Re: [PHP-DB] Need help with duplicate entries

2001-10-30 Thread Jon Farmer

Use a  Select Distinct. query. See www.mysql.com/doc  for more info

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Systems Programmer, Entanet www.enta.net
Tel 01952 428969 Mob 07763 620378
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  - Original Message - 
  From: Chris Payne 
  To: [EMAIL PROTECTED] 
  Sent: Monday, October 15, 2001 9:59 PM
  Subject: [PHP-DB] Need help with duplicate entries


Hi there everyone,

I'm working on a project for a friend who owns a travel agent, he has a MySQL 
database which works very fast, but the problem is that there are alot of duplicate 
entries.  When I am retrieving the results from the DB and getting it ready to display 
on the page, how do I eliminate duplicates via a query?  What I mean is (See below) I 
have backpackeurope.com many times but for different countries, when you search for 
backpacking it brings all the countries up under one another - how do I make it only 
bring 1 entry up of each entry rather than all of them?

Confused?  That's how I feel :-)

Thank you all so much.

Chris Payne

www.backpackeurope.com Backpackers/Hostels in Austria
Backpacking and hostelling tips and links for student and budget travellers 
planning a trip to europe.
[EMAIL PROTECTED] - rating: . Category: Accommodation 
  

  


www.backpackeurope.com Backpackers/Hostels in England
Backpacking and hostelling tips and links for student and budget travellers 
planning a trip to europe.
[EMAIL PROTECTED] - rating: . Category: Accommodation 
   




[PHP-DB] select take (too) much time

2001-10-30 Thread Bas Jobsen

hello,

i have got a table table1:

CREATE TABLE table1
(
   id bigint(20) unsigned DEFAULT '0' NOT NULL auto_increment,
   refer varchar(255) NOT NULL,
   aantal int(9) DEFAULT '1' NOT NULL,
   time int(10) DEFAULT '0' NOT NULL,
   PRIMARY KEY (id),
   UNIQUE id (id)
);

now i insert about 200 rows in it.

After that i do i select (using phpMyAdmin):
SELECT table1 FROM table1

it seems this never stops sending data:
SHOW processlist:
Id User Host db Command Time State Info
171807   __   Query   300   Sending data   SELECT * FROM
table1

also a delete like DELETE FROM table1 WHERE time. will take (too)
much time.

All this give problems cause the table is locked when 'Sending data' and the
row of new inserts is growing.

Is there something wrong with my table-design?

Thanks for reading.

Bas





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Re: [PHP-DB] Variables in a loop

2001-10-30 Thread Bruno Gimenes Pereti

try

form...
input name=a[] value=..
input name=a[] value=..
 input name=a[] value=..
 input name=a[] value=..

and

for ($i=1; $i=10; $i++) { $tab[$i]=$a[$i] ;}

This way $a will be a array.

Hope it helps
Bruno Gimenes Pereti.

- Original Message -
From: LeTortorec, Jean-Louis [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, October 29, 2001 7:03 PM
Subject: [PHP-DB] Variables in a loop


 I'm trying to write a loop to read variables I receive from a form:

 form ...
 input name=a1 value=..
 input name=a2 value=..
 input name=a3 value=..
 input name=a4 value=..


 I'd like to get something like:

 for ($i=1; $i=10; $i++) { $tab[$i]=a.$i ;}


 The expression a.$i is actually a string, not a variable.  Any idea how
to
 read the value of that string?

 Thanks for your help.

 Jean-Louis







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[PHP-DB] Greetings from Online Email Telphone Psychics at absolutelypsychic.com

2001-10-30 Thread Jackie W

Hi  Greetings from http://www.absolutelypsychic.com I hope you are doing well.

Our site has Professional, Ethical, and Accurate Psychics, Astrologers and
Tarot Card readers that have been tested by management to assure
authenticity. Our readers do not promise any false prophesies nor do they
tell you what you want to hear - they have counseling skills, and
professionals.

 In fact, one of our readers' has a TV Show called Chartalk - those clips are
on our website. This gives you the opportunity to check his work out for free
 to observe. Including the predicting the WTC explosion - check it out - you
can see the clip is old and its verifiable through MNN in NYC.

Our prices are also very modest, we do not charge a fortune, nor are we
anywhere near a 900 line - we have experience in working on those and on
other sites and tailored to make this a good experience for everyone.

We hold chat parties where you can get mini readings as well.

Feel free to surf our site at any time there's plenty of information on there
to show you what we are about.

If you have any questions, please feel free to write back  to assist you any
way possible.

We do say please become more aware of our field, if anyone ever says to you
that they can cleanse you of problems, the thing they are going to cleanse is
your wallet !Don't fall for it!

Thanks
Love  Light
Jackie
http://www.absolutelypsychic.com
 
To remove please email back to [EMAIL PROTECTED]


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[PHP-DB] automated processes in mysql

2001-10-30 Thread Bas Jobsen

Hello,

Can i use mysql for automated processes?
do $query every hour.

Tnx,

Bas


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RE: [PHP-DB] automated processes in mysql

2001-10-30 Thread Rick Emery

in Unix, set-up a cron job.

In Windows, set-up an AT job.

-Original Message-
From: Bas Jobsen [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, October 30, 2001 9:36 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] automated processes in mysql


Hello,

Can i use mysql for automated processes?
do $query every hour.

Tnx,

Bas


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[PHP-DB] Advantage database

2001-10-30 Thread Andyr

Hello there,

I hope I am not disturbing anyone. I have a question.
I am using Advantage Database, I would like to know If PHP supports this
database format.

My email address is
[EMAIL PROTECTED]
Thank you for your help

Regards

Luis



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RE: [PHP-DB] automated processes in mysql

2001-10-30 Thread Rick Emery

mySQL does not include native support to launch queries at a specific
interval.  In the mySQL manual, I found the following application:

mysqltop.tar.gz:   Sends a query in a fixed time interval to the server and
shows the resulting table. By Thomas Wana. 


-Original Message-
From: Bas Jobsen [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, October 30, 2001 9:55 AM
To: DL Neil; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] automated processes in mysql


Hello,

Thank for all your soon responses. Well, oke, I know about corntab. But
someone told me myslq  can do the job itself.

Tnx again,

Bas


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[PHP-DB] www.Aerotaxi.net

2001-10-30 Thread kathy


www.Aerotaxi.net

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[PHP-DB] Re: RE: that book:

2001-10-30 Thread Russ Michell

Don't quote me on this but the ./configure command when compiling/re-compiling php 
should be run 
one level up from the dir you wish to make the action occur in. (One above 
/path/to/php4.0.6/bin 
so: ./bin/configure with --this with --that

I have cc'd this to the php-db list to make sure this is right (and I'm not even 
convinced myselfanyone??)
Cheers

Russ

On Mon, 29 Oct 2001 15:26:58 - [EMAIL PROTECTED] wrote:

 Russ:
 
 see below for the question I posted and the reply I got. I hope it makes
 some sense.
 
 My Question was:
 I have a RedHat 7.2 server which I configured using the automatic
 configuration GUI. It is running apache 1.3.20, mysql 3.23.41,and php 4.0.6.
 Apache and php are working fine but I created the phpinof.php page and it is
 missing any reference to mysql. I am real new to linux but someone I know
 who is helping me suggested I need to recompile php to integrate mysql and
 apxs. I searched the forum and a while back found this but I need to know is
 this right and if could some one interpret it for me! 
 
 ./configure --with-axps --with-mysql 
 make 
 make install 
 
 The response was:
 I don't think you're going to need to recompile. For one, Redhat's
 automatic configuaration GUI doesn't use source files uses RPM's
 (basically pre-compiled binaries). Thus, you probably don't have the source
 readily available and would need to download it. That's not a big problem
 though:) 
 
 More to the point, AFAIK, the RPM's are compiled using apxs and the
 --with-mysql option is default (you have to manually specify that you
 *don't* want MySQL support). Your best and easiest bet is to add one or more
 RPM ftp servers into the sources list of the PRM Manager (don't ask me
 how I don't use Redhat) and run a search for php-mysql. It'll turn up a
 bunch of hits (probably on the installation cd's as well) for the php-mysql
 rpm, just select it and install it. 
 
