peace, David ---End Message--- ---BeginMessage--- 2013/8/22 David Harkness davi...@highgearmedia.com On Wed, Aug 21, 2013 at 7:56 PM, Curtis Maurand cur...@maurand.comwrote: Sebastian Krebs wrote: Actually the problem is, that the dot . is already in use. With $foo.bar() you cannot tell, if you want to call the method bar() on the object $foo, or if you want to concatenate the value of $foo to the result of the function bar(). There is no other way around this than a different operator for method calls. I didn't think of that. It seems to me there could be an easier operator than - which sometimes will make me stop and look at what keys I'm trying to hit. Just a thought. I forgot about the concatenation operator which is + in Java/C# The PHP language developers were pretty stuck. Because of automatic string-to-numeric-conversion, they couldn't use + for string concatenation. Sadly, they chose . rather than .. which I believe one or two other languages use. If they had, . would have been available once objects rolled around in PHP 4/5. I suspect they chose - since that's used in C and C++ to dereference a pointer. Actually I think .. is quite error-prone, because it is hard to distinguish from . or _ on the _first_ glance, which makes the get quickly through the code. [1] So . is maybe not the best choice, but also remember when it was introduced: That was decades ago. That time it was (probably ;)) the best choice and nowadays I don't think it is too bad at all, beside that _other_ languages use it for other purposes now ;) [1] Yes, I know, that _ is not an operator, but mixed with strings and variables names it is there ;) Ever tried the jetbrains products? :D (No, they don't pay me) I have not, but it looks interesting. I'll have to try it. Those are very good products which have had a strong following for a decade. The free IDE NetBeans also has quite good support for both Java and PHP, and the latest beta version provides a web project that provides front- and back-end debugging of PHP + JavaScript. You can be stepping through JS code and hit an AJAX call and then seamlessly step through the PHP code that handles it. I use NetBeans for PHP/HTML/JS (though I am evaluating JetBrains' PHPStorm now) and Eclipse for Java. You can't beat Eclipse's
php-general Digest 23 Aug 2013 04:28:41 -0000 Issue 8341
php-general Digest 23 Aug 2013 04:28:41 - Issue 8341 Topics (messages 321953 through 321954): PHP 5.4.19 and PHP 5.5.3 Released! 321953 by: Stas Malyshev windows files and folders permission 321954 by: Emiliano Boragina Administrivia: To subscribe to the digest, e-mail: php-general-digest-subscr...@lists.php.net To unsubscribe from the digest, e-mail: php-general-digest-unsubscr...@lists.php.net To post to the list, e-mail: php-gene...@lists.php.net -- ---BeginMessage--- Hello! The PHP development team announces the immediate availability of PHP 5.4.19 and PHP 5.5.3. These releases fix a bug in the patch for CVE-2013-4248 in OpenSSL module and compile failure with ZTS enabled in PHP 5.4, which were introduced in previously released 5.4.18 and 5.5.2. All PHP users are encouraged to upgrade to either PHP 5.5.3 or PHP 5.4.19. For source downloads of PHP 5.4.19 and PHP 5.5.3 please visit our downloads page: http://www.php.net/downloads.php Windows binaries can be found on: http://windows.php.net/download/ The list of changes is recorded in the ChangeLog at: http://www.php.net/ChangeLog-5.php Regards, Stanislav Malyshev PHP 5.4 Release Manager ---End Message--- ---BeginMessage--- Night everyone, I did a upload page and when upload a JPG file this is not available. Why this happens? Thanks a lot. Emiliano Boragina | gráfico + web desarrollos comunicación + 15 33 92 60 02 » emiliano.borag...@gmail.com © 2013 ---End Message---
Re: [PHP] Re: PHP vs JAVA
2013/8/22 David Harkness davi...@highgearmedia.com On Wed, Aug 21, 2013 at 7:56 PM, Curtis Maurand cur...@maurand.comwrote: Sebastian Krebs wrote: Actually the problem is, that the dot . is already in use. With $foo.bar() you cannot tell, if you want to call the method bar() on the object $foo, or if you want to concatenate the value of $foo to the result of the function bar(). There is no other way around this than a different operator for method calls. I didn't think of that. It seems to me there could be an easier operator than - which sometimes will make me stop and look at what keys I'm trying to hit. Just a thought. I forgot about the concatenation operator which is + in Java/C# The PHP language developers were pretty stuck. Because of automatic string-to-numeric-conversion, they couldn't use + for