Hello,
To get an indication if all the water running through the ecat has been
fully evaporated it would only be necessary to add a dye (e.g red colour) to
the cold water in the tank.
If the water in the black hose is completely clear it would be prove that
all the water has been evaporated.
T
Hello Jouni
It is very important to notice that water boils at 100.5 C when the outside
air pressure is 1030 mBar, which can be the case when a high pressure
system is covering Italy ( a normal situation during spring and summer).
Look at to calculate the pressure corrected boilingpoint :
htt
.
Peter
- Original Message -
From: "Jed Rothwell"
To:
Sent: Monday, July 18, 2011 4:08 PM
Subject: Re: [Vo]:European Patent Office observer criticizes Rossi's E-Cat
P.J van Noorden wrote:
It is very important to notice that water boils at 100.5 C when the
outside air p
Hello Fran,
I don`t understand your statement: Now that Mills admits the “hydrino” is
actually fractiona Rydberg hydrogen the term hydrino not only becomes redundant
but also carries all the baggage of his previously wrong definition that caused
so much controversy.
I thought Mills has always s
On the pictures in the article:
http://www.nyteknik.se/incoming/article3144960.ece/BINARY/Download+the+report+by+Kullander+and+Ess%C3%A9n+%28pdf%29
)
it is seen that the copper tubes are corroded from the outside , probably
due to the high temperature of the reaction.
As Jones says it is very l
The energy release of the hydrino producing reaction is 50 MJ/mol hydrogen
gas. The prefered reactionproduct seems to be H1/4.
See http://www.blacklightpower.com/papers/Eng%20Power050410S.pdf
So if 25 kWh is produced (90 MJ) this should correspond to 1.8 moles of H2
gas = 3.6 grams.
Peter va
Hello
In figure 6 of the article
http://www.nyteknik.se/incoming/article3144960.ece/BINARY/Download+the+report+by+Kullander+and+Ess%C3%A9n+%28pdf%29
it is stated that the waterflow is 6.47 l/ hour= about 2 ml/sec. This is about
the waterflow of a espressomachine.
When 4kW is added to such a
ise around 40 degrees celsius
with 6.47l/hour.
But you will see this 40 degree rise only when the system is stationary, when
dynamic is over.
From: P.J van Noorden
Sent: Thursday, April 07, 2011 11:19 AM
To: vortex-l@eskimo.com
Subject: [Vo]:Problems with energy calculation Rossi d
* 4.2 J/(g*K) * 40 K = 300 J/s = 300 watt
From: P.J van Noorden
Sent: Saturday, April 09, 2011 4:36 PM
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Problems with energy calculation Rossi device
Hello Mattia,
When using a flow of 6.47 l/hour = 1.8 cc/ sec, and a temperature rise of
a simple calculation!
From: P.J van Noorden
Sent: Saturday, April 09, 2011 5:41 PM
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Problems with energy calculation Rossi device
Ofcourse. degr/sec is a typo.
But do you agree that if the temperature rise of a waterflow of 6.47 W/h is
30 de
Hello,
I have been looking at the calculations from Jed Rothwell, Robin van Spaandonk
and Jones Been.
I think the proposed heat transfer of 130 kW would be possible, but only with a
pressurised system (as in a nuclear reactor) to prevent steam production.
I find it difficult to understand tha
- Original Message -
From: Jed Rothwell
To: vortex-l@eskimo.com
Sent: Tuesday, April 19, 2011 4:49 PM
Subject: Re: [Vo]:Beene says the error is "at least 1000:1"
P.J van Noorden wrote:
I find it difficult to understand that in the Rossi reactor with a flow of
6l/h =
Hello Jed
Do you know if there is a independent report about the flow test in February in
which the water was not heated to the boilingpoint?
Peter
- Original Message -
From: Jed Rothwell
To: vortex-l@eskimo.com
Sent: Sunday, May 08, 2011 4:03 PM
Subject: Re: [Vo]:RE: Supe
Dear Joshua,
Critics of the so called "cold fusion" field, like you, always ask why there is
so less progress in this field
in the last 22 years,
This interesting video from 2006http://www.youtube.com/watch?v=89dbXdz--eI
about the research of cold fusion by Italian researchers (de Ninno e.a)
Hello,
Perhaps this link provides some usefull information about relative humidity RH
and temperature above 100 deg C.
http://www.macinstruments.com/relatv_c.htm
Peter v Noorden
- Original Message -
From: Jed Rothwell
To: vortex-l@eskimo.com
Sent: Tuesday, June 21, 2011 5:2
Jojo Jaro,
After a year I returned to the vortex list and was unpleasantly surprised to
read about the discussion about religion.
