On Sun, 2010-12-12 at 15:59 +1100, Erik Christiansen wrote:
... snip
>  That's controlled by the C1/C2 ratio. Consider the
> charge Q tranferred from C1 to C2 on one pulse:
> 
>    C1*V1 = Q = C2*V2
> 
> If C2 = 10*C1, then V2 = V1/10  , minus diode drops.

I found that even without a resistor across the bucket cap the bucket
would leak pretty rapidly. I don't know if the leak was into the scope
probe or something else. The 1X/10X probe setting didn't seem to make a
difference. I would think this unknown leak would make the calculations
more difficult, unless one could model the leak. The .1 to .3 uF C1/C2
ratio seemed to pass all tests on the bench.

... snip
> Hopefully that'll further help avoid the need to figure it all out the
> hard way. (Just yell out if too many details are spoiling the
> investigative fun. :-)
> 
> Erik

When I was much younger, I was pretty decent at math and pursued
mechanical engineering because I was fascinated by the thought of being
able the mathematically model a physical system and actually have the
real system match. I dropped out, but I still like to try to play with
math. Although, most times it's easier to guess and just get-r-done.

I revised my circuit:
http://www.wallacecompany.com/machine_shop/EMC2/Charge%20Pump/chpmp-5b.png 

I need to add a voltage regulator and filter caps, but there is no magic
there. I've noticed Matt's circuit is leaner because it doesn't need
one. My circuit might be improved with some I/O protection, but that
will make it more complex.

I've ordered some 74HC14's in order to build my latest try, but I'm
getting the itch to move on.

-- 
Kirk Wallace
http://www.wallacecompany.com/machine_shop/
http://www.wallacecompany.com/E45/index.html
California, USA


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