string concatenation. Sadly, they chose . rather than .. which I believe one or two other languages use. If they had, . would have been available once objects rolled around in PHP 4/5. I suspect they chose - since that's used in C and C++ to dereference a pointer. Actually I think .. is quite error-prone, because it is hard to distinguish from . or _ on the _first_ glance, which makes the get quickly through the code. [1] So . is maybe not the best choice, but also remember when it was introduced: That was decades ago. That time it was (probably ;)) the best choice and nowadays I don't think it is too bad at all, beside that _other_ languages use it for other purposes now ;) [1] Yes, I know, that _ is not an operator, but mixed with strings and variables names it is there ;) Ever tried the jetbrains products? :D (No, they don't pay me) I have not, but it looks interesting. I'll have to try it. Those are very good products which have had a strong following for a decade. The free IDE NetBeans also has quite good support for both Java and PHP, and the latest beta version provides a web project that provides front- and back-end debugging of PHP + JavaScript. You can be stepping through JS code and hit an AJAX call and then seamlessly step through the PHP code that handles it. I use NetBeans for PHP/HTML/JS (though I am evaluating JetBrains' PHPStorm now) and Eclipse for Java. You can't beat Eclipse's refactoring support in a free tool, though I think NetBeans is close to catching up. I would bet IntelliJ IDEA for Java by JetBrains is on par at least. Eclipse' code-completion and debugger never worked for me well (and most of the time: at all). It became slower and less responsive with every release. That was the reason I decided to leave it and I don't regret it :) Peace, David -- github.com/KingCrunch
Re: [PHP] Off the wall - sub-domain question
Is the subdomain also in a subfolder of the main domain? Jim Giner wrote: I have a main domain (of course) and a sub domain. I'm really trying to steer my personal stuff away from the main one and have focused all of my php development to the sub-domain. Lately I noticed that google catalogs my sub-domain site stuff under the main domain name and the links that come up lead to that domain name with the path that takes the user to the sub-domain's home folder and beyond. Is there something that php (apache??) can do to control either google's robots or the user's view (url) so that it appears as a page of my sub-domain? I'm really new at this stuff and know nothing. I'm lucky that google is even finding my site! IN advance - I apologize for this off-topic question, but this place is a source of much knowledge, so I just threw in a quick interlude here to pick someone's brain. :) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Off the wall - sub-domain question
On 8/22/2013 8:05 AM, Curtis Maurand wrote: Is the subdomain also in a subfolder of the main domain? Jim Giner wrote: I have a main domain (of course) and a sub domain. I'm really trying to steer my personal stuff away from the main one and have focused all of my php development to the sub-domain. Lately I noticed that google catalogs my sub-domain site stuff under the main domain name and the links that come up lead to that domain name with the path that takes the user to the sub-domain's home folder and beyond. Is there something that php (apache??) can do to control either google's robots or the user's view (url) so that it appears as a page of my sub-domain? I'm really new at this stuff and know nothing. I'm lucky that google is even finding my site! IN advance - I apologize for this off-topic question, but this place is a source of much knowledge, so I just threw in a quick interlude here to pick someone's brain. :) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Yes - the sub is an add-on domain to my primary domain. Hence the overlap and problem. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Off the wall - sub-domain question