It would be better to engage in a discussion how the brain generates a
believe in god, then to discuss which believe is "real" : Islam or
Christianity.
The only co
Dear Vorticians,
It is claimed that the experiment from Rossi released about 10kW of power.
Suppose that the experiment produced this amount of power during about 2
hours, then a total amount of 72 MJ is produced.
The amount of water that can be heated from 20 to 100 C is about 200
liters.( 20
Hello,
What I don`t understand is that with this system producing 15 kW of power
the temperature in the room isn`t higher then 23 degrees Celcius. This
amount of power corresponds to a group of 150 people or an intense
perpendicular solar flux through a large window of 15 m2. It seems that
ev
t.
The other transparent pipe is ending in a plastic vessel. Is this heated water
removed out of the room
through a drainpipe?
The somewhat younger Peter
This heat was removed by condensing the steam- by the cooling water.
Peter the Older
On Mon, Jan 17, 2011 at 1:45 PM, P.J van Noorden
Hello Jed,
How do we know that all the water ( 8.8 l) evaporated? Was the Rossi device
weighted before and after the test? The diameter of the device is about 10
cm, so there could still be a few liters inside after the experiment. An
easy way to measure the heat of this system more accuratel
I wondered why people had no problems with the 8 liters of watervapour which
was released into the room during the Rossi experiment. A simple experiment in
which I evaporised 8 liters of water in a room of 100 m3 with a powersource of
9 kW ( 3 heaters of each 3 kW) did produce a very humid atm
but roughly 1 or 2 inches away the
vapor condenses to tiny droplets which become a white fog.
On Tue, Jan 18, P.J van Noorden wrote:
I wondered why people had no problems with the 8 liters of watervapour
which was released into the room during the Rossi experiment. A simple
experim
I can confirm the problems which occur during plasma electrolysis: The
excess heat measured by Rossi would be correct if indeed all the water is
converted into steam , but in practice water can be taken away with the
watervapour in e.g plasma electrolysis experiments. In the past I did many
pla
,
on open cell CF experiments.
P.J van Noorden wrote:
I can confirm the problems which occur during plasma electrolysis: The
excess heat measured by Rossi would be correct if indeed all the water is
converted into steam , but in practice water can be taken away with the
watervapour
udulent
scamming.
Water vapor is virtually invisible…. On a tea kettle, the steam immediately
coming out of the kettle is transparent but roughly 1 or 2 inches away the
vapor condenses to tiny droplets which become a white fog.
On Tue, Jan 18, P.J van Noorden wrote:
I wonde
Jed
In 1990 I have been working with a self deviced electromagnet which was
powered by 25 ( and later 50) batteries of 12 V in parallel with a total
current of 1000 A continously to generate a very electric strong magnetic
field to detect possible neutron emission from an electrolytic experime
On January 15th 2011 the airpressure in Bologna about 1025 hPa ( High
pressure system) . At that airpressure water boils at 101 deg C. So the
higher temperature of the steam can be explained by the higher airpressure
and not be "superheated "steam.
Peter
- Original Message -
From
For everybody who is interested I have just downloaded the Washington Post
article.
Greetings
Peter van Noorden
Warming Up to Cold Fusion
Peter Hagelstein is trying to revive hope for a future of clean,
inexhaustible, inexpensive energy. Fifteen years after the scientific
embarrassment of the cen
A few years ago I did some interesting experiments with a plasma discharge
system send to me by Eugene Mallove.
This system was equiped with a reaction vessel connected with a long
vertical tube . The evaporated gasses could be condensed and where collected
in a second vessel.I used a K2CO3 solutio
ED]>
Sent: Thursday, December 02, 2004 3:51 PM
Subject: Re: comments on the Cirillo paper
> - Original Message -
> From: "P.J van Noorden"
>
> > It was very interesting to see that during evaporation a
> significant amount
> > (25%) of the radioactive Thall
omments on the Cirillo paper
> - Original Message -
> From: "P.J van Noorden"
>
> > We used 201 Thallium in our nuclear medicine department
> > to study the perfusion of the heart.The energy emission of
> radioactive
> > thallium is about 80 eV
ary coil) as a secondary
> calorimetric means. Cirillo's method is definitely susceptable to
> entrained water droplets.
