JNDI / web.xml question
I'm trying to clean up a few files that have JNDI data access. I want
to move the datasource name to the web.xml for easier maintenance and to
avoid having to hardcode it into the app.
If I have a datasource in the context-param area of the web.xml file,
how can it be called?
context-param
param-namejdbcDataSource/param-name
param-valuejava:comp/env/jdbc/RestaurantDS/param-value
/context-param
pageContext.
getServletContext().getInitParameter(insert-context-param-name-here);
The above doesn't work here... does anyone know how this can be done?
Thanks,
Jack
private void initialize()
{
try {
Context ctx = null;
DataSource ds = null;
Connection conn = null;
Result result = null;
try {
ctx = new InitialContext();
ds = (DataSource)
ctx.lookup(java:comp/env/jdbc/RestaurantDS);
} catch (Exception e) {
System.out.println(DataSource context lookup failed: + e);
}
try {
conn = ds.getConnection();
} catch (Exception e) {
System.out.println(DataSource getConnection failed: + e);
e.printStackTrace();
}
-
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New User Web.xml question
Windows Server 2k, Tomcat 4.1. I'm relatively new at building web applications. I'm ok with the programming, I've never learned how to make a web.xml file. I've gotten by on the invoker running all of my jsp pages. It's now time to do things right. I have many books in front of me. NetBeans The Definitive Guide Tomcat Kick Start Apache Tomcat Bible Tomcat The Definitive Guide Web Development with JavaServer Pages CORE JSTL Mastering the JSP Standard Tag Library CORE Servlets and JavaServer Pages I still have no clue. I only write jsp pages, no servlets. I understand that Tomcat converts this to a servlet. I understand that this servlet is a class. The sample web.xml in the ROOT directory of webapps does not mention a class, yet the index page runs. The sample web.xml in the examples directory of webapps has lots of filter and filter-mapping entries. I have only a vague idea of what they do. I have a few very simple webapps. 1 page to login, 1 page to search. I would like to make a web.xml file for my webapps. Right now, whatever I try I get a 404 error when I restart Tomcat, then I delete the web.xml I made and everything is good again. Can someone give me a tip. If your webapp's root was \\webserver\www.company.com file:///\\webserver\www.company.com%20and%20you%20added%20test.jsp and you added test.jsp to that web app. What entry would you make in your web.xml file? Thanks in advance.
RE: New User Web.xml question
Howdy, You don't need to declare JSPs in your web.xml even though they really are servlets, because there's a special servlet that serves JSP pages. That servlet is declared and mapped in the master web.xml file located in the $CATALINA_HOME/conf directory. Start with a web.xml file that just has an empty webapp element: ?xml version=1.0 encoding=ISO-8859-1? !DOCTYPE web-app PUBLIC -//Sun Microsystems, Inc.//DTD Web Application 2.3//EN http://java.sun.com/dtd/web-app_2_3.dtd; web-app /web-app Alternatively, you can use the basic web.xml provided in the tomcat First Webapp guide: http://jakarta.apache.org/tomcat/tomcat-5.0-doc/appdev/web.xml.txt (In general, I suggest reading http://jakarta.apache.org/tomcat/tomcat-5.0-doc/appdev/ before any of your many printed books). Yoav Shapira Millennium ChemInformatics -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Sent: Wednesday, February 25, 2004 12:14 PM To: [EMAIL PROTECTED] Subject: New User Web.xml question Windows Server 2k, Tomcat 4.1. I'm relatively new at building web applications. I'm ok with the programming, I've never learned how to make a web.xml file. I've gotten by on the invoker running all of my jsp pages. It's now time to do things right. I have many books in front of me. NetBeans The Definitive Guide Tomcat Kick Start Apache Tomcat Bible Tomcat The Definitive Guide Web Development with JavaServer Pages CORE JSTL Mastering the JSP Standard Tag Library CORE Servlets and JavaServer Pages I still have no clue. I only write jsp pages, no servlets. I understand that Tomcat converts this to a servlet. I understand that this servlet is a class. The sample web.xml in the ROOT directory of webapps does not mention a class, yet the index page runs. The sample web.xml in the examples directory of webapps has lots of filter and filter-mapping entries. I have only a vague idea of what they do. I have a few very simple webapps. 1 page to login, 1 page to search. I would like to make a web.xml file for my webapps. Right now, whatever I try I get a 404 error when I restart Tomcat, then I delete the web.xml I made and everything is good again. Can someone give me a tip. If your webapp's root was \\webserver\www.company.com file:///\\webserver\www.company.com%20and%20you%20added%20test.jsp and you added test.jsp to that web app. What entry would you make in your web.xml file? Thanks in advance. This e-mail, including any attachments, is a confidential business communication, and may contain information that is confidential, proprietary and/or privileged. This e-mail is intended only for the individual(s) to whom it is addressed, and may not be saved, copied, printed, disclosed or used by anyone else. If you are not the(an) intended recipient, please immediately delete this e-mail from your computer system and notify the sender. Thank you. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: New User Web.xml question
JSP do not need any entries in web.xml caused they are simply mapped by filename Servlets need an entry so that you can map the servlet class to a URL pattern Filip -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Sent: Wednesday, February 25, 2004 9:14 AM To: [EMAIL PROTECTED] Subject: New User Web.xml question Windows Server 2k, Tomcat 4.1. I'm relatively new at building web applications. I'm ok with the programming, I've never learned how to make a web.xml file. I've gotten by on the invoker running all of my jsp pages. It's now time to do things right. I have many books in front of me. NetBeans The Definitive Guide Tomcat Kick Start Apache Tomcat Bible Tomcat The Definitive Guide Web Development with JavaServer Pages CORE JSTL Mastering the JSP Standard Tag Library CORE Servlets and JavaServer Pages I still have no clue. I only write jsp pages, no servlets. I understand that Tomcat converts this to a servlet. I understand that this servlet is a class. The sample web.xml in the ROOT directory of webapps does not mention a class, yet the index page runs. The sample web.xml in the examples directory of webapps has lots of filter and filter-mapping entries. I have only a vague idea of what they do. I have a few very simple webapps. 1 page to login, 1 page to search. I would like to make a web.xml file for my webapps. Right now, whatever I try I get a 404 error when I restart Tomcat, then I delete the web.xml I made and everything is good again. Can someone give me a tip. If your webapp's root was \\webserver\www.company.com file:///\\webserver\www.company.com%20and%20you%20added%20test.jsp and you added test.jsp to that web app. What entry would you make in your web.xml file? Thanks in advance. --- Incoming mail is certified Virus Free. Checked by AVG anti-virus system (http://www.grisoft.com). Version: 6.0.594 / Virus Database: 377 - Release Date: 2/24/2004 --- Outgoing mail is certified Virus Free. Checked by AVG anti-virus system (http://www.grisoft.com). Version: 6.0.594 / Virus Database: 377 - Release Date: 2/24/2004 - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: New User Web.xml question
Thank you Flip and Yoav for your help. That cleared up a lot of confusion. I have used the empty web.xml listed below, restarted tomcat, and everything was fine. I then added some taglibs to the web.xml: ?xml version=1.0 encoding=ISO-8859-1? !DOCTYPE web-app PUBLIC -//Sun Microsystems, Inc.//DTD Web Application 2.3//EN http://java.sun.com/dtd/web-app_2_3.dtd; web-app taglib taglib-urihttp://jakarta.apache.org/taglibs/c/taglib-uri taglib-location/WEB-INF/c.tld/taglib-location /taglib taglib taglib-urihttp://jakarta.apache.org/taglibs/sql/taglib-uri taglib-location/WEB-INF/sql.tld/taglib-location /taglib /web-app When I restart Tomcat, I get a 404 error. Any ideas? -Original Message- From: Shapira, Yoav [mailto:[EMAIL PROTECTED] Sent: Wednesday, February 25, 2004 12:20 PM To: Tomcat Users List Subject: RE: New User Web.xml question Howdy, You don't need to declare JSPs in your web.xml even though they really are servlets, because there's a special servlet that serves JSP pages. That servlet is declared and mapped in the master web.xml file located in the $CATALINA_HOME/conf directory. Start with a web.xml file that just has an empty webapp element: ?xml version=1.0 encoding=ISO-8859-1? !DOCTYPE web-app PUBLIC -//Sun Microsystems, Inc.