one possibility is that the increase of the number of molecule and the
isotopic change 4-3-2 are not the same phenomenon...
imagine a transmutation from a diatomic gas to a mono-atomic gas...
other possibility discussed here is , since it is low pressure, some
dissociation
dunno if H+ D+ can stay
It doesn't matter about the detailed reaction that gets us there. The tale
is told in the ash product found in this *Mizuno experiment *and the proof
of a reverse of the PP fusion reaction is clear.
On Sun, Mar 30, 2014 at 1:50 AM, Eric Walker eric.wal...@gmail.com wrote:
On Sat, Mar 29, 2014
For D, certainly He4 is detected, correlated with heat. For H, it's a
harder issue, so we cannot know if its is fusion which is happening, that
is, with correlation with heat.
2014-03-29 2:47 GMT-03:00 Axil Axil janap...@gmail.com:
You said
Certainly, the only proof for fusion is the
On Fri, Mar 28, 2014 at 8:06 AM, Jones Beene jone...@pacbell.net wrote:
There would be a net decrease in gas quantity under any scenario in which
D2 reacts with nickel – never wound an increase be expected, even small -
much less a ~2:1 increase in gas quantity. Amazing.
I think the lead that
I wrote:
- The p+Ni lead appears to align with the thoughts of the
experimenters themselves, who included graphs of the neutron capture cross
sections for nickel in their slides.
I wrote p+Ni, but I meant d+Ni.
Eric
From: Eric Walker
The p+Ni lead appears to align with the thoughts of the
experimenters themselves, who included graphs of the neutron capture cross
sections for nickel in their slides.
I wrote p+Ni, but I meant d+Ni.
The d+Ni
On Sat, Mar 29, 2014 at 1:31 PM, Jones Beene jone...@pacbell.net wrote:
I wrote p+Ni, but I meant d+Ni.
The d+Ni reaction would have to be the Oppenheimer-Phillips version, to be
statistically relevant. Here is a blip on Passell’s O-P theroy. I have not
found it as a separate
On Sat, Mar 29, 2014 at 2:15 PM, Eric Walker eric.wal...@gmail.com wrote:
I just discovered that you wrote concerning the OP angle back in 2010 (and
Abd Lomax replied):
https://www.mail-archive.com/vortex-l@eskimo.com
That second link above, where Jones and Abd Lomax discuss the
I wrote:
The claim I will egregiously ignore for the moment as either being artifact
or something that is different from what we currently understand it to be
is the idea that there were twice as many gas molecules after the
experiment had run than at the time it had started.
I think I found
The decay of the neutron must be instansious because no indications of
neutron absorption into a deuterium nucleus to produce tritium. There is
no indication that any atom larger in mass than deuterium had been
generated.
You must assume instansious completion of the reaction exclusive of any
On Sat, Mar 29, 2014 at 9:11 PM, Axil Axil janap...@gmail.com wrote:
There is no indication that any atom larger in mass than deuterium had been
generated.
See the yellow arrow for species of mass 3 on pp. 38, 39, 41 and 42 of the
slides (according to Chrome):
all that affair look like a miracle inside the miracle...
I suspect all is the same animal, but this animal is joking with us.
time for more experiments.
Labs seeking fund ! Any other angel here?
2014-03-28 5:22 GMT+01:00 Eric Walker eric.wal...@gmail.com:
On Thu, Mar 27, 2014 at 9:14 PM,
” which I don’t know anything about.
Arnaud
_
From: Jones Beene [mailto:jone...@pacbell.net]
Sent: vendredi 28 mars 2014 05:15
To: vortex-l@eskimo.com
Subject: RE: [Vo]:Mizuno slides coming
Guys
a bit.
Dave
-Original Message-
From: Jones Beene jone...@pacbell.net
To: vortex-l vortex-l@eskimo.com
Sent: Fri, Mar 28, 2014 11:06 am
Subject: RE: [Vo]:Mizuno slides coming
*From:* Eric Walker
I would have thought that the protons would migrate out and recombine
in excess to
that of 1H. Let's allow the dust to settle a bit.