 In answer to your other question, the make options you've given in your post
 are valid and won't cause the make to barf and die (assuming you've got
 MySQL and APXS installed on your box). Personally I find it's useful to
 place the make clean command before the ./configure options. It ensures
 you're running a fresh install and not using an old cached config script. 
 
 ---
 
 Just one more question. Do you understand the './configure' command? does it
 have to be run from a particular directory to be affective? If so how might
 you find out?
 
 Thanks very much for your help today. It is much appreciated - I'm off to
 amazon now to get the book!
 
 James.
 
 -Original Message-
 From: Russ Michell [mailto:[EMAIL PROTECTED]]
 Sent: 29 October 2001 15:00
 To: [EMAIL PROTECTED]
 Subject: that book:
 
 
 James:
 
 The book is called:
 
 * Fast and Easy Web Development using PHP
 * By Julie C Meloni
 
 Paste this URL into your browser:
 http://www.amazon.com/exec/obidos/ASIN/076153055X/qid=1004367638/sr=1-6/ref=
 sr_1_15_6/104-6954028-5527930
 
 and check out also: www.thickbook.com (support website for the book)
 Good luck!
 
 Russ
 
 #---#
   
   Believe nothing - consider everything 
   
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   Anglia Polytechnic University Webteam
   Room 1C 'The Eastings' East Road, Cambridge
   
   e: [EMAIL PROTECTED]
   w: www.apu.ac.uk/webteam
 
   www.theruss.com
   
 #---#

#---#

  Believe nothing - consider everything   
  
  Russ Michell
  Anglia Polytechnic University Webteam
  Room 1C 'The Eastings' East Road, Cambridge
  
  e: [EMAIL PROTECTED]
  w: www.apu.ac.uk/webteam

  www.theruss.com

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[PHP-DB] PHP query on date field

2001-10-30 Thread Jason

Here is my problem once again... =P I am wondering if I should change the
date table to something other than date... maybe something like date_1?
Would doing that resolve my issue, because of the fact that the date
variable in php is function? Thanks in advance...
Jason

/* Form to supply variables */
form name=auth method=post action=http://path/to/search.php;
  pSearch for Ads/p
  First name:
  input type=text name=fname
  br
  Last name:
  input type=text name=lname
  br
  Area Code:nbsp;
  input type=text name=phonea size=3
maxlength=3
  Phone:
  input type=text name=phone size=8
maxlength=8
  br
  Date:
  input type=text name=date
  br
  p
input type=submit name=login
value=Submit
input type=reset name=reset value=Reset
  /p
/form

Once user clicks submit button it links to this php script to connect, query
and display results... eveything works fine except for the date variables.
If anyone with a little more know how can point me out the error I would
greatly appriciate it.

/* php script to connect, query and display results */
?php

mysql_connect (db_host, db_username, db_password) or die(Couldn't
connect!);

mysql_select_db (db_name) or die(Couldn't select database);

if ($fname == )
{$fname = '%';}
if ($lname == )
{$lname = '%';}
if (phonea == )
{$phonea = '%';}
if ($phone == )
{$phone = '%';}
if ($date == )
{$date = '%';}

$result = mysql_query (SELECT * FROM ads
 WHERE fname LIKE '%$fname%' AND lname LIKE
'%$lname%' AND phonea LIKE '%$phonea%' AND phone LIKE '%$phone%' AND date
LIKE '%$date%');

if ($row = mysql_fetch_array($result)) {

do {
  PRINT Your search results: brbr;
  PRINT bFirst Name: /b ;
  print $row[fname];
  print (br);
  PRINT bLast Name: /b ;
  print $row[lname];
  print (br);
  PRINT bAddress: /b ;
  print $row[address];
  print (br);
  PRINT bCity: /b ;
  print $row[city];
  print (br);
  PRINT bState: /b ;
  print $row[state];
  print (br);
  PRINT bZip: /b ;
  print $row[zip];
  print (br);
  PRINT bArea Code: /b ;
  print $row[phonea];
  print (br);
  PRINT bPhone: /b ;
  print $row[phone];
  print (br);
  PRINT bEmail: /b ;
  print $row[email];
  print (br);
  PRINT bWeeks: /b ;
  print $row[weeks];
  print (br);
  PRINT bCity 1: /b ;
  print $row[cty1];
  print (br);
  PRINT bCity 2: /b ;
  print $row[cty2];
  print (br);
  PRINT bCity 3: /b ;
  print $row[cty3];
  print (br);
  PRINT bAd: /b ;
  print $row[ad];
  print (br);
  PRINT bTotal: /b ;
  print $row[total];
  print (br);
  PRINT bNumber of weeks: /b ;
  print $row[num];
  print (br);
  PRINT bDate: /b ;
  print $row[date];
  print (br);
  PRINT bTime: /b ;
  print $row[time];
  print (br);
  print (hr);
} while($row = mysql_fetch_array($result));
} else {print Sorry, no records were found!;}

?



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Re: [PHP-DB] Variables in a loop

2001-10-30 Thread Jason G.


If you have a string that is the name of an input field, you can do one of 
3 things:

Ex:
$sName = input.$i;  //result = input1
$sName = input.$i;  //result = input2
etc...

1: Variable Variables
$value = $$sName;

2: If you posted the form
$value = $HTTP_POST_VARS[$sName];

3: If you used GET with the form
$value = $HTTP_GET_VARS[$sName];

Regards,
-Jason Garber
IonZoft.com






At 09:10 AM 10/30/2001 +0100, * RzE: wrote:
Original message
From: LeTortorec, Jean-Louis [EMAIL PROTECTED]
Date: Mon, Oct 29, 2001 at 04:03:45PM -0500
Message-ID: 615315231286D21182E40008C7B1EED23C6E76@COMPAQ3000
Subject: [PHP-DB] Variables in a loop

  I'm trying to write a loop to read variables I receive from a form:
 
  form ...
  input name=a1 value=..
  input name=a2 value=..
  input name=a3 value=..
  input name=a4 value=..
 
 
  I'd like to get something like:
 
  for ($i=1; $i=10; $i++) { $tab[$i]=a.$i ;}
 
 
  The expression a.$i is actually a string, not a variable.  Any idea 
 how to
  read the value of that string?
 
  Thanks for your help.
 
  Jean-Louis

/Original message

Reply

Why don't you just use an array?

form ...
input name=a[] value=..
input name=a[] value=..
input name=a[] value=..
input name=a[] value=..

/Reply

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* RzE:


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Re: [PHP-DB] PHP query on date field

2001-10-30 Thread Bruno Gimenes Pereti

Hi Jason,

What is the error message, in what line? I really can't find any error...
Just one standarlization point: why do you use ( ) when printing BR and
not in every other printing. For me, it's easyer to debug if every thing
that do the same thing is writen the same way.
Other thing out of the point. You could write all the line in one print
command:

print bTotal:/b $row['total']br;
or
print bTotal:/b . $row[total] .br;
or (my favorite)
?
bTotal/b ? print $row[total]; ?br;
?

Please send the error message, O got curios.. (sorry I don't remember how to
write it, I think I can understand what I mean :-)

Bruno Gimenes Pereti.

- Original Message -
From: Jason [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, October 30, 2001 3:31 PM
Subject: [PHP-DB] PHP query on date field


 Here is my problem once again... =P I am wondering if I should change the
 date table to something other than date... maybe something like date_1?
 Would doing that resolve my issue, because of the fact that the date
 variable in php is function? Thanks in advance...
 Jason


[snip]


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Re: [PHP-DB] PHP query on date field

2001-10-30 Thread Bruno Gimenes Pereti

What I use to do is to print the sql and try it in the command line to know
it I'm constructing it correctly.

$sql = select foo from bar...;
print $sqlbr\n;  ## add this line

execute your script and copy the line to the mysql command line. If the
result is what you expect it should be working.

{Hope this helps} else {tell us}.