//DTD Web Application 2.3//EN http://java.sun.com/dtd/web-app_2_3.dtd; web-app /web-app Alternatively, you can use the basic web.xml provided in the tomcat First Webapp guide: http://jakarta.apache.org/tomcat/tomcat-5.0-doc/appdev/web.xml.txt (In general, I suggest reading http://jakarta.apache.org/tomcat/tomcat-5.0-doc/appdev/ before any of your many printed books). Yoav Shapira Millennium ChemInformatics -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Sent: Wednesday, February 25, 2004 12:14 PM To: [EMAIL PROTECTED] Subject: New User Web.xml question Windows Server 2k, Tomcat 4.1. I'm relatively new at building web applications. I'm ok with the programming, I've never learned how to make a web.xml file. I've gotten by on the invoker running all of my jsp pages. It's now time to do things right. I have many books in front of me. NetBeans The Definitive Guide Tomcat Kick Start Apache Tomcat Bible Tomcat The Definitive Guide Web Development with JavaServer Pages CORE JSTL Mastering the JSP Standard Tag Library CORE Servlets and JavaServer Pages I still have no clue. I only write jsp pages, no servlets. I understand that Tomcat converts this to a servlet. I understand that this servlet is a class. The sample web.xml in the ROOT directory of webapps does not mention a class, yet the index page runs. The sample web.xml in the examples directory of webapps has lots of filter and filter-mapping entries. I have only a vague idea of what they do. I have a few very simple webapps. 1 page to login, 1 page to search. I would like to make a web.xml file for my webapps. Right now, whatever I try I get a 404 error when I restart Tomcat, then I delete the web.xml I made and everything is good again. Can someone give me a tip. If your webapp's root was \\webserver\www.company.com file:///\\webserver\www.company.com%20and%20you%20added%20test.jsp and you added test.jsp to that web app. What entry would you make in your web.xml file? Thanks in advance. This e-mail, including any attachments, is a confidential business communication, and may contain information that is confidential, proprietary and/or privileged. This e-mail is intended only for the individual(s) to whom it is addressed, and may not be saved, copied, printed, disclosed or used by anyone else. If you are not the(an) intended recipient, please immediately delete this e-mail from your computer system and notify the sender. Thank you. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: New User Web.xml question
Howdy, When I restart Tomcat, I get a 404 error. Any ideas? You don't get a 404 error when you restart tomcat. You get a 404 error when you try to access some resource that tomcat can't find. What resource, what is its mapping if any, and what errors are in your logs? Yoav Shapira This e-mail, including any attachments, is a confidential business communication, and may contain information that is confidential, proprietary and/or privileged. This e-mail is intended only for the individual(s) to whom it is addressed, and may not be saved, copied, printed, disclosed or used by anyone else. If you are not the(an) intended recipient, please immediately delete this e-mail from your computer system and notify the sender. Thank you. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: New User Web.xml question
) at org.apache.catalina.core.ContainerBase.stop(ContainerBase.java:1233) at org.apache.catalina.core.StandardService.stop(StandardService.java:554) at org.apache.catalina.core.StandardServer.stop(StandardServer.java:2225) at org.apache.catalina.startup.CatalinaService.stop(CatalinaService.java:295) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39 ) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl .java:25) at java.lang.reflect.Method.invoke(Method.java:324) at org.apache.catalina.startup.BootstrapService.stop(BootstrapService.java:260) at org.apache.catalina.startup.BootstrapService.main(BootstrapService.java:309) -Original Message- From: Shapira, Yoav [mailto:[EMAIL PROTECTED] Sent: Wednesday, February 25, 2004 1:52 PM To: Tomcat Users List Subject: RE: New User Web.xml question Howdy, When I restart Tomcat, I get a 404 error. Any ideas? You don't get a 404 error when you restart tomcat. You get a 404 error when you try to access some resource that tomcat can't find. What resource, what is its mapping if any, and what errors are in your logs? Yoav Shapira This e-mail, including any attachments, is a confidential business communication, and may contain information that is confidential, proprietary and/or privileged. This e-mail is intended only for the individual(s) to whom it is addressed, and may not be saved, copied, printed, disclosed or used by anyone else. If you are not the(an) intended recipient, please immediately delete this e-mail from your computer system and notify the sender. Thank you. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: New User Web.xml question
Hi, When you get an error processing your web.xml, the entire context becomes unavailable: all requests to it will result in 4xx or 5xx errors, depending on the request. As for the specific error: http://marc.theaimsgroup.com/?l=tomcat-userw=2r=1s=Exception+processi ng+tldq=b Yoav Shapira Millennium ChemInformatics -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Sent: Wednesday, February 25, 2004 2:31 PM To: [EMAIL PROTECTED] Subject: RE: New User Web.xml question Tomcat Log for web app, after I add taglibs to web.xml: 2004-02-25 13:41:02 WebappLoader[]: Deploying class repositories to work directory C:\Program Files\Apache Group\Tomcat 4.1\work\Standalone\www.company.com\_ 2004-02-25 13:41:02 WebappLoader[]: Deploy class files /WEB-INF/classes to E:\Inetpub\wwwroot\www.company.com\WEB-INF\classes 2004-02-25 13:41:02 WebappLoader[]: Deploy JAR /WEB-INF/lib/dom.jar to E:\Inetpub\wwwroot\www.company.com\WEB-INF\lib\dom.jar 2004-02-25 13:41:02 WebappLoader[]: Deploy JAR /WEB-INF/lib/jaxen-full.jar to E:\Inetpub\wwwroot\www.company.com\WEB-INF\lib\jaxen-full.jar 2004-02-25 13:41:02 WebappLoader[]: Deploy JAR /WEB-INF/lib/jaxp-api.jar to E:\Inetpub\wwwroot\www.company.com\WEB-INF\lib\jaxp-api.jar 2004-02-25 13:41:02 WebappLoader[]: Deploy JAR /WEB-INF/lib/jdbc2_0-stdext.jar to E:\Inetpub\wwwroot\www.company.com\WEB-INF\lib\jdbc2_0-stdext.jar 2004-02-25 13:41:02 WebappLoader[]: Deploy JAR /WEB-INF/lib/jstl.jar to E:\Inetpub\wwwroot\www.company.com\WEB-INF\lib\jstl.jar 2004-02-25 13:41:02 WebappLoader[]: Deploy JAR /WEB-INF/lib/sax.jar to E:\Inetpub\wwwroot\www.company.com\WEB-INF\lib\sax.jar 2004-02-25 13:41:02 WebappLoader[]: Deploy JAR /WEB-INF/lib/saxpath.jar to E:\Inetpub\wwwroot\www.company.com\WEB-INF\lib\saxpath.jar 2004-02-25 13:41:02 WebappLoader[]: Deploy JAR /WEB-INF/lib/standard.jar to E:\Inetpub\wwwroot\www.company.com\WEB-INF\lib\standard.jar 2004-02-25 13:41:02 WebappLoader[]: Deploy JAR /WEB-INF/lib/xalan.jar to E:\Inetpub\wwwroot\www.company.com\WEB-INF\lib\xalan.jar 2004-02-25 13:41:02 WebappLoader[]: Deploy JAR /WEB-INF/lib/xercesImpl.jar to E:\Inetpub\wwwroot\www.company.com\WEB-INF\lib\xercesImpl.jar 2004-02-25 13:41:02 WebappLoader[]: Reloading checks are enabled for this Context 2004-02-25 13:41:02 ContextConfig[] Exception processing TLD at resource path /WEB-INF/c.tld javax.servlet.ServletException: Exception processing TLD at resource path /WEB-INF/c.tld at org.apache.catalina.startup.ContextConfig.tldScanTld(ContextConfig.java :101 0 ) at org.apache.catalina.startup.ContextConfig.tldScan(ContextConfig.java:87 0) at org.apache.catalina.startup.ContextConfig.start(ContextConfig.java:647) at org.apache.catalina.startup.ContextConfig.lifecycleEvent(ContextConfig. java : 243) at org.apache.catalina.util.LifecycleSupport.fireLifecycleEvent(LifecycleS uppo r t.java:166) at org.apache.catalina.core.StandardContext.start(StandardContext.java:356 8) at org.apache.catalina.startup.HostConfig.checkWebXmlLastModified(HostConf ig.j a va:614) at org.apache.catalina.startup.HostConfig.run(HostConfig.java:854) at java.lang.Thread.run(Thread.java:534) - Root Cause - java.lang.IllegalArgumentException: Invalid TLD resource path /WEB- INF/c.tld at org.apache.catalina.startup.ContextConfig.tldScanTld(ContextConfig.java :100 2 ) at org.apache.catalina.startup.ContextConfig.tldScan(ContextConfig.java:87 0) at org.apache.catalina.startup.ContextConfig.start(ContextConfig.java:647) at org.apache.catalina.startup.ContextConfig.lifecycleEvent(ContextConfig. java : 243) at org.apache.catalina.util.LifecycleSupport.fireLifecycleEvent(LifecycleS uppo r t.java:166) at org.apache.catalina.core.StandardContext.start(StandardContext.java:356 8) at org.apache.catalina.startup.HostConfig.checkWebXmlLastModified(HostConf ig.j a va:614) at org.apache.catalina.startup.HostConfig.run(HostConfig.java:854) at java.lang.Thread.run(Thread.java:534) 2004-02-25 13:41:02 ContextConfig[]: Marking this application unavailable due to previous error(s) 2004-02-25 13:41:02 StandardManager[]: Seeding random number generator class java.security.SecureRandom 2004-02-25 13:41:02 StandardManager[]: Seeding of random number generator has been completed 2004-02-25 13:41:02 StandardContext[]: Context startup failed due to previous errors 2004-02-25 13:41:39 StandardHost[www.company.com]: Removing web application at context path 2004-02-25 13:41:39 StandardHost[www.company.com]: ContainerBase.removeChild: stop: LifecycleException: Container StandardContext[] has not been started at org.apache.catalina.core.StandardContext.stop(StandardContext.java:3644 ) at org.apache.catalina.core.ContainerBase.removeChild(ContainerBase.java:1 036) at org.apache.catalina.core.StandardHostDeployer.remove(StandardHostDeploy er.j a va:470
