HI!
mea culpa... I didn't check it previously but now...
I included
. /usr/IBMdb2/V7.1/db2profile
in
/etc/init.d/httpd
NOW IT WORKS!!!
It was all about environment.
THANKS ALL for advices/inspiration!!!
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ah ... apologies
i was confused by the 'i want to pay by check' on an otherwise blank page.
following the link does indeed give the offers you suggested.
shame i'm in the uk ...
once again, apologies abound.
Steve
-Original Message-
From: Rick Emery [mailto:[EMAIL PROTECTED]]
Sen
Using phpadmin, when I try to import a csv file into a database table, I get
the following mysql errorcode:2 error which says the following file is not
found:
c:windowstempphp48..
Appreciate any help...
Thanks.
Geetha
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Hello Scott,
Tuesday, 13 March 2001, you wrote:
SK> I fairly new to php and have a question about mysql and arrays.
SK> What I am trying to do is pull multiple rows of data out of a mysql database
SK> and I need to use that data as input for another table. I have tried to use
SK> mysql_fetch
Hi
Does anyone have a simple php script for requiring entry of an email and
password (settable by user) for access, that is logged in mysql for
checking proper combination, and if new, creates new entry? I have a
script that adds the info to database, but what I need to do:
1. is if the info is
Mario Henrique Cruz Torres wrote:
> Hello people, I have an Apache server running with PHP3, yesterday I
> installed PHP4, and changed httpd.conf to run php4 scripts, but when I try to
> see a php page, my browser asks if I want to download the file. I´m want know
> how a httpd.conf file wo
Mario:
Ensure you have the following written similarly to this and UNCOMMENTED!
# AddType allows you to tweak mime.types without actually editing it, or to
# make certain files to be certain types.
#
# For example, the PHP3 module (not part of the Apache distribution)
# will typically use:
#
Well a rather simple solution is:
$R_Check=mysql_query("select email from table where email='$email' and
password='$password'");
if(mysql_num_rows($R_Check)) { header("Location: log_in.php"); }
else
{
$Error="";
$R_Check=mysql_query("select email from table where email='$email'");
if
I've got a loop which includes the following coming from mySQL
if ($art_nr1 != '') {
$i++;
echo "
";
I've now got the following
art_nr_1=12456
quant1="" or 1 or so
And now comes the bit which doesn't work !
for ($i=1; $i<50; $i++) :
$varid = "quant".$i ;
if
Hi there:
Not sure this'll work but it's some way towards it I would think:
(Note all occurances of the variable: '$display_this'
//Start off the display item outside the loop
$display_this = "";
if ($art_nr1 != '') {
$i++;
$display_this .= "
";
I've no
sorry I don't think I explained that very clearly !
The first loop's on a page which works fine, and it's in a form
with article numbers and then an input field for quantites !
It's the next page that's giving me headaches !
The user submitted the form with all article numbers and some with a
quan
On Tue, Mar 13, 2001 at 07:56:31PM +0100, paauwe wrote:
> what is a parse error?
A simple search on dictionary.com came up with this definition for
parse:
Of fish, to have to remove the bones yourself. "I object to parsing
fish", means "I don't want to get a whole fish, but a sliced one is
oka
driving me up the bloody wall !
I'm sure it's something simple !
This works fine
for ($i=1; $i<50; $i++) :
$varid = "quant".$i ;
if ($$varid != "") {
echo
"
";
}
but the moment I change it to $art_nr_$i it doesn't ???
> sorry I don't think I explained that very clearly !
> The first loop's
>>hey all..
>>
>>I really don't get why I am getting this error.. Can somebody help me
>>out? what does a parse error mean?
>>Error:
>>Parse error: parse error in /home/httpd/html/test/php-test/CVzenden.php
>>on line 35
>>
>>CVzenden.php:
>>
>>$conn=ibase_connect("localhost:/home/httpd/html/test/
Technically, he shouldn't have to list the fields he is inserting into if he
is inserting into the fields in order. Unless that's some funky Interbase
requirement.
A parse error is usually a PHP syntactical error. Can you post the whole of
line "35" so we can see? :)
---
I have a calendar system that details the appointments for various
departments in the company and am having problems with the sheers size of
the html docs that are returned.
One department insists that they nned to see all the users in one go (approx
110) and the calendars for 3 months.
This cau
1. What is connection id? We will see this like "your mysql connection id is
12" when you enter into the mysql client programme.
2. Why will the connection id in mysql increase when you
exit the mysql and login again? But I think the connection id should be
cleared when user exit mysql.