Bruno Gimenes Pereti.

- Original Message -
From: Big Nickel [EMAIL PROTECTED]
To: Bruno Gimenes Pereti [EMAIL PROTECTED]
Sent: Tuesday, October 30, 2001 4:02 PM
Subject: Re: [PHP-DB] PHP query on date field


 I apologize... there really isn't any error messages.. it just shows that
 there are no results to be displayed but when i telnet into the db there
are
 plenty of dates that met my search criteria. I just need to know why it
wont
 display the results... and I am thinking that because in php the date
 function is the same thing i am using for a variable... not sure if that
is
 the problem but i am open to suggestions on it. Thanks again.


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RE: [PHP-DB] PHP query on date field

2001-10-30 Thread Rick Emery

First, I agree with Bruno concerning putting print all on one line, as you
and I discussed previously Jason.

Second, keep using DATE data type in mySQL.  Simply specify to the user how
the date is to be entered on the form.  DATE is maintained in mySQL as
-MM-DD.
User that

-Original Message-
From: Bruno Gimenes Pereti [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, October 30, 2001 11:42 AM
To: PHP-DB
Subject: Re: [PHP-DB] PHP query on date field


Hi Jason,

What is the error message, in what line? I really can't find any error...
Just one standarlization point: why do you use ( ) when printing BR and
not in every other printing. For me, it's easyer to debug if every thing
that do the same thing is writen the same way.
Other thing out of the point. You could write all the line in one print
command:

print bTotal:/b $row['total']br;
or
print bTotal:/b . $row[total] .br;
or (my favorite)
?
bTotal/b ? print $row[total]; ?br;
?

Please send the error message, O got curios.. (sorry I don't remember how to
write it, I think I can understand what I mean :-)

Bruno Gimenes Pereti.

- Original Message -
From: Jason [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, October 30, 2001 3:31 PM
Subject: [PHP-DB] PHP query on date field


 Here is my problem once again... =P I am wondering if I should change the
 date table to something other than date... maybe something like date_1?
 Would doing that resolve my issue, because of the fact that the date
 variable in php is function? Thanks in advance...
 Jason


[snip]


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Re: [PHP-DB] PHP query on date field

2001-10-30 Thread Jason Wong

On Wednesday 31 October 2001 01:31 am, Jason wrote:

 Here is my problem once again... =P I am wondering if I should change
 the date table to something other than date... maybe something like
 date_1? Would doing that resolve my issue, because of the fact that
 the date variable in php is function? Thanks in advance...

What is the format of date as defined in your database? If date is of 
type DATE or DATETIME then 

 $result = mysql_query (SELECT * FROM ads
  WHERE fname LIKE '%$fname%' AND lname LIKE
 '%$lname%' AND phonea LIKE '%$phonea%' AND phone LIKE '%$phone%' AND
 date LIKE '%$date%');

should be changed to:

   $result = mysql_query (SELECT * FROM ads
   WHERE fname LIKE '%$fname%' 
 AND lname LIKE '%$lname%' 
 AND phonea LIKE '%$phonea%' 
 AND phone LIKE '%$phone%' 
 AND date = '$date'
 );
hth
-- 
Jason Wong
Gremlins Associates
www.gremlins.com.hk

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Re: [PHP-DB] executing system commands

2001-10-30 Thread B. PERRINE

Get a look at the PHP manual on www.php.net or mirror, 
annoted version, 
command : system,
there is a good example.

regards
B.

le jeu 25-10-2001 à 12:46, Ric Manalac a écrit :
 hi,
 
 i'm a newbiew php developer. i'm trying to
 execute a system command in one of my
 php scripts. what i would like to do is to
 create a directory. my code goes like this:
 
 // chunk of code starts here
 $directory = generate_sessionid();
 $command = mkdir /home/httpd/html/miroku/downloads/$directory;
 system($command, $dirsuccess);
 // chunk of code ends here
 
 generate_sessionid() is a function that
 generates a string that contains 16 random
 integers (0-9). i want to use that random string
 as the name of the directory that i'm creating.
 i checked php3.ini if safe mode is on but it is
 set to Off. thanks in advance!
 
 regards,
 
 ric
 
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Re: [PHP-DB] PHP query on date field

2001-10-30 Thread biorn

Isn't date a reserved word that should not be used as a field name?  It 
appeared that what was asked was if he should change the name of his field 
from date to date_1.  It should definitely be changed if it is now called 
date.


Jason Wong [EMAIL PROTECTED] said:

 On Wednesday 31 October 2001 01:31 am, Jason wrote:
 
  Here is my problem once again... =P I am wondering if I should change
  the date table to something other than date... maybe something like
  date_1? Would doing that resolve my issue, because of the fact that
  the date variable in php is function? Thanks in advance...
 
 What is the format of date as defined in your database? If date is of 
 type DATE or DATETIME then 
 
  $result = mysql_query (SELECT * FROM ads
   WHERE fname LIKE '%$fname%' AND lname LIKE
  '%$lname%' AND phonea LIKE '%$phonea%' AND phone LIKE '%$phone%' AND
  date LIKE '%$date%');
 
 should be changed to:
 
$result = mysql_query (SELECT * FROM ads
WHERE fname LIKE '%$fname%' 
  AND lname LIKE '%$lname%' 
  AND phonea LIKE '%$phonea%' 
  AND phone LIKE '%$phone%' 
  AND date = '$date'
  );
 hth
 -- 
 Jason Wong
 Gremlins Associates
 www.gremlins.com.hk
 
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Re: [PHP-DB] PHP query on date field

2001-10-30 Thread Jason Wong

On Wednesday 31 October 2001 02:57 am, [EMAIL PROTECTED] wrote:

 Isn't date a reserved word that should not be used as a field name? 
 It appeared that what was asked was if he should change the name of
 his field from date to date_1.  It should definitely be changed if it
 is now called date.

According to the docs, date is *not* a reserved word in MySQL, so he 
should be OK.

-- 
Jason Wong
Gremlins Associates
www.gremlins.com.hk

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Re: [PHP-DB] PHP query on date field

2001-10-30 Thread Bruno Gimenes Pereti

Hi again Jason,

I think Jason Wong got the problem I missed, it's the date format. If you
tested like I sad in the last mail you already found it. When you query:

SELECT * FROM ads WHERE date = '%$date%';

you get an empty result.

So, that's the solution...

Bruno Gimenes Pereti.

 What is the format of date as defined in your database? If date is of
 type DATE or DATETIME then

  $result = mysql_query (SELECT * FROM ads
   WHERE fname LIKE '%$fname%' AND lname LIKE
  '%$lname%' AND phonea LIKE '%$phonea%' AND phone LIKE '%$phone%' AND
  date LIKE '%$date%');

 should be changed to:

$result = mysql_query (SELECT * FROM ads
WHERE fname LIKE '%$fname%'
  AND lname LIKE '%$lname%'
  AND phonea LIKE '%$phonea%'
  AND phone LIKE '%$phone%'
  AND date = '$date'
  );


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Re: [PHP-DB] PHP query on date field

2001-10-30 Thread Jason

Ok well I have made the changes and tested it out but using the search
string 10/15/2001 still provided no results... here is the script that
parses the date for entry into the database...
$date =  (date(m/d/Y)) ; #this date is used in the online database

$A = (date(A));

$Hou = (date(H));
if ($Hou == 00){
$Hou = 10;
$format = PM;
}
if ($Hou == 01){
$Hou = 11;
$format = PM;
}
if ($Hou == 02){
$Hou = 12;
$format = AM;
}
if ($Hou == 03){
$Hou = 01;
$format = AM;
}
if ($Hou == 04){
$Hou = 02;
$format = AM;
}
if ($Hou == 05){
$Hou = 03;
$format = AM;
}
if ($Hou == 06){
$Hou = 04;
$format = AM;
}
if ($Hou == 07){
$Hou = 05;
$format = AM;
}
if ($Hou == 08){
$Hou = 06;
$format = AM;
}
if ($Hou == 09){
$Hou = 07;
$format = AM;
}
if ($Hou == 10){
$Hou = 08;
$format = AM;
}
if ($Hou == 11){
$Hou = 09;
$format = AM;
}
if ($Hou == 12){
$Hou = 10;
$format = AM;
}
if ($Hou == 13){
$Hou = 11;
$format = AM;
}
if ($Hou == 14){
$Hou = 12;
$format = PM;
}
if ($Hou == 15){
$Hou = 01;
$format = PM;
}
if ($Hou == 16){
$Hou = 02;
$format = PM;
}
if ($Hou == 17){
$Hou = 03;
$format = PM;
}
if ($Hou == 18){
$Hou = 04;
$format = PM;
}
if ($Hou == 19){
$Hou = 05;
$format = PM;
}
if ($Hou == 20){
$Hou = 06;
$format = PM;
}
if ($Hou == 21){
$Hou = 07;
$format = PM;
}
if ($Hou == 22){
$Hou = 08;
$format = PM;
}
if ($Hou == 23){
$Hou = 09;
$format = PM;
}
I am wondering if I should let the date be put into the db as 2001-15-10...

[EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 Isn't date a reserved word that should not be used as a field name?  It
 appeared that what was asked was if he should change the name of his field
 from date to date_1.  It should definitely be changed if it is now called
 date.


 Jason Wong [EMAIL PROTECTED] said:

  On Wednesday 31 October 2001 01:31 am, Jason wrote:
 
   Here is my problem once again... =P I am wondering if I should change
   the date table to something other than date... maybe something like
   date_1? Would doing that resolve my issue, because of the fact that
   the date variable in php is function? Thanks in advance...
 
  What is the format of date as defined in your database? If date is of
  type DATE or DATETIME then
 
   $result = mysql_query (SELECT * FROM ads
WHERE fname LIKE '%$fname%' AND lname LIKE
   '%$lname%' AND phonea LIKE '%$phonea%' AND phone LIKE '%$phone%' AND
   date LIKE '%$date%');
 
  should be changed to:
 
 $result = mysql_query (SELECT * FROM ads
 WHERE fname LIKE '%$fname%'
   AND lname LIKE '%$lname%'
   AND phonea LIKE '%$phonea%'
   AND phone LIKE '%$phone%'
   AND date = '$date'
   );
  hth
  --
  Jason Wong
  Gremlins Associates
  www.gremlins.com.hk
 
  --
  PHP Database Mailing List (http://www.php.net/)
  To unsubscribe, e-mail: [EMAIL PROTECTED]
  For additional commands, e-mail: [EMAIL PROTECTED]
  To contact the list administrators, e-mail: [EMAIL PROTECTED]
 



 --






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RE: [PHP-DB] PHP query on date field

2001-10-30 Thread Rick Emery

Jason,

date(H) converts to a 24-hour clock.  That is, 00 is 12 mid-night, 01 is 1
AM, 13 is 1 PM, 14 is 2 PM, 23 is 11 PM, etc.

I do not understand the reasons for your computation that, say 00, is 10 PM.

-Original Message-
From: Jason [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, October 30, 2001 2:20 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] PHP query on date field


Ok well I have made the changes and tested it out but using the search
string 10/15/2001 still provided no results... here is the script that
parses the date for entry into the database...
$date =  (date(m/d/Y)) ; #this date is used in the online database

$A = (date(A));

$Hou = (date(H));
if ($Hou == 00){
$Hou = 10;
$format = PM;
}
if ($Hou == 01){
$Hou = 11;
$format = PM;
}
if ($Hou == 02){
$Hou = 12;
$format = AM;
}
if ($Hou == 03){
$Hou = 01;
$format = AM;
}
if ($Hou == 04){
$Hou = 02;
$format = AM;
}
if ($Hou == 05){
$Hou = 03;
$format = AM;
}
if ($Hou == 06){
$Hou = 04;
$format = AM;
}
if ($Hou == 07){
$Hou = 05;
$format = AM;
}
if ($Hou == 08){
$Hou = 06;
$format = AM;
}
if ($Hou == 09){
$Hou = 07;
$format = AM;
}
if ($Hou == 10){
$Hou = 08;
$format = AM;
}
if ($Hou == 11){
$Hou = 09;
$format = AM;
}
if ($Hou == 12){
$Hou = 10;
$format = AM;
}
if ($Hou == 13){
$Hou = 11;
$format = AM;
}
if ($Hou == 14){
$Hou = 12;
$format = PM;
}
if ($Hou == 15){
$Hou = 01;
$format = PM;
}
if ($Hou == 16){
$Hou = 02;
$format = PM;
}
if ($Hou == 17){
$Hou = 03;
$format = PM;
}
if ($Hou == 18){
$Hou = 04;
$format = PM;
}
if ($Hou == 19){
$Hou = 05;
$format = PM;
}
if ($Hou == 20){
$Hou = 06;
$format = PM;
}
if ($Hou == 21){
$Hou = 07;
$format = PM;
}
if ($Hou == 22){
$Hou = 08;
$format = PM;
}
if ($Hou == 23){
$Hou = 09;
$format = PM;
}
I am wondering if I should let the date be put into the db as 2001-15-10...

[EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 Isn't date a reserved word that should not be used as a field name?  It
 appeared that what was asked was if he should change the name of his field
 from date to date_1.  It should definitely be changed if it is now called
 date.


 Jason Wong [EMAIL PROTECTED] said:

  On Wednesday 31 October 2001 01:31 am, Jason wrote:
 
   Here is my problem once again... =P I am wondering if I should change
   the date table to something other than date... maybe something like
   date_1? Would doing that resolve my issue, because of the fact that
   the date variable in php is function? Thanks in advance...
 
  What is the format of date as defined in your database? If date is of
  type DATE or DATETIME then
 
   $result = mysql_query (SELECT * FROM ads
WHERE fname LIKE '%$fname%' AND lname LIKE
   '%$lname%' AND phonea LIKE '%$phonea%' AND phone LIKE '%$phone%' AND
   date LIKE '%$date%');
 
  should be changed to:
 
 $result = mysql_query (SELECT * FROM ads
 WHERE fname LIKE '%$fname%'
   AND lname LIKE '%$lname%'
   AND phonea LIKE '%$phonea%'
   AND phone LIKE '%$phone%'
   AND date = '$date'
   );
  hth
  --
  Jason Wong
  Gremlins Associates
  www.gremlins.com.hk
 
  --
  PHP Database Mailing List (http://www.php.net/)
  To unsubscribe, e-mail: [EMAIL PROTECTED]
  For additional commands, e-mail: [EMAIL PROTECTED]
  To contact the list administrators, e-mail: [EMAIL PROTECTED]
 



 --






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Re: [PHP-DB] PHP query on date field

2001-10-30 Thread Jason

Rick,
This portion of the site was done by a previous employee and well you
know the expression.. If its not broke don't fix it. Well now that I
cannot query the db by the date it is now broke and I am still figuring out
how MySQL is taking entries to the db so I figured this bit of information
would maybe sum up the problem in the date field.  I have been reading up on
the date function in the MySQL book I have but somethings it just doesn't
cover. So please excuse my being vague. Thanks,
Jason
Rick Emery [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 Jason,

 date(H) converts to a 24-hour clock.  That is, 00 is 12 mid-night, 01 is
1
 AM, 13 is 1 PM, 14 is 2 PM, 23 is 11 PM, etc.

 I do not understand the reasons for your computation that, say 00, is 10
PM.