web.xml question
Hi, This is an (hopefully) easy question: I run my new web application but do not seem to get the servlet to run. I can run a simple index.html page (machine:port/my-web-appl/index.html) within my web application installation so $CATALINA_HOME/webapps/my-web-appl/index.html is found. But when I try to call a servlet having simply in web.xml: !DOCTYPE web-app PUBLIC -//Sun Microsystems, Inc.//DTD Web Application 2.3//EN http://java.sun.com/dtd /web-app_2_3.dtd web-app servlet servlet-nameRegEntryPage/servlet-name servlet-classcom.mot.sps.ipr.ipConsumer.registration.RegEntryPage/servlet-class /servlet /web-app and by calling it in the browser with machine:port/my-web-appl/RegEntryPage it fails. Has someone a quick answer? The log file simply says: Mapping contextPath='/iprweb' with requestURI='/iprweb/RegEntryPage' and relativeURI='/RegEntryPage' 2003-07-14 17:00:40 StandardContext[/iprweb]: Trying exact match 2003-07-14 17:00:40 StandardContext[/iprweb]: Trying prefix match 2003-07-14 17:00:40 StandardContext[/iprweb]: Trying extension match 2003-07-14 17:00:40 StandardContext[/iprweb]: Trying default match 2003-07-14 17:00:40 StandardContext[/iprweb]: Mapped to servlet 'default' with servlet path '/RegEntryPage' and path info 'null' and update=true Thanks. Astrid
Re: web.xml question
http://jakarta.apache.org/tomcat/faq/misc.html#invoker You'll need to map your servlet to a URL. John On Mon, 14 Jul 2003 17:02:17 +0200, Astrid Wagner [EMAIL PROTECTED] wrote: Hi, This is an (hopefully) easy question: I run my new web application but do not seem to get the servlet to run. I can run a simple index.html page (machine:port/my-web- appl/index.html) within my web application installation so $CATALINA_HOME/webapps/my-web-appl/index.html is found. But when I try to call a servlet having simply in web.xml: !DOCTYPE web-app PUBLIC -//Sun Microsystems, Inc.//DTD Web Application 2.3//EN http://java.sun.com/dtd /web-app_2_3.dtd web-app servlet servlet-nameRegEntryPage/servlet-name servlet- classcom.mot.sps.ipr.ipConsumer.registration.RegEntryPage/servlet- class /servlet /web-app and by calling it in the browser with machine:port/my-web- appl/RegEntryPage it fails. Has someone a quick answer? The log file simply says: Mapping contextPath='/iprweb' with requestURI='/iprweb/RegEntryPage' and relativeURI='/RegEntryPage' 2003-07-14 17:00:40 StandardContext[/iprweb]: Trying exact match 2003-07-14 17:00:40 StandardContext[/iprweb]: Trying prefix match 2003-07-14 17:00:40 StandardContext[/iprweb]: Trying extension match 2003-07-14 17:00:40 StandardContext[/iprweb]: Trying default match 2003-07-14 17:00:40 StandardContext[/iprweb]: Mapped to servlet 'default' with servlet path '/RegEntryPage' and path info 'null' and update=true Thanks. Astrid -- Using M2, Opera's revolutionary e-mail client: http://www.opera.com/m2/ - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
web.xml question
Is it necessary that for each of the servlet elements in the web.xml, a corresponding servlet-mapping element should be there? (For a context other than root). Thanks -Manoj.
RE: web.xml question
Hi, No. Yoav Shapira Millennium ChemInformatics -Original Message- From: Pooleery, Manoj [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:22 PM To: 'Tomcat Users List' Subject: web.xml question Is it necessary that for each of the servlet elements in the web.xml, a corresponding servlet-mapping element should be there? (For a context other than root). Thanks -Manoj. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: web.xml question
Not really, if you have a servlet is used for startup a background process, then you do not need a mapping section. - Original Message - From: Pooleery, Manoj [EMAIL PROTECTED] To: 'Tomcat Users List' [EMAIL PROTECTED] Sent: Monday, February 03, 2003 2:22 PM Subject: web.xml question Is it necessary that for each of the servlet elements in the web.xml, a corresponding servlet-mapping element should be there? (For a context other than root). Thanks -Manoj. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: web.xml question
Maybe I am doing this incorrectly - but I have a servlet class in my WEB-INF/classes directory(SessionTestServlet.class) and in my web.xml, I have an entry like this servlet servlet-nameSessionTest/servlet-name servlet-classSessionTestServlet/servlet-class /servlet When I type http://localhost:8080/test/SessioinTest, it gives me an error saying requested resource not found. What could I be doing wrong? Thanks -Manoj. -Original Message- From: Paul Hsu [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:24 PM To: Tomcat Users List Subject: Re: web.xml question Not really, if you have a servlet is used for startup a background process, then you do not need a mapping section. - Original Message - From: Pooleery, Manoj [EMAIL PROTECTED] To: 'Tomcat Users List' [EMAIL PROTECTED] Sent: Monday, February 03, 2003 2:22 PM Subject: web.xml question Is it necessary that for each of the servlet elements in the web.xml, a corresponding servlet-mapping element should be there? (For a context other than root). Thanks -Manoj. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: web.xml question
Is your Servlet have a package name? If no, it should. example: WEB-INF/classes/my/package/SessionTestServlet and then try something like that servlet-nameSessionTest/servlet-name servlet-classmy.package.SessionTestServlet/servlet-class -- Jeanfrancois Pooleery, Manoj wrote: Maybe I am doing this incorrectly - but I have a servlet class in my WEB-INF/classes directory(SessionTestServlet.class) and in my web.xml, I have an entry like this servlet servlet-nameSessionTest/servlet-name servlet-classSessionTestServlet/servlet-class /servlet When I type http://localhost:8080/test/SessioinTest, it gives me an error saying requested resource not found. What could I be doing wrong? Thanks -Manoj. -Original Message- From: Paul Hsu [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:24 PM To: Tomcat Users List Subject: Re: web.xml question Not really, if you have a servlet is used for startup a background process, then you do not need a mapping section. - Original Message - From: Pooleery, Manoj [EMAIL PROTECTED] To: 'Tomcat Users List' [EMAIL PROTECTED] Sent: Monday, February 03, 2003 2:22 PM Subject: web.xml question Is it necessary that for each of the servlet elements in the web.xml, a corresponding servlet-mapping element should be there? (For a context other than root). Thanks -Manoj. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: web.xml question
If you don't have a servlet-mapping with a url-pattern then typing something into the browser will have no effect. Erik Pooleery, Manoj wrote: Maybe I am doing this incorrectly - but I have a servlet class in my WEB-INF/classes directory(SessionTestServlet.class) and in my web.xml, I have an entry like this servlet servlet-nameSessionTest/servlet-name servlet-classSessionTestServlet/servlet-class /servlet When I type http://localhost:8080/test/SessioinTest, it gives me an error saying requested resource not found. What could I be doing wrong? Thanks -Manoj. -Original Message- From: Paul Hsu [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:24 PM To: Tomcat Users List Subject: Re: web.xml question Not really, if you have a servlet is used for startup a background process, then you do not need a mapping section. - Original Message - From: Pooleery, Manoj [EMAIL PROTECTED] To: 'Tomcat Users List' [EMAIL PROTECTED] Sent: Monday, February 03, 2003 2:22 PM Subject: web.xml question Is it necessary that for each of the servlet elements in the web.xml, a corresponding servlet-mapping element should be there? (For a context other than root). Thanks -Manoj. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: web.xml question
Hi, I think you need to change your url to the following: http://localhost:8080/test/servlets/SessioinTest or change servlets to servlet, not sure which at this point. This is basically how you call a servlet that is not mapped to a specific url pattern in your web.xml config file. I am assuming test is your context name!? ... -Original Message- From: Pooleery, Manoj [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 4:31 PM To: 'Tomcat Users List' Subject: RE: web.xml question Maybe I am doing this incorrectly - but I have a servlet class in my WEB-INF/classes directory(SessionTestServlet.class) and in my web.xml, I have an entry like this servlet servlet-nameSessionTest/servlet-name servlet-classSessionTestServlet/servlet-class /servlet When I type http://localhost:8080/test/SessioinTest, it gives me an error saying requested resource not found. What could I be doing wrong? Thanks -Manoj. -Original Message- From: Paul Hsu [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:24 PM To: Tomcat Users List Subject: Re: web.xml question Not really, if you have a servlet is used for startup a background process, then you do not need a mapping section. - Original Message - From: Pooleery, Manoj [EMAIL PROTECTED] To: 'Tomcat Users List' [EMAIL PROTECTED] Sent: Monday, February 03, 2003 2:22 PM Subject: web.xml question Is it necessary that for each of the servlet elements in the web.xml, a corresponding servlet-mapping element should be there? (For a context other than root). Thanks -Manoj. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: web.xml question
