> > > As I wrote in response to Gustav, I did 100 trials with no > switching > > > and won 76 times. > > >*snip* > P.S. Is somebody capable of computing the odds for winning those 76 > out of 100?
If I'm correct this should just be a binomial distribution: P(n out of 100 success without switching doors)= (100 choose n) * P(winning without switching)^n * (1-P(losing without switching))^(100-n) = (100 choose n) * (1/3)^n *(2/3)^(100-n) Thus, the probability of having 76 success out of 100 without switching doors = 2.59697e-18 = 0.000000000000000259697% -Daniel ------------------------ Yahoo! Groups Sponsor --------------------~--> Get fast access to your favorite Yahoo! Groups. Make Yahoo! your home page http://us.click.yahoo.com/dpRU5A/wUILAA/yQLSAA/MXMplB/TM --------------------------------------------------------------------~-> Yahoo! Groups Links <*> To visit your group on the web, go to: http://groups.yahoo.com/group/speedsolvingrubikscube/ <*> To unsubscribe from this group, send an email to: [EMAIL PROTECTED] <*> Your use of Yahoo! Groups is subject to: http://docs.yahoo.com/info/terms/