 -Original Message-
 From: Jason [mailto:[EMAIL PROTECTED]]
 Sent: Tuesday, October 30, 2001 2:20 PM
 To: [EMAIL PROTECTED]
 Subject: Re: [PHP-DB] PHP query on date field


 Ok well I have made the changes and tested it out but using the search
 string 10/15/2001 still provided no results... here is the script that
 parses the date for entry into the database...
 $date =  (date(m/d/Y)) ; #this date is used in the online database

 $A = (date(A));

 $Hou = (date(H));
 if ($Hou == 00){
 $Hou = 10;
 $format = PM;
 }
 if ($Hou == 01){
 $Hou = 11;
 $format = PM;
 }
 if ($Hou == 02){
 $Hou = 12;
 $format = AM;
 }
 if ($Hou == 03){
 $Hou = 01;
 $format = AM;
 }
 if ($Hou == 04){
 $Hou = 02;
 $format = AM;
 }
 if ($Hou == 05){
 $Hou = 03;
 $format = AM;
 }
 if ($Hou == 06){
 $Hou = 04;
 $format = AM;
 }
 if ($Hou == 07){
 $Hou = 05;
 $format = AM;
 }
 if ($Hou == 08){
 $Hou = 06;
 $format = AM;
 }
 if ($Hou == 09){
 $Hou = 07;
 $format = AM;
 }
 if ($Hou == 10){
 $Hou = 08;
 $format = AM;
 }
 if ($Hou == 11){
 $Hou = 09;
 $format = AM;
 }
 if ($Hou == 12){
 $Hou = 10;
 $format = AM;
 }
 if ($Hou == 13){
 $Hou = 11;
 $format = AM;
 }
 if ($Hou == 14){
 $Hou = 12;
 $format = PM;
 }
 if ($Hou == 15){
 $Hou = 01;
 $format = PM;
 }
 if ($Hou == 16){
 $Hou = 02;
 $format = PM;
 }
 if ($Hou == 17){
 $Hou = 03;
 $format = PM;
 }
 if ($Hou == 18){
 $Hou = 04;
 $format = PM;
 }
 if ($Hou == 19){
 $Hou = 05;
 $format = PM;
 }
 if ($Hou == 20){
 $Hou = 06;
 $format = PM;
 }
 if ($Hou == 21){
 $Hou = 07;
 $format = PM;
 }
 if ($Hou == 22){
 $Hou = 08;
 $format = PM;
 }
 if ($Hou == 23){
 $Hou = 09;
 $format = PM;
 }
 I am wondering if I should let the date be put into the db as
2001-15-10...

 [EMAIL PROTECTED] wrote in message
 [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
  Isn't date a reserved word that should not be used as a field name?  It
  appeared that what was asked was if he should change the name of his
field
  from date to date_1.  It should definitely be changed if it is now
called
  date.
 
 
  Jason Wong [EMAIL PROTECTED] said:
 
   On Wednesday 31 October 2001 01:31 am, Jason wrote:
  
Here is my problem once again... =P I am wondering if I should
change
the date table to something other than date... maybe something like
date_1? Would doing that resolve my issue, because of the fact that
the date variable in php is function? Thanks in advance...
  
   What is the format of date as defined in your database? If date is of
   type DATE or DATETIME then
  
$result = mysql_query (SELECT * FROM ads
 WHERE fname LIKE '%$fname%' AND lname LIKE
'%$lname%' AND phonea LIKE '%$phonea%' AND phone LIKE '%$phone%' AND
date LIKE '%$date%');
  
   should be changed to:
  
  $result = mysql_query (SELECT * FROM ads
  WHERE fname LIKE '%$fname%'
AND lname LIKE '%$lname%'
AND phonea LIKE '%$phonea%'
AND phone LIKE '%$phone%'
AND date = '$date'
);
   hth
   --
   Jason Wong
   Gremlins Associates
   www.gremlins.com.hk
  
   --
   PHP Database Mailing List (http://www.php.net/)
   To unsubscribe, e-mail: [EMAIL PROTECTED]
   For additional commands, e-mail: [EMAIL PROTECTED]
   To contact the list administrators, e-mail:
[EMAIL PROTECTED]
  
 
 
 
  --
 
 
 



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 To unsubscribe, e-mail: [EMAIL PROTECTED]
 For additional commands, e-mail: [EMAIL PROTECTED]
 To contact the list administrators, e-mail: [EMAIL PROTECTED]





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Re: [PHP-DB] PHP query on date field

2001-10-30 Thread Jason

Just to clear some things up... so instead of the long winded bit of code
that was previously setup to change the format of the date for the date
field in the db, I should use the 2 lines of code? Definately skeptical on
this one... but you know more about this than I.

Rick Emery [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 Assuming you correct the hours calculation per my previous email, then:

 $format = ($Hou12?) PM : AM ;
 $Hou -= ($Hou12?) 12 : 0;

 And you can do away with all the constructs.

 -Original Message-
 From: Rick Emery
 Sent: Tuesday, October 30, 2001 2:09 PM
 To: 'Jason'; [EMAIL PROTECTED]
 Subject: RE: [PHP-DB] PHP query on date field


 Jason,

 date(H) converts to a 24-hour clock.  That is, 00 is 12 mid-night, 01 is
1
 AM, 13 is 1 PM, 14 is 2 PM, 23 is 11 PM, etc.

 I do not understand the reasons for your computation that, say 00, is 10
PM.

 -Original Message-
 From: Jason [mailto:[EMAIL PROTECTED]]
 Sent: Tuesday, October 30, 2001 2:20 PM
 To: [EMAIL PROTECTED]
 Subject: Re: [PHP-DB] PHP query on date field


 Ok well I have made the changes and tested it out but using the search
 string 10/15/2001 still provided no results... here is the script that
 parses the date for entry into the database...
 $date =  (date(m/d/Y)) ; #this date is used in the online database

 $A = (date(A));

 $Hou = (date(H));
 if ($Hou == 00){
 $Hou = 10;
 $format = PM;
 }
 if ($Hou == 01){
 $Hou = 11;
 $format = PM;
 }
 if ($Hou == 02){
 $Hou = 12;
 $format = AM;
 }
 if ($Hou == 03){
 $Hou = 01;
 $format = AM;
 }
 if ($Hou == 04){
 $Hou = 02;
 $format = AM;
 }
 if ($Hou == 05){
 $Hou = 03;
 $format = AM;
 }
 if ($Hou == 06){
 $Hou = 04;
 $format = AM;
 }
 if ($Hou == 07){
 $Hou = 05;
 $format = AM;
 }
 if ($Hou == 08){
 $Hou = 06;
 $format = AM;
 }
 if ($Hou == 09){
 $Hou = 07;
 $format = AM;
 }
 if ($Hou == 10){
 $Hou = 08;
 $format = AM;
 }
 if ($Hou == 11){
 $Hou = 09;
 $format = AM;
 }
 if ($Hou == 12){
 $Hou = 10;
 $format = AM;
 }
 if ($Hou == 13){
 $Hou = 11;
 $format = AM;
 }
 if ($Hou == 14){
 $Hou = 12;
 $format = PM;
 }
 if ($Hou == 15){
 $Hou = 01;
 $format = PM;
 }
 if ($Hou == 16){
 $Hou = 02;
 $format = PM;
 }
 if ($Hou == 17){
 $Hou = 03;
 $format = PM;
 }
 if ($Hou == 18){
 $Hou = 04;
 $format = PM;
 }
 if ($Hou == 19){
 $Hou = 05;
 $format = PM;
 }
 if ($Hou == 20){
 $Hou = 06;
 $format = PM;
 }
 if ($Hou == 21){
 $Hou = 07;
 $format = PM;
 }
 if ($Hou == 22){
 $Hou = 08;
 $format = PM;
 }
 if ($Hou == 23){
 $Hou = 09;
 $format = PM;
 }
 I am wondering if I should let the date be put into the db as
2001-15-10...

 [EMAIL PROTECTED] wrote in message
 [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
  Isn't date a reserved word that should not be used as a field name?  It
  appeared that what was asked was if he should change the name of his
field
  from date to date_1.  It should definitely be changed if it is now
called
  date.
 
 
  Jason Wong [EMAIL PROTECTED] said:
 
   On Wednesday 31 October 2001 01:31 am, Jason wrote:
  
Here is my problem once again... =P I am wondering if I should
change
the date table to something other than date... maybe something like
date_1? Would doing that resolve my issue, because of the fact that
the date variable in php is function? Thanks in advance...
  
