Not to beat a dead horse, but I have a problem associated with
differences between 4.3 and 4.0.6. My local server (Mac OSX) is running
4.3 and has globals off. I designed the code to run with $_SESSION for
my log in pages, and they work fine. Then I had to move the files to a
client's server
just as a quick fix. I use the following snip to take an array of
choices, enter it into a varchar field (or text if you expect alot) and
extract back to array:
$choicesArray is a list of checkboxes from a form
// put data into table
$checkList = implode(;, $choicesArray);
I'd like to get some opinions from the list.
We run php/mysql on our linux servers located behind a firewall. Many
of our clients have scripts that access their databases via php running
on the hosting server, and the general access is set up as:
$hostname = localhost;
$database =
One comment is to be sure the destination folder has write privileges
for world.
My typical usage is:
2) // datafile is field name for image/file upload browser
$img_dir = ../photos; // must be 777 access
if($datafile_name != ) {
if ($datafile_name != none) {
An Real World example of how I do a similar thing might help:
My list with checkboxes (since this is dynamic, I don't know what
numbers are assigned) $itemID is the id of the record from the mysql
table, so the check box name is 'chk_12' for id=12. $checkAll is a flag
if the user selected the
I have two tables, one contains event information and the other dates
that the event takes place:
| id| int(11) | | PRI | 0 | auto_increment |
| title | varchar(100) | YES | | NULL||
| location | varchar(100) | YES | | NULL
Thanks.
My error seemed to be just in the group declaration. Comparing yours
and mine with slight modifications to yours that eventually worked as
desired:
yours:
select e.id, title, min(event_date) as event_date from eventTable e,
dateTable d where e.id = d.event_key group by e.id;
mine:
I have a manual and use it plus lots of sample code to work through,
but there are times when we hit a wall and a simple second set of
eyes to spot what should be obvious is helpful.
I appreciate having a forum to throw out a question and get a rapid
response. I could have rewritten this
I am trying to accomplish is an array('Atomic Coffee', 'Duane's
House Of Pizza','Hi-Ho Tavern','Speak Easy','Village Inn')
Help??
Terry Romine
Web Developer
JumpInteractive.com
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my improvement is:
===
$counter = 1;
echo table border=1tr; //start of table
for ($i=0;$i$num_rows; $i++) //loop through the number of records
{
$row = mysql_fetch_array($result); //Get associate row
echo td$row[0]/td; //Print out the NAME
if($counter =(!
I've run into a sticky case where my query is failing (PHP4.x/MySQL).
I have a table where the price value is imported from an external
source, so I can't change it on the fly, and they embed thousands
seperators (in my case ','). When I try to do a query such as .. where
price = '25' ..
I have a form with a multi-line select field:
select name=cities size=5 multiple
?
$sql=select City from table group by City
;
Great!! Works like a charm.
Terry
On Thursday, July 18, 2002, at 10:27 AM, Jason Wong wrote:
On Thursday 18 July 2002 23:18, Terry Romine wrote:
I have a form with a multi-line select field:
select name=cities size=5 multiple
Use:
select name=cities[] size=5
I'm having a problem with cookies over several pages. I've tried to set
them up per the manual, ie: prior to header, and using
setcookie('cookiename',$value,time()+3600). The cookie seems to be
created fine on the first page, and passed to the second page, but is
not maintained when the pages
1) no, the commented
setcookie(user_data,,time()+(3600));// set for 6 weeks *24*7*6
I would move the *24*7*6 back into the (3600) to make it so. I just
want to test for an hour
2) so maybe this is a problem with the server? I've been tearing my hair
out because neither cookies
as in
if (!isset($_COOKIE['user_data'])) {
setcookie(user_data,,time()+(3600));// set for 6 weeks
*24*7*6
}
??
nah.. that doesn't work either. It still creates a new cookie.
On Wednesday, July 3, 2002, at 10:05 AM, [EMAIL PROTECTED] wrote:
Is this a
just checked and the server is running Apache 1.6.19 and PHP 4.0.6
Terry
On Wednesday, July 3, 2002, at 09:52 AM,
[EMAIL PROTECTED] wrote:
Trust me this does not work with php 4.2.1 and apache 2.0.39 from what
I am told if you get the cvs for apache 2.0.4 it should but I just down
graded
routine before
assigning my string to a variable that will be used in a SQL statement?