Dave
-Original Message-
From: Jones Beene jone...@pacbell.net
To: vortex-l vortex-l@eskimo.com
Sent: Fri, Mar 28, 2014 11:06 am
Subject: RE: [Vo]:Mizuno slides coming
*From:* Eric Walker
I would have thought
The particularities of this reaction could be simply caused by the
proximity of nuclei to each other, that is, the distances between atoms as
a result of chemical bonds. If no nano particles are formed by deuterium,
from a chemical standpoint the positions of their nuclei are not in close
To be specific, please locate this information you recommend for me.
On Fri, Mar 28, 2014 at 12:54 PM, Daniel Rocha danieldi...@gmail.comwrote:
Axil, why don't you try to take things from the side of Akito? Also, try
to look for solutions of femto atoms. You'd be much closer to the truth.
Heh, just look for Akito and Andrew Meulember on Jed's library.
2014-03-28 13:57 GMT-03:00 Axil Axil janap...@gmail.com:
To be specific, please locate this information you recommend for me.
On Fri, Mar 28, 2014 at 12:54 PM, Daniel Rocha danieldi...@gmail.comwrote:
Axil, why don't you try
Axil, why don't you try to take things from the side of Akito? Also, try to
look for solutions of femto atoms. You'd be much closer to the truth.
--
Daniel Rocha - RJ
danieldi...@gmail.com
From: David Roberson
The main problem I see with this line of reasoning is that
Rossi and DGT are getting positive results. Why would that happen unless
the normal hydrogen reacts with nickel directly?
Protium does react directly ! This goes
Funny, that was the first thing I noticed when scanning the slides and it
seemed to me such an obvious dataum that I assumed they must have based the
imputations that followed on it. However, I haven't looked closely at
those imputations because until someone else actually replicates this
The theories that you recommend are predicated on the absorption of
hydrogen into a metal lattice. This lattice confinement defines the
positions of the nuclei that are to undergo fusion. In all cases these
theories revolve around a positional CONFINEMENT involved of atoms to be
proximate to the
, 2014 11:06 am
Subject: RE: [Vo]:Mizuno slides coming
From:Eric Walker
I would havethought that the protons would migrate out and recombine to form
H2. ButI don't think that would account for a twofold increase.
Therewould be a net decrease in gas quantity under any scenario in which D2
But Nickel does absorb. And why can't EMF projection of force be more
easily done inside a lattice? Not that the lattice is fundamental here. But
confinement for compression is.
--
Daniel Rocha - RJ
danieldi...@gmail.com
The reaction in this system is fission without any compression involved.
On Fri, Mar 28, 2014 at 1:53 PM, Daniel Rocha danieldi...@gmail.com wrote:
But Nickel does absorb. And why can't EMF projection of force be more
easily done inside a lattice? Not that the lattice is fundamental here. But
From: Eric Walker
I would have thought that the protons would migrate out and recombine to form
H2. But I don't think that would account for a twofold increase.
There would be a net decrease in gas quantity under any scenario in which D2
reacts with nickel – never wound an increase
Well, and you can see that this is a different type of fusion/fission. I
don't get your objection.
2014-03-28 15:02 GMT-03:00 Axil Axil janap...@gmail.com:
I understand fission to be a process where in all cases a external
stimuli affects the disruption of the atomic nucleus.
On Fri, Mar
objection to what?
On Fri, Mar 28, 2014 at 2:05 PM, Daniel Rocha danieldi...@gmail.com wrote:
Well, and you can see that this is a different type of fusion/fission. I
don't get your objection.
2014-03-28 15:02 GMT-03:00 Axil Axil janap...@gmail.com:
I understand fission to be a process
To the mechanisms I pointed out to you.
2014-03-28 15:06 GMT-03:00 Axil Axil janap...@gmail.com:
objection to what?
On Fri, Mar 28, 2014 at 2:05 PM, Daniel Rocha danieldi...@gmail.comwrote:
Well, and you can see that this is a different type of fusion/fission. I
don't get your objection.
https://www.youtube.com/watch?v=RcTSUJUCRHE
The composite model does not fit what is going on in this system. If it
does in your opinion, then explain how it does.