   What is the format of date as defined in your database? If date is of
   type DATE or DATETIME then
  
$result = mysql_query (SELECT * FROM ads
 WHERE fname LIKE '%$fname%' AND lname LIKE
'%$lname%' AND phonea LIKE '%$phonea%' AND phone LIKE '%$phone%' AND
date LIKE '%$date%');
  
   should be changed to:
  
  $result = mysql_query (SELECT * FROM ads
  WHERE fname LIKE '%$fname%'
AND lname LIKE '%$lname%'
AND phonea LIKE '%$phonea%'
AND phone LIKE '%$phone%'
AND date = '$date'
);
   hth
   --
   Jason Wong
   Gremlins Associates
   www.gremlins.com.hk
  
   --
   PHP Database Mailing List (http://www.php.net/)
   To unsubscribe, e-mail: [EMAIL PROTECTED]
   For additional commands, e-mail: [EMAIL PROTECTED]
   To contact the list administrators, e-mail:
[EMAIL PROTECTED]
  
 
 
 
  --
 
 
 



 --
 PHP Database Mailing List (http://www.php.net/)
 To unsubscribe, e-mail: [EMAIL PROTECTED]
 For additional commands, e-mail: [EMAIL PROTECTED]
 To contact the list administrators, e-mail: [EMAIL PROTECTED]





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To unsubscribe, e-mail: [EMAIL PROTECTED]
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RE: [PHP-DB] PHP query on date field

2001-10-30 Thread Rick Emery

This is what I'm saying...

I encourage you to try it and experiment.

-Original Message-
From: Jason [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, October 30, 2001 2:51 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] PHP query on date field


Just to clear some things up... so instead of the long winded bit of code
that was previously setup to change the format of the date for the date
field in the db, I should use the 2 lines of code? Definately skeptical on
this one... but you know more about this than I.

Rick Emery [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 Assuming you correct the hours calculation per my previous email, then:

 $format = ($Hou12?) PM : AM ;
 $Hou -= ($Hou12?) 12 : 0;

 And you can do away with all the constructs.

 -Original Message-
 From: Rick Emery
 Sent: Tuesday, October 30, 2001 2:09 PM
 To: 'Jason'; [EMAIL PROTECTED]
 Subject: RE: [PHP-DB] PHP query on date field


 Jason,

 date(H) converts to a 24-hour clock.  That is, 00 is 12 mid-night, 01 is
1
 AM, 13 is 1 PM, 14 is 2 PM, 23 is 11 PM, etc.

 I do not understand the reasons for your computation that, say 00, is 10
PM.

 -Original Message-
 From: Jason [mailto:[EMAIL PROTECTED]]
 Sent: Tuesday, October 30, 2001 2:20 PM
 To: [EMAIL PROTECTED]
 Subject: Re: [PHP-DB] PHP query on date field


 Ok well I have made the changes and tested it out but using the search
 string 10/15/2001 still provided no results... here is the script that
 parses the date for entry into the database...
 $date =  (date(m/d/Y)) ; #this date is used in the online database

 $A = (date(A));

 $Hou = (date(H));
 if ($Hou == 00){
 $Hou = 10;
 $format = PM;
 }
 if ($Hou == 01){
 $Hou = 11;
 $format = PM;
 }
 if ($Hou == 02){
 $Hou = 12;
 $format = AM;
 }
 if ($Hou == 03){
 $Hou = 01;
 $format = AM;
 }
 if ($Hou == 04){
 $Hou = 02;
 $format = AM;
 }
 if ($Hou == 05){
 $Hou = 03;
 $format = AM;
 }
 if ($Hou == 06){
 $Hou = 04;
 $format = AM;
 }
 if ($Hou == 07){
 $Hou = 05;
 $format = AM;
 }
 if ($Hou == 08){
 $Hou = 06;
 $format = AM;
 }
 if ($Hou == 09){
 $Hou = 07;
 $format = AM;
 }
 if ($Hou == 10){
 $Hou = 08;
 $format = AM;
 }
 if ($Hou == 11){
 $Hou = 09;
 $format = AM;
 }
 if ($Hou == 12){
 $Hou = 10;
 $format = AM;
 }
 if ($Hou == 13){
 $Hou = 11;
 $format = AM;
 }
 if ($Hou == 14){
 $Hou = 12;
 $format = PM;
 }
 if ($Hou == 15){
 $Hou = 01;
 $format = PM;
 }
 if ($Hou == 16){
 $Hou = 02;
 $format = PM;
 }
 if ($Hou == 17){
 $Hou = 03;
 $format = PM;
 }
 if ($Hou == 18){
 $Hou = 04;
 $format = PM;
 }
 if ($Hou == 19){
 $Hou = 05;
 $format = PM;
 }
 if ($Hou == 20){
 $Hou = 06;
 $format = PM;
 }
 if ($Hou == 21){
 $Hou = 07;
 $format = PM;
 }
 if ($Hou == 22){
 $Hou = 08;
 $format = PM;
 }
 if ($Hou == 23){
 $Hou = 09;
 $format = PM;
 }
 I am wondering if I should let the date be put into the db as
2001-15-10...

 [EMAIL PROTECTED] wrote in message
 [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
  Isn't date a reserved word that should not be used as a field name?  It
  appeared that what was asked was if he should change the name of his
field
  from date to date_1.  It should definitely be changed if it is now
called
  date.
 
 
  Jason Wong [EMAIL PROTECTED] said:
 
   On Wednesday 31 October 2001 01:31 am, Jason wrote:
  
Here is my problem once again... =P I am wondering if I should
change
the date table to something other than date... maybe something like
date_1? Would doing that resolve my issue, because of the fact that
the date variable in php is function? Thanks in advance...
  
   What is the format of date as defined in your database? If date is of
   type DATE or DATETIME then
  
$result = mysql_query (SELECT * FROM ads
 WHERE fname LIKE '%$fname%' AND lname LIKE
'%$lname%' AND phonea LIKE '%$phonea%' AND phone LIKE '%$phone%' AND
date LIKE '%$date%');
  
   should be changed to:
  
  $result = mysql_query (SELECT * FROM ads
  WHERE fname LIKE '%$fname%'
AND lname LIKE '%$lname%'
AND phonea LIKE '%$phonea%'
AND phone LIKE '%$phone%'
AND date = '$date'
);
   hth
   --
   Jason Wong
   Gremlins Associates
   www.gremlins.com.hk
  
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[EMAIL PROTECTED]
  
 
 
 
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To contact the list 

Re: [PHP-DB] PHP query on date field

2001-10-30 Thread Jason Wong

On Wednesday 31 October 2001 04:34 am, Jason wrote:

 This portion of the site was done by a previous employee and well
 you know the expression.. If its not broke don't fix it. Well now
 that I cannot query the db by the date it is now broke and I am still
 figuring out how MySQL is taking entries to the db so I figured this
 bit of information would maybe sum up the problem in the date field. 
 I have been reading up on the date function in the MySQL book I have
 but somethings it just doesn't cover. So please excuse my being
 vague. Thanks,
 Jason

What data type is your date field -- CHAR? INT? DATE?


  date(H) converts to a 24-hour clock.  That is, 00 is 12
  mid-night, 01 is

 1

  AM, 13 is 1 PM, 14 is 2 PM, 23 is 11 PM, etc.
 
  I do not understand the reasons for your computation that, say 00,
  is 10

A stab in the dark -- could it be some time-zone adjustment?

  Ok well I have made the changes and tested it out but using the
  search string 10/15/2001 still provided no results... 

The changes would only work if your date field is of data type DATE (or 
DATETIME).

  here is the
  script that parses the date for entry into the database...
  $date =  (date(m/d/Y)) ; #this date is used in the online
  database
  I am wondering if I should let the date be put into the db as

 2001-15-10...

Changing the format of your dates to standard DATE or DATETIME *would* 
be a sensible thing to do :)


-- 
Jason Wong
Gremlins Associates
www.gremlins.com.hk

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[PHP-DB] What's wrong with my function? :(

2001-10-30 Thread TorrentUK

Please could some take a look at this code and tell me why when I take my IF
statements out of the function and put in them in the same place where I
call the function from they work, but as soon as I replace them with the
function name they don't?