>
> I would assume P.J van Noorden (he can clue us in) used an ordinary
> laboratory condenser. Such condensers are typically made of glass and
used
> in ei
Hello,
New solar concentrator without parabolic mirror.
System is flat and can produce electricity and heat
http://suncycle.nl/#
Peter v Noorden
Hello Jed,
Yes it is but it is capable to concentrate sunlight on a high efficiency
solar cel during the day, while the sun moves. The system is rather flat
Peter
- Original Message -
From: Jed Rothwell
To: vortex-l@eskimo.com
Sent: Thursday, April 25, 2013 3:55 PM
Subject: R
Hello Jones
I have talked to plasmaphysicists and they say that the continuumspectrum (
which was reproduced) proves that there is a until now unknown physical proces
going on when hydrogen atoms collide (probably during 3 body reactions).
Peter v Noorden
- Original Message -
Fro
s indicate that a novel chemical power source
is present and that it forms the energetic hydrogen plasma that is a potential
new light source.
On Mon, Jan 20, 2014 at 12:15 PM, P.J van Noorden
wrote:
Hello Jones
I have talked to plasmaphysicists and they say that the continu
Hello Jones
You mean the experiment in which a very long capillary tube of nickel was
pressurised with H2 gas and put in a K2CO3 solution?
Peter
- Original Message -
From: "Jones Beene"
To:
Sent: Monday, January 20, 2014 7:11 PM
Subject: RE: [Vo]:BLP's announcement
Mike,
I am
Frank,
You say that Mill`s device is a million times hotter than fire.
That is not correct:
The powerdensity of the hydrino reaction is 1 million times higher that that of
gasoline combusion mainly due to the rate of hydrino transition compared to the
rate of gasoiline combustion ( 5000 times
where are the X-rays?
-Original Message-
From: P.J van Noorden
To: vortex-l
Sent: Sat, Jan 25, 2014 6:48 pm
Subject: Re: [Vo]:Understandin BLP: Chapter 3
Frank,
You say that Mill`s device is a million times hotter than fire.
That is not correct:
The powerdensity of
Jojo,
Here in the Netherlands they(christians) were cutting throats in the 80 y war
between 1568 and 1648.
Peter
- Original Message -
From: Jojo Jaro
To: vortex-l@eskimo.com
Sent: Wednesday, January 02, 2013 2:06 PM
Subject: Re: [Vo]:OT: The Truth about islam and little gir
: Wednesday, January 02, 2013 7:53 PM
Subject: Re: [Vo]:OT: The Truth about islam and little girls.
Can you elaborate? Which war is this? Which Christian denominations or
groups?
Jojo
- Original Message -
From: P.J van Noorden
To: vortex-l@eskimo.com
Sent: Thursday
Hello Vortexians,
I just stumbled on this:
http://www.tue.nl/universiteit/nieuws-en-pers/agenda/2013-01-21-cold-fusion-2013/
Coincidentally I am in Eindhoven on that day, so I will attend the
colloquium.
Peter v Noorden
Jean-Paul Biberian will give an update overview of coldfusion research.
- Original Message -
From: "P.J van Noorden"
To:
Sent: Tuesday, January 15, 2013 5:19 PM
Subject: [Vo]:colloquium cold fusion 2013 in eindhoven
Hello Vortexians,
I just stumbled on this:
http://
: [Vo]:colloquium cold fusion 2013 in eindhoven
P.J van Noorden wrote:
I just stumbled on this:
http://www.tue.nl/universiteit/nieuws-en-pers/agenda/2013-01-21-cold-fusion-2013/
This link does not work for me.
Jean-Paul is writing a book about cold fusion. I guess he will
Subject: Re: [Vo]:colloquium cold fusion 2013 in eindhoven
Don't forget to register for this event, Peter.
On Tue, Jan 15, 2013 at 8:40 PM, P.J van Noorden
wrote:
This link is hopefully correct
http://www.tue.nl/en/university/departments/electrical-engineering/department
test
- Original Message -
From: David Roberson
To: vortex-l@eskimo.com
Sent: Thursday, February 07, 2013 4:33 PM
Subject: Re: [Vo]: MFMP Null Result
I wish I knew how to answer this line of inquiry. If you are suggesting that
there should be LENR activity and thus a readi
Hello Jed,
Interesting question.