Thanks,
Blaine
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Terry Romine
Web Developer
JumpInteractive.com
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delete.php
Terry Romine
Web Developer
JumpInteractive.com
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Terry Romine
Web Developer
JumpInteractive.com
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page (select_class.php) to
process the form, does the data get reverted somehow? The data just
doesn't seem to get updated to the form inputs.
What might I be missing?
Thanks in advance
Terry Romine
Web Developer
JumpInteractive.com
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PHP Database Mailing List (http://www.php.net
.
Whatsupwiththat???
On Wednesday, May 15, 2002, at 09:57 AM, matt stewart wrote:
You need to look up $HTTP_SESSION_VARS['name'] - that's how to change
the
variables when they are already set..
i think most people have this problem when they first use sessions!
Terry Romine
Web Developer
, May 15, 2002, at 09:57 AM, matt stewart wrote:
You need to look up $HTTP_SESSION_VARS['name'] - that's how to change
the
variables when they are already set..
i think most people have this problem when they first use sessions!
Terry Romine
Web Developer
JumpInteractive.com
--
PHP
, 2002, at 11:01 AM, matt stewart wrote:
don't think you can have an array as a session variable, you'd have to
set
it as character delimited string or something.
Terry Romine
Web Developer
JumpInteractive.com
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Is there an easy way (say using eregi_replace) to find a link reference
in a blob of text and add the a href anchor around it? Something like:
text has a link to a website at
http://www.whatever.com/mydirectory/mypage.html ...
and converts it to
text has a link to a
I have a small situation where it would be good to be able to embed a
perl routing in a php script. Is this possible? Or do I need to pass
control from php to a perl script and return?
A quick synopsis would be (in pseudo code)
?php
if($theFileType == pdf {
// call
.
On Wednesday, October 24, 2001, at 11:05 AM, Terry Romine wrote:
I have a small situation where it would be good to be able to embed a
perl routing in a php script. Is this possible? Or do I need to pass
control from php to a perl script and return?
A quick synopsis would be (in pseudo code
But how do you set it so a webuser would run sudo? That sounds pretty
dangerous, to me.
I have a similar situation where I want PHP to create a subdirectory and
set privileges to it based on the login user. I end up having to create
the directory by hand via SSH and then run the php script.
I normally work PHP/MySQL but now I have a customer that is adamant
about keeping their data in an Access DB. I tried to use ADODB to do
generic access scripts, but that doesn't seem to work out for me. I get
an unsupported function just trying to make a connection. One problem is
that my
On Thursday, March 29, 2001, at 04:58 PM, Scott Kalbach wrote:
I have the individual queries in include files. It does the first 2
queries
fine,but when it gets to the third, the value of $customer seems to be
gone,
so I get no result for the rest of the query's. I looked in my scripts
I like your simplicity and straightforwardness.
My code tends toward:
switch($submit) {
case: "Accept":
.. insert record
break;
case: "Delete":
.. delete record
break;
case "Cancel":
..
"select data_name,data_number from myTable order data_number DESC"
The "DESC" is descending.
HTH
Terry
On Friday, March 23, 2001, at 03:02 PM, Sunil Jagarlamudi wrote:
I am trying to read a file which has two columns with names and numbers and
I am trying to sort them numerically, with
check where you are getting "$mysql_link" that is the problem I usually associate with
the error you report.
if $mysql_link is undefined, MySQL can't perform the query.
Terry
On Tuesday, March 20, 2001, at 12:06 AM, Toke Herkild wrote:
$mysql_result = mysql_query($query,
even better to use:
echo("\$PASS = $PASSbr\$PASSNOG = $PASSNOG");
which will show the variable name whether it has anything defined or not.
Terry
On Wednesday, March 14, 2001, at 03:21 PM, Ivo Stoykov wrote:
Hi Duky
Try to add this before if statement
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