Appreciate any help.
torrent

Here's the code...

// Define the rating's filter
?php
 function RatingFilter () {
  if ($br) {$sql.=  and beg_rate = '2';}

  if ($ir) {$sql.=  and int_rate = '2';}

  if ($ar) {$sql.=  and adv_rate = '2';}

  if ($sr) {$sql.=  and sbd_rate = '2';}

 }
?


if ($search) {

 include ('logon-inc.php');

 $sql = SELECT rsrt_name, ctry_name FROM resort_tbl WHERE
ctry_name='$country[0]';

 RatingFilter(); --- If I put 'if' statement here instead it works


 for ($n=1; count($country)  $n; $n++){

  $sql.=  or ctry_name='$country[$n]';

  RatingFilter(); -- Or here
 }
 .
 .
 .
 .
 }




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Re: [PHP-DB] PHP query on date field

2001-10-30 Thread Jason

The date field is varchar. And I believe it is for daylight savings. I am
trying out a couple of things on a test date field so I will get back with
you guys after I try your suggestions. And by the way I sincerely appriciate
all the help you and Rick are giving me. Thanks again,
jason
Jason Wong [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]...
 On Wednesday 31 October 2001 04:34 am, Jason wrote:

  This portion of the site was done by a previous employee and well
  you know the expression.. If its not broke don't fix it. Well now
  that I cannot query the db by the date it is now broke and I am still
  figuring out how MySQL is taking entries to the db so I figured this
  bit of information would maybe sum up the problem in the date field.
  I have been reading up on the date function in the MySQL book I have
  but somethings it just doesn't cover. So please excuse my being
  vague. Thanks,
  Jason

 What data type is your date field -- CHAR? INT? DATE?


   date(H) converts to a 24-hour clock.  That is, 00 is 12
   mid-night, 01 is
 
  1
 
   AM, 13 is 1 PM, 14 is 2 PM, 23 is 11 PM, etc.
  
   I do not understand the reasons for your computation that, say 00,
   is 10

 A stab in the dark -- could it be some time-zone adjustment?

   Ok well I have made the changes and tested it out but using the
   search string 10/15/2001 still provided no results...

 The changes would only work if your date field is of data type DATE (or
 DATETIME).

   here is the
   script that parses the date for entry into the database...
   $date =  (date(m/d/Y)) ; #this date is used in the online
   database
   I am wondering if I should let the date be put into the db as
 
  2001-15-10...

 Changing the format of your dates to standard DATE or DATETIME *would*
 be a sensible thing to do :)


 --
 Jason Wong
 Gremlins Associates
 www.gremlins.com.hk



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Re: [PHP-DB] What's wrong with my function? :(

2001-10-30 Thread Charles F. McKnight



On Tue, 30 Oct 2001, TorrentUK wrote:

SNIP

you either need to pass the variables to the function or use global
variables in the function see
http://www.php.net/manual/en/language.variables.scope.php
 
 Here's the code...
 
 // Define the rating's filter
 ?php
  function RatingFilter () {
   if ($br) {$sql.=  and beg_rate = '2';}
 
   if ($ir) {$sql.=  and int_rate = '2';}
 
   if ($ar) {$sql.=  and adv_rate = '2';}
 
   if ($sr) {$sql.=  and sbd_rate = '2';}
 
  }
 ?
 
 
 if ($search) {
 
  include ('logon-inc.php');
 
  $sql = SELECT rsrt_name, ctry_name FROM resort_tbl WHERE
 ctry_name='$country[0]';
 
  RatingFilter(); --- If I put 'if' statement here instead it works
 
 
  for ($n=1; count($country)  $n; $n++){
 
   $sql.=  or ctry_name='$country[$n]';
 
   RatingFilter(); -- Or here
  }
  .
  .
  .
  .
  }
 
 
 
 
 

-- 
Charles F. McKnight   IRC: sokudo  | Doubt is not a pleasant condition, but
[EMAIL PROTECTED]  ICQ: 2794793 | certainty is absurd.
[EMAIL PROTECTED] PGP: 0x20A5BCE5  | - Voltaire
[ http://chucksays.mywebsitesucks.com ]-


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RE: [PHP-DB] What's wrong with my function? :(

2001-10-30 Thread Leotta, Natalie (NCI/IMS)

I'm new to PHP but one thing I think might be happening is that maybe the
changes aren't being made to a global (I'm a Java programmer) $sql so they
aren't being kept.  Does it actually break or is it not appending the
additional string?  I'd try printing out the $sql and see what you're
getting - possibly at different stages of the program - like before and
after you call your function.

Good luck!

-Natalie

 -Original Message-
 From: TorrentUK [SMTP:[EMAIL PROTECTED]]
 Sent: Tuesday, October 30, 2001 3:50 PM
 To:   [EMAIL PROTECTED]
 Subject:  [PHP-DB] What's wrong with my function? :(
 
 Please could some take a look at this code and tell me why when I take my
 IF
 statements out of the function and put in them in the same place where I
 call the function from they work, but as soon as I replace them with the
 function name they don't?
 
 Appreciate any help.
 torrent
 
 Here's the code...
 
 // Define the rating's filter
 ?php
  function RatingFilter () {
   if ($br) {$sql.=  and beg_rate = '2';}
 
   if ($ir) {$sql.=  and int_rate = '2';}
 
   if ($ar) {$sql.=  and adv_rate = '2';}
 
   if ($sr) {$sql.=  and sbd_rate = '2';}
 
  }
 ?
 
 
 if ($search) {
 
  include ('logon-inc.php');
 
  $sql = SELECT rsrt_name, ctry_name FROM resort_tbl WHERE
 ctry_name='$country[0]';
 
  RatingFilter(); --- If I put 'if' statement here instead it works
 
 
  for ($n=1; count($country)  $n; $n++){
 
   $sql.=  or ctry_name='$country[$n]';
 
   RatingFilter(); -- Or here
  }
  .
  .
  .
  .
  }
 
 
 
 
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Re: [PHP-DB] What's wrong with my function? :(

2001-10-30 Thread TorrentUK

Yep, that'll be it.
Thanks for the help. :)

torrent

Charles F. McKnight [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...


 On Tue, 30 Oct 2001, TorrentUK wrote:

 SNIP

 you either need to pass the variables to the function or use global
 variables in the function see
 http://www.php.net/manual/en/language.variables.scope.php

  Here's the code...
 
  // Define the rating's filter
  ?php
   function RatingFilter () {
if ($br) {$sql.=  and beg_rate = '2';}
 
if ($ir) {$sql.=  and int_rate = '2';}
 
if ($ar) {$sql.=  and adv_rate = '2';}
 
if ($sr) {$sql.=  and sbd_rate = '2';}
 
   }
  ?
 
 
  if ($search) {
 
   include ('logon-inc.php');
 
   $sql = SELECT rsrt_name, ctry_name FROM resort_tbl WHERE
  ctry_name='$country[0]';
 
   RatingFilter(); --- If I put 'if' statement here instead it works
 
 
   for ($n=1; count($country)  $n; $n++){
 
$sql.=  or ctry_name='$country[$n]';
 
RatingFilter(); -- Or here
   }
   .
   .
   .
   .
   }
 
 
 
 
 

 --
 Charles F. McKnight   IRC: sokudo  | Doubt is not a pleasant
condition, but
 [EMAIL PROTECTED]  ICQ: 2794793 | certainty is absurd.
 [EMAIL PROTECTED] PGP: 0x20A5BCE5  | -
Voltaire
 [
http://chucksays.mywebsitesucks.com ]-




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[PHP-DB] Learning PHP Sessions

2001-10-30 Thread Matthew Tedder

?php
/*
Hi,

I'm new to PHP and am having trouble understanding how to use PHP 
sessions.  My book tells in near the beginning how to start them and register 
session variables, but I can't figure out how to destroy a session or later 
read those session variables.  I'm also trying to do this across frames, but 
can't even get it to work within a single page.