On Fri, Mar 28, 2014 at 2:08 PM, Daniel Rocha danieldi...@gmail.com wrote:
To the mechanisms I pointed out to you.
2014-03-28
I cannot explain everything. I'm sorry. But I can give you hints.
2014-03-28 15:12 GMT-03:00 Axil Axil janap...@gmail.com:
https://www.youtube.com/watch?v=RcTSUJUCRHE
The composite model does not fit what is going on in this system. If it
does in your opinion, then explain how it does.
Give me the hints that deal with fission.
On Fri, Mar 28, 2014 at 2:17 PM, Daniel Rocha danieldi...@gmail.com wrote:
I cannot explain everything. I'm sorry. But I can give you hints.
2014-03-28 15:12 GMT-03:00 Axil Axil janap...@gmail.com:
https://www.youtube.com/watch?v=RcTSUJUCRHE
The
What kind of fission?
2014-03-28 15:19 GMT-03:00 Axil Axil janap...@gmail.com:
Give me the hints that deal with fission.
On Fri, Mar 28, 2014 at 2:17 PM, Daniel Rocha danieldi...@gmail.comwrote:
I cannot explain everything. I'm sorry. But I can give you hints.
2014-03-28 15:12
I understand fission to be a process where in all cases a external
stimuli affects the disruption of the atomic nucleus.
On Fri, Mar 28, 2014 at 1:59 PM, Daniel Rocha danieldi...@gmail.com wrote:
How can you be sure that no compression is involved?
2014-03-28 14:55 GMT-03:00 Axil Axil
The fission or deuterium into protium,
On Fri, Mar 28, 2014 at 2:20 PM, Daniel Rocha danieldi...@gmail.com wrote:
What kind of fission?
2014-03-28 15:19 GMT-03:00 Axil Axil janap...@gmail.com:
Give me the hints that deal with fission.
On Fri, Mar 28, 2014 at 2:17 PM, Daniel Rocha
That's an endothermic reaction. And I don't see where it would fit anywhere
in any scheme.
--
Daniel Rocha - RJ
danieldi...@gmail.com
How can you be sure that no compression is involved?
2014-03-28 14:55 GMT-03:00 Axil Axil janap...@gmail.com:
The reaction in this system is fission without any compression involved.
On Fri, Mar 28, 2014 at 1:53 PM, Daniel Rocha danieldi...@gmail.comwrote:
But Nickel does absorb. And why
Jones Beene said:
Neutron decay is exothermic, but the stripping reaction itself - where the
neutron is separated from deuterium involves kinetic energy depletion - so
yes, the net reaction is not necessarily gainful unless the kinetic energy
of the deuteron is supplied in a gainful way, or
What neutron decay? Weren't you talking about deuteron yielding 2 hydrogen?
2014-03-28 15:37 GMT-03:00 Axil Axil janap...@gmail.com:
Jones Beene said:
Neutron decay is exothermic, but the stripping reaction itself - where
the neutron is separated from deuterium involves kinetic energy
A neutron becomes a proton with a gain of .75 MeV,
P + N = 2P
On Fri, Mar 28, 2014 at 3:21 PM, Daniel Rocha danieldi...@gmail.com wrote:
What neutron decay? Weren't you talking about deuteron yielding 2 hydrogen?
2014-03-28 15:37 GMT-03:00 Axil Axil janap...@gmail.com:
Jones Beene said:
That's not quite correct, you should do like this
D - P + N - 2P + e
It's endothermic
2014-03-28 16:57 GMT-03:00 Axil Axil janap...@gmail.com:
A neutron becomes a proton with a gain of .75 MeV,
P + N = 2P
On Fri, Mar 28, 2014 at 3:21 PM, Daniel Rocha danieldi...@gmail.comwrote:
What
If it were endothermic, it would never happen.