-Original Message- From: Haytham Samad [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:47 PM To: Tomcat Users List Subject: RE: web.xml question Hi, I think you need to change your url to the following: http://localhost:8080/test/servlets/SessioinTest or change servlets to servlet, not sure which at this point. This is basically how you call a servlet that is not mapped to a specific url pattern in your web.xml config file. I am assuming test is your context name!? Note that in Tomcat 4.1.12 and later, this won't work either on an out-of-the-box install. You should define an explicit servlet-mapping in your web.xml. -- Tim Moore / Blackboard Inc. / Software Engineer 1899 L Street, NW / 5th Floor / Washington, DC 20036 Phone 202-463-4860 ext. 258 / Fax 202-463-4863 ... -Original Message- From: Pooleery, Manoj [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 4:31 PM To: 'Tomcat Users List' Subject: RE: web.xml question Maybe I am doing this incorrectly - but I have a servlet class in my WEB-INF/classes directory(SessionTestServlet.class) and in my web.xml, I have an entry like this servlet servlet-nameSessionTest/servlet-name servlet-classSessionTestServlet/servlet-class /servlet When I type http://localhost:8080/test/SessioinTest, it gives me an error saying requested resource not found. What could I be doing wrong? Thanks -Manoj. -Original Message- From: Paul Hsu [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:24 PM To: Tomcat Users List Subject: Re: web.xml question Not really, if you have a servlet is used for startup a background process, then you do not need a mapping section. - Original Message - From: Pooleery, Manoj [EMAIL PROTECTED] To: 'Tomcat Users List' [EMAIL PROTECTED] Sent: Monday, February 03, 2003 2:22 PM Subject: web.xml question Is it necessary that for each of the servlet elements in the web.xml, a corresponding servlet-mapping element should be there? (For a context other than root). Thanks -Manoj. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: web.xml question
Is there some documentation regarding this? I remember this used to work earlier. is this the case only with tomcat or with all app servers? I tried out different options like putting /servlets or /servlet before the servlet class, but the only time it worked was when I specified the servlet class in the web.xml AND a servlet-mapping entry as well. My question is, is this a standard being followed universally? Thanks -Manoj. -Original Message- From: Tim Moore [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:50 PM To: Tomcat Users List Subject: RE: web.xml question -Original Message- From: Haytham Samad [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:47 PM To: Tomcat Users List Subject: RE: web.xml question Hi, I think you need to change your url to the following: http://localhost:8080/test/servlets/SessioinTest or change servlets to servlet, not sure which at this point. This is basically how you call a servlet that is not mapped to a specific url pattern in your web.xml config file. I am assuming test is your context name!? Note that in Tomcat 4.1.12 and later, this won't work either on an out-of-the-box install. You should define an explicit servlet-mapping in your web.xml. -- Tim Moore / Blackboard Inc. / Software Engineer 1899 L Street, NW / 5th Floor / Washington, DC 20036 Phone 202-463-4860 ext. 258 / Fax 202-463-4863 ... -Original Message- From: Pooleery, Manoj [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 4:31 PM To: 'Tomcat Users List' Subject: RE: web.xml question Maybe I am doing this incorrectly - but I have a servlet class in my WEB-INF/classes directory(SessionTestServlet.class) and in my web.xml, I have an entry like this servlet servlet-nameSessionTest/servlet-name servlet-classSessionTestServlet/servlet-class /servlet When I type http://localhost:8080/test/SessioinTest, it gives me an error saying requested resource not found. What could I be doing wrong? Thanks -Manoj. -Original Message- From: Paul Hsu [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:24 PM To: Tomcat Users List Subject: Re: web.xml question Not really, if you have a servlet is used for startup a background process, then you do not need a mapping section. - Original Message - From: Pooleery, Manoj [EMAIL PROTECTED] To: 'Tomcat Users List' [EMAIL PROTECTED] Sent: Monday, February 03, 2003 2:22 PM Subject: web.xml question Is it necessary that for each of the servlet elements in the web.xml, a corresponding servlet-mapping element should be there? (For a context other than root). Thanks -Manoj. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: web.xml question
A typo? http://localhost:8080/test/SessionTest instead of http://localhost:8080/test/SessioinTest Larry [EMAIL PROTECTED] 02/03/03 15:32 PM Maybe I am doing this incorrectly - but I have a servlet class in my WEB-INF/classes directory(SessionTestServlet.class) and in my web.xml, I have an entry like this servlet servlet-nameSessionTest/servlet-name servlet-classSessionTestServlet/servlet-class /servlet When I type http://localhost:8080/test/SessioinTest, it gives me an error saying requested resource not found. What could I be doing wrong? Thanks -Manoj. -Original Message- From: Paul Hsu [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:24 PM To: Tomcat Users List Subject: Re: web.xml question Not really, if you have a servlet is used for startup a background process, then you do not need a mapping section. - Original Message - From: Pooleery, Manoj [EMAIL PROTECTED] To: 'Tomcat Users List' [EMAIL PROTECTED] Sent: Monday, February 03, 2003 2:22 PM Subject: web.xml question Is it necessary that for each of the servlet elements in the web.xml, a corresponding servlet-mapping element should be there? (For a context other than root). Thanks -Manoj. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: web.xml question
Sorry that I mistyped the URL. It is not because of a typo. -Original Message- From: Larry Meadors [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:36 PM To: [EMAIL PROTECTED] Subject: RE: web.xml question A typo? http://localhost:8080/test/SessionTest instead of http://localhost:8080/test/SessioinTest Larry [EMAIL PROTECTED] 02/03/03 15:32 PM Maybe I am doing this incorrectly - but I have a servlet class in my WEB-INF/classes directory(SessionTestServlet.class) and in my web.xml, I have an entry like this servlet servlet-nameSessionTest/servlet-name servlet-classSessionTestServlet/servlet-class /servlet When I type http://localhost:8080/test/SessioinTest, it gives me an error saying requested resource not found. What could I be doing wrong? Thanks -Manoj. -Original Message- From: Paul Hsu [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:24 PM To: Tomcat Users List Subject: Re: web.xml question Not really, if you have a servlet is used for startup a background process, then you do not need a mapping section. - Original Message - From: Pooleery, Manoj [EMAIL PROTECTED] To: 'Tomcat Users List' [EMAIL PROTECTED] Sent: Monday, February 03, 2003 2:22 PM Subject: web.xml question Is it necessary that for each of the servlet elements in the web.xml, a corresponding servlet-mapping element should be there? (For a context other than root). Thanks -Manoj. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: web.xml question
Tim, Thanks for the clarification there. I have not used this in a while since I typically map my servlets to a url. Haytham -Original Message- From: Haytham Samad [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 4:47 PM To: Tomcat Users List Subject: RE: web.xml question Hi, I think you need to change your url to the following: http://localhost:8080/test/servlets/SessioinTest or change servlets to servlet, not sure which at this point. This is basically how you call a servlet that is not mapped to a specific url pattern in your web.xml config file. I am assuming test is your context name!? ... -Original Message- From: Pooleery, Manoj [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 4:31 PM To: 'Tomcat Users List' Subject: RE: web.xml question Maybe I am doing this incorrectly - but I have a servlet class in my WEB-INF/classes directory(SessionTestServlet.class) and in my web.xml, I have an entry like this servlet servlet-nameSessionTest/servlet-name servlet-classSessionTestServlet/servlet-class /servlet When I type http://localhost:8080/test/SessioinTest, it gives me an error saying requested resource not found. What could I be doing wrong? Thanks -Manoj. -Original Message- From: Paul Hsu [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:24 PM To: Tomcat Users List Subject: Re: web.xml question Not really, if you have a servlet is used for startup a background process, then you do not need a mapping section. - Original Message - From: Pooleery, Manoj [EMAIL PROTECTED] To: 'Tomcat Users List' [EMAIL PROTECTED] Sent: Monday, February 03, 2003 2:22 PM Subject: web.xml question Is it necessary that for each of the servlet elements in the web.xml, a corresponding servlet-mapping element should be there? (For a context other than root). Thanks -Manoj. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: web.xml question