I wonder if this has been tried in the past or recently.
Peter
- Original Message -
From: Jed Rothwell
To: vortex-l@eskimo.com
Sent: Tuesday, February 12, 2013 9:02 PM
Subject: Re: [Vo]:Bose Einstein Condensate formed at Room Temperature
E
Hello,
As far as I know because of the low heat production ( 25-50W for 5 km nickle
tubing as an kathode) and the saftely risk of developing this boilersystem (it
can explode) thermacore shifted the interest to heatpipe cooling systems for
computers.
Peter v Noorden
- Original Message --
Hello Axil,
I just send an article about the theory of R.Mills to vortex.
It was an attachment so it is probably rejected. I thought about that only
after I send it to vortex.
If you are interested I can send it to you.
The article is called: The fallacy of Feynman's and related arguments on the
boundary.
Hydrinos violate the rules of quantum mechanics.
On Sat, Apr 6, 2013 at 5:47 PM, P.J van Noorden
wrote:
Hello Axil,
I just send an article about the theory of R.Mills to vortex.
It was an attachment so it is probably rejected. I thought about that only
after I
See press release and validation reports from Blacklightpower:
http://dev.blacklightpower.com/press/052212-2/
http://www.blacklightpower.com/technology/validation-reports/
Peter
Hello,
From Randell Mills I understood that only H can be a catalyst because the
atom has to be neutral. He+ is not neutral, so it is difficult / impossible
to collaps.
Peter van Noorden
- Original Message -
From:
To:
Sent: Wednesday, August 15, 2012 7:18 AM
Subject: Re: [Vo]:I
Meshuganon will probably turn out to be hydrino/deuterino
Peter
- Original Message -
From: Jed Rothwell
To: vortex-l@eskimo.com
Sent: Friday, September 13, 2013 7:43 PM
Subject: Re: [Vo]:Meshuganon, pseudo-scientists and other ridiculing terms...
Alain Sepeda wrote:
Hello Steven
Blacklightpower has made a 10W CIHT cell which can produce electricity from
watervapour.
The composition of the electrode is such that the hydrino producing reaction
is facilitated and the electronshifts caused by transition of the electrons
to sub groundstate levels can be used e
10W cell cost in quantity one?
On Sat, Nov 30, 2013 at 12:36 AM, P.J van Noorden
wrote:
Hello Steven
Blacklightpower has made a 10W CIHT cell which can produce electricity from
watervapour.
The composition of the electrode is such that the hydrino producing
reaction is
ks for the report, P.J.
Hopefully, Mike is listening in. ;-)
Regards,
Steven Vincent Johnson
svjart.OrionWorks.com
www.zazzle.com/orionworks
tech.groups.yahoo.com/group/newvortex/
From: P.J van Noorden [mailto:pjvannoor...@caiway.nl]
Sent: Saturday, Novemb
: Axil Axil
To: vortex-l
Sent: Saturday, November 30, 2013 6:48 PM
Subject: Re: [Vo]:Re:
According to Mill theory, what causes the electron/hydrino to enter the
fractional charge state?
On Sat, Nov 30, 2013 at 12:08 PM, P.J van Noorden
wrote:
Hello Steven,
There have been
rging for a 10W
cell in quantity one?"
On Sat, Nov 30, 2013 at 6:35 AM, P.J van Noorden
wrote:
Hello James,
According to BLP the material cost of a CIHT cell of 1kW will cost only
$100.
There are no expensive materials needed.
Peter
- Origin
lower energy hydrino accept energy from a catalyst that has not yet
released the same amount of energy in the form of radiation? It is common for
energy to be traded in both directions according to thermodynamic laws.
Dave
-Original Message-
From: P.J van Noorden
To: vortex-l
Hi James
Mills atomic model considers the normal ground state as a treshold between
photon and photonless transitions between quantumlevels in the atom. So there
is no spontaneous transition possible of the electron to subground levels. Only
when a catalyst is used which can absorb n x 27.2 eV
Hello John
Please look at the very important video of the research done by A. de Ninno
more then 10 years ago in which she confirmed that the excess heatrelease was
related to 4He production.
http://www.youtube.com/watch?v=bujrxqwRwc0
Peter van Noorden
- Original Message -
From: J
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