On Fri, Mar 28, 2014 at 6:32 PM, Daniel Rocha danieldi...@gmail.com wrote:
That's not quite correct, you should do like this
D - P + N - 2P + e
It's endothermic
2014-03-28 16:57 GMT-03:00 Axil Axil janap...@gmail.com:
A neutron becomes a
The decay of the neutron is associated with a quark
transformationhttp://hyperphysics.phy-astr.gsu.edu/hbase/particles/qrkdec.html#c1in
which a down quark is converted to an up by the weak interaction . The
average lifetime of 10.3 min/0.693 = 14.9 minutes is surprisingly long for
a particle decay
That doesn't make sense. The total energy is negative, it's endodermic, so
this is not an explanation for cold fusion.
2014-03-28 20:36 GMT-03:00 Axil Axil janap...@gmail.com:
The decay of the neutron is associated with a quark
Take note:
The neutron is about 0.2% more massive than a proton, which translates to
an energy difference of 1.29 MeV.
When a heavy particle becomes a lighter one, the mass difference (.2%) is
converted to energy via E=MC^2. You have your signs confused.
On Fri, Mar 28, 2014 at 7:40 PM, Daniel
You forgot the deuteron.
2014-03-28 21:24 GMT-03:00 Axil Axil janap...@gmail.com:
Take note:
The neutron is about 0.2% more massive than a proton, which translates to
an energy difference of 1.29 MeV.
When a heavy particle becomes a lighter one, the mass difference (.2%) is
converted to
Remember Jones Beene said:
Neutron decay is exothermic, but the stripping reaction itself - where the
neutron is separated from deuterium involves kinetic energy depletion - *so
yes, the net reaction is not necessarily gainful unless the kinetic energy
of the deuteron is supplied in a gainful
*Takahashi
2014-03-28 21:50 GMT-03:00 Daniel Rocha danieldi...@gmail.com:
I just pointed out to you Akito Takashi (including those we did together)
and Andrew Meulemberg's papers.
2014-03-28 21:43 GMT-03:00 Axil Axil janap...@gmail.com:
Remember Jones Beene said:
Neutron decay is
I just pointed out to you Akito Takashi (including those we did together)
and Andrew Meulemberg's papers.
2014-03-28 21:43 GMT-03:00 Axil Axil janap...@gmail.com:
Remember Jones Beene said:
Neutron decay is exothermic, but the stripping reaction itself - where
the neutron is separated from
Ok, explain how these theories produce the results observed in this system,
I don't see how. but I am open to a change of mind.
On Fri, Mar 28, 2014 at 8:50 PM, Daniel Rocha danieldi...@gmail.com wrote:
I just pointed out to you Akito Takashi (including those we did together)
and Andrew
FYI
Summary of Theory
Akito Takahashi proposes a nonlinear Langevin equation that depicts a
tetrahedral symmetric condensate with four deuterons and four electrons.
Takahashi proposes this as a seed of four-deuterium fusion with helium-4
products in condensed matter. TSC condenses in about 1.4fs
An incoming and focused compression wave comes and compresses the H(D) into
polyhedral shape, when the compressive achieves around 10eV per atom,
Akito's mechanism kicks in. It shrinks the polyhedra until compton
wavelength. Less than that and the relativistic effects become dominant.
Then, there
You just wrote 2 heliums from Be8 decay
2014-03-28 22:04 GMT-03:00 Axil Axil janap...@gmail.com:
No Helium is seen in this system. Start with that.
--
Daniel Rocha - RJ
danieldi...@gmail.com
Regarding:
many particles convering into a nuclear fusion
Explain the details of this fusion reaction with emphasis on how D becomes
2 H. exclusive of any other nuclear reactions apparent.
On Fri, Mar 28, 2014 at 9:27 PM, Daniel Rocha danieldi...@gmail.com wrote:
An incoming and focused
Yes, this is not happening in this system. ergo, the Akito Takahashi theory
does not apply to the experimental data.
On Fri, Mar 28, 2014 at 9:29 PM, Daniel Rocha danieldi...@gmail.com wrote:
You just wrote 2 heliums from Be8 decay
2014-03-28 22:04 GMT-03:00 Axil Axil
The D does not become H. What you may have is 4H+4E -H + T.