This does not apply (by default) in Tomcat 4.1 or later. Haytham Samad wrote: Hi, I think you need to change your url to the following: http://localhost:8080/test/servlets/SessioinTest or change servlets to servlet, not sure which at this point. This is basically how you call a servlet that is not mapped to a specific url pattern in your web.xml config file. I am assuming test is your context name!? ... -Original Message- From: Pooleery, Manoj [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 4:31 PM To: 'Tomcat Users List' Subject: RE: web.xml question Maybe I am doing this incorrectly - but I have a servlet class in my WEB-INF/classes directory(SessionTestServlet.class) and in my web.xml, I have an entry like this servlet servlet-nameSessionTest/servlet-name servlet-classSessionTestServlet/servlet-class /servlet When I type http://localhost:8080/test/SessioinTest, it gives me an error saying requested resource not found. What could I be doing wrong? Thanks -Manoj. -Original Message- From: Paul Hsu [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:24 PM To: Tomcat Users List Subject: Re: web.xml question Not really, if you have a servlet is used for startup a background process, then you do not need a mapping section. - Original Message - From: Pooleery, Manoj [EMAIL PROTECTED] To: 'Tomcat Users List' [EMAIL PROTECTED] Sent: Monday, February 03, 2003 2:22 PM Subject: web.xml question Is it necessary that for each of the servlet elements in the web.xml, a corresponding servlet-mapping element should be there? (For a context other than root). Thanks -Manoj. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: web.xml question
-Original Message- From: Pooleery, Manoj [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:54 PM To: 'Tomcat Users List' Subject: RE: web.xml question Is there some documentation regarding this? The Tomcat 4.1.12 release notes. I remember this used to work earlier. Right. The invoker servlet was disabled due to inherent security risks. is this the case only with tomcat or with all app servers? Well, it never worked across all app servers in the first place. The invoker servlet is common in many app servers, but it was never part of the spec. I tried out different options like putting /servlets or /servlet before the servlet class, but the only time it worked was when I specified the servlet class in the web.xml AND a servlet-mapping entry as well. My question is, is this a standard being followed universally? The /servlet thing was never any kind of magic special case, it was just mapped to a servlet called InvokerServlet that invokes other servlets by name. Frequently, however, this poses security risks that might not be known to server administrators or application developers, so in Tomcat 4.1.12 and later, the mapping to the InvokerServlet is commented out by default. It is generally true that for a URL to be served by a servlet container, it needs to refer either to a resource in the webapp, or a mapping defined for a servlet or filter. -- Tim Moore / Blackboard Inc. / Software Engineer 1899 L Street, NW / 5th Floor / Washington, DC 20036 Phone 202-463-4860 ext. 258 / Fax 202-463-4863 Thanks -Manoj. -Original Message- From: Tim Moore [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:50 PM To: Tomcat Users List Subject: RE: web.xml question -Original Message- From: Haytham Samad [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:47 PM To: Tomcat Users List Subject: RE: web.xml question Hi, I think you need to change your url to the following: http://localhost:8080/test/servlets/SessioinTest or change servlets to servlet, not sure which at this point. This is basically how you call a servlet that is not mapped to a specific url pattern in your web.xml config file. I am assuming test is your context name!? Note that in Tomcat 4.1.12 and later, this won't work either on an out-of-the-box install. You should define an explicit servlet-mapping in your web.xml. -- Tim Moore / Blackboard Inc. / Software Engineer 1899 L Street, NW / 5th Floor / Washington, DC 20036 Phone 202-463-4860 ext. 258 / Fax 202-463-4863 ... -Original Message- From: Pooleery, Manoj [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 4:31 PM To: 'Tomcat Users List' Subject: RE: web.xml question Maybe I am doing this incorrectly - but I have a servlet class in my WEB-INF/classes directory(SessionTestServlet.class) and in my web.xml, I have an entry like this servlet servlet-nameSessionTest/servlet-name servlet-classSessionTestServlet/servlet-class /servlet When I type http://localhost:8080/test/SessioinTest, it gives me an error saying requested resource not found. What could I be doing wrong? Thanks -Manoj. -Original Message- From: Paul Hsu [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:24 PM To: Tomcat Users List Subject: Re: web.xml question Not really, if you have a servlet is used for startup a background process, then you do not need a mapping section. - Original Message - From: Pooleery, Manoj [EMAIL PROTECTED] To: 'Tomcat Users List' [EMAIL PROTECTED] Sent: Monday, February 03, 2003 2:22 PM Subject: web.xml question Is it necessary that for each of the servlet elements in the web.xml, a corresponding servlet-mapping element should be there? (For a context other than root). Thanks -Manoj. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: web.xml question
Read recent posts on this. At 05:49 PM 2/3/03 -0500, you wrote: -Original Message- From: Haytham Samad [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:47 PM To: Tomcat Users List Subject: RE: web.xml question Hi, I think you need to change your url to the following: http://localhost:8080/test/servlets/SessioinTest or change servlets to servlet, not sure which at this point. This is basically how you call a servlet that is not mapped to a specific url pattern in your web.xml config file. I am assuming test is your context name!? Note that in Tomcat 4.1.12 and later, this won't work either on an out-of-the-box install. You should define an explicit servlet-mapping in your web.xml. -- Tim Moore / Blackboard Inc. / Software Engineer 1899 L Street, NW / 5th Floor / Washington, DC 20036 Phone 202-463-4860 ext. 258 / Fax 202-463-4863 ... -Original Message- From: Pooleery, Manoj [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 4:31 PM To: 'Tomcat Users List' Subject: RE: web.xml question Maybe I am doing this incorrectly - but I have a servlet class in my WEB-INF/classes directory(SessionTestServlet.class) and in my web.xml, I have an entry like this servlet servlet-nameSessionTest/servlet-name servlet-classSessionTestServlet/servlet-class /servlet When I type http://localhost:8080/test/SessioinTest, it gives me an error saying requested resource not found. What could I be doing wrong? Thanks -Manoj. -Original Message- From: Paul Hsu [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:24 PM To: Tomcat Users List Subject: Re: web.xml question Not really, if you have a servlet is used for startup a background process, then you do not need a mapping section. - Original Message - From: Pooleery, Manoj [EMAIL PROTECTED] To: 'Tomcat Users List' [EMAIL PROTECTED] Sent: Monday, February 03, 2003 2:22 PM Subject: web.xml question Is it necessary that for each of the servlet elements in the web.xml, a corresponding servlet-mapping element should be there? (For a context other than root). Thanks -Manoj. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] LEGAL NOTICE This electronic mail transmission and any accompanying documents contain information belonging to the sender which may be confidential and legally privileged. This information is intended only for the use of the individual or entity to whom this electronic mail transmission was sent as indicated above. If you are not the intended recipient, any disclosure, copying, distribution, or action taken in reliance on the contents of the information contained in this transmission is strictly prohibited. If you have received this transmission in error, please delete the message. Thank you - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: web.xml question