Here's what I've learned so far and what my problems are:
*/

/* To start a session */
session_start();

/* To register a session variable */
session_register(myvar);
$myvar = some value;

/*
PROBLEM #1:  From the above commands, I get a $PHPSESSID that seems to be 
globally available for use, but I cannot seem to read my values back out of 
the registered session variable from anywhere...  I tried:
*/

print $myvar\n;   /* and absolutely nothing is printed */

/* To destroy a session */
session_destroy();

/*
PROBLEM #2:  This says there is no session to destroy.  It's rather strange 
because I can still print the $PHPSESSID value..

I've attached my code...

*/
?

?php

/*= Check for New User Session =*/
if(!isset($PHPSESSID))
{
  session_start();
  session_register(UserName);
  session_register(UserPage);
  $UserName = guest;
  $UserPage = Home;
};

/*= Main Switchboard for Pages =*/
include includes/bodyhead.html;
switch($action)
{
  case Home:
ShowHome();
break;
  case Login:
ShowLogin();
break;
  case AuthUser:
AuthUser($UserName, $UserPassword);
break;
  case Logout:
ShowLogout();
break;
  default:
ShowMessage(Service Not Yet Implemented);
break;
}
include includes/bodyfoot.html;

/*= Function To Show Home Page =*/
function ShowHome()
{
  include includes/home.html;
}

/*= Function To Show Login Page =*/
function ShowLogin()
{
  print form type=put action=right.php\n;
  print input type=hidden name=action value=AuthUser\n;
  print table border=1 width=100%\n;
  print trtd bgcolor=yellow align=centerUSER AUTHORIZATION/td/tr\n;
  print /table\n;

  print table align=center\n;
  print tr\n;
  print tdfont color=yellowbUser Name:/b/font/td\n;
  print td align=centerinput type=text name=UserName length=16 
maxlength=16/td\n;
  print /tr\n;
  print tr\n;
  print tdfont color=yellowbPassword:/b/font/td\n;
  print td align=centerinput type=password name=UserPassword length=16 
maxlength=16/td\n;
  print /tr\n;
  print tr\n;
  print td align=center /td\n;
  print td align=centerinput type=submit name=UserLogin value='USER 
LOGIN'/td\n;
  print /tr\n;
  print /table\n;

  print table border=1 width=100%\n;
  print trtd bgcolor=yellow align=centerUNAUTHORIZED ENTRY IS PUNISHABLE BY 
LAW/td/tr\n;
  print /table\n;
  print /form\n;
}

/*= Function Authenticate User (from Login Page) =*/
function AuthUser($User, $User)
{
  if($User == guest)
  {
ShowMessage(For guest users, authorization is not required.  However, priviledges 
are limited.);
  }
  else
  {
ShowMessage(Authorization Feature Not Yet Implemented);
  }
}

/*= Function To Logout User =*/
function ShowLogout()
{
  ShowMessage(Your Session Has Been Terminated.\nThank You for Properly Logging Out, 
$UserName!);
  session_destroy();
}

/*= Function To Show Generic Messages =*/
function ShowMessage($message)
{
  print br\n;
  print table border=2 align=center\n;
  print trtd align=centerfont color=yellow$message/font/td/tr\n;
  print /table\n;
}

?



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[PHP-DB] any extra work need to make php mysql function available?

2001-10-30 Thread JIM

hi all,
i am using redhat. i am able to run php script thro' webpage. but, failed to
use mysql functions in php. is there any extra work need to initialize these
functions?
my code and error are shown as below,
code 

?
echo  text generated by php br\n;
echo $rmnum;
printf( b4 connected br\n);
$link=mysql_pconnect(192.168.0.101, chaze, sochausee) or die
(failed);
mysql_select_db(stjohn);
?

result 

text generated by php
b4 connected

Fatal error: Call to undefined function: mysql_pconnect() in
/home/chaze/public_html/sjc/energy.php on line 7


any comments?
thanks,
jim



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Re: [PHP-DB] Learning PHP Sessions

2001-10-30 Thread Szii

You do not need to destroy session variables.  You can
session_unregister() them, if you'd like.

$session_start();
$foo = Hi;
session_register(foo);

Next page...

if (isset($foo))
{
  echo $foo; // will print Hi if done correctly
  session_unregister(foo);
}

Sessions are automatically destroyed when the client-side browser
shuts down and the garbage collector runs.  If you want to force
a session deletion, use session_destroy().  Use it with caution, though,
since it's usually better to let the garbage collector do the work
periodically instead of cleaning up each session individually.

Check out http://www.php.net/manual/en/ref.session.php

'Luck

-Szii

- Original Message -
From: Matthew Tedder [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, October 30, 2001 12:30 PM
Subject: [PHP-DB] Learning PHP Sessions


 ?php
 /*
 Hi,

 I'm new to PHP and am having trouble understanding how to use PHP
 sessions.  My book tells in near the beginning how to start them and
register
 session variables, but I can't figure out how to destroy a session or
later
 read those session variables.  I'm also trying to do this across frames,
but
 can't even get it to work within a single page.

 Here's what I've learned so far and what my problems are:
 */

 /* To start a session */
 session_start();

 /* To register a session variable */
 session_register(myvar);
 $myvar = some value;

 /*
 PROBLEM #1:  From the above commands, I get a $PHPSESSID that seems to be
 globally available for use, but I cannot seem to read my values back out
of
 the registered session variable from anywhere...  I tried:
 */

 print $myvar\n;   /* and absolutely nothing is printed */

 /* To destroy a session */
 session_destroy();

 /*
 PROBLEM #2:  This says there is no session to destroy.  It's rather
strange
 because I can still print the $PHPSESSID value..

 I've attached my code...

 */
 ?






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Re: [PHP-DB] PHP query on date field

2001-10-30 Thread Jason Wong

On Wednesday 31 October 2001 05:11 am, Jason wrote:
 The date field is varchar. And I believe it is for daylight savings.
 I am trying out a couple of things on a test date field so I will get
 back with you guys after I try your suggestions. And by the way I
 sincerely appriciate all the help you and Rick are giving me. Thanks
 again,

In that case your original:

   date like '%$date%'

should work as long as $date is formatted the same as what is stored in 
the db.

Really, you should convert your date field into DATE or DATETIME then 
you can use all the nifty date/time functions that MySQL provides!

regards
-- 
Jason Wong
Gremlins Associates
www.gremlins.com.hk

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[PHP-DB] very strange problem for mysql query

2001-10-30 Thread JIM

hi,
i found very strange problem on mysql query. here is my code and result...
very strange!
pls help ...! thanks,

* code ***
?
$link=mysql_pconnect(192.168.0.101, chaze, apple) or die (failed);
mysql_select_db(stjohn);
$query=select * from user a, data b where a.room_num = b.room_num and
a.room_num =  . $room_num;
$result=mysql_query($query);
//$row=mysql_num_rows($result);
$row=mysql_fetch_object($result);
if ($row-id != $id)
{
 printf(wrong id!);
 header(location:http://www.php.net;);
 mysql_close($link);
 exit();
}
printf(update: %s, room no.: %sbr, $row-update_time, $row-room_num );
printf(update: %s, room no.: %sbr, $row-update_time, $row-room_num );
printf(%s %s $sbr, $row-name, $row-room_num, $row-update_time);
printf(%s %s $sbr, $row-name, $row-update_time, $row-room_num);
mysql_close($link);
?

* result ***

update: 20011029120609, room no.: 9001
update: 20011029120609, room no.: 9001
jim lo 9001
jim lo 20011029120609







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Re: [PHP-DB] very strange problem for mysql query

2001-10-30 Thread Jason Wong

On Wednesday 31 October 2001 14:42 pm, JIM wrote:

 hi,
 i found very strange problem on mysql query. here is my code and
 result... very strange!
 pls help ...! thanks,

[snip]


 printf(%s %s $sbr, $row-name, $row-room_num,
 $row-update_time); 
 printf(%s %s $sbr, $row-name, $row-update_time, $row-room_num);

These should be:

 printf(%s, %s, %sbr, .);

regards
-- 
Jason Wong
Gremlins Associates
www.gremlins.com.hk

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