The only way that I know of to take care of that is to put a file in your main directory called robots.txt. In that file you will put: User-agent: * Disallow: /FolderName On Thu, Aug 22, 2013 at 6:19 AM, Jim Giner jim.gi...@albanyhandball.comwrote: On 8/22/2013 8:05 AM, Curtis Maurand wrote: Is the subdomain also in a subfolder of the main domain? Jim Giner wrote: I have a main domain (of course) and a sub domain. I'm really trying to steer my personal stuff away from the main one and have focused all of my php development to the sub-domain. Lately I noticed that google catalogs my sub-domain site stuff under the main domain name and the links that come up lead to that domain name with the path that takes the user to the sub-domain's home folder and beyond. Is there something that php (apache??) can do to control either google's robots or the user's view (url) so that it appears as a page of my sub-domain? I'm really new at this stuff and know nothing. I'm lucky that google is even finding my site! IN advance - I apologize for this off-topic question, but this place is a source of much knowledge, so I just threw in a quick interlude here to pick someone's brain. :) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Yes - the sub is an add-on domain to my primary domain. Hence the overlap and problem. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- Willie Matthews matthews.wil...@gmail.com
Re: [PHP] Off the wall - sub-domain question
On 8/22/2013 9:43 AM, Willie wrote: The only way that I know of to take care of that is to put a file in your main directory called robots.txt. In that file you will put: User-agent: * Disallow: /FolderName On Thu, Aug 22, 2013 at 6:19 AM, Jim Giner jim.gi...@albanyhandball.comwrote: On 8/22/2013 8:05 AM, Curtis Maurand wrote: Is the subdomain also in a subfolder of the main domain? Jim Giner wrote: I have a main domain (of course) and a sub domain. I'm really trying to steer my personal stuff away from the main one and have focused all of my php development to the sub-domain. Lately I noticed that google catalogs my sub-domain site stuff under the main domain name and the links that come up lead to that domain name with the path that takes the user to the sub-domain's home folder and beyond. Is there something that php (apache??) can do to control either google's robots or the user's view (url) so that it appears as a page of my sub-domain? I'm really new at this stuff and know nothing. I'm lucky that google is even finding my site! IN advance - I apologize for this off-topic question, but this place is a source of much knowledge, so I just threw in a quick interlude here to pick someone's brain. :) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Yes - the sub is an add-on domain to my primary domain. Hence the overlap and problem. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php I'll try it. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Off the wall - sub-domain question
So its indexing http://www.domain.com/subdomain/page.php and you would rather it index http://subdomain.domain.com/page.php. If that is the case then what Willie said holds true User-agent: * Disallow: /subdomain Place a robots.txt in the domain.com public root directory. To Googles indexer http://subdomain.domain.com/page.php and http://www.domain.com/subdomain/page.php are totally different and therefore blocking /subdomain will not affect subdomain.domain.com. Sign up for Google Webmaster and add two sites subdomain.domain and www.domain that way you can delete improperly indexed pages. Do some test scans and see if there are links on your www.domain that are linked to www.domain.com/subdomain rather then subdomain.domain.com On Thu, Aug 22, 2013 at 9:43 AM, Willie matthews.wil...@gmail.com wrote: The only way that I know of to take care of that is to put a file in your main directory called robots.txt. In that file you will put: User-agent: * Disallow: /FolderName On Thu, Aug 22, 2013 at 6:19 AM, Jim Giner jim.gi...@albanyhandball.com wrote: On 8/22/2013 8:05 AM, Curtis Maurand wrote: Is the subdomain also in a subfolder of the main domain? Jim Giner wrote: I have a main domain (of course) and a sub domain. I'm really trying to steer my personal stuff away from the main one and have focused all of my php development to the sub-domain. Lately I noticed that google catalogs my sub-domain site stuff under the main domain name and the links that come up lead to that domain name with the path that takes the user to the sub-domain's home folder and beyond. Is there something that php (apache??) can do to control either google's robots or the user's view (url) so that it appears as a page of my sub-domain? I'm really new at this stuff and know nothing. I'm lucky that google is even finding my site! IN advance - I apologize for this off-topic question, but this place is a source of much knowledge, so I just threw in a quick interlude here to pick someone's brain. :) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Yes - the sub is an add-on domain to my primary domain. Hence the overlap and problem. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- Willie Matthews matthews.wil...@gmail.com -- Thank you, Dan Cell: 484-459-2856 https://www.facebook.com/dpmccullough http://www.linkedin.com/in/danmccullough