2014-03-28 22:59 GMT-03:00 Axil Axil janap...@gmail.com:
Yes, this is not happening in this system. ergo, the Akito Takahashi
theory does not apply to the experimental data.
On Fri, Mar 28, 2014 at 9:29 PM, Daniel Rocha
If T was produced in any quantity , Volume/cm3 would have dropped but it
never did, it increased monotonically. It never decreased not even
temporally.
On Fri, Mar 28, 2014 at 10:09 PM, Daniel Rocha danieldi...@gmail.comwrote:
The D does not become H. What you may have is 4H+4E -H + T.
What are you talking about? It's just what I wrote.
2014-03-29 2:20 GMT-03:00 Axil Axil janap...@gmail.com:
If T was produced in any quantity , Volume/cm3 would have dropped but it
never did, it increased monotonically. It never decreased not even
temporally.
On Fri, Mar 28, 2014 at
you said
*What you may have is 4H+4E -H + T. *
this reaction would mark a decrease in volume/cm3 which never happened.
therefore T and/or 3He was never generated. There was no fusion to heavier
elements taking place, only fission to lighter atoms (H).
On Sat, Mar 29, 2014 at 1:22 AM, Daniel
I have no idea of what you are saying. Certainly, the only proof for fusion
is the generation of He4. Perhaps, traces of T. Anything else is not
certain, that is, not independently tested and related to the generated
heat.
The quantity of fused H is too small, so, the ration (V(T)/V(H)) will
You said
Certainly, the only proof for fusion is the generation of He4
Will you accept this
since the is no He4 detected, then there is no fusion taking place.
On Sat, Mar 29, 2014 at 1:41 AM, Daniel Rocha danieldi...@gmail.com wrote:
I have no idea of what you are saying. Certainly, the
Okay, I started from scratch with a new version of the PowerPoint slides.
The PDF file shrank from 40,060 KB down to 4,591 KB. Acrobat is
unpredictable. It is the format where documents go to die.
I will upload this version this morning and then go back to yesterday's
version and replace the
From: Jed Rothwell
I will upload this version this morning and then go back to
yesterday's version and replace the Japanese text in some of the graphs
later on.
Thanks to Jed from all of us ! This is most informative, and possibly it is
the most important single
Going from D to H should be endothermic.
Harry
On Thu, Mar 27, 2014 at 11:37 AM, Jones Beene jone...@pacbell.net wrote:
From: Jed Rothwell
I will upload this version this morning and then go back to
yesterday's version and replace the Japanese text in some
Neutron decay is exothermic, but the stripping reaction itself - where the
neutron is separated from deuterium involves kinetic energy depletion - so
yes, the net reaction is not necessarily gainful unless the kinetic energy
of the deuteron is supplied in a gainful way, or unless the bond energy
Transmutation of neutrons into protons is consistent with the posit
that p-mesons are catalyzed out of a degenerate vacuum forced by the
application of extreme magnetic fields.
for reference:
*The **P **and **A **mesons in strong abelian magnetic field in SU(2)
lattice gauge theory.*
Attention water-heads (Mizuno literally means 'From Water')
Here is another weird and wonderful implication of the recent Mizuno paper
which would explain how two deuterons react in such a way as to provide more
energy than chemical but with few gamma rays and few neutrons - and with
lots of
Jones Beene jone...@pacbell.net wrote:
Attention water-heads (“Mizuno” literally means 'From Water')
It means water field (水野) The second character is field or plain.
Iwamura (岩村) means rock + village. Dr. Rockville. Most Japanese personal
names are descriptions of places. Many English names
Like piantelli's approach, this technology is a low gain approach because
the SPP pumping is very weak.
Both DGT and Rossi have very high levels of polariton pumping including
additional nanoparticle generation. They both have the Cat and Mouse
architecture where the Mouse pumps SPP and the Cat
what about the electrons in that stripping, and the neutrino...
does it stay positives?
what is the equation?
naively I imagine
np+np - 4p + 2e +2!v
is it still positive?
electrons cost 511kev to create, about the gain...
I don't master enough to be sure of anything
2014-03-27 18:58
From: alain.coetm...@gmail.com
what about the electrons in that stripping, and the neutrino...