Thank yo
The first thing I would look at ( having had the same issue ) is whats
actually in the document. I managed to reduce the size of data delivered by
60% by 2 methods.
1. Ruthless use of css in table formatting.
2. Creating javascript functions for even the smallest inline feature such
as mouseover
Hi Steve,
if your users have all JavaScript enabled, you could generate the HTML-Doc
clientside, using things like document.write or document.writeln.
Hope this helps.
Greetinx,
Mike
Michael Rudel
- Web-Development, Systemadministration -
_
AFAIK the connection id is a used by the server to identify the correct
connection.
if it reset itself there would be duplicate connections.
e.g. user 1 connects and gets connection 1.
user 2 connects and gets connection 2. then disconnects.
if the connection index was reset user 2 would get c
i've used both already. not so ruthless with the css and there is no java at
all in there. just html.
the db produces 15 sessions per working week for 100 users for 12 weeks so
there is a fair chunk of data there ...
-Original Message-
From: Mark Newnham [mailto:[EMAIL PROTECTED]]
Sent:
Hi,
I'm putting together a db with articles in it. Would it be better to have two
tables with the main text of the articles in it linked to a main article
table or just chuck it all in together in one table.
I want to be able to do a full text search on the articles.
Any help please,
Cheers,
Steve,
look at the output buffering/filtering methods in PHP (ob_) In
particular, you can enable the gzip filter to automatically zip your html
server side, assuming your user's browsers support auto gzip deflation,
which the newer browsers seem to
"Steve Brett" <[EMAIL PROTECTED]> w
I have two machines: the first one runs Red Hat 7.0 with php 4.0.1pl2 (as
it came in Red Hat 7.0 installation) and the other one runs Red Hat 7.0 with
Oracle 8.1.6.
I need to connect PHP with Oracle but when I run something like
'OCILogon(...)' I got a 'Call to undefined function:
I wouldn't know about flushing the buffer.
Another approach would be changing to ADO. This being an intranet, i'd
assume that you could force users to use IE on windows (or provide a IE
specific page but keep the current page for other brwosers).
This way you either connect direct to the database
Hi all,
Any news about connecting PHP to PROGRESS?
I'm using PHP+APACHE+MYSQL and I'm curious.
Thanks,
==
Hector M Banda Voice: (949) 784-3143
Progress Programmer/Analyst Fax: (425) 790-6379
Hi I have little tiny script like so..
-
---
no I know there has to be a more efficient way of returning the $row and
$row1 without writing it down like so..
anyone one can throw me a clue? :)
Thank
Andre
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Hi Hector,
You may use OpenLink's ODBC drivers to do this. The drivers are available
at http://www.openlinksw.com and a HOWTO on ODBC and PHP is at
www.iodbc.org.
Best regards,
Andrew
--
Andrew Hill - OpenLink Software
Director Technology Evangelism
eBusiness
Hi--
I'm trying to evaluate the following lines to see if "$myrow" is false or
true, can you help?
-
$sql = "SELECT * FROM Employees WHERE ID=$id";
$result = pg_exec($db, $sql) or die(include("../sqlerror.inc"));
$myrow = pg_
Hi--
Sorry, but I didn't finish my previous e-mail :)
>Hi--
>I'm trying to evaluate the following lines to see if "$myrow" is false or
true, can you help?
-
$sql = "SELECT * FROM Employees WHERE ID=$id";
$result = pg_exec($db,
HI-- Sorry again...aggg...
Hi--
I'm trying to evaluate the following lines to see if "$myrow" is false or
true, can you help?
-
$db .;
$sql = "SELECT * FROM Employees WHERE ID=$id";
$result = pg_exec($db, $sql);
$myro
Morning !!! experts
Sorry its lil bit off list question but u r the experts remember !
Is there nething in php similar to javascript's following code ??>>:
document.form1.text1.value =>> ?
so that i can fetch the value of any textbox into php variable [$var]
thx in advance.
Viv
Hello
Anybody know where i can get hold of this. Informix site at
www.informix.com/evaluate..has for every OS other than
Linux
Thanks
Marios
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To c
I get this too, but it's a problem thats only recently developed - import from
cvs has worked fine previously. I had thought it may be connected with a recent
upgrade to a newer version of the server I'm using (Omnihttpd Pro) which I think
also came with a newer version of PHP (its now 4.04pl1)..
Does your ISP have XML and Sabloton support installed for PHP? If so it would be
worth considering an XML solution.
Alan Hale
"David W. Fenton" wrote:
> I'm very new to PHP, and don't know where to look to answer this
> question.
