On 12/28/2013 4:21 PM, Edgar L. Owen wrote:
Brent,
The equations produce the results, you are trying to impose unwarranted interpretations
on them...
But decoherence doesn't "produce" *a* result. It produces a set of probabilities. How do
you get from there to the definite observation?
And indcidentally, there's a step in decoherence which is NOT "in the equations". That is
taking a partial trace over the environment in some particular basis (the "pointer"
basis). This is not an evolution of the Schrodinger equation.
Brent
EDgar
On Saturday, December 28, 2013 6:12:47 PM UTC-5, Brent wrote:
On 12/28/2013 1:44 PM, Edgar L. Owen wrote:
Jason,
You'll have to ask the physicists who do think that. I can't speak for them.
There is a good mathematical theory of decoherence that works fine in this
world.
It says nothing about MW whatsoever.
Why do you think there is a connection?
Decoherence only diagonalizes the system+measurement density matrix under a
partial
trace (over the environment). The diagonal them contains the probability
values for
the different eigenstates of the measurement operator. So then how do you
get from
there to a definite result? Do you, like Omnes, simply observe that you
have
predicted probabilities and so one of them obtains. Or do you go with
Evertt and
say that all of them exist with different measures and the apparent
randomness is an
illusion due to our consciousness being relative to the different outcomes?
Brent
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