Pooleery, Manoj wrote: Is there some documentation regarding this? I remember this used to work earlier. is this the case only with tomcat or with all app servers? I tried out different options like putting /servlets or /servlet before the servlet class, but the only time it worked was when I specified the servlet class in the web.xml AND a servlet-mapping entry as well. My question is, is this a standard being followed universally? This raises a good point -- considering that probably 99% of tutorials and books teach Hello World using the invoker servlet, I'm surprised there isn't a strong warning that this functionality has been disabled on the front page of the Tomcat pages. Then again, a big warning about the introduction of superglobals and deprecation of register_globals on the PHP site didn't do anything to stop the tide of confusion, so maybe it'd be for naught. Erik - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: web.xml question
On Mon, 3 Feb 2003, Pooleery, Manoj wrote: Date: Mon, 3 Feb 2003 17:22:16 -0500 From: Pooleery, Manoj [EMAIL PROTECTED] Reply-To: Tomcat Users List [EMAIL PROTECTED] To: 'Tomcat Users List' [EMAIL PROTECTED] Subject: web.xml question Is it necessary that for each of the servlet elements in the web.xml, a corresponding servlet-mapping element should be there? (For a context other than root). If you want your servlet to be accessible from a client request, you need to provide at least one mapping for it. It's perfectly legal to have more than one mapping, if that suits your needs -- but a servlet definition that does not have at least one servlet-mapping is not going to be of much use to you. Thanks -Manoj. Craig - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: web.xml question
On Mon, 3 Feb 2003, Erik Price wrote: Date: Mon, 03 Feb 2003 18:00:35 -0500 From: Erik Price [EMAIL PROTECTED] Reply-To: Tomcat Users List [EMAIL PROTECTED] To: Tomcat Users List [EMAIL PROTECTED] Subject: Re: web.xml question Pooleery, Manoj wrote: Is there some documentation regarding this? I remember this used to work earlier. is this the case only with tomcat or with all app servers? I tried out different options like putting /servlets or /servlet before the servlet class, but the only time it worked was when I specified the servlet class in the web.xml AND a servlet-mapping entry as well. My question is, is this a standard being followed universally? This raises a good point -- considering that probably 99% of tutorials and books teach Hello World using the invoker servlet, I'm surprised there isn't a strong warning that this functionality has been disabled on the front page of the Tomcat pages. Then again, a big warning about the introduction of superglobals and deprecation of register_globals on the PHP site didn't do anything to stop the tide of confusion, so maybe it'd be for naught. If people don't read the release notes, they aren't going to read warnings anywhere else either :-). Erik Craig - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
RE: web.xml question
It is since 4.1.12. Just read the release-note for changes under [4.1.12]. Regards, Michael -Original Message- From: Pooleery, Manoj [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 2:54 PM To: 'Tomcat Users List' Subject: RE: web.xml question Is there some documentation regarding this? I remember this used to work earlier. is this the case only with tomcat or with all app servers? I tried out different options like putting /servlets or /servlet before the servlet class, but the only time it worked was when I specified the servlet class in the web.xml AND a servlet-mapping entry as well. My question is, is this a standard being followed universally? Thanks -Manoj. -Original Message- From: Tim Moore [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:50 PM To: Tomcat Users List Subject: RE: web.xml question -Original Message- From: Haytham Samad [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:47 PM To: Tomcat Users List Subject: RE: web.xml question Hi, I think you need to change your url to the following: http://localhost:8080/test/servlets/SessioinTest or change servlets to servlet, not sure which at this point. This is basically how you call a servlet that is not mapped to a specific url pattern in your web.xml config file. I am assuming test is your context name!? Note that in Tomcat 4.1.12 and later, this won't work either on an out-of-the-box install. You should define an explicit servlet-mapping in your web.xml. -- Tim Moore / Blackboard Inc. / Software Engineer 1899 L Street, NW / 5th Floor / Washington, DC 20036 Phone 202-463-4860 ext. 258 / Fax 202-463-4863 ... -Original Message- From: Pooleery, Manoj [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 4:31 PM To: 'Tomcat Users List' Subject: RE: web.xml question Maybe I am doing this incorrectly - but I have a servlet class in my WEB-INF/classes directory(SessionTestServlet.class) and in my web.xml, I have an entry like this servlet servlet-nameSessionTest/servlet-name servlet-classSessionTestServlet/servlet-class /servlet When I type http://localhost:8080/test/SessioinTest, it gives me an error saying requested resource not found. What could I be doing wrong? Thanks -Manoj. -Original Message- From: Paul Hsu [mailto:[EMAIL PROTECTED]] Sent: Monday, February 03, 2003 5:24 PM To: Tomcat Users List Subject: Re: web.xml question Not really, if you have a servlet is used for startup a background process, then you do not need a mapping section. - Original Message - From: Pooleery, Manoj [EMAIL PROTECTED] To: 'Tomcat Users List' [EMAIL PROTECTED] Sent: Monday, February 03, 2003 2:22 PM Subject: web.xml question Is it necessary that for each of the servlet elements in the web.xml, a corresponding servlet-mapping element should be there? (For a context other than root). Thanks -Manoj. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
web.xml question
!DOCTYPE web-app PUBLIC -//Sun Microsystems, Inc.//DTD Web Application 2.2//EN http://java.sun.com/dtd/web-app_2_2.dtd http://java.sun.com/dtd/web-app_2_2.dtd; we put in the web.xml file and ship the application assuming everybody has internet connection, what is the preferred way when customers don't have internet connection. Dinesh
web.xml question
!DOCTYPE web-app PUBLIC -//Sun Microsystems, Inc.//DTD Web Application 2.2//EN http://java.sun.com/dtd/web-app_2_2.dtd http://java.sun.com/dtd/web-app_2_2.dtd; we put above lines in the web.xml file and ship the application assuming everybody has internet connection, what is the preferred way when customers don't have internet connection. Dinesh
Re: web.xml question
Which version are you using? If you are using 4.x, Tomcat will redirect the remote DOCTYPE to a local version. The remote version is never used. -- Jeanfrancois Dinesh Khetarpal wrote: !DOCTYPE web-app PUBLIC -//Sun Microsystems, Inc.//DTD Web Application 2.2//EN http://java.sun.com/dtd/web-app_2_2.dtd http://java.sun.com/dtd/web-app_2_2.dtd; we put above lines in the web.xml file and ship the application assuming everybody has internet connection, what is the preferred way when customers don't have internet connection. Dinesh -- To unsubscribe, e-mail: mailto:[EMAIL PROTECTED] For additional commands, e-mail: mailto:[EMAIL PROTECTED]
Re: web.xml question
Tomcat is programmed to look for the dtd in the $CATALINA_HOME/common/lib/servlet.jar. This is how you can run Tomcat offline w/o facing any problems :-) Rosh Dinesh Khetarpal To: [EMAIL PROTECTED] dkhetarpal@karorcc: a.caSubject: web.xml question 08/22/02 09:39 AM Please respond to Tomcat Users List !DOCTYPE web-app PUBLIC -//Sun Microsystems, Inc.//DTD Web Application 2.2//EN http://java.sun.com/dtd/web-app_2_2.dtd http://java.sun.com/dtd/web-app_2_2.dtd; we put in the web.xml file and ship the application assuming everybody has internet connection, what is the preferred way when customers don't have internet connection. Dinesh -- To unsubscribe, e-mail: mailto:[EMAIL PROTECTED] For additional commands, e-mail: mailto:[EMAIL PROTECTED]
Re: web.xml Question
i think in the same way... there should be a necessary reason to do so, that we are missing, otherwise it seems illogical - Original Message - From: Nikola Milutinovic [EMAIL PROTECTED] To: Tomcat Users List [EMAIL PROTECTED] Sent: Tuesday, January 22, 2002 3:56 PM Subject: Re: web.xml Question Usually the web.xml file of a web application starts with the following: !DOCTYPE web-app PUBLIC -//Sun Microsystems, Inc.//DTD Web Application 2.3//EN http://java.sun.com/dtd/web-app_2_3.dtd; This URL referst to the dtd file on SUN's server. I think most XML parsers like SAX need to read the dtd file to be able to parse the XML file. That would be a big problem. I'm no expert on the mnatter, but since web-app DTD is something no Servlet container can work without, couldn't the the container provide it to the parser? That URL is just an identifier, saying yes, I'm build upon Sun's public DTD for web.xml. So, the container could tell the parser look, here is that DTD, don't go fetching it. Maybe it's naive of me, but that's how I would do it. I've been using Tomcat for some time now and it never complained on web.xml. I'm behind a firewall and Tomcat is not even aware of that. Nix. -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
Re: web.xml Question