>
> Is it possible to use a collection of delimited text files wi
At 05:05 PM 3/14/2001 +, you wrote:
>I'm putting together a db with articles in it. Would it be better to have two
>tables with the main text of the articles in it linked to a main article
>table or just chuck it all in together in one table.
>I want to be able to do a full text search on the
Can somebody tell me what the proper statement is for this? I want two
variables to match with eachother but this doesn't seems to work. Help
please? THNX
if ($PASS != $PASSNOG) {
echo "password doesn't match! $back";
exit;
}
Duky
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PHP Database Mailing List (http://www.p
Hi all,
I have a few questions about PHP and databases :
- how do you insert a character string into a database when it is stored in an
array ? For example I have the name of a person in an array called "$name" and
when I insert it into the field "name" in my table, I get a field with "array
Duky,
Have you tried to use:
if ($PASS == $PASSNOG) {
# do whatever.
}
If you're taking data from a form, you might want to do a trim to remove any
trailing spaces
if ($PASS == trim($PASSNOG)) {
# do whatever
}
There's also...
http://www.php.net/manual/en/function.str
Laurent,
Show us the code/statements you are using. It is easier to help you that
way.
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, March 14, 2001 1:43 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] PHP and MySQL
Hi all,
I have a few questions
I'm assuming these are strings you are comparing, correct? If so, try this:
if(strcmp($PASS, $PASSNOG))
{
echo "password doesn't match! $back";
exit;
}
http://www.php.net/manual/en/function.strcmp.php
Josh Hoover
KnowledgeStorm, Inc.
[EMAIL PROTECTED]
Searching for a new IT s
Ànd what statement for not matching? this maybe?
if ($PASS !== $PASSNOG) {
# do whatever.
}
Duky
Duky wrote:
>
> Can somebody tell me what the proper statement is for this? I want two
> variables to match with eachother but this doesn't seems to work. Help
> please? THNX
>
>if
Duky,
Did you check if you have named correctly your variables in your form? Your statement
is more than corret. Try "echoing" your variables before making the comparision to
verify if they are set. If not probabily you have a spelling problem on the form
variables.
BR,
Fábio Ottolini
P.S.:
Well,
No and Yes.
If the form is posted, whichever page that it was posted too will have
$HTTP_POST_VARS["text1"]
set to whatever was in the textbox. $text1 may also be a global variable,
depending on your php.ini settings for register_globals and also
variable_order.
It took me a while to feel
Assume in HTML file is:
http://my_site.com/do_form.php3">
Then, in do_form.php3:
$text1 refers to the name of the field in the HTML form. This convention
applies to all fields in the form, including checkboxes, radio buttons,
submit buttons, etc.
-Original Message-
From: vivek
The variables are the right ones...
"Fabio Ottolini (EDB)" wrote:
>
> Duky,
>
> Did you check if you have named correctly your variables in your form? Your
>statement is more than corret. Try "echoing" your variables before making the
>comparision to verify if they are set. If not probabily y
Hi Duky
Try to add this before if statement
echo("$PASS$PASSNOG");
it will show you whether your vars are correct and whether there is
something in at all!
if ($PASS != $PASSNOG) {
echo "password doesn't match! $back";
exit;
}
Good luck
Ivo
"Duky" <[EMAIL PROTECTED]> w
Hi,
my exact problem is the following. Here is my form :
login :
group :
password :
when I put the data
Seems like you need to try curly braces.
${art_nr}_${i}
""Keith Whyman"" <[EMAIL PROTECTED]> wrote in message
024d01c0ac8f$1a6373c0$0b64a8c0@server">news:024d01c0ac8f$1a6373c0$0b64a8c0@server...
>
> driving me up the bloody wall !
> I'm sure it's something simple !
> This works fine
>
>
> for ($i
At 10:21 PM 3/14/2001 +0100, Ivo Stoykov wrote:
>Try to add this before if statement
>echo("$PASS$PASSNOG");
A more accurate way to tell this would be to do the following:
echo "\"".$PASS."\",\"",$PASSNOG,"\"\n";
This was you will see embedded spaces and carriage returns which will not
be
Try
if($myrow = pg_fetch_array($result,0)) {
do whatever
} else {
or die(include("../sqlerror.inc"));
}
and it will work accordingly
Ivo
""Julio Cuz, Jr."" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> HI-- Sorry again...aggg...
>
> Hi--
>
Why don't you try wqith cicle?
""Mrvball008"" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Hi I have little tiny script like so..
