Brent,

You are quibbling. It's just in other equations in the process. If it 
wasn't, it couldn't be computed and we would have no theory of decoherence 
that produces results but of course we do...

Edgar



On Saturday, December 28, 2013 7:28:24 PM UTC-5, Brent wrote:
>
>  On 12/28/2013 4:21 PM, Edgar L. Owen wrote:
>  
> Brent, 
>
>  The equations produce the results, you are trying to impose unwarranted 
> interpretations on them...
>  
>
> But decoherence doesn't "produce" *a* result.  It produces a set of 
> probabilities.  How do you get from there to the definite observation?
>
> And indcidentally, there's a step in decoherence which is NOT "in the 
> equations".  That is taking a partial trace over the environment in some 
> particular basis (the "pointer" basis).  This is not an evolution of the 
> Schrodinger equation.
>
> Brent
>
>  
>  EDgar
>
>  
>  
> On Saturday, December 28, 2013 6:12:47 PM UTC-5, Brent wrote: 
>>
>>  On 12/28/2013 1:44 PM, Edgar L. Owen wrote:
>>  
>> Jason, 
>>
>>  You'll have to ask the physicists who do think that. I can't speak for 
>> them.
>>
>>  There is a good mathematical theory of decoherence that works fine in 
>> this world. It says nothing about MW whatsoever.
>>
>>  Why do you think there is a connection?
>>
>>
>> Decoherence only diagonalizes the system+measurement density matrix under 
>> a partial trace (over the environment).  The diagonal them contains the 
>> probability values for the different eigenstates of the measurement 
>> operator.  So then how do you get from there to a definite result?  Do you, 
>> like Omnes, simply observe that you have predicted probabilities and so one 
>> of them obtains.  Or do you go with Evertt and say that all of them exist 
>> with different measures and the apparent randomness is an illusion due to 
>> our consciousness being relative to the different outcomes?
>>
>> Brent
>>  
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