OK, I just wanted to know how this works. My development environment is not the same as an environment in a large company which usually has a lot of restrictions regarding accessing the internet. I have made a simple test and unplugged the network cable of my workstation. TOMCAT still started without a problem. So it seems that the DTD's are somehow embedded in the source code. Thanks for your information. Thomas At 22.01.2002 16:44, you wrote: i think in the same way... there should be a necessary reason to do so, that we are missing, otherwise it seems illogical - Original Message - From: Nikola Milutinovic [EMAIL PROTECTED] To: Tomcat Users List [EMAIL PROTECTED] Sent: Tuesday, January 22, 2002 3:56 PM Subject: Re: web.xml Question Usually the web.xml file of a web application starts with the following: !DOCTYPE web-app PUBLIC -//Sun Microsystems, Inc.//DTD Web Application 2.3//EN http://java.sun.com/dtd/web-app_2_3.dtd; This URL referst to the dtd file on SUN's server. I think most XML parsers like SAX need to read the dtd file to be able to parse the XML file. That would be a big problem. I'm no expert on the mnatter, but since web-app DTD is something no Servlet container can work without, couldn't the the container provide it to the parser? That URL is just an identifier, saying yes, I'm build upon Sun's public DTD for web.xml. So, the container could tell the parser look, here is that DTD, don't go fetching it. Maybe it's naive of me, but that's how I would do it. I've been using Tomcat for some time now and it never complained on web.xml. I'm behind a firewall and Tomcat is not even aware of that. Nix. -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
RE: web.xml Question
I'm no expert on XML, but I do write documents in XML which are then parsed/interpreted by a servlet (which I didn't write). As far as I know, any XML document will parse without a DTD. A DTD just provides the syntax - e.g. tag names, tag attributes, tag structures (list of tags that a tag can contain). Without a DTD, the document is just checked for well-formedness - e.g. that all start tags have an end tag. It should be possible to store the web.xml DTD locally and modify the identifier to point to it. Don't ask me what the syntax of the identifier is - all I know is that it's different for DTDs that are local! Look in a good XML book (e.g. New Riders, Inside XML). I guess that having the DTD locally would also help when creating server.xml and web.xml files: you'd be able to use an XML editor with the DTD and therefore guarantee that all your service, engine, etc. tags where in the right order, with the right attributes. Thanks, John Quote for the week: The men with the muck-rakes are often indispensable to the well-being of society; but only if they know when to stop raking the muck. Theodore Roosevelt, Speech in New York, 11 Nov. 1902 -Original Message- From: Tom Bednarz [mailto:[EMAIL PROTECTED]] Sent: 22 January 2002 07:49 To: [EMAIL PROTECTED] Subject: web.xml Question Hi everybody, Usually the web.xml file of a web application starts with the following: !DOCTYPE web-app PUBLIC -//Sun Microsystems, Inc.//DTD Web Application 2.3//EN http://java.sun.com/dtd/web-app_2_3.dtd; This URL referst to the dtd file on SUN's server. I think most XML parsers like SAX need to read the dtd file to be able to parse the XML file. Questions: What happens if I deploy an application on an Intranet which allows access to the internet only through a proxy server (with username / password authentication)? The dtd cannot be accessed and must be someware on the local disk. I found that TOMCAT has a web.xml in its conf directory. Could anybody explain me, which XML files I need to change and where do I need to put the downloaded web-app_2_3.dtd file? Is the web.xml in the conf directory like a parent to all web.xml files found under webapps\application\WEB-INF? (Something like the defaults for all web apps)? Could anybody help me out of this XML jungle? Many thanks! Thomas -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
Re: web.xml Question
It's included in $CATALINA_HOME/common/lib/servlet.jar. Tom Bednarz list@bednarzTo: [EMAIL PROTECTED] .ch cc: Subject: web.xml Question 01/22/02 01:48 AM Please respond to Tomcat Users List Hi everybody, Usually the web.xml file of a web application starts with the following: !DOCTYPE web-app PUBLIC -//Sun Microsystems, Inc.//DTD Web Application 2.3//EN http://java.sun.com/dtd/web-app_2_3.dtd; This URL referst to the dtd file on SUN's server. I think most XML parsers like SAX need to read the dtd file to be able to parse the XML file. Questions: What happens if I deploy an application on an Intranet which allows access to the internet only through a proxy server (with username / password authentication)? The dtd cannot be accessed and must be someware on the local disk. I found that TOMCAT has a web.xml in its conf directory. Could anybody explain me, which XML files I need to change and where do I need to put the downloaded web-app_2_3.dtd file? Is the web.xml in the conf directory like a parent to all web.xml files found under webapps\application\WEB-INF? (Something like the defaults for all web apps)? Could anybody help me out of this XML jungle? Many thanks! Thomas -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED] -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
Re: web.xml Question
On Tue, 22 Jan 2002, Tom Bednarz wrote: Date: Tue, 22 Jan 2002 08:48:40 +0100 From: Tom Bednarz [EMAIL PROTECTED] Reply-To: Tomcat Users List [EMAIL PROTECTED] To: [EMAIL PROTECTED] Subject: web.xml Question Hi everybody, Usually the web.xml file of a web application starts with the following: !DOCTYPE web-app PUBLIC -//Sun Microsystems, Inc.//DTD Web Application 2.3//EN http://java.sun.com/dtd/web-app_2_3.dtd; This URL referst to the dtd file on SUN's server. I think most XML parsers like SAX need to read the dtd file to be able to parse the XML file. Questions: What happens if I deploy an application on an Intranet which allows access to the internet only through a proxy server (with username / password authentication)? The dtd cannot be accessed and must be someware on the local disk. It's actually inside the servlet.jar file. Tomcat registers a local copy of the DTDs it uses, so as long as you spell the public identifier correctly the internal copy will be used. I use this mode of operation all the time, to run Tomcat on a disconnected laptop. The only other reason it might not work is if you are using an XML parser that does not properly implement the SAX EntityResolver APIs. I found that TOMCAT has a web.xml in its conf directory. Could anybody explain me, which XML files I need to change and where do I need to put the downloaded web-app_2_3.dtd file? Is the web.xml in the conf directory like a parent to all web.xml files found under webapps\application\WEB-INF? (Something like the defaults for all web apps)? Could anybody help me out of this XML jungle? Many thanks! Thomas Craig -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
web.xml Question
Hi everybody, Usually the web.xml file of a web application starts with the following: !DOCTYPE web-app PUBLIC -//Sun Microsystems, Inc.//DTD Web Application 2.3//EN http://java.sun.com/dtd/web-app_2_3.dtd; This URL referst to the dtd file on SUN's server. I think most XML parsers like SAX need to read the dtd file to be able to parse the XML file. Questions: What happens if I deploy an application on an Intranet which allows access to the internet only through a proxy server (with username / password authentication)? The dtd cannot be accessed and must be someware on the local disk. I found that TOMCAT has a web.xml in its conf directory. Could anybody explain me, which XML files I need to change and where do I need to put the downloaded web-app_2_3.dtd file? Is the web.xml in the conf directory like a parent to all web.xml files found under webapps\application\WEB-INF? (Something like the defaults for all web apps)? Could anybody help me out of this XML jungle? Many thanks! Thomas -- To unsubscribe: mailto:[EMAIL PROTECTED] For additional commands: mailto:[EMAIL PROTECTED] Troubles with the list: mailto:[EMAIL PROTECTED]
Re: web.xml Question
Usually the web.xml file of a web application starts with the following: !DOCTYPE web-app PUBLIC -//Sun Microsystems, Inc.//DTD Web Application 2.3//EN http://java.sun.com/dtd/web-app_2_3.dtd; This URL referst to the dtd file on SUN's server. I think most XML parsers like SAX need to read the dtd file to be able to parse the XML file. That would be a big problem. I'm no expert on the mnatter, but since web-app DTD is something no Servlet container can work without, couldn't the the container provide it to the parser? That URL is just an identifier, saying yes, I'm build upon Sun's public DTD for web.xml. So, the container could tell the parser look, here is that DTD, don't go fetching it. Maybe it's naive of me, but that's how I would do it. I've been using Tomcat for some time now and it never complained on web.xml. I'm behind a firewall and Tomcat is not even aware of that. Nix.