Re: [PHP] Off the wall - sub-domain question
Jim Giner wrote: Yes - the sub is an add-on domain to my primary domain. Hence the overlap and problem. I don't think there is any way to get google to separate filing information on different subdomains from the main domain, but you can stop them filing content altogether by identifying folders you do not want them to use. I have fun with them indexing the page histories if I forget to block that particular functions .php file. -- Lester Caine - G8HFL - Contact - http://lsces.co.uk/wiki/?page=contact L.S.Caine Electronic Services - http://lsces.co.uk EnquirySolve - http://enquirysolve.com/ Model Engineers Digital Workshop - http://medw.co.uk Rainbow Digital Media - http://rainbowdigitalmedia.co.uk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: PHP vs JAVA
On Thu, Aug 22, 2013 at 12:29 AM, Sebastian Krebs krebs@gmail.comwrote: Actually I think .. is quite error-prone, because it is hard to distinguish from . or _ on the _first_ glance, which makes the get quickly through the code. [1] I surround all operators except member access (. and -) with spaces, so that wouldn't be a problem for me. I thought there was an older language that used .., but all I can find now is Lua which was developed in the early nineties. So . is maybe not the best choice, but also remember when it was introduced: That was decades ago. That time it was (probably ;)) the best choice and nowadays I don't think it is too bad at all, beside that _other_ languages use it for other purposes now ;) C introduced . as the field access operator for structs in the early seventies, C++ kept it for object access, and Java adopted it in the early nineties. C's use of pointers required a way to access members through a pointer, and I suppose KR thought - looked like following a pointer (I agree). Since PHP was modeled on Perl and wouldn't implement objects or structs for another decade, it adopted . for string concatenation. It works fine, and I don't have too much trouble bouncing back-and-forth. I honestly would have preferred . to be overloaded when the left hand side was an object. In the rare cases that you want to convert an object to a string to be concatenated with the RHS, you can always cast it to string, use strval(), or call __toString() manually. But I'm not staging any protests over the use of -. :) Eclipse' code-completion and debugger never worked for me well (and most of the time: at all). It became slower and less responsive with every release. That was the reason I decided to leave it and I don't regret it :) I agree about the slowness, and until this latest release I've always left autocompletion manual (ctrl + space). They did something with Kepler to speed it up drastically, so much so I have it turned on with every keypress. However, it's a little too aggressive in providing choices. Typing null which is a Java keyword as in PHP, it will insert nullValue() which is a method from Hamcrest. :( After a couple weeks of this, I think I'll be switching it back to manual activation. I can type quickly enough that I only need it when I'm not sure of a method name. NetBeans, while not as good with refactoring and plugin support, is still zippier than Eclipse. And my short time with the JetBrains products found them to be fast as well. Eclipse's PHP support via PDT is not nearly as good as NetBeans, and no doubt PHPStorm beats them both. Peace, David
[PHP] PHP 5.4.19 and PHP 5.5.3 Released!
Hello! The PHP development team announces the immediate availability of PHP 5.4.19 and PHP 5.5.3. These releases fix a bug in the patch for CVE-2013-4248 in OpenSSL module and compile failure with ZTS enabled in PHP 5.4, which were introduced in previously released 5.4.18 and 5.5.2. All PHP users are encouraged to upgrade to either PHP 5.5.3 or PHP 5.4.19. For source downloads of PHP 5.4.19 and PHP 5.5.3 please visit our downloads page: http://www.php.net/downloads.php Windows binaries can be found on: http://windows.php.net/download/ The list of changes is recorded in the ChangeLog at: http://www.php.net/ChangeLog-5.php Regards, Stanislav Malyshev PHP 5.4 Release Manager -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] windows files and folders permission
Night everyone, I did a upload page and when upload a JPG file this is not available. Why this happens? Thanks a lot. Emiliano Boragina | gráfico + web desarrollos comunicación + 15 33 92 60 02 » emiliano.borag...@gmail.com © 2013 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