>
> -
> $dbName = "somedb";
> $dbPass = "somepass";
> $dbUserName = "someuser";
> $host = "localhost";
> $db = mysql_
I don't understand. What is your question?
Robert Zwink
-Original Message-
From: Keith Whyman [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, March 13, 2001 11:32 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Sure it's simple but.
I've got a several links(each with a seperate arti
You are going to need to post more information. Maybe send part of the
script that is having the problem.
I'm sure there are quite a few people familiar with classes on this list,
but unfortunatly your question may not have enough information.
Also: You posted this question to the php-db list.
Use: echo mysql_field_name($result, $i);
Like this:
Robert Zwink
DISCLAIMER This is not my syntax, it is taken from the original poster's
message.
-Original Message-
From: Mike [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, March 13, 2001 7:31 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB]
even better to use:
echo("\$PASS = $PASS\$PASSNOG = $PASSNOG");
which will show the variable name whether it has anything defined or not.
Terry
On Wednesday, March 14, 2001, at 03:21 PM, Ivo Stoykov wrote:
> Hi Duky
>
> Try to add this before if statement
>echo("$PASS$PASSNOG");
Here's my php program, I think $result never gets assigned a value, staying
null or whatever.
$link = mysql_connect("host");
mysql_select_db("dbname");
$result = mysql_query ("SELECT * FROM table");
$fields = mysql_num_fields ($result);
$rows = mysql_num_rows ($result);
$table = mysql_field_t
On my Linux RH 6.2 computer, when working with Apache, mySQL and PHP, there is no
problems showing the source code to my code developing friends. If I rename the
php-file to phps it works just well.
BUT, when doing the very same thing on my W98 or W2k machines, the source code will
not show. T
This following script might help. It assumes you are reading in a file with
the following format:
0;this is line zero
1;this is a line one
2;this is a line two
3;this is a line three
4;this is a line four
5;this is a line five
http://www.yoursite.com/index.phtml?method=id&product_id=123
if($met
Use or die( mysql_error()) on every mysql function
or command you're performing, this will tell you what is going wrong .
HTH
Jayme.
-Mensagem Original-
De: <[EMAIL PROTECTED]>
Para: <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>
Enviada em: quarta-feira, 14 de março de 2001 19:47
Assun
Hmm.. maybe I wasn't clear enough... what I want is to check is WHEN the
two passwords aren't the same, then it should echo "password doesn't
match!". So when NOT the same, then echo. What to use for the NOT??
should it then be something like this with the exlamationmark?
if ($PASS !== $P
use just one = sign. So,
if ($PASS != $PASSNOG) {...
At 01:41 AM 3/15/01 +0100, Duky wrote:
>Hmm.. maybe I wasn't clear enough... what I want is to check is WHEN the
>two passwords aren't the same, then it should echo "password doesn't
>match!". So when NOT the same, then echo. What to use for
I am trying to display info from 2 tables in a search result format.
My problem is... how do I get the variables to display together?
for example:
A user selects a city to search apartments in.
$sql = "SELECT * FROM $table_name WHERE apt_city = \"$apt_city\"
";
$result = mysql_query($sql, $co
>From the document, the connection opened by pconnect() will not close
after you use.
And it will store it and reuse at next time.
I would like to ask, it is keep open until I shutdown apache?
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For addi
If the tables have a one to many relationship you can use nested while
loops:
while(1st loop){
// display header - master table
while(2nd loop){
// display features - detail table
}
}
HTH
Jayme.
-Mensagem Original-
De: olinux <[EMAIL PROTECTED]>
Para: PHP-DB <[EM
hi there
__
Do You Yahoo!?
Yahoo! Auctions - Buy the things you want at great prices.
http://auctions.yahoo.com/
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I'm trying to read a text file into a blob field in a database with the
following code:
$cvfile=".txt";
$exist = file_exists($cvfile);
echo "File exists $exist";
$result1=mysql_query("select * from $TA");
$rows=mysql_num_rows($result1);
echo "$rows";
$result=mysql_query("update $TA set P1desc
Check out :
http://www.weberdev.com/index.php3?GoTo=ViewArticle.php3?ArticleID=17
Sincerely
berber
Visit http://www.weberdev.com Today!!!
To see where PHP might take you tomorrow.
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, March 14,
A quick question, which executes faster ?
Suppose i have a table with 6 fields and I need to use all of the info in the table,
SELECT * FROM $table_name WHERE id = \"$id\"
or
SELECT field1, field2, field3, field4, field5, field6 FROM $table_name WHERE id =
\"$id\"
I understand that they do t
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