Alain - I started a new thread to address some of the problems.
The DD-BOP reaction in the context of Mizuno's new paper
Yes there are problems with this hypothesis - but Mizuno's amazing
On Thu, Mar 27, 2014 at 8:55 AM, H Veeder hveeder...@gmail.com wrote:
Going from D to H should be endothermic.
Exciting slides. I do not have the wherewithal to assess their
calorimetry, so I will assume it is accurate.
Here are some exothermic reactions involving generation of H from D:
You only have to compare the mass difference before and after the
reaction. No QM can change it.
The reaction D to 2p is endothermic!
There must be better ideas of watt happened in the experiment. The He4
from CF of Deuterium was find in Pd systems.
Maybe the use of Ni
changes something.
I se you was quicker with neutron capture.
But the should look for
He4 in the Ni metall.
On Thu, 27 Mar 2014 20:06:03 -0700, Eric Walker
wrote:
On Thu, Mar 27, 2014 at 8:55 AM, H Veeder wrote:
Going from
D to H should be endothermic.
Exciting slides. I do not have the
wherewithal
On Thu, Mar 27, 2014 at 8:20 PM, torulf.gr...@bredband.net wrote:
I se you was quicker with neutron capture.
But the should look for He4 in the Ni metall.
Good idea. 4He does not migrate in palladium, so it may not migrate in
nickel either.
Eric
Eric, I was referring to Jones post where he was taking about stripping the
neutron from a deuterium to make hydrogen, but the fusion reactions you
listed below are worth considering too.
Harry
On Thu, Mar 27, 2014 at 11:06 PM, Eric Walker eric.wal...@gmail.com wrote:
On Thu, Mar 27, 2014 at
I wrote:
What is interesting in the above scenario is that we are looking at the
possibility not of proton capture but of neutron capture.
The Oppenheimer-Phillips process (mentioned by Jones) becomes quite
interesting in the context of a d+Ni reaction. Given the very strong
repulsion of the
No Way. That kind of radiation would stand out like a sore thumb.
With 150 watts of energy from average 7 MeV protons for 30 days, the Mizuno lab
would be a small Fukushima…
From: torulf.gr...@bredband.net
I see you was quicker with neutron capture.
But the should look for He4 in
Listen to Hagelstein answer a question about fission at the 47:50 min mark.
https://www.youtube.com/watch?v=PUHYf8WZ8w4list=UUH78efhknLR-cuL9w2hVcUQ
To explain transmutation from lower to higher mass nuclei he proposes an
inverse fractionation process to liberate a neutron from one nucleus
Guys,
You may have missed one huge detail. Did not the gas quantity in the reactor
actually increase significantly after 30 days compared to initial conditions
?
Maybe I am the one to have misinterpreted that detail, which would be
extremely important and would seem to negate the possibility of
On Thu, Mar 27, 2014 at 9:14 PM, Jones Beene jone...@pacbell.net wrote:
You may have missed one huge detail. Did not the gas quantity in the reactor
actually increase significantly after 30 days compared to initial
conditions
?
Yes. Interesting detail. I hope they give out more
Mizuno sent me a revised version of the slides presented by Yoshida at MIT.
A lot of the text is in Japanese, especially the text embedded in the
graphs. I think it would be more useful to readers if I translate this. So
I will translate it and upload it to LENR-CANR.org. Soon.
- Jed
Oops. I meant Mr. Yoshino (吉野).
- Jed
Okay, I now have revised revised and revised expanded slides. Some from
Mizuno and some from Yoshino. I may not be able to upload them until
tomorrow. But you'll like 'em.
I translated most of the text into English.
Most of the photos of equipment are same ones I used in the ICCF18 poster.
The
Stop the teasin already :)
On Wed, Mar 26, 2014 at 1:28 PM, Jed Rothwell jedrothw...@gmail.com wrote:
Okay, I now have revised revised and revised expanded slides. Some from
Mizuno and some from Yoshino. I may not be able to upload them until
tomorrow. But you'll like 'em.
I translated
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