Web.xml Question
Hi I have two tomcat instances , each one of them has it's own server.xml file and it's context. My directory structure is webapps -App1-WEB-INF-web.xml -App2-WEB-INF-web.xml Tomcat#1 has App1 context and Tomcat#2 has App2 context (defined in server1.xml and server2.xml) On my web.xml files i have load-on-startup directive. My Problem is that i expexted that each tomcat will activate its own web.xml file ( in it's WEB-INF directory of the context) But every tomcat uses both web.xml files The indication of the problem is that both tomcat's instances try to load on startup all the servlets defined in the web.xml files. Tomcat version 3.2.1 Apache version 1.3.14 (Unix) mod_jk
Re: Web.xml Question
On Sunday 01 April 2001 11:48, Amir Nuri wrote: Hi I have two tomcat instances , each one of them has it's own server.xml file and it's context. My directory structure is webapps -App1-WEB-INF-web.xml -App2-WEB-INF-web.xml Tomcat#1 has App1 context and Tomcat#2 has App2 context (defined in server1.xml and server2.xml) On my web.xml files i have load-on-startup directive. My Problem is that i expexted that each tomcat will activate its own web.xml file ( in it's WEB-INF directory of the context) But every tomcat uses both web.xml files The indication of the problem is that both tomcat's instances try to load on startup all the servlets defined in the web.xml files. Tomcat version 3.2.1 Apache version 1.3.14 (Unix) mod_jk If both Tomcat instances use the same webapps directory, each Tomcat instance will try to load all of the webapps within the webapps directory, regardless of whether a particular webapp is identified in the server.xml file. I believe that if you don't want to automatically pick up everything in the webapps directory, you will need to uncomment the following line in your server.xml file: ContextInterceptor className="org.apache.tomcat.context.AutoSetup" / -- Ed Gomolka ([EMAIL PROTECTED])
Re: Web.xml Question
Oops. I meant "comment out" in my last post, rather than "uncomment". Sorry about that. Ed On Sunday 01 April 2001 15:38, Ed Gomolka wrote: On Sunday 01 April 2001 11:48, Amir Nuri wrote: Hi I have two tomcat instances , each one of them has it's own server.xml file and it's context. My directory structure is webapps -App1-WEB-INF-web.xml -App2-WEB-INF-web.xml Tomcat#1 has App1 context and Tomcat#2 has App2 context (defined in server1.xml and server2.xml) On my web.xml files i have load-on-startup directive. My Problem is that i expexted that each tomcat will activate its own web.xml file ( in it's WEB-INF directory of the context) But every tomcat uses both web.xml files The indication of the problem is that both tomcat's instances try to load on startup all the servlets defined in the web.xml files. Tomcat version 3.2.1 Apache version 1.3.14 (Unix) mod_jk If both Tomcat instances use the same webapps directory, each Tomcat instance will try to load all of the webapps within the webapps directory, regardless of whether a particular webapp is identified in the server.xml file. I believe that if you don't want to automatically pick up everything in the webapps directory, you will need to uncomment the following line in your server.xml file: ContextInterceptor className="org.apache.tomcat.context.AutoSetup" / -- Ed Gomolka ([EMAIL PROTECTED])
Re: web.xml question
On Wed, 6 Dec 2000, Kedar Choudary wrote: Regarding the second question, unfortunately, there seems to be no way to specify a servelt, in place of a "welcome-file". So, I guess, easiest way to setup your servlet as welcome-file, will be to have a index.jsp in your context's root directory which simply forwards the request to your servlet, using jsp:forward. Can't you use a servlet as a welcome-file in your welcome-file-list tag in web.xml then? I've never done it myself, but I've also not read anything that says you can't. Catherine Kedar Choudhary. - Original Message - From: Vanja Vlaski [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Tuesday, December 05, 2000 3:58 PM Subject: web.xml question Since I am new to the tomcat I have one probably stupid question.Do I have to register all the servlets I use in web.xml or just the first servlet that is called? Also how can I call the servlet at the beging instead of index.html? Thanks _ Get more from the Web. FREE MSN Explorer download : http://explorer.msn.com
web.xml question
Since I am new to the tomcat I have one probably stupid question.Do I have to register all the servlets I use in web.xml or just the first servlet that is called? Also how can I call the servlet at the beging instead of index.html? Thanks _ Get more from the Web. FREE MSN Explorer download : http://explorer.msn.com
web.xml question
In web.xml do I have to register all the servlets I will use or only first one that is being invoked? Also how do I call servlet first instead of index.html? Thanks From: "G.Nagarajan" [EMAIL PROTECTED] Reply-To: [EMAIL PROTECTED] To: [EMAIL PROTECTED] Subject: RE: tools for Stress Testing Date: Tue, 5 Dec 2000 11:29:55 +0100 tools for Stress TestingHi, Try OpenSta.org, MS web stress tool, www.rswsoftware.com. These should help. I am using OpenSta for testing my jsps and servlets and it takes care of handling cookies. Cheers, Nagaraj. -Original Message- From: Chris Chen [mailto:[EMAIL PROTECTED]] Sent: Monday, December 04, 2000 9:06 PM To: '[EMAIL PROTECTED]' Subject: tools for Stress Testing Hi all, I am just wondering if there is a way to do a stress testing on my jsp/servlet pages even I am using the session tracking in my application. for example, I have: 1.jsp for user logon checking 2.jsp for loading data from database 3.jsp for business data calculation 4.jsp for modifying data to database The application works like: when user passed 1.jsp, there will be a set of data in their session, hold by Java data Beans, from database. Base on those data, 3.jsp will performance a certain business logic, then 4.jsp will write data to database. I want to build a set of benchmark/stress testing for all those *.jsp pages. How long it will take? How's the response performance? ... How could I do this? Is there any this kind of tools? By using Tomcat, how can I let tomcat know that I am in the session, and performance certain data set for me? Regards, Chris _ Get more from the Web. FREE MSN Explorer download : http://explorer.msn.com
Re: web.xml question
Hi, You dont *have* to register any servlet in web.xml. Registering servlet in web.xml is only required if you want to access the servlet by a "nickname". Typically one creates a nickname for his servlet in web.xml to 1) Hide the actual implementation class name being exposed to the world in the URL 2) To create short name, espicially to drop that long list of package prefixes. But you can verywell access any servlet, that is present in WEB-INF/classes directory, by URL /yourcontext/servlet/package.prefix.classname. Regarding the second question, unfortunately, there seems to be no way to specify a servelt, in place of a "welcome-file". So, I guess, easiest way to setup your servlet as welcome-file, will be to have a index.jsp in your context's root directory which simply forwards the request to your servlet, using jsp:forward. Kedar Choudhary. - Original Message - From: Vanja Vlaski [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Tuesday, December 05, 2000 3:58 PM Subject: web.xml question Since I am new to the tomcat I have one probably stupid question.Do I have to register all the servlets I use in web.xml or just the first servlet that is called? Also how can I call the servlet at the beging instead of index.html? Thanks _ Get more from the Web. FREE MSN Explorer download : http://explorer.msn.com
